List the 7 participants in Metabolic Reactions and then describe the.pdf
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List the 7 participants in Metabolic Reactions and then describe the 2 different types of metabolic pathways found in biological systems. Solution Answer: Seven participants in metabolic reactions: Two types of metabolic pathways: ICatabolic pathwayAnabolic pathwayPathway in which a substrate is broken into simpler molecule.Releases energy.Eg. Cellular respiration.Pathway in which new complex product is made from simpler substrate .Consumes energy.Eg. Synthesis of macromolecules, like protein..
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Can someone please help me write a case brief for two supreme court .pdf
Can someone please help me write a case brief for two supreme court cases:
1) Terry v. Ohio : https://supreme.justia.com/cases/federal/us/392/1/case.html
and
2) Gideon V. Wainwright : https://supreme.justia.com/cases/federal/us/372/335/cases.html
Solution
U.S. Supreme Court
Terry v. Ohio, 392 U.S. 1 (1968)
Terry v. Ohio
No. 67
Argued December 12, 1967
Decided June 10, 1968
392 U.S. 1
CERTIORARI TO THE SUPREME COURT OF OHIO
MR. CHIEF JUSTICE WARREN delivered the opinion of the Court.
This case presents serious questions concerning the role of the Fourth Amendment in the
confrontation on the street between the citizen and the policeman investigating suspicious
circumstances.
Petitioner Terry was convicted of carrying a concealed weapon and sentenced to the statutorily
prescribed term of one to three years in the penitentiary. [Footnote 1] Following
[5]
the denial of a pretrial motion to suppress, the prosecution introduced in evidence two revolvers
and a number of bullets seized from Terry and a codefendant, Richard Chilton, [Footnote 2] by
Cleveland Police Detective Martin McFadden. At the hearing on the motion to suppress this
evidence, Officer McFadden testified that, while he was patrolling in plain clothes in downtown
Cleveland at approximately 2:30 in the afternoon of October 31, 1963, his attention was attracted
by two men, Chilton and Terry, standing on the corner of Huron Road and Euclid Avenue. He
had never seen the two men before, and he was unable to say precisely what first drew his eye to
them. However, he testified that he had been a policeman for 39 years and a detective for 35, and
that he had been assigned to patrol this vicinity of downtown Cleveland for shoplifters and
pickpockets for 30 years. He explained that he had developed routine habits of observation over
the years, and that he would \"stand and watch people or walk and watch people at many
intervals of the day.\" He added: \"Now, in this case, when I looked over, they didn\'t look right
to me at the time.\"
His interest aroused, Officer McFadden took up a post of observation in the entrance to a store
300 to 400 feet
[6]
away from the two men. \"I get more purpose to watch them when I seen their movements,\" he
testified. He saw one of the men leave the other one and walk southwest on Huron Road, past
some stores. The man paused for a moment and looked in a store window, then walked on a short
distance, turned around and walked back toward the corner, pausing once again to look in the
same store window. He rejoined his companion at the corner, and the two conferred briefly. Then
the second man went through the same series of motions, strolling down Huron Road, looking in
the same window, walking on a short distance, turning back, peering in the store window again,
and returning to confer with the first man at the corner. The two men repeated this ritual
alternately between five and six times apiece -- in all, roughly a dozen trips. At one point, while
the two were s.
Analysis of data collected in a study of educational levels (Did not .pdf
Analysis of data collected in a study of educational levels (Did not complete High school
degree, and College degree), of voters and their political party affiliations (Democrat,
Republican and Independent) resulted X^2 = 13.42. Test with a = 0.01 to determine whether
party affiliation is Independent of the educational level of voters.
Solution
Here, the number of levels for educations level is a = 2.
also, the number of levels for party affiliation is b = 3.
Thus,
df = (a-1)(b-1) = 2
At df = 2, alpha = 0.01, the critical value for chi^2 is
chi^2 (critical) = 9.210340372
As chi^2 = 13.42 > 9.21, then we REJECT THE NULL HYPOTHESIS.
There is significant evidence that party affiliation is NOT INDEPENDENT of the educational
level of voters. [CONCLUSION].
As individuals age, they are likely to becomeMore alike and less .pdf
As individuals age, they are likely to become:
More alike and less individual
Increasingly stubborn and difficult
More compliant and less demanding
More like themselvesa.
More alike and less individualb.
Increasingly stubborn and difficultc.
More compliant and less demandingd.
More like themselves
Solution
Ans. It depends upon the individual but in most of the cases it has been observed the responsible
ones become more compliant and less demanding and the one which has an attitude problem
tends to be more stubborn and difficult..
APARTMENT BUILDING HOMEWORK1 What’s the problemSuppose you want.pdf
APARTMENT BUILDING HOMEWORK
1 What’s the problem?
Suppose you want to model an apartment building so that you can calculate the number of
windows (and their sizes) that are in the building. We are modelling the building with the
following classes:
1. Building, which contains several types of apartments.
2. Apartment and its subclasses OneBedroom, TwoBedroom, and ThreeBedroom. An instance of
this class is to represent a type of apartments, which includes a field to store the number of units
of this type.
3. Room and its subclass LivingRoom, MasterBedroom, and GuestRoom. Each room has some
windows of certain size. Different type of rooms have windows of different sizes.
4. Window and WindowOrder Window object has just the width and height of the window.
Window order object has a window object and the number of window for that order.
2 What to implement?
You will fill in the methods for classes described above. The provided code template has
instruction in the comments above the methods that you will implement.
3 What is provided? We provide a driver class Hwk6.java, a test class Test.java, and a bunch of
template classes. Note that each file may contain multiple classes. I usually group related classes
in the same file. For example, the file Apartment.java contains not only Apartment class but also
its subclasses.
4 What does output look like? If you run the driver class Hwk6.java you will see output that
looks like the followings.
20 apartments with (Living room: 5 (6 X 8 window)) (Master bedroom: 3 (4 X 6 window))
15 apartments with (Living room: 5 (6 X 8 window)) (Master bedroom: 3 (4 X 6 window))
(Guest room: 2 (5 X 6 window))
10 apartments with (Living room: 5 (6 X 8 window)) (Master bedroom: 3 (4 X 6 window))
(Guest room: 2 (5 X 6 window)) (Guest room: 2 (5 X 6 window))
Window orders are:
300 6 X 8 window
180 4 X 6 window
120 5 X 6 window
PROVIDED MAIN CLASS
package hwk6;
public class Hwk6 {
public static void main(String[] args) {
Apartment[] apartments = { new OneBedroom(20), new TwoBedroom(15), new
ThreeBedroom(10) };
Building building = new Building(apartments);
WindowOrder[] orders = building.order();
System.out.println(building);
System.out.println(\"Window orders are: \");
for(WindowOrder order: orders) {
System.out.println(order);
}
}
}
Building Template:
package hwk6;
public class Building {
Apartment[] apartments;
public Building(Apartment[] apartments) {
this.apartments= apartments;
}
// Return an array of window orders for all apartments in the building
// Ensure that the orders for windows of the same sizes are merged.
WindowOrder[] order() {
// TODO
}
// return a string to represent all types of apartments in the building such as:
// 20 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6 window))
// 15 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6
window))(Guest room: 2 (5 X 6 window))
// 10 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6
window))(Guest.
Why does Ernst Mayrs biological species concept NOT apply to Archae.pdf
Why does Ernst Mayr\'s biological species concept NOT apply to Archaea and Bacteria?
Bacteria and Archaea do not have life cycles characterized by meiosis and fertilization. Archaea
and Bacteria have circular chromosomes. Many Bacteria and Archaea live in environments
where oxygen is absent. Prokaryotic organisms are too small to track in natural environments.
Solution
We know that a species is an interbreeding population, which is isolated from other
populations, this applies for eukaryotic species. The bacteria and archaea undergo asexual
reproduction in which they do not have meiosis and fertilization. Hence option A is answer..
Write a A minimum of 2 pages of text describing the hardware compone.pdf
Write a A minimum of 2 pages of text describing the hardware components of REFERnet
(more info here: http://www.refersoftware.com/refernet.aspx
Paper and should include things such as brand of CPU’s, servers, networks; their speed and
amount of storage; number and type of end-users, etc. You must identify all of the major
hardware elements (components) of the information system, describe the function of each, and
evaluate how well the element is performing that function. Preferably, most of the information
should come from an interview with someone in the IS function at your workplace. This is not to
be a list of specifications but a narrative providing and explaining the specifications along with a
beginning analysis of the hardware elements.
Solution
Computer hardware is the physical parts or segments of a PC, for example, screen, console, PC
information stockpiling, hard plate drive (HDD), realistic card, sound card, memory (RAM),
motherboard, et cetera, all of which are unmistakable physical items.
Computer hardware is the physical parts or segments of a PC, for example, screen, console, PC
information stockpiling, hard plate drive (HDD), realistic card, sound card, memory (RAM),
motherboard, et cetera, all of which are substantial physical objects.[1] By difference,
programming is directions that can be put away and keep running by equipment.
CPU : The CPU is the shortened form for focal preparing unit. Now and then alluded to just as
the focal processor, yet more generally called processor, the CPU is the brains of the PC where
most estimations occur.
The two imoportent parts of a CPU is:
1: The number juggling rationale unit (ALU), the performence of ALU is do the math and
coherent operations.
2 :The control unit (CU) the performence of CU concentrates guidelines from memory and
disentangles and executes them, approaching the ALU when fundamental.
The brands of CPU are,which are uisng in the REFERnet.
