natural logs - exponential modelling
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1. The population will take 29.4 years to double based on the given growth rate of 2.36% per year and original population of 76,504,077. 2. Plugging the values into the exponential growth formula and taking the logarithm of both sides allows you to isolate the time variable. 3. The population will reach 80,000,000 in 1.9 years based on the same growth rate and original population starting value.
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The expansion of AI services necessitates enhanced computational capabilities on edge devices. Temporal Event Neural Networks (TENNs), developed by BrainChip, represent a novel and highly efficient state-space network. TENNs demonstrate exceptional proficiency in handling multi-dimensional streaming data, facilitating advancements in object detection, action recognition, speech enhancement and language model/sequence generation. Through the utilization of polynomial-based continuous convolutions, TENNs streamline models, expedite training processes and significantly diminish memory requirements, achieving notable reductions of up to 50x in parameters and 5,000x in energy consumption compared to prevailing methodologies like transformers.
Integration with BrainChip’s Akida neuromorphic hardware IP further enhances TENNs’ capabilities, enabling the realization of highly capable, portable and passively cooled edge devices. This presentation delves into the technical innovations underlying TENNs, presents real-world benchmarks, and elucidates how this cutting-edge approach is positioned to revolutionize edge AI across diverse applications.Skybuffer SAM4U tool for SAP license adoption
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Main news related to the CCS TSI 2023 (2023/1695)
An English 🇬🇧 translation of a presentation to the speech I gave about the main changes brought by CCS TSI 2023 at the biggest Czech conference on Communications and signalling systems on Railways, which was held in Clarion Hotel Olomouc from 7th to 9th November 2023 (konferenceszt.cz). Attended by around 500 participants and 200 on-line followers.
The original Czech 🇨🇿 version of the presentation can be found here: https://www.slideshare.net/slideshow/hlavni-novinky-souvisejici-s-ccs-tsi-2023-2023-1695/269688092 .
The videorecording (in Czech) from the presentation is available here: https://youtu.be/WzjJWm4IyPk?si=SImb06tuXGb30BEH .
zkStudyClub - LatticeFold: A Lattice-based Folding Scheme and its Application...
Folding is a recent technique for building efficient recursive SNARKs. Several elegant folding protocols have been proposed, such as Nova, Supernova, Hypernova, Protostar, and others. However, all of them rely on an additively homomorphic commitment scheme based on discrete log, and are therefore not post-quantum secure. In this work we present LatticeFold, the first lattice-based folding protocol based on the Module SIS problem. This folding protocol naturally leads to an efficient recursive lattice-based SNARK and an efficient PCD scheme. LatticeFold supports folding low-degree relations, such as R1CS, as well as high-degree relations, such as CCS. The key challenge is to construct a secure folding protocol that works with the Ajtai commitment scheme. The difficulty, is ensuring that extracted witnesses are low norm through many rounds of folding. We present a novel technique using the sumcheck protocol to ensure that extracted witnesses are always low norm no matter how many rounds of folding are used. Our evaluation of the final proof system suggests that it is as performant as Hypernova, while providing post-quantum security.
Paper Link: https://eprint.iacr.org/2024/257
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natural logs - exponential modelling
- 1. a.) Calculate how many years the population will take to double. Given: P = 2Po = 153 008 154 Total Population when doubled Po = 76 504 077 Original Population Rate per year r = 2.36 % or 0.0236 t = ? Years The formula we are using is.. rt P = Poe 1
- 2. First, plug in the given values to the equation. rt P = Poe 153 008 154 = 76 504 077 e(0.0236)t 1 Then reduce both sides by multiplying 76 504 077 ( ) ( ) 1 1 153 008 154 = 76 504 077 e(0.0236)t 76 504 077 76 504 077 2 = e(0.0236)t 2
- 3. Find the ln of both sides. ln e will reduced since it means the same thing. ln 2 = 0.0236t 1 Isolate t by multiplying 0.0236 ) ) ( ( 1 1 ln 2 = 0.0236t 0.0236 0.0236 ln 2 = t 0.0236 29.4 years = t 3
- 4. b.) Calculate when the population will reach 80 000 000. Given: P = 2Po = 153 008 154 Total Population when doubled Po = 76 504 077 Original Population Rate per year r = 2.36 % or 0.0236 t = ? Years The formula we are using is.. P = Poert 4
- 5. First, plug in the given values to the equation. P = Poert 80 000 000 = 76 504 077 e(0.0236)t 1 Then reduced both sides by multiplying 76 504 077 ( ) ( ) 1 1 (0.0236)t 80 000 000 = 76 504 077 e 76 504 077 76 504 077 1.045695905 = e(0.0236)t 5
- 6. Find the ln of both sides. ln e will reduced since it means the same thing. ln ( 1.045695905) = 0.0236t 1 Isolate t by multiplying 0.0236 ) ) ( ( 1 1 ln ( 1.045695905) = 0.0236t 0.0236 0.0236 ln (1.045695905) = t (0.0236) 1.9 years = t 6