Hashing based on another type of data structure Hashing is implem.pdf
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Hashing based on another type of data structure : Hashing is implemented by using the datastructure, in this use a certain structure which can map keys to values. Unique object is required for unique hash code : Every unique hash code maintains unique object. Hash codes assign to same position in hash table : There are different hash codes which assign to same position in hash table. Collissions exist in a hash table : Since assigning different hash codes assign to same bucket may raise collission. Option 1, 2 and 3 are correct choice. Solution Hashing based on another type of data structure : Hashing is implemented by using the datastructure, in this use a certain structure which can map keys to values. Unique object is required for unique hash code : Every unique hash code maintains unique object. Hash codes assign to same position in hash table : There are different hash codes which assign to same position in hash table. Collissions exist in a hash table : Since assigning different hash codes assign to same bucket may raise collission. Option 1, 2 and 3 are correct choice..
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The H shell contains a total of 11 orbitals. s=1 .pdf
The H shell contains a total of 11 orbitals with s=1, p=3, d=5, f=7, g=9 and h=11 orbitals. There is a difference of two between each set of consecutive orbitals in the H shell.
The burning of coal releases SO2 into the atmosph.pdf
The burning of coal releases SO2 into the atmosphere, where it turns into H2SO4,
which is a strong diprotic acid. This sulphuric acid returns to the surface of the earth through
rain, hence acid rain. The following (from wikipedia) shows the transformation of SO2 into
H2SO4. In the gas phase sulfur dioxide is oxidized by reaction with the hydroxyl radical via an
intermolecular reaction [5]: SO2 + OH· ? HOSO2· which is followed by: HOSO2· + O2 ? HO2·
+ SO3 In the presence of water, sulfur trioxide (SO3) is converted rapidly to sulfuric acid: SO3
(g) + H2O (l) ? H2SO4 (l) The limestone basin lake can still contain life, because limestone
contains a lot of calcium carbonate. Calcium carbonate neutralizes acids according to the
following reaction: CaCO3 (s) + H2SO4 (aq) <-> CaSO4 (aq) + CO2 (g) + H2O (l) (CaCO3 is
basic) Hence, the limestone basin reduces the lakes acidity. Clay consists of minute charged
particles. According to chemistryquestion.com \"Clay in soil has a property of ion exchange.
Under acidic conditions, H+ is adsorbed on the surface of clay and Ca2+ etc. are eluted instead.\"
Or as elmhurst.edu puts it \"The hydrogen ions in the sulfuric acid trade places with the metal
ions. The hydrogen ions are retained and neutralized by the soil.\" Hence, clay maintains a high
concentration of H+, which makes life impossible.
Solution
The burning of coal releases SO2 into the atmosphere, where it turns into H2SO4,
which is a strong diprotic acid. This sulphuric acid returns to the surface of the earth through
rain, hence acid rain. The following (from wikipedia) shows the transformation of SO2 into
H2SO4. In the gas phase sulfur dioxide is oxidized by reaction with the hydroxyl radical via an
intermolecular reaction [5]: SO2 + OH· ? HOSO2· which is followed by: HOSO2· + O2 ? HO2·
+ SO3 In the presence of water, sulfur trioxide (SO3) is converted rapidly to sulfuric acid: SO3
(g) + H2O (l) ? H2SO4 (l) The limestone basin lake can still contain life, because limestone
contains a lot of calcium carbonate. Calcium carbonate neutralizes acids according to the
following reaction: CaCO3 (s) + H2SO4 (aq) <-> CaSO4 (aq) + CO2 (g) + H2O (l) (CaCO3 is
basic) Hence, the limestone basin reduces the lakes acidity. Clay consists of minute charged
particles. According to chemistryquestion.com \"Clay in soil has a property of ion exchange.
