maincpp include ListItemh include ltstringgt in.pdf
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(main.cpp) #include "ListItem.h" #include <string> #include <list> #include <vector> #include <algorithm> #include <iostream> using namespace std; int main () { // working with a vector of ints int myints[] = { 5, 10, 15, 20 }; std::vector<int> vectorOfNums (myints,myints+4); std::vector<int>::iterator vectItr; // TODO: write call to find() to search for 15 in the vectorOfNums if (vectItr != vectorOfNums.end()) std::cout << "Element found: " << *vectItr << 'n'; else std::cout << "Element not foundn"; // TODO: write call to find() to search for 85 in the vectorOfNums if (vectItr != vectorOfNums.end()) std::cout << "Element found: " << *vectItr << 'n'; else std::cout << "Element not foundn"; // working with a list of strings std::list<std::string> listOfWords; std::list<std::string>::iterator listIter; listOfWords.push_back("house"); listOfWords.push_back("cup"); listOfWords.push_back("car"); listOfWords.push_back("lamp"); // TODO: write call to find() to search for 'lamp' in the listOfWords and write // the code to test for it // TODO: write call to find() to search for 'music' in the listOfWords and write // the code to test for it // working with a list of listItems std::list<ListItem> listOfItems; std::list<ListItem>::iterator listItemIter; listOfItems.push_back(ListItem("shoes", 150.95)); listOfItems.push_back(ListItem("laptop", 1245.85)); listOfItems.push_back(ListItem("dress", 85.68)); listOfItems.push_back(ListItem("polo shirt", 25.67)); // TODO: write call to find() to search for the 'dress' object in the listOfItems and write // the code to test for it // TODO: write call to find() to search for the 'slacks' object that cost '85.68' in the listOfItems and write // the code to test for it return 0; } (ListItem.h) #ifndef LISTITEMH #define LISTITEMH #include <string> using namespace std; class ListItem { public: ListItem(); ListItem(string itemInit, double priceInit); // Print this node void PrintNodeData(); // TODO: write the prototype for the '==' overload // TODO: write the prototype for '<<' overload (hint: must be a friend) private: string item; double price; }; #endif (ListIem.cpp) #include "ListItem.h" #include <iostream> ListItem::ListItem() { item = ""; price = 0.0; } ListItem::ListItem(string itemInit, double priceInit) { item = itemInit; price = priceInit; } // Print this node void ListItem::PrintNodeData() { cout << item << ": $" << price << endl; } // TODO: write the definition for the '==' overload // TODO: write the prototype for '<<' overload Given a Listitem class, complete main() using algorithms from the STL (STL Algorithms). An example algorithm the find(): find (Inputiterator first, Inputiterator last, const T& val) The find uses two iterators for the bounds of the search, first and last. The 3rd parameter is the value being searched for. if we look inside the find() we might see code like this (ref cplusplus.com): The description of find () states "The function uses operator== to compare the individual elements to .
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![(main.cpp)
#include "ListItem.h"
#include <string>
#include <list>
#include <vector>
#include <algorithm>
#include <iostream>
using namespace std;
int main () {
// working with a vector of ints
int myints[] = { 5, 10, 15, 20 };
std::vector<int> vectorOfNums (myints,myints+4);
std::vector<int>::iterator vectItr;
// TODO: write call to find() to search for 15 in the vectorOfNums
if (vectItr != vectorOfNums.end())
std::cout << "Element found: " << *vectItr << 'n';
else
std::cout << "Element not foundn";
// TODO: write call to find() to search for 85 in the vectorOfNums
if (vectItr != vectorOfNums.end())
std::cout << "Element found: " << *vectItr << 'n';
else
std::cout << "Element not foundn";
// working with a list of strings
std::list<std::string> listOfWords;
std::list<std::string>::iterator listIter;
listOfWords.push_back("house");
listOfWords.push_back("cup");
listOfWords.push_back("car");
listOfWords.push_back("lamp");
// TODO: write call to find() to search for 'lamp' in the listOfWords and write
// the code to test for it
// TODO: write call to find() to search for 'music' in the listOfWords and write
// the code to test for it
// working with a list of listItems
std::list<ListItem> listOfItems;
std::list<ListItem>::iterator listItemIter;
listOfItems.push_back(ListItem("shoes", 150.95));
listOfItems.push_back(ListItem("laptop", 1245.85));
listOfItems.push_back(ListItem("dress", 85.68));](https://image.slidesharecdn.com/maincppincludelistitemhincludeltstringgtin-230318115019-39c7e4de/85/maincpp-include-ListItemh-include-ltstringgt-in-pdf-1-320.jpg)
Recommended
lab08build.bat@echo offclsset DRIVE_LETTER=1s.docx
lab08/build.bat
@echo off
cls
set DRIVE_LETTER=%1:
set PATH=%DRIVE_LETTER%\MinGW\bin;%DRIVE_LETTER%\MinGW\msys\1.0\bin;%DRIVE_LETTER%\MinGW\gtkmm3\bin;%DRIVE_LETTER%\MinGW\gtk\bin;c:\Windows;c:\Windows\system32
set PROJECT_PATH=.
make DRIVE_LETTER="%DRIVE_LETTER%" PROJECT_DIR="%PROJECT_PATH%"
lab08/CSC2110/CD.h
#if !defined CD_H
#define CD_H
#include "Song.h"
#include "Text.h"
using CSC2110::String;
#include "ListArray.h"
using CSC2110::ListArray;
namespace CSC2110
{
class CD
{
private:
String* artist;
String* title;
int year;
int rating;
int num_tracks;
ListArray<Song>* songs;
public:
CD(String* artist, String* title, int year, int rating, int num_tracks);
virtual ~CD();
String* getKey();
void addSong(String* title, String* length);
void displayCD();
static ListArray<CD>* readCDs(const char* file_name);
static int compare_items(CD* one, CD* two);
static int compare_keys(String* sk, CD* cd);
static char getRadixChar(CD* cd, int index); //1-based
};
}
#endif
lab08/CSC2110/Double.h
#if !defined (DOUBLE_H)
#define DOUBLE_H
namespace CSC2110
{
class Double
{
private:
double value;
public:
Double(double val);
~Double();
double getValue();
};
}
#endif
lab08/CSC2110/HighPerformanceCounter.h
#if !defined (HIGHPERFORMANCECOUNTER_H)
#define HIGHPERFORMANCECOUNTER_H
namespace CSC2110
{
class HighPerformanceCounter
{
private:
double micro_spt; //micro_seconds per tick
HighPerformanceCounter();
static HighPerformanceCounter* hpc;
static int getTicksPerSecond();
public:
virtual ~HighPerformanceCounter();
static HighPerformanceCounter* getHighPerformanceCounter();
int getCurrentTimeInTicks();
double getTimeDifferenceInMicroSeconds(int start_time, int end_time);
};
}
#endif
lab08/CSC2110/Integer.h
#if !defined (INTEGER_H)
#define INTEGER_H
namespace CSC2110
{
class Integer
{
private:
int value;
public:
Integer(int val);
virtual ~Integer();
int getValue();
};
}
#endif
lab08/CSC2110/Keyboard.h
#if !defined KEYBOARD_H
#define KEYBOARD_H
#include "Text.h"
using CSC2110::String;
#include <string>
using namespace std;
namespace CSC2110
{
class Keyboard
{
private:
Keyboard();
public:
virtual ~Keyboard();
static Keyboard* getKeyboard();
//pre: the string (character literal) that will prompt the user for input
//post: the input read from the keyboard interpreted as an int is returned
int readInt(string prompt);
int getValidatedInt(string prompt, int min, int max);
//pre: the string that will prompt the user for input
//post: the input read from the keyboard interpreted as a double is returned
double readDouble(string prompt);
double getValidatedDouble(string prom ...
This is the main file include itemh include itemList.pdf
//This is the main file
#include "item.h"
#include "itemList.h"
int main()
{
//create a list of items
ItemList groceryList;
//create temp variables
Item anItem;
int count = 0, newNum = 0;
char newName[MAXCHAR], findName[MAXCHAR];
//read from user and add to list
cin >> count;
cin.ignore(100, 'n');
for(int i = 0; i < count; i++)
{
cin >> newName;
cin >> newNum;
cin.ignore(100, 'n');
anItem.setItemName(newName);
anItem.setNumItems(newNum);
groceryList.InsertAtFront(anItem);
}
groceryList.showList();
cin >> findName;
if(!groceryList.findItem(findName))
{
cout << "Item not found!";
}
return 0;
}
item.h
//Item header file
//
#pragma once
#include <iostream>
#include <cstring>
using namespace std;
//constant for char arrays
const int MAXCHAR = 101;
//class definition
class Item {
private:
char *itemName;
int numberOfItems;
public:
//Constructors
Item();
Item(char *, int);
//copy constructor
Item(const Item &anItem);
//destructor
~Item();
//mutators
void setItemName(char *);
void setNumItems(int);
//accessors
void getItemName(char *);
int getNumItems();
//print item
void printItem();
//assignment op overloading
Item& operator= (const Item& anItem);
};
item.cpp
//This is the implementation file for item.h (the Item class)
#include "item.h"
//default constructor
Item::Item()
{
//allocate memory for itemName
itemName = new char[MAXCHAR];
strcpy(this->itemName, "no name");
numberOfItems = 0;
}
//constructor with parameters
Item::Item(char tempItemName[], int tempNumItems)
{
//allocate memory for itemName
itemName = new char[strlen(tempItemName) + 1];
strcpy(itemName, tempItemName);
numberOfItems = tempNumItems;
}
//Copy Constructor
Item::Item(const Item &anItem)
{
//allocate memory for itemName
itemName = new char[strlen(anItem.itemName) + 1];
strcpy(itemName, anItem.itemName);
numberOfItems = anItem.numberOfItems;
}
//destructor
Item::~Item()
{
//deallocate the memory for itemName
if(itemName)
{
delete [] itemName;
itemName = NULL;
}
}
//mutator functions
void Item::setItemName(char *newItemName)
{
if(itemName)
{
delete [] itemName;
}
itemName = new char[strlen(newItemName) + 1];
strcpy(itemName, newItemName);
}
//for numberofitems
void Item::setNumItems(int newNum)
{
numberOfItems = newNum;
}
//accessor functions
void Item::getItemName(char *returnItemName)
{
strcpy(returnItemName, itemName);
}
int Item::getNumItems()
{
return numberOfItems;
}
//print the item
void Item::printItem()
{
cout << numberOfItems << ' ' << itemName << endl;
}
//assignment operator overload
Item& Item::operator= (const Item& anItem)
{
//if it is a self copy, don't do anything
if (this == &anItem)
return *this;
//make current object *this a copy of the passed in item
else
{
this->setItemName(anItem.itemName);
this->numberOfItems = anItem.numberOfItems;
return *this;
}
}
itemList.h
//This is the itemList header file.
//Class for a list of items
#pragma once
#include "item.h"
//define class for a list of items
class ItemList
{
private:
//struct for each Node
struct Node
{
Item d.
DoublyList-cpp- #include -DoublyList-h- using namespace std- void Doub.pdf
DoublyList.cpp:
#include "DoublyList.h"
using namespace std;
void DoublyList::insertFront(int newData)
{
if (first == nullptr)
{
first = new DLLNode(newData, nullptr, nullptr);
last = first;
// Common error: Forgetting to reset pointer last.
}
else
{
first = new DLLNode(newData, nullptr, first);
first->getNext()->setPrev(first);
// Common error: Forgetting to connect pointer
// prev of what is now the second node to the
// new first node.
}
++count;
}
void DoublyList::printForward() const
{
DLLNode* current = first;
while (current != nullptr)
{
cout << current->getData() << " ";
current = current->getNext();
}
}
void DoublyList::printReverse() const
{
DLLNode* current = last;
while (current != nullptr)
{
cout << current->getData() << " ";
current = current->getPrev();
}
}
void DoublyList::clearList()
{
DLLNode* temp = first;
while (first != nullptr)
{
first = first->getNext();
delete temp;
temp = first;
}
last = nullptr;
// Don't forget to reset pointer last to nullptr.
count = 0;
}
DoublyList::~DoublyList()
{
if (first != nullptr)
clearList();
}
DoublyList.h
#ifndef DOUBLYLIST_H
#define DOUBLYLIST_H
#include <string>
#include <iostream>
class DLLNode
{
public:
DLLNode() : data(0), prev(nullptr), next(nullptr) {}
DLLNode(int theData, DLLNode* prevLink, DLLNode* nextLink)
: data(theData), prev(prevLink), next(nextLink) {}
int getData() const { return data; }
DLLNode* getPrev() const { return prev; }
DLLNode* getNext() const { return next; }
void setData(int theData) { data = theData; }
void setPrev(DLLNode* prevLink) { prev = prevLink; }
void setNext(DLLNode* nextLink) { next = nextLink; }
~DLLNode(){}
private:
int data; // To simplify, we are using only one piece of data.
