In Java....The methods should work as add(Node) It has to take a .pdf
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In Java.... The methods should work as: add(Node) It has to take a new Node and add that to the next address of previous Node. findNode(Node) It has to take a node and checks if the node is in the list. size() It should return the size of the NodeList. public class NodeList { private int size = 0; private Node root = null; /* * It has to take a new Node and add that to the next address of previous Node. * If the list is empty, assign it as the \"root\" * @Param - Node */ public void add(Node node) { // Implement this method!!! } /* * It has to return the size of the NodeList * * @return size */ public int size() { // Implement this method!!! } /* * It has to take a Node and checks if the node is in the list. * If it finds the node, it returns true, otherwise false * * @param - Node * @return boolean true/false */ public boolean findNode(Node node){ // Implement this method!!! } } Solution public class NodeList { private int size = 0; private Node root = null; /* * It has to take a new Node and add that to the next address of previous Node. * If the list is empty, assign it as the \"root\" * @Param - Node */ public void add(Node node) { // Implement this method!!! if(node==null) return; if(root == null) root=node; else{ Node temp = root; while(temp.next!=null){ temp = temp.next; } temp.next = node; } } /* * It has to return the size of the NodeList * * @return size */ public int size() { // Implement this method!!! int count =0; if(root==null) return count; else{ Node temp = root; while(temp!=null){ temp= temp.next; count++; } } return count; } /* * It has to take a Node and checks if the node is in the list. * If it finds the node, it returns true, otherwise false * * @param - Node * @return boolean true/false */ public boolean findNode(Node node){ // Implement this method!!! boolean flag = false; if(root == null) return false; else{ Node temp = root; while(temp!=null){ if(temp==node){ flag = true; break; } } return flag; } } } also find the defination of class Node class Node{ int data; Node next; }.
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Write the following using javaGiven a class ‘Node’ and ‘NodeList’,.pdf
Write the following using java
Given a class ‘Node’ and ‘NodeList’, that contains the below information diagram.
-id: int
-name: String
-next: Node
+Node(id: int, name: String)
+setId(id: int): void
+getId(): int
+setName(name: String) : void
+getName(): String
+setNext(node: Node): void
+getNext(): Node
NodeList
-size: int
-root: Node
+add(node: Node): void
+size(): int
+findNode(node: Node): boolean
Implement add(Node), findNode(Node) and size methods in the NodeList class which is
provided to you. The methods should work as:
Using the following main method:
public static void main(String[] args)
{
NodeList list = new NodeList();
Node node = new Node(1, \"Book\");
Node node2 = new Node(2, \"Lappy\");
list.add(node);
list.add(node2);
System.out.println(\"Length : \"+list.size());
Node node3 = new Node(3, \"Glass\");
Node node4 = new Node(4, \"Pen\");
list.add(node3);
System.out.println(\"Length : \"+list.size());
if(list.findNode(node3)) System.out.println(\"Node found: \"+ node3.getName());
else
System.out.println(\"Node not found: \"+ node3.getName());
if(list.findNode(node4)) System.out.println(\"Node found: \"+ node4.getName());
else
System.out.println(\"Node not found: \"+ node4.getName());
}
Then it should return the following output:
Length : 2
Length : 3
Node found: Glass
Node not found: Pen
The given Node class is:
public class Node
{
private int id = 0;
private String name = \"\";
private Node next;
public Node(int id, String name)
{
this.id = id;
this.name = name;
this.next = null;
}
public Node getNext()
{
return next;
}
public void setNext(Node node)
{
this.next = node
}
public int getId()
{
return id;
{
public void setId(int id)
{
this.id = id;
}
public String getName()
{
return name;
}
public void setName(String name)
{
this.name = name;
}
public String toString()
{
return \"ID : \"+this.id+\" Name : \"+this.name;
}
}
The given NodeList class is:
public class NodeList
{
private int size = 0;
private Node root = null;
/*
* It has to take a new Node and add that to the next address of previous Node.
* If the list is empty, assign it as the \"root\"
* @Param - Node
*/
public void add(Node node)
{
// Implement this method!!!
}
/*
* It has to return the size of the NodeList
*
* @return size
*/
public int size()
{
// Implement this method!!!
}
/*
* It has to take a Node and checks if the node is in the list.
* If it finds the node, it returns true, otherwise false
*
* @param - Node
* @return boolean true/false
*/
public boolean findNode(Node node)
{
// Implement this method!!!
}
}Node
-id: int
-name: String
-next: Node
+Node(id: int, name: String)
+setId(id: int): void
+getId(): int
+setName(name: String) : void
+getName(): String
+setNext(node: Node): void
+getNext(): Node
Solution
Hi, Please find my implementation.
Please let me know in case of any issue.
############ Node.java #############
public class Node
{
private int id = 0;
private String name = \"\";
private Node next;
public Node(int id, String name)
{
this.id = id;
this..
The LinkedList1 class implements a Linked list. class.pdf
/**
The LinkedList1 class implements a Linked list.
*/
class LinkedList1
{
/**
The Node class stores a list element
and a reference to the next node.
*/
private class Node
{
String value;
Node next;
/**
Constructor.
@param val The element to store in the node.
@param n The reference to the successor node.
*/
Node(String val, Node n)
{
value = val;
next = n;
}
/**
Constructor.
@param val The element to store in the node.
*/
Node(String val)
{
// Call the other (sister) constructor.
this(val, null);
}
}
private Node first; // list head
private Node last; // last element in list
/**
Constructor.
*/
public LinkedList1()
{
first = null;
last = null;
}
/**
The isEmpty method checks to see
if the list is empty.
@return true if list is empty,
false otherwise.
*/
public boolean isEmpty()
{
return first == null;
}
/**
The size method returns the length of the list.
@return The number of elements in the list.
*/
public int size()
{
int count = 0;
Node p = first;
while (p != null)
{
// There is an element at p
count ++;
p = p.next;
}
return count;
}
/**
The add method adds an element to
the end of the list.
@param e The value to add to the
end of the list.
*/
public void add(String e)
{
if (isEmpty())
{
first = new Node(e);
last = first;
}
else
{
// Add to end of existing list
last.next = new Node(e);
last = last.next;
}
}
/**
The add method adds an element at a position.
@param e The element to add to the list.
@param index The position at which to add
the element.
@exception IndexOutOfBoundsException When
index is out of bounds.
*/
public void add(int index, String e)
{
if (index < 0 || index > size())
{
String message = String.valueOf(index);
throw new IndexOutOfBoundsException(message);
}
// Index is at least 0
if (index == 0)
{
// New element goes at beginning
first = new Node(e, first);
if (last == null)
last = first;
return;
}
// Set a reference pred to point to the node that
// will be the predecessor of the new node
Node pred = first;
for (int k = 1; k <= index - 1; k++)
{
pred = pred.next;
}
// Splice in a node containing the new element
pred.next = new Node(e, pred.next);
// Is there a new last element ?
if (pred.next.next == null)
last = pred.next;
}
/**
The toString method computes the string
representation of the list.
@return The string form of the list.
*/
public String toString()
{
StringBuilder strBuilder = new StringBuilder();
// Use p to walk down the linked list
Node p = first;
while (p != null)
{
strBuilder.append(p.value + \"\ \");
p = p.next;
}
return strBuilder.toString();
}
/**
The remove method removes the element at an index.
@param index The index of the element to remove.
@return The element removed.
@exception IndexOutOfBoundsException When index is
out of bounds.
*/
public String remove(int index)
{
if (index < 0 || index >= size())
{
String message = String.valueOf(index);
throw new IndexOutOfBoundsException(message);
}
String element; // The element to return
if (index == 0)
{
// Removal of first item in the list
element.
Note- Can someone help me with the Public boolean add(E value) method.pdf
Note: Can someone help me with the Public boolean add(E value) method and Private void
add(E value,Node n) method. I have everything but it is not working. Also need help with the
remove methods. Both public and private methods for remove. package edu.ust.cisc; import
java.util.Iterator; import java.util.NoSuchElementException; public class CiscSortedLinkedList
> implements CiscList { /** * A reference to this list's dummy node. Its next reference should
refer to the node containing the first element * in this list, or it should refer to itself if the list is
empty. The next reference within the node containing * the last element in this list should refer to
dummy, thus creating a cyclic list. */ private Node dummy; /** * Number of elements in the list.
*/ private int size; /** * Constructs an empty CiscSortedLinkedList instance with a non-null
dummy node whose next reference refers to * itself. */ public CiscSortedLinkedList() { dummy
= new Node<>(null, null); dummy.next = dummy; } /** * Returns the number of elements in
this list. * * @return the number of elements in this list */ @Override public int size() { return
size; } /** * Returns {@code true} if this list contains no elements. * * @return {@code true} if
this list contains no elements */ @Override public boolean isEmpty() { return size==0; } /** *
Returns {@code true} if this list contains the specified element (compared using the {@code
equals} method). * This implementation should stop searching as soon as it is able to determine
that the specified element is not * present. * @param o element whose presence in this list is to
be tested * @return {@code true} if this list contains the specified element * @throws
NullPointerException if the specified element is null */ @Override public boolean
contains(Object o) { if(o==null){ throw new NullPointerException(); } return
containsHelper(o,dummy.next); } private boolean containsHelper(Object o, Node node){
if(node== dummy){ return false; } else if(o.equals(node.data)){ return true; } else{ return
containsHelper(o,node.next); } } /** * Returns an iterator over the elements in this list in proper
sequence. * * @return an iterator over the elements in this list in proper sequence */ @Override
public Iterator iterator() { //return new Iterator (){ //private Node curr = dummy.next; //private
Node prev = dummy; //private boolean canRemove = false; return new CiscLinkedListIterator();
} /** * Returns an array containing all of the elements in this list in proper sequence (from first
to last element). * *
The returned array will be "safe" in that no references to it are maintained by this list. (In other
words, * this method must allocate a new array even if this list is backed by an array). The caller
is thus free to modify * the returned array. * * @return an array containing all of the elements in
this list in proper sequence */ @Override public Object[] toArray() { Object[] arr = new
Object[size]; int i = 0; for(Node current = dummy;curren.
please i need help Im writing a program to test the merge sort alg.pdf
please i need help I\'m writing a program to test the merge sort algorithm for linked lists.
I need to Print the list before being sorted and the list after sorting the elements
here is my code only help in test program the four classes are ok except the test program.
TEST PROGRAM
import java.io.*;
import java.util.*;
public class Ch9_ProgExercise7 {
Scanner input = new Scanner(System.in);
public static void main(String[] args) throws IOException {
OrderedLinkedList list
= new OrderedLinkedList(); //Line 1
IntElement num = new IntElement(); //Line 2
// Prompt the user to enter some integers
System.out.println(\"Enter integers numbers \");
String temp = input.hasnextLine();
String[] split = temp.split(\" \");
for (int i = 0; i < split.length; i++) {
Integer a = Integer.parseInt(split[i]);
// insert the intgers into the list you created above
num.setNum(a);
list.insertNode(num);
}
System.out.println();
// Print the list before being sorted
// call the mergesort method
System.out.println();
// print the list after sorting the elements
}
}
ORDEREDLICKEDLIST CLASS
public class OrderedLinkedList extends LinkedListClass
{
//default constructor
public OrderedLinkedList()
{
super();
}
//copy constructor
public OrderedLinkedList(OrderedLinkedList otherList)
{
super(otherList);
}
public void linkedInsertionSort()
{
LinkedListNode lastInOrder;
LinkedListNode firstOutOfOrder;
LinkedListNode current;
LinkedListNode trailCurrent;
lastInOrder = first;
if(first == null)
System.out.println(\"Cannot sort an empty list\");
else
if(first.link == null)
System.out.println(\"The list is of length 1. \"
+ \"Already in order\");
else
while(lastInOrder.link != null)
{
firstOutOfOrder = lastInOrder.link;
if(firstOutOfOrder.info.compareTo(first.info) < 0)
{
lastInOrder.link = firstOutOfOrder.link;
firstOutOfOrder.link = first;
first = firstOutOfOrder;
}
else
{
trailCurrent = first;
current = first.link;
while(current.info.compareTo(firstOutOfOrder.info) < 0)
{
trailCurrent = current;
current = current.link;
}
if(current != firstOutOfOrder)
{
lastInOrder.link = firstOutOfOrder.link;
firstOutOfOrder.link = current;
trailCurrent.link = firstOutOfOrder;
}
else
lastInOrder = lastInOrder.link;
}
}
}//end linkedInsertionSort
//Method to determine whether searchItem is in
//the list.
//Postcondition: Returns true if searchItem is found
// in the list; otherwise, it returns
// false.
public boolean search(DataElement searchItem)
{
LinkedListNode current; //variable to traverse the list
boolean found;
current = first; //set current to point to the first
//node in the list
found = false; //set found to false
while(current != null && !found ) //search the list
if(current.info.compareTo(searchItem) >= 0)
found = true;
else
current = current.link; //make current point to
//the next node
if(found)
found = current.info.equals(searchItem);
return found;
}
//Method to insert insertItem in the list
//Postcondition: first points to the new list,
// newItem is inserted at the proper place
//.
Javai have to make a method that takes a linked list and then retu.pdf
Java
i have to make a method that takes a linked list and then returns a new linked list that is the
reverse of the original
this is the starting code
/**
* LinkedList lab.
* @author Emma Cheney
* @version 10/2/23
*/
public class LinkedList {
/**
* Internal Node class used for the linked list.
*/
public class Node {
String key;
int value;
Node next;
/**
* Node Constructor.
* @param key The Key
* @param value The Value
*/
public Node(String key, int value) {
this.key = key;
this.value = value;
}
}
private Node head;
private Node tail;
/**
* The default constructor.
*/
public LinkedList() {
head = null;
tail = null;
}
/**
* Add the key, value pair to the head of the linkedlist.
* @param key The Key
* @param val The Value
*
*/
public void addHead(String key, int val) {
Node n = new Node(key, val);
if (head == null) {
head = n;
tail = n;
} else {
n.next = head;
head = n;
}
}
/**
* Add the key, val pair to the tail of the linkedlist.
* @param key The Key
* @param val The Value
*/
public void addTail(String key, int val) {
Node n = new Node(key, val);
if (tail == null) {
head = n;
tail = n;
} else {
tail.next = n;
tail = n;
}
}
/**
* Returns the String format of the linkedlist.
* @return String The String format.
*/
public String toString() {
String ret = "";
Node curr = head;
while (curr != null) {
if (curr.next != null) {
ret += curr.key + ":" + curr.value + ", ";
} else {
ret += curr.key + ":" + curr.value;
}
curr = curr.next;
}
return ret;
}
/**
* Locate the Node in the linkedlist with the given key.
* @param key The key to find in the LinkedList
* @return Node Returns the Node with the given key or null if non-existent.
*/
private Node find(String key) {
Node curr = head;
while (curr != null) {
if (curr.key.equals(key)) {
return curr;
}
curr = curr.next;
}
return null;
} A static method called reversed that takes a LinkedList as a parameter and returns a new
LinkedList that is reversed. f; traverse through the input list (starting at the head). In order to
reverse the ordering, you need to add the current node's key and value onto the head of the new
list (addHead method). Do not change the input list or any values in it. Example (result in red)
//assumelistcontainsthesekeysandvalues://ie:6,bi:48,bi:73,bi:63LinkedList.reversed(list);bi:63,bi:
73,bi:48,ie:6.
Note- Can someone help me with the private E get(int index- int curren (1).docx
Note: Can someone help me with the private E get(int index, int currentIndex, Node n)method. The code is not running. Also I need help with the public void add(int index, E element) method too. Please use the parameters provided with the code to solve. package edu.ust.cisc; import java.util.Iterator; import java.util.NoSuchElementException; public class CiscSortedLinkedList > implements CiscList { /** * A reference to this list's dummy node. Its next reference should refer to the node containing the first element * in this list, or it should refer to itself if the list is empty. The next reference within the node containing * the last element in this list should refer to dummy, thus creating a cyclic list. */ private Node dummy; /** * Number of elements in the list. */ private int size; /** * Constructs an empty CiscSortedLinkedList instance with a non-null dummy node whose next reference refers to * itself. */ public CiscSortedLinkedList() { dummy = new Node<>(null, null); dummy.next = dummy; } /** * Returns the number of elements in this list. * * @return the number of elements in this list */ @Override public int size() { return size; } /** * Returns {@code true} if this list contains no elements. * * @return {@code true} if this list contains no elements */ @Override public boolean isEmpty() { return size==0; } /** * Returns {@code true} if this list contains the specified element (compared using the {@code equals} method). * This implementation should stop searching as soon as it is able to determine that the specified element is not * present. * * @param o element whose presence in this list is to be tested * @return {@code true} if this list contains the specified element * @throws NullPointerException if the specified element is null */ @Override public boolean contains(Object o) { if(o==null){ throw new NullPointerException(); } return containsHelper(o,dummy.next); } private boolean containsHelper(Object o, Node node){ if(node== dummy){ return false; } else if(o.equals(node.data)){ return true; } else{ return containsHelper(o,node.next); } } /** * Returns an iterator over the elements in this list in proper sequence. * * @return an iterator over the elements in this list in proper sequence */ @Override public Iterator iterator() { //return new Iterator (){ //private Node curr = dummy.next; //private Node prev = dummy; //private boolean canRemove = false; return null; } /** * Returns an array containing all of the elements in this list in proper sequence (from first to last element). *
The returned array will be "safe" in that no references to it are maintained by this list. (In other words, * this method must allocate a new array even if this list is backed by an array). The caller is thus free to modify * the returned array. * * @return an array containing all of the elements in this list in proper sequence */ @Override public Object[] toArray() { Object[] arr = new Object[size]; int i = 0; for(Node current = dummy;current!=null;cur.
Data Structures in C++I am really new to C++, so links are really .pdf
Data Structures in C++
I am really new to C++, so links are really hard topic for me. It would be nice if you can provide
explanations of what doubly linked lists are and of some of you steps... Thank you
In this assignment, you will implement a doubly-linked list class, together with some list
operations. To make things easier, you’ll implement a list of int, rather than a template class.
