Prezentacija "Sebični džin" za 2. razred osnovne škole iz predmeta "Srpski jezik". Učiteljica Đurđica Stojković, Osnovna škola "Jovan Popović" Banoštor.
How to Make Social Media Work for B2B and B2GMailerMailer
There is a lot of buzz about using social media to grow your business. Does it work for B2B or B2G companies? Yes. Forty years ago, researcher Mark Granovetter proposed a theory about social interaction. He suggested that people close to you know about the same opportunities, projects, people, job openings and events that you do. If you expand your reach beyond your closer circles, you tap into your other connections, which expose you to a whole new set of options. You can leverage social media to make this happen.
This presentation will provide actionable tips on using social media to grow your B2B/B2G business.
Join us and you’ll learn:
· Which social media activities result in the most traction and which are a waste of time
· How to position your company as a trusted source
· How to nurture leads that are not "sales-ready”
· What to share with businesses and government agencies so they think of you as they write their RFPs
Prezentacija "Sebični džin" za 2. razred osnovne škole iz predmeta "Srpski jezik". Učiteljica Đurđica Stojković, Osnovna škola "Jovan Popović" Banoštor.
How to Make Social Media Work for B2B and B2GMailerMailer
There is a lot of buzz about using social media to grow your business. Does it work for B2B or B2G companies? Yes. Forty years ago, researcher Mark Granovetter proposed a theory about social interaction. He suggested that people close to you know about the same opportunities, projects, people, job openings and events that you do. If you expand your reach beyond your closer circles, you tap into your other connections, which expose you to a whole new set of options. You can leverage social media to make this happen.
This presentation will provide actionable tips on using social media to grow your B2B/B2G business.
Join us and you’ll learn:
· Which social media activities result in the most traction and which are a waste of time
· How to position your company as a trusted source
· How to nurture leads that are not "sales-ready”
· What to share with businesses and government agencies so they think of you as they write their RFPs
Summertime IT Marketing an Hour a WeekMailerMailer
Learn how to grow your IT business by setting aside one hour per week to focus on marketing. You will find out which activities generate leads effectively even during summertime months when business might be a little slower. At the end of the webinar, you will have an actionable marketing plan to put in place immediately.
Para mi hermoso bebe que ya esta en el cielo con los demás animalitos un homenaje para que sepa que siempre lo recordaremos y que lo amamos muchisisimoo.......
1. 1. Koju bi brzinu postigla kuglica mase 5g i naboja 5μC, ako bi se gibala s mjesta potencijala
30000V na 3000V?
m = 5 g = 5 ⋅ 10 −3 kg
Q = 5µC = 5 ⋅ 10 −6 C
ϕ1 = 30000V
ϕ 2 = 3000V
v=?
m ⋅ v2
Ek =
2
U = ∆ϕ
U = 27000V
W = Ek
W = U ⋅Q
m ⋅ v2
U ⋅Q =
2
2 ⋅U ⋅ Q
v2 =
m
2 ⋅U ⋅ Q
v=
m
v = 3 6ms −1
v ≈ 7.35ms −1
2. 2. Kapacitet kondenzatora je 1.3 pF. Ako udvostručimo razmak među pločama i između njih
stavimo vosak kapacitet će biti 2.6 pF. Kolika je relativna permitivnost voska?
C1 = 1.3 pF
C2 = 2.6 pF
εr = ?
C1 1
=
C2 2
2C1 = C2
2d1 = d 2
S
C = ε0 ⋅ εr ⋅
d
S S
2 ⋅ ε0 ⋅ = ε0 ⋅ εr ⋅
d1 2d1
1
2 = εr ⋅
2
εr = 4
3. 3. Paralelni spoj od 54 žarulja otpora 800Ω priključen je na napon od 220V preko vodiča
otpora 1 Ω. Koliki je napon na svakoj žarulji?
N = 54
Ržarulje = R1 = ... = R54 = 800Ω
Rvodičo = 1Ω
800Ω
Ržarulja = ≈ 14.82Ω
54
Ruk = 14.82Ω + 1Ω = 15.82Ω
U uk = 220V
U uk = I uk ⋅ Ruk
220V
I uk = I žarulja = = 13.9 A
15.82Ω
U žarulje = U žarulja
U žarulja = Ržarulja ⋅ I žarulja
U žarulje ≈ 206V
4. 4. Kolika je snaga električnog uređaja priključenog na 220V, ako se 1L vode ugrije od 20°C
do temperature vrenja za 3.5min.
U = 220V
V = 1L
∆T = 80 K
t = 3.5 min = 210 s
Q =W = ?
ρ = 1kgL−1
m = 1kg
c = 4190 J ( kgK )
−1
Q
c=
m∆T
Q = 335200 J
P=?
W
P= ≈ 1596.19W
t
5. 5. 3 otpornika otpora 20Ω, 40Ω i 60Ω spojena su paralelno. Jakost struje kroz otpornik s
najmanjim otporom je 6A. Izračunaj jakost struje kroz ostale otpornike i ukupnu jakost u
krugu.
R1 = 20Ω
R2 = 40Ω
R3 = 60Ω
I1 = 6 A
I 2,3,uk = ?
U uk
I=
R
U uk = stalan = 120V
I 2 = 3A
I3 = 2A
I uk = I 1 + I 2 + 3 = 11A
