In the Mexican swordtail fish, the wild-type color is olive-green. Ot.pdf
•
0 likes•3 views
In the Mexican swordtail fish, the wild-type color is olive-green. Other color variants include golden and Take caution with ratio there is some reduced viability in this system. Matings involving fish of these three phenotypes are shown below: Explain the inheritance of these color phenotypes in the fish Solution At any rate, the mode of inheritance of albinism in the goldfish has not hitherto been known. Using mates of different varieties of the goldfish, scientists arrived at the conclusion that albinism of the goldfish is not a simple Mendelian character but it is represented by the double homozygote of two non-linked autosomal recessive genes since because the F2 generation shows 15:1 ratio for non-albino and albino types like we see in the case of duplicate genes. example: If the animal was A/a, because a is recessive and A is dominant, the animal\'s phenotype wouldn\'t be albino, but it would still carry the gene for albinism (since it has an \"a\"). Since it carries both \"A\" and \"a\", it is known as \"heterozygous\". If the animal had the A/A combination, its phenotype wouldn\'t be albino, and it wouldn\'t carry the gene for albinism (both genes being the same, it is called \"homozygous\" for \"A\"). If it were homozygous for \"a\" (i.e. a/a), the animal\'s phenotype would be albino. Since \"a\" is recessive, both alleles need to be \"a\" in order for albinism to be expressed in the phenotype. The genes for the pigment cells are inherited independently of one another, and there is no known linkage to any other genes. So, each pigment type is coded by two different genes, one on each of a pair of chromosomes. The phenotype of wild type animals is dark, non-melanoid, non- albino and non-axanthic. The golden colour (D/D a/a or D/d a/a). It has normal migration of pigment cells, but lacks melanophores, hence the yellow/gold appearance..
Report
Share
Report
Share
Download to read offline
Recommended
Multiple alleles.pdf
Multiple alleles
Characteristics of mutiple alleles
Reason of Multiple alleles
Examples of multiple alleles
INHERTANCE PATTEREN IN ANMALS,SEGREGATION ,INDEPENDENT ASSORTMENT,MULTIPLE AL...
MILLER AND HARLEY 5TH EDITION
CHAPTER # 3 "CELL DIVISION AND INHERITANCE"
TOPIC : INHERITANCE PATTERN IN ANIMALS "
Multiple allele of rabbit coat color
it is possible to have more than two allelic forms, i.e., multiple alleles, of one kind of gene.
The best examples of multiple allelic system have been observed in coat colour of rabbits, wings of Drosophila and blood groups in man
allelomorphs, monohybrid cross dihybrid cross mutant alleles
wild type
4. Gene interaction - Epistasis - Dominant & Recessive, Non-epistatsis
Basics of Undergraduate/university fellows
Epistasis is a Greek word that means standing over.
BATESON used term epistasis to describe the masking effect in 1909
The term epistasis describes a certain relationship between genes, where an allele of
one gene hides or masks the visible output or phenotype of another gene.
When two different genes which are not alleles, both affect the same character in such
a way that the expression of one masks (inhibits or suppresses) the expression of the
other gene, the phenomenon is said to be epistasis.
The gene that suppresses other gene expression is known as Epistatic gene.
The gene that is suppressed or remain obscure is called Hypostatic gene
The classical phenotypic ratio of 9:3:3:1 F2 ratio becomes modified by epistasis.
Recommended
Multiple alleles.pdf
Multiple alleles
Characteristics of mutiple alleles
Reason of Multiple alleles
Examples of multiple alleles
INHERTANCE PATTEREN IN ANMALS,SEGREGATION ,INDEPENDENT ASSORTMENT,MULTIPLE AL...
MILLER AND HARLEY 5TH EDITION
CHAPTER # 3 "CELL DIVISION AND INHERITANCE"
TOPIC : INHERITANCE PATTERN IN ANIMALS "
Multiple allele of rabbit coat color
it is possible to have more than two allelic forms, i.e., multiple alleles, of one kind of gene.
The best examples of multiple allelic system have been observed in coat colour of rabbits, wings of Drosophila and blood groups in man
allelomorphs, monohybrid cross dihybrid cross mutant alleles
wild type
4. Gene interaction - Epistasis - Dominant & Recessive, Non-epistatsis
Basics of Undergraduate/university fellows
Epistasis is a Greek word that means standing over.
BATESON used term epistasis to describe the masking effect in 1909
The term epistasis describes a certain relationship between genes, where an allele of
one gene hides or masks the visible output or phenotype of another gene.
When two different genes which are not alleles, both affect the same character in such
a way that the expression of one masks (inhibits or suppresses) the expression of the
other gene, the phenomenon is said to be epistasis.
The gene that suppresses other gene expression is known as Epistatic gene.
The gene that is suppressed or remain obscure is called Hypostatic gene
The classical phenotypic ratio of 9:3:3:1 F2 ratio becomes modified by epistasis.
Codominance
Examples of Codominance. The best example, in this case, is the codominance blood type. ABO group is considered to be a codominant blood group where both father’s and mother’s blood group is expressed. It means that the properties of the blood groups exist in the ABO type.
Codominance is a relationship between two versions of a gene. Individuals receive one version of a gene, called an allele, from each parent. If the alleles are different, the dominant allele usually will be expressed, while the effect of the other allele, called recessive, is masked.
Multiple Alleles
Features of multiple alleles. The same genes have more than two alleles. All multiple alleles in homologous chromosomes occupy the respective loci. A chromosome or gamete only has one group allele. Each human contains only two separate gene alleles, one for each homologous pair of chromosomes carrying the gene.
More than two alternative alleles of a gene are known as multiple alleles in a population occupying the same locus on a chromosome or its homologue. ... Multiple alleles express various alternatives of one trait. Different alleles can exhibit codominance, dominance-recessive behaviour or incomplete dominance.
In 1905, the French biologist Lucien Cuénot discovered an interestin.pdf
In 1905, the French biologist Lucien Cuénot discovered an interesting mutant mouse displaying a
yellow coat color. He bred the mouse and its progeny for several generations but could never
obtain a pure breeding stock of yellow mice! Normal mice have a coat color called Agouti which
appears gray. When he crossed pure breeding gray Agouti mice with the yellow mouse, half the
progeny had the gray Agouti coat and half had the light yellow coat. When he crossed the F1
yellow mice with each other, he found that 1/3 of the F2 progeny had the gray Agouti coat and
2/3 had the yellow coat. When he crossed the F2 yellow progeny with pure breeding Agouti
mice, he found again that they produced 50% gray Agouti mice and 50% yellow mice.