DLLNode* prev;
DLLNode* next;
};
class DoublyList
{
public:
DoublyList() : first(nullptr), last(nullptr), count(0) {}
void insertFront(int newData);
void printForward() const;
void printReverse() const;
void rotateNodesRight(int);
void clearList();
~DoublyList();
private:
// Pointer to the first node in the list.
DLLNode*first;
// Pointer to the last node in the list.
DLLNode*last;
// Number of nodes in the list.
int count;
};
#endif
Main.cpp
#include "DoublyList.h"
#include <iostream>
#include <vector>
using namespace std;
int main()
{
vector<vector<int>> data = {
{25, 76, 35, 67, 15, 98},
{1, 2, 3, 4, 5, 6, 7, 8, 9},
{10, 20},
{34, 56, 78, 12, 89, 34, 76, 28, 54, 22, 41},
{123, 873, 619},
};
vector<int> nodesToRotate = { 2, 3, 1, 9, 2 };
{
DoublyList doublyList;
int vectorSize = static_cast<int>(data.size());
for (int i = 0; i < vectorSize; ++i)
{
int innerSize = static_cast<int>(data[i].size());
for (int j = innerSize - 1; j >= 0; --j)
doublyList.insertFront(data[i].at(j));
cout << "Rotate right: " << nodesToRotate[i] << "\n";
cout << " List is: ";
doublyList.printForward();
cout << "\n";
doublyList.rotateNodesRight(nodesToRotate[i]);
cout << "After rotating:";
cout << "\n Print forward: ";
doublyList.printForward();
cout << "\nPrint backwards: ";
doublyList.printReverse(.
Need done for Date Structures please! 4-18 LAB- Sorted number list imp.pdf
Need done for Date Structures please!
4.18 LAB: Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number.
AnswerNote LinkedList.cpp is written and driver program main.cpp.pdf
Answer:
Note: LinkedList.cpp is written and driver program main.cpp is also given.
//ListInterface.h
#ifndef _LIST_INTERFACE
#define _LIST_INTERFACE
template
class ListInterface
{
public:
virtual bool isEmpty() const = 0;
virtual int getLength() const = 0;
virtual bool insert(int newPosition, const ItemType& newEntry) = 0;
virtual bool remove(int position) = 0;
virtual void clear() = 0;
virtual ItemType getEntry(int position) const = 0;
virtual void replace(int position, const ItemType& newEntry) = 0;
}; // end ListInterface
#endif
//Node.h
#ifndef NODE_
#define NODE_
template
class Node
{
private:
ItemType item; // A data item
Node* next; // Pointer to next node
public:
Node();
Node(const ItemType& anItem);
Node(const ItemType& anItem, Node* nextNodePtr);
void setItem(const ItemType& anItem);
void setNext(Node* nextNodePtr);
ItemType getItem() const ;
Node* getNext() const ;
}; // end Node
#endif
//Node.cpp
#include \"Node.h\"
template
Node::Node() : next(nullptr)
{
} // end default constructor
template
Node::Node(const ItemType& anItem) : item(anItem), next(nullptr)
{
} // end constructor
template
Node::Node(const ItemType& anItem, Node* nextNodePtr) :
item(anItem), next(nextNodePtr)
{
} // end constructor
template
void Node::setItem(const ItemType& anItem)
{
item = anItem;
} // end setItem
template
void Node::setNext(Node* nextNodePtr)
{
next = nextNodePtr;
} // end setNext
template
ItemType Node::getItem() const
{
return item;
} // end getItem
template
Node* Node::getNext() const
{
return next;
} // end getNext
//PrecondViolatedExcept.h
#ifndef PRECOND_VIOLATED_EXCEPT_
#define PRECOND_VIOLATED_EXCEPT_
#include
#include
class PrecondViolatedExcept : public std::logic_error
{
public:
PrecondViolatedExcept(const std::string& message = \"\");
}; // end PrecondViolatedExcept
#endif
//PrecondViolatedExcept.cpp
#include \"PrecondViolatedExcept.h\"
PrecondViolatedExcept::PrecondViolatedExcept(const std::string& message)
: std::logic_error(\"Precondition Violated Exception: \" + message)
{
} // end constructor
//LinkedList.h
#ifndef LINKED_LIST_
#define LINKED_LIST_
#include \"ListInterface.h\"
#include \"Node.h\"
#include
#include \"PrecondViolatedExcept.h\"
template
class LinkedList : public ListInterface
{
private:
Node* headPtr; // Pointer to first node in the chain;
// (contains the first entry in the list)
int itemCount; // Current count of list items
// Locates a specified node in this linked list.
Node* getNodeAt(int position) const;
public:
LinkedList();
LinkedList(const LinkedList& aList);
virtual ~LinkedList();
bool isEmpty() const;
int getLength() const;
bool insert(int newPosition, const ItemType& newEntry);
bool remove(int position);
void clear();
ItemType getEntry(int position) const;
void replace(int position, const ItemType& newEntry);
}; // end LinkedList
#endif
//LinkedList.cpp
#include \"LinkedList.h\"
#include
#include
#include
#include
//Default constructor
template
LinkedList::LinkedList() : headPtr(nullptr), itemCount(0)
{
.
Write a program to find the number of comparisons using the binary se.docx
Write a program to find the number of comparisons using the binary se
String searching
An O(n+m) in time and O(1) in space search-algorithm for substr, length m, in target string, length n. Simpler than trie or Knuth-Morris-Pratt. Can be reduced to O(n) using Group Theoretic O(1)-updatable hash that replaces the cumulative sum, which requires an O(m) verification step because "+" is commutative and cannot distinguish between anagrams: a+b+c = a+c+b = c+a+b etc. I am not uploading the hash, because it means giving away R&D I do in quantum simulations.
Recommended
lab08build.bat@echo offclsset DRIVE_LETTER=1s.docx
lab08/build.bat
@echo off
cls
set DRIVE_LETTER=%1:
set PATH=%DRIVE_LETTER%\MinGW\bin;%DRIVE_LETTER%\MinGW\msys\1.0\bin;%DRIVE_LETTER%\MinGW\gtkmm3\bin;%DRIVE_LETTER%\MinGW\gtk\bin;c:\Windows;c:\Windows\system32
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lab08/CSC2110/CD.h
#if !defined CD_H
#define CD_H
#include "Song.h"
#include "Text.h"
using CSC2110::String;
#include "ListArray.h"
using CSC2110::ListArray;
namespace CSC2110
{
class CD
{
private:
String* artist;
String* title;
int year;
int rating;
int num_tracks;
ListArray<Song>* songs;
public:
CD(String* artist, String* title, int year, int rating, int num_tracks);
virtual ~CD();
String* getKey();
void addSong(String* title, String* length);
void displayCD();
static ListArray<CD>* readCDs(const char* file_name);
static int compare_items(CD* one, CD* two);
static int compare_keys(String* sk, CD* cd);
static char getRadixChar(CD* cd, int index); //1-based
};
}
#endif
lab08/CSC2110/Double.h
#if !defined (DOUBLE_H)
#define DOUBLE_H
namespace CSC2110
{
class Double
{
private:
double value;
public:
Double(double val);
~Double();
double getValue();
};
}
#endif
lab08/CSC2110/HighPerformanceCounter.h
#if !defined (HIGHPERFORMANCECOUNTER_H)
#define HIGHPERFORMANCECOUNTER_H
namespace CSC2110
{
class HighPerformanceCounter
{
private:
double micro_spt; //micro_seconds per tick
HighPerformanceCounter();
static HighPerformanceCounter* hpc;
static int getTicksPerSecond();
public:
virtual ~HighPerformanceCounter();
static HighPerformanceCounter* getHighPerformanceCounter();
int getCurrentTimeInTicks();
double getTimeDifferenceInMicroSeconds(int start_time, int end_time);
};
}
#endif
lab08/CSC2110/Integer.h
#if !defined (INTEGER_H)
#define INTEGER_H
namespace CSC2110
{
class Integer
{
private:
int value;
public:
Integer(int val);
virtual ~Integer();
int getValue();
};
}
#endif
lab08/CSC2110/Keyboard.h
#if !defined KEYBOARD_H
#define KEYBOARD_H
#include "Text.h"
using CSC2110::String;
#include <string>
using namespace std;
namespace CSC2110
{
class Keyboard
{
private:
Keyboard();
public:
virtual ~Keyboard();
static Keyboard* getKeyboard();
//pre: the string (character literal) that will prompt the user for input
//post: the input read from the keyboard interpreted as an int is returned
int readInt(string prompt);
int getValidatedInt(string prompt, int min, int max);
//pre: the string that will prompt the user for input
//post: the input read from the keyboard interpreted as a double is returned
double readDouble(string prompt);
double getValidatedDouble(string prom ...
This is the main file include itemh include itemList.pdf
//This is the main file
#include "item.h"
#include "itemList.h"
int main()
{
//create a list of items
ItemList groceryList;
//create temp variables
Item anItem;
int count = 0, newNum = 0;
char newName[MAXCHAR], findName[MAXCHAR];
//read from user and add to list
cin >> count;
cin.ignore(100, 'n');
for(int i = 0; i < count; i++)
{
cin >> newName;
cin >> newNum;
cin.ignore(100, 'n');
anItem.setItemName(newName);
anItem.setNumItems(newNum);
groceryList.InsertAtFront(anItem);
}
groceryList.showList();
cin >> findName;
if(!groceryList.findItem(findName))
{
cout << "Item not found!";
}
return 0;
}
item.h
//Item header file
//
#pragma once
#include <iostream>
#include <cstring>
using namespace std;
//constant for char arrays
const int MAXCHAR = 101;
//class definition
class Item {
private:
char *itemName;
int numberOfItems;
public:
//Constructors
Item();
Item(char *, int);
//copy constructor
Item(const Item &anItem);
//destructor
~Item();
//mutators
void setItemName(char *);
void setNumItems(int);
//accessors
void getItemName(char *);
int getNumItems();
//print item
void printItem();
//assignment op overloading
Item& operator= (const Item& anItem);
};
item.cpp
//This is the implementation file for item.h (the Item class)
#include "item.h"
//default constructor
Item::Item()
{
//allocate memory for itemName
itemName = new char[MAXCHAR];
strcpy(this->itemName, "no name");
numberOfItems = 0;
}
//constructor with parameters
Item::Item(char tempItemName[], int tempNumItems)
{
//allocate memory for itemName
itemName = new char[strlen(tempItemName) + 1];
strcpy(itemName, tempItemName);
numberOfItems = tempNumItems;
}
//Copy Constructor
Item::Item(const Item &anItem)
{
//allocate memory for itemName
itemName = new char[strlen(anItem.itemName) + 1];
strcpy(itemName, anItem.itemName);
numberOfItems = anItem.numberOfItems;
}
//destructor
Item::~Item()
{
//deallocate the memory for itemName
if(itemName)
{
delete [] itemName;
itemName = NULL;
}
}
//mutator functions
void Item::setItemName(char *newItemName)
{
if(itemName)
{
delete [] itemName;
}
itemName = new char[strlen(newItemName) + 1];
strcpy(itemName, newItemName);
}
//for numberofitems
void Item::setNumItems(int newNum)
{
numberOfItems = newNum;
}
//accessor functions
void Item::getItemName(char *returnItemName)
{
strcpy(returnItemName, itemName);
}
int Item::getNumItems()
{
return numberOfItems;
}
//print the item
void Item::printItem()
{
cout << numberOfItems << ' ' << itemName << endl;
}
//assignment operator overload
Item& Item::operator= (const Item& anItem)
{
//if it is a self copy, don't do anything
if (this == &anItem)
return *this;
//make current object *this a copy of the passed in item
else
{
this->setItemName(anItem.itemName);
this->numberOfItems = anItem.numberOfItems;
return *this;
}
}
itemList.h
//This is the itemList header file.