Solution
A variable helps us to identify the data. For ex: int a = 5; Here 5 is identified through variable a.
Now, if we have collection of integers, we need some representation to identify them. We call it
array. For ex: int arr[5]
This array is nothing but a Data Structure.
So, a Data Structure is a way to group the data.
There are many Data Structures available like Arrays, Linked List, Doubly-Linked list, Stack,
Queue, etc.
Doubly-Linked list are the ones where you can traverse from the current node both in left and
right directions.
Why so many different types of Data Structures are required ?
Answer is very simple, grouping of data, storage of data and accessing the data is different.
For example, in case of Arrays we store all the data in contiguous locations.
What if we are not able to store the data in contiguous locations because we have huge data.
Answer is go for Linked List/Doubly-Linked list.
Here we can store the data anywhere and link the data through pointers.
I will try to provide comments for the code you have given. May be this can help you.
#pragma once
/*
dlist.h
Doubly-linked lists of ints
*/
#include
class dlist {
public:
dlist() { }
// Here we are creating a NODE, it has a integer value and two pointers.
// One pointer is to move to next node and other to go back to previous node.
struct node {
int value;
node* next;
node* prev;
};
// To return head pointer, i.e. start of the Doubly-Linked list.
node* head() const { return _head; }
// To return Tail pointer, i.e. end of the Doubly-Linked list.
node* tail() const { return _tail; }
// **** Implement ALL the following methods ****
// Returns the node at a particular index (0 is the head).
node* at(int index){
int cnt = 0;
struct node* tmp = head();
while(tmp!=NULL)
{
if (cnt+1 == index)
return tmp;
tmp = tmp->next;
}
}
// Insert a new value, after an existing one
void insert(node *previous, int value){
// check if the given previous is NULL
if (previous == NULL)
{
printf(\"the given previous node cannot be NULL\");
return;
}
// allocate new node
struct node* new_node =(struct node*) malloc(sizeof(struct node));
// put in the data
new_node->data = new_data;
// Make next of new node as next of previous
new_node->next = previous->next;
// Make the next of previous as new_node
previous->next = new_node;
// Make previous as previous of new_node
new_node->prev = previous;
// Change previous of new_node\'s next node
if (new_node->next != NULL)
new_node->next->prev = new_node;
}
// Delete the given node
void del(node* which){
struct node* head_ref = head();
/* base case */
if(*head_ref == NUL.
This assignment and the next (#5) involve design and development of a.pdf
This assignment and the next (#5) involve design and development of a sequential
non contiguous and dynamic datastructure called LinkedList. A linked list object is
a container consisting of connected ListNode objects. As before, we are not going
to use pre-fabricated classes from the c++ library, but construct the LinkedList
ADT from scratch.
The first step is construction and testing of the ListNode class. A ListNode object
contains a data field and a pointer to the next ListNode object (note the recursive
definition).
#This assignment requires you to
1. Read the Assignment 4 Notes
2. Watch the Assignment 4 Support video
3. Implement the following methods of the ListNode class
-custom constructor
-setters for next pointer and data
4. Implement the insert and remove method in the main program
5. Scan the given template to find the above //TODO and implement the code
needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
void insert(ListNode<int> * &front,int value)
# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
#include <iostream>
#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
Recommended
Write the following using javaGiven a class ‘Node’ and ‘NodeList’,.pdf
Write the following using java
Given a class ‘Node’ and ‘NodeList’, that contains the below information diagram.
-id: int
-name: String
-next: Node
+Node(id: int, name: String)
+setId(id: int): void
+getId(): int
+setName(name: String) : void
+getName(): String
+setNext(node: Node): void
+getNext(): Node
NodeList
-size: int
-root: Node
+add(node: Node): void
+size(): int
+findNode(node: Node): boolean
Implement add(Node), findNode(Node) and size methods in the NodeList class which is
provided to you. The methods should work as:
Using the following main method:
public static void main(String[] args)
{
NodeList list = new NodeList();
Node node = new Node(1, \"Book\");
Node node2 = new Node(2, \"Lappy\");
list.add(node);
list.add(node2);
System.out.println(\"Length : \"+list.size());
Node node3 = new Node(3, \"Glass\");
Node node4 = new Node(4, \"Pen\");
list.add(node3);
System.out.println(\"Length : \"+list.size());
if(list.findNode(node3)) System.out.println(\"Node found: \"+ node3.getName());
else
System.out.println(\"Node not found: \"+ node3.getName());
if(list.findNode(node4)) System.out.println(\"Node found: \"+ node4.getName());
else
System.out.println(\"Node not found: \"+ node4.getName());
}
Then it should return the following output:
Length : 2
Length : 3
Node found: Glass
Node not found: Pen
The given Node class is:
public class Node
{
private int id = 0;
private String name = \"\";
private Node next;
public Node(int id, String name)
{
this.id = id;
this.name = name;
this.next = null;
}
public Node getNext()
{
return next;
}
public void setNext(Node node)
{
this.next = node
}
public int getId()
{
return id;
{
public void setId(int id)
{
this.id = id;
}
public String getName()
{
return name;
}
public void setName(String name)
{
this.name = name;
}
public String toString()
{
return \"ID : \"+this.id+\" Name : \"+this.name;
}
}
The given NodeList class is:
public class NodeList
{
private int size = 0;
private Node root = null;
/*
* It has to take a new Node and add that to the next address of previous Node.
* If the list is empty, assign it as the \"root\"
* @Param - Node
*/
public void add(Node node)
{
// Implement this method!!!
}
/*
* It has to return the size of the NodeList
*
* @return size
*/
public int size()
{
// Implement this method!!!
}
/*
* It has to take a Node and checks if the node is in the list.
* If it finds the node, it returns true, otherwise false
*
* @param - Node
* @return boolean true/false
*/
public boolean findNode(Node node)
{
// Implement this method!!!
}
}Node
-id: int
-name: String
-next: Node
+Node(id: int, name: String)
+setId(id: int): void
+getId(): int
+setName(name: String) : void
+getName(): String
+setNext(node: Node): void
+getNext(): Node
Solution
Hi, Please find my implementation.
Please let me know in case of any issue.
############ Node.java #############
public class Node
{
private int id = 0;
private String name = \"\";
private Node next;
public Node(int id, String name)
{
this.id = id;
this..
The LinkedList1 class implements a Linked list. class.pdf
/**
The LinkedList1 class implements a Linked list.
*/
class LinkedList1
{
/**
The Node class stores a list element
and a reference to the next node.
*/
private class Node
{
String value;
Node next;
/**
Constructor.
@param val The element to store in the node.
@param n The reference to the successor node.
*/
Node(String val, Node n)
{
value = val;
next = n;
}
/**
Constructor.
@param val The element to store in the node.
*/
Node(String val)
{
// Call the other (sister) constructor.
this(val, null);
}
}
private Node first; // list head
private Node last; // last element in list
/**
Constructor.
*/
public LinkedList1()
{
first = null;
last = null;
}
/**
The isEmpty method checks to see
if the list is empty.
@return true if list is empty,
false otherwise.
*/
public boolean isEmpty()
{
return first == null;
}
/**
The size method returns the length of the list.
@return The number of elements in the list.
*/
public int size()
{
int count = 0;
Node p = first;
while (p != null)
{
// There is an element at p
count ++;
p = p.next;
}
return count;
}
/**
The add method adds an element to
the end of the list.
@param e The value to add to the
end of the list.
*/
public void add(String e)
{
if (isEmpty())
{
first = new Node(e);
last = first;
}
else
{
// Add to end of existing list
last.next = new Node(e);
last = last.next;
}
}
/**
The add method adds an element at a position.
@param e The element to add to the list.
@param index The position at which to add
the element.
@exception IndexOutOfBoundsException When
index is out of bounds.
*/
public void add(int index, String e)
{
if (index < 0 || index > size())
{
String message = String.valueOf(index);
throw new IndexOutOfBoundsException(message);
}
// Index is at least 0
if (index == 0)
{
// New element goes at beginning
first = new Node(e, first);
if (last == null)
last = first;
return;
}
// Set a reference pred to point to the node that
// will be the predecessor of the new node
Node pred = first;
for (int k = 1; k <= index - 1; k++)
{
pred = pred.next;
}
// Splice in a node containing the new element
pred.next = new Node(e, pred.next);
// Is there a new last element ?
if (pred.next.next == null)
last = pred.next;
}
/**
The toString method computes the string
representation of the list.
@return The string form of the list.
*/
public String toString()
{
StringBuilder strBuilder = new StringBuilder();
// Use p to walk down the linked list
Node p = first;
while (p != null)
{
strBuilder.append(p.value + \"\ \");
p = p.next;
}
return strBuilder.toString();
}
/**
The remove method removes the element at an index.
@param index The index of the element to remove.
@return The element removed.
@exception IndexOutOfBoundsException When index is
out of bounds.
*/
public String remove(int index)
{
if (index < 0 || index >= size())
{
String message = String.valueOf(index);
throw new IndexOutOfBoundsException(message);
}
String element; // The element to return
if (index == 0)
{
// Removal of first item in the list
element.
Note- Can someone help me with the Public boolean add(E value) method.pdf
Note: Can someone help me with the Public boolean add(E value) method and Private void
add(E value,Node n) method. I have everything but it is not working. Also need help with the
remove methods. Both public and private methods for remove. package edu.ust.cisc; import
java.util.Iterator; import java.util.NoSuchElementException; public class CiscSortedLinkedList
> implements CiscList { /** * A reference to this list's dummy node. Its next reference should
refer to the node containing the first element * in this list, or it should refer to itself if the list is
empty. The next reference within the node containing * the last element in this list should refer to
dummy, thus creating a cyclic list. */ private Node dummy; /** * Number of elements in the list.
*/ private int size; /** * Constructs an empty CiscSortedLinkedList instance with a non-null
dummy node whose next reference refers to * itself. */ public CiscSortedLinkedList() { dummy
= new Node<>(null, null); dummy.next = dummy; } /** * Returns the number of elements in
this list. * * @return the number of elements in this list */ @Override public int size() { return
size; } /** * Returns {@code true} if this list contains no elements. * * @return {@code true} if
this list contains no elements */ @Override public boolean isEmpty() { return size==0; } /** *
Returns {@code true} if this list contains the specified element (compared using the {@code
equals} method). * This implementation should stop searching as soon as it is able to determine
that the specified element is not * present. * @param o element whose presence in this list is to
be tested * @return {@code true} if this list contains the specified element * @throws
NullPointerException if the specified element is null */ @Override public boolean
contains(Object o) { if(o==null){ throw new NullPointerException(); } return
containsHelper(o,dummy.next); } private boolean containsHelper(Object o, Node node){
if(node== dummy){ return false; } else if(o.equals(node.data)){ return true; } else{ return
containsHelper(o,node.next); } } /** * Returns an iterator over the elements in this list in proper
sequence. * * @return an iterator over the elements in this list in proper sequence */ @Override
public Iterator iterator() { //return new Iterator (){ //private Node curr = dummy.next; //private
Node prev = dummy; //private boolean canRemove = false; return new CiscLinkedListIterator();
} /** * Returns an array containing all of the elements in this list in proper sequence (from first
to last element). * *
The returned array will be "safe" in that no references to it are maintained by this list. (In other
words, * this method must allocate a new array even if this list is backed by an array). The caller
is thus free to modify * the returned array. * * @return an array containing all of the elements in
this list in proper sequence */ @Override public Object[] toArray() { Object[] arr = new
Object[size]; int i = 0; for(Node current = dummy;curren.
please i need help Im writing a program to test the merge sort alg.pdf
please i need help I\'m writing a program to test the merge sort algorithm for linked lists.
I need to Print the list before being sorted and the list after sorting the elements
here is my code only help in test program the four classes are ok except the test program.
TEST PROGRAM
import java.io.*;
import java.util.*;
public class Ch9_ProgExercise7 {
Scanner input = new Scanner(System.in);
public static void main(String[] args) throws IOException {
OrderedLinkedList list
= new OrderedLinkedList(); //Line 1
IntElement num = new IntElement(); //Line 2
// Prompt the user to enter some integers
System.out.println(\"Enter integers numbers \");
String temp = input.hasnextLine();
String[] split = temp.split(\" \");
for (int i = 0; i < split.length; i++) {
Integer a = Integer.parseInt(split[i]);
// insert the intgers into the list you created above
num.setNum(a);
list.insertNode(num);
}
System.out.println();
// Print the list before being sorted
// call the mergesort method
System.out.println();
// print the list after sorting the elements
}
}
ORDEREDLICKEDLIST CLASS
public class OrderedLinkedList extends LinkedListClass
{
//default constructor
public OrderedLinkedList()
{
super();
}
//copy constructor
public OrderedLinkedList(OrderedLinkedList otherList)
{
super(otherList);
}
public void linkedInsertionSort()
{
LinkedListNode lastInOrder;
LinkedListNode firstOutOfOrder;
LinkedListNode current;
LinkedListNode trailCurrent;
lastInOrder = first;
if(first == null)
System.out.println(\"Cannot sort an empty list\");
else
if(first.link == null)
System.out.println(\"The list is of length 1. \"
+ \"Already in order\");
else
while(lastInOrder.link != null)
{
firstOutOfOrder = lastInOrder.link;
if(firstOutOfOrder.info.compareTo(first.info) < 0)
{
lastInOrder.link = firstOutOfOrder.link;
firstOutOfOrder.link = first;
first = firstOutOfOrder;
}
else
{
trailCurrent = first;
current = first.link;
while(current.info.compareTo(firstOutOfOrder.info) < 0)
{
trailCurrent = current;
current = current.link;
}
if(current != firstOutOfOrder)
{
lastInOrder.link = firstOutOfOrder.link;
firstOutOfOrder.link = current;
trailCurrent.link = firstOutOfOrder;
}
else
lastInOrder = lastInOrder.link;
}
}
}//end linkedInsertionSort
//Method to determine whether searchItem is in
//the list.
//Postcondition: Returns true if searchItem is found
// in the list; otherwise, it returns
// false.
public boolean search(DataElement searchItem)
{
LinkedListNode current; //variable to traverse the list
boolean found;
current = first; //set current to point to the first
//node in the list
found = false; //set found to false
while(current != null && !found ) //search the list
if(current.info.compareTo(searchItem) >= 0)
found = true;
else
current = current.link; //make current point to
//the next node
if(found)
found = current.info.equals(searchItem);
return found;
}
//Method to insert insertItem in the list
//Postcondition: first points to the new list,
// newItem is inserted at the proper place
//.
Javai have to make a method that takes a linked list and then retu.pdf
Java
i have to make a method that takes a linked list and then returns a new linked list that is the
reverse of the original
this is the starting code
/**
* LinkedList lab.
* @author Emma Cheney
* @version 10/2/23
*/
public class LinkedList {
/**
* Internal Node class used for the linked list.
*/
public class Node {
String key;
int value;
Node next;
/**
* Node Constructor.
* @param key The Key
* @param value The Value
*/
public Node(String key, int value) {
this.key = key;
this.value = value;
}
}
private Node head;
private Node tail;
/**
* The default constructor.
*/
public LinkedList() {
head = null;
tail = null;
}
/**
* Add the key, value pair to the head of the linkedlist.
* @param key The Key
* @param val The Value
*
*/
public void addHead(String key, int val) {
Node n = new Node(key, val);
if (head == null) {
head = n;
tail = n;
} else {
n.next = head;
head = n;
}
}
/**
* Add the key, val pair to the tail of the linkedlist.
* @param key The Key
* @param val The Value
*/
public void addTail(String key, int val) {
Node n = new Node(key, val);
if (tail == null) {
head = n;
tail = n;
} else {
tail.next = n;
tail = n;
}
}
/**
* Returns the String format of the linkedlist.
* @return String The String format.
*/
public String toString() {
String ret = "";
Node curr = head;
while (curr != null) {
if (curr.next != null) {
ret += curr.key + ":" + curr.value + ", ";
} else {
ret += curr.key + ":" + curr.value;
}
curr = curr.next;
}
return ret;
}
/**
* Locate the Node in the linkedlist with the given key.
* @param key The key to find in the LinkedList
* @return Node Returns the Node with the given key or null if non-existent.
*/
private Node find(String key) {
Node curr = head;
while (curr != null) {
if (curr.key.equals(key)) {
return curr;
}
curr = curr.next;
}
return null;
} A static method called reversed that takes a LinkedList as a parameter and returns a new
LinkedList that is reversed. f; traverse through the input list (starting at the head). In order to
reverse the ordering, you need to add the current node's key and value onto the head of the new
list (addHead method). Do not change the input list or any values in it. Example (result in red)
//assumelistcontainsthesekeysandvalues://ie:6,bi:48,bi:73,bi:63LinkedList.reversed(list);bi:63,bi:
73,bi:48,ie:6.
Note- Can someone help me with the private E get(int index- int curren (1).docx
Note: Can someone help me with the private E get(int index, int currentIndex, Node n)method. The code is not running. Also I need help with the public void add(int index, E element) method too. Please use the parameters provided with the code to solve. package edu.ust.cisc; import java.util.Iterator; import java.util.NoSuchElementException; public class CiscSortedLinkedList > implements CiscList { /** * A reference to this list's dummy node. Its next reference should refer to the node containing the first element * in this list, or it should refer to itself if the list is empty. The next reference within the node containing * the last element in this list should refer to dummy, thus creating a cyclic list. */ private Node dummy; /** * Number of elements in the list. */ private int size; /** * Constructs an empty CiscSortedLinkedList instance with a non-null dummy node whose next reference refers to * itself. */ public CiscSortedLinkedList() { dummy = new Node<>(null, null); dummy.next = dummy; } /** * Returns the number of elements in this list. * * @return the number of elements in this list */ @Override public int size() { return size; } /** * Returns {@code true} if this list contains no elements. * * @return {@code true} if this list contains no elements */ @Override public boolean isEmpty() { return size==0; } /** * Returns {@code true} if this list contains the specified element (compared using the {@code equals} method). * This implementation should stop searching as soon as it is able to determine that the specified element is not * present. * * @param o element whose presence in this list is to be tested * @return {@code true} if this list contains the specified element * @throws NullPointerException if the specified element is null */ @Override public boolean contains(Object o) { if(o==null){ throw new NullPointerException(); } return containsHelper(o,dummy.next); } private boolean containsHelper(Object o, Node node){ if(node== dummy){ return false; } else if(o.equals(node.data)){ return true; } else{ return containsHelper(o,node.next); } } /** * Returns an iterator over the elements in this list in proper sequence. * * @return an iterator over the elements in this list in proper sequence */ @Override public Iterator iterator() { //return new Iterator (){ //private Node curr = dummy.next; //private Node prev = dummy; //private boolean canRemove = false; return null; } /** * Returns an array containing all of the elements in this list in proper sequence (from first to last element). *
The returned array will be "safe" in that no references to it are maintained by this list. (In other words, * this method must allocate a new array even if this list is backed by an array). The caller is thus free to modify * the returned array. * * @return an array containing all of the elements in this list in proper sequence */ @Override public Object[] toArray() { Object[] arr = new Object[size]; int i = 0; for(Node current = dummy;current!=null;cur.