Based on these results, you would conclude that relative to the Agouti coat color, the Yellow
coat color is:
A. Completely Dominant
B. Incompletely Dominant
C. Co-dominant
D. Incompletely Penetrant
E. Recessive
Cuénot was never able to produce a pure breeding strain of yellow mice even after trying several
crosses for several years. Provide a one-sentence explanation for why Cuénot was unable to
obtain yellow mice but not a pure breeding stock of yellow mice.
Solution
(A) It is complete dominant. As per definition, dominant allele shows phenotype in homozygous.
Genes are located on chromosomes and consist of DNA. They are passed from parents to their
offspring through reproduction. Genes also contain information about a specific characteristic or
trait and can either be dominant or recessive. Each gene has a designated place on every
chromosome, called a locus. All copies of a gene are not identical and alternative forms of a gene
is called alleles that lead to the alternative or different form of one trait. Alleles are helpful in
identification of the two members of a gene pair, which produce opposite contrasting
phenotypes, e.g., b is an allele of B and vice versa. When the two alleles of a gene are identical,
the individual is homozygous for that trail, and on the other hand, if there are two different
alleles, the individual is heterozygous. A homozygous pair can be either dominant (AA, BB) or
recessive (aa, bb). Heterozygous pairs are made up of one dominant and one recessive allele (Aa,
Bb). In heterozygous individuals, only one allele, the dominant one, is able to express itself,
while the other allele, the recessive, is hidden but still present. The dominant genes are denoted
by upper case letters and recessive genes are denoted by lower case letters. The word genotype
was created to identify genes of an individual and phenotype for the external appearance of the
trait and genes.Phenotype and genotype are terms used to describe the difference between the
visible expressions of the trait versus the actual gene makeup. An individual, which expresses a
dominant trait may carry a recessive allele, but the recessive expression is hidden by its dominant
partner. Mendel\'s observations from these experiments can be summar.
Year 10 science genetics
Year 10 science genetic lesson. Cover Punnett squares, Alleles, recessive, phenotypes, genotypes, homozygous, heterozygous and basic blood types
Multiple alleles and blood group in man.pptx
Blood groups in human is controlled by more than two alleles. The mechanism of multiple allele is better explained using blood group.
Interaction of genes for slide share
This power point presentation is designed to explain deviation of Mendelian dihybrid ratio due to interaction of genes which may be of following types
1.Two gene pairs affecting same character – 9:3:3:1
2.Epistasis, one gene hides effect of other
a) Recessive Epistasis - 9:3:4
b) Dominant epistasis - 12:3:1
3.Complementary genes - 9:7 ( 2 genes responsible for production of a particular phenotype )
4. Duplicate genes – 15:1 ( same effect given by either of two genes )
5. Polymeric gene action - 9:6:1
6. Inhibitory gene action - 13 : 3
Each interaction is typical in itself and ratios obtained are different
What two kinds of secondary bonds hold polymer chains together Which.pdf
What two kinds of secondary bonds hold polymer chains together? Which is stronger?
Solution
there are three kinds of secondary forces in polymers
1. Polar
2. Hydrogen Bond
3. Non Polar
Out of these three polar bond is more strong because these bond are formed between a
electronegative atom such as oxygen, fluorine and positive atoms like hydrogen and carbon. This
bond has characteristics of Ionic bond and hence it is stronger..
When hiking up most Stratovolcanoes, which rock composition(s) will .pdf
When hiking up most Stratovolcanoes, which rock composition(s) will you see from its base to
its summit? a. Mafic at the bottom, intermediate in the middle, and felsic at the top b. Felsic at
the bottom, intermediate in the middle, and mafic at the top c. Intermediate from bottom to top d.
Felsic from bottom to top
Solution
option (a) is correct
A . Mafic at the bottom ,
intermediate in the middle ,
and felsic at the top ..
More Related Content
Similar to In the Mexican swordtail fish, the wild-type color is olive-green. Ot.pdf
Codominance
Examples of Codominance. The best example, in this case, is the codominance blood type. ABO group is considered to be a codominant blood group where both father’s and mother’s blood group is expressed. It means that the properties of the blood groups exist in the ABO type.
Codominance is a relationship between two versions of a gene. Individuals receive one version of a gene, called an allele, from each parent. If the alleles are different, the dominant allele usually will be expressed, while the effect of the other allele, called recessive, is masked.
Multiple Alleles
Features of multiple alleles. The same genes have more than two alleles. All multiple alleles in homologous chromosomes occupy the respective loci. A chromosome or gamete only has one group allele. Each human contains only two separate gene alleles, one for each homologous pair of chromosomes carrying the gene.
More than two alternative alleles of a gene are known as multiple alleles in a population occupying the same locus on a chromosome or its homologue. ... Multiple alleles express various alternatives of one trait. Different alleles can exhibit codominance, dominance-recessive behaviour or incomplete dominance.
In 1905, the French biologist Lucien Cuénot discovered an interestin.pdf
In 1905, the French biologist Lucien Cuénot discovered an interesting mutant mouse displaying a
yellow coat color. He bred the mouse and its progeny for several generations but could never
obtain a pure breeding stock of yellow mice! Normal mice have a coat color called Agouti which
appears gray. When he crossed pure breeding gray Agouti mice with the yellow mouse, half the
progeny had the gray Agouti coat and half had the light yellow coat. When he crossed the F1
yellow mice with each other, he found that 1/3 of the F2 progeny had the gray Agouti coat and
2/3 had the yellow coat. When he crossed the F2 yellow progeny with pure breeding Agouti
mice, he found again that they produced 50% gray Agouti mice and 50% yellow mice.
Based on these results, you would conclude that relative to the Agouti coat color, the Yellow
coat color is:
A. Completely Dominant
B. Incompletely Dominant
C. Co-dominant
D. Incompletely Penetrant
E. Recessive
Cuénot was never able to produce a pure breeding strain of yellow mice even after trying several
crosses for several years. Provide a one-sentence explanation for why Cuénot was unable to
obtain yellow mice but not a pure breeding stock of yellow mice.