Building a PC can be a muddled procedure, particularly on the off chance that you are
unpracticed, considering that there are an interminable mix of parts that you could use to
assemble a framework. There\'s the issue of picking an arrangement of segments that are all good
with each other, alongside different components that you have to weigh, including value, needs
and that\'s only the tip of the iceberg.
With regards to CPUs, you have one of two firms to browse: AMD and Intel. These
organizations make for all intents and purposes the majority of the world\'s desktop PC CPUs,
yet that is the place the similitudes between the two firms end, generally. Along these lines,
should you go for an AMD or Intel CPU when assembling your PC.
Both organizations offer processors at an extensive variety of value focuses, however AMD
chips are accessible for less. The slightest costly Sempron and Athlon double center processors
offer for amongst $30 and $40. Intel\'s slightest costly Celeron, the G1820 double center, is $45.
That doesn\'t really mean A.
Which of the following would be sufficient for the Hardy-Weinberg equ.pdf
Which of the following would be sufficient for the Hardy-Weinberg equation to accurately
predict genotype frequencies from allele frequencies? p + q = 1 the population is not evolving
due to natural selection. the population is not evolving due to any of the conditions that disrupt
Hardy-Weinberg equilibrium. the population is infinitely large. in a village, if the proportion of
individuals who have sickle-cell disease is 0.10, and the population is assumed to be at Hardy-
Weinberg equilibrium, what is the expected frequency of the HbS allele? 0.32 0.18 0.90 0.01 in a
village where the proportion of individuals who are susceptible to malaria (genotype HbA/HbA)
is 0.31, and the population is assumed to be at Hardy-Weinberg equilibrium, what proportion of
the population should be heterozygous HbA/HbS?
Solution
Ans. 5.5. Correct option- C
Option A. Incorrect. A population NOT at Hardy-Weinberg (HW) equilibrium also has p + q= 1.
Since the frequencies p, and q are calculated considering their relative abundance, their sum of
always 1.0. However, the value of p and q changes over generations when population is
evolving. The value of p and q remains constant over generations if the population is at HW
equilibrium.
Option B. Incorrect. Factors other than natural selection, like genetic drift, bottle-neck effect, etc.
also disrupt HW equilibrium. So, even if natural selection does not occur, the population may
evolve through genetic drift, etc.
Option C. Correct. HW equation holds true when no factor causes evolution of the population.
Option D. Incorrect. HW equation holds true when no factor causes evolution of the population.
Being a large population do not exclude the possibilities of evolution.
Ans. 5.6.
Normal, dominant allele = HbA
Mutant, recessive allele = Hbs
Normal, homozygous genotype = HbA HbA - susceptible to malaria
Normal, heterozygous genotype = HbA Hbs - it is a carrier, but unaffected by disease
Recessive, affected genotype = Hbs Hbs - affected with sickle-cell disease
Now,
Hardy- Weinberg Equation for 2 allele system (for a population at HW equilibrium)
p + q = 1 - equation 1
(p + q)2 = p2 + q2 + 2pq = 1 - equation 2
Where,
p = allelic frequency of dominant allele HbA
q = allelic frequency of recessive allele HbS
p2 = genotypic frequency of HbA HbA
q2 = genotypic frequency of Hbs Hbs
2pq = genotypic frequency of HbA Hbs
Given,
Frequency of Hbs Hbsindividuals = q2 = 0.10
Or, q2 = 0.10
Or, q = (0.10)1/2 = 0.316 = 0.32 ; [Note: (0.10)1/2 is under root (.010)]
Hence, frequency of allele HbS = q = 0.32
Correct option. A.
Ans. 5.7
Given,
Frequency of HbA HbAindividuals = p2 = 0.31
Or, p = (0.31)1/2 = 0.55677
Hence, frequency of HbA allele = 0.55677
Putting the value of p in equation 1-
p + q = 1
or, q = 1 – 0.55677 = 0.44323
Hence, q = 0.44323
Now,
Frequency of the heterozygotes (HbA Hbs) = 2 pq = 2 x (0.55677) x (0.44323) = 0.493
Hence, frequency of heterozygotes = 0.493
% of heterozygotes = 49.3 %.
Which of the following is NOT a measure of precision 8 O (A) standar.pdf
Which of the following is NOT a measure of precision? 8 O (A) standard deviation O (B)
median O (C) variance ·(D) range
Solution
The range is not a measure of precision.
The range of values often considers an aunt of confidence probability which depends on the
distribution of the error around the mean value. the other parameter such as median, standard
deviation, and variance all are measures of precision around a central value..
Recommended
Can someone please help me write a case brief for two supreme court .pdf
Can someone please help me write a case brief for two supreme court cases:
1) Terry v. Ohio : https://supreme.justia.com/cases/federal/us/392/1/case.html
and
2) Gideon V. Wainwright : https://supreme.justia.com/cases/federal/us/372/335/cases.html
Solution
U.S. Supreme Court
Terry v. Ohio, 392 U.S. 1 (1968)
Terry v. Ohio
No. 67
Argued December 12, 1967
Decided June 10, 1968
392 U.S. 1
CERTIORARI TO THE SUPREME COURT OF OHIO
MR. CHIEF JUSTICE WARREN delivered the opinion of the Court.
This case presents serious questions concerning the role of the Fourth Amendment in the
confrontation on the street between the citizen and the policeman investigating suspicious
circumstances.
Petitioner Terry was convicted of carrying a concealed weapon and sentenced to the statutorily
prescribed term of one to three years in the penitentiary. [Footnote 1] Following
[5]
the denial of a pretrial motion to suppress, the prosecution introduced in evidence two revolvers
and a number of bullets seized from Terry and a codefendant, Richard Chilton, [Footnote 2] by
Cleveland Police Detective Martin McFadden. At the hearing on the motion to suppress this
evidence, Officer McFadden testified that, while he was patrolling in plain clothes in downtown
Cleveland at approximately 2:30 in the afternoon of October 31, 1963, his attention was attracted
by two men, Chilton and Terry, standing on the corner of Huron Road and Euclid Avenue. He
had never seen the two men before, and he was unable to say precisely what first drew his eye to
them. However, he testified that he had been a policeman for 39 years and a detective for 35, and
that he had been assigned to patrol this vicinity of downtown Cleveland for shoplifters and
pickpockets for 30 years. He explained that he had developed routine habits of observation over
the years, and that he would \"stand and watch people or walk and watch people at many
intervals of the day.\" He added: \"Now, in this case, when I looked over, they didn\'t look right
to me at the time.\"
His interest aroused, Officer McFadden took up a post of observation in the entrance to a store
300 to 400 feet
[6]
away from the two men. \"I get more purpose to watch them when I seen their movements,\" he
testified. He saw one of the men leave the other one and walk southwest on Huron Road, past
some stores. The man paused for a moment and looked in a store window, then walked on a short
distance, turned around and walked back toward the corner, pausing once again to look in the
same store window. He rejoined his companion at the corner, and the two conferred briefly. Then
the second man went through the same series of motions, strolling down Huron Road, looking in
the same window, walking on a short distance, turning back, peering in the store window again,
and returning to confer with the first man at the corner. The two men repeated this ritual
alternately between five and six times apiece -- in all, roughly a dozen trips. At one point, while
the two were s.
Analysis of data collected in a study of educational levels (Did not .pdf
Analysis of data collected in a study of educational levels (Did not complete High school
degree, and College degree), of voters and their political party affiliations (Democrat,
Republican and Independent) resulted X^2 = 13.42. Test with a = 0.01 to determine whether
party affiliation is Independent of the educational level of voters.
Solution
Here, the number of levels for educations level is a = 2.
also, the number of levels for party affiliation is b = 3.
Thus,
df = (a-1)(b-1) = 2
At df = 2, alpha = 0.01, the critical value for chi^2 is
chi^2 (critical) = 9.210340372
As chi^2 = 13.42 > 9.21, then we REJECT THE NULL HYPOTHESIS.
There is significant evidence that party affiliation is NOT INDEPENDENT of the educational
level of voters. [CONCLUSION].
As individuals age, they are likely to becomeMore alike and less .pdf
As individuals age, they are likely to become:
More alike and less individual
Increasingly stubborn and difficult
More compliant and less demanding
More like themselvesa.
More alike and less individualb.
Increasingly stubborn and difficultc.
More compliant and less demandingd.
More like themselves
Solution
Ans. It depends upon the individual but in most of the cases it has been observed the responsible
ones become more compliant and less demanding and the one which has an attitude problem
tends to be more stubborn and difficult..
APARTMENT BUILDING HOMEWORK1 What’s the problemSuppose you want.pdf
APARTMENT BUILDING HOMEWORK
1 What’s the problem?
Suppose you want to model an apartment building so that you can calculate the number of
windows (and their sizes) that are in the building. We are modelling the building with the
following classes:
1. Building, which contains several types of apartments.
2. Apartment and its subclasses OneBedroom, TwoBedroom, and ThreeBedroom. An instance of
this class is to represent a type of apartments, which includes a field to store the number of units
of this type.
3. Room and its subclass LivingRoom, MasterBedroom, and GuestRoom. Each room has some
windows of certain size. Different type of rooms have windows of different sizes.
4. Window and WindowOrder Window object has just the width and height of the window.
Window order object has a window object and the number of window for that order.
2 What to implement?
You will fill in the methods for classes described above. The provided code template has
instruction in the comments above the methods that you will implement.
3 What is provided? We provide a driver class Hwk6.java, a test class Test.java, and a bunch of
template classes. Note that each file may contain multiple classes. I usually group related classes
in the same file. For example, the file Apartment.java contains not only Apartment class but also
its subclasses.
4 What does output look like? If you run the driver class Hwk6.java you will see output that
looks like the followings.