Under acidic conditions, H+ is adsorbed on the surface of clay and Ca2+ etc. are eluted instead.\"
Or as elmhurst.edu puts it \"The hydrogen ions in the sulfuric acid trade places with the metal
ions. The hydrogen ions are retained and neutralized by the soil.\" Hence, clay maintains a high
concentration of H+, which makes life impossible..
pOH = 14 - pH = 14 - 12.50 = 1.5 pOH = -log[OH-] .pdf
pOH = 14 - pH = 14 - 12.50 = 1.5 pOH = -log[OH-] = 1.5 M2 = [OH-] = 0.032 M
V2 = 2.50 L M1 = 0.455 M M1V1 = M2V2 V1 = M2V2/M1 = 0.032 x 2.50 / 0.455 = 0.176 L
Solution
pOH = 14 - pH = 14 - 12.50 = 1.5 pOH = -log[OH-] = 1.5 M2 = [OH-] = 0.032 M
V2 = 2.50 L M1 = 0.455 M M1V1 = M2V2 V1 = M2V2/M1 = 0.032 x 2.50 / 0.455 = 0.176 L.
Naproxen sodium is very polar because it is ionic.pdf
The document discusses and ranks the polarity of several compounds from least polar to most polar. Naproxen sodium is the most polar due to being ionic. Ibuprofen is the least polar with only a polar carboxylic acid group and nonpolar structures. The other compounds have varying numbers of polar groups like hydroxyl, carbonyl, and amide groups attached to mostly nonpolar ring structures.
In benzene delocalised electrons are contained in.pdf
In benzene delocalised electrons are contained in an orbital that extends to the
adjacent atoms, so the electrons are not specifically linked to an atom which gives rise to
different canonical forms (or resonance structures)
Solution
In benzene delocalised electrons are contained in an orbital that extends to the
adjacent atoms, so the electrons are not specifically linked to an atom which gives rise to
different canonical forms (or resonance structures).
H2SO4(aq) + Ba(OH)2(aq) -- BaSO4(s) + 2H22O(l) .pdf
H2SO4(aq) + Ba(OH)2(aq) --> BaSO4(s) + 2H22O(l) SO the ions that react are
Ba(2+) and SO4(2-) and the others H+ and OH- react to create water.
Solution
H2SO4(aq) + Ba(OH)2(aq) --> BaSO4(s) + 2H22O(l) SO the ions that react are
Ba(2+) and SO4(2-) and the others H+ and OH- react to create water..
Reptiles have thick,scaly skin that helps conserve moisture inside t.pdf
Reptiles have thick,scaly skin that helps conserve moisture inside their bodies,an essential
feature that helps them survive not only on land,but in dry,desert areas as well.The skin is
waterproof.Reptiles also tend to have efficient excretory systems,removing as much moisture as
possible before releasing waste.This typically leads to firm feces and highly concentrated
urine.Kidneys concentrates the urine so that the reptiles lose very little water.They depend on
their surrounding environment to control their body temperature.Reptiles shows behavioral
adaptations to regulate body temperature,such as lying in sunny places to warm up and finding
shady spots or going underground to cool down.
Reptiles reproduce sexually through internal fertilization;some species are ovoviviparous(lay
eggs) and others are viviparous.Laying eggs that can survive on land is a major adaptation
allowing reptiles to live away from aquatic environments.Amphibians tend to lay soft,gelatinous
eggs,and most use forms of external fertilization.Such eggs will not survive the dry conditions
found on land.Whereas reptiles lay eggs covered in a thick,leathery coating or hard calcium
shells after using internal fertilization to create viable eggs.Some reptiles deliver live
babies,carrying the eggs inside their bodies until the babies are ready to be born.
Solution
Reptiles have thick,scaly skin that helps conserve moisture inside their bodies,an essential
feature that helps them survive not only on land,but in dry,desert areas as well.The skin is
waterproof.Reptiles also tend to have efficient excretory systems,removing as much moisture as
possible before releasing waste.This typically leads to firm feces and highly concentrated
urine.Kidneys concentrates the urine so that the reptiles lose very little water.They depend on
their surrounding environment to control their body temperature.Reptiles shows behavioral
adaptations to regulate body temperature,such as lying in sunny places to warm up and finding
shady spots or going underground to cool down.
Reptiles reproduce sexually through internal fertilization;some species are ovoviviparous(lay
eggs) and others are viviparous.Laying eggs that can survive on land is a major adaptation
allowing reptiles to live away from aquatic environments.Amphibians tend to lay soft,gelatinous
eggs,and most use forms of external fertilization.Such eggs will not survive the dry conditions
found on land.Whereas reptiles lay eggs covered in a thick,leathery coating or hard calcium
shells after using internal fertilization to create viable eggs.Some reptiles deliver live
babies,carrying the eggs inside their bodies until the babies are ready to be born..