Solution
(A) It is complete dominant. As per definition, dominant allele shows phenotype in homozygous.
Genes are located on chromosomes and consist of DNA. They are passed from parents to their
offspring through reproduction. Genes also contain information about a specific characteristic or
trait and can either be dominant or recessive. Each gene has a designated place on every
chromosome, called a locus. All copies of a gene are not identical and alternative forms of a gene
is called alleles that lead to the alternative or different form of one trait. Alleles are helpful in
identification of the two members of a gene pair, which produce opposite contrasting
phenotypes, e.g., b is an allele of B and vice versa. When the two alleles of a gene are identical,
the individual is homozygous for that trail, and on the other hand, if there are two different
alleles, the individual is heterozygous. A homozygous pair can be either dominant (AA, BB) or
recessive (aa, bb). Heterozygous pairs are made up of one dominant and one recessive allele (Aa,
Bb). In heterozygous individuals, only one allele, the dominant one, is able to express itself,
while the other allele, the recessive, is hidden but still present. The dominant genes are denoted
by upper case letters and recessive genes are denoted by lower case letters. The word genotype
was created to identify genes of an individual and phenotype for the external appearance of the
trait and genes.Phenotype and genotype are terms used to describe the difference between the
visible expressions of the trait versus the actual gene makeup. An individual, which expresses a
dominant trait may carry a recessive allele, but the recessive expression is hidden by its dominant
partner. Mendel\'s observations from these experiments can be summar.
Year 10 science genetics
Year 10 science genetic lesson. Cover Punnett squares, Alleles, recessive, phenotypes, genotypes, homozygous, heterozygous and basic blood types
Multiple alleles and blood group in man.pptx
Blood groups in human is controlled by more than two alleles. The mechanism of multiple allele is better explained using blood group.
Interaction of genes for slide share
This power point presentation is designed to explain deviation of Mendelian dihybrid ratio due to interaction of genes which may be of following types
1.Two gene pairs affecting same character – 9:3:3:1
2.Epistasis, one gene hides effect of other
a) Recessive Epistasis - 9:3:4
b) Dominant epistasis - 12:3:1
3.Complementary genes - 9:7 ( 2 genes responsible for production of a particular phenotype )
4. Duplicate genes – 15:1 ( same effect given by either of two genes )
5. Polymeric gene action - 9:6:1
6. Inhibitory gene action - 13 : 3
Each interaction is typical in itself and ratios obtained are different
Similar to In the Mexican swordtail fish, the wild-type color is olive-green. Ot.pdf (20)
In 1905, the French biologist Lucien Cuénot discovered an interestin.pdf
In 1905, the French biologist Lucien Cuénot discovered an interestin.pdf
More from suhshbhosale
What two kinds of secondary bonds hold polymer chains together Which.pdf
What two kinds of secondary bonds hold polymer chains together? Which is stronger?
Solution
there are three kinds of secondary forces in polymers
1. Polar
2. Hydrogen Bond
3. Non Polar
Out of these three polar bond is more strong because these bond are formed between a
electronegative atom such as oxygen, fluorine and positive atoms like hydrogen and carbon. This
bond has characteristics of Ionic bond and hence it is stronger..
When hiking up most Stratovolcanoes, which rock composition(s) will .pdf
When hiking up most Stratovolcanoes, which rock composition(s) will you see from its base to
its summit? a. Mafic at the bottom, intermediate in the middle, and felsic at the top b. Felsic at
the bottom, intermediate in the middle, and mafic at the top c. Intermediate from bottom to top d.
Felsic from bottom to top
Solution
option (a) is correct
A . Mafic at the bottom ,
intermediate in the middle ,
and felsic at the top ..
What image of society is held by the three major theoretical approac.pdf
What image of society is held by the three major theoretical approaches? What core questions
does each approach ask? Which of the three approaches strikes you as the most useful? Why?
Solution
The three major theoretical approaches:-
1) Symbolic interactionism
2) Conflict Theory
3) Functionalism
Explanation:-
1) Symbolic interactionism:- emphasises on the language and symbols that help us to give
meaning to the experiences in our life. It is basically slices of society. It is distinctive approach to
the study of human life and human conduct.
2) Conflict Theory:- This theory argues that individuals and groups i.e., social classes within
society have different amounts of material and non-material resources (such as the wealthy vs.
the poor) and that the more powerful groups use their dominance and power in order to exploit
groups with less power.
3) Functionalism:-This theory focuses how everyone take a part in society, how is the behaviour
of the people in the society. It shows the social ethics of an individual. It distinguishes between
good and bad..
What are the major evolutionary trends that developedamong major v.pdf
What are the major evolutionary trends that developed
among major vertebrate groups, specifically those that
allowed for the transition from aquatic to terrestrial life?
Solution
Major evolutionary trends, specifically those that allowed for the transition from aquatic to
terrestrial life. These trends are developed respiration, protective and insulating body covering.
From transition from aquatic to terrestrial life changing to efficient reproductive methods like
placenta for some animals and also morphology of organism evolved such that for land they
would have paired , muscular appendages used for crawling and walking.
True or falsea. List index values must be integers.b. Lists can.pdf
True or false?
a. List index values must be integers.
b. Lists can change their size, getting larger or smaller.
c. A function cannot return a list.
d. All elements of a list are of the same type.
e. Lists cannot contain strings as elements.
f. A function cannot change the length of a list argument.
Solution
Below are True statements
a. List index values must be integers.
b. Lists can change their size, getting larger or smaller.
f. A function cannot change the length of a list argument.
Below are False statements
A function cannot return a list.
All elements of a list are of the same type.
e. Lists cannot contain strings as elements..
True false correction questions and fill in the blank. Same rules app.pdf
True false correction questions and fill in the blank. Same rules apply as to question 1 on the
true false part. Correct errors in the first part of the sentence (prior to the semicolon) Klebsiella
pneumonia causes COPD and urinary tract infections; the gram + organism also causes urinary
tract infections and can be part of the flora in this part of the body (give part of body).
Solution
true
Klebsiella pneumoniae causes chronic obstructive pulmonary disorder and urinary tract
infections.
the gram positive organism Lactobacillus delbrueckii also causes urinary tract infections and can
be part of flora in Vvagina of female body.
