MineSweeper.java public class MS { public static void main(Strin.pdf
•
0 likes•3 views
MineSweeper.java public class MS { public static void main(String[] args) { Gamegm= new Game(); } } --> Game.java public class Game { private Bd bd; boolean fnsh = false; boolean w = false; int tn=0; public jg(){ bd = new Bd(); Py(bd); } public void Py(Bd bd){ do{ tn++; System.out.println(\"Turn \"+tn); bd.show(); fnsh = bd.setPosition(); if(!fnsh){ bd.openNeighbors(); fnsh = bd.w(); } }while(!fnsh); if(bd.w()){ System.out.println(\"Congratulations, you let the 10 fields with the mns in \"+tn+\" tns\"); bd.showMines(); } else { System.out.println(\"Mine! You lost!\"); bd.showMines(); } } } --> Bd.java import java.util.Rnm; import java.util.Scanner; public class Bd { private int[][] mns; private char[][] bdgame; private int Line, Clm; Rnm rnm = new Rnm(); Scanner input = new Scanner(System.in); public Bd (){ mns = new int[10][10]; bdgame = new char[10][10]; stMs(); rnmMines(); fillTips(); startBd(); } public boolean w(){ int ct=0; for(int line = 1 ; line < 9 ; line++) for(int clm = 1 ; clm < 9 ; clm++) if(bdgame[line][clm]==\'_\') ct++; if(ct == 10) return true; else return false; } public void oN(){ for(int i=-1 ; i<2 ; i++) for(int j=-1 ; j<2 ; j++) if( (mns[Ln+i][Clm+j] != -1) && (Ln != 0 && Ln != 9 && Clm != 0 && Clm != 9) ) bdgame[Ln+i][Clm+j]=Character.forDigit(mns[Ln+i][Clm+j], 10); } public int getPosition(int Ln, int Clm){ retn mns[Ln][Clm]; } public boolean setPosition(){ do{ System.out.print(\"\ Ln: \"); Ln = input.nextInt(); System.out.print(\"Clm: \"); Clm = input.nextInt(); if( (bdgame[Ln][Clm] != \'_\') && ((Ln < 9 && Ln > 0) && (Clm < 9 && Clm > 0))) System.out.println(\"Field already shown\"); if( Ln < 1 || Ln > 8 || Clm < 1 || Clm > 8) System.out.println(\"Choose a number between 1 and 8\"); }while((Ln < 1 || Ln > 8 || Clm < 1 || Clm > 8) || (bdgame[Ln][Clm] != \'_\') ); if(getPosition(Ln, Clm)== -1) retn true; else retn false; } public void show(){ System.out.println(\"\ Lns\"); for(int Ln = 8 ; Ln > 0 ; Ln--){ System.out.print(\" \"+Ln + \" \"); for(int Clm = 1 ; Clm < 9 ; Clm++){ System.out.print(\" \"+ bdgame[Ln][Clm]); } System.out.println(); } System.out.println(\"\ 1 2 3 4 5 6 7 8\"); System.out.println(\" Clms\"); } public void fillTips(){ for(int ln=1 ; ln < 9 ; ln++) for(int clm=1 ; clm < 9 ; clm++){ for(int i=-1 ; i<=1 ; i++) for(int j=-1 ; j<=1 ; j++) if(mns[ln][clm] != -1) if(mns[ln+i][clm+j] == -1) mns[ln][clm]++; } } public void showMines(){ for(int i=1 ; i < 9; i++) for(int j=1 ; j < 9 ; j++) if(mns[i][j] == -1) bdgame[i][j]=\'*\'; show(); } public void startBd(){ for(int i=1 ; i Solution MineSweeper.java public class MS { public static void main(String[] args) { Gamegm= new Game(); } } --> Game.java public class Game { private Bd bd; boolean fnsh = false; boolean w = false; int tn=0; public jg(){ bd = new Bd(); Py(bd); } public void Py(Bd bd){ do{ tn++; System.out.println(\"Turn \"+tn); bd.show(); fnsh = bd.setPosition(); if(!fnsh){ bd.openNeighbors(); fnsh = bd.w(); } }while(!fnsh); if(bd.w()){ System.out.pr.
Report
Share
Report
Share
Download to read offline
![MineSweeper.java
public class MS {
public static void main(String[] args) {
Gamegm= new Game();
}
}
--> Game.java
public class Game {
private Bd bd;
boolean fnsh = false;
boolean w = false;
int tn=0;
public jg(){
bd = new Bd();
Py(bd);
}
public void Py(Bd bd){
do{
tn++;
System.out.println("Turn "+tn);
bd.show();
fnsh = bd.setPosition();
if(!fnsh){
bd.openNeighbors();
fnsh = bd.w();
}
}while(!fnsh);
if(bd.w()){
System.out.println("Congratulations, you let the 10 fields with the mns in "+tn+" tns");
bd.showMines();](https://image.slidesharecdn.com/minesweeper-230409024700-876961e1/85/MineSweeper-java-public-class-MS-public-static-void-main-Strin-pdf-1-320.jpg)
![} else {
System.out.println("Mine! You lost!");
bd.showMines();
}
}
}
--> Bd.java
import java.util.Rnm;
import java.util.Scanner;
public class Bd {
private int[][] mns;
private char[][] bdgame;
private int Line, Clm;
Rnm rnm = new Rnm();
Scanner input = new Scanner(System.in);
public Bd (){
mns = new int[10][10];
bdgame = new char[10][10];
stMs();
rnmMines();
fillTips();
startBd();
}
public boolean w(){
int ct=0;
for(int line = 1 ; line < 9 ; line++)
for(int clm = 1 ; clm < 9 ; clm++)
if(bdgame[line][clm]=='_')
ct++;
if(ct == 10)
return true;
else
return false;](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Recommended
Find the output of the following code (Java for ICSE)
This document consists of some important practice questions for ICSE Class X Exams from the section of find the output. It is also supplemented with past years question papers
import java.util.Scanner;public class Main { public static in.pdf
import java.util.Scanner;
public class Main {
public static int gridArray1[][] = null;
public static int gridArray2[][] = null;
public static boolean playerTurn = true;
public static int count = 0;
public static void setGridDimensions(int x_max, int y_max) {
Main.gridArray1 = new int[x_max][y_max];
Main.gridArray2 = new int[x_max][y_max];
for (int i = 0; i < x_max; i++) {
for (int j = 0; j < y_max; j++) {
gridArray1[i][j] = -1;
gridArray2[i][j] = -1;
}
}
}
static void placeShip(int starting_x, int starting_y, int length, int direction) {
count++;
int ships[] = new int[10];
int battleshipArrayPositions1[] = new int[4];
int cruiserArrayPositions1[] = new int[3];
int submarineArrayPositions1[] = new int[3];
int destroyerArrayPositions1[] = new int[2];
int carrierArrayPositions2[] = new int[5];
int battleshipArrayPositions2[] = new int[4];
int cruiserArrayPositions2[] = new int[3];
int submarineArrayPositions2[] = new int[3];
int destroyerArrayPositions2[] = new int[2];
if (playerTurn) {
if (direction == 0) {
for (int i = starting_x; i < starting_x + length; i++) {
Main.gridArray1[i][starting_y] = 0;
}
} else {
for (int i = starting_y; i < starting_y + length; i++) {
Main.gridArray1[starting_x][i] = 0;
}
}
} else {
if (direction == 0) {
for (int i = starting_x; i < starting_x + length; i++) {
Main.gridArray2[i][starting_y] = 0;
}
} else {
for (int i = starting_y; i < starting_y + length; i++) {
Main.gridArray2[starting_x][i] = 0;
}
}
}
}
boolean isConflictingShipPlacement(int starting_x, int starting_y, int length, int direction) {
return false;
}
static int shoot(int x, int y) {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (Main.gridArray2[i][j] == 0) {
return 0;
}
}
}
} else {
}
return 0;
}
boolean hasBeenAttempted(int x, int y) {
return false;
}
static void displayGrid(boolean showShips) {
int count = 0;
System.out.print(\" 0 1 2 3 4 5 6 7 8 9\");
if (showShips) {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray1[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray1[i][j] == 0) {
System.out.print(\"@ \");
} else if (Main.gridArray1[i][j] == 1) {
System.out.print(\"+ \");
} else {
System.out.print(\"X \");
}
}
}
} else {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray2[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray2[i][j] == 0) {
System.out.print(\"@ \");
} else if (Main.gridArray2[i][j] == 1) {
System.out.print(\"+ \");
} else {
System.out.print(\"X \");
}
}
}
}
} else {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray1[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray1[i][j] == 0) {
System.out.print(\"- \");
} el.
In Java using Eclipse, Im suppose to write a class that encapsulat.pdf
In Java using Eclipse, I\'m suppose to write a class that encapsulates a tic tac toe board using two
dimensional arrays. It should only involve the human player vs. the computer, and should
randomly select who should use \'X\' or \'O\' and whether the human player or the computer
should go first. Verify that all moves by the human player are to a valid space on the tic-tac-toe
board, and an incorrect choice should not halt or terminate the game. Below is my Java program
that is currently a work in progress. Can you help me remodify it? Thanks.
import java.util.Scanner;
public class LeavinesTicTacToe
{
public static Scanner sc = new Scanner(System.in);
public static void main(String[] args)
{
final int SIZE = 3;
char[][] board = new char[SIZE][SIZE]; // game board
resetBoard(board); // initialize the board (with \' \' for all cells)
// First, welcome message and display the board.
System.out.println(\"===== WELCOME TO THE TIC-TAC-TOE GAME!! =====\ \");
showBoard(board);
// Then ask the user which symbol (x or o) he/she wants to play.
System.out.print(\" Which symbol do you want to play, \\\"x\\\" or \\\"o\\\"? \");
char userSymbol = sc.next().toLowerCase().charAt(0);
char compSymbol = (userSymbol == \'x\') ? \'o\' : \'x\';
// Also ask whether or not the user wants to go first.
System.out.println();
System.out.print(\" Do you want to go first (y/n)? \");
char ans = sc.next().toLowerCase().charAt(0);
int turn; // 0 -- the user, 1 -- the computer
int remainCount = SIZE * SIZE; // empty cell count
// THE VERY FIRST MOVE.
if (ans == \'y\') {
turn = 0;
userPlay(board, userSymbol); // user puts his/her first tic
}
else {
turn = 1;
compPlay(board, compSymbol); // computer puts its first tic
}
// Show the board, and decrement the count of remaining cells.
showBoard(board);
remainCount--;
// Play the game until either one wins.
boolean done = false;
int winner = -1; // 0 -- the user, 1 -- the computer, -1 -- draw
while (!done && remainCount > 0) {
// If there is a winner at this time, set the winner and the done flag to true.
done = isGameWon(board, turn, userSymbol, compSymbol); // Did the turn won?
if (done)
winner = turn; // the one who made the last move won the game
else {
// No winner yet. Find the next turn and play.
turn = (turn + 1 ) % 2;
if (turn == 0)
userPlay(board, userSymbol);
else
compPlay(board, compSymbol);
// Show the board after one tic, and decrement the rem count.
showBoard(board);
remainCount--;
}
}
// Winner is found. Declare the winner.
if (winner == 0)
System.out.println(\"\ ** YOU WON. CONGRATULATIONS!! **\");
else if (winner == 1)
System.out.println(\"\ ** YOU LOST.. Maybe next time :) **\");
else
System.out.println(\"\ ** DRAW... **\");
}
public static void resetBoard(char[][] brd)
{
for (int i = 0; i < brd.length; i++)
for (int j = 0; j < brd[0].length; j++)
brd[i][j] = \' \';
}
public static void showBoard(char[][] brd)
{
int numRow = brd.length;
int numCol = brd[0].length;
System.out.println();
// First write the column he.
The main class of the tictoe game looks like.public class Main {.pdf
The main class of the tictoe game looks like.
public class Main {
public void play() {
TicTacToe game = new TicTacToe();
System.out.println(\"Welcome! Tic Tac Toe is a two player game.\");
System.out.print(\"Enter player one\'s name: \");
game.setPlayer1(game.getPrompt());
System.out.print(\"Enter player two\'s name: \");
game.setPlayer2(game.getPrompt());
boolean markerOk = false;
while (!markerOk) {
System.out.print(\"Select any letter as \" + game.getPlayer1() + \"\'s marker: \");
String marker = game.getPrompt();
if (marker.length() == 1 &&
Character.isLetter(marker.toCharArray()[0])) {
markerOk = true;
game.setMarker1(marker.toCharArray()[0]);
} else {
System.out.println(\"Invalid marker, try again\");
}
}
markerOk = false;
while (!markerOk) {
System.out.print(\"Select any letter as \" + game.getPlayer2() + \"\'s marker: \");
String marker = game.getPrompt();
if (marker.length() == 1 &&
Character.isLetter(marker.toCharArray()[0])) {
markerOk = true;
game.setMarker2(marker.toCharArray()[0]);
} else {
System.out.println(\"Invalid marker, try again\");
}
}
boolean continuePlaying = true;
while (continuePlaying) {
game.init();
System.out.println();
System.out.println(game.getRules());
System.out.println();
System.out.println(game.drawBoard());
System.out.println();
String player = null;
while (!game.winner() && game.getPlays() < 9) {
player = game.getCurrentPlayer() == 1 ? game.getPlayer1() : game.getPlayer2();
boolean validPick = false;
while (!validPick) {
System.out.print(\"It is \" + player + \"\'s turn. Pick a square: \");
String square = game.getPrompt();
if (square.length() == 1 && Character.isDigit(square.toCharArray()[0])) {
int pick = 0;
try {
pick = Integer.parseInt(square);
} catch (NumberFormatException e) {
//Do nothing here, it\'ll evaluate as an invalid pick on the next row.