It is a known factor that HIV AIDS is unevenly evade the several r.pdf
It is a known factor that HIV / AIDS is unevenly evade the several region of the world’s
population. To understand that what those factors are responsible for the uneven distribution of
HIV / AIDS are explained below.
Economic Reason:
There are many countries in the world which are majorly known as Un developed, Developing
and Developed countries. The economic reason behind these major factors are uneven
distribution of natural resources, under education are some of them to list out. Since undeveloped
countries are lacking education as well as poverty; disease such as AIDS are more prevalent in
these regions. In the underdeveloped countries it is seen that as an estimated 70,000 teenaged
girls die each year during pregnancy and even the childbirth and more than one million infants
born to adolescent girls die before their first birthday. This is because of health consequences in
the teenage pregnancies are forced to their death sentence in poorest countries. Studies revealed
that about 2 millions or more of them suffered chronic illness or disabilities, shame and
abandonment in the underdeveloped countries. It is also seen that each year 2.2 to 4 million
adolescents option to unsafe abortions. This can be said that the adolescent pregnancy and
childbearing have distinct and important damaging consequences at global, societal and personal
levels in the world.
Cultural Reason:
In the world the cultural and sexual practices between the religions are different. There are
majorly two groups of population the low prevalence group is largely Muslim and the high
prevalence group is largely non-Muslim. Some of the factors like drug abuse, homosexuality,
extramarital and premarital sex are strongly prohibited in Muslim religion. The major impact of
cultural reason as religion can be clearly seen from the HIV prevalence in South Africa and
Uganda and by the difference that the classification and listing of HIV may change across the
national borders. The studies showed that the highest HIV/AIDS prevalence countries in sub-
Saharan are Swaziland (25.9%), Botswana (24.8%) and Lesotho (23.6%). The conservative
explanation is that the syndrome has increase in the heterosexually into neighbouring and
affluent South Africa (17.8%). It is known that the Botswana is almost bordered to the north by
low prevalence Angola (2%). It is seen reasonably and perhaps surprisingly consistent that the
HIV/AIDS cases are especially in association between the high prevalence in non-Muslim and
lower prevalence in predominantly Muslim countries.
Geographic reasons:
It has been observed that the geography of HIV infection in Africa having the highest incidence
rates of HIV / AIDS reported has varied features at each scale. The transmission of the
HIV/AIDS is oriented preferentially according to axes and poles where the virus spread out
because of local environmental factors which were found favourable conditions to dissemination.
It can be understand that the local combination .
Recommended
The H shell contains a total of 11 orbitals. s=1 .pdf
The H shell contains a total of 11 orbitals with s=1, p=3, d=5, f=7, g=9 and h=11 orbitals. There is a difference of two between each set of consecutive orbitals in the H shell.
The burning of coal releases SO2 into the atmosph.pdf
The burning of coal releases SO2 into the atmosphere, where it turns into H2SO4,
which is a strong diprotic acid. This sulphuric acid returns to the surface of the earth through
rain, hence acid rain. The following (from wikipedia) shows the transformation of SO2 into
H2SO4. In the gas phase sulfur dioxide is oxidized by reaction with the hydroxyl radical via an
intermolecular reaction [5]: SO2 + OH· ? HOSO2· which is followed by: HOSO2· + O2 ? HO2·
+ SO3 In the presence of water, sulfur trioxide (SO3) is converted rapidly to sulfuric acid: SO3
(g) + H2O (l) ? H2SO4 (l) The limestone basin lake can still contain life, because limestone
contains a lot of calcium carbonate. Calcium carbonate neutralizes acids according to the
following reaction: CaCO3 (s) + H2SO4 (aq) <-> CaSO4 (aq) + CO2 (g) + H2O (l) (CaCO3 is
basic) Hence, the limestone basin reduces the lakes acidity. Clay consists of minute charged
particles. According to chemistryquestion.com \"Clay in soil has a property of ion exchange.
