BIBIN CHIDAMBARANATHAN
STRESS ON AN OBLIQUE
SECTION OF A BODY SUBJECTED
TO DIRECT STRESS IN TWO
MUTUALLY PERPENDICULAR
DIRECTIONS
1 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
BIBIN CHIDAMBARANATHAN
ANALYTICAL
METHOD
2 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
STRESS ON AN OBLIQUE SECTION OF A BODY
SUBJECTED TO DIRECT STRESS IN TWO MUTUALLY
PERPENDICULAR DIRECTIONS
3 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
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6 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
Stress on an oblique section of a body subjected to
direct stress in two mutually perpendicular directions
7 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
Normal stress across the section AB
𝜎𝑛 =
𝜎𝑥 + 𝜎𝑦
2
−
𝜎𝑥 − 𝜎𝑦
2
cos 2𝜃
Shear stress (tangential stress) across the section AB
𝜏 =
𝜎𝑥 − 𝜎𝑦
2
sin 2𝜃
Maximum shear stress
𝜏𝑚𝑎𝑥 =
𝜎𝑥 − 𝜎𝑦
2
Resultant stress
𝜎𝑅 = 𝜎𝑛
2
+ 𝜏2
Direction of Resultant stress
𝜃 = tan−1
(
𝜏
𝜎𝑛
)
8 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
BIBIN CHIDAMBARANATHAN
PROBLEMS
9 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
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14 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
BIBIN CHIDAMBARANATHAN
GRAPHICAL
METHOD
15 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
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18 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
BIBIN CHIDAMBARANATHAN
PROBLEMS
19 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
20 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
21 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
22 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
23 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
BIBIN CHIDAMBARANATHAN
STRESS ON AN OBLIQUE
SECTION OF A BODY SUBJECTED
TO SIMPLE SHEAR STRESS
24 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
BIBIN CHIDAMBARANATHAN
ANALYTICAL
METHOD
25 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
Stress on an oblique section of a body subjected to
simple shear stress
26 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
27 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
28 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
29 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
Stress on an oblique section of a body subjected to
simple shear stress
30 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
Normal stress across the section AB
𝜎𝑛 = 𝜏𝑥𝑦 sin 2𝜃
Shear stress (tangential stress) across the section AB
𝜏 = −𝜏𝑥𝑦 Cos 2𝜃
Resultant stress
𝜎𝑅 = 𝜎𝑛
2
+ 𝜏2
Direction of Resultant stress
𝜃 = tan−1
(
𝜏
𝜎𝑛
)
31 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11
Thank You
32 BIBIN CHIDAMBARANATHAN, ASP/MECH, RMKCET 5/11

Lecture 39 som 11.05.2021