//Class for a list of items
#pragma once
#include "item.h"
//define class for a list of items
class ItemList
{
private:
//struct for each Node
struct Node
{
Item d.
DoublyList-cpp- #include -DoublyList-h- using namespace std- void Doub.pdf
DoublyList.cpp:
#include "DoublyList.h"
using namespace std;
void DoublyList::insertFront(int newData)
{
if (first == nullptr)
{
first = new DLLNode(newData, nullptr, nullptr);
last = first;
// Common error: Forgetting to reset pointer last.
}
else
{
first = new DLLNode(newData, nullptr, first);
first->getNext()->setPrev(first);
// Common error: Forgetting to connect pointer
// prev of what is now the second node to the
// new first node.
}
++count;
}
void DoublyList::printForward() const
{
DLLNode* current = first;
while (current != nullptr)
{
cout << current->getData() << " ";
current = current->getNext();
}
}
void DoublyList::printReverse() const
{
DLLNode* current = last;
while (current != nullptr)
{
cout << current->getData() << " ";
current = current->getPrev();
}
}
void DoublyList::clearList()
{
DLLNode* temp = first;
while (first != nullptr)
{
first = first->getNext();
delete temp;
temp = first;
}
last = nullptr;
// Don't forget to reset pointer last to nullptr.
count = 0;
}
DoublyList::~DoublyList()
{
if (first != nullptr)
clearList();
}
DoublyList.h
#ifndef DOUBLYLIST_H
#define DOUBLYLIST_H
#include <string>
#include <iostream>
class DLLNode
{
public:
DLLNode() : data(0), prev(nullptr), next(nullptr) {}
DLLNode(int theData, DLLNode* prevLink, DLLNode* nextLink)
: data(theData), prev(prevLink), next(nextLink) {}
int getData() const { return data; }
DLLNode* getPrev() const { return prev; }
DLLNode* getNext() const { return next; }
void setData(int theData) { data = theData; }
void setPrev(DLLNode* prevLink) { prev = prevLink; }
void setNext(DLLNode* nextLink) { next = nextLink; }
~DLLNode(){}
private:
int data; // To simplify, we are using only one piece of data.
DLLNode* prev;
DLLNode* next;
};
class DoublyList
{
public:
DoublyList() : first(nullptr), last(nullptr), count(0) {}
void insertFront(int newData);
void printForward() const;
void printReverse() const;
void rotateNodesRight(int);
void clearList();
~DoublyList();
private:
// Pointer to the first node in the list.
DLLNode*first;
// Pointer to the last node in the list.
DLLNode*last;
// Number of nodes in the list.
int count;
};
#endif
Main.cpp
#include "DoublyList.h"
#include <iostream>
#include <vector>
using namespace std;
int main()
{
vector<vector<int>> data = {
{25, 76, 35, 67, 15, 98},
{1, 2, 3, 4, 5, 6, 7, 8, 9},
{10, 20},
{34, 56, 78, 12, 89, 34, 76, 28, 54, 22, 41},
{123, 873, 619},
};
vector<int> nodesToRotate = { 2, 3, 1, 9, 2 };
{
DoublyList doublyList;
int vectorSize = static_cast<int>(data.size());
for (int i = 0; i < vectorSize; ++i)
{
int innerSize = static_cast<int>(data[i].size());
for (int j = innerSize - 1; j >= 0; --j)
doublyList.insertFront(data[i].at(j));
cout << "Rotate right: " << nodesToRotate[i] << "\n";
cout << " List is: ";
doublyList.printForward();
cout << "\n";
doublyList.rotateNodesRight(nodesToRotate[i]);
cout << "After rotating:";
cout << "\n Print forward: ";
doublyList.printForward();
cout << "\nPrint backwards: ";
doublyList.printReverse(.
Need done for Date Structures please! 4-18 LAB- Sorted number list imp.pdf
Need done for Date Structures please!
4.18 LAB: Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number.
AnswerNote LinkedList.cpp is written and driver program main.cpp.pdf
Answer:
Note: LinkedList.cpp is written and driver program main.cpp is also given.
//ListInterface.h
#ifndef _LIST_INTERFACE
#define _LIST_INTERFACE
template
class ListInterface
{
public:
virtual bool isEmpty() const = 0;
virtual int getLength() const = 0;
virtual bool insert(int newPosition, const ItemType& newEntry) = 0;
virtual bool remove(int position) = 0;
virtual void clear() = 0;
virtual ItemType getEntry(int position) const = 0;
virtual void replace(int position, const ItemType& newEntry) = 0;
}; // end ListInterface
#endif
//Node.h
#ifndef NODE_
#define NODE_
template
class Node
{
private:
ItemType item; // A data item
Node* next; // Pointer to next node
public:
Node();
Node(const ItemType& anItem);
Node(const ItemType& anItem, Node* nextNodePtr);
void setItem(const ItemType& anItem);
void setNext(Node* nextNodePtr);
ItemType getItem() const ;
Node* getNext() const ;
}; // end Node
#endif
//Node.cpp
#include \"Node.h\"
template
Node::Node() : next(nullptr)
{
} // end default constructor
template
Node::Node(const ItemType& anItem) : item(anItem), next(nullptr)
{
} // end constructor
template
Node::Node(const ItemType& anItem, Node* nextNodePtr) :
item(anItem), next(nextNodePtr)
{
} // end constructor
template
void Node::setItem(const ItemType& anItem)
{
item = anItem;
} // end setItem
template
void Node::setNext(Node* nextNodePtr)
{
next = nextNodePtr;
} // end setNext
template
ItemType Node::getItem() const
{
return item;
} // end getItem
template
Node* Node::getNext() const
{
return next;
} // end getNext
//PrecondViolatedExcept.h
#ifndef PRECOND_VIOLATED_EXCEPT_
#define PRECOND_VIOLATED_EXCEPT_
#include
#include
class PrecondViolatedExcept : public std::logic_error
{
public:
PrecondViolatedExcept(const std::string& message = \"\");
}; // end PrecondViolatedExcept
#endif
//PrecondViolatedExcept.cpp
#include \"PrecondViolatedExcept.h\"
PrecondViolatedExcept::PrecondViolatedExcept(const std::string& message)
: std::logic_error(\"Precondition Violated Exception: \" + message)
{
} // end constructor
//LinkedList.h
#ifndef LINKED_LIST_
#define LINKED_LIST_
#include \"ListInterface.h\"
#include \"Node.h\"
#include
#include \"PrecondViolatedExcept.h\"
template
class LinkedList : public ListInterface
{
private:
Node* headPtr; // Pointer to first node in the chain;
// (contains the first entry in the list)
int itemCount; // Current count of list items
// Locates a specified node in this linked list.
Node* getNodeAt(int position) const;
public:
LinkedList();
LinkedList(const LinkedList& aList);
virtual ~LinkedList();
bool isEmpty() const;
int getLength() const;
bool insert(int newPosition, const ItemType& newEntry);
bool remove(int position);
void clear();
ItemType getEntry(int position) const;
void replace(int position, const ItemType& newEntry);
}; // end LinkedList
#endif
//LinkedList.cpp
#include \"LinkedList.h\"
#include
#include
#include
#include
//Default constructor
template
LinkedList::LinkedList() : headPtr(nullptr), itemCount(0)
{
.
Write a program to find the number of comparisons using the binary se.docx
Write a program to find the number of comparisons using the binary se
String searching
An O(n+m) in time and O(1) in space search-algorithm for substr, length m, in target string, length n. Simpler than trie or Knuth-Morris-Pratt. Can be reduced to O(n) using Group Theoretic O(1)-updatable hash that replaces the cumulative sum, which requires an O(m) verification step because "+" is commutative and cannot distinguish between anagrams: a+b+c = a+c+b = c+a+b etc. I am not uploading the hash, because it means giving away R&D I do in quantum simulations.
Dynamic Objects,Pointer to function,Array & Pointer,Character String Processing
This is an PPT of C++ Programming Language. This includes the various topics such as "Dynamic Objects,Pointer to function,Array & Pointer,Character String Processing ".
Imugi: Compiler made with Python
[PyConKR 2018] Imugi: Compiler made with Python.
https://www.pycon.kr/2018/program/2/
GitHub: https://github.com/hahnlee/imugi
Implementation File- -------------------------------------------------.docx
Implementation File:
---------------------------------------------------------
//----- List.cpp -----
#include <iostream>
using namespace std;
#include "linkedlist.h"
//-- Definition of the class constructor
List::List()
: first(0), mySize(0)
{ }
//-- Definition of the copy constructor
List::List( const List & origList)
{
mySize = origList.mySize;
first = 0;
if (mySize == 0) return ;
NodePointer origPtr, lastPtr;
first = new Node(origList.first->data); // copy first node
lastPtr = first;
origPtr = origList.first->next;
while (origPtr != 0)
{
lastPtr->next = new Node(origPtr->data);
origPtr = origPtr->next;
lastPtr = lastPtr->next;
}
}
//-- Definition of the destructor
inline List::~List()
{
NodePointer prev = first,
ptr;
while (prev != 0)
{
ptr = prev->next;
delete prev;
prev = ptr;
}
}
// Definition of empty()
bool List::empty()
{
return mySize == 0;
}
//-- Definition of the assignment operator
const List & List:: operator =( const List & rightSide)
{
mySize = rightSide.mySize;
first = 0;
if (mySize == 0) return * this ;
if ( this != &rightSide)
{
this ->~List();
NodePointer origPtr, lastPtr;
first = new Node(rightSide.first->data); // copy first node
lastPtr = first;
origPtr = rightSide.first->next;
while (origPtr != 0)
{
lastPtr->next = new Node(origPtr->data);
origPtr = origPtr->next;
lastPtr = lastPtr->next;
}
}
return * this ;
}
//-- Definition of insert()
void List::insert(ElementType dataVal, int index)
{
if (index < 0 || index > mySize)
{
cerr << "Illegal location to insert -- " << index << endl;
return ;
}
mySize++;
NodePointer newPtr = new Node(dataVal),
predPtr = first;
if (index == 0)
{
newPtr->next = first;
first = newPtr;
}
else
{
for ( int i = 1; i < index; i++)
predPtr = predPtr->next;
newPtr->next = predPtr->next;
predPtr->next = newPtr;
}
}
//-- Definition of erase()
void List::erase( int index)
{
if (index < 0 || index >= mySize)
{
cerr << "Illegal location to delete -- " << index << endl;
return ;
}
mySize--;
NodePointer ptr,
predPtr = first;
if (index == 0)
{
ptr = first;
first = ptr->next;
delete ptr;
}
else
{
for ( int i = 1; i < index; i++)
predPtr = predPtr->next;
ptr = predPtr->next;
predPtr->next = ptr->next;
delete ptr;
}
}
//-- Definition of display()
void List::display(ostream & out) const
{
NodePointer ptr = first;
while (ptr != 0)
{
out << ptr->data << " ";
ptr = ptr->next;
}
}
//-- Definition of the output operator
ostream & operator <<(ostream & out, const List & aList)
{
aList.display(out);
return out;
}
nstructions: For this lab, you will write a program that reads in a list of items for a camera store. The items for the list are in a file called InventoryFile.txt. The program will give the user options to insert an item, remove an item, display the list of items, search for an item, or exit the program. Each line of the file InventoryFile has the following format: Item Number - an integer Number in stock - an integer (between 0 and 999) Unit Price - a floating-point value Minimum inventory level - an inte.