Under acidic conditions, H+ is adsorbed on the surface of clay and Ca2+ etc. are eluted instead.\"
Or as elmhurst.edu puts it \"The hydrogen ions in the sulfuric acid trade places with the metal
ions. The hydrogen ions are retained and neutralized by the soil.\" Hence, clay maintains a high
concentration of H+, which makes life impossible.
Solution
The burning of coal releases SO2 into the atmosphere, where it turns into H2SO4,
which is a strong diprotic acid. This sulphuric acid returns to the surface of the earth through
rain, hence acid rain. The following (from wikipedia) shows the transformation of SO2 into
H2SO4. In the gas phase sulfur dioxide is oxidized by reaction with the hydroxyl radical via an
intermolecular reaction [5]: SO2 + OH· ? HOSO2· which is followed by: HOSO2· + O2 ? HO2·
+ SO3 In the presence of water, sulfur trioxide (SO3) is converted rapidly to sulfuric acid: SO3
(g) + H2O (l) ? H2SO4 (l) The limestone basin lake can still contain life, because limestone
contains a lot of calcium carbonate. Calcium carbonate neutralizes acids according to the
following reaction: CaCO3 (s) + H2SO4 (aq) <-> CaSO4 (aq) + CO2 (g) + H2O (l) (CaCO3 is
basic) Hence, the limestone basin reduces the lakes acidity. Clay consists of minute charged
particles. According to chemistryquestion.com \"Clay in soil has a property of ion exchange.
Under acidic conditions, H+ is adsorbed on the surface of clay and Ca2+ etc. are eluted instead.\"
Or as elmhurst.edu puts it \"The hydrogen ions in the sulfuric acid trade places with the metal
ions. The hydrogen ions are retained and neutralized by the soil.\" Hence, clay maintains a high
concentration of H+, which makes life impossible..
pOH = 14 - pH = 14 - 12.50 = 1.5 pOH = -log[OH-] .pdf
pOH = 14 - pH = 14 - 12.50 = 1.5 pOH = -log[OH-] = 1.5 M2 = [OH-] = 0.032 M
V2 = 2.50 L M1 = 0.455 M M1V1 = M2V2 V1 = M2V2/M1 = 0.032 x 2.50 / 0.455 = 0.176 L
Solution
pOH = 14 - pH = 14 - 12.50 = 1.5 pOH = -log[OH-] = 1.5 M2 = [OH-] = 0.032 M
V2 = 2.50 L M1 = 0.455 M M1V1 = M2V2 V1 = M2V2/M1 = 0.032 x 2.50 / 0.455 = 0.176 L.
Naproxen sodium is very polar because it is ionic.pdf
The document discusses and ranks the polarity of several compounds from least polar to most polar. Naproxen sodium is the most polar due to being ionic. Ibuprofen is the least polar with only a polar carboxylic acid group and nonpolar structures. The other compounds have varying numbers of polar groups like hydroxyl, carbonyl, and amide groups attached to mostly nonpolar ring structures.
In benzene delocalised electrons are contained in.pdf
In benzene delocalised electrons are contained in an orbital that extends to the
adjacent atoms, so the electrons are not specifically linked to an atom which gives rise to
different canonical forms (or resonance structures)
Solution
In benzene delocalised electrons are contained in an orbital that extends to the
adjacent atoms, so the electrons are not specifically linked to an atom which gives rise to
different canonical forms (or resonance structures).
H2SO4(aq) + Ba(OH)2(aq) -- BaSO4(s) + 2H22O(l) .pdf
H2SO4(aq) + Ba(OH)2(aq) --> BaSO4(s) + 2H22O(l) SO the ions that react are
Ba(2+) and SO4(2-) and the others H+ and OH- react to create water.
Solution
H2SO4(aq) + Ba(OH)2(aq) --> BaSO4(s) + 2H22O(l) SO the ions that react are
Ba(2+) and SO4(2-) and the others H+ and OH- react to create water..