}
validPick = game.placeMarker(pick);
}
if (!validPick) {
System.out.println(\"Square can not be selected. Retry\");
}
}
game.switchPlayers();
System.out.println();
System.out.println(game.drawBoard());
System.out.println();
}
if (game.winner()) {
System.out.println(\"Game Over - \" + player + \" WINS!!!\");
} else {
System.out.println(\"Game Over - Draw\");
}
System.out.println();
System.out.print(\"Play again? (Y/N): \");
String choice = game.getPrompt();
if (!choice.equalsIgnoreCase(\"Y\")) {
continuePlaying = false;
}
}
}
public static void main(String[] args) {
Main main = new Main();
main.play();
}
}
The TicTacToe class code will be like
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
/**
*
* author Iamavinashkotina
*/
public class TicTacToe {
private char[][] board = new char[3][3];
private String player1;
private String player2;
private int currentPlayer;
private char marker1;
private char marker2;
private int plays;
private BufferedReader reader =
new BufferedReader(new InputStreamReader(System.in));
protected void init() {
int counter = 0;
for (int i = 0; i < 3; i++) {
for (int i1 = 0; i1 < 3; i1++) {.
Recommended
Find the output of the following code (Java for ICSE)
This document consists of some important practice questions for ICSE Class X Exams from the section of find the output. It is also supplemented with past years question papers
import java.util.Scanner;public class Main { public static in.pdf
import java.util.Scanner;
public class Main {
public static int gridArray1[][] = null;
public static int gridArray2[][] = null;
public static boolean playerTurn = true;
public static int count = 0;
public static void setGridDimensions(int x_max, int y_max) {
Main.gridArray1 = new int[x_max][y_max];
Main.gridArray2 = new int[x_max][y_max];
for (int i = 0; i < x_max; i++) {
for (int j = 0; j < y_max; j++) {
gridArray1[i][j] = -1;
gridArray2[i][j] = -1;
}
}
}
static void placeShip(int starting_x, int starting_y, int length, int direction) {
count++;
int ships[] = new int[10];
int battleshipArrayPositions1[] = new int[4];
int cruiserArrayPositions1[] = new int[3];
int submarineArrayPositions1[] = new int[3];
int destroyerArrayPositions1[] = new int[2];
int carrierArrayPositions2[] = new int[5];
int battleshipArrayPositions2[] = new int[4];
int cruiserArrayPositions2[] = new int[3];
int submarineArrayPositions2[] = new int[3];
int destroyerArrayPositions2[] = new int[2];
if (playerTurn) {
if (direction == 0) {
for (int i = starting_x; i < starting_x + length; i++) {
Main.gridArray1[i][starting_y] = 0;
}
} else {
for (int i = starting_y; i < starting_y + length; i++) {
Main.gridArray1[starting_x][i] = 0;
}
}
} else {
if (direction == 0) {
for (int i = starting_x; i < starting_x + length; i++) {
Main.gridArray2[i][starting_y] = 0;
}
} else {
for (int i = starting_y; i < starting_y + length; i++) {
Main.gridArray2[starting_x][i] = 0;
}
}
}
}
boolean isConflictingShipPlacement(int starting_x, int starting_y, int length, int direction) {
return false;
}
static int shoot(int x, int y) {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (Main.gridArray2[i][j] == 0) {
return 0;
}
}
}
} else {
}
return 0;
}
boolean hasBeenAttempted(int x, int y) {
return false;
}
static void displayGrid(boolean showShips) {
int count = 0;
System.out.print(\" 0 1 2 3 4 5 6 7 8 9\");
if (showShips) {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray1[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray1[i][j] == 0) {
System.out.print(\"@ \");
} else if (Main.gridArray1[i][j] == 1) {
System.out.print(\"+ \");
} else {
System.out.print(\"X \");
}
}
}
} else {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray2[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray2[i][j] == 0) {
System.out.print(\"@ \");
} else if (Main.gridArray2[i][j] == 1) {
System.out.print(\"+ \");
} else {
System.out.print(\"X \");
}
}
}
}
} else {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray1[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray1[i][j] == 0) {
System.out.print(\"- \");
} el.
In Java using Eclipse, Im suppose to write a class that encapsulat.pdf
In Java using Eclipse, I\'m suppose to write a class that encapsulates a tic tac toe board using two
dimensional arrays. It should only involve the human player vs. the computer, and should
randomly select who should use \'X\' or \'O\' and whether the human player or the computer
should go first. Verify that all moves by the human player are to a valid space on the tic-tac-toe
board, and an incorrect choice should not halt or terminate the game. Below is my Java program
that is currently a work in progress. Can you help me remodify it? Thanks.
import java.util.Scanner;
public class LeavinesTicTacToe
{
public static Scanner sc = new Scanner(System.in);
public static void main(String[] args)
{
final int SIZE = 3;
char[][] board = new char[SIZE][SIZE]; // game board
resetBoard(board); // initialize the board (with \' \' for all cells)
// First, welcome message and display the board.
System.out.println(\"===== WELCOME TO THE TIC-TAC-TOE GAME!! =====\ \");
showBoard(board);
// Then ask the user which symbol (x or o) he/she wants to play.
System.out.print(\" Which symbol do you want to play, \\\"x\\\" or \\\"o\\\"? \");
char userSymbol = sc.next().toLowerCase().charAt(0);
char compSymbol = (userSymbol == \'x\') ? \'o\' : \'x\';
// Also ask whether or not the user wants to go first.
System.out.println();
System.out.print(\" Do you want to go first (y/n)? \");
char ans = sc.next().toLowerCase().charAt(0);
int turn; // 0 -- the user, 1 -- the computer
int remainCount = SIZE * SIZE; // empty cell count
// THE VERY FIRST MOVE.
if (ans == \'y\') {
turn = 0;
userPlay(board, userSymbol); // user puts his/her first tic
}
else {
turn = 1;
compPlay(board, compSymbol); // computer puts its first tic
}
// Show the board, and decrement the count of remaining cells.
showBoard(board);
remainCount--;
// Play the game until either one wins.
boolean done = false;
int winner = -1; // 0 -- the user, 1 -- the computer, -1 -- draw
while (!done && remainCount > 0) {
// If there is a winner at this time, set the winner and the done flag to true.
done = isGameWon(board, turn, userSymbol, compSymbol); // Did the turn won?
if (done)
winner = turn; // the one who made the last move won the game
else {
// No winner yet. Find the next turn and play.
turn = (turn + 1 ) % 2;
if (turn == 0)
userPlay(board, userSymbol);
else
compPlay(board, compSymbol);
// Show the board after one tic, and decrement the rem count.
showBoard(board);
remainCount--;
}
}
// Winner is found. Declare the winner.
if (winner == 0)
System.out.println(\"\ ** YOU WON. CONGRATULATIONS!! **\");
else if (winner == 1)
System.out.println(\"\ ** YOU LOST.. Maybe next time :) **\");
else
System.out.println(\"\ ** DRAW... **\");
}
public static void resetBoard(char[][] brd)
{
for (int i = 0; i < brd.length; i++)
for (int j = 0; j < brd[0].length; j++)
brd[i][j] = \' \';
}
public static void showBoard(char[][] brd)
{
int numRow = brd.length;
int numCol = brd[0].length;
System.out.println();
// First write the column he.
The main class of the tictoe game looks like.public class Main {.pdf
The main class of the tictoe game looks like.
public class Main {
public void play() {
TicTacToe game = new TicTacToe();
System.out.println(\"Welcome! Tic Tac Toe is a two player game.\");
System.out.print(\"Enter player one\'s name: \");
game.setPlayer1(game.getPrompt());
System.out.print(\"Enter player two\'s name: \");
game.setPlayer2(game.getPrompt());
boolean markerOk = false;
while (!markerOk) {
System.out.print(\"Select any letter as \" + game.getPlayer1() + \"\'s marker: \");
String marker = game.getPrompt();
if (marker.length() == 1 &&
Character.isLetter(marker.toCharArray()[0])) {
markerOk = true;
game.setMarker1(marker.toCharArray()[0]);
} else {
System.out.println(\"Invalid marker, try again\");
}
}
markerOk = false;
while (!markerOk) {
System.out.print(\"Select any letter as \" + game.getPlayer2() + \"\'s marker: \");
String marker = game.getPrompt();
if (marker.length() == 1 &&
Character.isLetter(marker.toCharArray()[0])) {
markerOk = true;
game.setMarker2(marker.toCharArray()[0]);
} else {
System.out.println(\"Invalid marker, try again\");
}
}
boolean continuePlaying = true;
while (continuePlaying) {
game.init();
System.out.println();
System.out.println(game.getRules());
System.out.println();
System.out.println(game.drawBoard());
System.out.println();
String player = null;
while (!game.winner() && game.getPlays() < 9) {
player = game.getCurrentPlayer() == 1 ? game.getPlayer1() : game.getPlayer2();
boolean validPick = false;
while (!validPick) {
System.out.print(\"It is \" + player + \"\'s turn. Pick a square: \");
String square = game.getPrompt();
if (square.length() == 1 && Character.isDigit(square.toCharArray()[0])) {
int pick = 0;
try {
pick = Integer.parseInt(square);
} catch (NumberFormatException e) {
//Do nothing here, it\'ll evaluate as an invalid pick on the next row.
}
validPick = game.placeMarker(pick);
}
if (!validPick) {
System.out.println(\"Square can not be selected. Retry\");
}
}
game.switchPlayers();
System.out.println();
System.out.println(game.drawBoard());
System.out.println();
}
if (game.winner()) {
System.out.println(\"Game Over - \" + player + \" WINS!!!\");
} else {
System.out.println(\"Game Over - Draw\");
}
System.out.println();
System.out.print(\"Play again? (Y/N): \");
String choice = game.getPrompt();
if (!choice.equalsIgnoreCase(\"Y\")) {
continuePlaying = false;
}
}
}
public static void main(String[] args) {
Main main = new Main();
main.play();
}
}
The TicTacToe class code will be like
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
/**
*
* author Iamavinashkotina
*/
public class TicTacToe {
private char[][] board = new char[3][3];
private String player1;
private String player2;
private int currentPlayer;
private char marker1;
private char marker2;
private int plays;
private BufferedReader reader =
new BufferedReader(new InputStreamReader(System.in));
protected void init() {
int counter = 0;
for (int i = 0; i < 3; i++) {
for (int i1 = 0; i1 < 3; i1++) {.
package Assignment;import java.util.;public class assignment .pdf
package Assignment;
import java.util.*;
public class assignment
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
String repeat = \"\";
do
{
byte [][] map1 = {};
byte positionx = 54, positiony = 17 , finishx = 2 , finishy = 1;
String z = \" \";
String movement = \"\";
String done = \"\";
do
{
for (int i = 1 ; i <= 25 ; i++)
System.out.println();
for (int y = 0 ; y <= map1.length-1 ; y++)
{
for (int x = 0 ; x <= map1[1].length-1 ; x++)
{
if (x == positionx && y == positiony)
{
System.out.print(z);
}
else if(y == finishy && x == finishx)
{
System.out.print(\"X\");
}
else if (map1[y][x]==1)
{
System.out.print(\"?\");
}
else
{
System.out.print(\" \");
}
}
System.out.println();
}
System.out.println(\"W = up , A = left , S = down , D = right\");
System.out.print(\"Input Movement = \");
movement = input.nextLine();
if (movement.equalsIgnoreCase(\"a\"))
{
positionx--;
if (map1[positiony][positionx]==1)
positionx++;
}
else if(movement.equalsIgnoreCase(\"w\"))
{
positiony--;
if(map1[positiony][positionx]==1)
positiony++;
}
else if (movement.equalsIgnoreCase(\"S\"))
{
positiony++;
if(map1[positiony][positionx]==1)
positiony--;
}
else if(movement.equalsIgnoreCase(\"d\"))
{
positionx++;
if(map1[positiony][positionx]==1)
positionx--;
}
}
while (positionx!=finishx ||positiony!=finishy);
System.out.println(\"Good Job, you have passed stage 1\");
input.nextLine();
byte [][] map2 = { };
byte positionx2 = 54, positiony2 = 17 , finishx2 = 2 , finishy2 = 1;
String movement2 = \"\";
String done2 = \"\";
do
{
for (int i = 1 ; i <= 25 ; i++)
System.out.println();
for (int y = 0 ; y <= map2.length-1 ; y++)
{
for (int x = 0 ; x <= map2[1].length-1 ; x++)
{
if (x == positionx2 && y == positiony2)
{
System.out.print(z);
}
else if(y == finishy2 && x == finishx2)
{
System.out.print(\"X\");
}
else if (map2[y][x]==1)
{
System.out.print(\"?\");
}
else
{
System.out.print(\" \");
}
}
System.out.println();
}
System.out.println(\"W = up , A = left , S = down , D = right\");
System.out.print(\"Input Movement = \");
movement2 = input.nextLine();
if (movement2.equalsIgnoreCase(\"a\"))
{
positionx2--;
if (map2[positiony2][positionx2]==1)
positionx2++;
}
else if(movement2.equalsIgnoreCase(\"w\"))
{
positiony2--;
if(map2[positiony2][positionx2]==1)
positiony2++;
}
else if (movement2.equalsIgnoreCase(\"S\"))
{
positiony2++;
if(map2[positiony2][positionx2]==1)
positiony2--;
}
else if(movement2.equalsIgnoreCase(\"d\"))
{
positionx2++;
if(map2[positiony2][positionx2]==1)
positionx2--;
}
}
while(positionx2!=finishx2 ||positiony2!=finishy2);
System.out.println(\"Good Job, you have passed stage 2\");
input.nextLine();
byte [][] map3 = {};
byte positionx3 = 54, positiony3 = 17 , finishx3 = 2 , finishy3 = 1;
String movement3 = \"\";
String done3 = \"\";
do
{
for (int i = 1 ; i <= 25 ; i++)
System.out.println();
for (int y = 0 ; y <= map3.length-1 ; y++)
{
for (int x = 0 ; x <= map3[1].length-1 ; x++)
{
if (x == positionx3 && y == positiony3)
{
System.out.print(.