Need help with the TODO's (DONE IN C++) #pragma once #include -funct.pdf
Need help with the TODO's (DONE IN C++)
#pragma once
#include <functional> // std::less
#include <iostream>
#include <queue> // std::queue
#include <utility> // std::pair
template <typename K, typename V, typename Comparator = std::less<K>>
class BinarySearchTree
{
public:
using key_type = K;
using value_type = V;
using key_compare = Comparator;
using pair = std::pair<key_type, value_type>;
using pointer = pair*;
using const_pointer = const pair*;
using reference = pair&;
using const_reference = const pair&;
using difference_type = ptrdiff_t;
using size_type = size_t;
private:
struct BinaryNode
{
pair element;
BinaryNode *left;
BinaryNode *right;
BinaryNode( const_reference theElement, BinaryNode *lt, BinaryNode *rt )
: element{ theElement }, left{ lt }, right{ rt } { }
BinaryNode( pair && theElement, BinaryNode *lt, BinaryNode *rt )
: element{ std::move( theElement ) }, left{ lt }, right{ rt } { }
};
using node = BinaryNode;
using node_ptr = node*;
using const_node_ptr = const node*;
node_ptr _root;
size_type _size;
key_compare comp;
public:
BinarySearchTree() {
// TODO
}
BinarySearchTree( const BinarySearchTree & rhs ) {
// TODO
}
BinarySearchTree( BinarySearchTree && rhs ) {
// TODO
}
~BinarySearchTree() {
// TODO
}
const_reference min() const { return min( _root )->element; }
const_reference max() const { return max( _root )->element; }
const_reference root() const {
// TODO
}
bool contains( const key_type & x ) const { return contains( x, _root ); }
value_type & find( const key_type & key ) { return find( key, _root )->element.second; }
const value_type & find( const key_type & key ) const { return find( key, _root )-
>element.second; }
bool empty() const {
// TODO
}
size_type size() const {
// TODO
}
void clear() {
clear( _root );
_size = 0;
}
void insert( const_reference x ) { insert( x, _root ); }
void insert( pair && x ) { insert( std::move( x ), _root ); }
void erase( const key_type & x ) { erase(x, _root); }
BinarySearchTree & operator=( const BinarySearchTree & rhs ) {
// TODO
}
BinarySearchTree & operator=( BinarySearchTree && rhs ) {
// TODO
}
private:
void insert( const_reference x, node_ptr & t ) {
// TODO
}
void insert( pair && x, node_ptr & t ) {
// TODO
}
void erase( const key_type & x, node_ptr & t ) {
// TODO
}
const_node_ptr min( const_node_ptr t ) const {
// TODO
}
const_node_ptr max( const_node_ptr t ) const {
// TODO
}
bool contains( const key_type & x, const_node_ptr t ) const {
// TODO
}
node_ptr find( const key_type & key, node_ptr t ) {
// TODO
}
const_node_ptr find( const key_type & key, const_node_ptr t ) const {
// TODO
}
void clear( node_ptr & t ) {
// TODO
}
node_ptr clone ( const_node_ptr t ) const {
// TODO
}
public:
template <typename KK, typename VV, typename CC>
friend void printLevelByLevel( const BinarySearchTree<KK, VV, CC>& bst, std::ostream & out
);
template <typename KK, typename VV, typename CC>
friend std::ostream& printNode(std::ostream& o, const typename BinarySearchTree<KK, VV,
CC>::node& bn);.
Inspect the class declaration for a doubly-linked list node in Node-h-.pdf
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables: a double data value, a pointer to the next node, and a pointer to the previous
node. Each member variable is protected. So code outside of the class must use the provided
getter and setter member functions to get or set a member variable. Node.h is read only, since no
changes are required. Step 2: Implement the Insert() member function A class for a sorted,
doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList class's
Insert() member function. The function must create a new node with the parameter value, then
insert the node into the proper sorted position in the linked list. Ex: Suppose a
SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node with data
value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order
and yielding: 23 35.5 47.25 86 Step 3: Test in develop mode Code in main() takes a space-
separated list of numbers and inserts each into a SortedNumberList. The list is displayed after
each insertion. Ex: If input is 77 15 -42 63.5 then output is: List after inserting 77: 77 List after
inserting 15: 15 77 List after inserting -42: -42 15 77 List after inserting 63.5: -42 15 63.5 77 Try
various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove()
member function Implement the SortedNumberList class's Remove() member function. The
function takes a parameter for the number to be removed from the list. If the number does not
exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the
number is removed from the list and true is returned. Uncomment the commented-out part in
main() that reads a second input line and removes numbers from the list. Test in develop mode to
ensure that insertion and removal both work properly, then submit code for grading. Ex: If input
is 84 72 19 61 19 84 then output is: List after inserting 84: 84 List after inserting 72: 72 84 List
after inserting 19: 19 72 84 List after inserting 61: 19 61 72 84 List after removing 19: 61 72 84
List after removing 84: 61 72
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std; void PrintList(SortedNumberList& list); vector SpaceSplit(string source);
int main(int argc, char *argv[]) { // Read the line of input numbers string inputLine; getline(cin,
inputLine); // Split on space character vector terms = SpaceSplit(inputLine); // Insert each value
and show the sorted list's contents after each insertion SortedNumberList list; for (auto term :
terms) { double number = stod(term); cout << "List after inserting " << number << ": " << endl;
list.Insert(number); PrintList(list); } /* // Read the input line with numbers to remove getline(cin,
inputLi.
Need to be done in C Please Sorted number list implementation with.pdf
Need to be done in C Please
Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
Main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number);
PrintList(list);
.
You are required to implement the following functions for doubly linke.docx
You are required to implement the following functions for doubly linked lists.
Note that code for creating a doubly linked list from an array of values is given to you, as well as testing code (driver program) to make sure that all functions work as expected.
1. find: Returns true if the given value is found in the list, and false otherwise.
template <typename Object>
bool findInDLL(DoubleNode<Object>* head, Object value);
2. insertBefore: Finds a given value and inserts a new node before it with a new value. Returns true if the insertion is successful, else false.
template <typename Object>
bool insertBeforeDLL(DoubleNode<Object>*& head, Object value, Object newValue);
3. erase: Finds a given value and deletes the matching node from the linked list. Returns true if the insertion is successful, else false.
template <typename Object>
bool eraseInDLL(DoubleNode<Object>*& head, Object value);
Sample output:
Printing Double linked list:
1 2 4 7 6 8
Finding 7 in the List:
7 exist in the list
Inserting 3 before 4 :
1 2 3 4 7 6 8
Inserting 0 before 1 (inserting at the start of the list):
0 1 2 3 4 7 6 8
Deleting 3:
0 1 2 4 7 6 8
Deleting 8 (deleting last element in the list):
0 1 2 4 7 6
Deleting 0 (deleting first element in the list):
1 2 4 7 6
Deleting -99 (trying to delete an element which is not present in the list):
Value not Found!
GIVEN THE C++ TEMPLATE PROGRAM
#include <iostream>
#include <string>
using namespace std;
//Doubly Linked List structure
template <typename Object>
struct DoubleNode
{
Object data;
DoubleNode *prev;
DoubleNode *next;
DoubleNode(const Object & d = Object{}, DoubleNode * p = nullptr, DoubleNode * n = nullptr)
: data{ d }, prev{ p }, next{ n } { }
};
//function to create Doubly Linked List with values
template <typename Object>
DoubleNode<Object>* createDLL(Object ary[], int size)
{
DoubleNode<Object>* first = new DoubleNode<Object>(ary[0]);
DoubleNode<Object>* temp = first;
for (int i = 1; i < size; i++)
{
DoubleNode<Object>* node = new DoubleNode<Object>(ary[i]);
temp->next = node;
node->prev = temp;
temp = node;
}
return first;
}
template <typename Object>
void printDLL(DoubleNode<Object>* head)
{
while (head != nullptr)
{
cout << head->data << "\t";
head = head->next;
}
cout << endl;
}
template <typename Object>
bool findInDLL(DoubleNode<Object>* head, Object value)
{
//your code goes here
}
template <typename Object>
bool insertBeforeDLL(DoubleNode<Object>* & head, Object givenValue, Object newValue) {
DoubleNode<Object> *newNode = new DoubleNode<Object>(newValue);
//your code goes here
}
template <typename Object>
bool eraseInDLL(DoubleNode<Object>*& head, Object givenValue) {
DoubleNode<Object> *temp = head;
//your code goes here
}
int main()
{
int ary[] = { 1,2,4,7,6,8 }, size = 6;
DoubleNode<int>* head = createDLL<int>(ary, size);
cout << "Printing Double linked list: \n";
printDLL(head);
cout << "\nFinding 7 in the List: \n";
if (findIn.
Need to be done in C++ Please Sorted number list implementation wit.pdf
Need to be done in C++ Please
Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
Main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number);
PrintList(list).
Given an array nums of size n- return the majority element- The majori.pdf
Given an array nums of size n, return the majority element.
The majority element is the element that appears more than round(n/2) times. You may assume
that the majority element always exists in the array.
Use the code template main_find_major_element
main_find_major_element:
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
// implement the function here.
int findMajorityElement(vector< int > &v)
{
return 0;
}
int main()
{
int n;
cout << "Enter the size of the vector: ";
cin >> n;
vector< int > input;
int element;
cout << "Enter the elements of the vector: ";
for ( int i = 0; i < n; i++)
{ cin >> element;
input.push_back(element);
}
int result = findMajorityElement(input);
cout << "The Majority Element is: " << result << endl;
return 0;
}
Examples:
Input:
Output:
3
Input:
Output:
2.
C++11 - STL Additions
This presentation considers certain specific features of C++11 and additions to STL library (uniform initialization, new containers and methods, move semantics).
Presentation by Taras Protsiv (Software Engineer, GlobalLogic), Kyiv, delivered at GlobalLogic C++ TechTalk in Lviv, September 18, 2014.
More details -
http://www.globallogic.com.ua/press-releases/lviv-cpp-techtalk-coverage
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf
Assignment is:
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Turn in .cpp
file AND Turn in a \"print-screen\' of your output (press \"print-screen\' on keyboard, then
\'paste\' in MS-Word)\"
How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *firs.
How do you stop infinite loop Because I believe that it is making a.pdf
How do you stop infinite loop? Because I believe that it is making an infinite circular list.
c++ code:
Here is the list class:
#ifndef LIN_J_LIST
#define LIN_J_LIST
typedef unsigned int uint;
#include
#include
using namespace std;
/**
* a simplified generic singly linked list class to illustrate C++ concepts
* @author Jerry Lin
* @version 2/17/17
*/
template< typename Object >
class List
{
private:
/**
* A class to store data and provide a link to the next node in the list
*/
class Node
{
public:
/**
* The constructor
* @param data the data to be stored in this node
*/
explicit Node( const Object & data )
: data{ data }, next{ nullptr } {}
Object data;
Node * next;
};
public:
/**
* The constructor for an empty list
*/
List()
: size{ 0 }, first{ nullptr }, last{ nullptr } {}
/**
* the copy constructor-creates and copy the list
*/
List( List && rhs ) = delete;
List( const List & rhs )
{
count = 0;
size = 0;
if(rhs.size != 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first;
size++;
while(current->next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op.
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode->next;
size++;
}
}
// you document and implement this method
}
/**
* the operator= method-copies the list
*/
List & operator=( List && rhs) = delete;
List & operator=( const List & rhs )
{
count = 0;
size = 0;
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
if(rhs.size!= 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first; //create a temporary to store
size++;
while(current -> next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode -> next;
size++;
}
}
return *this;
// you document and implement this method
}
/**
* accessor
* @return count
*/
int get_count() const
{
return count;
}
/**
* The destructor that gets rid of everything that\'s in the list and
* resets it to empty. If the list is already empty, do nothing.
*/
~List()
{
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
}
/**
* Put a new element onto the beginning of the list
* @param item the data the new element will contain
*/
void push_front( const Object& item )
{
Node * new_node = new Node( item );//basic op.
if(is_empty())
{
last = new_node;
}
else
{
new_node->next = first;
}
first = new_node;
size++;
/* you complete the rest */
}
/**
* Remove the element that\'s at the front of the list. Causes an
* assertion error if the list is empty.
*/
void pop_front()
{
assert( !is_empty() );
Node * temp = first;
if( first == last )
{
first = last = nullptr;
}
else
{
first = first->next;
}
delete temp;
size--;
}
/**
* Accessor to return the da.
Write the C++ code for a function getInput which will read in an unkno.docx
Write the C++ code for a function getInput which will read in an unknown of values from a file and store them in a one-dimensional array of integers. The function stores, in a reference parameter, the actual number of values it reads. The input file is declared and opened in main(), so the input filestream variable is needed as a function parameter. Write a C ++ function to find the minimum in a designated row of a 2-dimensional array which has 10 columns. The function parameters are the array, the row index of the row in which the minimum is to be found, and a reference parameter for the minimum value.