Reptiles have thick,scaly skin that helps conserve moisture inside t.pdf
Reptiles have thick,scaly skin that helps conserve moisture inside their bodies,an essential
feature that helps them survive not only on land,but in dry,desert areas as well.The skin is
waterproof.Reptiles also tend to have efficient excretory systems,removing as much moisture as
possible before releasing waste.This typically leads to firm feces and highly concentrated
urine.Kidneys concentrates the urine so that the reptiles lose very little water.They depend on
their surrounding environment to control their body temperature.Reptiles shows behavioral
adaptations to regulate body temperature,such as lying in sunny places to warm up and finding
shady spots or going underground to cool down.
Reptiles reproduce sexually through internal fertilization;some species are ovoviviparous(lay
eggs) and others are viviparous.Laying eggs that can survive on land is a major adaptation
allowing reptiles to live away from aquatic environments.Amphibians tend to lay soft,gelatinous
eggs,and most use forms of external fertilization.Such eggs will not survive the dry conditions
found on land.Whereas reptiles lay eggs covered in a thick,leathery coating or hard calcium
shells after using internal fertilization to create viable eggs.Some reptiles deliver live
babies,carrying the eggs inside their bodies until the babies are ready to be born.
Solution
Reptiles have thick,scaly skin that helps conserve moisture inside their bodies,an essential
feature that helps them survive not only on land,but in dry,desert areas as well.The skin is
waterproof.Reptiles also tend to have efficient excretory systems,removing as much moisture as
possible before releasing waste.This typically leads to firm feces and highly concentrated
urine.Kidneys concentrates the urine so that the reptiles lose very little water.They depend on
their surrounding environment to control their body temperature.Reptiles shows behavioral
adaptations to regulate body temperature,such as lying in sunny places to warm up and finding
shady spots or going underground to cool down.
Reptiles reproduce sexually through internal fertilization;some species are ovoviviparous(lay
eggs) and others are viviparous.Laying eggs that can survive on land is a major adaptation
allowing reptiles to live away from aquatic environments.Amphibians tend to lay soft,gelatinous
eggs,and most use forms of external fertilization.Such eggs will not survive the dry conditions
found on land.Whereas reptiles lay eggs covered in a thick,leathery coating or hard calcium
shells after using internal fertilization to create viable eggs.Some reptiles deliver live
babies,carrying the eggs inside their bodies until the babies are ready to be born..
It is a known factor that HIV AIDS is unevenly evade the several r.pdf
It is a known factor that HIV / AIDS is unevenly evade the several region of the world’s
population. To understand that what those factors are responsible for the uneven distribution of
HIV / AIDS are explained below.
Economic Reason:
There are many countries in the world which are majorly known as Un developed, Developing
and Developed countries. The economic reason behind these major factors are uneven
distribution of natural resources, under education are some of them to list out. Since undeveloped
countries are lacking education as well as poverty; disease such as AIDS are more prevalent in
these regions. In the underdeveloped countries it is seen that as an estimated 70,000 teenaged
girls die each year during pregnancy and even the childbirth and more than one million infants
born to adolescent girls die before their first birthday. This is because of health consequences in
the teenage pregnancies are forced to their death sentence in poorest countries. Studies revealed
that about 2 millions or more of them suffered chronic illness or disabilities, shame and
abandonment in the underdeveloped countries. It is also seen that each year 2.2 to 4 million
adolescents option to unsafe abortions. This can be said that the adolescent pregnancy and
childbearing have distinct and important damaging consequences at global, societal and personal
levels in the world.
Cultural Reason:
In the world the cultural and sexual practices between the religions are different. There are
majorly two groups of population the low prevalence group is largely Muslim and the high
prevalence group is largely non-Muslim. Some of the factors like drug abuse, homosexuality,
extramarital and premarital sex are strongly prohibited in Muslim religion. The major impact of
cultural reason as religion can be clearly seen from the HIV prevalence in South Africa and
Uganda and by the difference that the classification and listing of HIV may change across the
national borders. The studies showed that the highest HIV/AIDS prevalence countries in sub-
Saharan are Swaziland (25.9%), Botswana (24.8%) and Lesotho (23.6%). The conservative
explanation is that the syndrome has increase in the heterosexually into neighbouring and
affluent South Africa (17.8%). It is known that the Botswana is almost bordered to the north by
low prevalence Angola (2%). It is seen reasonably and perhaps surprisingly consistent that the
HIV/AIDS cases are especially in association between the high prevalence in non-Muslim and
lower prevalence in predominantly Muslim countries.