Data Structures in C++I am really new to C++, so links are really .pdf
Data Structures in C++
I am really new to C++, so links are really hard topic for me. It would be nice if you can provide
explanations of what doubly linked lists are and of some of you steps... Thank you
In this assignment, you will implement a doubly-linked list class, together with some list
operations. To make things easier, you’ll implement a list of int, rather than a template class.
Solution
A variable helps us to identify the data. For ex: int a = 5; Here 5 is identified through variable a.
Now, if we have collection of integers, we need some representation to identify them. We call it
array. For ex: int arr[5]
This array is nothing but a Data Structure.
So, a Data Structure is a way to group the data.
There are many Data Structures available like Arrays, Linked List, Doubly-Linked list, Stack,
Queue, etc.
Doubly-Linked list are the ones where you can traverse from the current node both in left and
right directions.
Why so many different types of Data Structures are required ?
Answer is very simple, grouping of data, storage of data and accessing the data is different.
For example, in case of Arrays we store all the data in contiguous locations.
What if we are not able to store the data in contiguous locations because we have huge data.
Answer is go for Linked List/Doubly-Linked list.
Here we can store the data anywhere and link the data through pointers.
I will try to provide comments for the code you have given. May be this can help you.
#pragma once
/*
dlist.h
Doubly-linked lists of ints
*/
#include
class dlist {
public:
dlist() { }
// Here we are creating a NODE, it has a integer value and two pointers.
// One pointer is to move to next node and other to go back to previous node.
struct node {
int value;
node* next;
node* prev;
};
// To return head pointer, i.e. start of the Doubly-Linked list.
node* head() const { return _head; }
// To return Tail pointer, i.e. end of the Doubly-Linked list.
node* tail() const { return _tail; }
// **** Implement ALL the following methods ****
// Returns the node at a particular index (0 is the head).
node* at(int index){
int cnt = 0;
struct node* tmp = head();
while(tmp!=NULL)
{
if (cnt+1 == index)
return tmp;
tmp = tmp->next;
}
}
// Insert a new value, after an existing one
void insert(node *previous, int value){
// check if the given previous is NULL
if (previous == NULL)
{
printf(\"the given previous node cannot be NULL\");
return;
}
// allocate new node
struct node* new_node =(struct node*) malloc(sizeof(struct node));
// put in the data
new_node->data = new_data;
// Make next of new node as next of previous
new_node->next = previous->next;
// Make the next of previous as new_node
previous->next = new_node;
// Make previous as previous of new_node
new_node->prev = previous;
// Change previous of new_node\'s next node
if (new_node->next != NULL)
new_node->next->prev = new_node;
}
// Delete the given node
void del(node* which){
struct node* head_ref = head();
/* base case */
if(*head_ref == NUL.
This assignment and the next (#5) involve design and development of a.pdf
This assignment and the next (#5) involve design and development of a sequential
non contiguous and dynamic datastructure called LinkedList. A linked list object is
a container consisting of connected ListNode objects. As before, we are not going
to use pre-fabricated classes from the c++ library, but construct the LinkedList
ADT from scratch.
The first step is construction and testing of the ListNode class. A ListNode object
contains a data field and a pointer to the next ListNode object (note the recursive
definition).
#This assignment requires you to
1. Read the Assignment 4 Notes
2. Watch the Assignment 4 Support video
3. Implement the following methods of the ListNode class
-custom constructor
-setters for next pointer and data
4. Implement the insert and remove method in the main program
5. Scan the given template to find the above //TODO and implement the code
needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
void insert(ListNode<int> * &front,int value)
# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
#include <iostream>
#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
Sorted number list implementation with linked listsStep 1 Inspec.pdf
Sorted number list implementation with linked lists
Step 1: Inspect the Node.java file
Inspect the class declaration for a doubly-linked list node in Node.java. Access Node.java by
clicking on the orange arrow next to LabProgram.java at the top of the coding window. The
Node class has three fields:
a double data value,
a reference to the next node, and
a reference to the previous node.
Each field is protected. So code outside of the class must use the provided getter and setter
methods to get or set a field.
Node.java is read only, since no changes are required.
Step 2: Implement the insert() method
A class for a sorted, doubly-linked list is declared in SortedNumberList.java. Implement the
SortedNumberList class's insert() method. The method must create a new node with the
parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then insert(33.5) is called. A new
node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the remove() method
Implement the SortedNumberList class's remove() method. The method takes a parameter for the
number to be removed from the list. If the number does not exist in the list, the list is not
changed and false is returned. Otherwise, the first instance of the number is removed from the
list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
Given templates:
LabProgram.java
import java.util.Scanner;
import java.io.PrintWriter;
public class LabProgram {
// Prints the SortedNumberList's contents, in order from head to tail
public static void printList(SortedNumberList list) {
Node node = list.head;
while (null != node) {
System.out.print(node.getData() + " ");
node = node.getNext();
}
System.out.println();
}
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
String inputLine;
// Read the line of input numbers
inputLine = scnr.nextLine();
// Split on space character
String[] terms = inputLine.split(" ");
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list = new SortedNumberList();
for (Object term : terms) {
double number = Double.parseDouble(term.toString());
System.out.println("List after inserting " + number + ": ");
list.insert(number);
printList(list);
}
/*
// Read the input line with numbers to remove
inputLine = scnr.nextLine();
terms = inputLine.split(" ".
C Homework Help
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--INSTRUCTION- --It helps to first create if-then-else structure to fi.pdf
This document contains code and comments for implementing a linked list data structure in C++. It includes function definitions and comments for common linked list operations like adding/removing nodes from the front/rear, checking if empty, getting length, converting to a string, and displaying all nodes. There are also TODO notes to fill in code for more advanced operations like deleting/inserting at a specified position, a copy constructor, and an assignment operator.
Need Help!! C++ #include-iostream- #include-linkedlist-h- using namesp.pdf
Need Help!! C++
#include<iostream>
#include"linkedlist.h"
using namespace std;
/**
* @brief Destructor to destroy all nodes and release memory
*/
LinkedList::~LinkedList() {
//TODO: Add code here. Make sure memory is released properly.
}
/**
* @brief Purpose: Checks if the list is empty
* @return true if the list is empty, false otherwise
*/
bool LinkedList::isEmpty() const {
// TODO: Add code here
return count == 0;
}
/**
* @brief Get the number of nodes in the list
* @return int The number of nodes in the list
*/
int LinkedList::length() const{
//TODO: Add code here
}
/**
* @brief Convert the list to a string
*
*/
string LinkedList::toString() {
string str = "[";
Node *ptr = front;
if (ptr != nullptr) {
// Head node is not preceded by separator
str += to_string(ptr->val);
ptr = ptr->next;
}
while (ptr != nullptr) {
str += ", " + to_string(ptr->val);
ptr = ptr->next;
}
str += "]";
return str;
}
/**
* @brief Displays the contents of the list
*/
void LinkedList::displayAll() {
cout << toString() << endl;
}
//TODO: Add comments
void LinkedList::addRear(T val) {
// TODO: Add code here
// consider the two cases of whether the list was empty
}
//TODO: Add comments
void LinkedList::addFront(T val) {
// TODO: Add code here
// consider the two cases of whether the list was empty
}
//TODO: Add comments
bool LinkedList::deleteFront(T &OldNum) {
// TODO: Add code here
// consider if the list was empty and return false if the list is empty
// consider the special case of deleting the only node in the list
}
//TODO: Add comments
bool LinkedList::deleteRear(T &OldNum) {
// TODO: Add code here
// consider if the list was empty and return false if the list is empty
// consider the special case of deleting the only node in the list
}
/* --- harder ones for test 2 and 3 -- */
/**
* @brief Delete a node at a given position from the list. The
* node at position pos is deleted and the value of the deleted node is returned in val.
* The valid range of pos is 1 to count. pos = 1 is the first node, and pos = count is the last node.
* @param pos: position of the node to be deleted
* @param val: it is set to the value of the node to be deleted
* @return true: if the node was deleted successfully
* @return false: if the node was not deleted successfully because the position was out of range
*/
bool LinkedList::deleteAt(int pos, T &val) {
//TODO: Add code here
// check if the pos is valid first, then move the ptr to the rigth positon
// consider the special case of deleting the first node and the last node
// Do not forget to set value.
}
/**
* @brief Insert a value at a specified position in the list. The valid pos is in the range of 1 to
count+1.
* The value will be inserted before the node at the specified position. if pos = 1, the value will be
inserted
* at the front of the list. if pos = count+1, the value will be inserted at the rear of the list.
* @param pos: position to insert the value at.
* @param val: value to insert.
* @return true: if the value was inserte.
Please help me to make a programming project I have to sue them today- (1).pdf
Please help me to make a programming project I have to sue them today. Please help me make a
UnsortedList and SortedList classes. The instructor give me The code of the List and AbstracList
Classes that 2 pages we do not modify them. Do not modify this pages!!! List.java import
java.util.Iterator; /** * Represents List interface. * * @author Varik Hoang * @version Sep 26,
2016 * @param is of any object type. */ public interface List { /** * The method returns the
current number of elements in the list. * * @return the current number of elements in the list
greater than or equal 0 */ public int getSize(); /** * The method returns whether the list is empty.
* * @return true if list is empty, false otherwise. */ public boolean isEmpty(); /** * The method
returns whether value is in the list. * * @param value the value is assigned * @return true if
value in the list, false otherwise. */ public boolean contains(Type value); /** * The method
inserts an element into the list. * * @param value the value is assigned */ public void insert(Type
value); /** * The method clears the list. */ public void clear(); /** * The method returns a string
representation of list contents. * * @return a string representation of list contents. * @see
Object#toString() */ @Override public String toString(); /** * /** * The method removes first
element occurrence from the list. * * @param value the value is assigned * @return the removed
value */ public Type remove(Type value); /** * The method returns the index of value. * *
@param value the value is assigned. * @return the index of value if in the list, -1 otherwise. */
public int getIndex(Type value); /** * The method removes value at the given index. * *
@param index the index must be in range of 0 and size * @return the removed value * @throws
IndexOutOfBoundsException if index less than 0 or index greater than * or equal size */ public
Type removeAtIndex(int index); /** * The method replaces the value at the given index with the
given value. * * @param index the index must be in range of 0 and size * @param value the
value is assigned * @throws IndexOutOfBoundsException if index less 0 or index greater than
size */ public void set(int index, Type value); /** * Returns the value at the given index in the
list. * * @param index the index must be in range of 0 and size * @throws
IndexOutOfBoundsException if index less than 0 or greater size * @return the value at the given
index in the list. */ public Type get(int index); /** * The method returns an iterator for this list. *
* @return an iterator for the list. */ public Iterator iterator(); } Do not modify this pages public
abstract class AbstractList implements List { /** * The reference to the last element */ protected
ListNode tail; /** * The size of the list */ protected int size; /** * The constructor that initiate the
tail and size references */ public AbstractList() { tail = null; size = 0; } @Override public int
getSize() { return size; } @Override public bool.
main.cpp#include TreeNode.h GIVEN void inorderTraversal(.pdf
main.cpp
#include "TreeNode.h"
//GIVEN
void inorderTraversal(TreeNode * root);
//TODO
TreeNode * search(TreeNode * node,int data);
//GIVEN
void insert(TreeNode * node,int data);
//GIVEN
bool isNull(TreeNode * node){
return node==nullptr;
}
int main() {
// create the root, gets set to null
TreeNode * root;
// create the roor and set the data of root to 5
root= new TreeNode(5);
//create two additional nodes with data values 10 and 3
// these will go to the right and left of root respectively
TreeNode * ten= new TreeNode(10);
TreeNode * three= new TreeNode(3);
//connect ten to the right of root (which has data 5)
root->setRight(ten);
//connect three to the left of root (which has data 5)
root->setLeft(three);
// note this can also be done as
//root.setRight(new TreeNode(10));
//root.setLeft(new TreeNode(3);)
// add two more nodes
//the first has data value 7. So to keep the tree in insorted order, it should get attached as the left
node of ten
// the second has data value 4. So to keep the tree in insorted order, it should get attached as the
right node of three
ten->addLeft(7);
three->addRight(4);
std::cout<<"**************************************\n";
std::cout<<"Printing the Inorder Traversal\n";
inorderTraversal(root);
std::cout<<"**************************************\n";
std::cout<<"Searching for Node \n";
TreeNode* result = search(root,4);
if (result!=nullptr){
std::cout<<"Found "<getData()<<"\n";
}
else
std::cout<<"Not Found "<<4<<"\n";
result = search(root,1);
if (result!=nullptr){
std::cout<<"Found "<getData()<<"\n";
}
else
std::cout<<"Not Found "<<1<<"\n";
std::cout<<"**************************************\n";
std::cout<<"Inserting 6\n";
insert(root,6);
std::cout<<"**************************************\n";
std::cout<<"Printing the Inorder Traversal\n";
inorderTraversal(root);
}
// uses recursion
void inorderTraversal(TreeNode * node){
// exit case
if (isNull(node)) return;
if (node->isLeaf()){
std::cout<<"Printing Leaf Node "<getData()<<"\n";
return;}
// reached a node with no left, so print the node and travel right
if (!isNull(node->getLeft()))
// if there is a left path, then travel further on that
inorderTraversal(node->getLeft());
std::cout<<"Printing Node "<getData()<<"\n";
// save and travel the right path of the current node being processed
inorderTraversal(node->getRight());
}
// uses recursion
//TODO
TreeNode * search(TreeNode * node, int data){
// if the node is null return the null ptr
//if this nodes data equals the search date return found
// if not, if the left tree exists and search data less than
//this nodes data return the result of recursive all to search with left pointer
// if no left tree, but right tree exists and search data greater than
//this nodes data return the result of recursive all to search with right pointer
// if both above conditions not true return null ptr
}
//uses recursion
void insert(TreeNode * node,int data){
if (node->getData()==data)
return;
else if(datagetData()){
if (!isNull(node->getLeft.
import java.util.Iterator; import java.util.NoSuchElementException; .pdf
import java.util.Iterator; import java.util.NoSuchElementException; /** * An implementation
of MyList with a linked list (a longer exercise would be to * implement the List interface as is
done in the class java.util.LinkedList: * the source of the LinkedList class is available from Sun.
Check it out). */ public class MyLinkedList implements MyList { // A private class to
represent a Node in the linked list private class Node { public E item;
public Node next; // a convenient constructor public Node(E o) {
this.item = o; this.next = null; } } // The start of the linked
list private Node head; // The last Node in the linked list private Node tail;
// Number of elements in the list private int size; /** * Creates an empty list (this
constructor is not necessary) */ public MyLinkedList() { } /** *
Returns the number of elements in this list. */ public int size() { return size;
} /** * Returns true if this list contains no elements. */ public boolean
isEmpty() { return size == 0; } /** * Appends the specified element to
the end of this list */ public boolean add(E o) { Node n = new Node(o);
// If this is the first element in the list if (head == null) { head = n;
} else { // If the list is not empty, use tail tail.next = n;
} // update tail tail = n; // update size size++;
return true; } /** * Empties this List */ public void clear() {
// update head, tail and size head = tail = null; size = 0; } /**
* Returns the element at the specified position in this list. */ public E get(int index) {
if (index < 0 || index >= size) { throw new
IndexOutOfBoundsException(\"index = \" + index); } // Find it
Node n = head; for (int i = 0; i < index; i++) { n = n.next; }
return n.item; } /** * Returns the index of the specified element (-1 if
there is no match) */ public int indexOf(Object o) { // If o is null
int index = 0; Node p = head; if (o == null) // look for a null element in the
list { while (p != null) { if (p.item == null) {
return index; } index++;
p = p.next; } } else // o is an object (use equals) {
while (p != null) { if (o.equals(p.item)) { return
index; } index++; p = p.next;
} } // if we get here, o is not in the list return -1; }
/** * Returns true if this list contains the specified element. */ public boolean
contains(Object o) { // easy with indexOf return indexOf(o) != -1; }
/** * Removes the element in the List at position index */ public boolean
remove(int index) { if (index < 0 || index >= size) { throw new
IndexOutOfBoundsException(\"index = \" + index); } // Find the
corresponding node Node prev = null, p = head; for (int i = 0; i < index; i++)
{ prev = p; p = p.next; } // Remove it
// Special case for the first node if (p == head) { head = head.next;
} else { prev.next = p.next; } // If the last node has been
removed, update tail if (p == tail) { tail = prev; } //
update size size--; return true; } /** * Removes the element
in the List at position index */ public boolean remove(Object o) { // easy
with indexOf and remove int index = i.
