MonsterAttack.javapublic class MonsterAttack { int id; .pdf
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// MonsterAttack.java public class MonsterAttack { int id; int day, month, year; String nameOfMonster; String location; int numOfVictims; public MonsterAttack(int id, String date, String nameOfMonster, String location, int numOfVictims) { String arr[] = date.split(\"/\"); this.id = id; this.day = Integer.parseInt(arr[1]); this.month = Integer.parseInt(arr[0]); this.year = Integer.parseInt(arr[2]); this.nameOfMonster = nameOfMonster; this.location = location; this.numOfVictims = numOfVictims; } int getId() { return id; } void setId(int id) { this.id = id; } String getNameOfMonster() { return nameOfMonster; } void setNameOfMonster(String nameOfMonster) { this.nameOfMonster = nameOfMonster; } String getLocation() { return location; } void setLocation(String location) { this.location = location; } int getNumOfVictims() { return numOfVictims; } void setNumOfVictims(int numOfVictims) { this.numOfVictims = numOfVictims; } String getDate(){ return month + \"/\" + day + \"/\" + year; } void setDate(String date){ String arr[] = date.split(\"/\"); this.day = Integer.parseInt(arr[1]); this.month = Integer.parseInt(arr[0]); this.year = Integer.parseInt(arr[2]); } public String toString(){ return \"Attack # \" + id + \"occurred on \" + getDate() + \". \" + nameOfMonster + \"attacked \" + location + \", resulting in \" + numOfVictims + \" tragic fatalities.\"; } } // AttackMonitor.java import java.util.ArrayList; import javax.swing.JOptionPane; public class AttackMonitor{ ArrayList attacks = new ArrayList(); void input(){ String nameOfMonster, location, date; int id, numOfVictims; nameOfMonster = JOptionPane.showInputDialog(\"Enter the name of the monster\"); location = JOptionPane.showInputDialog(\"Enter the location of attack\"); date = JOptionPane.showInputDialog(\"Enter the date of attack\"); id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id of attack\")); numOfVictims = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the number of victims\")); MonsterAttack temp = new MonsterAttack(id, date, nameOfMonster, location, numOfVictims); attacks.add(temp); } void display(){ for(int i = 0; i < attacks.size(); i++){ System.out.println(attacks.get(i)); } } void delete(){ display(); int id = Integer.parseInt(JOptionPane.showInputDialog(\"Enter the id of attack to delete\")); int i; for(i = 0; i < attacks.size(); i++){ if(attacks.get(i).getId() == id){ break; } } if(i != attacks.size()) attacks.remove(i); } void monitor(){ int choice = Integer.parseInt(JOptionPane.showInputDialog(\"Enter 1 for adding new attack, 2 for displaying attacks, 3 for deleting an attack, any other number to exit\")); switch (choice) { case 1: input(); break; case 2: display(); break; case 3: delete(); break; default: return; } } } // MonsterAttackDriver.java Give sample input/output ot input file Solution // MonsterAttack.java public class MonsterAttack { int id; int day, month, year; String nameOfMonster; String location; int numOfVictims; public MonsterAttack(int id,.
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![// MonsterAttack.java
public class MonsterAttack {
int id;
int day, month, year;
String nameOfMonster;
String location;
int numOfVictims;
public MonsterAttack(int id, String date, String nameOfMonster, String location, int
numOfVictims) {
String arr[] = date.split("/");
this.id = id;
this.day = Integer.parseInt(arr[1]);
this.month = Integer.parseInt(arr[0]);
this.year = Integer.parseInt(arr[2]);
this.nameOfMonster = nameOfMonster;
this.location = location;
this.numOfVictims = numOfVictims;
}
int getId() {
return id;
}
void setId(int id) {
this.id = id;
}
String getNameOfMonster() {
return nameOfMonster;
}
void setNameOfMonster(String nameOfMonster) {
this.nameOfMonster = nameOfMonster;
}
String getLocation() {
return location;
}
void setLocation(String location) {
this.location = location;](https://image.slidesharecdn.com/monsterattack-230413072516-60a8baf0/85/MonsterAttack-javapublic-class-MonsterAttack-int-id-pdf-1-320.jpg)
![}
int getNumOfVictims() {
return numOfVictims;
}
void setNumOfVictims(int numOfVictims) {
this.numOfVictims = numOfVictims;
}
String getDate(){
return month + "/" + day + "/" + year;
}
void setDate(String date){
String arr[] = date.split("/");
this.day = Integer.parseInt(arr[1]);
this.month = Integer.parseInt(arr[0]);
this.year = Integer.parseInt(arr[2]);
}
public String toString(){
return "Attack # " + id + "occurred on " + getDate() + ". " + nameOfMonster +
"attacked " + location + ", resulting in " + numOfVictims + " tragic fatalities.";
}
}
// AttackMonitor.java
import java.util.ArrayList;
import javax.swing.JOptionPane;
public class AttackMonitor{
ArrayList attacks = new ArrayList();
void input(){
String nameOfMonster, location, date;
int id, numOfVictims;
nameOfMonster = JOptionPane.showInputDialog("Enter the name of the monster");
location = JOptionPane.showInputDialog("Enter the location of attack");
date = JOptionPane.showInputDialog("Enter the date of attack");
id = Integer.parseInt(JOptionPane.showInputDialog("Enter the id of attack"));
numOfVictims = Integer.parseInt(JOptionPane.showInputDialog("Enter the number of
victims"));](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
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Consider the classes below- Here is the code for the ParentChildRelati.pdf
Consider the classes below:
Here is the code for the ParentChildRelation class:
import java.util.Date;
import java.util.Map;
public class ParentChildRelation {
private int rec_id;
private String name;
private Date startDate;
private Date endDate;
private Map<String, Integer> childData;
public int getRec_id() {
return rec_id;
}
public void setRec_id(int rec_id) {
this.rec_id = rec_id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Date getStartDate() {
return startDate;
}
public void setStartDate(Date startDate) {
this.startDate = startDate;
}
public Date getEndDate() {
return endDate;
}
public void setEndDate(Date endDate) {
this.endDate = endDate;
}
public Map<String, Integer> getChildData() {
return childData;
}
public void setChildData(Map<String, Integer> childData) {
this.childData = childData;
}
}
Here is the code for the Service class:
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Date;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class ParentChildRelationService {
private List<ParentChildRelation> parentChildRelationList;
public void init() {
parentChildRelationList = new ArrayList<>();
// Adding records for Unit01
ParentChildRelation unit01Record1 = new ParentChildRelation();
unit01Record1.setRec_id(1001);
unit01Record1.setName("Unit01");
DateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy");
try {
Date startDate = dateFormat.parse("01-01-2023");
Date endDate = dateFormat.parse("31-01-2023");
unit01Record1.setStartDate(startDate);
unit01Record1.setEndDate(endDate);
} catch (Exception e) {
e.printStackTrace();
}
Map<String, Integer> unit01Record1ChildData = new HashMap<>();
unit01Record1ChildData.put("key1", 83);
unit01Record1ChildData.put("key2", 65);
unit01Record1ChildData.put("key3", 96);
unit01Record1ChildData.put("key4", 45);
unit01Record1ChildData.put("key5", 25);
unit01Record1ChildData.put("key6", 98);
unit01Record1ChildData.put("key7", 45);
unit01Record1.setChildData(unit01Record1ChildData);
parentChildRelationList.add(unit01Record1);
ParentChildRelation unit01Record2 = new ParentChildRelation();
unit01Record2.setRec_id(1002);
unit01Record2.setName("Unit01");
try {
Date startDate = dateFormat.parse("01-02-2023");
Date endDate = dateFormat.parse("28-02-2023");
unit01Record2.setStartDate(startDate);
unit01Record2.setEndDate(endDate);
} catch (Exception e) {
e.printStackTrace();
}
Map<String, Integer> unit01Record2ChildData = new HashMap<>();
unit01Record2ChildData.put("key1", 45);
unit01Record2ChildData.put("key2", 98);
unit01Record2ChildData.put("key3", 25);
unit01Record2ChildData.put("key4", 36);
unit01Record2ChildData.put("key5", 95);
unit01Record2ChildData.put("key6", 83);
unit01Record2ChildData.put("key7", 65);
unit01Record2.setChildData(unit01Record2ChildData);
parentChildRelationList.add(unit01Record2);
// Adding records for Unit02
ParentChildRelation unit02Record1 .