Geographic reasons:
It has been observed that the geography of HIV infection in Africa having the highest incidence
rates of HIV / AIDS reported has varied features at each scale. The transmission of the
HIV/AIDS is oriented preferentially according to axes and poles where the virus spread out
because of local environmental factors which were found favourable conditions to dissemination.
It can be understand that the local combination .
touchesSolutiontouches.pdf
This very short document does not contain enough contextual information to generate a meaningful 3 sentence summary. The document consists of only 3 words with no other context provided.
There are various factors are responsible for reproductive isolation.pdf
There are various factors are responsible for reproductive isolation during the period of
geographical isolation.
1. Species specific breeding season: in this the species of same genus having different time for
breading will not able to interbreed. Failure of fertilization of egg: this is also happen even the
species are interbred.
2. Prezygotic isolation-
3. Postzygotic isolation-
Solution
There are various factors are responsible for reproductive isolation during the period of
geographical isolation.
1. Species specific breeding season: in this the species of same genus having different time for
breading will not able to interbreed. Failure of fertilization of egg: this is also happen even the
species are interbred.
2. Prezygotic isolation-
3. Postzygotic isolation-.
The film is a mix of social drama and comedy. The content is present.pdf
The film is a mix of social drama and comedy. The content is presented in a satire. How did
people survived the great depression of the world is being documented here. The conditions
werre miserable like acute shortage of work, factory closings, labor strikes and political unrest
etc.
Before we go on to the answers of the given questions lets first have a quick view on the possible
ehtical dilemmas of the film:
The major ethical dilemmas consist whether out of poverty stealing is right or wrong and
whether the replacement of labors for machines that makes the life of labors miserable is right or
wrong.. However this movie glorifies the struggle of the poor rather than verifying them for
stealing food to survive. By glorifying the struggle the movie takes on yet another social issue:
when the poor steal to eat it is not criminal, just survival. The entire movie is spent giving
specific (and comical) examples of the increasing futility of working for a living in a world
where machines and assembly lines are replacing skilled laborers. Minor ones include
1) The major ethical dillema of replacaement of skilled labors over machines leads to the
construct of the movie. The ethics of Modern Times is best represented in the closing scenes of
the film, starting with Chaplin’s sly and explicit dance, through to the closing credits, when
Chaplin and Goddard walk off into the sunrise, no scene drives it home as well as does the final
scene, when they give up and move on.
The dilemmas that are still remain unanswered include many such as, spying of employers on
employees; in the world of progress does honesty has its place as soon as Goddard obtains
money through hard work, she is arrested for prior vagrancy, thus throwing her back into
vagrancy; etc.
2) Spying is a clear cut threat to privacy of individuals. Although it is necessary to make
effeciecny through labor works but adopting such method is extreme autocratic that makes only
employees disgust and left them to disloyal to employers. Employees need to be motivated
through great leadership various incentives, attachment to the company to make best out of them.
Honesty can not be left in vain in any stage of progress in world. It is a prerequiste to have best
welfare of the societ as whole in fast developments in the economies that may lead to threat to
welfare in general. Goddard should have not run from the prior crime as it had led her into
another crime of being run away from law.
Solution
The film is a mix of social drama and comedy. The content is presented in a satire. How did
people survived the great depression of the world is being documented here. The conditions
werre miserable like acute shortage of work, factory closings, labor strikes and political unrest
etc.
Before we go on to the answers of the given questions lets first have a quick view on the possible
ehtical dilemmas of the film:
The major ethical dilemmas consist whether out of poverty stealing is right or wrong and
whether the .
The chart shows how to interpret the experimental results to identif.pdf
The chart shows how to interpret the experimental results to identify unknown species. Suppose
you started the experiment with collection of sample. The nature of sample itself gives some idea
on what is to be identified. Let the sample is stool sample collected froma person suffering from
diarrhea. The suspected organisms are gram negative enteropathogens like E. coli, Shigella
(though it causes dysentry and not diarrhea), Salmonella, Vibrio, etc.