Dividing a linked list into two sublists of almost equal sizesa. A.pdf
Dividing a linked list into two sublists of almost equal sizes
a. Add the operation divideMid to the class linkedListType as follows:
Consider the following statements:
unorderedLinkedList myList;
unorderedLinkedList subList;
Suppose myList points to the list with elements 34 65 27 89 12 (in this order). The statement:
myList.divideMid(subList); divides myList into two sublists: myList points to the list with the
elements 34 65 27,
and subList points to the sublist with the elements 89 12.
b. Write the definition of the function template to implement the operation divideMid. Also,
write a program to test your function. The header files linkedList.h and unorderedLinkedList.h
are supplied. Your test program should produce output similar to this:
Turn in:
linkedList.h with modifications
Your test program.
(C++)
Required code is below:
#ifndef H_UnorderedLinkedList
#define H_UnorderedLinkedList
#include \"linkedList.h\"
using namespace std;
template
class unorderedLinkedList: public linkedListType
{
public:
bool search(const Type& searchItem) const;
//Function to determine whether searchItem is in the list.
//Postcondition: Returns true if searchItem is in the
// list, otherwise the value false is
// returned.
void insertFirst(const Type& newItem);
//Function to insert newItem at the beginning of the list.
//Postcondition: first points to the new list, newItem is
// inserted at the beginning of the list,
// last points to the last node in the
// list, and count is incremented by 1.
void insertLast(const Type& newItem);
//Function to insert newItem at the end of the list.
//Postcondition: first points to the new list, newItem
// is inserted at the end of the list,
// last points to the last node in the
// list, and count is incremented by 1.
void deleteNode(const Type& deleteItem);
//Function to delete deleteItem from the list.
//Postcondition: If found, the node containing
// deleteItem is deleted from the list.
// first points to the first node, last
// points to the last node of the updated
// list, and count is decremented by 1.
};
template
bool unorderedLinkedList::
search(const Type& searchItem) const
{
nodeType *current; //pointer to traverse the list
bool found = false;
current = this->first; //set current to point to the first
//node in the list
while (current != NULL && !found) //search the list
if (current->info == searchItem) //searchItem is found
found = true;
else
current = current->link; //make current point to
//the next node
return found;
}//end search
template
void unorderedLinkedList::insertFirst(const Type& newItem)
{
nodeType *newNode; //pointer to create the new node
newNode = new nodeType; //create the new node
newNode->info = newItem; //store the new item in the node
newNode->link = this->first; //insert newNode before first
this->first = newNode; //make first point to the
//actual first node
this->count++; //increment count
if (this->last == NULL) //if the list was empty, newNode is also
//the last node in the list
this->l.
Program to insert in a sorted list #includestdio.h#include.pdf
* Program to insert in a sorted list */
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* function to insert a new_node in a list. Note that this
function expects a pointer to head_ref as this can modify the
head of the input linked list (similar to push())*/
void sortedInsert(struct node** head_ref, struct node* new_node)
{
struct node* current;
/* Special case for the head end */
if (*head_ref == NULL || (*head_ref)->data >= new_node->data)
{
new_node->next = *head_ref;
*head_ref = new_node;
}
else
{
/* Locate the node before the point of insertion */
current = *head_ref;
while (current->next!=NULL &&
current->next->data < new_node->data)
{
current = current->next;
}
new_node->next = current->next;
current->next = new_node;
}
}
/* BELOW FUNCTIONS ARE JUST UTILITY TO TEST sortedInsert */
/* A utility function to create a new node */
struct node *newNode(int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
new_node->next = NULL;
return new_node;
}
/* Function to print linked list */
void printList(struct node *head)
{
struct node *temp = head;
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
/* Drier program to test count function*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
struct node *new_node = newNode(5);
sortedInsert(&head, new_node);
new_node = newNode(10);
sortedInsert(&head, new_node);
new_node = newNode(7);
sortedInsert(&head, new_node);
new_node = newNode(3);
sortedInsert(&head, new_node);
new_node = newNode(1);
sortedInsert(&head, new_node);
new_node = newNode(9);
sortedInsert(&head, new_node);
printf(\"\ Created Linked List\ \");
printList(head);
return 0;
}
public class Listnode {
//*** fields ***
private Object data;
private Listnode next;
//*** methods ***
// 2 constructors
public Listnode(Object d) {
this(d, null);
}
public Listnode(Object d, Listnode n) {
data = d;
next = n;
}
// access to fields
public Object getData() {
return data;
}
public Listnode getNext() {
return next;
}
// modify fields
public void setData(Object ob) {
data = ob;
}
public void setNext(Listnode n) {
next = n;
}
}
Thsi below program print out all the varibles in SLL
#include
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Given a reference (pointer to pointer) to the head
of a list and an int, push a new node on the front
of the list. */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref) = new_node;
}
/* Takes head pointer of the linked list and index
as arguments and return data at index*/
int GetNth(struct node* head, int index)
{
struct node* current = head;
int .
C Exam Help
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PROBLEM STATEMENTIn this assignment, you will complete DoubleEnde.pdf
PROBLEM STATEMENT:
In this assignment, you will complete DoubleEndedList.java that implements the ListInterface as
well as an interface called DoubleEndedInterface which represents the list's entries by using a
chain of nodes that has both a head reference and a tail reference. Be sure to read through the
code and understand the implementation.
WHAT IS PROVIDED:
- A driver class to test your code. You should not modify this file!
- A list interface (ListInterface.java)
- A double ended interface (DoubleEndedInterface.java)
- An incomplete DoubleEndedList class (DoubleEndedList.java)
WHAT YOU NEED TO DO:
4. Complete the DoubleEndedList class
4. Run the driver and make sure your output is exactly the same as mine (at the bottom of
Driver.java)
\} // end else numberofEntries--; else throw new IndexOut0fBoundsException("Illegal position
given to remove operation."); return result; // Return removed entry }//endreturnreve public T
replace(int givenPosition, T newEntry) \{ T replace(int givenPosition, T newEntry) \{ if
((givenPosition >=1)&& (givenPosition <= numberOfEntries)) \{ // Assertion: The list is not
empty Node desiredNode = getNodeAt (givenPosition); ToriginalEntry = desiredNode.getData();
desiredNode.setData(newEntry); return originalEntry; f // end if else throw new
IndexOut0fBoundsException("Illegal position given to replace operation."); replace if ((
givenPosition >=1)&& (givenPosition <= number0fEntries)) \{ // Assertion: The list is not
empty Node desiredNode = getNodeAt ( givenPosition); T originalEntry = desiredNode.
getData( ); desiredNode.setData(newEntry); return originalentry; \} // end if throw new
Index0ut0fBoundsException("Illegal position given to replace operation."); \} // end replace
public T getEntry(int givenPosition) \{ if ((givenPosition >=1) \&\& (givenPosition < =
number0fEntries ) ) \{ // Assertion: The list is not empty return getNodeAt (givenPosition).
getData(); else // end if throw new IndexOut0fBoundsException("Illegal position given to
getEntry operation."); \} // end getEntry public boolean contains ( T anEntry) \{ boolean found =
false; Node currentNode = firstNode; while (!found && (currentNode != null)) \{ if
(anEntry.equals (currentNode.getData())) else found = true; \} // end while currentNode =
currentNode. getNextNode () ; return found; \} // end contains public int getLength() \{ return
numberofEntries; \} // end getLength public boolean isEmpty() \{ return number0fEntries ==0;
\} // end isEmpty public T[] toArray() \{ // The cast is safe because the new array contains null
entries aSuppressWarnings ("unchecked") T[] result =(T[]) new 0bject [numberofEntries]; //
Unchecked cast int index =0; Node currentNode = firstNode; while ((index < numberOfEntries)
\&\& (currentNode != null)) \& result [ index ]= currentNode. getData () ; currentNode =
currentNode.getNextNode ( ); index++; 3 // end while return result; 3 // end toArray // Returns a
reference to the node at a given position. // Precondition: L.
How do you stop infinite loop Because I believe that it is making a.pdf
How do you stop infinite loop? Because I believe that it is making an infinite circular list.
c++ code:
Here is the list class:
#ifndef LIN_J_LIST
#define LIN_J_LIST
typedef unsigned int uint;
#include
#include
using namespace std;
/**
* a simplified generic singly linked list class to illustrate C++ concepts
* @author Jerry Lin
* @version 2/17/17
*/
template< typename Object >
class List
{
private:
/**
* A class to store data and provide a link to the next node in the list
*/
class Node
{
public:
/**
* The constructor
* @param data the data to be stored in this node
*/
explicit Node( const Object & data )
: data{ data }, next{ nullptr } {}
Object data;
Node * next;
};
public:
/**
* The constructor for an empty list
*/
List()
: size{ 0 }, first{ nullptr }, last{ nullptr } {}
/**
* the copy constructor-creates and copy the list
*/
List( List && rhs ) = delete;
List( const List & rhs )
{
count = 0;
size = 0;
if(rhs.size != 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first;
size++;
while(current->next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op.
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode->next;
size++;
}
}
// you document and implement this method
}
/**
* the operator= method-copies the list
*/
List & operator=( List && rhs) = delete;
List & operator=( const List & rhs )
{
count = 0;
size = 0;
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
if(rhs.size!= 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first; //create a temporary to store
size++;
while(current -> next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode -> next;
size++;
}
}
return *this;
// you document and implement this method
}
/**
* accessor
* @return count
*/
int get_count() const
{
return count;
}
/**
* The destructor that gets rid of everything that\'s in the list and
* resets it to empty. If the list is already empty, do nothing.
*/
~List()
{
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
}
/**
* Put a new element onto the beginning of the list
* @param item the data the new element will contain
*/
void push_front( const Object& item )
{
Node * new_node = new Node( item );//basic op.
if(is_empty())
{
last = new_node;
}
else
{
new_node->next = first;
}
first = new_node;
size++;
/* you complete the rest */
}
/**
* Remove the element that\'s at the front of the list. Causes an
* assertion error if the list is empty.
*/
void pop_front()
{
assert( !is_empty() );
Node * temp = first;
if( first == last )
{
first = last = nullptr;
}
else
{
first = first->next;
}
delete temp;
size--;
}
/**
* Accessor to return the da.
How do I fix it in LinkedList.javathis is what i didLabProgra.pdf
The document provides instructions for implementing iterator methods in a LinkedList class. It describes updating the default constructor to initialize the iterator field to null, and modifying removeFirst() and removeLast() methods to handle cases where the iterator is at the first or last node. It then lists 8 steps to implement iterator methods like positionIterator(), offEnd(), getIterator(), advanceIterator(), reverseIterator(), addIterator(), and removeIterator(). The main() method creates a linked list and calls the iterator methods to test their functionality.
Problem- Describe an algorithm for concatenating two singly linked lis.pdf
Problem: Describe an algorithm for concatenating two singly linked lists L and M, into a single
list L that contains all the nodes of L followed by all the nodes of M. Modify the
SinglyLinkedList class to contain the method:
public void concatenate(SinglyLinkedList other) { ... }
PLEASE PLEASE USE THE CODE BELOW..... THANK YOU
public class SinglyLinkedList<E> implements Cloneable {
//---------------- nested Node class ----------------
/**
* Node of a singly linked list, which stores a reference to its
* element and to the subsequent node in the list (or null if this
* is the last node).
*/
private static class Node<E> {
/** The element stored at this node */
private E element; // reference to the element stored at this node
/** A reference to the subsequent node in the list */
private Node<E> next; // reference to the subsequent node in the list
/**
* Creates a node with the given element and next node.
*
* @param e the element to be stored
* @param n reference to a node that should follow the new node
*/
public Node(E e, Node<E> n) {
element = e;
next = n;
}
// Accessor methods
/**
* Returns the element stored at the node.
* @return the element stored at the node
*/
public E getElement() { return element; }
/**
* Returns the node that follows this one (or null if no such node).
* @return the following node
*/
public Node<E> getNext() { return next; }
// Modifier methods
/**
* Sets the node's next reference to point to Node n.
* @param n the node that should follow this one
*/
public void setNext(Node<E> n) { next = n; }
} //----------- end of nested Node class -----------
// instance variables of the SinglyLinkedList
/** The head node of the list */
private Node<E> head = null; // head node of the list (or null if empty)
/** The last node of the list */
private Node<E> tail = null; // last node of the list (or null if empty)
/** Number of nodes in the list */
private int size = 0; // number of nodes in the list
/** Constructs an initially empty list. */
public SinglyLinkedList() { } // constructs an initially empty list
// access methods
/**
* Returns the number of elements in the linked list.
* @return number of elements in the linked list
*/
public int size() { return size; }
/**
* Tests whether the linked list is empty.
* @return true if the linked list is empty, false otherwise
*/
public boolean isEmpty() { return size == 0; }
/**
* Returns (but does not remove) the first element of the list
* @return element at the front of the list (or null if empty)
*/
public E first() { // returns (but does not remove) the first element
if (isEmpty()) return null;
return head.getElement();
}
/**
* Returns (but does not remove) the last element of the list.
* @return element at the end of the list (or null if empty)
*/
public E last() { // returns (but does not remove) the last element
if (isEmpty()) return null;
return tail.getElement();
}
// update methods
/**
* Adds an element to the front of the list.
* @param e the new element to add
*/
public vo.
I need help implementing a Stack with this java programming assignme.pdf
I need help implementing a Stack with this java programming assignment:
Given a doubly linked list (code provided below) implement a Stack. You must use the doubly
link list class and utilize it as an object in your implementation of the stack.
A Stack is a Last in First Out (LiFO) structure which translates to the processes of outputting the
last element which was inputted in the collection. The Stack is based on the process of putting
things on top of one another and taking the item on top (think of a stack of papers).
Operations to implement:
push (E): Add an element to the start of the sequence
pop: Remove an element from the start of the sequence
Peek: Return the first element of the sequence without removing it
atIndex(x): Return the element at the given index (x) Or throw an exception if it is out of bound
(if you can control the user input then do that instead)
Size: Return the size of the Stack
isEmpty: Boolean, returns true if the Stack is empty
Empty: Empty the Stack
Code Part 1:
public class DoublyLinkedList{
private DNode head;
private DNode tail;
private int size;
public DoublyLinkedList(){ // construct an empty list
this.tail = new DNode (null, null, this.head);
this.head = new DNode (null, this.tail, null);
this.size = 0;
}
public DoublyLinkedList(DNode next){ // constructs a list
// out of a single node
this.tail = new DNode (null, null, next);
this.head = new DNode (null, next, null);
next.changeNext(this.tail);
next.changePrev(this.head);
this.size = 1;
}
public DoublyLinkedList(Object [] objectArray){ // construct a list out of
// an array
this.tail = new DNode (null, null, this.head);
this.head = new DNode (null, this.tail, null);
DNode temp = this.head;
for (Object e : objectArray)
{
//Anonomus function
new DNode (e, temp.getNext(),temp).insertBetweenNodes(temp, temp.getNext());
temp = temp.getNext();
this.size += 1;
}
}
public void addToFrontofList(Object toAdd){ // Appends the begining
// of the list
DNode temp = new DNode (toAdd, this.head.getNext(), this.head);
this.head.getNext().changePrev(temp);
this.head.changeNext(temp);
this.size += 1;
}
public void addToendofList (Object toAdd) // appends the end of the list
// with a node
{
DNode temp = new DNode (toAdd, this.tail, this.tail.getPrev());
this.tail.getPrev().changeNext(temp);
this.tail.changePrev(temp);
this.size += 1;
}
public void insertAfterNode(DNode current, Object input)// Inserts a new
// a new node after
// current node
{
current.insertAfterNode(input);
this.size += 1;
}
public int getSize() // returns the size of the list
{
return this.size;
}
public String toString()
{
String result = \"\";
for (DNode temp = this.head.getNext();
temp.hasNext(); temp = temp.getNext())
{
result += temp.getValue();
result += \" -> \";
}
result += \"End of list\";
return result;
}
}
and code part2:
public class DNode{
private Object e; // place holder for the type of object the
//collection is storing
private DNode next; // reference to the next node in the sequence
// of.
Describe an algorithm for concatenating two singly linked lists L and.pdf
Dataset:
https://docs.google.com/spreadsheets/d/1NxuGt4LJ3ofi2PaWLWpAl90JmfqMKcGV/edit?usp=sharing&ouid=111109979069524025260&rtpof=true&sd=true
Q1) What is the average tenure of those customers of the telecom operator who are still with the
company as a customer and also those who have stopped using the services provided by the
company? (1 mark)
Here, churn = 'No' means that the customer is currently associated with the company, and churn
= 'Yes' means that the customer has stopped using the services provided by the company.
Q2)What is the monthly average revenue generated by the customers who are with the company
and also those who have left? (1 mark)
Q3) Find the percentage of churn and non-churn customers for each category of the following
services: (4 marks)
-MultipleLines
-PaperlessBilling
-OnlineSecurity
-OnlineBackup
-DeviceProtection
-TechSupport
-StreamingTV
-StreamingMovies.
Help please!!(Include your modified DList.java source code file in.pdf
Help please!!
(Include your modified DList.java source code file in your homework solution zip archive)
Using
whatever Java IDE you prefer, create a project and add DList.java and DListTest.java to it (these
files are provided
in the Week 6 Source zip archive). Modify DList to implement a method that removes all
occurrences of a specific
integer from the list. Here is the pseudocode:
Method removeAll(In: Integer pData) Returns Nothing
Define index variable i and initialize i to 0
While i < the size of this Dlist Do
If get(i) equals pData Then
remove(i)
Else
Increment i
End If
End While
End Method removeAll
Next, modify DListTest() to add test case 21 which tests that removeAll() works correctly.
WHat more do i need to provide to get help on this???
Solution
/* DListNode.java */
/**
* A DListNode is a node in a DList (doubly-linked list).
*/
class DListNode {
/**
* item references the item stored in the current node.
* prev references the previous node in the DList.
* next references the next node in the DList.
*
* DO NOT CHANGE THE FOLLOWING FIELD DECLARATIONS.
*/
public Object item;
protected DListNode prev;
protected DListNode next;
/**
* DListNode() constructor.
* @param i the item to store in the node.
* @param p the node previous to this node.
* @param n the node following this node.
*/
DListNode(Object i, DListNode p, DListNode n) {
item = i;
prev = p;
next = n;
}
}
/* DList.java */
/**
* A DList is a mutable doubly-linked list ADT. Its implementation is
* circularly-linked and employs a sentinel (dummy) node at the head
* of the list.
