BIBIN CHIDAMBARANATHAN
STRESS ON AN OBLIQUE
SECTION OF A BODY SUBJECTED
TO DIRECT STRESSES IN TWO
MUTUALLY PERPENDICULAR
DIRECTIONS ACCOMPANIED BY
A SIMPLE SHEAR STRESS
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BIBIN CHIDAMBARANATHAN
ANALYTICAL
METHOD
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STRESS ON AN OBLIQUE SECTION OF A BODY
SUBJECTED TO DIRECT STRESSES IN TWO MUTUALLY
PERPENDICULAR DIRECTIONS ACCOMPANIED BY A
SIMPLE SHEAR STRESS
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STRESS ON AN OBLIQUE SECTION OF A BODY
SUBJECTED TO DIRECT STRESSES IN TWO MUTUALLY
PERPENDICULAR DIRECTIONS ACCOMPANIED BY A
SIMPLE SHEAR STRESS
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Normal stress across the section AB
𝜎𝑛 =
𝜎𝑥 + 𝜎𝑦
2
−
𝜎𝑥 − 𝜎𝑦
2
cos 2𝜃 − 𝜏𝑥𝑦 𝑆𝑖𝑛 2𝜃
Shear stress (tangential stress) across the section AB
𝜏 =
𝜎𝑥 − 𝜎𝑦
2
sin 2𝜃 − 𝜏𝑥𝑦 𝐶𝑜𝑠 2𝜃
Maximum shear stress
𝜏𝑚𝑎𝑥 =
𝜎𝑥 − 𝜎𝑦
2
2
+ 𝜏𝑥𝑦
2
Resultant stress
𝜎𝑅 = 𝜎𝑛
2
+ 𝜏2
Direction of Resultant stress
𝜃𝑅 = tan−1
(
𝜏
𝜎𝑛
)
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Maximum principal stress
𝜎𝑝1 =
𝜎𝑥 + 𝜎𝑦
2
+
𝜎𝑥 − 𝜎𝑦
2
2
+ 𝜏𝑥𝑦
2
Minimum principal stress
𝜎𝑝1 =
𝜎𝑥 + 𝜎𝑦
2
−
𝜎𝑥 − 𝜎𝑦
2
2
+ 𝜏𝑥𝑦
2
Direction of Maximum shear stress
𝜃𝑠 =
1
2
tan−1
(
𝜎𝑥 − 𝜎𝑦
2𝜏𝑥𝑦
)
Direction of Maximum principal stress
𝜃𝑝 =
1
2
tan−1
(
2𝜏𝑥𝑦
𝜎𝑥 − 𝜎𝑦
)
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BIBIN CHIDAMBARANATHAN
PROBLEMS
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Thank You
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Lecture 42 som 18.05.2021