Solution
4.
#include<iostream.h>
#include<conio.h>
void min_row(int a[4][10],int row)
{
int m=a[row][0];
for(int i=1;i<10;i++)
{
if(a[row][i]<m)
m=a[row][i];
}
cout<<\"minimum number in row \"<<row<<\" is \"<<m;
}
void main()
{
int arr[4][10],i,j,r;
clrscr();
cout<<\"Enter Element to the matrix\";
for(i=0;i<4;i++)
{
cout<<\" Row \"<<i<<\" :\";
for(j=0;j<10;j++)
{
cout<<\"Column \"<<j<<\":\";
cin>>arr[i][j];
}
}
cout<<\"\ Enter the row number\";
cin>>r;
min_row(arr,r);
getch();
}
.
Data Matrix is Such data set can be represented by a n by.pdf
Data Matrix is:
Such data set can be represented by a n by p matrix, where there are n rows, one for each object,
and p columns, one for each attribute
O Can be thought of as points in a multi-dimensional space, where each dimension represents a
distinct
attribute
O Neither A or B
Both A and B.
Desarrolle un modelo de lienzo de modelo de negocio con det.pdf
Desarrolle un modelo de lienzo de modelo de negocio (con detalles) para "Holachef" India
con la siguiente rbrica. No des definicin pero analiza cada punto en el contexto de
Holachef...
SOCIOS CLAVE
ACTIVIDADES CLAVE
RECURSOS CLAVE
PROPUESTA DE VALOR
RELACIN CON EL CLIENTE
CANALES
SEGMENTOS DE CLIENTES
ESTRUCTURA DE COSTO
FLUJOS DE INGRESOS)
Descripcin de Holachef
Saurabh Saxena (en lo sucesivo, Saurabh) era un entusiasta. l haba estado constantemente
buscando una cocina nica, novedosa pero asequible y con variedad que se pueda comer todos
los das.
Descubri que tal experiencia era difcil de conseguir ya que, en general, la calidad de la comida
era
no era satisfactorio, era inconsistente, tena ofertas limitadas, era costoso y difcil de
alcanzan en el da a da (Oficina Holachef, 2015a, 2015b).
Holachef.com se convirti en la segunda apuesta empresarial de Saurabh. Holachef.com se
se denominar en adelante Holachef. Holachef fue conceptualizado para abordar los problemas de
necesidades alimentarias en los hogares de la megaciudad de Mumbai. la captacin de clientes de
Holachef es ms cmoda usando (colocando
pedidos y visualizacin del men) aplicaciones mviles y dispositivos porttiles. El holachef
la plataforma permite a los clientes ver el men y ordenar en lnea; as, Saurabh describe
Holachef como restaurante de alta cocina en la nube. Es interesante notar que a diferencia de un
ladrillo y
restaurante de mortero donde la carta de men es fija, la oferta gastronmica en Holachef es
dinmica
en la naturaleza segn la prerrogativa del chef. El sitio web enumera un nuevo men todos los das.
en Bombay,
Holachef puede usar la tecnologa porque la poblacin joven trabajadora se siente cmoda usando
l. Holachef haba recaudado fondos de la Serie A de Rs 20 millones de rupias en una ronda
liderada por Kalaari Capital en
Junio de 2015. India Quotient de Anand Lunia tambin particip en esta inversin. holachef tenia
recaud un fondo semilla de Rs 2 millones de rupias de India Quotient en febrero de 2015. En
septiembre de 2015,
Ratan Tata tambin haba invertido una cantidad no revelada en Holachef (Holachef Office, 2015a,
2015b; Et Bureau, 2016; Reddy, 2016; Oficina Holachef, 2015c).
Holachef comenz en 2014 en el rea del mercado de prueba, Powai, que se encuentra en la regin
central de
la gran rea metropolitana de Mumbai. Se ha expandido a los suburbios del este de Mumbai:
Ghatkopar, Kanjurmarg, Bhandup y Mulund. En el oeste, se ha expandido hasta Andheri y
Vileparl. El crecimiento de Holachef a lo largo de los aos se ha tabulado en la Tabla I.
Saurabh est muy ilusionado con el equipo que ha creado en Holachef. holachef
los empleados trabajan 24/7 para desarrollar el negocio. Saurabh tambin espera expandir su
equipo a medida que se ampla la huella. Las funciones principales de Holachef son tres, a saber,
la alimentacin, la tecnologa y la logstica.
Producir Alimentos es la parte en la que el chef prepara los platos para Holachef empleando un
nmero de chefs expertos. La logstica .
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Imugi: Compiler made with Python
[PyConKR 2018] Imugi: Compiler made with Python.
https://www.pycon.kr/2018/program/2/
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Implementation File- -------------------------------------------------.docx
Implementation File:
---------------------------------------------------------
//----- List.cpp -----
#include <iostream>
using namespace std;
#include "linkedlist.h"
//-- Definition of the class constructor
List::List()
: first(0), mySize(0)
{ }
//-- Definition of the copy constructor
List::List( const List & origList)
{
mySize = origList.mySize;
first = 0;
if (mySize == 0) return ;
NodePointer origPtr, lastPtr;
first = new Node(origList.first->data); // copy first node
lastPtr = first;
origPtr = origList.first->next;
while (origPtr != 0)
{
lastPtr->next = new Node(origPtr->data);
origPtr = origPtr->next;
lastPtr = lastPtr->next;
}
}
//-- Definition of the destructor
inline List::~List()
{
NodePointer prev = first,
ptr;
while (prev != 0)
{
ptr = prev->next;
delete prev;
prev = ptr;
}
}
// Definition of empty()
bool List::empty()
{
return mySize == 0;
}
//-- Definition of the assignment operator
const List & List:: operator =( const List & rightSide)
{
mySize = rightSide.mySize;
first = 0;
if (mySize == 0) return * this ;
if ( this != &rightSide)
{
this ->~List();
NodePointer origPtr, lastPtr;
first = new Node(rightSide.first->data); // copy first node
lastPtr = first;
origPtr = rightSide.first->next;
while (origPtr != 0)
{
lastPtr->next = new Node(origPtr->data);
origPtr = origPtr->next;
lastPtr = lastPtr->next;
}
}
return * this ;
}
//-- Definition of insert()
void List::insert(ElementType dataVal, int index)
{
if (index < 0 || index > mySize)
{
cerr << "Illegal location to insert -- " << index << endl;
return ;
}
mySize++;
NodePointer newPtr = new Node(dataVal),
predPtr = first;
if (index == 0)
{
newPtr->next = first;
first = newPtr;
}
else
{
for ( int i = 1; i < index; i++)
predPtr = predPtr->next;
newPtr->next = predPtr->next;
predPtr->next = newPtr;
}
}
//-- Definition of erase()
void List::erase( int index)
{
if (index < 0 || index >= mySize)
{
cerr << "Illegal location to delete -- " << index << endl;
return ;
}
mySize--;
NodePointer ptr,
predPtr = first;
if (index == 0)
{
ptr = first;
first = ptr->next;
delete ptr;
}
else
{
for ( int i = 1; i < index; i++)
predPtr = predPtr->next;
ptr = predPtr->next;
predPtr->next = ptr->next;
delete ptr;
}
}
//-- Definition of display()
void List::display(ostream & out) const
{
NodePointer ptr = first;
while (ptr != 0)
{
out << ptr->data << " ";
ptr = ptr->next;
}
}
//-- Definition of the output operator
ostream & operator <<(ostream & out, const List & aList)
{
aList.display(out);
return out;
}
nstructions: For this lab, you will write a program that reads in a list of items for a camera store. The items for the list are in a file called InventoryFile.txt. The program will give the user options to insert an item, remove an item, display the list of items, search for an item, or exit the program. Each line of the file InventoryFile has the following format: Item Number - an integer Number in stock - an integer (between 0 and 999) Unit Price - a floating-point value Minimum inventory level - an inte.
Need help with the TODO's (DONE IN C++) #pragma once #include -funct.pdf
Need help with the TODO's (DONE IN C++)
#pragma once
#include <functional> // std::less
#include <iostream>
#include <queue> // std::queue
#include <utility> // std::pair
template <typename K, typename V, typename Comparator = std::less<K>>
class BinarySearchTree
{
public:
using key_type = K;
using value_type = V;
using key_compare = Comparator;
using pair = std::pair<key_type, value_type>;
using pointer = pair*;
using const_pointer = const pair*;
using reference = pair&;
using const_reference = const pair&;
using difference_type = ptrdiff_t;
using size_type = size_t;
private:
struct BinaryNode
{
pair element;
BinaryNode *left;
BinaryNode *right;
BinaryNode( const_reference theElement, BinaryNode *lt, BinaryNode *rt )
: element{ theElement }, left{ lt }, right{ rt } { }
BinaryNode( pair && theElement, BinaryNode *lt, BinaryNode *rt )
: element{ std::move( theElement ) }, left{ lt }, right{ rt } { }
};
using node = BinaryNode;
using node_ptr = node*;
using const_node_ptr = const node*;
node_ptr _root;
size_type _size;
key_compare comp;
public:
BinarySearchTree() {
// TODO
}
BinarySearchTree( const BinarySearchTree & rhs ) {
// TODO
}
BinarySearchTree( BinarySearchTree && rhs ) {
// TODO
}
~BinarySearchTree() {
// TODO
}
const_reference min() const { return min( _root )->element; }
const_reference max() const { return max( _root )->element; }
const_reference root() const {
// TODO
}
bool contains( const key_type & x ) const { return contains( x, _root ); }
value_type & find( const key_type & key ) { return find( key, _root )->element.second; }
const value_type & find( const key_type & key ) const { return find( key, _root )-
>element.second; }
bool empty() const {
// TODO
}
size_type size() const {
// TODO
}
void clear() {
clear( _root );
_size = 0;
}
void insert( const_reference x ) { insert( x, _root ); }
void insert( pair && x ) { insert( std::move( x ), _root ); }
void erase( const key_type & x ) { erase(x, _root); }
BinarySearchTree & operator=( const BinarySearchTree & rhs ) {
// TODO
}
BinarySearchTree & operator=( BinarySearchTree && rhs ) {
// TODO
}
private:
void insert( const_reference x, node_ptr & t ) {
// TODO
}
void insert( pair && x, node_ptr & t ) {
// TODO
}
void erase( const key_type & x, node_ptr & t ) {
// TODO
}
const_node_ptr min( const_node_ptr t ) const {
// TODO
}
const_node_ptr max( const_node_ptr t ) const {
// TODO
}
bool contains( const key_type & x, const_node_ptr t ) const {
// TODO
}
node_ptr find( const key_type & key, node_ptr t ) {
// TODO
}
const_node_ptr find( const key_type & key, const_node_ptr t ) const {
// TODO
}
void clear( node_ptr & t ) {
// TODO
}
node_ptr clone ( const_node_ptr t ) const {
// TODO
}
public:
template <typename KK, typename VV, typename CC>
friend void printLevelByLevel( const BinarySearchTree<KK, VV, CC>& bst, std::ostream & out
);
template <typename KK, typename VV, typename CC>
friend std::ostream& printNode(std::ostream& o, const typename BinarySearchTree<KK, VV,
CC>::node& bn);.
Inspect the class declaration for a doubly-linked list node in Node-h-.pdf
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables: a double data value, a pointer to the next node, and a pointer to the previous
node. Each member variable is protected. So code outside of the class must use the provided
getter and setter member functions to get or set a member variable. Node.h is read only, since no
changes are required. Step 2: Implement the Insert() member function A class for a sorted,
doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList class's
Insert() member function. The function must create a new node with the parameter value, then
insert the node into the proper sorted position in the linked list. Ex: Suppose a
SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node with data
value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order
and yielding: 23 35.5 47.25 86 Step 3: Test in develop mode Code in main() takes a space-
separated list of numbers and inserts each into a SortedNumberList. The list is displayed after
each insertion. Ex: If input is 77 15 -42 63.5 then output is: List after inserting 77: 77 List after
inserting 15: 15 77 List after inserting -42: -42 15 77 List after inserting 63.5: -42 15 63.5 77 Try
various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove()
member function Implement the SortedNumberList class's Remove() member function. The
function takes a parameter for the number to be removed from the list. If the number does not
exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the
number is removed from the list and true is returned. Uncomment the commented-out part in
main() that reads a second input line and removes numbers from the list. Test in develop mode to
ensure that insertion and removal both work properly, then submit code for grading. Ex: If input
is 84 72 19 61 19 84 then output is: List after inserting 84: 84 List after inserting 72: 72 84 List
after inserting 19: 19 72 84 List after inserting 61: 19 61 72 84 List after removing 19: 61 72 84
List after removing 84: 61 72
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std; void PrintList(SortedNumberList& list); vector SpaceSplit(string source);
int main(int argc, char *argv[]) { // Read the line of input numbers string inputLine; getline(cin,
inputLine); // Split on space character vector terms = SpaceSplit(inputLine); // Insert each value
and show the sorted list's contents after each insertion SortedNumberList list; for (auto term :
terms) { double number = stod(term); cout << "List after inserting " << number << ": " << endl;
list.Insert(number); PrintList(list); } /* // Read the input line with numbers to remove getline(cin,
inputLi.
