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Name: Zia Mohi-U-Din
Roll NO: 15103122-016
Smester:4th
Problem#018
Subject: Assignment
University Of Gujarat (Hafiz Hayaat Campus)
Problem# 3.18
 Air at 6.9 bar.260 is threshold to 5.5bar
before expanding through a nozzle to a
pressure of 1.1 bar. Assuming that air
flows reversibly in steady flow through the
nozzle, and that no heat is rejected ,
calculate the velocity of the air at exit
from the nozzle when the inlet velocity is
100m/s.
Solution# 3.18
 AS we know that for a perfect gas, h=CpT ,
hence for a throttling process.
T2 = T1 = 533K
then,
T3 = 533×(1.1/5.5)0.4/1.4
= 366.5K
Solution# 3.18
 For Flow through the nozzle.
Cp T2 +(C2)²/2 =Cp T3+(C3)²/2
(C3)²= 2 × 1.005 × 10³ × (533-336.5)+(100)²
=423 × 10³
i.e. Exit velocity = 636 m/s
Mechanical book Problem 3.18

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Mechanical book Problem 3.18

  • 1. Name: Zia Mohi-U-Din Roll NO: 15103122-016 Smester:4th Problem#018 Subject: Assignment University Of Gujarat (Hafiz Hayaat Campus)
  • 2.
  • 3. Problem# 3.18  Air at 6.9 bar.260 is threshold to 5.5bar before expanding through a nozzle to a pressure of 1.1 bar. Assuming that air flows reversibly in steady flow through the nozzle, and that no heat is rejected , calculate the velocity of the air at exit from the nozzle when the inlet velocity is 100m/s.
  • 4. Solution# 3.18  AS we know that for a perfect gas, h=CpT , hence for a throttling process. T2 = T1 = 533K then, T3 = 533×(1.1/5.5)0.4/1.4 = 366.5K
  • 5. Solution# 3.18  For Flow through the nozzle. Cp T2 +(C2)²/2 =Cp T3+(C3)²/2 (C3)²= 2 × 1.005 × 10³ × (533-336.5)+(100)² =423 × 10³ i.e. Exit velocity = 636 m/s