Utility Classes Are Killing Us
JBreak 2017; Novosibirsk, Russia; 4 April 2017; video is here: https://www.youtube.com/watch?v=85B3FV_sB60
Java Programpublic class Fraction { instance variablesin.pdf
Java Program
public class Fraction {
//instance variables
int num;
int den;
//default construtcor
Fraction()
{
num=0;
den=1;
}
//parametrized constructor
Fraction(int n,int d)
{
num=n;
den=d;
}
//print fraction object
public void print()
{
System.out.println(num+\"/\"+den);
}
//return double value of fraction
public void printAsDouble()
{
try
{
double div=(double)num/(double)den;
System.out.println(div);
}
catch(ArithmeticException e)
{
System.out.println(\"infinity\");
}
catch(Exception e)
{
System.out.println(e);
}
}
//add two fractions
public Fraction add(Fraction param)
{
int tnum=(this.num *param.den)+(this.den*param.num);
int tden=this.den*param.den;
this.num=tnum;
this.den=tden;
return this;
}
//multiply two fractions
public Fraction multiply(Fraction param)
{
int tnum=(this.num *param.num);
int tden=this.den*param.den;
this.num=tnum;
this.den=tden;
return this;
}
}
public static void main(String[] args)
{
Scanner stdIn = new Scanner(System.in);
Fraction c, d, x; // Fraction objects
System.out.println(\"Enter numerator; then denominator.\");
c = new Fraction(stdIn.nextInt(), stdIn.nextInt());
c.print();
System.out.println(\"Enter numerator; then denominator.\");
d = new Fraction(stdIn.nextInt(), stdIn.nextInt());
d.print();
x = new Fraction(); // create a fraction for number 0
System.out.println(\"Sum:\");
x.add(c).add(d);
x.print();
x.printAsDouble();
x = new Fraction(1, 1); // create a fraction for number 1
System.out.println(\"Product:\");
x.multiply(c).multiply(d);
x.print();
x.printAsDouble();
System.out.println(\"Enter numerator; then denominator.\");
x = new Fraction(stdIn.nextInt(), stdIn.nextInt());
x.printAsDouble();
} //end main Modify the code so that it can handle negative numerators and negative
denominators, and provide a helping method that performs fraction reduction. Sample session
using negative numbers and reduction Enter numerator, then denominator. -5 -8 5/8 Enter
numerator, then denominator. 4 -10 2/5 Sum: 9/40 0.225 Product: 0.25 Enter numerator, then
denominator. 0 -0 indeterminate
Solution
//Fraction.java
import java.util.Scanner;
public class Fraction {
//instance variables
int num;
int den;
//default construtcor
Fraction()
{
num=0;
den=1;
}
// greatest common divisor to reduce fraction
int gcd(int n1, int n2)
{
if (n2 != 0)
return gcd(n2, n1 % n2);
else
return n1;
}
//parametrized constructor
Fraction(int n,int d)
{
num=n;
den=d;
if(d == 0)
{
System.out.println(\"indeterminate\");
System.exit(1);
}
int hcf = gcd(num,den);
num = num/hcf;
den = den/hcf;
}
//print fraction object
public void print()
{
if( (num < 0 && den > 0))
System.out.println(num+\"/\"+den);
else if((num > 0 && den < 0))
System.out.println(\"-\" + num+\"/\"+ (-1*den));
else if(num < 0 && den < 0)
System.out.println( (-1*num)+\"/\"+ (-1*den));
else
System.out.println(num+\"/\"+den);
}
//return double value of fraction
public void printAsDouble()
{
try
{
double div=(double)num/(double)den;
System.out.println(div);
}
catch(ArithmeticException e.
public interface Game Note interface in place of class { .pdf
public interface Game // Note *interface* in place of *class*
{
/// play the game and return the final score
/// where a higher score should be better,
/// and a negative score is allowed.
int play(); // Note semicolon in place of a body
// You can have multiple method headings declared
}
--------------------------------------------------------------------------------------------------------------
import java.util.*;
/// Starting point for Interface Lab.
public class PlayGames
{
private static Scanner in;
private static Random rand = new Random();
private static int gameCount = 0;
public static Game popRandom(Game[] g)
{
int n = gameCount;
int i = rand.nextInt(n);
Game ret = g[i];
g[i] = g[n-1];
gameCount--;
return ret;
}
public static void main(String[] args)
{
Game[] games = new Game[10]; // Note Game as a type
games[gameCount] = new AdditionGame(rand, 100);
gameCount++; // next index to put a Game at
// write at least 2 more different types of Game classes
// and add a new one of each type to games
// ...
in = new Scanner(System.in);
int totScore = 0;
do {
Game g = popRandom(games);
totScore += g.play(); // use numerical result from the game
} while (gameCount > 0 && agree(\"Want a game? \"));
System.out.println(\"Thanks for Playing!\");
System.out.println(\"Your total score is \" + totScore);
}
public static boolean agree(String prompt)
{
System.out.print(prompt);
String input = in.next();
if (input.equalsIgnoreCase(\"y\")) return true;
return false;
}
--------------------------------------------------------------------------------------------------------------------
--
import java.util.*;
public class AdditionGame implements Game // note implements!!
{
private Random rand;
private int n;
// Constructor for objects of class AdditionGame
public AdditionGame(Random r, int big)
{
rand = r;
n = big;
}
// play all games and keep score.
public int play() // exactly matches heading in Game interface
{
final int numGames = 3;
Scanner in = new Scanner(System.in);
int score = 0;
System.out.println(\"Welcome to the addition game! We\'ll now play \" + numGames
+ \" rounds.\");
for (int i = 0; i < numGames; i++) {
int x = rand.nextInt(n), y = rand.nextInt(n), ans = x+y;
System.out.print(String.format(\"Enter the sum: %d + %d = \", x, y));
int val = in.nextInt();
if (ans == val) {
System.out.println(\"Correct!\");
score++;
}
else
System.out.println(\"Wrong! Right answer is \" + ans);
}
System.out.println(\"Thanks for playing the addition game. Your score is \" + score +
\".\");
System.out.println();
return score;
}
}
--------------------------------------------------------------------------------------------------------------------
---
Create two classes that implement a Game interface:
------------------------------------
There is a Game interface defined, and also a PlayGames class that uses objects from classes that
implement that interface. The Game interface declares a single abstract method play that returns
an int, the score from playing the gam.
Team public class Team { private String teamId; priva.pdf
Team:
public class Team {
private String teamId;
private String name;
private String firstName;
private String lastName;
private String phoneNumber;
private String emailAddress;
Team(String teamId, String name, String firstName, String lastName, String phoneNumber,
String emailAddress) {
this.teamId = teamId;
this.name = name;
this.firstName = firstName;
this.lastName = lastName;
this.phoneNumber = phoneNumber;
this.emailAddress = emailAddress;
}
public String getTeamId() {
return teamId;
}
public void setTeamId(String teamId) {
this.teamId = teamId;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getPhoneNumber() {
return phoneNumber;
}
public void setPhoneNumber(String phoneNumber) {
this.phoneNumber = phoneNumber;
}
public String getEmailAddress() {
return emailAddress;
}
public void setEmailAddress(String emailAddress) {
this.emailAddress = emailAddress;
}
public static boolean checkEmailAddress(String emailAddress) {
return emailAddress.contains(\"@\");
}
@Override
public String toString() {
return \"Team [teamId=\" + teamId + \", name=\" + name + \", firstName=\" + firstName +
\", lastName=\" + lastName
+ \", phoneNumber=\" + phoneNumber + \", emailAddress=\" + emailAddress + \"]\";
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((emailAddress == null) ? 0 : emailAddress.hashCode());
result = prime * result + ((firstName == null) ? 0 : firstName.hashCode());
result = prime * result + ((lastName == null) ? 0 : lastName.hashCode());
result = prime * result + ((name == null) ? 0 : name.hashCode());
result = prime * result + ((phoneNumber == null) ? 0 : phoneNumber.hashCode());
result = prime * result + ((teamId == null) ? 0 : teamId.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Team other = (Team) obj;
if (emailAddress == null) {
if (other.emailAddress != null)
return false;
} else if (!emailAddress.equals(other.emailAddress))
return false;
if (firstName == null) {
if (other.firstName != null)
return false;
} else if (!firstName.equals(other.firstName))
return false;
if (lastName == null) {
if (other.lastName != null)
return false;
} else if (!lastName.equals(other.lastName))
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
if (phoneNumber == null) {
if (other.phoneNumber != null)
return false;
} else if (!phoneNumber.equals(other.phoneNumber))
return false;
if (teamId == null) {
if (other.teamId != null)
return false;
} else if (!teamId.equals(other.teamId))
return false;
r.
import java.util.Scanner;public class Main {private static i.pdf
import java.util.Scanner;
public class Main {
private static int n;
private static int[] referenceString;
private static int[] physicalFrames;
private static int[] victimPages;
private static int pageFaults;
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int choice;
do {
System.out.println("0 Exit");
System.out.println("1 Input N");
System.out.println("2 Input the reference string");
System.out.println("3 Simulate the OPT algorithm");
System.out.println("4 Simulate the NEW algorithm");
System.out.print("Select option: ");
choice = input.nextInt();
switch (choice) {
case 0:
System.out.println("Exiting the program...");
break;
case 1:
System.out.print("Enter the value of N (2-8): ");
n = input.nextInt();
if (n < 2 || n > 8) {
System.out.println("Invalid value of N!");
n = 0;
} else {
physicalFrames = new int[n];
victimPages = new int[n];
System.out.println("N set to " + n + ".");
}
break;
case 2:
if (n == 0) {
System.out.println("Please enter the value of N first!");
} else {
System.out.print("Enter the reference string (length at least " + n + ", max length 20): ");
String[] strArr = input.next().split("");
int len = strArr.length;
if (len < n || len > 20) {
System.out.println("Invalid length of reference string!");
} else {
referenceString = new int[len];
for (int i = 0; i < len; i++) {
int page = Integer.parseInt(strArr[i]);
if (page < 0 || page > 9) {
System.out.println("Invalid page number!");
referenceString = null;
break;
}
referenceString[i] = page;
}
if (referenceString != null) {
System.out.println("Reference string set to " + input.next() + ".");
}
}
}
break;
case 3:
if (n == 0) {
System.out.println("Please enter the value of N first!");
} else if (referenceString == null) {
System.out.println("Please enter the reference string first!");
} else {
System.out.println("Simulating the OPT algorithm...");
simulateOPT();
}
break;
case 4:
if (n == 0) {
System.out.println("Please enter the value of N first!");
} else if (referenceString == null) {
System.out.println("Please enter the reference string first!");
} else {
System.out.println("Simulating the NEW algorithm...");
simulateNEW();
}
break;
default:
System.out.println("Invalid choice!");
break;
}
System.out.println();
} while (choice != 0);
}
private static void simulateOPT() {
pageFaults = 0;
int len = referenceString.length;
System.out.println("Reference String\tPhysical Frames\tPage Faults\tVictim Pages");
for (int i = 0; i < len; i++) {
int page = referenceString[i];
boolean found = false;
for (int j = 0; j < n; j++) {
if (physicalFrames[j] == page) {
found = true;
break;
}
}
if (!found) {
pageFaults++;
int maxDist = 0;
int victimPage = -1;
for (int j = 0; j < n; j++) {
int dist = 0;
for (int k = i + 1; k < len; k++) {
dist++;
if (physicalFrames[j] == referenceString[k]) {
break;
}
}
if (dist > maxDist) {
maxDist = dist;
victimPage = j;
}
}
physicalFrames[victimPage] = page;
victimPages[i] = physicalFrames[victimPage];
} else {
victimPages[i] = -1;.
