The document provides instructions to construct the bisector of an angle ABC using compasses. It involves drawing an arc from point B as the center to intersect rays BA and BC at points E and D. Arcs are then drawn from D and E as centers intersecting at point F. The ray BF is the bisector of angle ABC as triangles BEF and BDF have been proven congruent using side-side-side and corresponding parts of congruent triangles properties.

1. Made by : T.Pratap
class : Ixth ‘c’
Roll no: 21

2. Construction 11.1:to construct the
bisector of an angle ABC
• Steps to construct :
• Taking B as centre and any radius, draw an arc to intersect the
rays BA and BC, say at E and D respectively
• Next, taking D and E as centers and with the radius more than
½ DE, draw arcs to intersect each other, say at F.
• Draw the ray BF this ray BF is the required bisector of the angle
ABC.

3. • In triangles BEF and BDF,
• BE = BD (Radii of the same arc)
• EF = DF (Arcs of equal radii)
• BF = BF (Common)
• Therefore, BEF = BDF (SSS rule)
• This gives EBF = DBF (CPCT)