20 apartments with (Living room: 5 (6 X 8 window)) (Master bedroom: 3 (4 X 6 window))
15 apartments with (Living room: 5 (6 X 8 window)) (Master bedroom: 3 (4 X 6 window))
(Guest room: 2 (5 X 6 window))
10 apartments with (Living room: 5 (6 X 8 window)) (Master bedroom: 3 (4 X 6 window))
(Guest room: 2 (5 X 6 window)) (Guest room: 2 (5 X 6 window))
Window orders are:
300 6 X 8 window
180 4 X 6 window
120 5 X 6 window
PROVIDED MAIN CLASS
package hwk6;
public class Hwk6 {
public static void main(String[] args) {
Apartment[] apartments = { new OneBedroom(20), new TwoBedroom(15), new
ThreeBedroom(10) };
Building building = new Building(apartments);
WindowOrder[] orders = building.order();
System.out.println(building);
System.out.println(\"Window orders are: \");
for(WindowOrder order: orders) {
System.out.println(order);
}
}
}
Building Template:
package hwk6;
public class Building {
Apartment[] apartments;
public Building(Apartment[] apartments) {
this.apartments= apartments;
}
// Return an array of window orders for all apartments in the building
// Ensure that the orders for windows of the same sizes are merged.
WindowOrder[] order() {
// TODO
}
// return a string to represent all types of apartments in the building such as:
// 20 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6 window))
// 15 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6
window))(Guest room: 2 (5 X 6 window))
// 10 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6
window))(Guest.
Why does Ernst Mayrs biological species concept NOT apply to Archae.pdf
Why does Ernst Mayr\'s biological species concept NOT apply to Archaea and Bacteria?
Bacteria and Archaea do not have life cycles characterized by meiosis and fertilization. Archaea
and Bacteria have circular chromosomes. Many Bacteria and Archaea live in environments
where oxygen is absent. Prokaryotic organisms are too small to track in natural environments.
Solution
We know that a species is an interbreeding population, which is isolated from other
populations, this applies for eukaryotic species. The bacteria and archaea undergo asexual
reproduction in which they do not have meiosis and fertilization. Hence option A is answer..
Write a A minimum of 2 pages of text describing the hardware compone.pdf
Write a A minimum of 2 pages of text describing the hardware components of REFERnet
(more info here: http://www.refersoftware.com/refernet.aspx
Paper and should include things such as brand of CPU’s, servers, networks; their speed and
amount of storage; number and type of end-users, etc. You must identify all of the major
hardware elements (components) of the information system, describe the function of each, and
evaluate how well the element is performing that function. Preferably, most of the information
should come from an interview with someone in the IS function at your workplace. This is not to
be a list of specifications but a narrative providing and explaining the specifications along with a
beginning analysis of the hardware elements.
Solution
Computer hardware is the physical parts or segments of a PC, for example, screen, console, PC
information stockpiling, hard plate drive (HDD), realistic card, sound card, memory (RAM),
motherboard, et cetera, all of which are unmistakable physical items.
Computer hardware is the physical parts or segments of a PC, for example, screen, console, PC
information stockpiling, hard plate drive (HDD), realistic card, sound card, memory (RAM),
motherboard, et cetera, all of which are substantial physical objects.[1] By difference,
programming is directions that can be put away and keep running by equipment.
CPU : The CPU is the shortened form for focal preparing unit. Now and then alluded to just as
the focal processor, yet more generally called processor, the CPU is the brains of the PC where
most estimations occur.
The two imoportent parts of a CPU is:
1: The number juggling rationale unit (ALU), the performence of ALU is do the math and
coherent operations.
2 :The control unit (CU) the performence of CU concentrates guidelines from memory and
disentangles and executes them, approaching the ALU when fundamental.
The brands of CPU are,which are uisng in the REFERnet.
Building a PC can be a muddled procedure, particularly on the off chance that you are
unpracticed, considering that there are an interminable mix of parts that you could use to
assemble a framework. There\'s the issue of picking an arrangement of segments that are all good
with each other, alongside different components that you have to weigh, including value, needs
and that\'s only the tip of the iceberg.
With regards to CPUs, you have one of two firms to browse: AMD and Intel. These
organizations make for all intents and purposes the majority of the world\'s desktop PC CPUs,
yet that is the place the similitudes between the two firms end, generally. Along these lines,
should you go for an AMD or Intel CPU when assembling your PC.
Both organizations offer processors at an extensive variety of value focuses, however AMD
chips are accessible for less. The slightest costly Sempron and Athlon double center processors
offer for amongst $30 and $40. Intel\'s slightest costly Celeron, the G1820 double center, is $45.
That doesn\'t really mean A.
Which of the following would be sufficient for the Hardy-Weinberg equ.pdf
Which of the following would be sufficient for the Hardy-Weinberg equation to accurately
predict genotype frequencies from allele frequencies? p + q = 1 the population is not evolving
due to natural selection. the population is not evolving due to any of the conditions that disrupt
Hardy-Weinberg equilibrium. the population is infinitely large. in a village, if the proportion of
individuals who have sickle-cell disease is 0.10, and the population is assumed to be at Hardy-
Weinberg equilibrium, what is the expected frequency of the HbS allele? 0.32 0.18 0.90 0.01 in a
village where the proportion of individuals who are susceptible to malaria (genotype HbA/HbA)
is 0.31, and the population is assumed to be at Hardy-Weinberg equilibrium, what proportion of
the population should be heterozygous HbA/HbS?
Solution
Ans. 5.5. Correct option- C
Option A. Incorrect. A population NOT at Hardy-Weinberg (HW) equilibrium also has p + q= 1.
Since the frequencies p, and q are calculated considering their relative abundance, their sum of
always 1.0. However, the value of p and q changes over generations when population is
evolving. The value of p and q remains constant over generations if the population is at HW
equilibrium.
Option B. Incorrect. Factors other than natural selection, like genetic drift, bottle-neck effect, etc.
also disrupt HW equilibrium. So, even if natural selection does not occur, the population may
evolve through genetic drift, etc.
Option C. Correct. HW equation holds true when no factor causes evolution of the population.
Option D. Incorrect. HW equation holds true when no factor causes evolution of the population.
Being a large population do not exclude the possibilities of evolution.
Ans. 5.6.
Normal, dominant allele = HbA
Mutant, recessive allele = Hbs
Normal, homozygous genotype = HbA HbA - susceptible to malaria
Normal, heterozygous genotype = HbA Hbs - it is a carrier, but unaffected by disease
Recessive, affected genotype = Hbs Hbs - affected with sickle-cell disease
Now,
Hardy- Weinberg Equation for 2 allele system (for a population at HW equilibrium)
p + q = 1 - equation 1
(p + q)2 = p2 + q2 + 2pq = 1 - equation 2
Where,
p = allelic frequency of dominant allele HbA
q = allelic frequency of recessive allele HbS
p2 = genotypic frequency of HbA HbA
q2 = genotypic frequency of Hbs Hbs
2pq = genotypic frequency of HbA Hbs
Given,
Frequency of Hbs Hbsindividuals = q2 = 0.10
Or, q2 = 0.10
Or, q = (0.10)1/2 = 0.316 = 0.32 ; [Note: (0.10)1/2 is under root (.010)]
Hence, frequency of allele HbS = q = 0.32
Correct option. A.
Ans. 5.7
Given,
Frequency of HbA HbAindividuals = p2 = 0.31
Or, p = (0.31)1/2 = 0.55677
Hence, frequency of HbA allele = 0.55677
Putting the value of p in equation 1-
p + q = 1
or, q = 1 – 0.55677 = 0.44323
Hence, q = 0.44323
Now,
Frequency of the heterozygotes (HbA Hbs) = 2 pq = 2 x (0.55677) x (0.44323) = 0.493
Hence, frequency of heterozygotes = 0.493
% of heterozygotes = 49.3 %.
Which of the following is NOT a measure of precision 8 O (A) standar.pdf
Which of the following is NOT a measure of precision? 8 O (A) standard deviation O (B)
median O (C) variance ·(D) range
Solution
The range is not a measure of precision.
The range of values often considers an aunt of confidence probability which depends on the
distribution of the error around the mean value. the other parameter such as median, standard
deviation, and variance all are measures of precision around a central value..
Write C++ variable declarations to create one int variable called num.pdf
Write C++ variable declarations to create one int variable called number, two real variables
called signal and pi where pi is initialized to 3 .14159, and two bool variables called flag and bit
where flag is initialized to false. No main () program is necessary and comments are optional. Be
sure to strike the Enter key before you click on the Save button.
Solution
int number;
double signal;
double pi=3.14159;//initialized
bool flag=false;//initialized
bool bit;.
Why do a lot of scientist feel like god doesnt exist What is th.pdf
Why do a lot of scientist feel like god doesn\'t exist? What is their reasoning for? What evidence
supports their claims?
Why do a lot of scientist feel like god doesn\'t exist? What is their reasoning for? What evidence
supports their claims?
Solution
A lot of scientist feels like god does not exist because of evolutionary and natural selection
aspects of species in their natality & mortality and during their individual development. Every
species evolution is scientifically correlated with various evidences that species was not created
by a specific \"creator\" because species has created from biological matter finally from
prokaryotes to eukaryotes. Some scientists have supported that the belief of human growth and
emotions are completely hormone related but not due to \"creator or God\". There are other
evidences as described that the natural selection is not associated with \"myths & belief of God\"
and it has completely different to explain the kind of adaptations acquired by the species during
evolution. Theological aspects are independent of structural adaptations developed by the
individual species as these adaptations are completely relies upon genetic variations Evolution in
terms of natural selection and natural theology is not a common topic of conversation because it
is an offensive subject a better conversation due to insufficient evidence about the origin of
species and creation. Origin of species either by a creator or by nature is still in a great religious
debate as various scientific hypotheses are describing that evolution started from aquatic region
to land stage according to natural selections and genetic variations but various philosophical,
religious and mythological beliefs are describing that evolution is from a unknown creator and
nature. There is no availability of adequate evidence to resolve this great debate so people might
just not or talk about creation or evolution at all..