You will write a multi-interface version of the well-known concentra.pdf
You will write a multi-interface version of the well-known concentration game: 1. The game
displays a grid of upper-case letters, with each letter appearing twice. 2. A player has a few
seconds to memorize the letters before they disappear. 3. The player then has to remember where
each pair was located.
line, then MultiConcentration starts with the text interface.
First the new game display will show the user the pairs he/she must guess, in a format similar to
the following example for size = 6
D H B C M I
H G K K A R
C N R E O E
Q O A Q L F
L F J P B G
P D N M I J
Memorize the above grid!
Note that the new game display uses pairs of distinct single uppercase capital letters distributed
at random on a square grid, starting at A and continuing until the grid is full.
This new game display shows for 10 seconds, after which it scrolls out of view. (To scroll it just
write about 25 newlines.) Then the standard game display appears.
The standard game display will look like the following example for size = 6
1 2 3 4 5 6
7 8 9 10 11 12
13 14 15 16 17 18
19 20 21 22 23 24
25 26 27 28 29 30
21 32 33 34 35 36
Enter a pair of numbers, or \"R\" to reset, or \"Q\" to quit:
reset, or \"Q\" to quit:
If the player makes an invalid entry (e.g. numbers out of range, number already guessed, no
blank separator, etc.) then a \"please reenter\" message is printed and the same display is shown
again.
If the player makes a bad guess, then a \"Sorry...\" message is printed and the same display is
shown again.
If the player enters an \"R\" for reset, then we start over, that is, the computer calculates a new
set of pairs and shows the new game display again.
If the player enters a \"Q\" for quit, then the game prints a \"Game Over\" message and ends.
3.4 Graphic Game Interface
If the player used the \"-g\" flag on the startup command line then MultiConcentration starts up
with the graphic interface.
You may design the graphic interface as you choose, as long as you use Swing and preserve the
steps in the game as described in the previous section.
One possible graphic interface is shown in Figure 1. In this design the new game display and the
standard game display have been replaced by a grid of buttons. Instead of entering pairs of
numbers, the player clicks on two of the buttons. The \"reset\" and \"quit\" commands are given
using a menu. Letters that have been correctly guessed are shown with a pink background color.
Messages to the player are shown in a text area under the grid.
4 GENERAL REQUIREMENTS
4.1 Design Requirements
Design your program with GUI classes, a main class, and Application Logic / Data classes as
described in my overheads on Design for Testability.
Do not use a package statement; name the main class MultiConcentration. (Otherwise the
startup command given in 3.1 would not work.)
You should have at least 5 classes, and not one of them should have more than 40% of the code.
Solution
import java.io.OutputStream;
import java.io.PrintStream;
public cl.
The following code, is a one player battleship game in JAVA. Im tryi.pdf
The following code, is a one player battleship game in JAVA. Im trying to Enhance the game to
be a two player game (were a player plays aggainst a computer opponent). With TWO boards
displayed side by side. The player and the computer must take turns selecting the coordinates on
their own boards. (the ships cannot be placed adjacent to each other).
BattleShipGame.java
package battleship;
import java.util.ArrayList;
import java.util.Scanner;
public class BattleshipGame {
private Ocean ocean;
private boolean[][] availableSpot;
private Scanner sc;
public BattleshipGame() {
// define a new ocean and a new 2D array to store available coordinates
ocean = new Ocean();
availableSpot = new boolean[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++){
availableSpot[i][j] = true;
}
}
}
/**
* prints the game menu and info
* //param select
*/
public void print(int select){
String info;
switch (select) {
case 1: info = \"Welcome to the World of Battleship!\";
break;
case 2: info = \"Enter coordinates to fire: \";
break;
case 3: info = \"Shots fired: \"+ocean.getShotsFired()+\", Ships sunk:
\"+ocean.getShipsSunk();
break;
case 4: info = \"Congratulations! You win!\";
break;
case 99: info = \"Invalid input. Please re-enter:\";
break;
case 100: info = \"--------------------------------------------\";
break;
case 101: info = \"\ ============================================\";
break;
default: info = \"Error selection\";
break;
}
System.out.println(info);
}
/**
* check if the input is valid
* //param input
* //return boolean
*/
public boolean checkValidInput(String input){
ArrayList numList = new ArrayList();
for (int i=0;i<10;i++){
numList.add(\"\"+i);
}
String[] coordinates = input.split(\" \");
//returns false if there are not 2 strings
if (coordinates.length!=2){
return false;
}
//returns false if any of the strings is not a single digit number
for (String str: coordinates){
if (numList.contains(str)==false){
return false;
}
}
//returns false if the coordinates have already been shot at
int row = Integer.parseInt(coordinates[0]);
int column = Integer.parseInt(coordinates[1]);
if (this.availableSpot[row][column]==false){
return false;
}
return true;
}
/**
* get the coordinates to shoot at from the String input
* //param input
* //return int[] coordinates
*/
public int[] getCoordinates(String input){
int[] coordinates = new int[2];
String[] strList = input.split(\" \");
int row = Integer.parseInt(strList[0]);
int column = Integer.parseInt(strList[1]);
coordinates[0] = row;
coordinates[1] = column;
return coordinates;
}
/**
* play the battleship game
*/
public void play(){
print(101);
print(1);
ocean.placeAllShipsRandomly();
boolean isGameOver = ocean.isGameOver();
sc = new Scanner(System.in);
//print the ocean and start the game
ocean.print();
print(3);
while (!isGameOver){
print(2);
String input = sc.nextLine();
//check if input is valid
while (!checkValidInput(input)){
print(99);
input = sc.nextLine();
}
//get coordinates and fire
int[] coord.
1) (i)Finance (H)(ii) Corporation (J)(iii) Treasurer (G)(iv) L.pdf
1) (i)Finance (H)
(ii) Corporation (J)
(iii) Treasurer (G)
(iv) Limited Liability (I)
(v) Business Ethics (C)
(vi) Limited Partner (D)
(vii) Double taxation of dividends (A)
(viii) Shareholder wealth maximisation (B)
(ix) Stakeholder (E)
(x) Value (F)
2) The CFO in a company is responsible for Accounting, investments and Research and
development departments.
Solution
1) (i)Finance (H)
(ii) Corporation (J)
(iii) Treasurer (G)
(iv) Limited Liability (I)
(v) Business Ethics (C)
(vi) Limited Partner (D)
(vii) Double taxation of dividends (A)
(viii) Shareholder wealth maximisation (B)
(ix) Stakeholder (E)
(x) Value (F)
2) The CFO in a company is responsible for Accounting, investments and Research and
development departments..
let no, na,nw be the refractive indices of oil, air and waterrespec.pdf
let no, na,nw be the refractive indices of oil, air and waterrespectively then from snells law
Solution
let no, na,nw be the refractive indices of oil, air and waterrespectively then from snells law.
More Related Content
Similar to MineSweeper.java public class MS { public static void main(Strin.pdf
package Assignment;import java.util.;public class assignment .pdf
package Assignment;
import java.util.*;
public class assignment
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
String repeat = \"\";
do
{
byte [][] map1 = {};
byte positionx = 54, positiony = 17 , finishx = 2 , finishy = 1;
String z = \" \";
String movement = \"\";
String done = \"\";
do
{
for (int i = 1 ; i <= 25 ; i++)
System.out.println();
for (int y = 0 ; y <= map1.length-1 ; y++)
{
for (int x = 0 ; x <= map1[1].length-1 ; x++)
{
if (x == positionx && y == positiony)
{
System.out.print(z);
}
else if(y == finishy && x == finishx)
{
System.out.print(\"X\");
}
else if (map1[y][x]==1)
{
System.out.print(\"?\");
}
else
{
System.out.print(\" \");
}
}
System.out.println();
}
System.out.println(\"W = up , A = left , S = down , D = right\");
System.out.print(\"Input Movement = \");
movement = input.nextLine();
if (movement.equalsIgnoreCase(\"a\"))
{
positionx--;
if (map1[positiony][positionx]==1)
positionx++;
}
else if(movement.equalsIgnoreCase(\"w\"))
{
positiony--;
if(map1[positiony][positionx]==1)
positiony++;
}
else if (movement.equalsIgnoreCase(\"S\"))
{
positiony++;
if(map1[positiony][positionx]==1)
positiony--;
}
else if(movement.equalsIgnoreCase(\"d\"))
{
positionx++;
if(map1[positiony][positionx]==1)
positionx--;
}
}
while (positionx!=finishx ||positiony!=finishy);
System.out.println(\"Good Job, you have passed stage 1\");
input.nextLine();
byte [][] map2 = { };
byte positionx2 = 54, positiony2 = 17 , finishx2 = 2 , finishy2 = 1;
String movement2 = \"\";
String done2 = \"\";
do
{
for (int i = 1 ; i <= 25 ; i++)
System.out.println();
for (int y = 0 ; y <= map2.length-1 ; y++)
{
for (int x = 0 ; x <= map2[1].length-1 ; x++)
{
if (x == positionx2 && y == positiony2)
{
System.out.print(z);
}
else if(y == finishy2 && x == finishx2)
{
System.out.print(\"X\");
}
else if (map2[y][x]==1)
{
System.out.print(\"?\");
}
else
{
System.out.print(\" \");
}
}
System.out.println();
}
System.out.println(\"W = up , A = left , S = down , D = right\");
System.out.print(\"Input Movement = \");
movement2 = input.nextLine();
if (movement2.equalsIgnoreCase(\"a\"))
{
positionx2--;
if (map2[positiony2][positionx2]==1)
positionx2++;
}
else if(movement2.equalsIgnoreCase(\"w\"))
{
positiony2--;
if(map2[positiony2][positionx2]==1)
positiony2++;
}
else if (movement2.equalsIgnoreCase(\"S\"))
{
positiony2++;
if(map2[positiony2][positionx2]==1)
positiony2--;
}
else if(movement2.equalsIgnoreCase(\"d\"))
{
positionx2++;
if(map2[positiony2][positionx2]==1)
positionx2--;
}
}
while(positionx2!=finishx2 ||positiony2!=finishy2);
System.out.println(\"Good Job, you have passed stage 2\");
input.nextLine();
byte [][] map3 = {};
byte positionx3 = 54, positiony3 = 17 , finishx3 = 2 , finishy3 = 1;
String movement3 = \"\";
String done3 = \"\";
do
{
for (int i = 1 ; i <= 25 ; i++)
System.out.println();
for (int y = 0 ; y <= map3.length-1 ; y++)
{
for (int x = 0 ; x <= map3[1].length-1 ; x++)
{
if (x == positionx3 && y == positiony3)
{
System.out.print(.
Utility Classes Are Killing Us
JBreak 2017; Novosibirsk, Russia; 4 April 2017; video is here: https://www.youtube.com/watch?v=85B3FV_sB60
Java Programpublic class Fraction { instance variablesin.pdf
Java Program
public class Fraction {
//instance variables
int num;
int den;
//default construtcor
Fraction()
{
num=0;
den=1;
}
//parametrized constructor
Fraction(int n,int d)
{
num=n;
den=d;
}
//print fraction object
public void print()
{
System.out.println(num+\"/\"+den);
}
//return double value of fraction
public void printAsDouble()
{
try
{
double div=(double)num/(double)den;
System.out.println(div);
}
catch(ArithmeticException e)
{
System.out.println(\"infinity\");
}
catch(Exception e)
{
System.out.println(e);
}
}
//add two fractions
public Fraction add(Fraction param)
{
int tnum=(this.num *param.den)+(this.den*param.num);
int tden=this.den*param.den;
this.num=tnum;
this.den=tden;
return this;
}
//multiply two fractions
public Fraction multiply(Fraction param)
{
int tnum=(this.num *param.num);
int tden=this.den*param.den;
this.num=tnum;
this.den=tden;
return this;
}
}
public static void main(String[] args)
{
Scanner stdIn = new Scanner(System.in);
Fraction c, d, x; // Fraction objects
System.out.println(\"Enter numerator; then denominator.\");
c = new Fraction(stdIn.nextInt(), stdIn.nextInt());
c.print();
System.out.println(\"Enter numerator; then denominator.\");
d = new Fraction(stdIn.nextInt(), stdIn.nextInt());
d.print();
x = new Fraction(); // create a fraction for number 0
System.out.println(\"Sum:\");
x.add(c).add(d);
x.print();
x.printAsDouble();
x = new Fraction(1, 1); // create a fraction for number 1
System.out.println(\"Product:\");
x.multiply(c).multiply(d);
x.print();
x.printAsDouble();
System.out.println(\"Enter numerator; then denominator.\");
x = new Fraction(stdIn.nextInt(), stdIn.nextInt());
x.printAsDouble();
} //end main Modify the code so that it can handle negative numerators and negative
denominators, and provide a helping method that performs fraction reduction. Sample session
using negative numbers and reduction Enter numerator, then denominator. -5 -8 5/8 Enter
numerator, then denominator. 4 -10 2/5 Sum: 9/40 0.225 Product: 0.25 Enter numerator, then
denominator. 0 -0 indeterminate
Solution
//Fraction.java
import java.util.Scanner;
public class Fraction {
//instance variables
int num;
int den;
//default construtcor
Fraction()
{
num=0;
den=1;
}
// greatest common divisor to reduce fraction
int gcd(int n1, int n2)
{
if (n2 != 0)
return gcd(n2, n1 % n2);
else
return n1;
}
//parametrized constructor
Fraction(int n,int d)
{
num=n;
den=d;
if(d == 0)
{
System.out.println(\"indeterminate\");
System.exit(1);
}
int hcf = gcd(num,den);
num = num/hcf;
den = den/hcf;
}
//print fraction object
public void print()
{
if( (num < 0 && den > 0))
System.out.println(num+\"/\"+den);
else if((num > 0 && den < 0))
System.out.println(\"-\" + num+\"/\"+ (-1*den));
else if(num < 0 && den < 0)
System.out.println( (-1*num)+\"/\"+ (-1*den));
else
System.out.println(num+\"/\"+den);
}
//return double value of fraction
public void printAsDouble()
{
try
{
double div=(double)num/(double)den;
System.out.println(div);
}
catch(ArithmeticException e.