Show that all the singular points of the following functions are pol.pdf
Show that all the singular points of the following functions are poles. Determine the order of
each pole and the corresponding residue.
z + 1/z2 ? 2z
tanh z
z/cos z
Find the residue at z = 0 for the following functions:
csc2 z z-3
csc(z22)
zcos(1/z)
Solution
the pole i found was z = ?/2 + 2n? and -?/2 +2n? i attempted to find the residues using limits.
limz??/2 + 2n? (z-(?/2 + 2n?)) z/cosz doing some annoying algebra and just evaluating at ?/2 +
2n? i get 0/0. so i can use L\'hopitals rule, right? doing so i get my limit to equal ?/2 + 6n?.
The article at those photos groups 20 amino acids into 6 groups acco.pdf
The article at those photos groups 20 amino acids into 6 groups according to 8 amino acid
properties (size, partial volume, hydrophobicity, etc.). Perform the PCA analysis and show the
2D plot of 20 AAs according to the largest two principal components. the original strands and
one newly synthesized n RNA replication merely lead to mistakes in a sin strand that is
complementary t it. Clearly, both gle short-lived mRNA. Hence accurate DNA replica strands of
DNA contain the ful nformation n tion is very important. sary to recreate the other strand. The
key processes called this section \"closing the loop\" because of DNA replication occur at a
replication fork (Fi in the order that we presented things here, DNA 2.7(d)). At this point, the
two old strands are separ- replication is the last link in the cycle of mechan ated from one another
and the new strands are syn sms for synthesis of the major biological macro- thesized. The main
enzyme that does this job is DNA molecules. There is, however, a more fund lymerase III. This
enzyme catalyzesthe addition of sense in which this whole process is a loop. Clearly nucleotides
to the 3\'ends of the growing strands (at proteins cannot be synthesized without DN the heads of
the arrows in Fig 2.7(d)). The new cause proteins do not store genetic information DNA can
store this information, but it cannot carry strand is therefore synthesized in the 5\' to 3\' direc-
tion (as with mRNA synthesis during transcription) out the catalytic roles necessary for
metabolism in On one strand, called the leading strand, synthesis and it cann ot replicate itself
without the aid a cel is possible in a continuous unbroken fashion. How of proteins. There is thus
a chicken and egg situ ever, on the lagging strand on the opposite side, con ation: \"Which came
first, DNA or proteins Many tinuous synthesis is not possible and it is necessary peopl e now
believe that RNA preceded both DNA to initiate synthesis independently many times The and
proteins, and that there was a period in the new strand is therefore formed in pieces, which are
Earth\'s history when RNA played both the genetic known as Okazaki fragments and catalytic
roles. This is a tempting hypothesis DNA polymerase III is able to carry out theaddition because
several types of catalytic RNA are known of new nucleotides to a strand but it cannot initiate a
(both naturally occurring and artificially synthes- new strand. This is in contrast to RNA
polymerase ized sequences and because many viruses use which is able to perform both initiation
and addition RNA as their genetic materialtoday As with all con DNA polymerase therefore
needs a short sequence jectures related to the origin of life and very early called a primer, from
which to begin. Prime evolution, however, it is difficult to prove that an short sequences of RNA
ndicated by dotted lines in RNA world once existed. Fig. 2.7(d) that are synthesized by a form of
RNA polymerase called primase The processes of DNA s.
Studying Viruses can be important because they are often disease .pdf
Studying Viruses can be important because they are often disease causing pathogens. Howeve,
because of how easy they are to control and mainpulate in the laboratory, viruses can be good
tools to study basic, fundamental principles of cell and molecular biology. Concisely explain one
example of how viruses were used to make a critical molecular genetics discovery (briefly, how
was the experiment done, and what was concluded?)
Studying Viruses can be important because they are often disease causing pathogens. Howeve,
because of how easy they are to control and mainpulate in the laboratory, viruses can be good
tools to study basic, fundamental principles of cell and molecular biology. Concisely explain one
example of how viruses were used to make a critical molecular genetics discovery (briefly, how
was the experiment done, and what was concluded?)
Solution
Viruses are intracellular parasites that are effective after infecting particular host cells. Viral
infection starts offevolved when proteins on the surface of a virion bind to particular receptor
proteins at the host cells. The specificity of this interaction determines the host range of an
endemic.
Aside from being the causative agents of many sicknesses, viruses are vital gear in cellular
biology research, mainly in research on macromolecular synthesis.
Individual viral particles (virions) usually incorporate both an RNA or a DNA genome,
surrounded via multiple copies of 1 or a small variety of coat proteins, forming the nucleocapsid.
The nucleocapsid of many animal viruses is surrounded with the aid of a phospholipid bilayer, or
envelope.
During lytic replication, host-cell ribosomes and enzymes are used to explicit viral proteins,
which then viral genome and package it into viral coats. The multiple progeny virions produced
within a single infected cellular eventually are launched, following cellular lysis or gradual
disintegration of the cell . Progeny nucleocapsids of enveloped viruses are launched by using
budding of the host-cell membrane in which viral membrane proteins have been deposited.
Some bacterial viruses (bacteriophages) might also go through lysogeny following infection of
host cells. In this situation, the viral genome is incorporated into host-cell chromosomes, forming
a prophage this is replicated along with the host genome. When suitably activated, a prophage
enters the lytic cycle.
All retroviruses and some different animal viruses can combine their genomes into host-cell
chromosomes . In a few instances, this leads to abnormal cell replication and the eventual
improvement of cancers.
Recombinant viruses can be used as vectors to transduce genes into cells. In this method, viral
genes required for the lytic cycle are changed with the aid of other genes. The use of viral
vectors for gene remedy continues to be in its infancy, but has super ability for treatment of
diverse diseases..