Date.h#ifndef DateFormat#define DateFormat#includetime.h.pdf
//Date.h
#ifndef DateFormat
#define DateFormat
#include
#include
class Date {
public:
Date();
Date(int, int);
Date(int, int, int);
Date(char *, int, int);
voidsetMonth(int);
voidsetDay(int);
voidsetYear(int);
voidprintDateSlash(void) const;
voidprintDateMonth(void) const;
voidprintDateDay(void) const;
constchar *monthName(void) const;
intleapYear(void) const;
intdaysOfMonth(void) const;
voidchange(int);
intchange1(void) const;
voidchange2(constchar * const);
constchar *monthList(int) const;
intdays(int) const;
private:
int day;
int month;
int year;
};
class main {
public:
main();
virtual~main();
};
#endif
//Date.cpp
#include\"stdafx.h\"
#include
#include
#include
#include \"Date.h\"
Date::Date()
{
struct tm *ptr;
time_t t = time( 0 );
ptr = localtime( &t );
day = ptr->tm_mday;
month = 1 + ptr->tm_mon;
year = ptr->tm_year + 1900;
}
Date::Date( int ss, int ppp )
{
setYear( ppp );
change(ss);
}
Date::Date( int mm, int day1, int yy )
{
setYear( yy + 1900 );
setMonth( mm );
setDay(day1);
}
Date::Date( char *mPtr, int day1, int ppp )
{
setYear( ppp );
change2( mPtr );
setDay(day1);
}
voidDate::setDay( int d1 )
{ day = d1 >= 1 && d1 <= daysOfMonth() ? d1 : 1; }
voidDate::setMonth( int m ) { month = m >= 1 && m <= 12 ? m : 1; }
voidDate::setYear( int y ) { year = y >= 1900 && y <= 1999 ? y : 1900; }
voidDate::printDateSlash( void ) const
{
cout<< month << \'/\' << day << \'/\' << year << \'\ \'; }
voidDate::printDateMonth( void ) const
{
cout << monthName() << \' \' << day << \", \" << year << \'\ \'; }
voidDate::printDateDay( void ) const
{
cout << convert2() << \' \' << year << \'\ \'; }
constchar *Date::monthName( void ) const { return monthList( month - 1 ); }
intDate::daysOfMonth( void ) const
{ return leapYear() && month == 2 ? 29 : days( month ); }
intDate::leapYear( void ) const
{
if ( year % 400 == 0 || ( year % 4 == 0 && year % 100 != 0 ) )
return 1;
else
return 0;
}
voidDate::convert1( int ss )
{
int dayTotal = 0;
if ( ss < 1 || ss > 366 )
ss = 1;
setMonth( 1 );
for ( int m = 1; m < 13 && ( dayTotal + daysOfMonth() ) < ss; ++m ) {
dayTotal += daysOfMonth();
setMonth( m + 1 );
}
setDay( ss - dayTotal );
setMonth( m );
}
intDate::change1( void ) const
{
int ss = 0;
for ( int m = 1; m < month; ++m )
ss += days( m );
ss += day;
return ss;
}
voidDate::change2( constchar * const mPtr )
{
int flag = 0;
for ( int subscript = 0; subscript < 12; ++subscript )
if (!strcmp( mPtr, monthList( subscript ) ) ) {
setMonth( subscript + 1 );
flag = 1;
break;
}
if ( !flag )
setMonth( 1 );
}
constchar *Date::monthList( int mm ) const
{
char *months[] = { \"January\", \"February\", \"March\", \"April\", \"May\",
\"June\", \"July\", \"August\", \"September\", \"October\",
\"November\", \"December\" };
return months[ mm ];
}
intDate::days( int m ) const
{
constint monthDays[] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
return monthDays[ m - 1 ];
}
//main.cpp
#include \"Date.h\"
#include
using sts::cout
using std::endl
#include
#include
#include \"p7_07..
Overview You are tasked with writing a program called Social Security.pdf
Overview You are tasked with writing a program called Social Security that prompts the user to
enter the data (name and date-ofbirth)for a collection of people. The program will then process
this collection (array) of People (objects we create in another file) to determine who qualifies for
Social Security benefits. Specifications For our Social Security program we will need two java
files 1. Person java The person class which stores the data for a specific individual 2.
SocialSecurity.java (The driver) Details for these two class files appear below. Person ava UML
diagram name: String birthdate: LocalDate Person0 Person (newName: String, month: int, day:
int, year: int) NetName newName: String) void getName(): String set BirthDate month int, day:
int, year int) void get BirthDate 0 LocalDate toString(): String calculate Age(myBirth
LocalDate) int Person ava method description Two constructors 1. A Default constructor that
creates a Person whose name and birthdate are set to null. 2. A parameterized constructor that
accepts a String representation of the name, and three integers corresponding to the month, day,
and year in which the person was born. Setters and getters for the two instance variables. A
toString0 method that prints the person in the form dob
Solution
import java.time.LocalDate;
import java.time.Period;
import java.time.format.DateTimeFormatter;
import java.util.Scanner;
class Person {
String name;
LocalDate birthdate;
public Person() {
super();
}
public Person(String name, int month, int day, int year) {
super();
this.name = name;
this.birthdate = LocalDate.of(year, month, day);
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public LocalDate getBirthdate() {
return birthdate;
}
public void setBirthdate(int month, int day, int year) {
this.birthdate = LocalDate.of(year, month, day);
}
@Override
public String toString() {
DateTimeFormatter formatter = DateTimeFormatter.ofPattern(\"MM/dd/yyyy\");
birthdate.format(formatter);
return \"Person [name=\" + name + \", birthdate=\" + birthdate + \"]\";
}
public int calculateAge() {
return Period.between(birthdate, LocalDate.now()).getYears();
}
public void qualifySSN() {
if(this.calculateAge()>66)
System.out.println(\"Qualifies for Social Security Benifits\");
else
System.out.println(\"Doesnot qualifies for Social Security Benefits\");
}
}
public class SocialSecurity {
public static void main(String[] args) {
if (args.length > 1)
System.out.println(\"Invalid number of command line arguments\");
int num = Integer.parseInt(args[0]);
Person[] p = new Person[num];
Scanner in = new Scanner(System.in).useDelimiter(\"\\\ \");
;
for (int i = 0; i < num; i++) {
System.out.println(\"enter persons name\");
String name = in.next();
System.out.println(\"enter date of birth in the format Month Day Year\");
String dob = in.next();
String[] temp = dob.split(\" \");
p[i] = new Person(name, Integer.parseInt(temp[0]), Integer.parseInt(temp[1]),
Integer.pa.
srcArtifact.javasrcArtifact.javaclassArtifactextendsCave{pub.docx
src/Artifact.javasrc/Artifact.javaclassArtifactextendsCave{
publicint creatureIndex =0;
publicArtifact(int index,String type,int creatureIndex){
super(type, index);
this.creatureIndex = creatureIndex;
}
@Override
publicString toString(){
// Return neater output of the class data
return"[Artifact]: \n\tOwner Index = "
+Integer.toString(this.creatureIndex)
+" \n\tArtifact Type = "+this.type;
}
}
src/Cave.javasrc/Cave.javapublicclassCave{
publicint index =0;
publicString type =null;
publicString name =null;
/***
* Constructor
* @param index
*/
publicCave(int index){
this.index = index;
}
publicCave(int index,String type,String name){
this.index = index;
this.type = type;
this.name = name;
}
publicCave(int index,String name){
this.index = index;
this.name = name;
}
publicCave(String type,int index){
this.index = index;
this.type = type;
}
}
src/Creature.javasrc/Creature.javaimport java.awt.BorderLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.ArrayList;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JOptionPane;
import javax.swing.JPanel;
import javax.swing.JProgressBar;
classCreatureextendsCaveimplementsActionListener,Runnable{
publicint partyIndex =0;
publicint empathyValue;
publicint fearValue;
publicdouble carryingCapacity;
publicint age;
publicint weight;
publicdouble height;
publicArrayList<Treasure> treasures =newArrayList<Treasure>();
publicArrayList<Artifact> artifacts =newArrayList<Artifact>();
publicArrayList<Jobs> jobs =newArrayList<Jobs>();
publiclong jobTime =0;
publicJobs currentJob =null;
publicvolatileboolean runJob =false;
publicvolatileboolean cancelJob =false;
JButton cancelButton =newJButton("Cancel Job");
JButton startButton =newJButton("Start Job");
publicCreature(int index,String type,String name,int partyIndex,
int empathyValue,int fearValue,double carryingCapacity){
super(index, type, name);
this.partyIndex = partyIndex;
this.empathyValue = empathyValue;
this.fearValue = fearValue;
this.carryingCapacity = carryingCapacity;
}
publicCreature(int index,String type,String name,int partyIndex,
int empathyValue,int fearValue,double carryingCapacity,int age,
int weight,double height){
super(index, type, name);
this.partyIndex = partyIndex;
this.empathyValue = empathyValue;
this.fearValue = fearValue;
this.carryingCapacity = carryingCapacity;
this.age = age;
this.weight = weight;
this.height = height;
}
publicvoid addTreature(Treasure t){
if(t !=null&& t instanceofTreasure&& t.creatureIndex !=0){
this.treasures.add(t);
}
}
publicvoid addArtifact(Artifact a){
if(a !=null&& a instanceofArtifact&& a.creatureIndex !=0){
this.artifacts.add(a);
}
}
@Override
publicString toString(){
String output ="";
output +="[Creature]: \n\tType = "+this.type +" \n\tName = "
+this.name +" \n\tParty Index = "
+Integer.toString(this.partyIndex)+" \n\tEmpathy Value = "
+Integer.toString(this.empathyV.
Ast transformations
AST Transformations presentation from JavaZone. Covers: Project Lombok, Groovy AST Transformations, Spock (a little), and Mirah.