*
* DO NOT CHANGE ANY METHOD PROTOTYPES IN THIS FILE.
*/
class DList {
/**
* head references the sentinel node.
* size is the number of items in the list. (The sentinel node does not
* store an item.)
*
* DO NOT CHANGE THE FOLLOWING FIELD DECLARATIONS.
*/
protected DListNode head;
protected int size;
/* DList invariants:
* 1) head != null.
* 2) For any DListNode x in a DList, x.next != null.
* 3) For any DListNode x in a DList, x.prev != null.
* 4) For any DListNode x in a DList, if x.next == y, then y.prev == x.
* 5) For any DListNode x in a DList, if x.prev == y, then y.next == x.
* 6) size is the number of DListNodes, NOT COUNTING the sentinel,
* that can be accessed from the sentinel (head) by a sequence of
* \"next\" references.
*/
/**
* newNode() calls the DListNode constructor. Use this class to allocate
* new DListNodes rather than calling the DListNode constructor directly.
* That way, only this method needs to be overridden if a subclass of DList
* wants to use a different kind of node.
* @param item the item to store in the node.
* @param prev the node previous to this node.
* @param next the node following this node.
*/
protected DListNode newNode(Object item, DListNode prev, DListNode next) {
return new DListNode(item, prev, next);
}
/**
* DList() constructor for an empty DList.
*/
public DList() {
// Your solution here.
head = newNode(null, head, head);
head.prev = head;
head.next = head;
si.
How do I fix it in javaLinkedList.java Defines a doubl.pdf
How do I fix it in java?
LinkedList.java:
/**
* Defines a doubly-linked list class
* @author
* @author
*/
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
public T getFirst() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
if (iterator != null){
return iterator.data;
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return length;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return length == 0;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return iterator == null;
}
/**** MUTATORS ****/
public void addFirst(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
public void addLast(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIterator(T data) throws NullPointerException{
if(iterator != null){
Node newNode = new Node(data);
newNode.next = iterator.next;
iterator.next = newNode;
if (iterator == first){
first = newNode;
}
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/
public void removeFirst() throws NoSuchElementException {
if(is.
How do I fix it in LinkedList.javaLinkedList.java Define.pdf
How do I fix it in LinkedList.java?
LinkedList.java:
/**
* Defines a doubly-linked list class
* @author
* @author
*/
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
public T getFirst() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
if (iterator != null){
return iterator.data;
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return length;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return length == 0;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return iterator == null;
}
/**** MUTATORS ****/
public void addFirst(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
public void addLast(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIterator(T data) throws NullPointerException{
if(iterator != null){
Node newNode = new Node(data);
newNode.next = iterator.next;
iterator.next = newNode;
if (iterator == first){
first = newNode;
}
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/
public void removeFirst() throws NoSuchElementExcept.
hi i have to write a java program involving link lists. i have a pro.pdf
hi i have to write a java program involving link lists. i have a problem with the nodes, as it is
posting errors with the nodes.
please help me with this problem. thank you.
public class LinkLists {
/* only need to store a single pointer to the node at the head
* of the list.
* The pointer is null if the list is empty.
* Also record the size of the list.
*/
protected Node head;
/* invariant: size is the number of nodes in the list pointed to by head */
protected int size;
/* no-arguments default constructor creates an empty list */
public LinkLists() {
head = null; // start with an empty list
size = 0;
}
/* accessor method */
public int size() {
return size;
}
/* value to add to the end of the list
*/
public void add(T value) {
head = addAtEnd(head, value);
size++;
}
/* node of the list to which the value should be added
* value to add to the end of the list
*/
private Node addAtEnd(Node node, T value) {
if (node == null) { // special case
return new Node(value, null);
} else if (node.getNext() == null) { // other special case
node.setNext(new Node(value, null));
} else {
addAtEnd(node.getNext(), value);
}
return node;
}
/* iterative implementation of the same method
* value to add to the end of the list
*/
public void add2(T value) {
if (head == null) {
head = new Node(value, null);
} else {
Node node = head; // guaranteed not to be null initially
while (node.getNext() != null) {
node = node.getNext(); // guaranteed not to be null here
}
// now, node.getNext() is guaranteed to be null
// similar to the second special case in addAtEnd
node.setNext(new Node(value, null));
}
size++;
}
public void remove(int position) throws BadItemCountException {
if ((position < 1) || (position > size)) {
throw new
BadItemCountException(\"invalid position \" + position +
\", only 1..\" + size + \" available\");
}
if (position == 1) {
head = head.getNext();
} else {
Node node = head;
for (int i = 2; i < position; i++) {
node = node.getNext();
}
node.setNext(node.getNext().getNext());
}
size--; // one less item
}
public String toString() {
return toString(head);
}
private String toString(Node node) {
if (node == null) {
return \"\";
} else {
return node.getValue() + \"\ \" + toString(node.getNext());
}
}
public static void main(String[] args) {
/* create two empty lists, make sure they print out correctly */
LinkLists list1 = new LinkLists();
LinkLists list2 = new LinkLists();
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* insert some items, keep checking */
list1.add(\"hello\");
list1.add(\"world\");
list2.add(\"foo\");
list2.add(\"bar\");
list2.add(\"baz\");
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* remove an item at an invalid position */
boolean caught = false;
try {
list2.remove(4);
} catch .
An introduction and explanation of human factors and sociotechnical .pdf
An introduction and explanation of human factors and sociotechnical issues in medical
informatics
Solution
Healthcare is arguably the most complex of the complex,sociotechnical systems studied by the
human factors community .This complexity only looks to increase over the next five years as
massive changes in how care is delivered and re-imbursed are already underway.Not the least of
these changes is the not-so-subtle introduction of medical informatics and their corresponding
ripple effects on how the roles are designed,how work is co-ordinated,how primary and more
distant personnel are impacted and how power is allocated within the groups.Much of the
activity in medical informatics is conducted without the representation of human factors ,or even
without the knowledge of what human factors can contribute other than usable testing methods..
Astronomers were able to find a new planet in a far away solar system.pdf
Astronomers were able to find a new planet in a far away solar system. They are calling this
planet Nova, for the presence of abundant dements from a supernova. The people of planet Nova
speak in a strange language. Thankfully, a scientist was able to decode their language to English.
He found that they also use the same letters as English, but they swap each pair of consecutive
alphabets in English. For example, they swap A with B and Y with Z. Create a function that
reads a word in Nova and translates it into English.
Solution
def nova(st):
st = list(st)
for i in range(0,len(st)):
if st[i] == \'z\':
st[i] = \'a\'
elif st[i] == \'Z\':
st[i] = \'A\'
else:
st[i] = chr(ord(st[i])+1)
return \'\'.join(str(i) for i in st).
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Similar to In Java....The methods should work as add(Node) It has to take a .pdf
Sorted number list implementation with linked listsStep 1 Inspec.pdf
Sorted number list implementation with linked lists
Step 1: Inspect the Node.java file
Inspect the class declaration for a doubly-linked list node in Node.java. Access Node.java by
clicking on the orange arrow next to LabProgram.java at the top of the coding window. The
Node class has three fields:
a double data value,
a reference to the next node, and
a reference to the previous node.
Each field is protected. So code outside of the class must use the provided getter and setter
methods to get or set a field.
Node.java is read only, since no changes are required.
Step 2: Implement the insert() method
A class for a sorted, doubly-linked list is declared in SortedNumberList.java. Implement the
SortedNumberList class's insert() method. The method must create a new node with the
parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then insert(33.5) is called. A new
node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the remove() method
Implement the SortedNumberList class's remove() method. The method takes a parameter for the
number to be removed from the list. If the number does not exist in the list, the list is not
changed and false is returned. Otherwise, the first instance of the number is removed from the
list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
Given templates:
LabProgram.java
import java.util.Scanner;
import java.io.PrintWriter;
public class LabProgram {
// Prints the SortedNumberList's contents, in order from head to tail
public static void printList(SortedNumberList list) {
Node node = list.head;
while (null != node) {
System.out.print(node.getData() + " ");
node = node.getNext();
}
System.out.println();
}
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
String inputLine;
// Read the line of input numbers
inputLine = scnr.nextLine();
// Split on space character
String[] terms = inputLine.split(" ");
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list = new SortedNumberList();
for (Object term : terms) {
double number = Double.parseDouble(term.toString());
System.out.println("List after inserting " + number + ": ");
list.insert(number);
printList(list);
}
/*
// Read the input line with numbers to remove
inputLine = scnr.nextLine();
terms = inputLine.split(" ".
C Homework Help
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You can also call on +1 678 648 4277 for any assistance with C Homework.
--INSTRUCTION- --It helps to first create if-then-else structure to fi.pdf
This document contains code and comments for implementing a linked list data structure in C++. It includes function definitions and comments for common linked list operations like adding/removing nodes from the front/rear, checking if empty, getting length, converting to a string, and displaying all nodes. There are also TODO notes to fill in code for more advanced operations like deleting/inserting at a specified position, a copy constructor, and an assignment operator.
Need Help!! C++ #include-iostream- #include-linkedlist-h- using namesp.pdf
Need Help!! C++
#include<iostream>
#include"linkedlist.h"
using namespace std;
/**
* @brief Destructor to destroy all nodes and release memory
*/
LinkedList::~LinkedList() {
//TODO: Add code here. Make sure memory is released properly.
}
/**
* @brief Purpose: Checks if the list is empty
* @return true if the list is empty, false otherwise
*/
bool LinkedList::isEmpty() const {
// TODO: Add code here
return count == 0;
}
/**
* @brief Get the number of nodes in the list
* @return int The number of nodes in the list
*/
int LinkedList::length() const{
//TODO: Add code here
}
/**
* @brief Convert the list to a string
*
*/
string LinkedList::toString() {
string str = "[";
Node *ptr = front;
if (ptr != nullptr) {
// Head node is not preceded by separator
str += to_string(ptr->val);
ptr = ptr->next;
}
while (ptr != nullptr) {
str += ", " + to_string(ptr->val);
ptr = ptr->next;
}
str += "]";
return str;
}
/**
* @brief Displays the contents of the list
*/
void LinkedList::displayAll() {
cout << toString() << endl;
}
//TODO: Add comments
void LinkedList::addRear(T val) {
// TODO: Add code here
// consider the two cases of whether the list was empty
}
//TODO: Add comments
void LinkedList::addFront(T val) {
// TODO: Add code here
// consider the two cases of whether the list was empty
}
//TODO: Add comments
bool LinkedList::deleteFront(T &OldNum) {
// TODO: Add code here
// consider if the list was empty and return false if the list is empty
// consider the special case of deleting the only node in the list
}
//TODO: Add comments
bool LinkedList::deleteRear(T &OldNum) {
// TODO: Add code here
// consider if the list was empty and return false if the list is empty
// consider the special case of deleting the only node in the list
}
/* --- harder ones for test 2 and 3 -- */
/**
* @brief Delete a node at a given position from the list. The
* node at position pos is deleted and the value of the deleted node is returned in val.
* The valid range of pos is 1 to count. pos = 1 is the first node, and pos = count is the last node.
* @param pos: position of the node to be deleted
* @param val: it is set to the value of the node to be deleted
* @return true: if the node was deleted successfully
* @return false: if the node was not deleted successfully because the position was out of range
*/
bool LinkedList::deleteAt(int pos, T &val) {
//TODO: Add code here
// check if the pos is valid first, then move the ptr to the rigth positon
// consider the special case of deleting the first node and the last node
// Do not forget to set value.
}
/**
* @brief Insert a value at a specified position in the list. The valid pos is in the range of 1 to
count+1.
* The value will be inserted before the node at the specified position. if pos = 1, the value will be
inserted
* at the front of the list. if pos = count+1, the value will be inserted at the rear of the list.
* @param pos: position to insert the value at.
* @param val: value to insert.
* @return true: if the value was inserte.
Please help me to make a programming project I have to sue them today- (1).pdf
Please help me to make a programming project I have to sue them today. Please help me make a
UnsortedList and SortedList classes. The instructor give me The code of the List and AbstracList
Classes that 2 pages we do not modify them. Do not modify this pages!!! List.java import
java.util.Iterator; /** * Represents List interface. * * @author Varik Hoang * @version Sep 26,
2016 * @param is of any object type. */ public interface List { /** * The method returns the
current number of elements in the list. * * @return the current number of elements in the list
greater than or equal 0 */ public int getSize(); /** * The method returns whether the list is empty.
* * @return true if list is empty, false otherwise. */ public boolean isEmpty(); /** * The method
returns whether value is in the list. * * @param value the value is assigned * @return true if
value in the list, false otherwise. */ public boolean contains(Type value); /** * The method
inserts an element into the list. * * @param value the value is assigned */ public void insert(Type
value); /** * The method clears the list. */ public void clear(); /** * The method returns a string
representation of list contents. * * @return a string representation of list contents. * @see
Object#toString() */ @Override public String toString(); /** * /** * The method removes first
element occurrence from the list. * * @param value the value is assigned * @return the removed
value */ public Type remove(Type value); /** * The method returns the index of value. * *
@param value the value is assigned. * @return the index of value if in the list, -1 otherwise. */
public int getIndex(Type value); /** * The method removes value at the given index. * *
@param index the index must be in range of 0 and size * @return the removed value * @throws
IndexOutOfBoundsException if index less than 0 or index greater than * or equal size */ public
Type removeAtIndex(int index); /** * The method replaces the value at the given index with the
given value. * * @param index the index must be in range of 0 and size * @param value the
value is assigned * @throws IndexOutOfBoundsException if index less 0 or index greater than
size */ public void set(int index, Type value); /** * Returns the value at the given index in the
list. * * @param index the index must be in range of 0 and size * @throws
IndexOutOfBoundsException if index less than 0 or greater size * @return the value at the given
index in the list. */ public Type get(int index); /** * The method returns an iterator for this list. *
* @return an iterator for the list. */ public Iterator iterator(); } Do not modify this pages public
abstract class AbstractList implements List { /** * The reference to the last element */ protected
ListNode tail; /** * The size of the list */ protected int size; /** * The constructor that initiate the
tail and size references */ public AbstractList() { tail = null; size = 0; } @Override public int
getSize() { return size; } @Override public bool.
main.cpp#include TreeNode.h GIVEN void inorderTraversal(.pdf
main.cpp
#include "TreeNode.h"
//GIVEN
void inorderTraversal(TreeNode * root);
//TODO
TreeNode * search(TreeNode * node,int data);
//GIVEN
void insert(TreeNode * node,int data);
//GIVEN
bool isNull(TreeNode * node){
return node==nullptr;
}
int main() {
// create the root, gets set to null
TreeNode * root;
// create the roor and set the data of root to 5
root= new TreeNode(5);
//create two additional nodes with data values 10 and 3
// these will go to the right and left of root respectively
TreeNode * ten= new TreeNode(10);
TreeNode * three= new TreeNode(3);
//connect ten to the right of root (which has data 5)
root->setRight(ten);
//connect three to the left of root (which has data 5)
root->setLeft(three);
// note this can also be done as
//root.setRight(new TreeNode(10));
//root.setLeft(new TreeNode(3);)
// add two more nodes
//the first has data value 7. So to keep the tree in insorted order, it should get attached as the left
node of ten
// the second has data value 4. So to keep the tree in insorted order, it should get attached as the
right node of three
ten->addLeft(7);
three->addRight(4);
std::cout<<"**************************************\n";
std::cout<<"Printing the Inorder Traversal\n";
inorderTraversal(root);
std::cout<<"**************************************\n";
std::cout<<"Searching for Node \n";
TreeNode* result = search(root,4);
if (result!=nullptr){
std::cout<<"Found "<getData()<<"\n";
}
else
std::cout<<"Not Found "<<4<<"\n";
result = search(root,1);
if (result!=nullptr){
std::cout<<"Found "<getData()<<"\n";
}
else
std::cout<<"Not Found "<<1<<"\n";
std::cout<<"**************************************\n";
std::cout<<"Inserting 6\n";
insert(root,6);
std::cout<<"**************************************\n";
std::cout<<"Printing the Inorder Traversal\n";
inorderTraversal(root);
}
// uses recursion
void inorderTraversal(TreeNode * node){
// exit case
if (isNull(node)) return;
if (node->isLeaf()){
std::cout<<"Printing Leaf Node "<getData()<<"\n";
return;}
// reached a node with no left, so print the node and travel right
if (!isNull(node->getLeft()))
// if there is a left path, then travel further on that
inorderTraversal(node->getLeft());
std::cout<<"Printing Node "<getData()<<"\n";
// save and travel the right path of the current node being processed
inorderTraversal(node->getRight());
}
// uses recursion
//TODO
TreeNode * search(TreeNode * node, int data){
// if the node is null return the null ptr
//if this nodes data equals the search date return found
// if not, if the left tree exists and search data less than
//this nodes data return the result of recursive all to search with left pointer
// if no left tree, but right tree exists and search data greater than
//this nodes data return the result of recursive all to search with right pointer
// if both above conditions not true return null ptr
}
//uses recursion
void insert(TreeNode * node,int data){
if (node->getData()==data)
return;
else if(datagetData()){
if (!isNull(node->getLeft.
import java.util.Iterator; import java.util.NoSuchElementException; .pdf
import java.util.Iterator; import java.util.NoSuchElementException; /** * An implementation
of MyList with a linked list (a longer exercise would be to * implement the List interface as is
done in the class java.util.LinkedList: * the source of the LinkedList class is available from Sun.