State true or false with reason (all from Complex Analysis)-(a) P.pdf
State true or false with reason (all from Complex Analysis):-
(a) Power series has an antiderivative everywhere inside its disc of convergence
(c) There does not exist any analytic function f defined on C\\ {0} such that f \' (z) = 1/z
(d) If a mobius transformation T carries z1 and z2 into a same number w1 then either z1 = z2 or
else T is a constant map
Solution
(a) Power series has an antiderivative everywhere inside its disc of convergence. (TRUE).
send edited codeMain 2public class Main2 { public static voi.pdf
send edited code
Main 2
public class Main2 {
public static void main(String[] args) {
EZ.initialize(512, 512);
EZ.addImage(\"metropolis.jpg\", 256, 256);
Hero myHero = new Hero(100,390);
//HeroPlus mySecondHero = new HeroPlus(100,390);
while(true){
myHero.processStates();
//mySecondHero.processStates();
EZ.refreshScreen();
}
}
}
Hero Plus
public class HeroPlus {
EZImage heroStand;
EZImage heroJump;
EZImage heroLand;
EZImage heroHover;
EZImage heroPunch; // PUNCH
int posx = 0;
int posy = 0;
int heroState = STAND;
static final int STAND = 1;
static final int JUMP = 2;
static final int LAND = 3;
static final int HOVER = 4;
static final int PUNCH = 5;
static final int JUMPHEIGHT = 100;
static final int PUNCHDISTANCE = 50; // PUNCH
int punchCounter = 0; // PUNCH
int jumpCounter = 0;
HeroPlus(int x, int y) {
posx = x;
posy = y;
heroStand = EZ.addImage(\"superstand.png\", posx, posy);
heroLand = EZ.addImage(\"superland.png\", posx, posy);
heroJump = EZ.addImage(\"superjump.png\", posx, posy);
heroHover = EZ.addImage(\"superhover.png\", posx, posy);
heroPunch = EZ.addImage(\"superpunch.png\", posx, posy); // PUNCH
hideHero();
heroStand.show();
}
void hideHero() {
heroStand.hide();
heroLand.hide();
heroJump.hide();
heroHover.hide();
heroPunch.hide(); // PUNCH
}
void positionHero(int x, int y) {
heroStand.translateTo(x, y);
heroJump.translateTo(x, y);
heroLand.translateTo(x, y);
heroHover.translateTo(x, y);
heroPunch.translateTo(x, y); // PUNCH
}
void processStates() {
switch (heroState) {
case STAND:
if (EZInteraction.wasKeyPressed(\'j\')) {
heroState = JUMP;
jumpCounter = 0;
hideHero();
heroJump.show();
}
break;
case JUMP:
jumpCounter++;
if (EZInteraction.wasKeyPressed(\'p\')) {
punchCounter = 0;
hideHero();
heroPunch.show();
heroState = PUNCH;
}
if (jumpCounter > JUMPHEIGHT) {
heroState = LAND;
hideHero();
heroLand.show();
} else {
posy -= 2;
positionHero(posx, posy);
if (EZInteraction.wasKeyPressed(\'h\')) {
heroState = HOVER;
hideHero();
heroHover.show();
}
}
break;
case PUNCH: // PUNCH
punchCounter++;
posx += 2;
positionHero(posx, posy);
if (punchCounter > PUNCHDISTANCE) {
heroState = LAND;
hideHero();
heroLand.show();
}
break;
case LAND:
jumpCounter--;
if (jumpCounter <= 0) {
heroState = STAND;
hideHero();
heroStand.show();
} else {
posy += 2;
positionHero(posx, posy);
if (EZInteraction.wasKeyPressed(\'h\')) {
heroState = HOVER;
hideHero();
heroHover.show();
}
}
break;
case HOVER:
if (EZInteraction.wasKeyPressed(\'l\')) {
heroState = LAND;
hideHero();
heroLand.show();
}
break;
}
}
}
Solution
public class Main2 {
public static void main(String[] args) {
EZ.initialize(512, 512);
EZ.addImage(\"metropolis.jpg\", 256, 256);
// Hero myHero = new Hero(100,390);
HeroPlus mySecondHero = new HeroPlus(100,390);
while(true){
//myHero.processStates();
mySecondHero.processStates();
EZ.refreshScreen();
}
}
}
class HeroPlus {
EZImage heroStand;
EZImage heroJump;
EZImage heroLand;
EZImage heroHover;
EZImage heroPunch; // PUNCH
int posx = 0;
int posy = 0;
int her.
Question 16What is a common tactic hackers use to allow themselves.pdf
Question 16
What is a common tactic hackers use to allow themselves re-access to a system?
Keystroke capture
Trap door
Backdoor
Rootkit
2.5 points
Question 17
What types of viruses propagate through the Internet with no user intervention?
Virus hoaxes
Stealth viruses
Worms
Trojan Horses
2.5 points
Question 18
A Web merchant wants to ensure that people cannot deny that they entered into a transaction, so
they starting using digital signatures and encryption as part of their transaction processing. This
is an example of what?
Integrity
Confidentiality
Authenticity
Non-repudiation
2.5 points
Question 19
What is the main solution used to prevent unauthorized access to systems, data, and applications?
Passwords
User profiles
Biometrics
Firewalls
2.5 points
Question 20
Which of the following refers to security solutions that protect access to systems, applications, or
data by ensuring users or systems are authenticated and allowed to have such access?
Physical access controls
User Profiles
Logical access controls
System access controlsA.
Keystroke captureB.
Trap doorC.
BackdoorD.
Rootkit
Solution
16. (D) Rootkit
17. (C) Worms
18. (D) Non-repudiation
19. (D) Firewalls
20. (D) System access controls.
Qualified plan documents can be written to accommodate plan forfeitu.pdf
Qualified plan documents can be written to accommodate plan forfeitures in different ways.
Which of the following statements is correct?
A. Stock bonus plans always allocate plan forfeitures to participants’ accounts since it is a stock
plan.
B. Safe harbor 401(k) plans never allocate plan forfeitures of matching contributions to
participants’ accounts.
C. Defined benefit plans (but not cash balance plans) have two options to deal with forfeitures.
D. Employers can use the forfeited funds to pay other expenses of the business outside the
qualified plan.
Solution.
Proteins fold. How WhySolutionANSProtein folding Protein.pdf
Proteins fold. How? Why?
Solution
ANS:
Protein folding: Proteins are the molecules in the body which carries out many important
functions, such as enzymes and antibodies.
Before proteins carry out their function, they must first assemble themselves or fold.
PROTEIN FOLDING MODELS:
1. Frame work model:
In this the protein local elements which are stretches of amino acids liked by one another by
covalently with peptide bonds. The region of the primary amino acids sequence in peptide bonds
make different domains.in this domains some of regions are made with Alfa - helix and some are
beta sheet domains.
These primary elements form secondary structure independently of tertiary structure (kim and
baldwin).these elements can diffuse until they collided, successfully adhering and coalescing to
give the tertiary structure (diffus-collision model), (karplus and weaven).