public interface Game Note interface in place of class { .pdf
public interface Game // Note *interface* in place of *class*
{
/// play the game and return the final score
/// where a higher score should be better,
/// and a negative score is allowed.
int play(); // Note semicolon in place of a body
// You can have multiple method headings declared
}
--------------------------------------------------------------------------------------------------------------
import java.util.*;
/// Starting point for Interface Lab.
public class PlayGames
{
private static Scanner in;
private static Random rand = new Random();
private static int gameCount = 0;
public static Game popRandom(Game[] g)
{
int n = gameCount;
int i = rand.nextInt(n);
Game ret = g[i];
g[i] = g[n-1];
gameCount--;
return ret;
}
public static void main(String[] args)
{
Game[] games = new Game[10]; // Note Game as a type
games[gameCount] = new AdditionGame(rand, 100);
gameCount++; // next index to put a Game at
// write at least 2 more different types of Game classes
// and add a new one of each type to games
// ...
in = new Scanner(System.in);
int totScore = 0;
do {
Game g = popRandom(games);
totScore += g.play(); // use numerical result from the game
} while (gameCount > 0 && agree(\"Want a game? \"));
System.out.println(\"Thanks for Playing!\");
System.out.println(\"Your total score is \" + totScore);
}
public static boolean agree(String prompt)
{
System.out.print(prompt);
String input = in.next();
if (input.equalsIgnoreCase(\"y\")) return true;
return false;
}
--------------------------------------------------------------------------------------------------------------------
--
import java.util.*;
public class AdditionGame implements Game // note implements!!
{
private Random rand;
private int n;
// Constructor for objects of class AdditionGame
public AdditionGame(Random r, int big)
{
rand = r;
n = big;
}
// play all games and keep score.
public int play() // exactly matches heading in Game interface
{
final int numGames = 3;
Scanner in = new Scanner(System.in);
int score = 0;
System.out.println(\"Welcome to the addition game! We\'ll now play \" + numGames
+ \" rounds.\");
for (int i = 0; i < numGames; i++) {
int x = rand.nextInt(n), y = rand.nextInt(n), ans = x+y;
System.out.print(String.format(\"Enter the sum: %d + %d = \", x, y));
int val = in.nextInt();
if (ans == val) {
System.out.println(\"Correct!\");
score++;
}
else
System.out.println(\"Wrong! Right answer is \" + ans);
}
System.out.println(\"Thanks for playing the addition game. Your score is \" + score +
\".\");
System.out.println();
return score;
}
}
--------------------------------------------------------------------------------------------------------------------
---
Create two classes that implement a Game interface:
------------------------------------
There is a Game interface defined, and also a PlayGames class that uses objects from classes that
implement that interface. The Game interface declares a single abstract method play that returns
an int, the score from playing the gam.
Team public class Team { private String teamId; priva.pdf
Team:
public class Team {
private String teamId;
private String name;
private String firstName;
private String lastName;
private String phoneNumber;
private String emailAddress;
Team(String teamId, String name, String firstName, String lastName, String phoneNumber,
String emailAddress) {
this.teamId = teamId;
this.name = name;
this.firstName = firstName;
this.lastName = lastName;
this.phoneNumber = phoneNumber;
this.emailAddress = emailAddress;
}
public String getTeamId() {
return teamId;
}
public void setTeamId(String teamId) {
this.teamId = teamId;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getPhoneNumber() {
return phoneNumber;
}
public void setPhoneNumber(String phoneNumber) {
this.phoneNumber = phoneNumber;
}
public String getEmailAddress() {
return emailAddress;
}
public void setEmailAddress(String emailAddress) {
this.emailAddress = emailAddress;
}
public static boolean checkEmailAddress(String emailAddress) {
return emailAddress.contains(\"@\");
}
@Override
public String toString() {
return \"Team [teamId=\" + teamId + \", name=\" + name + \", firstName=\" + firstName +
\", lastName=\" + lastName
+ \", phoneNumber=\" + phoneNumber + \", emailAddress=\" + emailAddress + \"]\";
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((emailAddress == null) ? 0 : emailAddress.hashCode());
result = prime * result + ((firstName == null) ? 0 : firstName.hashCode());
result = prime * result + ((lastName == null) ? 0 : lastName.hashCode());
result = prime * result + ((name == null) ? 0 : name.hashCode());
result = prime * result + ((phoneNumber == null) ? 0 : phoneNumber.hashCode());
result = prime * result + ((teamId == null) ? 0 : teamId.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Team other = (Team) obj;
if (emailAddress == null) {
if (other.emailAddress != null)
return false;
} else if (!emailAddress.equals(other.emailAddress))
return false;
if (firstName == null) {
if (other.firstName != null)
return false;
} else if (!firstName.equals(other.firstName))
return false;
if (lastName == null) {
if (other.lastName != null)
return false;
} else if (!lastName.equals(other.lastName))
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
if (phoneNumber == null) {
if (other.phoneNumber != null)
return false;
} else if (!phoneNumber.equals(other.phoneNumber))
return false;
if (teamId == null) {
if (other.teamId != null)
return false;
} else if (!teamId.equals(other.teamId))
return false;
r.
import java.util.Scanner;public class Main {private static i.pdf
import java.util.Scanner;
public class Main {
private static int n;
private static int[] referenceString;
private static int[] physicalFrames;
private static int[] victimPages;
private static int pageFaults;
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int choice;
do {
System.out.println("0 Exit");
System.out.println("1 Input N");
System.out.println("2 Input the reference string");
System.out.println("3 Simulate the OPT algorithm");
System.out.println("4 Simulate the NEW algorithm");
System.out.print("Select option: ");
choice = input.nextInt();
switch (choice) {
case 0:
System.out.println("Exiting the program...");
break;
case 1:
System.out.print("Enter the value of N (2-8): ");
n = input.nextInt();
if (n < 2 || n > 8) {
System.out.println("Invalid value of N!");
n = 0;
} else {
physicalFrames = new int[n];
victimPages = new int[n];
System.out.println("N set to " + n + ".");
}
break;
case 2:
if (n == 0) {
System.out.println("Please enter the value of N first!");
} else {
System.out.print("Enter the reference string (length at least " + n + ", max length 20): ");
String[] strArr = input.next().split("");
int len = strArr.length;
if (len < n || len > 20) {
System.out.println("Invalid length of reference string!");
} else {
referenceString = new int[len];
for (int i = 0; i < len; i++) {
int page = Integer.parseInt(strArr[i]);
if (page < 0 || page > 9) {
System.out.println("Invalid page number!");
referenceString = null;
break;
}
referenceString[i] = page;
}
if (referenceString != null) {
System.out.println("Reference string set to " + input.next() + ".");
}
}
}
break;
case 3:
if (n == 0) {
System.out.println("Please enter the value of N first!");
} else if (referenceString == null) {
System.out.println("Please enter the reference string first!");
} else {
System.out.println("Simulating the OPT algorithm...");
simulateOPT();
}
break;
case 4:
if (n == 0) {
System.out.println("Please enter the value of N first!");
} else if (referenceString == null) {
System.out.println("Please enter the reference string first!");
} else {
System.out.println("Simulating the NEW algorithm...");
simulateNEW();
}
break;
default:
System.out.println("Invalid choice!");
break;
}
System.out.println();
} while (choice != 0);
}
private static void simulateOPT() {
pageFaults = 0;
int len = referenceString.length;
System.out.println("Reference String\tPhysical Frames\tPage Faults\tVictim Pages");
for (int i = 0; i < len; i++) {
int page = referenceString[i];
boolean found = false;
for (int j = 0; j < n; j++) {
if (physicalFrames[j] == page) {
found = true;
break;
}
}
if (!found) {
pageFaults++;
int maxDist = 0;
int victimPage = -1;
for (int j = 0; j < n; j++) {
int dist = 0;
for (int k = i + 1; k < len; k++) {
dist++;
if (physicalFrames[j] == referenceString[k]) {
break;
}
}
if (dist > maxDist) {
maxDist = dist;
victimPage = j;
}
}
physicalFrames[victimPage] = page;
victimPages[i] = physicalFrames[victimPage];
} else {
victimPages[i] = -1;.
You will write a multi-interface version of the well-known concentra.pdf
You will write a multi-interface version of the well-known concentration game: 1. The game
displays a grid of upper-case letters, with each letter appearing twice. 2. A player has a few
seconds to memorize the letters before they disappear. 3. The player then has to remember where
each pair was located.
line, then MultiConcentration starts with the text interface.
First the new game display will show the user the pairs he/she must guess, in a format similar to
the following example for size = 6
D H B C M I
H G K K A R
C N R E O E
Q O A Q L F
L F J P B G
P D N M I J
Memorize the above grid!
Note that the new game display uses pairs of distinct single uppercase capital letters distributed
at random on a square grid, starting at A and continuing until the grid is full.
This new game display shows for 10 seconds, after which it scrolls out of view. (To scroll it just
write about 25 newlines.) Then the standard game display appears.
The standard game display will look like the following example for size = 6
1 2 3 4 5 6
7 8 9 10 11 12
13 14 15 16 17 18
19 20 21 22 23 24
25 26 27 28 29 30
21 32 33 34 35 36
Enter a pair of numbers, or \"R\" to reset, or \"Q\" to quit:
reset, or \"Q\" to quit:
If the player makes an invalid entry (e.g. numbers out of range, number already guessed, no
blank separator, etc.) then a \"please reenter\" message is printed and the same display is shown
again.
If the player makes a bad guess, then a \"Sorry...\" message is printed and the same display is
shown again.
If the player enters an \"R\" for reset, then we start over, that is, the computer calculates a new
set of pairs and shows the new game display again.
If the player enters a \"Q\" for quit, then the game prints a \"Game Over\" message and ends.
3.4 Graphic Game Interface
If the player used the \"-g\" flag on the startup command line then MultiConcentration starts up
with the graphic interface.
You may design the graphic interface as you choose, as long as you use Swing and preserve the
steps in the game as described in the previous section.
One possible graphic interface is shown in Figure 1. In this design the new game display and the
standard game display have been replaced by a grid of buttons. Instead of entering pairs of
numbers, the player clicks on two of the buttons. The \"reset\" and \"quit\" commands are given
using a menu. Letters that have been correctly guessed are shown with a pink background color.
Messages to the player are shown in a text area under the grid.
4 GENERAL REQUIREMENTS
4.1 Design Requirements
Design your program with GUI classes, a main class, and Application Logic / Data classes as
described in my overheads on Design for Testability.
Do not use a package statement; name the main class MultiConcentration. (Otherwise the
startup command given in 3.1 would not work.)
You should have at least 5 classes, and not one of them should have more than 40% of the code.
Solution
import java.io.OutputStream;
import java.io.PrintStream;
public cl.
The following code, is a one player battleship game in JAVA. Im tryi.pdf
The following code, is a one player battleship game in JAVA. Im trying to Enhance the game to
be a two player game (were a player plays aggainst a computer opponent). With TWO boards
displayed side by side. The player and the computer must take turns selecting the coordinates on
their own boards. (the ships cannot be placed adjacent to each other).