What is the United States Comparative Advantage....please be specifi.pdf
What is the United States Comparative Advantage....please be specific if you can..
Solution
United States is richly endowed with highly educated workforce and technologically
sophisticated machinery and equipment. These endowments help United States in producing
human capital and physical capital intensive goods at lower opportunity cost vis-à-vis rest of the
world.
Production at lower opportunity cost implies that United States has comparative advantage in
production of human and physical capital intensive goods.
Semi-conductor, industrial machines, telecommunication equipments, civilian aircraft, organic
chemicals are some product categories that are both physical and human capital intensive and if
we analyze the export data of United States then we can see that top exports of United States
comprises of these very items. In fact, if we list the top 15 export items in United States then
almost all items comprises of goods that are capital intensive in nature both in terms of physical
capital as well as human capital.
Thus, United States has comparative advantage in production of capital (both human and
physical) intensive goods..
true false 1, Sampling is always wrong because it is stup.pdf
true/ false
1, Sampling is always wrong because it is stupid trying studying 300 million people with a
sample of 1500 2. Probability samples are the same as accidental samples. 3. The most important
feature of probability sampling is thatall members of the population have an equal chance of
representation 4. Snowball samples accumulate subjects through chains of referrals and are most
commoaly used in qualitative research 5. Stratification is the process of grouping the members of
a population into relatively homogencus strata before sampling 6. Sampling distributions are the
same as frequeney distributions in all material respects. 7. Samples generate parameter estimates
while populations generate statistics 8. The most carefully selected sample is almost never a
perfect representation of the population from which it was gathered. Some degree of sampling
error always exists. All naturally or randomly oocurring empirikal phenomena are normally
distributed. 10. In general, non-probability-sampling methods are not regurded as less reliable
than probability 9. samples. 11. Survey research involves the administration of questionnaires to
a sample of respondents selected from some population 12. Questionnaires may be administered
in four different ways: face-to-face interviews, telephone surveys, mail-surveys, and internet
surveys. 13. Face-to-face interviews are the very best method of survey research in all
circumstances 14. In survey research, response rates are the proportion of the sample that
actually completes the -15. An experiment is a method of scientific inquiry in which an
independent variable is deliberately manipulated in order to observe its effect on the dependent
variable
Solution
1) TRUE that is why we have sampling errors that we take into account in the calculation . Still
some sampling errors are unavoidable.
2)False probability sampling is a sampling technique in which probability of getting a sample is
calculated.
while accidental sampling does not meet this criterion.
3) FALSE in probabilistic sampling all members have equal chance of selection
4) TRUE it is right that snow ball sampling accumulates subject through chain of accumulation
but they are biased because they give people with higher social connection higher chance of
selection. This is non probabilistic sampling and used in qualitative research generally for those
groups which are hidden . These are not accessible to researchers through other methods..
The rearrangement of alleles by the process of crossing over is call.pdf
The rearrangement of alleles by the process of crossing over is called genetic linkage.
True or False
Solution
The answer is \"False\"
Crossing over is a physical exchange of genetic material between non-sister chromatids of two
homologus chromosomes. Crossing over is a method of exchange of genetic material during
meiosis I following synapsis.
Genetic linage, linked genes sit close together on a chromosome, making them likely to be
inherited together..
Susie has influenza A. She lives in a residence hall where there hav.pdf
Susie has influenza A. She lives in a residence hall where there have been 3 reported cases. She
also works in the recreation facility teaching several group fitness classes. Answer the following
questions about influenza.
1)Identify the cause of influenza and the effects it has on the lungs?
2)What education should be provided to residents, coworkers, and members of the recreation
facility regarding influenza?
3)At this point in the development of Susie’s illness is it safe to assume her roommates and
coworkers have all been exposed to the influenza?
4)Should Susie be allowed to participate in Midwest Fit Fest, a large group fitness instructor
conference this weekend? Why or why not?
5)What precautions can you take within your profession to limit your risk of infection?
6)Why do antibacterial drugs are not directly effective in the treatment of influenza.
Solution
1) The cause of influenza infection is influenza A virus. The virus contains 8 fragments of
segmented RNA. The viral coat contains glycoproteins neuraminidase and haemeagglutinin. The
virus exhibit antigenic drift and shift by changing these surface glycoprotein structures. Influenza
A virus causes flu with symptoms of high fever, chills, running nose, muscle and body pains and
fatigue. The lungs are severly infected due to body immune action against the virus causing
inflammation. Due to this, airways are obstructed and breathing becomes difficult.
2) Influenza is a contact disease and is spread by secretions, nasal droplets in air during sneezing
and coughing and also by unhygenic contact of clothes and surfaces containing secretions. The
coworkers and residents are educated to avoid contact of unhygenic surfaces and clothes. They
need to maintain some distance with the patient and better to wear masks to avoid inhalation of
droplets. The hands must be cleaned with handwash to maintain the hygiene. The floor and
surfaces are cleaned with disinfectants. The room is exposed to sunlight.
3) It is not safe for the coworkers and roommates to get exposed to Susie\'s illness. This is
because, the illness is highly communicable and spread rapidly leading to an endemic.
4) Susie is not allowed to participate in Midwest Fit Fest, a large group fitness instructor
conference during the weekend. This is because, she is a potent carrier of viral organisms and
may spread the disease to several others. So, to avoid spreading of disease she is not allowed to
attend the conference.
5) To avoid the risk of spreading infection precautions are taken. The precautions include the
wearing of mask, keeping covered when sneezing and coughing, keeping the surfaces , clothes
and hands always clean. Keeping the room exposed to sunlight and ventilation.
6) Since, influenza is a viral infection, antibacterial drugs does not show their effect on infection
and require antiviral agents to treat the infection..
Section 5 Controlling Risk Given the following categories or areas .pdf
Section 5: Controlling Risk Given the following categories or areas where risk exists, and then
the 3 assets for each, describe how you will test for associated risk: Administrative Human
resources: Hiring and termination practices Organizational structure: A formal security program
Security policies: Accurate, updated, and known or used Technical Access control: Least
privileged System architecture: Separated network segments System configurations: Default
configurations Physical Heating and air conditioning: Proper cooling and humidity Fire: Fire
suppression Flood: Data center location Once you have described the tests that will be conducted
to test each, assume that failure or holes were found in each of them. Next, describe at least 3
safeguards for each that could be put in place to address the risk.
Solution
Hazard administration is the procedure of distinguishing proof, examination and
acknowledgment or alleviation of instability in speculation choices. Basically, chance
administration happens whenever a speculator or asset chief examines and endeavors to measure
the potential for misfortunes in a venture and after that makes the fitting move (or inaction) given
his venture targets and hazard resistance.
The only sure way to avoid risk in nonprofits would be to lock the doors and put up a closed sign
in the window. Risks are inevitable and organizations have a moral and legal obligation to attend
to the safety and well-being of those they serve, those who work for them and others who come
into contact with their operations. This is known as \"Duty of Care.\"
Organizations need to look at all the risks throughout their entire operation and incorporate risk
management into all planning and decision-making. However, the specific focus of this section is
risk management as it applies to HR activities.
HR Activity Potential Risk Potential considerations
Hiring
While HR began discussing best termination practices three decades ago, much of that
conversation was from the standpoint of protecting the company rather than considering an
employee\'s feelings and future. In 1998, the Five O’Clock Club introduced the concept of
“termination with dignity” after a three-month project re-examining every part of the termination
process with the help of HR leaders and ethicists. “Phrases like termination with kindness or
termination with consideration don’t have the same depth of meaning,” explained Kate
Wendleton, the Five O’Clock Club’s founder. “The word ‘dignity’ carries a special weight; it has
historically been used by the United Nations with regard to human rights, by the Dalai Lama, and
by various religious and philosophical leaders. ‘Dignity’ means that humans should be treated as
persons, rather than objects that you are used to seeing and then throw away.” While other firms
have since copied the Club’s terminology, Wendleton pointed out, what lies behind many of their
programs is far from dignified.
HiringDiscriminatory practicesHiring unsuit.
5)Sonny has the following account balances as of January 1, 2018 bef.pdf
5)Sonny has the following account balances as of January 1, 2018 before an acquisition
transaction takes place.
The fair value of Sonny\' Land and Buildings are $200,000 and $300,000, respectively. On
January 1, 2018, Phillip Company issues 30,000 shares of its $10 par value ($25 fair value)
common stock in exchange for all of the shares of Sonny\' common stock. Phillip paid $10,000
for costs to issue the new shares of stock. Before the acquisition, Phillip has $700,000 in its
common stock account and $300,000 in its additional paid-in capital account.
On January 1, 2018, what value is assigned to Phillip\'s investment account?
A. $150,000.
B. $300,000.
C. $750,000.
D. $760,000.
E. $1,350,000.
6)Acquired in-process research and development is considered as
A. an indefinite-lived asset subject to testing for impairment.
B. a definite-lived asset subject to testing for impairment.
C. an indefinite-lived asset subject to amortization.
D. a definite-lived asset subject to amortization.
E. a research and development expense at the date of acquisition.
7) Sonny has the following account balances as of January 1, 2018 before an acquisition
transaction takes place.