Need to be done in C Please Sorted number list implementation with.pdf
Need to be done in C Please
Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
Main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number);
PrintList(list);
.
You are required to implement the following functions for doubly linke.docx
You are required to implement the following functions for doubly linked lists.
Note that code for creating a doubly linked list from an array of values is given to you, as well as testing code (driver program) to make sure that all functions work as expected.
1. find: Returns true if the given value is found in the list, and false otherwise.
template <typename Object>
bool findInDLL(DoubleNode<Object>* head, Object value);
2. insertBefore: Finds a given value and inserts a new node before it with a new value. Returns true if the insertion is successful, else false.
template <typename Object>
bool insertBeforeDLL(DoubleNode<Object>*& head, Object value, Object newValue);
3. erase: Finds a given value and deletes the matching node from the linked list. Returns true if the insertion is successful, else false.
template <typename Object>
bool eraseInDLL(DoubleNode<Object>*& head, Object value);
Sample output:
Printing Double linked list:
1 2 4 7 6 8
Finding 7 in the List:
7 exist in the list
Inserting 3 before 4 :
1 2 3 4 7 6 8
Inserting 0 before 1 (inserting at the start of the list):
0 1 2 3 4 7 6 8
Deleting 3:
0 1 2 4 7 6 8
Deleting 8 (deleting last element in the list):
0 1 2 4 7 6
Deleting 0 (deleting first element in the list):
1 2 4 7 6
Deleting -99 (trying to delete an element which is not present in the list):
Value not Found!
GIVEN THE C++ TEMPLATE PROGRAM
#include <iostream>
#include <string>
using namespace std;
//Doubly Linked List structure
template <typename Object>
struct DoubleNode
{
Object data;
DoubleNode *prev;
DoubleNode *next;
DoubleNode(const Object & d = Object{}, DoubleNode * p = nullptr, DoubleNode * n = nullptr)
: data{ d }, prev{ p }, next{ n } { }
};
//function to create Doubly Linked List with values
template <typename Object>
DoubleNode<Object>* createDLL(Object ary[], int size)
{
DoubleNode<Object>* first = new DoubleNode<Object>(ary[0]);
DoubleNode<Object>* temp = first;
for (int i = 1; i < size; i++)
{
DoubleNode<Object>* node = new DoubleNode<Object>(ary[i]);
temp->next = node;
node->prev = temp;
temp = node;
}
return first;
}
template <typename Object>
void printDLL(DoubleNode<Object>* head)
{
while (head != nullptr)
{
cout << head->data << "\t";
head = head->next;
}
cout << endl;
}
template <typename Object>
bool findInDLL(DoubleNode<Object>* head, Object value)
{
//your code goes here
}
template <typename Object>
bool insertBeforeDLL(DoubleNode<Object>* & head, Object givenValue, Object newValue) {
DoubleNode<Object> *newNode = new DoubleNode<Object>(newValue);
//your code goes here
}
template <typename Object>
bool eraseInDLL(DoubleNode<Object>*& head, Object givenValue) {
DoubleNode<Object> *temp = head;
//your code goes here
}
int main()
{
int ary[] = { 1,2,4,7,6,8 }, size = 6;
DoubleNode<int>* head = createDLL<int>(ary, size);
cout << "Printing Double linked list: \n";
printDLL(head);
cout << "\nFinding 7 in the List: \n";
if (findIn.
Need to be done in C++ Please Sorted number list implementation wit.pdf
Need to be done in C++ Please
Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
Main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number);
PrintList(list).
Given an array nums of size n- return the majority element- The majori.pdf
Given an array nums of size n, return the majority element.
The majority element is the element that appears more than round(n/2) times. You may assume
that the majority element always exists in the array.
Use the code template main_find_major_element
main_find_major_element:
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
// implement the function here.
int findMajorityElement(vector< int > &v)
{
return 0;
}
int main()
{
int n;
cout << "Enter the size of the vector: ";
cin >> n;
vector< int > input;
int element;
cout << "Enter the elements of the vector: ";
for ( int i = 0; i < n; i++)
{ cin >> element;
input.push_back(element);
}
int result = findMajorityElement(input);
cout << "The Majority Element is: " << result << endl;
return 0;
}
Examples:
Input:
Output:
3
Input:
Output:
2.
C++11 - STL Additions
This presentation considers certain specific features of C++11 and additions to STL library (uniform initialization, new containers and methods, move semantics).
Presentation by Taras Protsiv (Software Engineer, GlobalLogic), Kyiv, delivered at GlobalLogic C++ TechTalk in Lviv, September 18, 2014.
More details -
http://www.globallogic.com.ua/press-releases/lviv-cpp-techtalk-coverage
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf
Assignment is:
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Turn in .cpp
file AND Turn in a \"print-screen\' of your output (press \"print-screen\' on keyboard, then
\'paste\' in MS-Word)\"
How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *firs.
How do you stop infinite loop Because I believe that it is making a.pdf
How do you stop infinite loop? Because I believe that it is making an infinite circular list.
c++ code:
Here is the list class:
#ifndef LIN_J_LIST
#define LIN_J_LIST
typedef unsigned int uint;
#include
#include
using namespace std;
/**
* a simplified generic singly linked list class to illustrate C++ concepts
* @author Jerry Lin
* @version 2/17/17
*/
template< typename Object >
class List
{
private:
/**
* A class to store data and provide a link to the next node in the list
*/
class Node
{
public:
/**
* The constructor
* @param data the data to be stored in this node
*/
explicit Node( const Object & data )
: data{ data }, next{ nullptr } {}
Object data;
Node * next;
};
public:
/**
* The constructor for an empty list
*/
List()
: size{ 0 }, first{ nullptr }, last{ nullptr } {}
/**
* the copy constructor-creates and copy the list
*/
List( List && rhs ) = delete;
List( const List & rhs )
{
count = 0;
size = 0;
if(rhs.size != 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first;
size++;
while(current->next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op.
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode->next;
size++;
}
}
// you document and implement this method
}
/**
* the operator= method-copies the list
*/
List & operator=( List && rhs) = delete;
List & operator=( const List & rhs )
{
count = 0;
size = 0;
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
if(rhs.size!= 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first; //create a temporary to store
size++;
while(current -> next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode -> next;
size++;
}
}
return *this;
// you document and implement this method
}
/**
* accessor
* @return count
*/
int get_count() const
{
return count;
}
/**
* The destructor that gets rid of everything that\'s in the list and
* resets it to empty. If the list is already empty, do nothing.
*/
~List()
{
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
}
/**
* Put a new element onto the beginning of the list
* @param item the data the new element will contain
*/
void push_front( const Object& item )
{
Node * new_node = new Node( item );//basic op.
if(is_empty())
{
last = new_node;
}
else
{
new_node->next = first;
}
first = new_node;
size++;
/* you complete the rest */
}
/**
* Remove the element that\'s at the front of the list. Causes an
* assertion error if the list is empty.
*/
void pop_front()
{
assert( !is_empty() );
Node * temp = first;
if( first == last )
{
first = last = nullptr;
}
else
{
first = first->next;
}
delete temp;
size--;
}
/**
* Accessor to return the da.
Write the C++ code for a function getInput which will read in an unkno.docx
Write the C++ code for a function getInput which will read in an unknown of values from a file and store them in a one-dimensional array of integers. The function stores, in a reference parameter, the actual number of values it reads. The input file is declared and opened in main(), so the input filestream variable is needed as a function parameter. Write a C ++ function to find the minimum in a designated row of a 2-dimensional array which has 10 columns. The function parameters are the array, the row index of the row in which the minimum is to be found, and a reference parameter for the minimum value.
Solution
4.
#include<iostream.h>
#include<conio.h>
void min_row(int a[4][10],int row)
{
int m=a[row][0];
for(int i=1;i<10;i++)
{
if(a[row][i]<m)
m=a[row][i];
}
cout<<\"minimum number in row \"<<row<<\" is \"<<m;
}
void main()
{
int arr[4][10],i,j,r;
clrscr();
cout<<\"Enter Element to the matrix\";
for(i=0;i<4;i++)
{
cout<<\" Row \"<<i<<\" :\";
for(j=0;j<10;j++)
{
cout<<\"Column \"<<j<<\":\";
cin>>arr[i][j];
}
}
cout<<\"\ Enter the row number\";
cin>>r;
min_row(arr,r);
getch();
}
.
Similar to maincpp include ListItemh include ltstringgt in.pdf (20)
Dynamic Objects,Pointer to function,Array & Pointer,Character String Processing
Dynamic Objects,Pointer to function,Array & Pointer,Character String Processing
Implementation File- -------------------------------------------------.docx
Implementation File- -------------------------------------------------.docx
Need help with the TODO's (DONE IN C++) #pragma once #include -funct.pdf
Need help with the TODO's (DONE IN C++) #pragma once #include -funct.pdf
Inspect the class declaration for a doubly-linked list node in Node-h-.pdf
Inspect the class declaration for a doubly-linked list node in Node-h-.pdf
Need to be done in C Please Sorted number list implementation with.pdf
Need to be done in C Please Sorted number list implementation with.pdf
You are required to implement the following functions for doubly linke.docx
You are required to implement the following functions for doubly linke.docx
Need to be done in C++ Please Sorted number list implementation wit.pdf
Need to be done in C++ Please Sorted number list implementation wit.pdf
Given an array nums of size n- return the majority element- The majori.pdf
Given an array nums of size n- return the majority element- The majori.pdf
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdf
How do you stop infinite loop Because I believe that it is making a.pdf
How do you stop infinite loop Because I believe that it is making a.pdf
Write the C++ code for a function getInput which will read in an unkno.docx
Write the C++ code for a function getInput which will read in an unkno.docx
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Such data set can be represented by a n by p matrix, where there are n rows, one for each object,
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O Can be thought of as points in a multi-dimensional space, where each dimension represents a
distinct
attribute
O Neither A or B
Both A and B.
Desarrolle un modelo de lienzo de modelo de negocio con det.pdf
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no era satisfactorio, era inconsistente, tena ofertas limitadas, era costoso y difcil de
alcanzan en el da a da (Oficina Holachef, 2015a, 2015b).
Holachef.com se convirti en la segunda apuesta empresarial de Saurabh. Holachef.com se
se denominar en adelante Holachef. Holachef fue conceptualizado para abordar los problemas de
necesidades alimentarias en los hogares de la megaciudad de Mumbai. la captacin de clientes de
Holachef es ms cmoda usando (colocando
pedidos y visualizacin del men) aplicaciones mviles y dispositivos porttiles. El holachef
la plataforma permite a los clientes ver el men y ordenar en lnea; as, Saurabh describe
Holachef como restaurante de alta cocina en la nube. Es interesante notar que a diferencia de un
ladrillo y
restaurante de mortero donde la carta de men es fija, la oferta gastronmica en Holachef es
dinmica
en la naturaleza segn la prerrogativa del chef. El sitio web enumera un nuevo men todos los das.
en Bombay,
Holachef puede usar la tecnologa porque la poblacin joven trabajadora se siente cmoda usando
l. Holachef haba recaudado fondos de la Serie A de Rs 20 millones de rupias en una ronda
liderada por Kalaari Capital en
Junio de 2015. India Quotient de Anand Lunia tambin particip en esta inversin. holachef tenia
recaud un fondo semilla de Rs 2 millones de rupias de India Quotient en febrero de 2015. En
septiembre de 2015,
Ratan Tata tambin haba invertido una cantidad no revelada en Holachef (Holachef Office, 2015a,
2015b; Et Bureau, 2016; Reddy, 2016; Oficina Holachef, 2015c).
