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Mixtures
Mixtures
Three friends A, B and C play a game in a pub. The rules are simple. Whenever there is
a contest between any two of them, the one who has a higher percentage alcohol
should pour 200 ml of his wine into the one having lower percentage alcohol. The
game starts as a contest between A and B, then B and C and then C and A. Post this,
the game continues in the same cycle on and on. If a player has emptied all his
alcohol, then the remaining two play the game with the same rules. If two players
have the alcohol of the same percentage level, the younger one pours 200 ml of his
alcohol into the elder one’s glass. All three of them start the game with 600 ml of
wine. A’s wine has 60% alcohol, B’s has 48% alcohol and C’s has 50% alcohol. They take
3 minutes to play one round of this game. D, a fourth friend leaves the pub
immediately after the game begins, returns after an hour and drinks wine from the
person who has the highest alcohol percentage. What is the concentration of the
alcohol that D had?
(a) 51.5% (b) 52.67%
(c) 53% (d) Cannot be determined
Mixtures
Step 1: A vs B:
Since A has a higher percentage of alcohol than B, A has to give B
200 ml of wine. Considering that A has a 60% strength mixture, B will
end up having 800 ml of wine that has
60% × 1 + 48% × 3
4
= 51%
alcohol.
Mixtures
Step 2: B vs C:
B has a higher percentage of alcohol than C, so B has to give 200 ml
of alcohol to C now. C will end up having wine that has
51% × 1 + 50% × 3
4
= 50.25%
Mixtures
Step 3:
A gives C 200 mls of wine. We see that computing percentages is
going to cumbersome. So, let us just forget the numbers and think
about how the game pans out.
Mixtures
Step 4: A would give B 200 ml of wine. We note straight away that A
will always give the wine. A had the highest percentage alcohol to
start with. And no mixture can reach 60% alcohol levels. So, A will
give all his wine away by this round.
Post this, we notice that, between B and C whoever has higher
percentage alcohol will keep giving wine to the other. Eventually, all
the wine will be with just one person. At the rate of 3 minutes per
round, the game, the game will definitely be over before 1 hour.
So, the concentration of alcohol in the wine D drinks is
60% + 48% + 50%
3
= 52.67%. Answer choice (b)
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Mixtures - Fun question

  • 2. Mixtures Three friends A, B and C play a game in a pub. The rules are simple. Whenever there is a contest between any two of them, the one who has a higher percentage alcohol should pour 200 ml of his wine into the one having lower percentage alcohol. The game starts as a contest between A and B, then B and C and then C and A. Post this, the game continues in the same cycle on and on. If a player has emptied all his alcohol, then the remaining two play the game with the same rules. If two players have the alcohol of the same percentage level, the younger one pours 200 ml of his alcohol into the elder one’s glass. All three of them start the game with 600 ml of wine. A’s wine has 60% alcohol, B’s has 48% alcohol and C’s has 50% alcohol. They take 3 minutes to play one round of this game. D, a fourth friend leaves the pub immediately after the game begins, returns after an hour and drinks wine from the person who has the highest alcohol percentage. What is the concentration of the alcohol that D had? (a) 51.5% (b) 52.67% (c) 53% (d) Cannot be determined
  • 3. Mixtures Step 1: A vs B: Since A has a higher percentage of alcohol than B, A has to give B 200 ml of wine. Considering that A has a 60% strength mixture, B will end up having 800 ml of wine that has 60% × 1 + 48% × 3 4 = 51% alcohol.
  • 4. Mixtures Step 2: B vs C: B has a higher percentage of alcohol than C, so B has to give 200 ml of alcohol to C now. C will end up having wine that has 51% × 1 + 50% × 3 4 = 50.25%
  • 5. Mixtures Step 3: A gives C 200 mls of wine. We see that computing percentages is going to cumbersome. So, let us just forget the numbers and think about how the game pans out.
  • 6. Mixtures Step 4: A would give B 200 ml of wine. We note straight away that A will always give the wine. A had the highest percentage alcohol to start with. And no mixture can reach 60% alcohol levels. So, A will give all his wine away by this round. Post this, we notice that, between B and C whoever has higher percentage alcohol will keep giving wine to the other. Eventually, all the wine will be with just one person. At the rate of 3 minutes per round, the game, the game will definitely be over before 1 hour. So, the concentration of alcohol in the wine D drinks is 60% + 48% + 50% 3 = 52.67%. Answer choice (b)
  • 7. For the best online coaching for CAT, visit online.2iim.com