The fair value of Sonny\' Land and Buildings are $200,000 and $300,000, respectively. On
January 1, 2018, Phillip Company issues 30,000 shares of its $10 par value ($25 fair value)
common stock in exchange for all of the shares of Sonny\' common stock. Phillip paid $10,000
for costs to issue the new shares of stock. Before the acquisition, Phillip has $700,000 in its
common stock account and $300,000 in its additional paid-in capital account.
Immediately after the acquisition, what is the consolidated additional paid in capital?
A. $500,000.
B. $740,000.
C. $750,000.
D. $760,000.
E. $940,000.Inventory$100,000Land400,000Buildings (net)500,000Common
stock600,000Additional paid in capital200,000Retained
Earnings200,000Revenues450,000Expenses250,000
Solution
Part 5)
The value assigned to Phillip\'s investment account is determined as below:
Value Assigned to Philip\'s Investment Account = Number of Shares Issued*Fair Value Per
Share
Using the values provided in the question, we get,
Value Assigned to Philip\'s Investment Accounton January 1 2008 = 30,000*25 = $750,000
(which is Option C)
_____
Part 6)
An indefinite-lived asset subject to testing for impairment. (which is Option A)
_____
Explanation:
As per the applicable accounting rules/standards, the value of in-process research and
development is capitalized as an asset for the combined entity. It is treated as an intangible asset
having an indefinite life and is subject to impairment.
_____
Part 7)
The value of consolidated additional paid in capital is arrived as below:
Value of Consolidated Additional Paid in Capital = Current Balance in Phillip\'s Additional Paid-
In Capital Account + Increase in Additional Paid in Capital on the Date of Acquisition
Using the values provided in the question, we get,
Value of Consolidated Additional Paid.
Question In C Programming In mathematics, a set is a colle...Sav.pdf
Question: In C Programming: In mathematics, a set is a colle...
Save
In C Programming:
In mathematics, a set is a collection of distinct elements (say integer numbers). For example,
A={2, 5, 7} and B={3, 5, 8, 10} are two different sets. There are several basic operations for
constructing new sets from given two sets, but let\'s just consider three basic ones:
C = union(A,B); ---> C = A B={2, 5, 7, 8, 10} C = intersection(A,B); ---> C = A B={5}
C = difference(A,B); ---> C = A-B = A \\ B ={2, 7} also aka. complement
You are asked to develop a set library (using two different representations: array and link list)
and then implement a driver program that gets two sets and one of the above operation as a
command to apply, then it prints the resulting set...
Developing set library: For interface, create an interface file set.h which contains boiler plate and
the followings:
typedef int setElementT;
typedef struct setCDT *setADT;
setADT setNew(); /* create a new empty set */
void setFree(setADT S); /* free the space allocated for the set S */
int setInsertElementSorted(setADT S, setElementT E);
/* if not successful, return 0; otherwise, return the num of elements after the insertion. Also note
that the elements might be given in different orders, but your function should always keep the set
in a sorted manner after each insertion */
setADT setUnion(setADT A, setADT B);
/* returns a new set containing A B */
setADT setIntersection(setADT A, setADT B);
/* returns a new set containing A B */
setADT setDifference(setADT A, setADT B);
/* returns a new set containing A \\ B */
int setCardinality(setADT S);
/* return the number of elements in S */
void setPrint(setADT S, char *name);
/* print elements of S, A = {2, 5, 7} */
For implementation, you will be asked to have two different implementations:
(40pt) First implement set library as setArrayImp.c which uses a constant size array to store set
elements (suppose max set size is 100). [hint: see ch2 slides 72-78 ]
(40pt) Second implement this library as setLinkedListImp.c which uses a dynamic single linked
list to store set elements.
Develop a driver.c program and compile it with two different imp of set library (20 pt)
1. Create two sets called A and B.
2. Ask user to enter positive integers for set A (end input when user enters -1)
3. Ask user to enter positive integers for set B (end input when user enters -1)
4. In a loop 4.1. Ask user to enter a command:
4.2 If Q is entered, quit from this loop.
4.3 If U, I, or D is entered, compute set C as union, intersection, or difference. setPrint(A, \"A\");
setPrint(A, \"B\"); setPrint(C, \"C\"); print the number of elements in C setFree(C);
5. free A and B
Compile/execute driver.c with setArrayImp.c as well as setListImp.c
//no include files needed
Solution
Create set.h first with the following
typedef int setElementT;
typedef struct setCDT *setADT;
setADT setNew(); /* Creates a new empty set */
void setFree(setADT S); /* Frees the space allocated for the set .
Q1. What is the primary reason that Fenders blue butterflies are e.pdf
Q1. What is the primary reason that Fender\'s blue butterflies are endangered?
The recent increase in fire frequency and severity has greatly reduced habitat quality.
The butterfly\'s primary host plant, Kincaid\'s lupine, became extinct in the 1930s.
Increases in disease prevalence and predation have diminished their numbers.
Urbanization and agriculture have reduced and fragmented the butterfly\'s preferred habitat.
Solution
Option (d) is correct: Urbanization and agriculture have reduced and fragmented the butterfly\'s
prefered habitat.
Fender\'s blue butterfly is an endangered subspecies of butterfly endemic to the Willamette
Valley of northwestern Oregon, United States. The prime reason for its population decline is that
its native prairie habitat has been largely converted to agriculture, subjected to fire suppression
and invaded by non-native plants. With massive changes in the fire regime, disturbances that
maintained native prairies have been greatly altered, allowing tree and shrub species to invade
and shade out low-growing Kincaid\'s lupine, the species upon which this butterfly depends.
Also,the non-native species such as Himalayan blackberry has aggressively overtaken open
spaces.
Loss of native prairie habitat has resulted in the isolation of butterfly populations. Thus, these
butterfly populations are more vulnerable to natural and human-made disturbances. As the
number of sites have declined and the distance between them has increased and the opportunities
for adult movement between populations are reduced, which were earlier inter-connected. Thus
the Fender\'s blue butterflies populations is isolated, has become endangered and faces a higher
risk of extinction..
Normality assumption is very important. A researcher is interested i.pdf
Normality assumption is very important. A researcher is interested in studying body temperature.
He collected the data below from 10 persons. Could you please as a statistician check the data
follow Normal distribution or not using Normal quantile plot?
96.3 96.7 96.9 97.0 97.1 97.1 97.2 97.4 95.5 97.1
Solution
The normal probability plot is
The points are in the form of a straight line. therefore the given data is normal..
Punnett square Father and mother are heterozygous and each are .pdf
Punnett square: Father and mother are heterozygous and each are carriers for a dominant linked
disorder. What is the % chance the child will be born with the disorder
Punnett square: Father and mother are heterozygous and each are carriers for a dominant linked
disorder. What is the % chance the child will be born with the disorder
Punnett square: Father and mother are heterozygous and each are carriers for a dominant linked
disorder. What is the % chance the child will be born with the disorder
Solution
parents
A
a
A
AA
Aa
a
Aa
aa
Since parents are heterozygotic carriers their phenotype is Aa Aa
The gamets are A a
Progeny 25%AA 50%Aa 25%aa ie 1:2:1
25% chance for having the disease(AA)
parents
A
a
A
AA
Aa
a
Aa
aa.
Property Values Is this rooted tree Leaf vertices Intenal vertices A.pdf
Property Values Is this rooted tree? Leaf vertices Intenal vertices Ancestors of vertice H Decend
ants of vertice D Siblings of vertice G Parent vertice of F Given the following tree, fill out the
table
Solution
yes it is a rooted tree
b)K,L,M ,G,F,I,J are leafs
c)intenal vertices:B,C,D,E,H
D)A
E)M
F)E,F,H,I,J
G)B.
Predict the type of bonding that holds the following atomsmolecules .pdf
Predict the type of bonding that holds the following atoms/molecules together in the following
solid materials. Briefly explain why you have made the prediction for each material. Where
appropriate include calculations. BaO CdS FeO Brass (a copper rich copper-zinc alloy) Solid
neon Polyethylene (a largely linear thermoplastic polymer) AIP
Solution
In Bao , CDs , FeO ionic bonding exist as it is between metal and nom metal ..Ba , Cd , Fe, exists
as cations in +2 state and O as -2 anion.
In Brass metallic bonding exist since only metals are present.
In solid neon vanderwalls force of attraction exists since it is inert gas .
In polyethylene and Aip covalent bond exist . Polyethylene is polymer of ethylene. And AIP
exist as solid plastics..
Please Explain CompletelyWhat is the reason the celiac trunk calle.pdf
Please Explain Completely
What is the reason the celiac trunk called a \"trunk.\" ? is it related to its length?
Solution
celiac trunk is the first major branch of abdominal aorta. it is the largest artery in abdominal
aorta, with its three branhes it supply oxygen to stomach,spleen,eosophagus,deodenum,panreas.
its name trunk is related to its lenght as it is the largest artery in abdominal aorta..
Paraphrase the following passageLong before scientists were able .pdf
Paraphrase the following passage:
Long before scientists were able to record spikes, they were able to stimulate the nervous system
using batteries (Leyden Jars experiment). Since nerves use electricity to communicate, they can
be manipulated with electricity as well. Luigi Galvani, an Italian scientist in the 1700’s,
discovered that electricity applied to the nerves of frog legs caused the large muscles to twitch.