Holachef comenz en 2014 en el rea del mercado de prueba, Powai, que se encuentra en la regin
central de
la gran rea metropolitana de Mumbai. Se ha expandido a los suburbios del este de Mumbai:
Ghatkopar, Kanjurmarg, Bhandup y Mulund. En el oeste, se ha expandido hasta Andheri y
Vileparl. El crecimiento de Holachef a lo largo de los aos se ha tabulado en la Tabla I.
Saurabh est muy ilusionado con el equipo que ha creado en Holachef. holachef
los empleados trabajan 24/7 para desarrollar el negocio. Saurabh tambin espera expandir su
equipo a medida que se ampla la huella. Las funciones principales de Holachef son tres, a saber,
la alimentacin, la tecnologa y la logstica.
Producir Alimentos es la parte en la que el chef prepara los platos para Holachef empleando un
nmero de chefs expertos. La logstica .
Bir hizmet irketi olan Easy Ltd bilano gn dzenlemeleri.pdf
Bir hizmet irketi olan Easy Ltd., bilano gn dzenlemelerinin kaydedilmesinden nce aadaki hesap
bakiyelerine sahiptir:
31 Aralk 2014 itibaryla Hesap Bakiyeleri (dzeltmeler ncesi)
hesap $
Nakit $39 200
Alacak hesaplar $14 000
Malzemeler 2 600 $
n demeli kira 1 800 $
Maddi, Tesis ve Ekipman (PP&E) $54 000
Dier dnen varlklar $10 200
denecek hesaplar 5 000 $
Banka Kredisi 10 000$
Katk sermaye (8 000 hisse) 32 000 $
Datlmam kazanlar (31/12/2013) 20 600 $
P&E'nin birikmi amortisman 24 000 $
Sat geliri $96 000
Sat getirisi 240 $
Genel giderler (ayrntl deil) 65 560 $
31 Aralk 2014 tarihine kadar henz kaydedilmemi dzeltmeler / ek bilgiler:
1. Mlkn faydal mr 9 yl ve hurda deeri 4500$. 2014 iin Amortisman hesaplayn (dz izgi yntemi).
2. Geen ay kullanlan kira 900 dolard;
3. 31 Aralk itibariyle alanlara yaplan ve denmesi gereken cretler, 2 200$;
4. 31 Aralk'taki malzeme says, elde ve iyi durumda 1200$ olduunu gsterdi;
5. Banka hesap zeti, henz kaydedilmemi olan 100 $'lk banka cretini gsteriyordu;
6. 65.560 $'lk Genel Gider tutarna, 1/4/2014 - 31/3/2015 dnemini kapsayan 1800 $'lk Konsey
Oranlar dahildir.
Gerekli:
I. alma kitabndaki ayarlamalardan nce Hesap bakiyelerini kaydedin
II. alma kitabndaki Ayarlamalar hesaplayn ve kaydedin, alma kitabn toplayn ve dengeleyin.
III. Dzeltmeler kaydedildikten sonra bir Bilano hazrlayn..
Assuming that the user inputs 1524 what does the following .pdf
Assuming that the user inputs 1524, what does the following code output? LSE A TRACE TABLE
to explain your answer int sum =0, digit; Scanner in = new Scanner(System.in);
System.out.println("Please input an integer >0 ); int num = in.nextInt (; do { digit = num % 10;
System.out.println( digit); sum += digit; num = num /10 } while ( num > 10) { System.out.println(
sum );.
1Which of the following best describes bryozoans aQuestion.pdf
1Which of the following best describes bryozoans?
a.Question options:
sessile, colonial, suspension feeders
infaunal, solitary, suspension feeders
nektonic, colonial, deposit feeders
benthic, solitary, autotrophic
b.
Brachiopods are:
Question options:
deposit feeders
predators
grazers
suspension feeders
c.
Match the life style term to the correct definition:
marine invertebrate creatures--who in their adult life--can not move from their living structure
marine invertebrates that filter edible particles out of muddy, bottom sediments, or that scrape
algae off of hard surfaces
usually single-celled photosynthetic and predatory creatures and the multicellular eggs &
hatchlings of animals that float on currents / tides
live on the bottom of a body of water; stream, lake, sea, ocean
marine invertebrates that have tentacles or other structures that are used to filter edible particles
out of the water as they float by
benthic
planktonic
sediment deposit feeder
sessile
suspension feeder
sessile, colonial, suspension feeders
infaunal, solitary, suspension feeders
nektonic, colonial, deposit feeders
benthic, solitary, autotrophic.
63 64 Data tablebalance sheet as of June 30 201X ente.pdf
6.3
6.4
Data tablebalance sheet as of June 30, 201X. enter a zero.)(b) Prepare the statement of owner's
equity. Complete the heading as well as the body of the statement. (There were no new
investments from the owner during the accounting period.) Less: in Capitalzero.) Assets Liabilities
and Owner's Equity Liabilities Owner's Equity Total Assets Total Liabilities and Owner's
EquityFrom the following accounts (not in order), prepare a post-closing trial balance for Wurley
Co. on October 31,201X. Note: These balances are before closing. (Click the icon to view the
accounts.) Data table.
PROBLEM 3 At yearend Myra Company reported cash and cash e.pdf
PROBLEM 3 At year-end, Myra Company reported cash and cash equivalents which comprised
the following: Cash on hand 500,000 Demand deposit 4,000,000 Certificate of deposit 2,000,000
Postdated customer check 300,000 Petty cash fund 50,000 Traveler's check 200,000 Manager's
check 100,000 Money order 150,000PROBLEM 6PROBLEM 7 What total amount should be 10
points reported as cash and cash equivalents on December 31 , 2020? *.
You are required to use Verilog structural modeling to desig.pdf
You are required to use Verilog structural modeling to design function F given by the following
equation: F(A,B,C,D)=(A.B)+(D)+(AC) Follow the instructions below: 1. Open Quartus II software
and create a new project. 2. Create and add a Verilog file named "lib.v" to your project..
Which of the following statements regarding DUNS is not true.pdf
Which of the following statements regarding DUNS is not true? Multiple Choice DUNS stands for
Data Universal Number System It is a unique 7digit code used to track whole families of
companies related through ownership.It is a unique 7 digit code used to track whole families of
companies related through ownership. Allows companies to be verified through a database. All of
the options are true..
What should Jamal propose as a strategy for BlackBerry as a .pdf
What should Jamal propose as a strategy for BlackBerry as a result of the SWOT assessment?
Assess Jamal's research. What additional information would you have included in your research to
augment your SWOT?development, and customer service to develop a single unified SWOT for
the entire company. Jamal called upon various departments to offer SWOT analyses because he
wanted to collaborate in order to pull together more detailed information. He reminded each
department to be honest in their assessment of their part of the company. Each department
offered information about their inner workings. The marketing department brought Jamal a SWOT
that analyzed product sales, pricing, advertising, and distribution. The finance department brought
Jamal the fiscal results from different products and areas of the company. The research and
development department reported on patents and product development. The operations
department brought statistics on how much fixed and operating capacity BlackBerry was utilizing,
and the customer service department reported on customer satisfaction levels with the company's
products and services. Strengths When Jamal analyzed the departmental SWOTs he was able to
identify several of BlackBerry's strengths. BlackBerry was once the most respected name in the
mobile communications industry, and the brand continued to be very well known. The brand
remained well liked by its supporters and still retained some popularity in its local market of
Canada. According to Barker (2011). "Throughout early decades of the twenty-first century, the
BlackBerry was synonymous with business connectivity. Its strong support for email, messaging,
global roaming, and mobile document editing made it the best in class among the other fledgling
smartphone platforms." Add in the fact that BlackBerry was a "cute" phone with the little
blackberry-shaped buttons, and BlackBerry had an easy time marketing their product. BlackBerry
had 595 million dollars in revenue in 2004, and revenues rose to a high of almost 20 billion dollars
in 2011. Unfortunately, revenue decreased to 2.1 billion dollars by 2016. BlackBerry's net income
also peaked in 2011 at 3.4 billion dollars. By 2016,Jamal had learned about SWOTs in his MBA
and knew the assessment tool was created by Albert Humphrey, who led a research project at
Stanford University in the 1960 s and 1970 s using data from many top companies. Humphrey's
goal was to identify why corporate planning failed. He identified areas of strategic importance that
he called SOFT: What is good in the present is Satisfactory, good in the future is an Opportunity;
bad in the present is a Fault, and bad in the future is a Threat" (Humphrey, 2005). "F" was
subsequently changed to "W" to better reflect the weaknesses that existed within the company.
The elements of the first SWOT were published in 1965 in Business Policy, Text and Cases by
Learned, Christensen, Andrews and Guth (Morrison, 2016). That text became the most popul.
What is the difference between the SW and OT areas of a SWOT.pdf
What is the difference between the SW and OT areas of a SWOT? Why is this difference relevant
and important? Use Jamal's research to produce a SWOT of BlackBerry to assess its strengths,
weaknesses, opportunities, and threats. The purpose of the SWOT should be to determine
strategies for BlackBerry to use for the next three to five years.Jamal Obu had been working at
BlackBerry Limited for five years as a marketing analyst when he was asked to conduct a strategic
environmental assessment for BlackBerry by the vice president of Marketing. Although BlackBerry
once enjoyed the bulk of the mobile phone market, by 2015 BlackBerry was struggling. The
competitive advantage that BlackBerry enjoyed was due in large part to their small phone with little
buttons that looked like blackberries. However, Apple and Samsung developed cell phones with
touchscreens and digital keyboards that made the BlackBerry cell phones appear ancient. Jamal's
boss wanted a strategic environmental assessment in order to guide the company in their strategic
planning. BlackBerry was caught completely off-guard by the rise of Apple's iPhone and they
needed to devise a strategic plan to recapture market share. Jamal and his fellow workers were
going to need to develop a vision for the future of the company if they expected to compete. Jamal
decided to use a SWOT (Strengths, Weaknesses, Opportunities, and Threats) as a framework to
evaluate BlackBerry's situation because he knew that format would allow him to organize the
quantitative and qualitative data necessary to help him understand the external and internal
factors at play.Jamal had leamed about SWOTs in his MBA and knew the assessment tool was
created by Albert Humphrey, who led a research project at Stanford University in the 1960 s and
1970 s using data from many top companies. Humphrey's goal was to identify why corporate
planning failed. He identified areas of strategic importance that he called SOFT: What is good in
the present is Satisfactory, good in the future is an Opportunity; bad in the present is a Fault, and
bad in the future is a Threat" (Humphrey, 2005). " F " was subsequently changed to "W" to better
reflect the weaknesses that existed within the company. The elements of the first SWOT were
published in 1965 in Business Policy, Text and Cases by Learned, Christensen, Andrews and
Guth (Morrison, 2016). That text became the most popular textbook in the academic study of
strategic management, and Jamal knew from completing strategic cases from that book that a
properly conducted SWOT could lead to finding new opportunities (such as entering a new
industry) that matched the strengths of their organization. He knew that SWOTs were valuable
tools that could be used to stay abreast of changing industry factors. As such, Jamal knew that
such an assessment could help inform BlackBerry's strategic planning, but he was unsure what
direction his SWOT might lead the company in their current dire situation. Identifying .
Use maple 13 to write the code 5 Consider the polar curve r.pdf
Use maple 13 to write the code
5. Consider the polar curve r()=2sincos4. (a) Graph the curve r() for 04. (b) Explain or show why
there is no curve in the third and fourth quadrant?.
The table shown below gives information on a variable for fo.pdf
The table shown below gives information on a variable for four samples selected from four
normally distributed populations with equal variances. By using ANOVA, we wish to test the null
hwpothesis that the means of the four corresponding populations are equal. The significance
levelis 5% The value of the test stathtic F, rounded to three decimal places is:.
Suppose X and Y are independent Paretodistributed with cu.pdf
Suppose X and Y are independent, Pareto-distributed, with cumulative distributions given by FX(x;
)=1x1,FY(y;)=1y1, with x,y1 and ,>0. Let Z=min{X,Y} and define the (non)censoring indicator ={10if
X<Yotherwise (This type of censoring is often known as "type I censoring.") (a) (10 marks) Obtain
the density function of Z(fZ) and the frequency function of (f). What are the distributions of Z and ?