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Consider the classes below- Here is the code for the ParentChildRelati.pdf
Consider the classes below:
Here is the code for the ParentChildRelation class:
import java.util.Date;
import java.util.Map;
public class ParentChildRelation {
private int rec_id;
private String name;
private Date startDate;
private Date endDate;
private Map<String, Integer> childData;
public int getRec_id() {
return rec_id;
}
public void setRec_id(int rec_id) {
this.rec_id = rec_id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Date getStartDate() {
return startDate;
}
public void setStartDate(Date startDate) {
this.startDate = startDate;
}
public Date getEndDate() {
return endDate;
}
public void setEndDate(Date endDate) {
this.endDate = endDate;
}
public Map<String, Integer> getChildData() {
return childData;
}
public void setChildData(Map<String, Integer> childData) {
this.childData = childData;
}
}
Here is the code for the Service class:
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Date;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class ParentChildRelationService {
private List<ParentChildRelation> parentChildRelationList;
public void init() {
parentChildRelationList = new ArrayList<>();
// Adding records for Unit01
ParentChildRelation unit01Record1 = new ParentChildRelation();
unit01Record1.setRec_id(1001);
unit01Record1.setName("Unit01");
DateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy");
try {
Date startDate = dateFormat.parse("01-01-2023");
Date endDate = dateFormat.parse("31-01-2023");
unit01Record1.setStartDate(startDate);
unit01Record1.setEndDate(endDate);
} catch (Exception e) {
e.printStackTrace();
}
Map<String, Integer> unit01Record1ChildData = new HashMap<>();
unit01Record1ChildData.put("key1", 83);
unit01Record1ChildData.put("key2", 65);
unit01Record1ChildData.put("key3", 96);
unit01Record1ChildData.put("key4", 45);
unit01Record1ChildData.put("key5", 25);
unit01Record1ChildData.put("key6", 98);
unit01Record1ChildData.put("key7", 45);
unit01Record1.setChildData(unit01Record1ChildData);
parentChildRelationList.add(unit01Record1);
ParentChildRelation unit01Record2 = new ParentChildRelation();
unit01Record2.setRec_id(1002);
unit01Record2.setName("Unit01");
try {
Date startDate = dateFormat.parse("01-02-2023");
Date endDate = dateFormat.parse("28-02-2023");
unit01Record2.setStartDate(startDate);
unit01Record2.setEndDate(endDate);
} catch (Exception e) {
e.printStackTrace();
}
Map<String, Integer> unit01Record2ChildData = new HashMap<>();
unit01Record2ChildData.put("key1", 45);
unit01Record2ChildData.put("key2", 98);
unit01Record2ChildData.put("key3", 25);
unit01Record2ChildData.put("key4", 36);
unit01Record2ChildData.put("key5", 95);
unit01Record2ChildData.put("key6", 83);
unit01Record2ChildData.put("key7", 65);
unit01Record2.setChildData(unit01Record2ChildData);
parentChildRelationList.add(unit01Record2);
// Adding records for Unit02
ParentChildRelation unit02Record1 .
Date.h#ifndef DateFormat#define DateFormat#includetime.h.pdf
//Date.h
#ifndef DateFormat
#define DateFormat
#include
#include
class Date {
public:
Date();
Date(int, int);
Date(int, int, int);
Date(char *, int, int);
voidsetMonth(int);
voidsetDay(int);
voidsetYear(int);
voidprintDateSlash(void) const;
voidprintDateMonth(void) const;
voidprintDateDay(void) const;
constchar *monthName(void) const;
intleapYear(void) const;
intdaysOfMonth(void) const;
voidchange(int);
intchange1(void) const;
voidchange2(constchar * const);
constchar *monthList(int) const;
intdays(int) const;
private:
int day;
int month;
int year;
};
class main {
public:
main();
virtual~main();
};
#endif
//Date.cpp
#include\"stdafx.h\"
#include
#include
#include
#include \"Date.h\"
Date::Date()
{
struct tm *ptr;
time_t t = time( 0 );
ptr = localtime( &t );
day = ptr->tm_mday;
month = 1 + ptr->tm_mon;
year = ptr->tm_year + 1900;
}
Date::Date( int ss, int ppp )
{
setYear( ppp );
change(ss);
}
Date::Date( int mm, int day1, int yy )
{
setYear( yy + 1900 );
setMonth( mm );
setDay(day1);
}
Date::Date( char *mPtr, int day1, int ppp )
{
setYear( ppp );
change2( mPtr );
setDay(day1);
}
voidDate::setDay( int d1 )
{ day = d1 >= 1 && d1 <= daysOfMonth() ? d1 : 1; }
voidDate::setMonth( int m ) { month = m >= 1 && m <= 12 ? m : 1; }
voidDate::setYear( int y ) { year = y >= 1900 && y <= 1999 ? y : 1900; }
voidDate::printDateSlash( void ) const
{
cout<< month << \'/\' << day << \'/\' << year << \'\ \'; }
voidDate::printDateMonth( void ) const
{
cout << monthName() << \' \' << day << \", \" << year << \'\ \'; }
voidDate::printDateDay( void ) const
{
cout << convert2() << \' \' << year << \'\ \'; }
constchar *Date::monthName( void ) const { return monthList( month - 1 ); }
intDate::daysOfMonth( void ) const
{ return leapYear() && month == 2 ? 29 : days( month ); }
intDate::leapYear( void ) const
{
if ( year % 400 == 0 || ( year % 4 == 0 && year % 100 != 0 ) )
return 1;
else
return 0;
}
voidDate::convert1( int ss )
{
int dayTotal = 0;
if ( ss < 1 || ss > 366 )
ss = 1;
setMonth( 1 );
for ( int m = 1; m < 13 && ( dayTotal + daysOfMonth() ) < ss; ++m ) {
dayTotal += daysOfMonth();
setMonth( m + 1 );
}
setDay( ss - dayTotal );
setMonth( m );
}
intDate::change1( void ) const
{
int ss = 0;
for ( int m = 1; m < month; ++m )
ss += days( m );
ss += day;
return ss;
}
voidDate::change2( constchar * const mPtr )
{
int flag = 0;
for ( int subscript = 0; subscript < 12; ++subscript )
if (!strcmp( mPtr, monthList( subscript ) ) ) {
setMonth( subscript + 1 );
flag = 1;
break;
}
if ( !flag )
setMonth( 1 );
}
constchar *Date::monthList( int mm ) const
{
char *months[] = { \"January\", \"February\", \"March\", \"April\", \"May\",
\"June\", \"July\", \"August\", \"September\", \"October\",
\"November\", \"December\" };
return months[ mm ];
}
intDate::days( int m ) const
{
constint monthDays[] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
return monthDays[ m - 1 ];
}
//main.cpp
#include \"Date.h\"
#include
using sts::cout
using std::endl
#include
#include
#include \"p7_07..
Overview You are tasked with writing a program called Social Security.pdf
Overview You are tasked with writing a program called Social Security that prompts the user to
enter the data (name and date-ofbirth)for a collection of people. The program will then process
this collection (array) of People (objects we create in another file) to determine who qualifies for
Social Security benefits. Specifications For our Social Security program we will need two java
files 1. Person java The person class which stores the data for a specific individual 2.
SocialSecurity.java (The driver) Details for these two class files appear below. Person ava UML
diagram name: String birthdate: LocalDate Person0 Person (newName: String, month: int, day:
int, year: int) NetName newName: String) void getName(): String set BirthDate month int, day:
int, year int) void get BirthDate 0 LocalDate toString(): String calculate Age(myBirth
LocalDate) int Person ava method description Two constructors 1. A Default constructor that
creates a Person whose name and birthdate are set to null. 2. A parameterized constructor that
accepts a String representation of the name, and three integers corresponding to the month, day,
and year in which the person was born. Setters and getters for the two instance variables. A
toString0 method that prints the person in the form dob
Solution
import java.time.LocalDate;
import java.time.Period;
import java.time.format.DateTimeFormatter;
import java.util.Scanner;
class Person {
String name;
LocalDate birthdate;
public Person() {
super();
}
public Person(String name, int month, int day, int year) {
super();
this.name = name;
this.birthdate = LocalDate.of(year, month, day);
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public LocalDate getBirthdate() {
return birthdate;
}
public void setBirthdate(int month, int day, int year) {
this.birthdate = LocalDate.of(year, month, day);
}
@Override
public String toString() {
DateTimeFormatter formatter = DateTimeFormatter.ofPattern(\"MM/dd/yyyy\");
birthdate.format(formatter);
return \"Person [name=\" + name + \", birthdate=\" + birthdate + \"]\";
}
public int calculateAge() {
return Period.between(birthdate, LocalDate.now()).getYears();
}
public void qualifySSN() {
if(this.calculateAge()>66)
System.out.println(\"Qualifies for Social Security Benifits\");
else
System.out.println(\"Doesnot qualifies for Social Security Benefits\");
}
}
public class SocialSecurity {
public static void main(String[] args) {
if (args.length > 1)
System.out.println(\"Invalid number of command line arguments\");
int num = Integer.parseInt(args[0]);
Person[] p = new Person[num];
Scanner in = new Scanner(System.in).useDelimiter(\"\\\ \");
;
for (int i = 0; i < num; i++) {
System.out.println(\"enter persons name\");
String name = in.next();
System.out.println(\"enter date of birth in the format Month Day Year\");
String dob = in.next();
String[] temp = dob.split(\" \");
p[i] = new Person(name, Integer.parseInt(temp[0]), Integer.parseInt(temp[1]),
Integer.pa.