Such discoveries led to debates at the time as to whether “animal electricity” was different from
the electricity during lightning storms. Galvani also tested this by hanging frogs legs off his back
porch during the thunderstorms and watching the legs twitch. Eventually, the scientific
community discovered that while electricity can indeed stimulate nervous system and muscle
tissue, the tissue itself generates electricity. This led to the beginnings of contemporary
neuroscience. In another famous experiment, German Medical Scientist Eduard Hitzig and
Gustav Fritsch in 1870 applied electricity current to the exposed cerebral cortex (wrinkly part of
brain) in dogs in their kitchen, showing that stimulation of different parts of the brain can cause
different types of movements.
Solution
The depolarization and spike production from neurons of nervous system was examined by the
various scientist through various experiments finally unraveled the neurons are going to work
through nerve potential such as electric potential to communicate (Scientist Leyden). This
electric potential have triggered twitching muscle activity via motor neurons & these aspects
were examined by working on large leg muscles of frog (L Galvani 1700) finally deduced that
animal electric potential id differed from electric potential observed during lightening. Therefore
these neuroscience research aspects have meticulously have later examined in exposed cerebral
cortex using electric current onto the “neurons of dogs” finally observed differential muscle
movements (E Hitzig 1870).
Plant diversityConiferophyta and anthrophyta do not haveuse flag.pdf
Plant diversity:
Coniferophyta and anthrophyta do not have/use flagellated sperm like all the other plant phyla.
Explain how their sperm move and fertilization takes place without flagella
Solution
The members of these phyla are wind and animal pollinated. Pollen grain move from stamen to
stigma via the action of wind or through an animal mediator. Pollen moves from staminate cones
reaches the stigma of ovulate cones. Ovulate cones have open scales. Upon arrival of pollen, the
scales close. Then, the pollen moves down towards the megasporangium. Fertilization occurs.
So, fertilization occurs without flagella..
Joe digs a ditch in 3.2 hours. Joe working with George can did the.pdf
Joe digs a ditch in 3.2 hours.
Joe working with George can did the same length ditch in 2.7 hours.
How long would it take George to dig the ditch by himself ?
Solution
Joe digs a ditch in 3.2 hours...so in 1 hour he digs 1/3.2 ditch=10/32=5/16
let george alone take x hrs to dig the ditch...so in 1 hour he digs 1/x ditch
so in 1 hour joe and george together dig 5/16+1/x ditch =(5x+16)/16x
so they take 16x/(5x+16) hrs to dig the ditch together
but this given as 2.7 hours
so 16x/(5x+16)=2.7
cross multiplying we get
16x=2.7(5x+16)=13.5x+43.2
16x-13.5x=43.2
2.5x=43.2
x=43.2/2.5=432/25=17.28 hours
so george alone takes 17.28 hrs to dig the ditch.
In some regions, particular plant foods are emphasized. As a specifi.pdf
In some regions, particular plant foods are emphasized. As a specific example, potatoes are
traditionally a major part of the diet in Ireland, Norway, and Lithuania. What does the ecological
setting have to do with this food-eating custom?
Solution
Ecological environment decides the food eating customs of people in that area. The food taken
by people daily, depends on the type of weather in that area. Places that are colder, people tend
to eat things with warm in metabolism, there. Places that are hot, people eat such food items
there, which can provide them relief from excess heat. Potato is a rich source of carbohydrate
and is warm food that provides heat to the body in its metabolism, so Ireland Norway Luthiania
being colder places, people opt to eat potato to maintain their body temperature.
The same way, In India nothern part is very cold, so people eat lot of dry fruits, rajma, chana,
meat, bajra and wheat in their diet. Such foods provide them warmth. In southern part of India,
there is hot temperature most of the year, so people there eat rice as main food, coconut water,
Vegetable stock like Rasam are included in food. Such foods provides them relief from heat..
In binary star systems we can often measure the sum of the masses of.pdf
In binary star systems we can often measure the sum of the masses of the stars and the ratio of
their masses. If m1+ m2= Mtot, and m1/m2= Y, derive an expression for the mass of each star in
terms of just Mtotand Y.
Solution
=>m1/m2 = Y
m1 =Ym2-------------1
=>m1+m2 =Mtot
Ym2+m2 = Mtot
(Y+1)m2 =Mtot
=>m2=Mtot/(Y+1)
From 1
=>m1= [Y/(Y+1)]Mtot.
MARUTI SUZUKI- A Successful Joint Venture in India.pptx
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Write C++ variable declarations to create one int variable called num.pdf
Write C++ variable declarations to create one int variable called number, two real variables
called signal and pi where pi is initialized to 3 .14159, and two bool variables called flag and bit
where flag is initialized to false. No main () program is necessary and comments are optional. Be
sure to strike the Enter key before you click on the Save button.
Solution
int number;
double signal;
double pi=3.14159;//initialized
bool flag=false;//initialized
bool bit;.
Why do a lot of scientist feel like god doesnt exist What is th.pdf
Why do a lot of scientist feel like god doesn\'t exist? What is their reasoning for? What evidence
supports their claims?
Why do a lot of scientist feel like god doesn\'t exist? What is their reasoning for? What evidence
supports their claims?
Solution
A lot of scientist feels like god does not exist because of evolutionary and natural selection
aspects of species in their natality & mortality and during their individual development. Every
species evolution is scientifically correlated with various evidences that species was not created
by a specific \"creator\" because species has created from biological matter finally from
prokaryotes to eukaryotes. Some scientists have supported that the belief of human growth and
emotions are completely hormone related but not due to \"creator or God\". There are other
evidences as described that the natural selection is not associated with \"myths & belief of God\"
and it has completely different to explain the kind of adaptations acquired by the species during
evolution. Theological aspects are independent of structural adaptations developed by the
individual species as these adaptations are completely relies upon genetic variations Evolution in
terms of natural selection and natural theology is not a common topic of conversation because it
is an offensive subject a better conversation due to insufficient evidence about the origin of
species and creation. Origin of species either by a creator or by nature is still in a great religious
debate as various scientific hypotheses are describing that evolution started from aquatic region
to land stage according to natural selections and genetic variations but various philosophical,
religious and mythological beliefs are describing that evolution is from a unknown creator and
nature. There is no availability of adequate evidence to resolve this great debate so people might
just not or talk about creation or evolution at all..
What is the United States Comparative Advantage....please be specifi.pdf
What is the United States Comparative Advantage....please be specific if you can..
Solution
United States is richly endowed with highly educated workforce and technologically
sophisticated machinery and equipment. These endowments help United States in producing
human capital and physical capital intensive goods at lower opportunity cost vis-à-vis rest of the
world.
Production at lower opportunity cost implies that United States has comparative advantage in
production of human and physical capital intensive goods.
Semi-conductor, industrial machines, telecommunication equipments, civilian aircraft, organic
chemicals are some product categories that are both physical and human capital intensive and if
we analyze the export data of United States then we can see that top exports of United States
comprises of these very items. In fact, if we list the top 15 export items in United States then
almost all items comprises of goods that are capital intensive in nature both in terms of physical
capital as well as human capital.
Thus, United States has comparative advantage in production of capital (both human and
physical) intensive goods..
true false 1, Sampling is always wrong because it is stup.pdf
true/ false
1, Sampling is always wrong because it is stupid trying studying 300 million people with a
sample of 1500 2. Probability samples are the same as accidental samples. 3. The most important
feature of probability sampling is thatall members of the population have an equal chance of
representation 4. Snowball samples accumulate subjects through chains of referrals and are most
commoaly used in qualitative research 5. Stratification is the process of grouping the members of
a population into relatively homogencus strata before sampling 6. Sampling distributions are the
same as frequeney distributions in all material respects. 7. Samples generate parameter estimates
while populations generate statistics 8. The most carefully selected sample is almost never a
perfect representation of the population from which it was gathered. Some degree of sampling
error always exists. All naturally or randomly oocurring empirikal phenomena are normally
distributed. 10. In general, non-probability-sampling methods are not regurded as less reliable
than probability 9. samples. 11. Survey research involves the administration of questionnaires to
a sample of respondents selected from some population 12. Questionnaires may be administered
in four different ways: face-to-face interviews, telephone surveys, mail-surveys, and internet
surveys. 13. Face-to-face interviews are the very best method of survey research in all
circumstances 14. In survey research, response rates are the proportion of the sample that
actually completes the -15. An experiment is a method of scientific inquiry in which an
independent variable is deliberately manipulated in order to observe its effect on the dependent
variable
Solution
1) TRUE that is why we have sampling errors that we take into account in the calculation . Still
some sampling errors are unavoidable.
2)False probability sampling is a sampling technique in which probability of getting a sample is
calculated.
while accidental sampling does not meet this criterion.
3) FALSE in probabilistic sampling all members have equal chance of selection
4) TRUE it is right that snow ball sampling accumulates subject through chain of accumulation
but they are biased because they give people with higher social connection higher chance of
selection. This is non probabilistic sampling and used in qualitative research generally for those
groups which are hidden . These are not accessible to researchers through other methods..
The rearrangement of alleles by the process of crossing over is call.pdf
The rearrangement of alleles by the process of crossing over is called genetic linkage.
True or False
Solution
The answer is \"False\"
Crossing over is a physical exchange of genetic material between non-sister chromatids of two
homologus chromosomes. Crossing over is a method of exchange of genetic material during
meiosis I following synapsis.
Genetic linage, linked genes sit close together on a chromosome, making them likely to be
inherited together..
Susie has influenza A. She lives in a residence hall where there hav.pdf
Susie has influenza A. She lives in a residence hall where there have been 3 reported cases. She
also works in the recreation facility teaching several group fitness classes. Answer the following
questions about influenza.
1)Identify the cause of influenza and the effects it has on the lungs?
2)What education should be provided to residents, coworkers, and members of the recreation
facility regarding influenza?