BattleShipGame.java
package battleship;
import java.util.ArrayList;
import java.util.Scanner;
public class BattleshipGame {
private Ocean ocean;
private boolean[][] availableSpot;
private Scanner sc;
public BattleshipGame() {
// define a new ocean and a new 2D array to store available coordinates
ocean = new Ocean();
availableSpot = new boolean[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++){
availableSpot[i][j] = true;
}
}
}
/**
* prints the game menu and info
* //param select
*/
public void print(int select){
String info;
switch (select) {
case 1: info = \"Welcome to the World of Battleship!\";
break;
case 2: info = \"Enter coordinates to fire: \";
break;
case 3: info = \"Shots fired: \"+ocean.getShotsFired()+\", Ships sunk:
\"+ocean.getShipsSunk();
break;
case 4: info = \"Congratulations! You win!\";
break;
case 99: info = \"Invalid input. Please re-enter:\";
break;
case 100: info = \"--------------------------------------------\";
break;
case 101: info = \"\ ============================================\";
break;
default: info = \"Error selection\";
break;
}
System.out.println(info);
}
/**
* check if the input is valid
* //param input
* //return boolean
*/
public boolean checkValidInput(String input){
ArrayList numList = new ArrayList();
for (int i=0;i<10;i++){
numList.add(\"\"+i);
}
String[] coordinates = input.split(\" \");
//returns false if there are not 2 strings
if (coordinates.length!=2){
return false;
}
//returns false if any of the strings is not a single digit number
for (String str: coordinates){
if (numList.contains(str)==false){
return false;
}
}
//returns false if the coordinates have already been shot at
int row = Integer.parseInt(coordinates[0]);
int column = Integer.parseInt(coordinates[1]);
if (this.availableSpot[row][column]==false){
return false;
}
return true;
}
/**
* get the coordinates to shoot at from the String input
* //param input
* //return int[] coordinates
*/
public int[] getCoordinates(String input){
int[] coordinates = new int[2];
String[] strList = input.split(\" \");
int row = Integer.parseInt(strList[0]);
int column = Integer.parseInt(strList[1]);
coordinates[0] = row;
coordinates[1] = column;
return coordinates;
}
/**
* play the battleship game
*/
public void play(){
print(101);
print(1);
ocean.placeAllShipsRandomly();
boolean isGameOver = ocean.isGameOver();
sc = new Scanner(System.in);
//print the ocean and start the game
ocean.print();
print(3);
while (!isGameOver){
print(2);
String input = sc.nextLine();
//check if input is valid
while (!checkValidInput(input)){
print(99);
input = sc.nextLine();
}
//get coordinates and fire
int[] coord.
Similar to MineSweeper.java public class MS { public static void main(Strin.pdf (20)
package Assignment;import java.util.;public class assignment .pdf
package Assignment;import java.util.;public class assignment .pdf
81818088 isc-class-xii-computer-science-project-java-programs
81818088 isc-class-xii-computer-science-project-java-programs
Java Programpublic class Fraction { instance variablesin.pdf
Java Programpublic class Fraction { instance variablesin.pdf
public interface Game Note interface in place of class { .pdf
public interface Game Note interface in place of class { .pdf
Team public class Team { private String teamId; priva.pdf
Team public class Team { private String teamId; priva.pdf
import java.util.Scanner;public class Main {private static i.pdf
import java.util.Scanner;public class Main {private static i.pdf
You will write a multi-interface version of the well-known concentra.pdf
You will write a multi-interface version of the well-known concentra.pdf
The following code, is a one player battleship game in JAVA. Im tryi.pdf
The following code, is a one player battleship game in JAVA. Im tryi.pdf
More from aniyathikitchen
1) (i)Finance (H)(ii) Corporation (J)(iii) Treasurer (G)(iv) L.pdf
1) (i)Finance (H)
(ii) Corporation (J)
(iii) Treasurer (G)
(iv) Limited Liability (I)
(v) Business Ethics (C)
(vi) Limited Partner (D)
(vii) Double taxation of dividends (A)
(viii) Shareholder wealth maximisation (B)
(ix) Stakeholder (E)
(x) Value (F)
2) The CFO in a company is responsible for Accounting, investments and Research and
development departments.
Solution
1) (i)Finance (H)
(ii) Corporation (J)
(iii) Treasurer (G)
(iv) Limited Liability (I)
(v) Business Ethics (C)
(vi) Limited Partner (D)
(vii) Double taxation of dividends (A)
(viii) Shareholder wealth maximisation (B)
(ix) Stakeholder (E)
(x) Value (F)
2) The CFO in a company is responsible for Accounting, investments and Research and
development departments..
let no, na,nw be the refractive indices of oil, air and waterrespec.pdf
let no, na,nw be the refractive indices of oil, air and waterrespectively then from snells law
Solution
let no, na,nw be the refractive indices of oil, air and waterrespectively then from snells law.
sol Quantum numbers describe an electrons shell.pdf
sol Quantum numbers describe an electron\'s shell number, sublevel, orbital, and
spin. Each electron in an atom has a unique set of quantum numbers that cannot be duplicated
by any other electron in the atom. The first quantum number, n, tells you which shell the
electron is in. n is always a positive whole number, so it could be 1, 2, 3, 4, etc . If the electron
is in the first shell (the shell closest to the nucleus), then n = 1 for that electron. n increases for
electrons in higher shells. The second quantum number, L, tells you what sublevel the electron
is in. Recall that there are four common sublevels in atoms. The value of L is also an integer.
It can be anywhere from 0 to n - 1. So in n = 1, L can only be 0. If n = 2, L can be 0 or 1. If n = 3,
L can be 0, 1, or 2. The value of L corresponds to a particular sublevel. For example, if an
electron is in an s-type sublevel, then its L value is 0. If it\'s in a p-type sublevel, its L value is
1. d-sublevel electrons have L = 2 and f-sublevel electrons have L = 3. The third quantum
number, m, tells you which orbital an electron is in. Each of the sublevels is further divided into
orbitals, which are regions of probability where electrons exist. The value of m can be anywhere
from -L to +L. If L = 0 (s-type sublevel), there is only one possible value of m: 0. . If L = 1 (p-
type sublevel), then there are three possible values of m: -1, 0, and +1. If L = 2 (d-type sublevel),
there are five possible values of m: -2, -1, 0, +1, and +2. If L = 3 (f-type sublevel), there are
seven possible values of m: -3, -2, -1, 0, +1, +2, and +3. The last quantum number is the spin
quantum number, s. Each of the orbitals described before can hold up to two electrons, but
they MUST have opposite spins. The spins are defined as +1/2 and -1/2. By convention, the
first electron in an orbital is assigned a spin of +1/2, and the second electron (if there is one) gets
a spin of -1/2.
Solution
sol Quantum numbers describe an electron\'s shell number, sublevel, orbital, and
spin. Each electron in an atom has a unique set of quantum numbers that cannot be duplicated
by any other electron in the atom. The first quantum number, n, tells you which shell the
electron is in. n is always a positive whole number, so it could be 1, 2, 3, 4, etc . If the electron
is in the first shell (the shell closest to the nucleus), then n = 1 for that electron. n increases for
electrons in higher shells. The second quantum number, L, tells you what sublevel the electron
is in. Recall that there are four common sublevels in atoms. The value of L is also an integer.
It can be anywhere from 0 to n - 1. So in n = 1, L can only be 0. If n = 2, L can be 0 or 1. If n = 3,
L can be 0, 1, or 2. The value of L corresponds to a particular sublevel. For example, if an
electron is in an s-type sublevel, then its L value is 0. If it\'s in a p-type sublevel, its L value is
1. d-sublevel electrons have L = 2 and f-sublevel electrons have L = 3. The third .
There should be a table in your book with these L.pdf
There should be a table in your book with these Look at the table and see ultraviolet
is higher frequency (shorter wavelength) than infrared ultraviolet is shorter wavelength than
microwaves visible is shorter wavelength than radiowaves visible is shorter wavelength than
infrared
Solution
There should be a table in your book with these Look at the table and see ultraviolet
is higher frequency (shorter wavelength) than infrared ultraviolet is shorter wavelength than
microwaves visible is shorter wavelength than radiowaves visible is shorter wavelength than
infrared.
single displacement occurs when an element takes .pdf
single displacement occurs when an element takes the place of an element in a
compound. Metals displace metals, nonmetals displace nonmetals. #1 no displacement; both
reacants combined (synthesis) #2 the element, hydrogen, replaced the tungsten (displacment) #3
the cadmium and sulfur both combined with the oxygen (oxidation-reduction) #4 the element
chromium displaced the hydrogen in the compound (displacement
Solution
single displacement occurs when an element takes the place of an element in a
compound. Metals displace metals, nonmetals displace nonmetals. #1 no displacement; both
reacants combined (synthesis) #2 the element, hydrogen, replaced the tungsten (displacment) #3
the cadmium and sulfur both combined with the oxygen (oxidation-reduction) #4 the element
chromium displaced the hydrogen in the compound (displacement.
pH Electrode Maintenance The entire glass membra.pdf
pH Electrode Maintenance The entire glass membrane must always be clean.
Rinsing the membrane with distilled water will often suffice for aqueous solutions. Rinsing the
electrode with a mild detergent solution once a week will be beneficial. An alkaline hypochlorite
solution can be used to clean electrode membranes subjected to solutions containing fat or
proteins. Between measurements, store the glass electrode in a pH buffer with pH < 7. High
temperature measurements, compounded by constant use in strong alkaline solutions or weak
solutions of hydrofluoric acid will drastically reduce the lifetime of the electrode, since the glass
membrane will slowly dissolve. Dry storage is recommended if the electrode will not be used
for two weeks or more. Before use, the electrode should be soaked well. Trapped air bubbles
around the inner reference electrode will produce an unstable reading. Swing the electrode in an
arc or tap it gently to remove the bubbles. The electrode may have to be heated gently to
approximately 60° C in a water bath if the air bubbles are trapped by KCl crystals. In order to
establish a stable, hydrated glass membrane, new or dry-stored electrodes should be soaked
overnight in 0.1 M HCl. After overnight soaking, rinsing, soaking in a buffer of pH = 4, and
again rinsing, the electrode should be ready for use. If a shorter soaking time is necessary, the
electrode should be calibrated frequently to adjust for drifting potentials. A sluggish response
for a glass electrode, even after proper maintenance has been performed, may dictate the need for
a slight etching of the outer glass layer of the membrane. The following treatment is only
recommended after all other measures have been used to improve response and have failed.
Soaked the glass membrane portion of the glass electrode in a 20% ammonium bifluoride
solution for one minute, followed by 15 seconds in 6 M hydrochloric acid. ( Since hydrofluoric
acid can be formed during this procedure, be careful if choosing this method of electrode
rejuvenation. ) Rinse the electrode well and soak for 24 hours in a pH buffer with pH < 7. The
proper functioning of the glass electrode depends on the hydration of the glass layer that takes
place on the surface of the pH sensitive glass membrane during soaking and measurement in
aqueous solutions. As long as the electrode is frequently rehydrated, accurate measurements in
non-aqueous or partly aqueous solutions are also possible. This can be accomplished by soaking
in a slightly acidic buffer. In non-aqueous solvents completely immiscible with water and before
soaking, the electrode should first be rinsed with a solvent which is miscible with both water and
the solvent before rinsing with water. The electrode cable and the electrode plug must be kept
clean and dry if reliable measurements are to be obtained because of the very small electrode
currents which pass through the glass electrode. A number of factors dictate the useful lifetime
of the.
O-O+ +e- is the correct answer as first ionizati.pdf
O->O+ +e- is the correct answer as first ionization is the removal of first electron
from the base atom.
Solution
O->O+ +e- is the correct answer as first ionization is the removal of first electron
from the base atom..
O and H always make covalent bond. You can tell .pdf
O and H always make covalent bond. You can tell because they are both non
metals. Two nonmetals always make a covalent bond.(If you see two non metals together, you
know that they can make a polar covalent or non polar covalent bond, but never ionic). Only
when metal combine with nonmetal, do they make a ionic bond. One other thing, Oxygen is
very electronegative atom (this means that it likes electrons a lot and attracts them toward itself
more strongly them most other atoms) therefore it tends to form polar covalent bonds. Polar
covalent bond is a kind of covalent bond where electrons are sheared unevenly. So the most
complete answer to your question is: oxygen and hydrogen make a polar covalent bond.
Solution
O and H always make covalent bond. You can tell because they are both non
metals. Two nonmetals always make a covalent bond.(If you see two non metals together, you
know that they can make a polar covalent or non polar covalent bond, but never ionic). Only
when metal combine with nonmetal, do they make a ionic bond. One other thing, Oxygen is
very electronegative atom (this means that it likes electrons a lot and attracts them toward itself
more strongly them most other atoms) therefore it tends to form polar covalent bonds. Polar
covalent bond is a kind of covalent bond where electrons are sheared unevenly. So the most
complete answer to your question is: oxygen and hydrogen make a polar covalent bond..
NiCO3 (s) + H2SO4 (aq) NiSO4 (s) + CO2 (g) + H2.pdf
NiCO3 (s) + H2SO4 (aq) ? NiSO4 (s) + CO2 (g) + H2O (l)
Solution
NiCO3 (s) + H2SO4 (aq) ? NiSO4 (s) + CO2 (g) + H2O (l).