Check it out). */ public class MyLinkedList implements MyList { // A private class to
represent a Node in the linked list private class Node { public E item;
public Node next; // a convenient constructor public Node(E o) {
this.item = o; this.next = null; } } // The start of the linked
list private Node head; // The last Node in the linked list private Node tail;
// Number of elements in the list private int size; /** * Creates an empty list (this
constructor is not necessary) */ public MyLinkedList() { } /** *
Returns the number of elements in this list. */ public int size() { return size;
} /** * Returns true if this list contains no elements. */ public boolean
isEmpty() { return size == 0; } /** * Appends the specified element to
the end of this list */ public boolean add(E o) { Node n = new Node(o);
// If this is the first element in the list if (head == null) { head = n;
} else { // If the list is not empty, use tail tail.next = n;
} // update tail tail = n; // update size size++;
return true; } /** * Empties this List */ public void clear() {
// update head, tail and size head = tail = null; size = 0; } /**
* Returns the element at the specified position in this list. */ public E get(int index) {
if (index < 0 || index >= size) { throw new
IndexOutOfBoundsException(\"index = \" + index); } // Find it
Node n = head; for (int i = 0; i < index; i++) { n = n.next; }
return n.item; } /** * Returns the index of the specified element (-1 if
there is no match) */ public int indexOf(Object o) { // If o is null
int index = 0; Node p = head; if (o == null) // look for a null element in the
list { while (p != null) { if (p.item == null) {
return index; } index++;
p = p.next; } } else // o is an object (use equals) {
while (p != null) { if (o.equals(p.item)) { return
index; } index++; p = p.next;
} } // if we get here, o is not in the list return -1; }
/** * Returns true if this list contains the specified element. */ public boolean
contains(Object o) { // easy with indexOf return indexOf(o) != -1; }
/** * Removes the element in the List at position index */ public boolean
remove(int index) { if (index < 0 || index >= size) { throw new
IndexOutOfBoundsException(\"index = \" + index); } // Find the
corresponding node Node prev = null, p = head; for (int i = 0; i < index; i++)
{ prev = p; p = p.next; } // Remove it
// Special case for the first node if (p == head) { head = head.next;
} else { prev.next = p.next; } // If the last node has been
removed, update tail if (p == tail) { tail = prev; } //
update size size--; return true; } /** * Removes the element
in the List at position index */ public boolean remove(Object o) { // easy
with indexOf and remove int index = i.
Dividing a linked list into two sublists of almost equal sizesa. A.pdf
Dividing a linked list into two sublists of almost equal sizes
a. Add the operation divideMid to the class linkedListType as follows:
Consider the following statements:
unorderedLinkedList myList;
unorderedLinkedList subList;
Suppose myList points to the list with elements 34 65 27 89 12 (in this order). The statement:
myList.divideMid(subList); divides myList into two sublists: myList points to the list with the
elements 34 65 27,
and subList points to the sublist with the elements 89 12.
b. Write the definition of the function template to implement the operation divideMid. Also,
write a program to test your function. The header files linkedList.h and unorderedLinkedList.h
are supplied. Your test program should produce output similar to this:
Turn in:
linkedList.h with modifications
Your test program.
(C++)
Required code is below:
#ifndef H_UnorderedLinkedList
#define H_UnorderedLinkedList
#include \"linkedList.h\"
using namespace std;
template
class unorderedLinkedList: public linkedListType
{
public:
bool search(const Type& searchItem) const;
//Function to determine whether searchItem is in the list.
//Postcondition: Returns true if searchItem is in the
// list, otherwise the value false is
// returned.
void insertFirst(const Type& newItem);
//Function to insert newItem at the beginning of the list.
//Postcondition: first points to the new list, newItem is
// inserted at the beginning of the list,
// last points to the last node in the
// list, and count is incremented by 1.
void insertLast(const Type& newItem);
//Function to insert newItem at the end of the list.
//Postcondition: first points to the new list, newItem
// is inserted at the end of the list,
// last points to the last node in the
// list, and count is incremented by 1.
void deleteNode(const Type& deleteItem);
//Function to delete deleteItem from the list.
//Postcondition: If found, the node containing
// deleteItem is deleted from the list.
// first points to the first node, last
// points to the last node of the updated
// list, and count is decremented by 1.
};
template
bool unorderedLinkedList::
search(const Type& searchItem) const
{
nodeType *current; //pointer to traverse the list
bool found = false;
current = this->first; //set current to point to the first
//node in the list
while (current != NULL && !found) //search the list
if (current->info == searchItem) //searchItem is found
found = true;
else
current = current->link; //make current point to
//the next node
return found;
}//end search
template
void unorderedLinkedList::insertFirst(const Type& newItem)
{
nodeType *newNode; //pointer to create the new node
newNode = new nodeType; //create the new node
newNode->info = newItem; //store the new item in the node
newNode->link = this->first; //insert newNode before first
this->first = newNode; //make first point to the
//actual first node
this->count++; //increment count
if (this->last == NULL) //if the list was empty, newNode is also
//the last node in the list
this->l.
Program to insert in a sorted list #includestdio.h#include.pdf
* Program to insert in a sorted list */
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* function to insert a new_node in a list. Note that this
function expects a pointer to head_ref as this can modify the
head of the input linked list (similar to push())*/
void sortedInsert(struct node** head_ref, struct node* new_node)
{
struct node* current;
/* Special case for the head end */
if (*head_ref == NULL || (*head_ref)->data >= new_node->data)
{
new_node->next = *head_ref;
*head_ref = new_node;
}
else
{
/* Locate the node before the point of insertion */
current = *head_ref;
while (current->next!=NULL &&
current->next->data < new_node->data)
{
current = current->next;
}
new_node->next = current->next;
current->next = new_node;
}
}
/* BELOW FUNCTIONS ARE JUST UTILITY TO TEST sortedInsert */
/* A utility function to create a new node */
struct node *newNode(int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
new_node->next = NULL;
return new_node;
}
/* Function to print linked list */
void printList(struct node *head)
{
struct node *temp = head;
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
/* Drier program to test count function*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
struct node *new_node = newNode(5);
sortedInsert(&head, new_node);
new_node = newNode(10);
sortedInsert(&head, new_node);
new_node = newNode(7);
sortedInsert(&head, new_node);
new_node = newNode(3);
sortedInsert(&head, new_node);
new_node = newNode(1);
sortedInsert(&head, new_node);
new_node = newNode(9);
sortedInsert(&head, new_node);
printf(\"\ Created Linked List\ \");
printList(head);
return 0;
}
public class Listnode {
//*** fields ***
private Object data;
private Listnode next;
//*** methods ***
// 2 constructors
public Listnode(Object d) {
this(d, null);
}
public Listnode(Object d, Listnode n) {
data = d;
next = n;
}
// access to fields
public Object getData() {
return data;
}
public Listnode getNext() {
return next;
}
// modify fields
public void setData(Object ob) {
data = ob;
}
public void setNext(Listnode n) {
next = n;
}
}
Thsi below program print out all the varibles in SLL
#include
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Given a reference (pointer to pointer) to the head
of a list and an int, push a new node on the front
of the list. */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref) = new_node;
}
/* Takes head pointer of the linked list and index
as arguments and return data at index*/
int GetNth(struct node* head, int index)
{
struct node* current = head;
int .
C Exam Help
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PROBLEM STATEMENTIn this assignment, you will complete DoubleEnde.pdf
PROBLEM STATEMENT:
In this assignment, you will complete DoubleEndedList.java that implements the ListInterface as
well as an interface called DoubleEndedInterface which represents the list's entries by using a
chain of nodes that has both a head reference and a tail reference. Be sure to read through the
code and understand the implementation.
WHAT IS PROVIDED:
- A driver class to test your code. You should not modify this file!
- A list interface (ListInterface.java)
- A double ended interface (DoubleEndedInterface.java)
- An incomplete DoubleEndedList class (DoubleEndedList.java)
WHAT YOU NEED TO DO:
4. Complete the DoubleEndedList class
4. Run the driver and make sure your output is exactly the same as mine (at the bottom of
Driver.java)
\} // end else numberofEntries--; else throw new IndexOut0fBoundsException("Illegal position
given to remove operation."); return result; // Return removed entry }//endreturnreve public T
replace(int givenPosition, T newEntry) \{ T replace(int givenPosition, T newEntry) \{ if
((givenPosition >=1)&& (givenPosition <= numberOfEntries)) \{ // Assertion: The list is not
empty Node desiredNode = getNodeAt (givenPosition); ToriginalEntry = desiredNode.getData();
desiredNode.setData(newEntry); return originalEntry; f // end if else throw new
IndexOut0fBoundsException("Illegal position given to replace operation."); replace if ((
givenPosition >=1)&& (givenPosition <= number0fEntries)) \{ // Assertion: The list is not
empty Node desiredNode = getNodeAt ( givenPosition); T originalEntry = desiredNode.
getData( ); desiredNode.setData(newEntry); return originalentry; \} // end if throw new
Index0ut0fBoundsException("Illegal position given to replace operation."); \} // end replace
public T getEntry(int givenPosition) \{ if ((givenPosition >=1) \&\& (givenPosition < =
number0fEntries ) ) \{ // Assertion: The list is not empty return getNodeAt (givenPosition).
getData(); else // end if throw new IndexOut0fBoundsException("Illegal position given to
getEntry operation."); \} // end getEntry public boolean contains ( T anEntry) \{ boolean found =
false; Node currentNode = firstNode; while (!found && (currentNode != null)) \{ if
(anEntry.equals (currentNode.getData())) else found = true; \} // end while currentNode =
currentNode. getNextNode () ; return found; \} // end contains public int getLength() \{ return
numberofEntries; \} // end getLength public boolean isEmpty() \{ return number0fEntries ==0;
\} // end isEmpty public T[] toArray() \{ // The cast is safe because the new array contains null
entries aSuppressWarnings ("unchecked") T[] result =(T[]) new 0bject [numberofEntries]; //
Unchecked cast int index =0; Node currentNode = firstNode; while ((index < numberOfEntries)
\&\& (currentNode != null)) \& result [ index ]= currentNode. getData () ; currentNode =
currentNode.getNextNode ( ); index++; 3 // end while return result; 3 // end toArray // Returns a
reference to the node at a given position. // Precondition: L.
How do you stop infinite loop Because I believe that it is making a.pdf
How do you stop infinite loop? Because I believe that it is making an infinite circular list.
c++ code:
Here is the list class:
#ifndef LIN_J_LIST
#define LIN_J_LIST
typedef unsigned int uint;
#include
#include
using namespace std;
/**
* a simplified generic singly linked list class to illustrate C++ concepts
* @author Jerry Lin
* @version 2/17/17
*/
template< typename Object >
class List
{
private:
/**
* A class to store data and provide a link to the next node in the list
*/
class Node
{
public:
/**
* The constructor
* @param data the data to be stored in this node
*/
explicit Node( const Object & data )
: data{ data }, next{ nullptr } {}
Object data;
Node * next;
};
public:
/**
* The constructor for an empty list
*/
List()
: size{ 0 }, first{ nullptr }, last{ nullptr } {}
/**
* the copy constructor-creates and copy the list
*/
List( List && rhs ) = delete;
List( const List & rhs )
{
count = 0;
size = 0;
if(rhs.size != 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first;
size++;
while(current->next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op.
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode->next;
size++;
}
}
// you document and implement this method
}
/**
* the operator= method-copies the list
*/
List & operator=( List && rhs) = delete;
List & operator=( const List & rhs )
{
count = 0;
size = 0;
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
if(rhs.size!= 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first; //create a temporary to store
size++;
while(current -> next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode -> next;
size++;
}
}
return *this;
// you document and implement this method
}
/**
* accessor
* @return count
*/
int get_count() const
{
return count;
}
/**
* The destructor that gets rid of everything that\'s in the list and
* resets it to empty. If the list is already empty, do nothing.
*/
~List()
{
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
}
/**
* Put a new element onto the beginning of the list
* @param item the data the new element will contain
*/
void push_front( const Object& item )
{
Node * new_node = new Node( item );//basic op.
if(is_empty())
{
last = new_node;
}
else
{
new_node->next = first;
}
first = new_node;
size++;
/* you complete the rest */
}
/**
* Remove the element that\'s at the front of the list. Causes an
* assertion error if the list is empty.
*/
void pop_front()
{
assert( !is_empty() );
Node * temp = first;
if( first == last )
{
first = last = nullptr;
}
else
{
first = first->next;
}
delete temp;
size--;
}
/**
* Accessor to return the da.
How do I fix it in LinkedList.javathis is what i didLabProgra.pdf
The document provides instructions for implementing iterator methods in a LinkedList class. It describes updating the default constructor to initialize the iterator field to null, and modifying removeFirst() and removeLast() methods to handle cases where the iterator is at the first or last node. It then lists 8 steps to implement iterator methods like positionIterator(), offEnd(), getIterator(), advanceIterator(), reverseIterator(), addIterator(), and removeIterator(). The main() method creates a linked list and calls the iterator methods to test their functionality.
Problem- Describe an algorithm for concatenating two singly linked lis.pdf
Problem: Describe an algorithm for concatenating two singly linked lists L and M, into a single
list L that contains all the nodes of L followed by all the nodes of M. Modify the
SinglyLinkedList class to contain the method:
public void concatenate(SinglyLinkedList other) { ... }
PLEASE PLEASE USE THE CODE BELOW..... THANK YOU
public class SinglyLinkedList<E> implements Cloneable {
//---------------- nested Node class ----------------
/**
* Node of a singly linked list, which stores a reference to its
* element and to the subsequent node in the list (or null if this
* is the last node).
*/
private static class Node<E> {
/** The element stored at this node */
private E element; // reference to the element stored at this node
/** A reference to the subsequent node in the list */
private Node<E> next; // reference to the subsequent node in the list
/**
* Creates a node with the given element and next node.
*
* @param e the element to be stored
* @param n reference to a node that should follow the new node
*/
public Node(E e, Node<E> n) {
element = e;
next = n;
}
// Accessor methods
/**
* Returns the element stored at the node.
* @return the element stored at the node
*/
public E getElement() { return element; }
/**
* Returns the node that follows this one (or null if no such node).
* @return the following node
*/
public Node<E> getNext() { return next; }
// Modifier methods
/**
* Sets the node's next reference to point to Node n.
* @param n the node that should follow this one
*/
public void setNext(Node<E> n) { next = n; }
} //----------- end of nested Node class -----------
// instance variables of the SinglyLinkedList
/** The head node of the list */
private Node<E> head = null; // head node of the list (or null if empty)
/** The last node of the list */
private Node<E> tail = null; // last node of the list (or null if empty)
/** Number of nodes in the list */
private int size = 0; // number of nodes in the list
/** Constructs an initially empty list. */
public SinglyLinkedList() { } // constructs an initially empty list
// access methods
/**
* Returns the number of elements in the linked list.
* @return number of elements in the linked list
*/
public int size() { return size; }
/**
* Tests whether the linked list is empty.
* @return true if the linked list is empty, false otherwise
*/
public boolean isEmpty() { return size == 0; }
/**
* Returns (but does not remove) the first element of the list
* @return element at the front of the list (or null if empty)
*/
public E first() { // returns (but does not remove) the first element
if (isEmpty()) return null;
return head.getElement();
}
/**
* Returns (but does not remove) the last element of the list.
* @return element at the end of the list (or null if empty)
*/
public E last() { // returns (but does not remove) the last element
if (isEmpty()) return null;
return tail.getElement();
}
// update methods
/**
* Adds an element to the front of the list.
* @param e the new element to add
*/
public vo.
I need help implementing a Stack with this java programming assignme.pdf
I need help implementing a Stack with this java programming assignment:
Given a doubly linked list (code provided below) implement a Stack. You must use the doubly
link list class and utilize it as an object in your implementation of the stack.
A Stack is a Last in First Out (LiFO) structure which translates to the processes of outputting the
last element which was inputted in the collection. The Stack is based on the process of putting
things on top of one another and taking the item on top (think of a stack of papers).
Operations to implement:
push (E): Add an element to the start of the sequence
pop: Remove an element from the start of the sequence
Peek: Return the first element of the sequence without removing it
atIndex(x): Return the element at the given index (x) Or throw an exception if it is out of bound
(if you can control the user input then do that instead)
Size: Return the size of the Stack
isEmpty: Boolean, returns true if the Stack is empty
Empty: Empty the Stack
Code Part 1:
public class DoublyLinkedList{
private DNode head;
private DNode tail;
private int size;
public DoublyLinkedList(){ // construct an empty list
this.tail = new DNode (null, null, this.head);
this.head = new DNode (null, this.tail, null);
this.size = 0;
}
public DoublyLinkedList(DNode next){ // constructs a list
// out of a single node
this.tail = new DNode (null, null, next);
this.head = new DNode (null, next, null);
next.changeNext(this.tail);
next.changePrev(this.head);
this.size = 1;
}
public DoublyLinkedList(Object [] objectArray){ // construct a list out of
// an array
this.tail = new DNode (null, null, this.head);
this.head = new DNode (null, this.tail, null);
DNode temp = this.head;
for (Object e : objectArray)
{
//Anonomus function
new DNode (e, temp.getNext(),temp).insertBetweenNodes(temp, temp.getNext());
temp = temp.getNext();
this.size += 1;
}
}
public void addToFrontofList(Object toAdd){ // Appends the begining
// of the list
DNode temp = new DNode (toAdd, this.head.getNext(), this.head);
this.head.getNext().changePrev(temp);
this.head.changeNext(temp);
this.size += 1;
}
public void addToendofList (Object toAdd) // appends the end of the list
// with a node
{
DNode temp = new DNode (toAdd, this.tail, this.tail.getPrev());
this.tail.getPrev().changeNext(temp);
this.tail.changePrev(temp);
this.size += 1;
}
public void insertAfterNode(DNode current, Object input)// Inserts a new
// a new node after
// current node
{
current.insertAfterNode(input);
this.size += 1;
}
public int getSize() // returns the size of the list
{
return this.size;
}
public String toString()
{
String result = \"\";
for (DNode temp = this.head.getNext();
temp.hasNext(); temp = temp.getNext())
{
result += temp.getValue();
result += \" -> \";
}
result += \"End of list\";
return result;
}
}
and code part2:
public class DNode{
private Object e; // place holder for the type of object the
//collection is storing
private DNode next; // reference to the next node in the sequence
// of.