3)At this point in the development of Susie’s illness is it safe to assume her roommates and
coworkers have all been exposed to the influenza?
4)Should Susie be allowed to participate in Midwest Fit Fest, a large group fitness instructor
conference this weekend? Why or why not?
5)What precautions can you take within your profession to limit your risk of infection?
6)Why do antibacterial drugs are not directly effective in the treatment of influenza.
Solution
1) The cause of influenza infection is influenza A virus. The virus contains 8 fragments of
segmented RNA. The viral coat contains glycoproteins neuraminidase and haemeagglutinin. The
virus exhibit antigenic drift and shift by changing these surface glycoprotein structures. Influenza
A virus causes flu with symptoms of high fever, chills, running nose, muscle and body pains and
fatigue. The lungs are severly infected due to body immune action against the virus causing
inflammation. Due to this, airways are obstructed and breathing becomes difficult.
2) Influenza is a contact disease and is spread by secretions, nasal droplets in air during sneezing
and coughing and also by unhygenic contact of clothes and surfaces containing secretions. The
coworkers and residents are educated to avoid contact of unhygenic surfaces and clothes. They
need to maintain some distance with the patient and better to wear masks to avoid inhalation of
droplets. The hands must be cleaned with handwash to maintain the hygiene. The floor and
surfaces are cleaned with disinfectants. The room is exposed to sunlight.
3) It is not safe for the coworkers and roommates to get exposed to Susie\'s illness. This is
because, the illness is highly communicable and spread rapidly leading to an endemic.
4) Susie is not allowed to participate in Midwest Fit Fest, a large group fitness instructor
conference during the weekend. This is because, she is a potent carrier of viral organisms and
may spread the disease to several others. So, to avoid spreading of disease she is not allowed to
attend the conference.
5) To avoid the risk of spreading infection precautions are taken. The precautions include the
wearing of mask, keeping covered when sneezing and coughing, keeping the surfaces , clothes
and hands always clean. Keeping the room exposed to sunlight and ventilation.
6) Since, influenza is a viral infection, antibacterial drugs does not show their effect on infection
and require antiviral agents to treat the infection..
Section 5 Controlling Risk Given the following categories or areas .pdf
Section 5: Controlling Risk Given the following categories or areas where risk exists, and then
the 3 assets for each, describe how you will test for associated risk: Administrative Human
resources: Hiring and termination practices Organizational structure: A formal security program
Security policies: Accurate, updated, and known or used Technical Access control: Least
privileged System architecture: Separated network segments System configurations: Default
configurations Physical Heating and air conditioning: Proper cooling and humidity Fire: Fire
suppression Flood: Data center location Once you have described the tests that will be conducted
to test each, assume that failure or holes were found in each of them. Next, describe at least 3
safeguards for each that could be put in place to address the risk.
Solution
Hazard administration is the procedure of distinguishing proof, examination and
acknowledgment or alleviation of instability in speculation choices. Basically, chance
administration happens whenever a speculator or asset chief examines and endeavors to measure
the potential for misfortunes in a venture and after that makes the fitting move (or inaction) given
his venture targets and hazard resistance.
The only sure way to avoid risk in nonprofits would be to lock the doors and put up a closed sign
in the window. Risks are inevitable and organizations have a moral and legal obligation to attend
to the safety and well-being of those they serve, those who work for them and others who come
into contact with their operations. This is known as \"Duty of Care.\"
Organizations need to look at all the risks throughout their entire operation and incorporate risk
management into all planning and decision-making. However, the specific focus of this section is
risk management as it applies to HR activities.
HR Activity Potential Risk Potential considerations
Hiring
While HR began discussing best termination practices three decades ago, much of that
conversation was from the standpoint of protecting the company rather than considering an
employee\'s feelings and future. In 1998, the Five O’Clock Club introduced the concept of
“termination with dignity” after a three-month project re-examining every part of the termination
process with the help of HR leaders and ethicists. “Phrases like termination with kindness or
termination with consideration don’t have the same depth of meaning,” explained Kate
Wendleton, the Five O’Clock Club’s founder. “The word ‘dignity’ carries a special weight; it has
historically been used by the United Nations with regard to human rights, by the Dalai Lama, and
by various religious and philosophical leaders. ‘Dignity’ means that humans should be treated as
persons, rather than objects that you are used to seeing and then throw away.” While other firms
have since copied the Club’s terminology, Wendleton pointed out, what lies behind many of their
programs is far from dignified.
HiringDiscriminatory practicesHiring unsuit.
5)Sonny has the following account balances as of January 1, 2018 bef.pdf
5)Sonny has the following account balances as of January 1, 2018 before an acquisition
transaction takes place.
The fair value of Sonny\' Land and Buildings are $200,000 and $300,000, respectively. On
January 1, 2018, Phillip Company issues 30,000 shares of its $10 par value ($25 fair value)
common stock in exchange for all of the shares of Sonny\' common stock. Phillip paid $10,000
for costs to issue the new shares of stock. Before the acquisition, Phillip has $700,000 in its
common stock account and $300,000 in its additional paid-in capital account.
On January 1, 2018, what value is assigned to Phillip\'s investment account?
A. $150,000.
B. $300,000.
C. $750,000.
D. $760,000.
E. $1,350,000.
6)Acquired in-process research and development is considered as
A. an indefinite-lived asset subject to testing for impairment.
B. a definite-lived asset subject to testing for impairment.
C. an indefinite-lived asset subject to amortization.
D. a definite-lived asset subject to amortization.
E. a research and development expense at the date of acquisition.
7) Sonny has the following account balances as of January 1, 2018 before an acquisition
transaction takes place.
The fair value of Sonny\' Land and Buildings are $200,000 and $300,000, respectively. On
January 1, 2018, Phillip Company issues 30,000 shares of its $10 par value ($25 fair value)
common stock in exchange for all of the shares of Sonny\' common stock. Phillip paid $10,000
for costs to issue the new shares of stock. Before the acquisition, Phillip has $700,000 in its
common stock account and $300,000 in its additional paid-in capital account.
Immediately after the acquisition, what is the consolidated additional paid in capital?
A. $500,000.
B. $740,000.
C. $750,000.
D. $760,000.
E. $940,000.Inventory$100,000Land400,000Buildings (net)500,000Common
stock600,000Additional paid in capital200,000Retained
Earnings200,000Revenues450,000Expenses250,000
Solution
Part 5)
The value assigned to Phillip\'s investment account is determined as below:
Value Assigned to Philip\'s Investment Account = Number of Shares Issued*Fair Value Per
Share
Using the values provided in the question, we get,
Value Assigned to Philip\'s Investment Accounton January 1 2008 = 30,000*25 = $750,000
(which is Option C)
_____
Part 6)
An indefinite-lived asset subject to testing for impairment. (which is Option A)
_____
Explanation:
As per the applicable accounting rules/standards, the value of in-process research and
development is capitalized as an asset for the combined entity. It is treated as an intangible asset
having an indefinite life and is subject to impairment.
_____
Part 7)
The value of consolidated additional paid in capital is arrived as below:
Value of Consolidated Additional Paid in Capital = Current Balance in Phillip\'s Additional Paid-
In Capital Account + Increase in Additional Paid in Capital on the Date of Acquisition
Using the values provided in the question, we get,
Value of Consolidated Additional Paid.
Question In C Programming In mathematics, a set is a colle...Sav.pdf
Question: In C Programming: In mathematics, a set is a colle...
Save
In C Programming:
In mathematics, a set is a collection of distinct elements (say integer numbers). For example,
A={2, 5, 7} and B={3, 5, 8, 10} are two different sets. There are several basic operations for
constructing new sets from given two sets, but let\'s just consider three basic ones:
C = union(A,B); ---> C = A B={2, 5, 7, 8, 10} C = intersection(A,B); ---> C = A B={5}
C = difference(A,B); ---> C = A-B = A \\ B ={2, 7} also aka. complement
You are asked to develop a set library (using two different representations: array and link list)
and then implement a driver program that gets two sets and one of the above operation as a
command to apply, then it prints the resulting set...
Developing set library: For interface, create an interface file set.h which contains boiler plate and
the followings:
typedef int setElementT;
typedef struct setCDT *setADT;
setADT setNew(); /* create a new empty set */
void setFree(setADT S); /* free the space allocated for the set S */
int setInsertElementSorted(setADT S, setElementT E);
/* if not successful, return 0; otherwise, return the num of elements after the insertion. Also note
that the elements might be given in different orders, but your function should always keep the set
in a sorted manner after each insertion */
setADT setUnion(setADT A, setADT B);
/* returns a new set containing A B */
setADT setIntersection(setADT A, setADT B);
/* returns a new set containing A B */
setADT setDifference(setADT A, setADT B);
/* returns a new set containing A \\ B */
int setCardinality(setADT S);
/* return the number of elements in S */
void setPrint(setADT S, char *name);
/* print elements of S, A = {2, 5, 7} */
For implementation, you will be asked to have two different implementations:
(40pt) First implement set library as setArrayImp.c which uses a constant size array to store set
elements (suppose max set size is 100). [hint: see ch2 slides 72-78 ]
(40pt) Second implement this library as setLinkedListImp.c which uses a dynamic single linked
list to store set elements.