When I was getting ready at home, I was excited and anxious, but as .pdf
When I was getting ready at home, I was excited and anxious, but as I was driving down the
road, I began to get nervous. I had to take the interstate, and my first thought was traffic. I was
scared that there was going to be a horrific accident on the busy interstate and that I would be
late on my first day. I was very relieved when I saw that the interstate was not as busy as I
thought it was going to be, and the drive down was a breeze. All of my favorite songs came on
the radio, and I began to grown excited and anxious again. When I drove up on the Macon State
campus, that terrible feeling came back again. I saw all of the cars and thought to myself
frantically, “Oh no!, what if I can’t find a parking spot and be late to class after all.” Luckly, I
found an excellent parking spot that wasn\'t too far away from where I needed to be.
My main fears were whether I would be able to find any topics of discussion while talking to the
new people I would meet; whether they would be receptive of me and would I be able to make
friends here.
Would I be able to share my thoughts with anyone; will the teachers like me and whether I would
be able to break the ice with my classmates.
There were a lot of all kinds of people there. Young teenagers, and older men and women.
When I arrived at my 9:30 class, I was very glad to see two of my friends from high school. My
professor was very nice and cordial. She introduced herself and explained very clearly what the
class was about and what was expected. The room we were in was very cold, and as my
professor continued her precise conversation, I began to get very sleepy. During the course of the
rest of my day, I saw some more of my friends from high school. My next two professors were
also nice. I began to get kind of worried when my History professor told us that reading is a
major part of this class. I guess I\'ll have to get used to reading more because I want to pass.
In conclusion, my first day of college turned out to be okay. I went from being excited and
anxious, to nervous, and then to calm when I realized that everything was good. My first day was
a great experience, and I hope that I will continue to enjoy it and be successful.
Solution
When I was getting ready at home, I was excited and anxious, but as I was driving down the
road, I began to get nervous. I had to take the interstate, and my first thought was traffic. I was
scared that there was going to be a horrific accident on the busy interstate and that I would be
late on my first day. I was very relieved when I saw that the interstate was not as busy as I
thought it was going to be, and the drive down was a breeze. All of my favorite songs came on
the radio, and I began to grown excited and anxious again. When I drove up on the Macon State
campus, that terrible feeling came back again. I saw all of the cars and thought to myself
frantically, “Oh no!, what if I can’t find a parking spot and be late to class after all.” Luckly, I
found an excellen.
Viruses are those biological entities which are intermediate between.pdf
Viruses are those biological entities which are intermediate between living and non-living.
Outside the host, they are non-living. Even in non-living state they can survive for millions of
years. So, there is no strategy in the world which will prove fatal to virus\' future in the world.
Second, viruses have a protein capsid and genetic material. There is no machinery like mitosis,
proofreading etc. in their body which will maintain their capsid and genetic material as it is. In
fact, their genetic material is highly subject to mutation depending on the host they infect. So, no
matter what immune mechanisms human evolve, there is no immune mechanism which will
combat these unknown parasites. Humans can only prevent the spread of some viruses, most of
which are those that had previously attacked humans; but for new viruses, humans will not be
able to develop immune system. So, complete protection is impossible.
Third, disease does not confer any kind of protection or survival to the virus. In fact the virus has
to leave this host and infect a new healthy host.
So, it is true that viruses cause disease accidently, but this does not mean that viruses\' future is at
stake because of this. Viruses will survive till the date biological world will survive.
Solution
Viruses are those biological entities which are intermediate between living and non-living.
Outside the host, they are non-living. Even in non-living state they can survive for millions of
years. So, there is no strategy in the world which will prove fatal to virus\' future in the world.
Second, viruses have a protein capsid and genetic material. There is no machinery like mitosis,
proofreading etc. in their body which will maintain their capsid and genetic material as it is. In
fact, their genetic material is highly subject to mutation depending on the host they infect. So, no
matter what immune mechanisms human evolve, there is no immune mechanism which will
combat these unknown parasites. Humans can only prevent the spread of some viruses, most of
which are those that had previously attacked humans; but for new viruses, humans will not be
able to develop immune system. So, complete protection is impossible.
Third, disease does not confer any kind of protection or survival to the virus. In fact the virus has
to leave this host and infect a new healthy host.
So, it is true that viruses cause disease accidently, but this does not mean that viruses\' future is at
stake because of this. Viruses will survive till the date biological world will survive..
The most probable answer if this question seems to be option B. The .pdf
The most probable answer if this question seems to be option B. The condition is also known as
ciliary dyskinesia in which movement in cilia does not occur resulting in inhibiting with the
process of sweeping of mucus and growing particles out of the lungs.
Solution
The most probable answer if this question seems to be option B. The condition is also known as
ciliary dyskinesia in which movement in cilia does not occur resulting in inhibiting with the
process of sweeping of mucus and growing particles out of the lungs..
Exactly how you have drawn it, this compounds I.pdf
Exactly how you have drawn it, this compound\'s IUPAC name is but-1-en-2-
ylbenzene.
Solution
Exactly how you have drawn it, this compound\'s IUPAC name is but-1-en-2-
ylbenzene..
The contamination could be due to the presence of yeast in the cultu.pdf
The contamination could be due to the presence of yeast in the culture. Cultures contaminated
with yeasts become turbid with no pH change. Under microscope, yeast appear as small spherical
particles.
It could not be bacterial contamination because bacterial contanmination is accompanied with
sudden drop in the pH of the culture medium.
It could not be virus or mycoplasma contamination because the media does not change turbid in
the case of mycoplasma contamination. They are very difficult to detect and they do not be
appear as small round dots under microscope.
It could not be mold contamination because the mycelia usually appear as thin, wisp-like
filaments under microscope.
Solution
The contamination could be due to the presence of yeast in the culture. Cultures contaminated
with yeasts become turbid with no pH change. Under microscope, yeast appear as small spherical
particles.
It could not be bacterial contamination because bacterial contanmination is accompanied with
sudden drop in the pH of the culture medium.
It could not be virus or mycoplasma contamination because the media does not change turbid in
the case of mycoplasma contamination. They are very difficult to detect and they do not be
appear as small round dots under microscope.
It could not be mold contamination because the mycelia usually appear as thin, wisp-like
filaments under microscope..
Systems Development Life Cycle(SDLC) is the step by step process whi.pdf
Systems Development Life Cycle(SDLC) is the step by step process which we are following to
complete software project that includes development and testing.
There are 6 different phases available in SDLC.
1.Requirements
2.Analysis
3.System Design
4.System Implementation / Coding
5.System Testing and Integration
6.Release or System maintenance
1.Requirements:
This is the first phase in SDLC,once the project has been confirmed between client and company
will provide directly requirements to the company BA team.
Defining the problems,adjectives such as resources and personal costs.
Studying the ability of providing alternative solutions after meeting with clients,suppliers,c
consultants and employees.
After analyzing this you have a three choices i.e. develop a new system,improve the current
system/project or leave a system.
2.System Analysis:
End users requirements should be determined and documented,what their expectations are there
for the system,and how it will perform.
It was very important to maintain strong communication level with the clients to make sure you
have a clear vision of a product.
3.System Design:
In this phase defines the elements of a system,the components,the security levels and the
modules,architecture and different interfaces.
In this design phase high level and low level designers will design system process.
4.System Implementation / Coding :
In this phase development team will involving to write the actual coding functional modules.
In this phase system is ready to be deployed and installed customer premises.
Training will be given end users depends upon the project
5.System testing and Integration testing
During this phase testing team involved to ensures customer satisfaction and it will no required
coding knowledge.
Testing team performed real users it was systematic process in testing and done the integration
testing and automation testing if required.
6.Release and system maintenance:
During this phase technical team will be involving delay the application into production
environment.
Technical team and testing team will be involving to provide support to client while using
application production.
In the above question is that critical activity may include the coding of the application as per
client requirement is very difficult and gathering the requirements from the client also very
effecient task in SDLC process.
My position include coding of a project and in that project client need the minimum 3 months of
time for deploying the application into the production then our manager and team lead will
mainly focus on the developer in the project.
If we develop project then the testing team will find the errors and then that errors we will again
rectify and where that bugs are impacting we will find.
B.
In project we are following the agile methodology.this will includes the following
Customer satisfaction by rapid delivery of useful software
Welcome changing requirements,e Ben late in development
Working software is .
d. spontaneous at all temperatures .pdf
d. spontaneous at all temperatures
Solution
d. spontaneous at all temperatures.
It is truebecause The SMTP server cannot find the destination emai.pdf
It is true
because The SMTP server cannot find the destination email address, so the message cannot be
delivered!
Solution
It is true
because The SMTP server cannot find the destination email address, so the message cannot be
delivered!.
Homo neanderthalensis are evolved and lived ina) Europe andor sou.pdf
Homo neanderthalensis are evolved and lived in
a) Europe and/or south western to central Asia.
The option is a
Solution
Homo neanderthalensis are evolved and lived in
a) Europe and/or south western to central Asia.
The option is a.
B. note aldehydes hydrolysis gives diol products.pdf
B. note: aldehydes hydrolysis gives diol products.
Solution
B. note: aldehydes hydrolysis gives diol products..
Hi,I have updated your code. It is working fine now. Highllighted .pdf
Hi,
I have updated your code. It is working fine now. Highllighted all code changes below.
Shapes.java
import java.util.Scanner;
public class Shapes
{
private int radius;
public Shapes(int radius){
this.radius = radius;
}
public void setradius( int radius )
{
}
public int getradius()
{
return radius;
}
public void report()
{
System.out.printf( \"Circle perimeter, area / Sphere volume:\");
System.out.println();
System.out.printf( \" perimeter : \" + 2. * Math.PI * getradius());
System.out.println();
System.out.printf( \" area : \" + Math.PI * getradius() * 1.);
System.out.println();
System.out.printf( \" volume : \" + (4 * Math.PI * Math.pow(getradius(),3)/3));
System.out.println();
System.out.printf( \"Square perimeter, area:\");
System.out.println();
System.out.printf( \" perimeter : \" + 2 *Math.E * 1.);
System.out.println();
System.out.printf( \" area : \" + Math.E * 1.* 1);
System.out.println();
}
public static void main( String[] args )
{
//System.out.printf( \"Radius (as integer) of bounding sphere?\ %s!\ \", getradius() );
Scanner input = new Scanner( System.in );
System.out.println(\"Enter the radius:\");
int radius = input.nextInt();
Shapes s = new Shapes(radius);
s.report();
}
}
Output:
import java.util.Scanner;
public class Shapes
{
private int radius;
public Shapes(int radius){
this.radius = radius;
}
public void setradius( int radius )
{
}
public int getradius()
{
return radius;
}
public void report()
{
System.out.printf( \"Circle perimeter, area / Sphere volume:\");
System.out.println();
System.out.printf( \" perimeter : \" + 2. * Math.PI * getradius());
System.out.println();
System.out.printf( \" area : \" + Math.PI * getradius() * 1.);
System.out.println();
System.out.printf( \" volume : \" + (4 * Math.PI * Math.pow(getradius(),3)/3));
System.out.println();
System.out.printf( \"Square perimeter, area:\");
System.out.println();
System.out.printf( \" perimeter : \" + 2 *Math.E * 1.);
System.out.println();
System.out.printf( \" area : \" + Math.E * 1.* 1);
System.out.println();
}
public static void main( String[] args )
{
//System.out.printf( \"Radius (as integer) of bounding sphere?\ %s!\ \", getradius() );
Scanner input = new Scanner( System.in );
System.out.println(\"Enter the radius:\");
int radius = input.nextInt();
Shapes s = new Shapes(radius);
s.report();
}
}
Solution
Hi,
I have updated your code. It is working fine now. Highllighted all code changes below.
Shapes.java
import java.util.Scanner;
public class Shapes
{
private int radius;
public Shapes(int radius){
this.radius = radius;
}
public void setradius( int radius )
{
}
public int getradius()
{
return radius;
}
public void report()
{
System.out.printf( \"Circle perimeter, area / Sphere volume:\");
System.out.println();
System.out.printf( \" perimeter : \" + 2. * Math.PI * getradius());
System.out.println();
System.out.printf( \" area : \" + Math.PI * getradius() * 1.);
System.out.println();
System.out.printf( \" volume : \" + (4 * Math.PI * Math.pow(getradius(),3)/3).