(b) (5 marks) Let Z1,,Zn be a random sample from fZ(z;), with =+, and let 1,,n be a random sample
from f(d;p), with p=/(+). Derive the maximum liklihood estimators of and p. (c) (8 marks) Appealing
to the asymptotic normality of the maximum likelihood estimator, provide a 95% confidence
interval for and for p..
Real Value Corporation the Company is a public company .pdf
Real Value Corporation (the Company) is a public company (and an SEC registrant) that creates
augmented reality technology. The Companys primary source of revenue is currently from
universities that use the Companys products to superimpose computer- generated images in the
classroom to enhance learning. In addition to its ordinary business activities, the Company invests
in equity securities (described below) to generate investment income, which is the case for all
investments made by the Company as described herein. The Companys fiscal year-end is
December 31. The Company files quarterly and annual financial statements with the SEC.
The Company purchases equity securities in the form of Series A preferred stock of Company X (a
private company) on February 1, 2020. The Company concludes that the equity security does not
have a readily determinable fair value and that it does not qualify for the practical expedient to
estimate fair value in accordance with ASC 820-10-35-59. In its Q1 2020 financial statements, the
Company accounts for this investment in accordance with ASC 321 and elects the measurement
alternative in ASC 321-10-35-2 on the date of purchase, as it does for all its investments described
herein.
The terms for the Company X Series A preferred stock are as follows:
Has substantive liquidation preference over any other class of shares Company X has
outstanding (these Series A shares would retain its substantive liquidation preference over any
class of shares Company X may issue at any point in the future).
Has no voting rights.
Can elect two members of the board of directors.
Receives dividends that are cumulative and participatory.
Can be converted to common stock at any time at the holders option.
Second Quarter Events
On April 1, 2020, the Company purchases additional shares of Series A preferred stock of
Company X as a part of an offering that Company X made to multiple investors; the price paid is
greater than what the Company paid in its purchase on February 1, 2020.
On May 1, 2020, the Company purchases equity securities in the form of Series A preferred stock
of Company Y (a private company). This Company Y Series A preferred stock provides for similar
rights and obligations provided for by the Company X Series A preferred stock, but the price paid
for the Company Y Series A preferred stock is greater than what the Company paid when it
purchased Company X Series A preferred stock on April 1, 2020.
On June 1, 2020, the Company purchases shares of Series B preferred stock of Company X as a
part of an offering that Company X made to multiple investors. The price paid is less than what the
Company paid when it purchased Series A preferred stock of Company X on February 1, 2020.
The terms for the Company X Series B preferred stock are identical to the Company X Series A
preferred stock except for the following:
Series A has a substantive liquidation preference over Series B.
Can only elect one member of the board of directors.
R.
pass but that all but the most sophisticated computer progra.pdf
pass but that all but the most sophisticated computer programs cannot is called 8. ---------------is a
form of malware that, if a user unknowingly downloads it to his or her smartphone, takes control of
the device and its data until the owner agrees to pay a ransom to the attacker. 9. A(n) -------------
attack is one in which a malicious hacker takes over computers via the Internet and causes them
to flood a target site with demands for data and other small tasks. 10. A(n) is malicious code
hidden inside a seemingly harmless program. 11. A(n) ..................is a large group of computers
controlled from one or more remote locations by hackers, without the knowledge or consent of
their owners. 12. ......................is a method of computing that delivers secure, private, and reliable
computing experiences. 13. The process of assessing security-related risks from both internal and
external threats to an organization's computers and networks is called a(n) 14. The written
statement that defines an organization's security requirements as well as the controls and
sanctions used to meet those requirements is known as a: a. risk assessment b. security policy c.
firewall d. none of the above 15. Implementation of a strong firewall provides adequate security for
almost any network. True or False?.
Nur Inc is a private company that designs manufactures a.pdf
Nur Inc., is a private company that designs, manufactures, and distributes branded consumer
products. During its most recent fiscal year, the had revenues of $200 million and earnings of $30
million. The company has filed a registration statement with the SEC for its IPO. Before the stock
is offered, Nur's investment bankers would like to estimate the value of the company using
comparable companies. The investment bankers have assembled the following information based
on data for other companies in the same industry that have recently gone public. In each case, the
ratios are based on the IPO price. After the IPO, Nur Inc will have 10 million shares outstanding.
Estimate the IPO price for Nur Inc using the price/earnings ratio and the price/revenues ratio..
MedTex una gran empresa farmacutica con sede en Texas qu.pdf
Med-Tex, una gran empresa farmacutica con sede en Texas, quiere establecer su presencia
expandindose en el extranjero. Los ejecutivos de la compaa evalan ubicaciones en todo el mundo
para encontrar el lugar ms adecuado para construir la ltima planta de fabricacin de Med-Tex. Cul
de los siguientes, si es cierto, respalda mejor el argumento de que Med-Tex debera construir sus
nuevas instalaciones en el Reino Unido (RU)?
Con base en las Dimensiones
de valor de Hofstede, la
compaa tejana se expandira
hacia una cultura similar
A.
reduciendo el riesgo asociado
con diferentes actitudes,
valores y estilos de
comunicacin.
El principal competidor de
Med-Tex recibi incentivos del
B. gobierno para construir una
nueva planta de fabricacin en el
Reino Unido
El idioma no es una barrera ya
que se habla ingls en ambos
C.
pases. Esto har que la
expansin sea un proceso fcil.
El propietario de Med-Tex viaja
D. a Inglaterra todo el tiempo y
tiene amigos all..
JS es un hombre de 42 aos que vive en el Medio Oeste y es m.pdf
JS es un hombre de 42 aos que vive en el Medio Oeste y es muy alrgico al polvo y al polen y
tiene antecedentes de asma leve. La esposa de J.S lo llev a la sala de emergencias cuando sus
sibilancias no respondan a su inhalador de fluticasona/salmeterol (Advair). JS no poda acostarse
y comenz a usar los msculos accesorios para respirar. JS se inicia inmediatamente con 4 L de
oxgeno por cnula nasal e intravenoso (IV) D5W a 75 ml/h. Se enva un conjunto de gases de
sangre arterial al laboratorio. JS parece ansioso y dice que le falta el aire.
Signos vitales
BP = 152/84 HR = 124 lpm RR = 42 Temp = 100.40F
ABG
pH = 7,31 PaCO2 = 48 HCO3 = 26 PaO2 = 55
Investigar la condicin del asma y las manifestaciones de la enfermedad. Analice el estudio de
caso proporcionado y determine qu sntomas respaldan el diagnstico de asma. Identificar el
tratamiento brindado en el departamento de emergencias y determinar qu terapias adicionales se
necesitan para mitigar los sntomas del asma y devolver al cliente su bienestar.
Prepare un documento de 3 a 5 pginas que describa las causas del asma, los sntomas que
presenta el cliente y el manejo del trastorno.
3 pginas por favor no menos. necesito 3 paginas.
If we had classified health worker as rich if they earned .pdf
If we had classified health worker as 'rich' if they earned over $50,000 per annum and 'poor' if they
earned less than $15,000 per annum then we have:. a) A categorical variable measured on a
continuous scale b) A discrete variable measured on a categorical scale c) A discrete variable
measured on a continuous scale d) A continuous variable measured on a discrete scale Question
5 (10 points) Which of the following are typically found in experimental designs? a)
Counterbalancing b) Random allocation of participants to conditions c) Interval level independent
variables d) None of the above.
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http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
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A Strategic Approach: GenAI in Education
Artificial Intelligence (AI) technologies such as Generative AI, Image Generators and Large Language Models have had a dramatic impact on teaching, learning and assessment over the past 18 months. The most immediate threat AI posed was to Academic Integrity with Higher Education Institutes (HEIs) focusing their efforts on combating the use of GenAI in assessment. Guidelines were developed for staff and students, policies put in place too. Innovative educators have forged paths in the use of Generative AI for teaching, learning and assessments leading to pockets of transformation springing up across HEIs, often with little or no top-down guidance, support or direction.
This Gasta posits a strategic approach to integrating AI into HEIs to prepare staff, students and the curriculum for an evolving world and workplace. We will highlight the advantages of working with these technologies beyond the realm of teaching, learning and assessment by considering prompt engineering skills, industry impact, curriculum changes, and the need for staff upskilling. In contrast, not engaging strategically with Generative AI poses risks, including falling behind peers, missed opportunities and failing to ensure our graduates remain employable. The rapid evolution of AI technologies necessitates a proactive and strategic approach if we are to remain relevant.
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Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
for Anti-inflammatory, Antiulcer, Anticancer, Wound healing, Antidiabetic, Hepatoprotective, Cardio protective, Diuretics and
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Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
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This slide is special for master students (MIBS & MIFB) in UUM. Also useful for readers who are interested in the topic of contemporary Islamic banking.
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This ppt include the description of the edible vaccine i.e. a new concept over the traditional vaccine administered by injection.
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maincpp include ListItemh include ltstringgt in.pdf
- 1. (main.cpp) #include "ListItem.h" #include <string> #include <list> #include <vector> #include <algorithm> #include <iostream> using namespace std; int main () { // working with a vector of ints int myints[] = { 5, 10, 15, 20 }; std::vector<int> vectorOfNums (myints,myints+4); std::vector<int>::iterator vectItr; // TODO: write call to find() to search for 15 in the vectorOfNums if (vectItr != vectorOfNums.end()) std::cout << "Element found: " << *vectItr << 'n'; else std::cout << "Element not foundn"; // TODO: write call to find() to search for 85 in the vectorOfNums if (vectItr != vectorOfNums.end()) std::cout << "Element found: " << *vectItr << 'n'; else std::cout << "Element not foundn"; // working with a list of strings std::list<std::string> listOfWords; std::list<std::string>::iterator listIter; listOfWords.push_back("house"); listOfWords.push_back("cup"); listOfWords.push_back("car"); listOfWords.push_back("lamp"); // TODO: write call to find() to search for 'lamp' in the listOfWords and write // the code to test for it // TODO: write call to find() to search for 'music' in the listOfWords and write // the code to test for it // working with a list of listItems std::list<ListItem> listOfItems; std::list<ListItem>::iterator listItemIter; listOfItems.push_back(ListItem("shoes", 150.95)); listOfItems.push_back(ListItem("laptop", 1245.85)); listOfItems.push_back(ListItem("dress", 85.68));
- 2. listOfItems.push_back(ListItem("polo shirt", 25.67)); // TODO: write call to find() to search for the 'dress' object in the listOfItems and write // the code to test for it // TODO: write call to find() to search for the 'slacks' object that cost '85.68' in the listOfItems and write // the code to test for it return 0; } (ListItem.h) #ifndef LISTITEMH #define LISTITEMH #include <string> using namespace std; class ListItem { public: ListItem(); ListItem(string itemInit, double priceInit); // Print this node void PrintNodeData(); // TODO: write the prototype for the '==' overload // TODO: write the prototype for '<<' overload (hint: must be a friend) private: string item; double price; }; #endif (ListIem.cpp) #include "ListItem.h" #include <iostream> ListItem::ListItem() { item = ""; price = 0.0; } ListItem::ListItem(string itemInit, double priceInit) { item = itemInit; price = priceInit; } // Print this node
- 3. void ListItem::PrintNodeData() { cout << item << ": $" << price << endl; } // TODO: write the definition for the '==' overload // TODO: write the prototype for '<<' overload Given a Listitem class, complete main() using algorithms from the STL (STL Algorithms). An example algorithm the find(): find (Inputiterator first, Inputiterator last, const T& val) The find uses two iterators for the bounds of the search, first and last. The 3rd parameter is the value being searched for. if we look inside the find() we might see code like this (ref cplusplus.com): The description of find () states "The function uses operator== to compare the individual elements to val". This means that any object we want to search for needs to be have the capability of performing ==. And this may mean implementing the overload if the data type of the object does not already have this overload. Note that C++ types like int, float, double, and string already support this. Your task is to follow the prompts in main() and write the code required. For some of the tests, you will need to provide support for overloaded operators in the Listltem class. 419632.1188960.q3zqy7