Develop a driver.c program and compile it with two different imp of set library (20 pt)
1. Create two sets called A and B.
2. Ask user to enter positive integers for set A (end input when user enters -1)
3. Ask user to enter positive integers for set B (end input when user enters -1)
4. In a loop 4.1. Ask user to enter a command:
4.2 If Q is entered, quit from this loop.
4.3 If U, I, or D is entered, compute set C as union, intersection, or difference. setPrint(A, \"A\");
setPrint(A, \"B\"); setPrint(C, \"C\"); print the number of elements in C setFree(C);
5. free A and B
Compile/execute driver.c with setArrayImp.c as well as setListImp.c
//no include files needed
Solution
Create set.h first with the following
typedef int setElementT;
typedef struct setCDT *setADT;
setADT setNew(); /* Creates a new empty set */
void setFree(setADT S); /* Frees the space allocated for the set .
Q1. What is the primary reason that Fenders blue butterflies are e.pdf
Q1. What is the primary reason that Fender\'s blue butterflies are endangered?
The recent increase in fire frequency and severity has greatly reduced habitat quality.
The butterfly\'s primary host plant, Kincaid\'s lupine, became extinct in the 1930s.
Increases in disease prevalence and predation have diminished their numbers.
Urbanization and agriculture have reduced and fragmented the butterfly\'s preferred habitat.
Solution
Option (d) is correct: Urbanization and agriculture have reduced and fragmented the butterfly\'s
prefered habitat.
Fender\'s blue butterfly is an endangered subspecies of butterfly endemic to the Willamette
Valley of northwestern Oregon, United States. The prime reason for its population decline is that
its native prairie habitat has been largely converted to agriculture, subjected to fire suppression
and invaded by non-native plants. With massive changes in the fire regime, disturbances that
maintained native prairies have been greatly altered, allowing tree and shrub species to invade
and shade out low-growing Kincaid\'s lupine, the species upon which this butterfly depends.
Also,the non-native species such as Himalayan blackberry has aggressively overtaken open
spaces.
Loss of native prairie habitat has resulted in the isolation of butterfly populations. Thus, these
butterfly populations are more vulnerable to natural and human-made disturbances. As the
number of sites have declined and the distance between them has increased and the opportunities
for adult movement between populations are reduced, which were earlier inter-connected. Thus
the Fender\'s blue butterflies populations is isolated, has become endangered and faces a higher
risk of extinction..
Normality assumption is very important. A researcher is interested i.pdf
Normality assumption is very important. A researcher is interested in studying body temperature.
He collected the data below from 10 persons. Could you please as a statistician check the data
follow Normal distribution or not using Normal quantile plot?
96.3 96.7 96.9 97.0 97.1 97.1 97.2 97.4 95.5 97.1
Solution
The normal probability plot is
The points are in the form of a straight line. therefore the given data is normal..
Punnett square Father and mother are heterozygous and each are .pdf
Punnett square: Father and mother are heterozygous and each are carriers for a dominant linked
disorder. What is the % chance the child will be born with the disorder
Punnett square: Father and mother are heterozygous and each are carriers for a dominant linked
disorder. What is the % chance the child will be born with the disorder
Punnett square: Father and mother are heterozygous and each are carriers for a dominant linked
disorder. What is the % chance the child will be born with the disorder
Solution
parents
A
a
A
AA
Aa
a
Aa
aa
Since parents are heterozygotic carriers their phenotype is Aa Aa
The gamets are A a
Progeny 25%AA 50%Aa 25%aa ie 1:2:1
25% chance for having the disease(AA)
parents
A
a
A
AA
Aa
a
Aa
aa.
Property Values Is this rooted tree Leaf vertices Intenal vertices A.pdf
Property Values Is this rooted tree? Leaf vertices Intenal vertices Ancestors of vertice H Decend
ants of vertice D Siblings of vertice G Parent vertice of F Given the following tree, fill out the
table
Solution
yes it is a rooted tree
b)K,L,M ,G,F,I,J are leafs
c)intenal vertices:B,C,D,E,H
D)A
E)M
F)E,F,H,I,J
G)B.
Predict the type of bonding that holds the following atomsmolecules .pdf
Predict the type of bonding that holds the following atoms/molecules together in the following
solid materials. Briefly explain why you have made the prediction for each material. Where
appropriate include calculations. BaO CdS FeO Brass (a copper rich copper-zinc alloy) Solid
neon Polyethylene (a largely linear thermoplastic polymer) AIP
Solution
In Bao , CDs , FeO ionic bonding exist as it is between metal and nom metal ..Ba , Cd , Fe, exists
as cations in +2 state and O as -2 anion.
In Brass metallic bonding exist since only metals are present.
In solid neon vanderwalls force of attraction exists since it is inert gas .
In polyethylene and Aip covalent bond exist . Polyethylene is polymer of ethylene. And AIP
exist as solid plastics..
Please Explain CompletelyWhat is the reason the celiac trunk calle.pdf
Please Explain Completely
What is the reason the celiac trunk called a \"trunk.\" ? is it related to its length?
Solution
celiac trunk is the first major branch of abdominal aorta. it is the largest artery in abdominal
aorta, with its three branhes it supply oxygen to stomach,spleen,eosophagus,deodenum,panreas.
its name trunk is related to its lenght as it is the largest artery in abdominal aorta..
Paraphrase the following passageLong before scientists were able .pdf
Paraphrase the following passage:
Long before scientists were able to record spikes, they were able to stimulate the nervous system
using batteries (Leyden Jars experiment). Since nerves use electricity to communicate, they can
be manipulated with electricity as well. Luigi Galvani, an Italian scientist in the 1700’s,
discovered that electricity applied to the nerves of frog legs caused the large muscles to twitch.
Such discoveries led to debates at the time as to whether “animal electricity” was different from
the electricity during lightning storms. Galvani also tested this by hanging frogs legs off his back
porch during the thunderstorms and watching the legs twitch. Eventually, the scientific
community discovered that while electricity can indeed stimulate nervous system and muscle
tissue, the tissue itself generates electricity. This led to the beginnings of contemporary
neuroscience. In another famous experiment, German Medical Scientist Eduard Hitzig and
Gustav Fritsch in 1870 applied electricity current to the exposed cerebral cortex (wrinkly part of
brain) in dogs in their kitchen, showing that stimulation of different parts of the brain can cause
different types of movements.
Solution
The depolarization and spike production from neurons of nervous system was examined by the
various scientist through various experiments finally unraveled the neurons are going to work
through nerve potential such as electric potential to communicate (Scientist Leyden). This
electric potential have triggered twitching muscle activity via motor neurons & these aspects
were examined by working on large leg muscles of frog (L Galvani 1700) finally deduced that
animal electric potential id differed from electric potential observed during lightening. Therefore
these neuroscience research aspects have meticulously have later examined in exposed cerebral
cortex using electric current onto the “neurons of dogs” finally observed differential muscle
movements (E Hitzig 1870).
Plant diversityConiferophyta and anthrophyta do not haveuse flag.pdf
Plant diversity:
Coniferophyta and anthrophyta do not have/use flagellated sperm like all the other plant phyla.
Explain how their sperm move and fertilization takes place without flagella
Solution
The members of these phyla are wind and animal pollinated. Pollen grain move from stamen to
stigma via the action of wind or through an animal mediator. Pollen moves from staminate cones
reaches the stigma of ovulate cones. Ovulate cones have open scales. Upon arrival of pollen, the
scales close. Then, the pollen moves down towards the megasporangium. Fertilization occurs.
So, fertilization occurs without flagella..
Joe digs a ditch in 3.2 hours. Joe working with George can did the.pdf
Joe digs a ditch in 3.2 hours.
Joe working with George can did the same length ditch in 2.7 hours.
How long would it take George to dig the ditch by himself ?
Solution
Joe digs a ditch in 3.2 hours...so in 1 hour he digs 1/3.2 ditch=10/32=5/16
let george alone take x hrs to dig the ditch...so in 1 hour he digs 1/x ditch
so in 1 hour joe and george together dig 5/16+1/x ditch =(5x+16)/16x
so they take 16x/(5x+16) hrs to dig the ditch together
but this given as 2.7 hours
so 16x/(5x+16)=2.7
cross multiplying we get
16x=2.7(5x+16)=13.5x+43.2
16x-13.5x=43.2
2.5x=43.2
x=43.2/2.5=432/25=17.28 hours
so george alone takes 17.28 hrs to dig the ditch.
In some regions, particular plant foods are emphasized. As a specifi.pdf
In some regions, particular plant foods are emphasized. As a specific example, potatoes are
traditionally a major part of the diet in Ireland, Norway, and Lithuania. What does the ecological
setting have to do with this food-eating custom?
Solution
Ecological environment decides the food eating customs of people in that area. The food taken
by people daily, depends on the type of weather in that area. Places that are colder, people tend
to eat things with warm in metabolism, there. Places that are hot, people eat such food items
there, which can provide them relief from excess heat. Potato is a rich source of carbohydrate
and is warm food that provides heat to the body in its metabolism, so Ireland Norway Luthiania
being colder places, people opt to eat potato to maintain their body temperature.
The same way, In India nothern part is very cold, so people eat lot of dry fruits, rajma, chana,
meat, bajra and wheat in their diet. Such foods provide them warmth. In southern part of India,
there is hot temperature most of the year, so people there eat rice as main food, coconut water,
Vegetable stock like Rasam are included in food. Such foods provides them relief from heat..
In binary star systems we can often measure the sum of the masses of.pdf
In binary star systems we can often measure the sum of the masses of the stars and the ratio of
their masses. If m1+ m2= Mtot, and m1/m2= Y, derive an expression for the mass of each star in
terms of just Mtotand Y.
Solution
=>m1/m2 = Y
m1 =Ym2-------------1
=>m1+m2 =Mtot
Ym2+m2 = Mtot
(Y+1)m2 =Mtot
=>m2=Mtot/(Y+1)
From 1
=>m1= [Y/(Y+1)]Mtot.
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Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
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● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
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Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
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