srcArtifact.javasrcArtifact.javaclassArtifactextendsCave{pub.docx
src/Artifact.javasrc/Artifact.javaclassArtifactextendsCave{
publicint creatureIndex =0;
publicArtifact(int index,String type,int creatureIndex){
super(type, index);
this.creatureIndex = creatureIndex;
}
@Override
publicString toString(){
// Return neater output of the class data
return"[Artifact]: \n\tOwner Index = "
+Integer.toString(this.creatureIndex)
+" \n\tArtifact Type = "+this.type;
}
}
src/Cave.javasrc/Cave.javapublicclassCave{
publicint index =0;
publicString type =null;
publicString name =null;
/***
* Constructor
* @param index
*/
publicCave(int index){
this.index = index;
}
publicCave(int index,String type,String name){
this.index = index;
this.type = type;
this.name = name;
}
publicCave(int index,String name){
this.index = index;
this.name = name;
}
publicCave(String type,int index){
this.index = index;
this.type = type;
}
}
src/Creature.javasrc/Creature.javaimport java.awt.BorderLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.ArrayList;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JOptionPane;
import javax.swing.JPanel;
import javax.swing.JProgressBar;
classCreatureextendsCaveimplementsActionListener,Runnable{
publicint partyIndex =0;
publicint empathyValue;
publicint fearValue;
publicdouble carryingCapacity;
publicint age;
publicint weight;
publicdouble height;
publicArrayList<Treasure> treasures =newArrayList<Treasure>();
publicArrayList<Artifact> artifacts =newArrayList<Artifact>();
publicArrayList<Jobs> jobs =newArrayList<Jobs>();
publiclong jobTime =0;
publicJobs currentJob =null;
publicvolatileboolean runJob =false;
publicvolatileboolean cancelJob =false;
JButton cancelButton =newJButton("Cancel Job");
JButton startButton =newJButton("Start Job");
publicCreature(int index,String type,String name,int partyIndex,
int empathyValue,int fearValue,double carryingCapacity){
super(index, type, name);
this.partyIndex = partyIndex;
this.empathyValue = empathyValue;
this.fearValue = fearValue;
this.carryingCapacity = carryingCapacity;
}
publicCreature(int index,String type,String name,int partyIndex,
int empathyValue,int fearValue,double carryingCapacity,int age,
int weight,double height){
super(index, type, name);
this.partyIndex = partyIndex;
this.empathyValue = empathyValue;
this.fearValue = fearValue;
this.carryingCapacity = carryingCapacity;
this.age = age;
this.weight = weight;
this.height = height;
}
publicvoid addTreature(Treasure t){
if(t !=null&& t instanceofTreasure&& t.creatureIndex !=0){
this.treasures.add(t);
}
}
publicvoid addArtifact(Artifact a){
if(a !=null&& a instanceofArtifact&& a.creatureIndex !=0){
this.artifacts.add(a);
}
}
@Override
publicString toString(){
String output ="";
output +="[Creature]: \n\tType = "+this.type +" \n\tName = "
+this.name +" \n\tParty Index = "
+Integer.toString(this.partyIndex)+" \n\tEmpathy Value = "
+Integer.toString(this.empathyV.
Ast transformations
AST Transformations presentation from JavaZone. Covers: Project Lombok, Groovy AST Transformations, Spock (a little), and Mirah.
X has +2 charge It has low first and second ioniz.pdf
X has +2 charge It has low first and second ionization energies. Hence it can give 2
electrons easily. Hence it will have +2 charge Y has larger ionization energy than X Hence atom
of Y is smaller than that of X(Same group)
Solution
X has +2 charge It has low first and second ionization energies. Hence it can give 2
electrons easily. Hence it will have +2 charge Y has larger ionization energy than X Hence atom
of Y is smaller than that of X(Same group).
Valence Bond Theory According to valence band the.pdf
Valence Bond Theory According to valence band theory a covalent bond is formed
between the two atoms by the overlap of half filled valence atomic orbitals of each atom
containing one unpaired electron. Valence bond theory considers that the overlapping atomic
orbitals of the participating atoms form a chemical bond. Because of the overlapping, it is most
probable that electrons should be in the bond region. Valence bond theory views bonds as
weakly coupled orbitals (small overlap). Valence bond theory is typically easier to employ in
ground state molecules. Hybridization It is the concept of mixing atomic orbitals to form new
hybrid orbitals suitable for the qualitative description of atomic bonding properties. Hybridised
orbitals are very useful in the explanation of the shape of molecular orbitals for molecules. It is
an integral part of valence bond theory. Molecular orbital theory molecular orbital (MO) theory
is a method for determining molecular structure in which electrons are not assigned to individual
bonds between atoms, but are treated as moving under the influence of the nuclei in the whole
molecule. In this theory, each molecule has a set of molecular orbitals, in which it is assumed
that the molecular orbital wave function ?f may be written as a simple weighted sum of the n
constituent atomic orbitals ?i Metallic Bonding Metallic bonding is the electrostatic attractive
forces between the delocalized electrons, called conduction electrons, gathered in an \"electron
sea\", and the positively charged metal ions.
Solution
Valence Bond Theory According to valence band theory a covalent bond is formed
between the two atoms by the overlap of half filled valence atomic orbitals of each atom
containing one unpaired electron. Valence bond theory considers that the overlapping atomic
orbitals of the participating atoms form a chemical bond. Because of the overlapping, it is most
probable that electrons should be in the bond region. Valence bond theory views bonds as
weakly coupled orbitals (small overlap). Valence bond theory is typically easier to employ in
ground state molecules. Hybridization It is the concept of mixing atomic orbitals to form new
hybrid orbitals suitable for the qualitative description of atomic bonding properties. Hybridised
orbitals are very useful in the explanation of the shape of molecular orbitals for molecules. It is
an integral part of valence bond theory. Molecular orbital theory molecular orbital (MO) theory
is a method for determining molecular structure in which electrons are not assigned to individual
bonds between atoms, but are treated as moving under the influence of the nuclei in the whole
molecule. In this theory, each molecule has a set of molecular orbitals, in which it is assumed
that the molecular orbital wave function ?f may be written as a simple weighted sum of the n
constituent atomic orbitals ?i Metallic Bonding Metallic bonding is the electrostatic attractive
forces between the delocalized e.
total volume =25+25=50 ml total millimoles of KI=.pdf
total volume =25+25=50 ml total millimoles of KI=25*0.2=5
conce=millimoles/volume in ml =5/50=0.1 similarly for other compound 25*0.2/50=0.1
Solution
total volume =25+25=50 ml total millimoles of KI=25*0.2=5
conce=millimoles/volume in ml =5/50=0.1 similarly for other compound 25*0.2/50=0.1.
This type of deformation is irreversible. However.pdf
This type of deformation is irreversible. However, an object in the plastic
deformation range will first have undergone elastic deformation, which is reversible, so the
object will return part way to its original shape
Solution
This type of deformation is irreversible. However, an object in the plastic
deformation range will first have undergone elastic deformation, which is reversible, so the
object will return part way to its original shape.
Some elements receive their respective symbol bas.pdf
Some elements receive their respective symbol based on their latin equivalence...
Ex: iron(Fe) = ferrous, lead(Pb) = plumbum, mercury(Hg) = hydrargyrum While others are
receive their symbol for where they are discovered or to the discoverer\'s home country... Ex:
Germanium (Germany), Californium (University of California) While others are named after
their founders... Ex: Einsteinium (Albert Einstein), Mendelevium (Dmitri Ivanovich Mendeleev)
When these elements are combined into compounds, there are a couple of tricks to help with
remembering them... Ex: 1. -ous compounds will generally have a lower charge than -ic
compounds 2. Hydro- compounds will have an addition of an H+ proton making the compound
an acid
Solution
Some elements receive their respective symbol based on their latin equivalence...
Ex: iron(Fe) = ferrous, lead(Pb) = plumbum, mercury(Hg) = hydrargyrum While others are
receive their symbol for where they are discovered or to the discoverer\'s home country... Ex:
Germanium (Germany), Californium (University of California) While others are named after
their founders... Ex: Einsteinium (Albert Einstein), Mendelevium (Dmitri Ivanovich Mendeleev)
When these elements are combined into compounds, there are a couple of tricks to help with
remembering them... Ex: 1. -ous compounds will generally have a lower charge than -ic
compounds 2. Hydro- compounds will have an addition of an H+ proton making the compound
an acid.
phosphonium ylide is produced when phosphonium ha.pdf
phosphonium ylide is produced when phosphonium halide salt reacts with a strong
base such as nBuLi.
Solution
phosphonium ylide is produced when phosphonium halide salt reacts with a strong
base such as nBuLi..
N1 V1 = N2 V2 50 x M1 = 1.50 x 2 x 17.7 M M1 = 1..pdf
N1 V1 = N2 V2 50 x M1 = 1.50 x 2 x 17.7 M M1 = 1.06 M
Solution
N1 V1 = N2 V2 50 x M1 = 1.50 x 2 x 17.7 M M1 = 1.06 M.
In chemistry, an amphoteric species is a molecule.pdf
In chemistry, an amphoteric species is a molecule or ion that can react as an acid as
well as a base. Zinc oxide (ZnO) reacts with both acids and with bases: In acid: ZnO + 2H+ ?
Zn2+ + H2O In base: ZnO + H2O + 2OH- ? [Zn(OH)4]2-
Solution
In chemistry, an amphoteric species is a molecule or ion that can react as an acid as
well as a base. Zinc oxide (ZnO) reacts with both acids and with bases: In acid: ZnO + 2H+ ?
Zn2+ + H2O In base: ZnO + H2O + 2OH- ? [Zn(OH)4]2-.
Chemistry is the science of matter, especially it.pdf
Chemistry is the science of matter, especially its chemical reactions, but also its
composition, structure and properties.[1][2] Chemistry is concerned with atoms and their
interactions with other atoms, and particularly with the properties of chemical bonds.
Solution
Chemistry is the science of matter, especially its chemical reactions, but also its
composition, structure and properties.[1][2] Chemistry is concerned with atoms and their
interactions with other atoms, and particularly with the properties of chemical bonds..
Before this confederates began their general advance, General Lee pl.pdf
Before this confederates began their general advance, General Lee planned to weaken any union
opposition with
(c) an artillery barrage
Solution
Before this confederates began their general advance, General Lee planned to weaken any union
opposition with
(c) an artillery barrage.
An understanding of periodic trends is important .pdf
An understanding of periodic trends is important because the trends:- 4. relate to
properties of elements and how they may react.
Solution
An understanding of periodic trends is important because the trends:- 4. relate to
properties of elements and how they may react..
Acid contains hydrogen ions. Thus, iodate will re.pdf
Acid contains hydrogen ions. Thus, iodate will react with hydrogen ion to form
iodine and water. 2IO3- + 12H+ + 10e- -> I2 + 6H2O Iodine and water will be further reduced
to form iodide ions. Thus, this will affect the titration process, thus it should be titrated
immediately. IO3- + 3H2O + 6e- -> I- + 6OH- Hope this helps!