2. The classic nucleation model:
It postulates that some neighboring residues in the sequence would form native secondary
structure that would act as a nucleus form which the native structure would propagate in a step
wise manner. Thus the tertiary structure would form as necessary consequence of the secondary
structure (wetlaufer).
3. Hydrophobic collapse model:
It is hypothesized that a protein would collapse rapidly around its hydrophobic side chain and
then arrange from restricted conformational space occupied by the intermediate. Here the
secondary structure would be directed by native like tertiary structure (ptitsyn & kwajima).
Leviathal’s paradox:
It is formulated by Cyrus Leviathal. It explains, there are vast too many different possible
conformations for a protein to fold by a random search.
Structural organization of protein:
1. Primary Structure: the sequence of amino acids along with the di sulphide bonds.
2. SECONDARY STRUCTURE:
Alfa Helices and Beta- Pleated sheets are most frequently occur in secondary structure in
polypeptides. Both of these can case local folding of protein.
The Alfa Helices in polypeptide made up of L- Alfa amino acids are right handed, the Alfa -
Helices is stabilized by hydrogen bonds formed between oxygen and amide hydrogen’s of
peptide bonds that are a part of linear sequence.
Beta- Pleated sheets: 2 types
A. Parallel: in this the adjacent hydrogen bonding segments are connected by cross over
connection [Right handed].
B. Anti-Parallel: In this the adjacent hydrogen bonding segments are connected by HAIRPIN
turns or reverse turn [Left Handed].
3. Tertiary structure: It is arisen because of the folding of poly peptides upon itself.
4. Quaternary structure:
Some proteins are made up of 2 or more polypeptides chains, the interaction between different
poly peptide are subunits gives rise to the quaternary structure..
PLN 360560 Environmental Impact Assessment Homework No. 4 1. An appl.pdf
PLN 360/560 Environmental Impact Assessment Homework No. 4 1. An applicant has applied
to the U.S. Army Corps of Engineers (USACE) for a Clean Water Act (CWA) Section 404
Permit to construct a marina at the mouth of Chaotic Creek on Bagel Bay on Lake Promise, a
Water of the United States and Class \"B\" surface water in New York State. This site is located
in the upper reach of a large commercial harbor used for deep-draft navigation. The project
entails (1) construction of a breakwall; (2) dredging (and future maintenance dredging) of
navigation entrance and creek channels; (3) installation of 50 docks with boat slips; and (4)
construction of a boat launching ramp. During construction, it is estimated that a total of 60,000
cubic yards of material will be dredged and need to be managed, and about 2,500 cubic yards of
fill will need to be placed in Lake Promise. Management alternatives for the dredged material
include placement at an upland permitted municipal landfill, or discharge at a designated open-
water site in the harbor. The site is an abandoned \"hole\" and since discharge of the dredged
sediment is conceived to have benefits through reducing DDE bioaccumulation through capping
and restoration of shallow water aquatic habitat, it is referred to as a habitat restoration site
(HRS). The applicant had a consultant sample the sediments to be dredged for the marina as well
as a lake reference area and HRS, and had the samples analyzed by a laboratory. The following
is a summary of the test results that are to be submitted with the application: Contaminant
Concentration in sediment sample of Concentration in Concentration in reference bulk HRS bulk
marina sediment to be sediment sample sediment sample dredged Bulk Standard sediment
elutriate (mg/kg)(mg/L) (mg/kg) (mg/kg) 13 0.02 Barium Cyanide Iron Mercury Dieldrin p.p\'-
DDE Chlorobenzene 16 65 0.70 13,000 120 14 53 0.40 12,500 130 0.60 11,000 100 0.02 3x10-7
8x10 1.3x10 0.32 0.008 0.0034 0.12 1.3 38,000 Total organic 21,000 10,300 carbon (TOC) a.
What type of CWA regulatory approvals (i.e., permits, etc.) would be required for this project?
(2 pts.)
Solution
Approvals required for this project -
Storm Water permit - Clean Water Act (CWA) permit coverage for discharge of storm water
runoff from the construction site which are issued throught the US Environmental protection
agency\'s NPDES (national pollutant discharge elimination system) or the state NPDES authority
Permit under section 404 of the CWA issued by US Army Crops for Engineers
Resource Conservation and Recovery Act (RCRA) permit for generators of hazardous wastes
(The RCRA regulations list quantities of hazardous wastes that determine whether a generator is
large or small.), Storage of hazardous wastes (The RCRA regulations specify the time hazardous
wastes can be stored at a site. If the storage time is exceeded, a RCRA permit is required) and
Transport, treatment, and disposal of hazardous wastes (a transporter should be a .
one of the main design goals for the java programming language is se.pdf
one of the main design goals for the java programming language is security. Explain, in detail
how java achieves this goal?
Solution
1.Security became an essential piece of a java language from the starting day itself.Additionally
it is an progressing design aim of the java community .An intrinsic security is observed ,hence
the java language is in much now-a-days which is the major cause.
2.Every action is possible through Java virtual machine(JVM) .it is mainly to establish the
attributes like trust,integrity,confidentiality..etc.
3.Java offers large compile perusal ,leads with secondary stage of examining .language attributes
motivates the programmers closely to good programming recurents. especially the memory
management representation is uncomplicated.it removes the total classes of programing mistakes
which causes a continous trouble to the C and C++ programmers.moreover the objects are
fabricated with a new operator.precised programmer defined pointer data types, pointer
arthematic and self-activated garbage collector is absent.
4.java language is manipulated in distributed domains that tells that the security is most
important including the security attributes which is intended in the java language and run time
system.
5.In case of network habitats ,the applications in java language are secured from interruption
with an unofficial code venturing to acheive alrady the scenes and occupy file systems..
Meyer and colleagues performed three rounds of X-ray crystallography.pdf
Meyer and colleagues performed three rounds of X-ray crystallography, each with a different
elastase crystal. For each experiment, they positioned the elastase crystal at a different angle.
Why might researchers have rotated elastase crystals to position them at different angles?