The sample is initially processed and inoculated on suitable bacteriological medium. Let the
sample is inoculated on EMB agar, thiosulfate-citrate-bile salts sucrose agar, and wilson and
blair bismuth sulfite agar. If colonies are found on EMB agar, the suspected organisms are
enterobacteriaceae.
The colony morphology is observed initially, the size, color, margins, texture, all indicate colony
morphology. If black colonies with metallic sheen is seen, it indicates E.coli. Pink color colonies
indicate Enterobacter. Further confirmation is done through gram staining. Gram staining gives
the result if the organism is gram positive or gram negative.
If the organism is gram negative, to further differentiate among the enterobacteriaceae, IMVIC
tests are done. Each organims of enterobacteriaceae show specific patterns of results for IMVIC
tests. Biochemical tests like oxidase and catalase help to differentiate if the organism is aerobic
or anaerobic.
Solution
The chart shows how to interpret the experimental results to identify unknown species. Suppose
you started the experiment with collection of sample. The nature of sample itself gives some idea
on what is to be identified. Let the sample is stool sample collected froma person suffering from
diarrhea. The suspected organisms are gram negative enteropathogens like E. coli, Shigella
(though it causes dysentry and not diarrhea), Salmonella, Vibrio, etc.
The sample is initially processed and inoculated on suitable bacteriological medium. Let the
sample is inoculated on EMB agar, thiosulfate-citrate-bile salts sucrose agar, and wilson and
blair bismuth sulfite agar. If colonies are found on EMB agar, the suspected organisms are
enterobacteriaceae.
The colony morphology is observed initially, the size, color, margins, texture, all indicate colony
morphology. If black colonies with metallic sheen is seen, it indicates E.coli. Pink color colonies
indicate Enterobacter. Further confirmation is done through gram staining. Gram staining gives
the result if the organism is gram positive or gram negative.
If the organism is gram negative, to further differentiate among the enterobacteriaceae, IMVIC
tests are done. Each organims of enterobacteriaceae show specific patterns of results for IMVIC
tests. Biochemical tests like oxidase and catalase help to differentiate if the organism is aerobic
or anaerobic..
Solution-D. Providing more favorable financial information.Expla.pdf
Solution
-
D. Providing more favorable financial information.
Explanation-
Internal control is important aspect for any company, in internal control the main focus area is
financial information because that information helps the company stakeholders as well as
company perfomance amongst the shareholders..
Implementing Systems OverviewHealth information technology (HIT) e.pdf
Implementing Systems Overview
Health information technology (HIT) encompasses implementing a broad scope of applications,
technology, and operational activities (1.1 HIT Visioning and Strategic Planning), depending on
your organization and its goals (1.2 Goal Setting). This tool provides an overview of a typical
implementation of an electronic health record (EHR) system for a hospital. Use this tool to
understand the broad range of topics that you will need to consider during HIT implementation.
Overview of Implementation
Although specifics with respect to an implementation will vary by vendor and application, any
implementation should follow a similar high level structure:
1. Project management
2. Workflow and process redesign
3. Detailed plan creation
4. Issues management
5. Workflow and process redesign
6. Preparing for and installing hardware
7. Network development/refinement
8. Security risk analysis and controls
9. Super user training
10. Software installation and system configuration (a.k.a., “system build”), including report
writing, interfaces, data conversion
11. Testing
12. End user training
13. Preparation for go live
14. Go live
15. Benefits realization and recognition
16. Optimization strategies
Project Management
Even though your vendor will supply significant project support, you need to designate an
individual within your hospital to be the project manager, representing your interests and
ensuring that information learned during the process is retained within the hospital for future
reference. (1.2 Project Management, 1.2 Project Management Job Description)
Your project manager will be responsible for many activities:
o Managing your harmonized project plan, making sure the project gets completed on time and
within budget.
o Organizing your staff resources, team building, maintaining the project budget, approving
invoices, and handling other elements of making sure the hospital completes the designated tasks
on the project plan completely, accurately, and on time.
o Carrying out your communication plan (1.1 Communication Plan), including reminding others
to perform their necessary communications and potentially even scripting them for others such as
the CEO.