Solution
Acid contains hydrogen ions. Thus, iodate will react with hydrogen ion to form
iodine and water. 2IO3- + 12H+ + 10e- -> I2 + 6H2O Iodine and water will be further reduced
to form iodide ions. Thus, this will affect the titration process, thus it should be titrated
immediately. IO3- + 3H2O + 6e- -> I- + 6OH- Hope this helps!.
There is a difference between to connect to a network and to communi.pdf
There is a difference between to connect to a network and to communicate over a network.
Connecting to a network requires that special hardware be installed in your computer. This
hardware is called connection devices. There are two common types of connection devices: 1-
Modem – short for modulator / demodulator - which connects computers using a standard
telephone line 2- Network interface card (NIC) – which connects computers using a special type
of network cabling Note that, NICs are not synonymous with Ethernet cards. An Ethernet card is
a particular type of NIC, and is the most popular in personal computers (PCs). Most of the time,
these devices are internal hardware, although they are available as an external peripherals. 6 In
order to communicate with another computer over a network, you must do two things: 1. Use the
set of rules governing communication over the network, called a protocol. Your computer will
generally handle this. 2. Know the address of the computer you want to communicate with.
There are two types of network addresses: a. Medium access control (MAC) address which is
used inside a single network b. Internet protocol (IP) address which is used on the Internet World
Wide Web The World Wide Web (web for short or www) is a collection of interlinked
multimedia documents that are stored on the Internet and accessed using a common protocol
(HTTP). Form this definition we can say that the web is part of the system that is primarily
include software components (text files, graphics files, sound files, video files…). So, what is the
relation between the internet and the World Wide Web? World Wide Web (WWW) is an Internet
based software application. Other Internet applications are: Email ftp (file transfer protocol)
Messenger 7 More than 90 percent of the internet applications are World Wide Web so it is valid
to use Internet and World Wide Web terms interchangeably. World Wide Web is tied up to
several terms such as web server, web browser and HTML or Hypertext Markup Language. In
the following paragraph those terms are briefly explained.
Solution
There is a difference between to connect to a network and to communicate over a network.
Connecting to a network requires that special hardware be installed in your computer. This
hardware is called connection devices. There are two common types of connection devices: 1-
Modem – short for modulator / demodulator - which connects computers using a standard
telephone line 2- Network interface card (NIC) – which connects computers using a special type
of network cabling Note that, NICs are not synonymous with Ethernet cards. An Ethernet card is
a particular type of NIC, and is the most popular in personal computers (PCs). Most of the time,
these devices are internal hardware, although they are available as an external peripherals. 6 In
order to communicate with another computer over a network, you must do two things: 1. Use the
set of rules governing communication over the network, calle.
The picture is not uploaded properly it is corrupted. please upload .pdf
The picture is not uploaded properly it is corrupted. please upload it properly for the answer
Thank you.
Solution
The picture is not uploaded properly it is corrupted. please upload it properly for the answer
Thank you..
No clarity in question . Not visibleSolutionNo clarity in ques.pdf
No clarity in question . Not visible
Solution
No clarity in question . Not visible.
Date Account title Debit credit jan 30 cash 45000 common sto.pdf
Date Account title Debit credit jan 30 cash 45000 common stock 45000 [being common
stock issued] feb1 Prepaid rent 24000 cash 24000 [being rent paid in advance for
2years] Apr 10 supplies 3200 Accounts payable 3200 [being supplies purchased on
account] july 1 cash 24000 Unearned service revenue 24000 [being fees received in
advance] july 20 Accounts payable 1500 cash 1500 [Being accounts payable paid]
Aug 15 Accounts receivable 18000 Service revenue 18000 [being services provided]
sep 15 cash 8400 service revenue 8400 [being services provided] oct 1 Salaries 12000
cash 12000 [salary paid ] oct cash 15000 Accounts receivable 15000 [being
receivables due collected] nov 16 Accounts receivable 42000 service revenue 42000
[being services provided] dec 1 Dividend paid 15000 cash 15000 [being dividend
paid] dec 31 Unearned service revenue 12000 service revenue 12000 [being services
provided during the year recorded] 24000 *6/12 [july - dec = 6 months ] dec 31 Salary
expense 3600 salary payable 3600 [being salary due but not paid ] dec 31 Rent
expense 11000 prepaid rent 11000 [being rent for the year recorded (24000/2 = 12000per
year or 12000*11/12 = 11000 ] [1 feb - 31 dec = 11 months] dec 31 supplies expense
2920 supplies 2920 [being supplies used recorded (3200 -280 ]
Solution
Date Account title Debit credit jan 30 cash 45000 common stock 45000 [being common
stock issued] feb1 Prepaid rent 24000 cash 24000 [being rent paid in advance for
2years] Apr 10 supplies 3200 Accounts payable 3200 [being supplies purchased on
account] july 1 cash 24000 Unearned service revenue 24000 [being fees received in
advance] july 20 Accounts payable 1500 cash 1500 [Being accounts payable paid]
Aug 15 Accounts receivable 18000 Service revenue 18000 [being services provided]
sep 15 cash 8400 service revenue 8400 [being services provided] oct 1 Salaries 12000
cash 12000 [salary paid ] oct cash 15000 Accounts receivable 15000 [being
receivables due collected] nov 16 Accounts receivable 42000 service revenue 42000
[being services provided] dec 1 Dividend paid 15000 cash 15000 [being dividend
paid] dec 31 Unearned service revenue 12000 service revenue 12000 [being services
provided during the year recorded] 24000 *6/12 [july - dec = 6 months ] dec 31 Salary
expense 3600 salary payable 3600 [being salary due but not paid ] dec 31 Rent
expense 11000 prepaid rent 11000 [being rent for the year recorded (24000/2 = 12000per
year or 12000*11/12 = 11000 ] [1 feb - 31 dec = 11 months] dec 31 supplies expense
2920 supplies 2920 [being supplies used recorded (3200 -280 ].
Initial Value=2.5Drift rate per annum=0.4Variance rate per annum.pdf
Initial Value=2.5
Drift rate per annum=0.4
Variance rate per annum=0.5
Standard deviation=(0.5^0.5)= 0.707107
At the end of second year:
Mean=2.5+(2*0.4)=3.3
Standard deviation=0.707107*(2^0.5)=1
Double of initial value=2*2.5=5
Z value=(5-mean)/Standard deviation=(5-3.3)/1=1.7
Cumulative area Under the Standard Normal Distribution Table
For z value=1.7
Cumulative area=N(d)=0.9554
The probability that cash position will be more than double(greater than 5):
(1-0.9554)=0.0446
The probability that cash position will be more than double(greater than 5)=4.46%
Cash position negative:
Mean=2.5+(2*0.4)=3.3
Standard deviation=0.707107*(2^0.5)=1
Cash position zero=0
Z value=(0-mean)/Standard deviation=(0-3.3)/1=-3.3
Cumulative area Under the Standard Normal Distribution Table
For z value=-3.3
Cumulative area=N(d)=0.0013 {Cumulative area N(d) given in table for -3, below -3 is not
mentioned in the table. The z value is rounded to -3}
The probability that cash position will be negative:
=0.0013
The probability that cash position negative=0.13%
The probability that cash position will be more than double=4.46%
The probability that cash position will be negative=0.13%
Solution
Initial Value=2.5
Drift rate per annum=0.4
Variance rate per annum=0.5
Standard deviation=(0.5^0.5)= 0.707107
At the end of second year:
Mean=2.5+(2*0.4)=3.3
Standard deviation=0.707107*(2^0.5)=1
Double of initial value=2*2.5=5
Z value=(5-mean)/Standard deviation=(5-3.3)/1=1.7
Cumulative area Under the Standard Normal Distribution Table
For z value=1.7
Cumulative area=N(d)=0.9554
The probability that cash position will be more than double(greater than 5):
(1-0.9554)=0.0446
The probability that cash position will be more than double(greater than 5)=4.46%
Cash position negative:
Mean=2.5+(2*0.4)=3.3
Standard deviation=0.707107*(2^0.5)=1
Cash position zero=0
Z value=(0-mean)/Standard deviation=(0-3.3)/1=-3.3
Cumulative area Under the Standard Normal Distribution Table
For z value=-3.3
Cumulative area=N(d)=0.0013 {Cumulative area N(d) given in table for -3, below -3 is not
mentioned in the table. The z value is rounded to -3}
The probability that cash position will be negative:
=0.0013
The probability that cash position negative=0.13%
The probability that cash position will be more than double=4.46%
The probability that cash position will be negative=0.13%.
IntroductionDarwin argused that living organisms evolved from one .pdf
Introduction
Darwin argused that living organisms evolved from one or a few simple forms of live through
the process of natural selection. The essence of this comprise a population differ in the numper
of viable offspring the produce during their lifetimes.
Give that sexual reproduction is the means by which genes are propagated into future
generations, sexual selection plays a large role in human evolution. Human sexuality then is of
interest to evolutionary psychologists who aim to investigate evolved mechanisms to attract and
secure mates.
When an environment stress is constant and lasts for many generation , successful adaptation
may develop through biological evolution. The human body raedily responds to changing
environment stresses in a variety and cultural ways. We can acclimatize to a wide range of
temperature and humidity. When traveling to hige altitudes, our bodies adjust so, that our cells
still receive sufficient oxygen. We also are constantly responding in physiological ways to
internal and external stresses such as, bactrial and viral infections aie, water pollution, dietary
imbalance, and overcrowding.
Humans normally respond to environmentalstresses in four ways;
1. genetic change
2. developmental adjustment
3. acclimatization
4. cutural practices and technology
Human sexuality refers to people sexual interst in and attraction to others it is the capacity to
have erotic or sexual feling and experiences.
Human sexuality can be understood as part of the social life of humans, governed by social
norms,m implied rules of behavior, and the status quo. Socity views on sexuality have changed
throughout history and are continuously evolved.