More from aniyathikitchen (20)
1) (i)Finance (H)(ii) Corporation (J)(iii) Treasurer (G)(iv) L.pdf
1) (i)Finance (H)(ii) Corporation (J)(iii) Treasurer (G)(iv) L.pdf
let no, na,nw be the refractive indices of oil, air and waterrespec.pdf
let no, na,nw be the refractive indices of oil, air and waterrespec.pdf
sol Quantum numbers describe an electrons shell.pdf
sol Quantum numbers describe an electrons shell.pdf
There should be a table in your book with these L.pdf
There should be a table in your book with these L.pdf
single displacement occurs when an element takes .pdf
single displacement occurs when an element takes .pdf
pH Electrode Maintenance The entire glass membra.pdf
pH Electrode Maintenance The entire glass membra.pdf
O-O+ +e- is the correct answer as first ionizati.pdf
O-O+ +e- is the correct answer as first ionizati.pdf
O and H always make covalent bond. You can tell .pdf
O and H always make covalent bond. You can tell .pdf
NiCO3 (s) + H2SO4 (aq) NiSO4 (s) + CO2 (g) + H2.pdf
NiCO3 (s) + H2SO4 (aq) NiSO4 (s) + CO2 (g) + H2.pdf
When I was getting ready at home, I was excited and anxious, but as .pdf
When I was getting ready at home, I was excited and anxious, but as .pdf
Viruses are those biological entities which are intermediate between.pdf
Viruses are those biological entities which are intermediate between.pdf
The most probable answer if this question seems to be option B. The .pdf
The most probable answer if this question seems to be option B. The .pdf
Exactly how you have drawn it, this compounds I.pdf
Exactly how you have drawn it, this compounds I.pdf
The contamination could be due to the presence of yeast in the cultu.pdf
The contamination could be due to the presence of yeast in the cultu.pdf
Systems Development Life Cycle(SDLC) is the step by step process whi.pdf
Systems Development Life Cycle(SDLC) is the step by step process whi.pdf
It is truebecause The SMTP server cannot find the destination emai.pdf
It is truebecause The SMTP server cannot find the destination emai.pdf
Homo neanderthalensis are evolved and lived ina) Europe andor sou.pdf
Homo neanderthalensis are evolved and lived ina) Europe andor sou.pdf
B. note aldehydes hydrolysis gives diol products.pdf
B. note aldehydes hydrolysis gives diol products.pdf
Hi,I have updated your code. It is working fine now. Highllighted .pdf
Hi,I have updated your code. It is working fine now. Highllighted .pdf
Recently uploaded
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
2024.06.01 Introducing a competency framework for languag learning materials ...
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
MASS MEDIA STUDIES-835-CLASS XI Resource Material.pdf
mass media studies
CBSE
Full Book
for class 11th
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
special B.ed 2nd year old paper_20240531.pdf
Instagram:-
https://instagram.com/special_education_needs_01?igshid=YmMyMTA2M2Y=
WhatsApp:-
https://chat.whatsapp.com/JVakNIYlSV94x7bwunO3Dc
YouTube:-
https://youtube.com/@special_education_needs
Teligram :- https://t.me/special_education_needs
Slide Shere :-
https://www.slideshare.net/shabnambano20?utm_campaign=profiletracking&utm_medium=sssite&utm_source=ssslideview
"Protectable subject matters, Protection in biotechnology, Protection of othe...
Protectable subject matters, Protection in biotechnology, Protection of other biological materials, Ownership and period of protection
CACJapan - GROUP Presentation 1- Wk 4.pdf
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
A Survey of Techniques for Maximizing LLM Performance.pptx
A Survey of Techniques for Maximizing LLM Performance
Embracing GenAI - A Strategic Imperative
Artificial Intelligence (AI) technologies such as Generative AI, Image Generators and Large Language Models have had a dramatic impact on teaching, learning and assessment over the past 18 months. The most immediate threat AI posed was to Academic Integrity with Higher Education Institutes (HEIs) focusing their efforts on combating the use of GenAI in assessment. Guidelines were developed for staff and students, policies put in place too. Innovative educators have forged paths in the use of Generative AI for teaching, learning and assessments leading to pockets of transformation springing up across HEIs, often with little or no top-down guidance, support or direction.
This Gasta posits a strategic approach to integrating AI into HEIs to prepare staff, students and the curriculum for an evolving world and workplace. We will highlight the advantages of working with these technologies beyond the realm of teaching, learning and assessment by considering prompt engineering skills, industry impact, curriculum changes, and the need for staff upskilling. In contrast, not engaging strategically with Generative AI poses risks, including falling behind peers, missed opportunities and failing to ensure our graduates remain employable. The rapid evolution of AI technologies necessitates a proactive and strategic approach if we are to remain relevant.
Operation Blue Star - Saka Neela Tara
Operation “Blue Star” is the only event in the history of Independent India where the state went into war with its own people. Even after about 40 years it is not clear if it was culmination of states anger over people of the region, a political game of power or start of dictatorial chapter in the democratic setup.
The people of Punjab felt alienated from main stream due to denial of their just demands during a long democratic struggle since independence. As it happen all over the word, it led to militant struggle with great loss of lives of military, police and civilian personnel. Killing of Indira Gandhi and massacre of innocent Sikhs in Delhi and other India cities was also associated with this movement.
Introduction to AI for Nonprofits with Tapp Network
Dive into the world of AI! Experts Jon Hill and Tareq Monaur will guide you through AI's role in enhancing nonprofit websites and basic marketing strategies, making it easy to understand and apply.
Biological Screening of Herbal Drugs in detailed.
Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
for Anti-inflammatory, Antiulcer, Anticancer, Wound healing, Antidiabetic, Hepatoprotective, Cardio protective, Diuretics and
Antifertility, Toxicity studies as per OECD guidelines
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...Dr. Vinod Kumar Kanvaria
Exploiting Artificial Intelligence for Empowering Researchers and Faculty,
International FDP on Fundamentals of Research in Social Sciences
at Integral University, Lucknow, 06.06.2024
By Dr. Vinod Kumar KanvariaChapter -12, Antibiotics (One Page Notes).pdf
This is a notes for the D.Pharm students and related to the antibiotic drugs.
Model Attribute Check Company Auto Property
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
Recently uploaded (20)
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
2024.06.01 Introducing a competency framework for languag learning materials ...
2024.06.01 Introducing a competency framework for languag learning materials ...
Multithreading_in_C++ - std::thread, race condition
Multithreading_in_C++ - std::thread, race condition
MASS MEDIA STUDIES-835-CLASS XI Resource Material.pdf
MASS MEDIA STUDIES-835-CLASS XI Resource Material.pdf
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI fund...
"Protectable subject matters, Protection in biotechnology, Protection of othe...
"Protectable subject matters, Protection in biotechnology, Protection of othe...
A Survey of Techniques for Maximizing LLM Performance.pptx
A Survey of Techniques for Maximizing LLM Performance.pptx
Introduction to AI for Nonprofits with Tapp Network
Introduction to AI for Nonprofits with Tapp Network
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
MineSweeper.java public class MS { public static void main(Strin.pdf
- 1. MineSweeper.java public class MS { public static void main(String[] args) { Gamegm= new Game(); } } --> Game.java public class Game { private Bd bd; boolean fnsh = false; boolean w = false; int tn=0; public jg(){ bd = new Bd(); Py(bd); } public void Py(Bd bd){ do{ tn++; System.out.println("Turn "+tn); bd.show(); fnsh = bd.setPosition(); if(!fnsh){ bd.openNeighbors(); fnsh = bd.w(); } }while(!fnsh); if(bd.w()){ System.out.println("Congratulations, you let the 10 fields with the mns in "+tn+" tns"); bd.showMines();
- 2. } else { System.out.println("Mine! You lost!"); bd.showMines(); } } } --> Bd.java import java.util.Rnm; import java.util.Scanner; public class Bd { private int[][] mns; private char[][] bdgame; private int Line, Clm; Rnm rnm = new Rnm(); Scanner input = new Scanner(System.in); public Bd (){ mns = new int[10][10]; bdgame = new char[10][10]; stMs(); rnmMines(); fillTips(); startBd(); } public boolean w(){ int ct=0; for(int line = 1 ; line < 9 ; line++) for(int clm = 1 ; clm < 9 ; clm++) if(bdgame[line][clm]=='_') ct++; if(ct == 10) return true; else return false;
- 3. } public void oN(){ for(int i=-1 ; i<2 ; i++) for(int j=-1 ; j<2 ; j++) if( (mns[Ln+i][Clm+j] != -1) && (Ln != 0 && Ln != 9 && Clm != 0 && Clm != 9) ) bdgame[Ln+i][Clm+j]=Character.forDigit(mns[Ln+i][Clm+j], 10); } public int getPosition(int Ln, int Clm){ retn mns[Ln][Clm]; } public boolean setPosition(){ do{ System.out.print(" Ln: "); Ln = input.nextInt(); System.out.print("Clm: "); Clm = input.nextInt(); if( (bdgame[Ln][Clm] != '_') && ((Ln < 9 && Ln > 0) && (Clm < 9 && Clm > 0))) System.out.println("Field already shown"); if( Ln < 1 || Ln > 8 || Clm < 1 || Clm > 8) System.out.println("Choose a number between 1 and 8"); }while((Ln < 1 || Ln > 8 || Clm < 1 || Clm > 8) || (bdgame[Ln][Clm] != '_') ); if(getPosition(Ln, Clm)== -1) retn true; else retn false; }
- 4. public void show(){ System.out.println(" Lns"); for(int Ln = 8 ; Ln > 0 ; Ln--){ System.out.print(" "+Ln + " "); for(int Clm = 1 ; Clm < 9 ; Clm++){ System.out.print(" "+ bdgame[Ln][Clm]); } System.out.println(); } System.out.println(" 1 2 3 4 5 6 7 8"); System.out.println(" Clms"); } public void fillTips(){ for(int ln=1 ; ln < 9 ; ln++) for(int clm=1 ; clm < 9 ; clm++){ for(int i=-1 ; i<=1 ; i++) for(int j=-1 ; j<=1 ; j++) if(mns[ln][clm] != -1) if(mns[ln+i][clm+j] == -1) mns[ln][clm]++; } } public void showMines(){ for(int i=1 ; i < 9; i++) for(int j=1 ; j < 9 ; j++) if(mns[i][j] == -1)
- 5. bdgame[i][j]='*'; show(); } public void startBd(){ for(int i=1 ; i Solution MineSweeper.java public class MS { public static void main(String[] args) { Gamegm= new Game(); } } --> Game.java public class Game { private Bd bd; boolean fnsh = false; boolean w = false; int tn=0; public jg(){ bd = new Bd(); Py(bd); } public void Py(Bd bd){ do{ tn++; System.out.println("Turn "+tn); bd.show(); fnsh = bd.setPosition(); if(!fnsh){ bd.openNeighbors();
- 6. fnsh = bd.w(); } }while(!fnsh); if(bd.w()){ System.out.println("Congratulations, you let the 10 fields with the mns in "+tn+" tns"); bd.showMines(); } else { System.out.println("Mine! You lost!"); bd.showMines(); } } } --> Bd.java import java.util.Rnm; import java.util.Scanner; public class Bd { private int[][] mns; private char[][] bdgame; private int Line, Clm; Rnm rnm = new Rnm(); Scanner input = new Scanner(System.in); public Bd (){ mns = new int[10][10]; bdgame = new char[10][10]; stMs(); rnmMines(); fillTips(); startBd(); } public boolean w(){ int ct=0;
- 7. for(int line = 1 ; line < 9 ; line++) for(int clm = 1 ; clm < 9 ; clm++) if(bdgame[line][clm]=='_') ct++; if(ct == 10) return true; else return false; } public void oN(){ for(int i=-1 ; i<2 ; i++) for(int j=-1 ; j<2 ; j++) if( (mns[Ln+i][Clm+j] != -1) && (Ln != 0 && Ln != 9 && Clm != 0 && Clm != 9) ) bdgame[Ln+i][Clm+j]=Character.forDigit(mns[Ln+i][Clm+j], 10); } public int getPosition(int Ln, int Clm){ retn mns[Ln][Clm]; } public boolean setPosition(){ do{ System.out.print(" Ln: "); Ln = input.nextInt(); System.out.print("Clm: "); Clm = input.nextInt(); if( (bdgame[Ln][Clm] != '_') && ((Ln < 9 && Ln > 0) && (Clm < 9 && Clm > 0))) System.out.println("Field already shown"); if( Ln < 1 || Ln > 8 || Clm < 1 || Clm > 8) System.out.println("Choose a number between 1 and 8");
- 8. }while((Ln < 1 || Ln > 8 || Clm < 1 || Clm > 8) || (bdgame[Ln][Clm] != '_') ); if(getPosition(Ln, Clm)== -1) retn true; else retn false; } public void show(){ System.out.println(" Lns"); for(int Ln = 8 ; Ln > 0 ; Ln--){ System.out.print(" "+Ln + " "); for(int Clm = 1 ; Clm < 9 ; Clm++){ System.out.print(" "+ bdgame[Ln][Clm]); } System.out.println(); } System.out.println(" 1 2 3 4 5 6 7 8"); System.out.println(" Clms"); } public void fillTips(){ for(int ln=1 ; ln < 9 ; ln++) for(int clm=1 ; clm < 9 ; clm++){ for(int i=-1 ; i<=1 ; i++) for(int j=-1 ; j<=1 ; j++) if(mns[ln][clm] != -1) if(mns[ln+i][clm+j] == -1) mns[ln][clm]++;
- 9. } } public void showMines(){ for(int i=1 ; i < 9; i++) for(int j=1 ; j < 9 ; j++) if(mns[i][j] == -1) bdgame[i][j]='*'; show(); } public void startBd(){ for(int i=1 ; i