Describe an algorithm for concatenating two singly linked lists L and.pdf
Dataset:
https://docs.google.com/spreadsheets/d/1NxuGt4LJ3ofi2PaWLWpAl90JmfqMKcGV/edit?usp=sharing&ouid=111109979069524025260&rtpof=true&sd=true
Q1) What is the average tenure of those customers of the telecom operator who are still with the
company as a customer and also those who have stopped using the services provided by the
company? (1 mark)
Here, churn = 'No' means that the customer is currently associated with the company, and churn
= 'Yes' means that the customer has stopped using the services provided by the company.
Q2)What is the monthly average revenue generated by the customers who are with the company
and also those who have left? (1 mark)
Q3) Find the percentage of churn and non-churn customers for each category of the following
services: (4 marks)
-MultipleLines
-PaperlessBilling
-OnlineSecurity
-OnlineBackup
-DeviceProtection
-TechSupport
-StreamingTV
-StreamingMovies.
Help please!!(Include your modified DList.java source code file in.pdf
Help please!!
(Include your modified DList.java source code file in your homework solution zip archive)
Using
whatever Java IDE you prefer, create a project and add DList.java and DListTest.java to it (these
files are provided
in the Week 6 Source zip archive). Modify DList to implement a method that removes all
occurrences of a specific
integer from the list. Here is the pseudocode:
Method removeAll(In: Integer pData) Returns Nothing
Define index variable i and initialize i to 0
While i < the size of this Dlist Do
If get(i) equals pData Then
remove(i)
Else
Increment i
End If
End While
End Method removeAll
Next, modify DListTest() to add test case 21 which tests that removeAll() works correctly.
WHat more do i need to provide to get help on this???
Solution
/* DListNode.java */
/**
* A DListNode is a node in a DList (doubly-linked list).
*/
class DListNode {
/**
* item references the item stored in the current node.
* prev references the previous node in the DList.
* next references the next node in the DList.
*
* DO NOT CHANGE THE FOLLOWING FIELD DECLARATIONS.
*/
public Object item;
protected DListNode prev;
protected DListNode next;
/**
* DListNode() constructor.
* @param i the item to store in the node.
* @param p the node previous to this node.
* @param n the node following this node.
*/
DListNode(Object i, DListNode p, DListNode n) {
item = i;
prev = p;
next = n;
}
}
/* DList.java */
/**
* A DList is a mutable doubly-linked list ADT. Its implementation is
* circularly-linked and employs a sentinel (dummy) node at the head
* of the list.
*
* DO NOT CHANGE ANY METHOD PROTOTYPES IN THIS FILE.
*/
class DList {
/**
* head references the sentinel node.
* size is the number of items in the list. (The sentinel node does not
* store an item.)
*
* DO NOT CHANGE THE FOLLOWING FIELD DECLARATIONS.
*/
protected DListNode head;
protected int size;
/* DList invariants:
* 1) head != null.
* 2) For any DListNode x in a DList, x.next != null.
* 3) For any DListNode x in a DList, x.prev != null.
* 4) For any DListNode x in a DList, if x.next == y, then y.prev == x.
* 5) For any DListNode x in a DList, if x.prev == y, then y.next == x.
* 6) size is the number of DListNodes, NOT COUNTING the sentinel,
* that can be accessed from the sentinel (head) by a sequence of
* \"next\" references.
*/
/**
* newNode() calls the DListNode constructor. Use this class to allocate
* new DListNodes rather than calling the DListNode constructor directly.
* That way, only this method needs to be overridden if a subclass of DList
* wants to use a different kind of node.
* @param item the item to store in the node.
* @param prev the node previous to this node.
* @param next the node following this node.
*/
protected DListNode newNode(Object item, DListNode prev, DListNode next) {
return new DListNode(item, prev, next);
}
/**
* DList() constructor for an empty DList.
*/
public DList() {
// Your solution here.
head = newNode(null, head, head);
head.prev = head;
head.next = head;
si.
How do I fix it in javaLinkedList.java Defines a doubl.pdf
How do I fix it in java?
LinkedList.java:
/**
* Defines a doubly-linked list class
* @author
* @author
*/
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
public T getFirst() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
if (iterator != null){
return iterator.data;
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return length;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return length == 0;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return iterator == null;
}
/**** MUTATORS ****/
public void addFirst(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
public void addLast(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIterator(T data) throws NullPointerException{
if(iterator != null){
Node newNode = new Node(data);
newNode.next = iterator.next;
iterator.next = newNode;
if (iterator == first){
first = newNode;
}
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/
public void removeFirst() throws NoSuchElementException {
if(is.
How do I fix it in LinkedList.javaLinkedList.java Define.pdf
How do I fix it in LinkedList.java?
LinkedList.java:
/**
* Defines a doubly-linked list class
* @author
* @author
*/
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
public T getFirst() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
if (iterator != null){
return iterator.data;
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return length;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return length == 0;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return iterator == null;
}
/**** MUTATORS ****/
public void addFirst(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
public void addLast(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIterator(T data) throws NullPointerException{
if(iterator != null){
Node newNode = new Node(data);
newNode.next = iterator.next;
iterator.next = newNode;
if (iterator == first){
first = newNode;
}
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/
public void removeFirst() throws NoSuchElementExcept.
hi i have to write a java program involving link lists. i have a pro.pdf
hi i have to write a java program involving link lists. i have a problem with the nodes, as it is
posting errors with the nodes.
please help me with this problem. thank you.
public class LinkLists {
/* only need to store a single pointer to the node at the head
* of the list.
* The pointer is null if the list is empty.
* Also record the size of the list.
*/
protected Node head;
/* invariant: size is the number of nodes in the list pointed to by head */
protected int size;
/* no-arguments default constructor creates an empty list */
public LinkLists() {
head = null; // start with an empty list
size = 0;
}
/* accessor method */
public int size() {
return size;
}
/* value to add to the end of the list
*/
public void add(T value) {
head = addAtEnd(head, value);
size++;
}
/* node of the list to which the value should be added
* value to add to the end of the list
*/
private Node addAtEnd(Node node, T value) {
if (node == null) { // special case
return new Node(value, null);
} else if (node.getNext() == null) { // other special case
node.setNext(new Node(value, null));
} else {
addAtEnd(node.getNext(), value);
}
return node;
}
/* iterative implementation of the same method
* value to add to the end of the list
*/
public void add2(T value) {
if (head == null) {
head = new Node(value, null);
} else {
Node node = head; // guaranteed not to be null initially
while (node.getNext() != null) {
node = node.getNext(); // guaranteed not to be null here
}
// now, node.getNext() is guaranteed to be null
// similar to the second special case in addAtEnd
node.setNext(new Node(value, null));
}
size++;
}
public void remove(int position) throws BadItemCountException {
if ((position < 1) || (position > size)) {
throw new
BadItemCountException(\"invalid position \" + position +
\", only 1..\" + size + \" available\");
}
if (position == 1) {
head = head.getNext();
} else {
Node node = head;
for (int i = 2; i < position; i++) {
node = node.getNext();
}
node.setNext(node.getNext().getNext());
}
size--; // one less item
}
public String toString() {
return toString(head);
}
private String toString(Node node) {
if (node == null) {
return \"\";
} else {
return node.getValue() + \"\ \" + toString(node.getNext());
}
}
public static void main(String[] args) {
/* create two empty lists, make sure they print out correctly */
LinkLists list1 = new LinkLists();
LinkLists list2 = new LinkLists();
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* insert some items, keep checking */
list1.add(\"hello\");
list1.add(\"world\");
list2.add(\"foo\");
list2.add(\"bar\");
list2.add(\"baz\");
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* remove an item at an invalid position */
boolean caught = false;
try {
list2.remove(4);
} catch .
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hi i have to write a java program involving link lists. i have a pro.pdf
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An introduction and explanation of human factors and sociotechnical .pdf
An introduction and explanation of human factors and sociotechnical issues in medical
informatics
Solution
Healthcare is arguably the most complex of the complex,sociotechnical systems studied by the
human factors community .This complexity only looks to increase over the next five years as
massive changes in how care is delivered and re-imbursed are already underway.Not the least of
these changes is the not-so-subtle introduction of medical informatics and their corresponding
ripple effects on how the roles are designed,how work is co-ordinated,how primary and more
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Astronomers were able to find a new planet in a far away solar system.pdf
Astronomers were able to find a new planet in a far away solar system. They are calling this
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speak in a strange language. Thankfully, a scientist was able to decode their language to English.
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reads a word in Nova and translates it into English.
Solution
def nova(st):
st = list(st)
for i in range(0,len(st)):
if st[i] == \'z\':
st[i] = \'a\'
elif st[i] == \'Z\':
st[i] = \'A\'
else:
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5. If we found AB+ blood at a crime scene and we knew one of our 5 suspects had a partial
Genotype that was determined to be IAI B CcEe would this be enough evidence to make this
suspect now a lead suspect. Why or Why not? Use Punnett squares to make your case. What
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6. A homicidal maniac has a genotype of IB I B Ccddeehhsese. At this murderer’s most recent
crime scene we find the murder’s baseball cap without blood, a pair of stained underwear no
blood, no fingerprints, no fibers, no hairs. Based on these items, do we have any possible
chemical, or immunological or other analyses we can perform that will identify the murderer as it
relates to the genotypic info we have on him or her. If so how would you go about doing those
studies
Solution
5. ANS:
No, At first the D antigen additional test would need to be performed. It is because AB+ is the
most common blood group and the the perp would have to be either Dd or DD (Rh+ve). we
could only really use the evidence to exclude suspects.
6. ANS:
In this case the blood strains are not there. Genetic material on it and use that to identify the
genotype is the best way to detects suspect. So genotyping performing will identify the murderer.
Genotype is used to determine the alleles that an individual possesses. Genotyping test is used
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All of the following individuals are U.S. residents: Kelly (27), her daughter Sydnee (4), and
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All of the following individuals are U.S. residents: Kelly (27), her daughter Sydnee (4), and
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All of the following individuals are U.S. residents: Kelly (27), her daughter Sydnee (4), and
Kelly\'s mother, June (50). All three lived together until the end of March, when Kelly moved
out. Then, in November, Kelly married Austin (29), and Sydnee moved in with Kelly and Austin,
who are filing a joint return. Sydnee does not pay over half the cost of her own support. If both
households try to claim Sydnee, who is entitled to do so?
All of the following individuals are U.S. residents: Kelly (27), her daughter Sydnee (4), and
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out. Then, in November, Kelly married Austin (29), and Sydnee moved in with Kelly and Austin,
who are filing a joint return. Sydnee does not pay over half the cost of her own support. If both
households try to claim Sydnee, who is entitled to do so?
Solution
According to the law passes in April,\"Parent paying child support
Sydnee is entitled to do so.
Blossom Company had these transactions during the current period..pdf
Blossom Company had these transactions during the current period.
Nov. 28June 12Issued 78,000 shares of $1 par value common stock for cash of $292,500.July
11Issued 2,500 shares of $100 par value preferred stock for cash at $104 per share.
Nov. 28Purchased 1,000 shares of treasury stock for $7,100. Prepare a tabular summary to record
the Blossom Company transactions. (Ifa transaction causes a decrease in Assets, Liabilities or
Stockholders\' Equity, place a negative sign (or parentheses) in front of the amount entered for
the particular Asset, Liability or Equity item that was reduced.) Assets Liabilities Stockholders\'
Equity Paid-in-Capital Retained Earnings Cash +Common Stock+ PIC in Excess of Pa +Pref.
Stock + + Revenue ExpenseDividend Com. Pref June 22 July 11 Nov. 28
Solution
Cash Liabilities Common stock PIC in excess of par Com. Pref. stock PIC in excess of par
Pref. Treasury stock Revenue Expenses Dividend 22-Jun 292500 78000 214500 11-Jul
260000 250000 10000 28-Nov -7100 -7100.
Using the case study below, develop a written report of your market .pdf
Using the case study below, develop a written report of your market analysis. Include a visual
diagram of your overall market analysis use of strategic thinking maps (see diagram in the
Module) as a tool to assist with the different facets of the strategic planning process.
The map is to be used as a supplement for your written market analysis. The market analysis
produced will be used in the final submission of your Capstone Project.
Your well-written market analysis should meet the following requirements:
Be 3-4 pages in length, not including the cover, abstract (optional), or reference pages.
Utilize headings to organize the content.
Include the strategic thinking map in addition to/or as a part of the 3-4 pages of content.
Include a minimum of four references with associated in-text citations.
The circumstances in Pocahontas County resonate in many rural communities across the country:
• A depressed local economy
• Substantial barriers to health access
• Difficulty in attracting health professionals.
Portrait of Pocahontas County
Pocahontas County is located in the southeast region of West Virginia. The county has a total of
942 square miles and is the site of the head waters for eight rivers: Cherry River, Cranberry
River, Elk River, Ganley River, Greenbriar River, Tygart Valley River, Williams River, and
Shaver Fork of the Cheat River. Pocahontas County consists of the following towns: Arborale,
Bartow, Buckeye, Cass, Dunmore, Durbin, Greenbank, Hillsboro, Marlington, and Slatyfork.
As of the 2010 Census there are 9,131 people residing in Pocahontas County. The racial makeup
is 98% Caucasian, .78% African American, .43% Hispanic, .14% Asian, and .07% Native
American. The median income for a household within the county is $26,401.
Access to Health Services
Pocahontas County has a shortage of healthcare providers. There is one hospital, Pocahontas
Memorial Hospital, and one nursing home, Pocahontas Center. The ratio for dentists is 8,851 to
1. The ratio for primary care physicians is 8508 to 1 (County Health Roadmaps & Rankings,
n.d.). The county’s physician-to-population ratio is significantly higher than the Unites States
overall ratio.
Pocahontas Memorial Hospital is a 25-bed, level-4 trauma center. A rural health clinic is located
within the hospital. The health clinic offers laboratory services, immunizations, disease
management, and monthly specialty clinics (cardiology, podiatry, and nephrology).
For more information about Pocahontas Memorial Hospital, visit the following website:
http://www.pmhwv.org/
Solution
Health care Limitations
Executive summary
The health care industry which is also known as the health economy or the medical industry is a
broad industry which specializes in the delivery of services regarding treatment of diseases,
conducting diagnostic services and therapies to identify various diseases so at to understand the
kind of treatment to be subjected to such diseases (World Health Organization. (2002). the
industr.
Which of the following is NOT a characteristic of a plasmid used as .pdf
Which of the following is NOT a characteristic of a plasmid used as a cloning vector?
A. contains a selection marker.
B. contains an origin of replication.
C. has a site for inserting foreign DNA.
D. integrates into the host chromosome.
E. has lacZ gene at the insertion site
Solution
D. integrates into the host chromosome.
a vector is a DNA molecule that is used as a vehivle for the introduction of foreign genetic
material in the cell.Most commonly used vectors are plasmids,cosnids,viral vectors.Some
features that are common to all vectors are origin of replication,multicloning site and a selectable
marker system.A vector replicates autonomously irrespective of the replication of host DNA.A
vector does not integrate into the host chromosome..
What is the evolutionary significance of the amniotic egg Solut.pdf
What is the evolutionary significance of the amniotic egg?
Solution
The fluid in the sac keeps the embryo moist. Birds, reptiles, and mammals have amniotic eggs.
Because amphibian eggs don\'t have an amnion, the eggs would dry out if they were laid on the
land, so amphibians lay their eggs in water. The larvae of most amphibians have gills and look
like fish when they are born..
What is the role of HTTP What types of objects are transmitted in H.pdf
What is the role of HTTP? What types of objects are transmitted in HTTP? Is HTML part of the
HTTP specification?
Solution
Hyper Text Transfer Protocol defines a set of rules that 2 entities namely Client and Server need
to follow while communicating with each other. It is a application layer protocol. This protocol
is based on Client and Server. Client is someone who needs something from web while server is
something who needs to listen to what Client wants and then need to send appropriate response.
Role of HTTP :
1. It allows Client/User to send request for any content that is available in web Server.
2. It provides authentication mechanisms like basic access authentication and digest access
authentication .
3. It allows the seamless transmission of Hyper Text from Server to Client and vice versa.
4. It allows persistent connections as well where a connection could be reused for more than one
request.
Objects Transmitted-
1. Request message - It is a command which Client sends to server which determines the content
wants to access.
Format - GET HTTP version
Example- GET /index.html/hello.jpg HTTP/1.1
2. Response Message - The server send a response to client request if the requested content is
available with it.
Format -
a) A status line which includes the status code and reason message (e.g., HTTP/1.1 200 OK,
which indicates that the client\'s request succeeded).
b) Response header fields (e.g., Content-Type: text/html).
c) An optional message body.
Example-
No, HTML is not a part of HTTP Specification..
What is the difference between a hash in perl and a hashtable in Jav.pdf
What is the difference between a hash in perl and a hashtable in Java? What are some concrete
examples?
Solution
There are lot of differece between hash in perl and hashtable in java
concrete Examples:
1) Insertion is done using a put method in java. It is done directly in perl
In Java: data.put(\'John Paul\',45)
In Perl; $data{\'John Paul\'} = 45;
2) In Java We have to specify datatypes of key and value before hand while defing the hashtable
variable. It is not necessary in perl..
What are the specific linkages among immune surveillance, clonal sel.pdf
What are the specific linkages among immune surveillance, clonal selection, and lymph nodes?
Solution
Immune Surveillance - A hypothesis that the immune system perceives and pulverizes tumor
cells that are continually emerging amid the life of the person. A body component by which early
growths are recognized as being strange and are assaulted and typically pulverised. Immune
Surveillance is a process in which a T cell-intervened handle without which tumor would be
much ordinary.
The immune sytem can distinguish and crush rising cancer cells since it perceives strange
antigens on the cell surface as \'foreign substance\' or outsider. Since outside substances are
typically risky to the body, the immune system is customised to demolish them. This consistent
checking of the body for little tumors is immune surveillance. The immune surveillance of living
body is known to work in the dismissal of tumor cells in people with inherited nonpolyposis
colon growth, likewise called Lynch disorder. Those people acquire a broken DNA confound
repair framework and as an outcome deliver numerous mutant proteins. At the point when such
mutant proteins show up on the surface of tumor cells, they are perceived as foriegn and rejected.