Each society has different norma about premarital sex, the age of sexual consent, homosexuality,
mastrubation, and other sextual behaviours. Individuals are socialized to these from an early age
by their family, education system, peers, media, and religion.
With the advent of patriarchal societies, gender roles around sexality became much more
stringent, and sexual norma began focusing on sexual possessiveness and the control of female
sexuality.
The United States is relatively restrictive compared to other industrialized nation when it comes
to its citizens general attitudes about sex when.
The messages that children are taught about sex play an important role in how they will grow
into their sexual selves and express their sexual motivations. How, what, when, and by whom
children should be taught about sex is a matter oa great debate in sex education.
Solution
Introduction
Darwin argused that living organisms evolved from one or a few simple forms of live through
the process of natural selection. The essence of this comprise a population differ in the numper
of viable offspring the produce during their lifetimes.
Give that sexual reproduction is the means by which genes are propagated into future
generations, sexual selection plays a large role in human evolution. Human sexuality then is of
int.
import java.awt.LinearGradientPaint; public class searchComparis.pdf
import java.awt.LinearGradientPaint;
public class searchComparision {
/**
* @param args
*/
public static void linearSearch(int arr[],int n)
{
for(int i =0;i=n)
{
break;
}
}
System.out.println(\"\");
}
static void binarySearch(int arr[],int start,int end,int n)
{
if(endn)
{
binarySearch(arr, start,mid-1,n);
}
else
{
binarySearch(arr,mid+1,end,n);
}
return;
}
public static void main(String[] args) {
// TODO Auto-generated method stub
int arr[] = {4,8,12,23,54,84,89,110};
int n=8;
linearSearch(arr,n);
binarySearch(arr,0,arr.length-1,n);
n=33;
linearSearch(arr,n);
binarySearch(arr,0,arr.length-1,n);
n=84;
linearSearch(arr,n);
binarySearch(arr,0,arr.length-1,n);
}
}
Solution
import java.awt.LinearGradientPaint;
public class searchComparision {
/**
* @param args
*/
public static void linearSearch(int arr[],int n)
{
for(int i =0;i=n)
{
break;
}
}
System.out.println(\"\");
}
static void binarySearch(int arr[],int start,int end,int n)
{
if(endn)
{
binarySearch(arr, start,mid-1,n);
}
else
{
binarySearch(arr,mid+1,end,n);
}
return;
}
public static void main(String[] args) {
// TODO Auto-generated method stub
int arr[] = {4,8,12,23,54,84,89,110};
int n=8;
linearSearch(arr,n);
binarySearch(arr,0,arr.length-1,n);
n=33;
linearSearch(arr,n);
binarySearch(arr,0,arr.length-1,n);
n=84;
linearSearch(arr,n);
binarySearch(arr,0,arr.length-1,n);
}
}.
MASS MEDIA STUDIES-835-CLASS XI Resource Material.pdf
mass media studies
CBSE
Full Book
for class 11th
special B.ed 2nd year old paper_20240531.pdf
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X has +2 charge It has low first and second ioniz.pdf
X has +2 charge It has low first and second ionization energies. Hence it can give 2
electrons easily. Hence it will have +2 charge Y has larger ionization energy than X Hence atom
of Y is smaller than that of X(Same group)
Solution
X has +2 charge It has low first and second ionization energies. Hence it can give 2
electrons easily. Hence it will have +2 charge Y has larger ionization energy than X Hence atom
of Y is smaller than that of X(Same group).
Valence Bond Theory According to valence band the.pdf
Valence Bond Theory According to valence band theory a covalent bond is formed
between the two atoms by the overlap of half filled valence atomic orbitals of each atom
containing one unpaired electron. Valence bond theory considers that the overlapping atomic
orbitals of the participating atoms form a chemical bond. Because of the overlapping, it is most
probable that electrons should be in the bond region. Valence bond theory views bonds as
weakly coupled orbitals (small overlap). Valence bond theory is typically easier to employ in
ground state molecules. Hybridization It is the concept of mixing atomic orbitals to form new
hybrid orbitals suitable for the qualitative description of atomic bonding properties. Hybridised
orbitals are very useful in the explanation of the shape of molecular orbitals for molecules. It is
an integral part of valence bond theory. Molecular orbital theory molecular orbital (MO) theory
is a method for determining molecular structure in which electrons are not assigned to individual
bonds between atoms, but are treated as moving under the influence of the nuclei in the whole
molecule. In this theory, each molecule has a set of molecular orbitals, in which it is assumed
that the molecular orbital wave function ?f may be written as a simple weighted sum of the n
constituent atomic orbitals ?i Metallic Bonding Metallic bonding is the electrostatic attractive
forces between the delocalized electrons, called conduction electrons, gathered in an \"electron
sea\", and the positively charged metal ions.
Solution
Valence Bond Theory According to valence band theory a covalent bond is formed
between the two atoms by the overlap of half filled valence atomic orbitals of each atom
containing one unpaired electron. Valence bond theory considers that the overlapping atomic
orbitals of the participating atoms form a chemical bond. Because of the overlapping, it is most
probable that electrons should be in the bond region. Valence bond theory views bonds as
weakly coupled orbitals (small overlap). Valence bond theory is typically easier to employ in
ground state molecules. Hybridization It is the concept of mixing atomic orbitals to form new
hybrid orbitals suitable for the qualitative description of atomic bonding properties. Hybridised
orbitals are very useful in the explanation of the shape of molecular orbitals for molecules. It is
an integral part of valence bond theory. Molecular orbital theory molecular orbital (MO) theory
is a method for determining molecular structure in which electrons are not assigned to individual
bonds between atoms, but are treated as moving under the influence of the nuclei in the whole
molecule. In this theory, each molecule has a set of molecular orbitals, in which it is assumed
that the molecular orbital wave function ?f may be written as a simple weighted sum of the n
constituent atomic orbitals ?i Metallic Bonding Metallic bonding is the electrostatic attractive
forces between the delocalized e.
total volume =25+25=50 ml total millimoles of KI=.pdf
total volume =25+25=50 ml total millimoles of KI=25*0.2=5
conce=millimoles/volume in ml =5/50=0.1 similarly for other compound 25*0.2/50=0.1
Solution
total volume =25+25=50 ml total millimoles of KI=25*0.2=5
conce=millimoles/volume in ml =5/50=0.1 similarly for other compound 25*0.2/50=0.1.
This type of deformation is irreversible. However.pdf
This type of deformation is irreversible. However, an object in the plastic
deformation range will first have undergone elastic deformation, which is reversible, so the
object will return part way to its original shape
Solution
This type of deformation is irreversible. However, an object in the plastic
deformation range will first have undergone elastic deformation, which is reversible, so the
object will return part way to its original shape.
Some elements receive their respective symbol bas.pdf
Some elements receive their respective symbol based on their latin equivalence...
Ex: iron(Fe) = ferrous, lead(Pb) = plumbum, mercury(Hg) = hydrargyrum While others are
receive their symbol for where they are discovered or to the discoverer\'s home country... Ex:
Germanium (Germany), Californium (University of California) While others are named after
their founders... Ex: Einsteinium (Albert Einstein), Mendelevium (Dmitri Ivanovich Mendeleev)
When these elements are combined into compounds, there are a couple of tricks to help with
remembering them... Ex: 1. -ous compounds will generally have a lower charge than -ic
compounds 2. Hydro- compounds will have an addition of an H+ proton making the compound
an acid
Solution
Some elements receive their respective symbol based on their latin equivalence...
Ex: iron(Fe) = ferrous, lead(Pb) = plumbum, mercury(Hg) = hydrargyrum While others are
receive their symbol for where they are discovered or to the discoverer\'s home country... Ex:
Germanium (Germany), Californium (University of California) While others are named after
their founders... Ex: Einsteinium (Albert Einstein), Mendelevium (Dmitri Ivanovich Mendeleev)
When these elements are combined into compounds, there are a couple of tricks to help with
remembering them... Ex: 1. -ous compounds will generally have a lower charge than -ic
compounds 2. Hydro- compounds will have an addition of an H+ proton making the compound
an acid.
phosphonium ylide is produced when phosphonium ha.pdf
phosphonium ylide is produced when phosphonium halide salt reacts with a strong
base such as nBuLi.
Solution
phosphonium ylide is produced when phosphonium halide salt reacts with a strong
base such as nBuLi..
N1 V1 = N2 V2 50 x M1 = 1.50 x 2 x 17.7 M M1 = 1..pdf
N1 V1 = N2 V2 50 x M1 = 1.50 x 2 x 17.7 M M1 = 1.06 M
Solution
N1 V1 = N2 V2 50 x M1 = 1.50 x 2 x 17.7 M M1 = 1.06 M.
In chemistry, an amphoteric species is a molecule.pdf
In chemistry, an amphoteric species is a molecule or ion that can react as an acid as
well as a base. Zinc oxide (ZnO) reacts with both acids and with bases: In acid: ZnO + 2H+ ?
Zn2+ + H2O In base: ZnO + H2O + 2OH- ? [Zn(OH)4]2-
Solution
In chemistry, an amphoteric species is a molecule or ion that can react as an acid as
well as a base. Zinc oxide (ZnO) reacts with both acids and with bases: In acid: ZnO + 2H+ ?
Zn2+ + H2O In base: ZnO + H2O + 2OH- ? [Zn(OH)4]2-.
Chemistry is the science of matter, especially it.pdf
Chemistry is the science of matter, especially its chemical reactions, but also its
composition, structure and properties.[1][2] Chemistry is concerned with atoms and their
interactions with other atoms, and particularly with the properties of chemical bonds.
Solution
Chemistry is the science of matter, especially its chemical reactions, but also its
composition, structure and properties.[1][2] Chemistry is concerned with atoms and their
interactions with other atoms, and particularly with the properties of chemical bonds..