Select one:
a. Similar to when you get X-rayed in different positions, X-rays would produce different images
depending on the angle and position of the elastase crystal. Researchers likely rotated elastase
crystals to different angles to understand the conformation of this enzyme from all sides.
b. There was no reason for the researchers to rotate the elastase crystals. It would have been
sufficient to carry out one X-ray crystallography experiment on an elastase crystal.
c. Rotating the elastase crystals to different angles likely affected the rate of the enzymatic
reaction; at a different angle, the hexapeptide substrate could remain bound to elastase for a
longer period of time. There was thus more time to get detailed X-ray images.
Solution
a.Similar to when you get X-rayed in different positions,X-rays would produce different images
depending on the angle and the position of the elactase crystal.Researchers likely rotated elastase
crystals to different angles and position of the elactase crystal.Researchers likely rotated elactase
crystals to different angles to understand to confirmation of this enzyme from all sides..
Numerous diseases are caused by problems in DNA replication or repai.pdf
Numerous diseases are caused by problems in DNA replication or repair. For example, Bloom
Syndrome is caused by a mutation in one of the helicase enzymes involved in DNA replication.
Select one of the enzymes involved in DNA replication or repair and find a disease related to a
mutation in this enzyme (a few of these diseases are mentioned in your textbook). Then, in at
least 3 pages, address the following topics: 1. What is the specific mutation? 2. What are the
symptoms of the disease? 3. How was the relationship between the mutation and the disease
discovered? 4. How does this mutation impact DNA replication and repair and how is this
different from normal DNA replication? 5. How does this mutation impact transcription and
translation and how is this different from normal transcription and translation? 6. How does this
problem in DNA replication lead to one symptom of the disease? 7. Give two examples of how
genetic engineering technology could be used to learn more about, detect earlier, or treat this
disease? Be sure to include a description of what genetic engineering is. You should write this
Assignment as an integrated paper that addresses all the questions. This Assignment should not
be done in question and answer format. Be sure to use appropriate headings for each section of
the paper.
Solution
Disease caused :Progressive external ophthalmoplegia (PEO) is caused by mutations in
mitochondrial DNA.
1.Specific mutation:Human mitochondrial DNA replication takes place by two-subunitsof DNA
polymerase gamma (polgamma).Mutations in the polymerase and exonuclease domains of the
human polgamma is the cause behind the occurence of PEO.
2.Symptoms of the disease:
3.Discovery of the relationship between DNA replication and repair: The diseases was
discovered the symptoms that the patients experience followed by a genetic test on muscle
biopsy sample.This led to the conclusion that there occured several deletions inmitochondrial
DNA.Research further revealed that there occured mutations in polgamma on chrmosome
15q25.In particular, three autosomal dominant mutations were revealed that altered the amino
acids located within polymerase motif B of polgamma.
4.Impact of mutation on DNA replication: The mutation resulted in dysfunctioning of the
polgamma and thus some regions of the mitochondrial DNA are deleted in comparision to
normal replication where the entire mitochondrial DNA is replicated fully.
5.Impact on transcription and translation: Mitochondrial DNA encodes 13 protein subunits of
multimeric oxidative phosphorylation, 2 ribosomal RNAs and all the translated RNAs that are
required for the translation of its own messenger RNA.In presence of mutations, some regions of
mitochindrial DNA is not replicated and this leads to impaired protein synthesis.
6.Problem in DNA replication lead to one symptom of the disease: Deletions in segments of
mitochondrial DNA leads to defective function of oxidative phosphorylation due to impaired
protein synth.
If we maintain a strict biological definition of “species”, H. sapie.pdf
If we maintain a strict biological definition of “species”, H. sapiens and H. neanderthalensis were
NOT separate species as they successfully interbred. What impact might this information have
on assigning a date to the origin of humans? Are there any other implications?
Solution
As we know the common male ancester is usually much younger than the common female
ancester.Moreover the Mitochondrial DNA which is present in the Neanderthals and it is absent
in humans
Suppose we have related populations A, B and C and we can have that A can interbreed with B,
and also the B can interbreed with C,.At the same time ,A can not interbreed with C. Noe a
ccording to the strict BSC, the A and B are in the same species and at the same time B and C are
in the same species, but A and C are not.These are the implications
here.
It is impossible to know the date of origins of humans due to difference between sapiens and
neanderthals.we can fix one date on which an old species was found and can assume it to be the
date of origin..
If taxpayers Monica, Traci , and Phillip are responsible persons in .pdf
If taxpayers Monica, Traci , and Phillip are responsible persons in the failure to withhold and pay
over employment taxes but only Monica and Traci acted willfully which of the following
statements is correct? A the IRs may assess the trust fund recovery penalty against Monica ,
Traci and Phillip, but can only collect it from Monica and Traci b. The IRS can only asses and
collect a trust fund recovery penalty from Phillip c. The IRS cannot assess a trust find recovery
penalty against Phillip d. the IRS may asses a trust fund recovery penalty against Monica , Traci,
and Phillip
Solution
The tax IRs may assess a trust recovery penalty against monica, traci, and phillip, but can only
collect it from monica and trici.
The employer need to withhold taxes from its employees wages and pay them to IRS. Withheld
taxes are been said as trust fund taxes. When these taxes are not paid by the employer
intenstionally or not to get paid the taxes IRs checks for the responsible person and willful
person and upon all IRs may assess for thr trust fund recovery. IRs may ask for to pay the
penality by any of the responsible persons..