Tumors that do rise are those that have figured out how to sidestep the body\'s immune system.
Lymph nodes are Bean Shaped and encapsulated antigen gathering tissues that channel lymph
and permit lymphocytes to test antigens gained from skin, GI tract and respiratory tract
- deliberately situated all through body, bolstered by reticular system of follicular DCs and
macrophages
- lymphocytes enter from blood crosswise over high endothelial venules and from the
interconnected lymphatic vessels; B cells relocate to the cortex and immune system
microorganisms move to paracortical area; plasma move to medulla and emit counter acting
agent
- DCs with antigen enter from lymphatic vessel; T cells and DCs reach each other the T cell tests
the antigens in setting of the MHC on the DC; enacted T cells leaves lymph hubs and enter the
blood to site of contamination.
Clonal Selection - Clonal selecction is a hypothesis clarifying how the cells of the immune
system deliver vast amounts of the correct counter acting agent at the ideal time, in the sense, at
the point when the proper antigen is experienced. It suggests that there is a previous pool of
lymphocytes i.e B cells comprising of various little subsets. Every subset conveys a one of a kind
arrangement of surface counter acting agent atoms with its own specific restricting qualities. In
the event that a cell experiences and ties the comparing antigen it is `selected\' – empowered to
partition more than once and deliver a substantial clone of indistinguishable cells, all emitting the
counter acting agent. The contribution of aide T cells is basic for actuation of the B cell. A type
of clonal determination is additionally summoned to clarify the improvement of immunological
resistance.
True or False –Paraeducators provide direct or indirect instructio.pdf
True or False –
Paraeducators provide direct or indirect instructional and other services to students under the
supervision of a lead paraeducator.
Solution
it is true
Roles And Responsibilities Of Paraeducators
Over the years, the roles and responsibilities of paraeducators have become more complex and
have expanded to include numerous aspects of the educational process for studentswith
disabilities (Drecktrah, 2000; French & Pickett, 1997; Pickett, 1999). In practice, the dutiesof a
paraeducator may include, but are not limited to:
•
providing direct and small group instruction
•
adapting and modifying curriculum
•
monitoring student behavior
•
communicating with parents and families (many believe this should not reflect the role
of paraeducators)
•
performing clerical duties, and
•
providing personal care.
The situation where the few who yell the loudest get heard Is ref.pdf
The situation where \"the few who yell the loudest get heard\" Is referred to as the Multiple
Choice special-interest effect. principal-agent problem. moral hazard problem.
Solution
Answer:- the situation where the few who yell the loudest gets heard is referred to as the
Correct Answer:- Special interest effect
Reason:- “the special interest effect,” explains why, over time, the legislative process tends to
generate more expansive government..
Templated Binary Tree implementing function help I need to im.pdf
\"Templated Binary Tree\" implementing function help ?
I need to implement header file which i am working on.
Void expandExternal and void preorder part :
1. Header File :
#ifndef BINARYTREE_H
#define BINARYTREE_H
#include
////////////////////////////////////
// Templated Node Interface
///////////////////////////////////
template // base element type
class Node { // a node of the tree
public:
Node() : elt(), par(NULL), left(NULL), right(NULL) { } // constructor
private:
E elt; // element value
Node* par; // parent
Node* left; // left child
Node* right; // right child
template friend class BinaryTree;
template friend class Position;
};
////////////////////////////////////
// Templated Binary Tree Interface
///////////////////////////////////
template // base element type
class BinaryTree
{
public: // public types
//Defines a node position
class Position
{
public:
Position(Node * _v = NULL) : v(_v) { } // constructor
//Returns the element at the position
E& operator*()
{
return v->elt;
}
//Returns a Position object
Position left() const // get left child
{
return Position(v->left);
}
//Returns a Position object
Position right() const // get right child
{
return Position(v->right);
}
//Returns a Position object
Position parent() const // get parent
{
return Position(v->par);
}
//Returns true or false
bool isRoot() const // root of tree?
{
return v->par == NULL;
}
//Returns true or false
bool isExternal() const // an external node?
{
return v->left == NULL && v->right == NULL;
}
//Returns true or false
bool isInternal() const // an external node?
{
return ! isExternal();
}
private:
Node* v;
template friend class BinaryTree;
};//End Position class definition
/* Position List type definition*/
typedef std::list PositionList;
public: //Binary member functions
BinaryTree() : _root(NULL), n(0) { }
~BinaryTree(); // The destructor need to properly deletes all nodes in the tree to prevent
memory leaks.
int size() const; // Returns and integer tof the number of nodes.
bool empty() const; // Returns a true if the tree is empty else false.
Position root() const; // Return the position of the root node.
void addRoot(); // Creates and adds the initial root node to the tree this must be added first.
void expandExternal(const Position& p); //Expands each external node with a left and right
child that are empty.
// What goes here?
PositionList positions() const; // Returns a std:list of the nodes in the tree call preorder()
function.
void preorder(Node* v, PositionList& pl) const; // Traversal algorithm for the tree to populate
the PositionList
// What goes here?
private:
Node * _root; // pointer to the root
int n; // number of nodes
};
#endif
Thank you
Solution
for the main function, try writing the code like this :
struct Node{
Comparable element;
Node *left;
Node *right;
Node(const Comparable & theElement, Node *lt, Node *rt )
: element( theElement ), left( lt ), right( rt ) {}
}; // Node{}
Node *root;
Node * findMin( Node *t ) const;
Node * findMax( Node *.
State if you agree or disagree with the question and comments made b.pdf
State if you agree or disagree with the question and comments made below and why?
Does Maryland’s new social media campaign rule go far enough to validate who is posting the
political information on social media? Maryland has begun a great new way of identifying
political advertisers support of particular politicians. But, this may not do everything that it needs
to do in order to validate who is behind the postings or what is the motivation of the poster. If a
political poster wished to disguise themselves and pretend to support a particular candidate, he or
she could easily tag the advertisement with the legally required statement but still not be
affiliated with the campaign they are supporting. This law would need to be broadened to include
campaign-assuming responsibility for monitoring or approving any post made in their name. In
order to achieve this goal, campaigns would need huge numbers of paid and volunteer team
members just to monitor social media. Otherwise, social media, such as Facebook and Twitter,
would need to have to take more responsibility for the IP addresses they allow to advertise on
their platforms. Since this is a new legal development, it will need to be fine-tuned in order to
protect the public from scammers.
Solution
With the emergence of social media networking being used to advertising in every field, the
same has been done by the political advertisers. With this grew the forgery in the posts that were
made in the name of political parties. So Maryland levied this law in which the political
advertisers will have to identify their political campaign material before posting it on social
media and can post it following set rules and guidelines.
In the above matter it is mentioned that these rules will not eradicate the issue of false
advertising totally as the political poster can be disguised and pretend to support a particular
candidate. Tagging the advertisement with a legally required statement can be done even though
they may not be affiliated with the campaign they are showing support for. To overcome this
forgery ways will have to be found out to monitor and approve any post made in the name of a
candidate or party by the party or candidates. For this special team members will have to be hired
to keep a monitoring eye on the posts on social media. Also the social media can help by keeping
a track of all the IP addresses they allow for the advertisements done ussing their platforms.
These steps are essential to be taken in the political advertising campaigns as they will help
erasing the false advertising in the names of political parties and make social media a trusted and
genuine platform for such advertising..
A number of benefits that one might expect to see from using a datab.pdf
A number of benefits that one might expect to see from using a database such as MySQL. List
four of these benefits and in your own words describe the benefit.
Solution
Some of the benefits are:
Heavily Supported: It supports software on a variety of platforms and operating systems
including Windows, Linux, Novell NetWare, UNIX and more.
Secure: It help solid data security layers to safeguard sensitive data from outside access. All
passwords used to entry the MySQL database are encrypted.
Fast: When compared to other database software MySQL is much agile in terms of performance,
and users still have approach to all the required features they would through other database
platforms.
Data Storage is Scalable: MySQL can handle a overall file size limit of about 4GB, however, this
can be enlarged to meet our needs – by as much as 8TB of data.
Manages Memory: The database software has been shown to guide memory vastly well and
prevents memory leaks which we might experience on a server where it’s not deployed..
QUESTION If you look at the code, youll see that we keep two list.pdf
QUESTION: If you look at the code, you\'ll see that we keep two lists, one to print the text in
forward order, and one to print the text in reverse order. The forward one is using our empty
add() function, so nothing gets put into it. You\'ll fix that, as well as modifiying insert() and
erase(). The reverse on works by inserting always at the head of the list, like a Stack.Functions
insert(), erase(), and add() must be modified so that if the last node of the list changes, List::last
must change, as well. YOU JUST HAVE TO COMPLETE THE LIST.CPP FILE SO THAT IT
PRINTS THE OUTPUT IN THE FORWARD ORDER.FINISH THE CODE ONLY IN
LIST.CPP FILE AND OTHER FILES ARE JUST FOR REFERENCE. MORE
INFORMATION AND HINTS ARE GIVEN IN THE COMMENTS IN LIST.CPP FILE.
HINT: AFTER the existing code runs, there\'s an easy way to know if you just changed the last
node in the list; if you did, it\'s time to update the \"last\" pointer. And remember that \'add\'-ing
the first item is a special case. We could make a Linked List behave a lot like a Queue if it were
really efficient to add a node at the end of the list, that is, without having to chase links from the
head to the tail. So we will add another pointer to our List class that will always point at the last
item in the list. Read the existing code carefully and understand how it works. The \"add\"
function is now empty. If you run the file you should get an output that starts out like this:
?CURRENT LIST.CPP:
CURRENT OUTPUT:
MAIN.CPP FILE:
LIST.H FILE: include list include
Solution
PROGRAM CODE:
/*
* List.cpp
*
* Created on: 29-Nov-2016
* Author: kasturi
*/
#include \"List.h\"
#include
#include
#include
using namespace std;
void List::insert(ElemetType item, int position)
{
Node * predptr = first;
for(int i=1; i< position && predptr && predptr->next; i++)
{
predptr = predptr->next;
}
Node * newptr = new Node;
newptr->payload = item;
if(!predptr)
{
newptr->next = 0;
first = newptr;
}
else if(position == 0)
{
newptr->next = first;
first = newptr;
}
else
{
newptr->next = predptr->next;
predptr->next = newptr;
}
}
void List::erase(int position)
{
Node * predptr = first;
for(int i=1; inext; i++)
{
predptr = predptr->next;
}
if(!predptr)
{
}
else if(position == 1)
{
first = predptr->next;
delete predptr;
}
else
{
Node *ptr = predptr->next;
predptr->next = ptr->next;
delete ptr;
}
}
void List::display(ostream& ostr)
{
Node * ptr = last; //changed the display function to print the first
while(ptr)
{
ostr<payload<next;
}
}
List::List()
{
first = 0;
last = 0;
}
List::~List()
{
while(first)
{
Node *nxt = first->next;
delete first;
first = nxt;
}
}
void List::add(ElemetType item)
{
//added code to add values into the last node
Node * predptr = last;
Node *newptr = new Node;
newptr->payload= item;
while( predptr && predptr->next)
{
predptr = predptr->next;
}
if(!predptr)
{
newptr->next = 0;
last = newptr;
}
else
{
newptr->next = predptr->next;
predptr->next = newptr;
}
}
OUTPUT:
Forward:
The
quick
brown
fox
jumped
over
the
back.
Question 11 What is the volume of 17.0 grams of carbon dioxide gas if.pdf
Question 11 What is the volume of 17.0 grams of carbon dioxide gas if its pressure is 568 Torr
and its temperature is 25 degrees Celsius? 4.2L O120.8 8.4 L 12.7L
Solution
Mole of carbon dioxide= mass/molar mass
Molar mass of co2 =44g/mol
Mole = 17/44=0.386 mole
We use pv=nrt
Pressure=568 torr. = 0.747 atm
R = 0.08206atm.L/mol.k
0.747*V= 0.386*0.07206*298
Volume=12.7 L.
Please help with this. program must be written in C# .. All of the g.pdf
Please help with this. program must be written in C# .. All of the game logic must be written in a
seperate class using using an array that is passed in through a prperty that represents the game
board. The class needs to have methods to determine of someone won, or if there was a tie,
make sure all business logic is in a seperate class anot behind the UI..
***** These are the complete in instructions for the game assignment design
Create a Tic-Tac-Toe game that can be played by two players. The form will consist of a Tic-
Tac-Toe board in which the users’ click on to choose their space. As the game is being played
the Game Status section will tell whose turn it is. When someone wins or there is a tie, a message
will be displayed in the Game status section telling the users the status. When someone wins the
game the winning move needs to be indicated. There also needs to be a section that keeps track
of the number of wins for each player, and the number of ties. When the game is finished the
user may click the “Start Game” button to start a new game.
This program will consist of the main form and at least one class that will define the rules of the
game. This class will have an array that is passed in through a property that represents the game
board. The class will then have methods within it that determines if someone won, if there is a
tie, or if neither has occurred yet. Make sure all business logic is in a separate class and not
behind the UI.
EXTRA CREDIT (10 Points)
Create a computer player that can be played against. The computer player will need to be smart
enough to make a winning move or to block a winning move.
Solution
using System;
using System.Collections.Generic;
using System.Drawing;
using System.Windows.Forms;
namespace Tic_Tac_Toe
{
///
/// Description of MainForm.
///
public partial class MainForm : Form
{
Logic logicObj = new Logic();
public MainForm()
{
//
// The InitializeComponent() call is required for Windows Forms designer support.
//
InitializeComponent();
//
// TODO: Add constructor code after the InitializeComponent() call.
//
}
int turn=1;
int click1=0,click2=0,click3=0,click4=0,click5=0,click6=0,click7=0,click8=0,click9=0;
int player1=0,player2=0;
void Button1Click(object sender, EventArgs e)
{
if(click1==0)
{
if(turn%2!=0)
{
button1.Text=\"X\";
click1++;
}
else
{
button1.Text=\"O\";
click1++;
}
turn++;
}
else
{
button1.Text=button1.Text;
}
display();
int a = logicObj.winLossFunc(button1.Text, button2.Text, button3.Text, button4.Text,
button5.Text, button6.Text, button7.Text, button8.Text, button9.Text);
if (a==1)
{
player1++;
player1score.Text = player1.ToString();
cleargame();
}
else if(a==2)
{
player2++;
player2score.Text = player2.ToString();
cleargame();
}
}
void Button2Click(object sender, EventArgs e)
{
if(click2==0)
{
if(turn%2!=0)
{
button2.Text=\"X\";
click2++;
}
else
{
button2.Text=\"O\";
click2++;
}
turn++;
}
else
{
button2.Text=button2.Text;
}
display();
int a = logicObj.winLossFunc(button1.Text, b.
Match the enzyme activity in DNA synthesis with its function. DNA po.pdf
Match the enzyme activity in DNA synthesis with its function. DNA pol III (_) fragments
Helicase (_) Primase (_) using template strand DNA pol I (_) double helix DNA ligase (_) adds
nucleotides Topoisomerase (_) primer A. anneals DNA B. relieves overwinding C. adds
nucleotides D. unwinds parental E. removes RNA primer, F. adds a short RNA 10
Proofreading and repair of the DNA double helix does NOT involves a. detecting a mis-match
in base pairs. b. removing the mis-match with a nuclease. c. annealing the Okazaki fragments
together with DNA ligase. d. repairing the mis-match with polymerase. e. annealing the edited
DNA with the rest of the molecule with ligase.
Solution
4. DNA Pol III- (C)- DNA polymerase III is the primary enzyme involved in DNA replication
which adds nucleotides to the 3\' end of the forming DNA strand during replication.
5. Helicase- (D)- Helicases are enzymes that separates double-stranded DNA into single strands
allowing each strand to be copied.
6. Primase- (F)- Primase functions by synthesizing short RNA sequences that are complementary
to a single-stranded DNA.
7. DNA Pol I- (E)- DNA polymerase-I fills in the necessary nucleotides between the Okazaki
fragments in a 5\'3\' direction.
8. DNA ligase- (A)- DNA ligases are essential for the joining of DNA fragments during
replication.
9. Topoisomerase- (B)-Topoisomerases are enzymes that participate in the overwinding or
underwinding of DNA.
10. Okazaki fragments are only formed during DNA replication and not observed during DNA
proof reading and repair. Therefore answer is (C).
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- 1. In Java.... The methods should work as: add(Node) It has to take a new Node and add that to the next address of previous Node. findNode(Node) It has to take a node and checks if the node is in the list. size() It should return the size of the NodeList. public class NodeList { private int size = 0; private Node root = null; /* * It has to take a new Node and add that to the next address of previous Node. * If the list is empty, assign it as the "root" * @Param - Node */ public void add(Node node) { // Implement this method!!! } /* * It has to return the size of the NodeList * * @return size */ public int size() { // Implement this method!!! } /* * It has to take a Node and checks if the node is in the list. * If it finds the node, it returns true, otherwise false * * @param - Node * @return boolean true/false */ public boolean findNode(Node node){ // Implement this method!!!
- 2. } } Solution public class NodeList { private int size = 0; private Node root = null; /* * It has to take a new Node and add that to the next address of previous Node. * If the list is empty, assign it as the "root" * @Param - Node */ public void add(Node node) { // Implement this method!!! if(node==null) return; if(root == null) root=node; else{ Node temp = root; while(temp.next!=null){ temp = temp.next; } temp.next = node; } } /* * It has to return the size of the NodeList * * @return size */ public int size() { // Implement this method!!!
- 3. int count =0; if(root==null) return count; else{ Node temp = root; while(temp!=null){ temp= temp.next; count++; } } return count; } /* * It has to take a Node and checks if the node is in the list. * If it finds the node, it returns true, otherwise false * * @param - Node * @return boolean true/false */ public boolean findNode(Node node){ // Implement this method!!! boolean flag = false; if(root == null) return false; else{ Node temp = root; while(temp!=null){ if(temp==node){ flag = true; break; } } return flag; } }
- 4. } also find the defination of class Node class Node{ int data; Node next; }