Before this confederates began their general advance, General Lee pl.pdf
Before this confederates began their general advance, General Lee planned to weaken any union
opposition with
(c) an artillery barrage
Solution
Before this confederates began their general advance, General Lee planned to weaken any union
opposition with
(c) an artillery barrage.
An understanding of periodic trends is important .pdf
An understanding of periodic trends is important because the trends:- 4. relate to
properties of elements and how they may react.
Solution
An understanding of periodic trends is important because the trends:- 4. relate to
properties of elements and how they may react..
Acid contains hydrogen ions. Thus, iodate will re.pdf
Acid contains hydrogen ions. Thus, iodate will react with hydrogen ion to form
iodine and water. 2IO3- + 12H+ + 10e- -> I2 + 6H2O Iodine and water will be further reduced
to form iodide ions. Thus, this will affect the titration process, thus it should be titrated
immediately. IO3- + 3H2O + 6e- -> I- + 6OH- Hope this helps!
Solution
Acid contains hydrogen ions. Thus, iodate will react with hydrogen ion to form
iodine and water. 2IO3- + 12H+ + 10e- -> I2 + 6H2O Iodine and water will be further reduced
to form iodide ions. Thus, this will affect the titration process, thus it should be titrated
immediately. IO3- + 3H2O + 6e- -> I- + 6OH- Hope this helps!.
There is a difference between to connect to a network and to communi.pdf
There is a difference between to connect to a network and to communicate over a network.
Connecting to a network requires that special hardware be installed in your computer. This
hardware is called connection devices. There are two common types of connection devices: 1-
Modem – short for modulator / demodulator - which connects computers using a standard
telephone line 2- Network interface card (NIC) – which connects computers using a special type
of network cabling Note that, NICs are not synonymous with Ethernet cards. An Ethernet card is
a particular type of NIC, and is the most popular in personal computers (PCs). Most of the time,
these devices are internal hardware, although they are available as an external peripherals. 6 In
order to communicate with another computer over a network, you must do two things: 1. Use the
set of rules governing communication over the network, called a protocol. Your computer will
generally handle this. 2. Know the address of the computer you want to communicate with.
There are two types of network addresses: a. Medium access control (MAC) address which is
used inside a single network b. Internet protocol (IP) address which is used on the Internet World
Wide Web The World Wide Web (web for short or www) is a collection of interlinked
multimedia documents that are stored on the Internet and accessed using a common protocol
(HTTP). Form this definition we can say that the web is part of the system that is primarily
include software components (text files, graphics files, sound files, video files…). So, what is the
relation between the internet and the World Wide Web? World Wide Web (WWW) is an Internet
based software application. Other Internet applications are: Email ftp (file transfer protocol)
Messenger 7 More than 90 percent of the internet applications are World Wide Web so it is valid
to use Internet and World Wide Web terms interchangeably. World Wide Web is tied up to
several terms such as web server, web browser and HTML or Hypertext Markup Language. In
the following paragraph those terms are briefly explained.
Solution
There is a difference between to connect to a network and to communicate over a network.
Connecting to a network requires that special hardware be installed in your computer. This
hardware is called connection devices. There are two common types of connection devices: 1-
Modem – short for modulator / demodulator - which connects computers using a standard
telephone line 2- Network interface card (NIC) – which connects computers using a special type
of network cabling Note that, NICs are not synonymous with Ethernet cards. An Ethernet card is
a particular type of NIC, and is the most popular in personal computers (PCs). Most of the time,
these devices are internal hardware, although they are available as an external peripherals. 6 In
order to communicate with another computer over a network, you must do two things: 1. Use the
set of rules governing communication over the network, calle.
The picture is not uploaded properly it is corrupted. please upload .pdf
The picture is not uploaded properly it is corrupted. please upload it properly for the answer
Thank you.
Solution
The picture is not uploaded properly it is corrupted. please upload it properly for the answer
Thank you..
No clarity in question . Not visibleSolutionNo clarity in ques.pdf
No clarity in question . Not visible
Solution
No clarity in question . Not visible.
Date Account title Debit credit jan 30 cash 45000 common sto.pdf
Date Account title Debit credit jan 30 cash 45000 common stock 45000 [being common
stock issued] feb1 Prepaid rent 24000 cash 24000 [being rent paid in advance for
2years] Apr 10 supplies 3200 Accounts payable 3200 [being supplies purchased on
account] july 1 cash 24000 Unearned service revenue 24000 [being fees received in
advance] july 20 Accounts payable 1500 cash 1500 [Being accounts payable paid]
Aug 15 Accounts receivable 18000 Service revenue 18000 [being services provided]
sep 15 cash 8400 service revenue 8400 [being services provided] oct 1 Salaries 12000
cash 12000 [salary paid ] oct cash 15000 Accounts receivable 15000 [being
receivables due collected] nov 16 Accounts receivable 42000 service revenue 42000
[being services provided] dec 1 Dividend paid 15000 cash 15000 [being dividend
paid] dec 31 Unearned service revenue 12000 service revenue 12000 [being services
provided during the year recorded] 24000 *6/12 [july - dec = 6 months ] dec 31 Salary
expense 3600 salary payable 3600 [being salary due but not paid ] dec 31 Rent
expense 11000 prepaid rent 11000 [being rent for the year recorded (24000/2 = 12000per
year or 12000*11/12 = 11000 ] [1 feb - 31 dec = 11 months] dec 31 supplies expense
2920 supplies 2920 [being supplies used recorded (3200 -280 ]
Solution
Date Account title Debit credit jan 30 cash 45000 common stock 45000 [being common
stock issued] feb1 Prepaid rent 24000 cash 24000 [being rent paid in advance for
2years] Apr 10 supplies 3200 Accounts payable 3200 [being supplies purchased on
account] july 1 cash 24000 Unearned service revenue 24000 [being fees received in
advance] july 20 Accounts payable 1500 cash 1500 [Being accounts payable paid]
Aug 15 Accounts receivable 18000 Service revenue 18000 [being services provided]
sep 15 cash 8400 service revenue 8400 [being services provided] oct 1 Salaries 12000
cash 12000 [salary paid ] oct cash 15000 Accounts receivable 15000 [being
receivables due collected] nov 16 Accounts receivable 42000 service revenue 42000
[being services provided] dec 1 Dividend paid 15000 cash 15000 [being dividend
paid] dec 31 Unearned service revenue 12000 service revenue 12000 [being services
provided during the year recorded] 24000 *6/12 [july - dec = 6 months ] dec 31 Salary
expense 3600 salary payable 3600 [being salary due but not paid ] dec 31 Rent
expense 11000 prepaid rent 11000 [being rent for the year recorded (24000/2 = 12000per
year or 12000*11/12 = 11000 ] [1 feb - 31 dec = 11 months] dec 31 supplies expense
2920 supplies 2920 [being supplies used recorded (3200 -280 ].
Initial Value=2.5Drift rate per annum=0.4Variance rate per annum.pdf
Initial Value=2.5
Drift rate per annum=0.4
Variance rate per annum=0.5
Standard deviation=(0.5^0.5)= 0.707107
At the end of second year:
Mean=2.5+(2*0.4)=3.3
Standard deviation=0.707107*(2^0.5)=1
Double of initial value=2*2.5=5
Z value=(5-mean)/Standard deviation=(5-3.3)/1=1.7
Cumulative area Under the Standard Normal Distribution Table
For z value=1.7
Cumulative area=N(d)=0.9554
The probability that cash position will be more than double(greater than 5):
(1-0.9554)=0.0446
The probability that cash position will be more than double(greater than 5)=4.46%
Cash position negative:
Mean=2.5+(2*0.4)=3.3
Standard deviation=0.707107*(2^0.5)=1
Cash position zero=0
Z value=(0-mean)/Standard deviation=(0-3.3)/1=-3.3
Cumulative area Under the Standard Normal Distribution Table
For z value=-3.3
Cumulative area=N(d)=0.0013 {Cumulative area N(d) given in table for -3, below -3 is not
mentioned in the table. The z value is rounded to -3}
The probability that cash position will be negative:
=0.0013
The probability that cash position negative=0.13%
The probability that cash position will be more than double=4.46%
The probability that cash position will be negative=0.13%
Solution
Initial Value=2.5
Drift rate per annum=0.4
Variance rate per annum=0.5
Standard deviation=(0.5^0.5)= 0.707107
At the end of second year:
Mean=2.5+(2*0.4)=3.3
Standard deviation=0.707107*(2^0.5)=1
Double of initial value=2*2.5=5
Z value=(5-mean)/Standard deviation=(5-3.3)/1=1.7
Cumulative area Under the Standard Normal Distribution Table
For z value=1.7
Cumulative area=N(d)=0.9554
The probability that cash position will be more than double(greater than 5):
(1-0.9554)=0.0446
The probability that cash position will be more than double(greater than 5)=4.46%
Cash position negative:
Mean=2.5+(2*0.4)=3.3
Standard deviation=0.707107*(2^0.5)=1
Cash position zero=0
Z value=(0-mean)/Standard deviation=(0-3.3)/1=-3.3
Cumulative area Under the Standard Normal Distribution Table
For z value=-3.3
Cumulative area=N(d)=0.0013 {Cumulative area N(d) given in table for -3, below -3 is not
mentioned in the table. The z value is rounded to -3}
The probability that cash position will be negative:
=0.0013
The probability that cash position negative=0.13%
The probability that cash position will be more than double=4.46%
The probability that cash position will be negative=0.13%.
IntroductionDarwin argused that living organisms evolved from one .pdf
Introduction
Darwin argused that living organisms evolved from one or a few simple forms of live through
the process of natural selection. The essence of this comprise a population differ in the numper
of viable offspring the produce during their lifetimes.