More from suhshbhosale (20)
What two kinds of secondary bonds hold polymer chains together Which.pdf
What two kinds of secondary bonds hold polymer chains together Which.pdf
When hiking up most Stratovolcanoes, which rock composition(s) will .pdf
When hiking up most Stratovolcanoes, which rock composition(s) will .pdf
What image of society is held by the three major theoretical approac.pdf
What image of society is held by the three major theoretical approac.pdf
What are the major evolutionary trends that developedamong major v.pdf
What are the major evolutionary trends that developedamong major v.pdf
True or falsea. List index values must be integers.b. Lists can.pdf
True or falsea. List index values must be integers.b. Lists can.pdf
True false correction questions and fill in the blank. Same rules app.pdf
True false correction questions and fill in the blank. Same rules app.pdf
Show that all the singular points of the following functions are pol.pdf
Show that all the singular points of the following functions are pol.pdf
The article at those photos groups 20 amino acids into 6 groups acco.pdf
The article at those photos groups 20 amino acids into 6 groups acco.pdf
Studying Viruses can be important because they are often disease .pdf
Studying Viruses can be important because they are often disease .pdf
State true or false with reason (all from Complex Analysis)-(a) P.pdf
State true or false with reason (all from Complex Analysis)-(a) P.pdf
send edited codeMain 2public class Main2 { public static voi.pdf
send edited codeMain 2public class Main2 { public static voi.pdf
Question 16What is a common tactic hackers use to allow themselves.pdf
Question 16What is a common tactic hackers use to allow themselves.pdf
Qualified plan documents can be written to accommodate plan forfeitu.pdf
Qualified plan documents can be written to accommodate plan forfeitu.pdf
Proteins fold. How WhySolutionANSProtein folding Protein.pdf
Proteins fold. How WhySolutionANSProtein folding Protein.pdf
PLN 360560 Environmental Impact Assessment Homework No. 4 1. An appl.pdf
PLN 360560 Environmental Impact Assessment Homework No. 4 1. An appl.pdf
one of the main design goals for the java programming language is se.pdf
one of the main design goals for the java programming language is se.pdf
Meyer and colleagues performed three rounds of X-ray crystallography.pdf
Meyer and colleagues performed three rounds of X-ray crystallography.pdf
Numerous diseases are caused by problems in DNA replication or repai.pdf
Numerous diseases are caused by problems in DNA replication or repai.pdf
If we maintain a strict biological definition of “species”, H. sapie.pdf
If we maintain a strict biological definition of “species”, H. sapie.pdf
If taxpayers Monica, Traci , and Phillip are responsible persons in .pdf
If taxpayers Monica, Traci , and Phillip are responsible persons in .pdf
Recently uploaded
Instructions for Submissions thorugh G- Classroom.pptx
This presentation provides a briefing on how to upload submissions and documents in Google Classroom. It was prepared as part of an orientation for new Sainik School in-service teacher trainees. As a training officer, my goal is to ensure that you are comfortable and proficient with this essential tool for managing assignments and fostering student engagement.
The French Revolution Class 9 Study Material pdf free download
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
For more information, visit-www.vavaclasses.com
The approach at University of Liverpool.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...Nguyen Thanh Tu Collection
https://app.box.com/s/hqnndn05v4q5a4k4jd597rkdbda0fnii1.4 modern child centered education - mahatma gandhi-2.pptx
Child centred education is an educational approach that priorities the interest, needs and abilities of the child in the learning process.
The geography of Taylor Swift - some ideas
Geographical themes connected with Taylor Swift's ERAS tour - coming to the UK in June 2024
Acetabularia Information For Class 9 .docx
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
Honest Reviews of Tim Han LMA Course Program.pptx
Personal development courses are widely available today, with each one promising life-changing outcomes. Tim Han’s Life Mastery Achievers (LMA) Course has drawn a lot of interest. In addition to offering my frank assessment of Success Insider’s LMA Course, this piece examines the course’s effects via a variety of Tim Han LMA course reviews and Success Insider comments.
Polish students' mobility in the Czech Republic
Polish students mobility to the Czech Republic within eTwinning project "Medieval adventures with Marco Polo"
678020731-Sumas-y-Restas-Para-Colorear.pdf
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK
Unit 2- Research Aptitude (UGC NET Paper I).pdf
This slide describes the research aptitude of unit 2 in the UGC NET paper I.
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
This slide is prepared for master's students (MIFB & MIBS) UUM. May it be useful to all.Home assignment II on Spectroscopy 2024 Answers.pdf
Answers to Home assignment on UV-Visible spectroscopy: Calculation of wavelength of UV-Visible absorption
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
Class 11 CBSE Business Studies Project ( AIDS TO TRADE - INSURANCE)
Biological Screening of Herbal Drugs in detailed.
Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
for Anti-inflammatory, Antiulcer, Anticancer, Wound healing, Antidiabetic, Hepatoprotective, Cardio protective, Diuretics and
Antifertility, Toxicity studies as per OECD guidelines
Supporting (UKRI) OA monographs at Salford.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
The Challenger.pdf DNHS Official Publication
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
Recently uploaded (20)
Adversarial Attention Modeling for Multi-dimensional Emotion Regression.pdf
Adversarial Attention Modeling for Multi-dimensional Emotion Regression.pdf
Instructions for Submissions thorugh G- Classroom.pptx
Instructions for Submissions thorugh G- Classroom.pptx
The French Revolution Class 9 Study Material pdf free download
The French Revolution Class 9 Study Material pdf free download
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
1.4 modern child centered education - mahatma gandhi-2.pptx
1.4 modern child centered education - mahatma gandhi-2.pptx
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptx
Home assignment II on Spectroscopy 2024 Answers.pdf
Home assignment II on Spectroscopy 2024 Answers.pdf
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
CLASS 11 CBSE B.St Project AIDS TO TRADE - INSURANCE
In the Mexican swordtail fish, the wild-type color is olive-green. Ot.pdf
- 1. In the Mexican swordtail fish, the wild-type color is olive-green. Other color variants include golden and Take caution with ratio there is some reduced viability in this system. Matings involving fish of these three phenotypes are shown below: Explain the inheritance of these color phenotypes in the fish Solution At any rate, the mode of inheritance of albinism in the goldfish has not hitherto been known. Using mates of different varieties of the goldfish, scientists arrived at the conclusion that albinism of the goldfish is not a simple Mendelian character but it is represented by the double homozygote of two non-linked autosomal recessive genes since because the F2 generation shows 15:1 ratio for non-albino and albino types like we see in the case of duplicate genes. example: If the animal was A/a, because a is recessive and A is dominant, the animal's phenotype wouldn't be albino, but it would still carry the gene for albinism (since it has an "a"). Since it carries both "A" and "a", it is known as "heterozygous". If the animal had the A/A combination, its phenotype wouldn't be albino, and it wouldn't carry the gene for albinism (both genes being the same, it is called "homozygous" for "A"). If it were homozygous for "a" (i.e. a/a), the animal's phenotype would be albino. Since "a" is recessive, both alleles need to be "a" in order for albinism to be expressed in the phenotype. The genes for the pigment cells are inherited independently of one another, and there is no known linkage to any other genes. So, each pigment type is coded by two different genes, one on each of a pair of chromosomes. The phenotype of wild type animals is dark, non-melanoid, non- albino and non-axanthic. The golden colour (D/D a/a or D/d a/a). It has normal migration of pigment cells, but lacks melanophores, hence the yellow/gold appearance.