Give that sexual reproduction is the means by which genes are propagated into future
generations, sexual selection plays a large role in human evolution. Human sexuality then is of
interest to evolutionary psychologists who aim to investigate evolved mechanisms to attract and
secure mates.
When an environment stress is constant and lasts for many generation , successful adaptation
may develop through biological evolution. The human body raedily responds to changing
environment stresses in a variety and cultural ways. We can acclimatize to a wide range of
temperature and humidity. When traveling to hige altitudes, our bodies adjust so, that our cells
still receive sufficient oxygen. We also are constantly responding in physiological ways to
internal and external stresses such as, bactrial and viral infections aie, water pollution, dietary
imbalance, and overcrowding.
Humans normally respond to environmentalstresses in four ways;
1. genetic change
2. developmental adjustment
3. acclimatization
4. cutural practices and technology
Human sexuality refers to people sexual interst in and attraction to others it is the capacity to
have erotic or sexual feling and experiences.
Human sexuality can be understood as part of the social life of humans, governed by social
norms,m implied rules of behavior, and the status quo. Socity views on sexuality have changed
throughout history and are continuously evolved.
Each society has different norma about premarital sex, the age of sexual consent, homosexuality,
mastrubation, and other sextual behaviours. Individuals are socialized to these from an early age
by their family, education system, peers, media, and religion.
With the advent of patriarchal societies, gender roles around sexality became much more
stringent, and sexual norma began focusing on sexual possessiveness and the control of female
sexuality.
The United States is relatively restrictive compared to other industrialized nation when it comes
to its citizens general attitudes about sex when.
The messages that children are taught about sex play an important role in how they will grow
into their sexual selves and express their sexual motivations. How, what, when, and by whom
children should be taught about sex is a matter oa great debate in sex education.
Solution
Introduction
Darwin argused that living organisms evolved from one or a few simple forms of live through
the process of natural selection. The essence of this comprise a population differ in the numper
of viable offspring the produce during their lifetimes.
Give that sexual reproduction is the means by which genes are propagated into future
generations, sexual selection plays a large role in human evolution. Human sexuality then is of
int.
import java.awt.LinearGradientPaint; public class searchComparis.pdf
import java.awt.LinearGradientPaint;
public class searchComparision {
/**
* @param args
*/
public static void linearSearch(int arr[],int n)
{
for(int i =0;i=n)
{
break;
}
}
System.out.println(\"\");
}
static void binarySearch(int arr[],int start,int end,int n)
{
if(endn)
{
binarySearch(arr, start,mid-1,n);
}
else
{
binarySearch(arr,mid+1,end,n);
}
return;
}
public static void main(String[] args) {
// TODO Auto-generated method stub
int arr[] = {4,8,12,23,54,84,89,110};
int n=8;
linearSearch(arr,n);
binarySearch(arr,0,arr.length-1,n);
n=33;
linearSearch(arr,n);
binarySearch(arr,0,arr.length-1,n);
n=84;
linearSearch(arr,n);
binarySearch(arr,0,arr.length-1,n);
}
}
Solution
import java.awt.LinearGradientPaint;
public class searchComparision {
/**
* @param args
*/
public static void linearSearch(int arr[],int n)
{
for(int i =0;i=n)
{
break;
}
}
System.out.println(\"\");
}
static void binarySearch(int arr[],int start,int end,int n)
{
if(endn)
{
binarySearch(arr, start,mid-1,n);
}
else
{
binarySearch(arr,mid+1,end,n);
}
return;
}
public static void main(String[] args) {
// TODO Auto-generated method stub
int arr[] = {4,8,12,23,54,84,89,110};
int n=8;
linearSearch(arr,n);
binarySearch(arr,0,arr.length-1,n);
n=33;
linearSearch(arr,n);
binarySearch(arr,0,arr.length-1,n);
n=84;
linearSearch(arr,n);
binarySearch(arr,0,arr.length-1,n);
}
}.
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Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
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Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
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MonsterAttack.javapublic class MonsterAttack { int id; .pdf
- 1. // MonsterAttack.java public class MonsterAttack { int id; int day, month, year; String nameOfMonster; String location; int numOfVictims; public MonsterAttack(int id, String date, String nameOfMonster, String location, int numOfVictims) { String arr[] = date.split("/"); this.id = id; this.day = Integer.parseInt(arr[1]); this.month = Integer.parseInt(arr[0]); this.year = Integer.parseInt(arr[2]); this.nameOfMonster = nameOfMonster; this.location = location; this.numOfVictims = numOfVictims; } int getId() { return id; } void setId(int id) { this.id = id; } String getNameOfMonster() { return nameOfMonster; } void setNameOfMonster(String nameOfMonster) { this.nameOfMonster = nameOfMonster; } String getLocation() { return location; } void setLocation(String location) { this.location = location;
- 2. } int getNumOfVictims() { return numOfVictims; } void setNumOfVictims(int numOfVictims) { this.numOfVictims = numOfVictims; } String getDate(){ return month + "/" + day + "/" + year; } void setDate(String date){ String arr[] = date.split("/"); this.day = Integer.parseInt(arr[1]); this.month = Integer.parseInt(arr[0]); this.year = Integer.parseInt(arr[2]); } public String toString(){ return "Attack # " + id + "occurred on " + getDate() + ". " + nameOfMonster + "attacked " + location + ", resulting in " + numOfVictims + " tragic fatalities."; } } // AttackMonitor.java import java.util.ArrayList; import javax.swing.JOptionPane; public class AttackMonitor{ ArrayList attacks = new ArrayList(); void input(){ String nameOfMonster, location, date; int id, numOfVictims; nameOfMonster = JOptionPane.showInputDialog("Enter the name of the monster"); location = JOptionPane.showInputDialog("Enter the location of attack"); date = JOptionPane.showInputDialog("Enter the date of attack"); id = Integer.parseInt(JOptionPane.showInputDialog("Enter the id of attack")); numOfVictims = Integer.parseInt(JOptionPane.showInputDialog("Enter the number of victims"));
- 3. MonsterAttack temp = new MonsterAttack(id, date, nameOfMonster, location, numOfVictims); attacks.add(temp); } void display(){ for(int i = 0; i < attacks.size(); i++){ System.out.println(attacks.get(i)); } } void delete(){ display(); int id = Integer.parseInt(JOptionPane.showInputDialog("Enter the id of attack to delete")); int i; for(i = 0; i < attacks.size(); i++){ if(attacks.get(i).getId() == id){ break; } } if(i != attacks.size()) attacks.remove(i); } void monitor(){ int choice = Integer.parseInt(JOptionPane.showInputDialog("Enter 1 for adding new attack, 2 for displaying attacks, 3 for deleting an attack, any other number to exit")); switch (choice) { case 1: input(); break; case 2: display(); break; case 3: delete(); break; default: return; }
- 4. } } // MonsterAttackDriver.java Give sample input/output ot input file Solution // MonsterAttack.java public class MonsterAttack { int id; int day, month, year; String nameOfMonster; String location; int numOfVictims; public MonsterAttack(int id, String date, String nameOfMonster, String location, int numOfVictims) { String arr[] = date.split("/"); this.id = id; this.day = Integer.parseInt(arr[1]); this.month = Integer.parseInt(arr[0]); this.year = Integer.parseInt(arr[2]); this.nameOfMonster = nameOfMonster; this.location = location; this.numOfVictims = numOfVictims; } int getId() { return id; } void setId(int id) { this.id = id; } String getNameOfMonster() { return nameOfMonster; } void setNameOfMonster(String nameOfMonster) {
- 5. this.nameOfMonster = nameOfMonster; } String getLocation() { return location; } void setLocation(String location) { this.location = location; } int getNumOfVictims() { return numOfVictims; } void setNumOfVictims(int numOfVictims) { this.numOfVictims = numOfVictims; } String getDate(){ return month + "/" + day + "/" + year; } void setDate(String date){ String arr[] = date.split("/"); this.day = Integer.parseInt(arr[1]); this.month = Integer.parseInt(arr[0]); this.year = Integer.parseInt(arr[2]); } public String toString(){ return "Attack # " + id + "occurred on " + getDate() + ". " + nameOfMonster + "attacked " + location + ", resulting in " + numOfVictims + " tragic fatalities."; } } // AttackMonitor.java import java.util.ArrayList; import javax.swing.JOptionPane; public class AttackMonitor{ ArrayList attacks = new ArrayList(); void input(){ String nameOfMonster, location, date;
- 6. int id, numOfVictims; nameOfMonster = JOptionPane.showInputDialog("Enter the name of the monster"); location = JOptionPane.showInputDialog("Enter the location of attack"); date = JOptionPane.showInputDialog("Enter the date of attack"); id = Integer.parseInt(JOptionPane.showInputDialog("Enter the id of attack")); numOfVictims = Integer.parseInt(JOptionPane.showInputDialog("Enter the number of victims")); MonsterAttack temp = new MonsterAttack(id, date, nameOfMonster, location, numOfVictims); attacks.add(temp); } void display(){ for(int i = 0; i < attacks.size(); i++){ System.out.println(attacks.get(i)); } } void delete(){ display(); int id = Integer.parseInt(JOptionPane.showInputDialog("Enter the id of attack to delete")); int i; for(i = 0; i < attacks.size(); i++){ if(attacks.get(i).getId() == id){ break; } } if(i != attacks.size()) attacks.remove(i); } void monitor(){ int choice = Integer.parseInt(JOptionPane.showInputDialog("Enter 1 for adding new attack, 2 for displaying attacks, 3 for deleting an attack, any other number to exit")); switch (choice) { case 1: input(); break; case 2: display();
- 7. break; case 3: delete(); break; default: return; } } } // MonsterAttackDriver.java Give sample input/output ot input file