Workflow and Process Redesign
Ideally during the planning phases you will map current workflows and processes, using these to
initiate change management and create expectations to achieve goals, to help you identify system
requirements and select the most appropriate vendor, and potentially even to make adjustments
in workflows and processes today where streamlining or other improvements are feasible without
HIT. Mapping current workflows and processes gives you slightly less work to do during
implementation. This step is essential for configuring the system to your specifications and
anticipating changes with the new system.
Over just the past few years, the industry as a whole has come to recognize that not attending to
workflow and process redesign during HIT planning .
Second option is the correct one dear... sorry i was unable to uploa.pdf
Second option is the correct one dear... sorry i was unable to upload the image again
H = -ve
S = -Ve
G = -ve
Solution
Second option is the correct one dear... sorry i was unable to upload the image again
H = -ve
S = -Ve
G = -ve.
proofSolutionproof.pdf
This very short document does not contain enough contextual information to generate a meaningful 3 sentence summary. It consists of only 4 words with no other context provided.
Ph = - log(1.0x10-2)= 2 log(10)= 2SolutionPh = - log(1.0x1.pdf
The document shows the calculation of the pH of a solution that has a hydrogen ion concentration of 1.0x10-2. It takes the negative logarithm of the hydrogen ion concentration to get the pH, which equals 2 log(10) or simply 2.
mport javafx.application.Application;import javafx.scene.Node;im.pdf
mport javafx.application.Application;
import javafx.scene.Node;
import javafx.scene.Scene;
import javafx.scene.SnapshotParameters;
import javafx.scene.effect.ColorAdjust;
import javafx.scene.image.Image;
import javafx.scene.image.ImageView;
import javafx.scene.image.WritableImage;
import javafx.scene.layout.HBox;
import javafx.scene.paint.Color;
import javafx.scene.paint.CycleMethod;
import javafx.scene.paint.RadialGradient;
import javafx.scene.paint.Stop;
import javafx.scene.shape.Circle;
import javafx.stage.Stage;
public class Main extends Application {
@Override
public void start(Stage primaryStage) {
HBox root = new HBox();
// create alpha masked image
Image image = createImage(createAlphaMaskedRing(200));
// create original imageview
ImageView original = new ImageView( image);
// create imageview with color adjustment
ImageView modified = new ImageView( image);
// colorAdjust effect
ColorAdjust colorAdjust = new ColorAdjust();
// set saturation to 1, otherwise hue won\'t have an effect
colorAdjust.setSaturation(1);
// define target color
Color targetColor = Color.GREEN;
// calculate hue: map from [0,360] to [-1,1]; TODO: here\'s the problem
double hue = map( targetColor.getHue(), 0, 360, -1, 1);
colorAdjust.setHue(hue);
// apply color adjustment
modified.setEffect(colorAdjust);
root.getChildren().addAll( original, modified);
Scene scene = new Scene(root,1024,500, Color.yellow);
primaryStage.setScene(scene);
primaryStage.show();
}
/**
* Snapshot an image out of a node, consider transparency.
* @param node
* @return
*/
public static Image createImage( Node node) {
WritableImage wi;
SnapshotParameters parameters = new SnapshotParameters();
parameters.setFill(Color.TRANSPARENT);
int imageWidth = (int) node.getBoundsInLocal().getWidth();
int imageHeight = (int) node.getBoundsInLocal().getHeight();
wi = new WritableImage( imageWidth, imageHeight)
node.snapshot(parameters, wi);
return wi;
}
/**
* Create an alpha masked ring with gradient colors from Blueto Yellow/Transparent. Used e.
g. for particles.
*
* @param radius
* @return
*/
public static Node createAlphaMaskedRing( double radius) {
Circle ring = new Circle(radius);
RadialGradient gradient1 = new RadialGradient(0,
.1,
0,
0,
radius,
false,
CycleMethod.NO_CYCLE,
new Stop(0, Color.WHITE.deriveColor(1,1,1,1)),
new Stop(1, Color.YELLOW.deriveColor(1,1,1,0)));
ring.setFill(gradient1);
return ring;
}
public static double map(double value, double start, double stop, double targetStart, double
targetStop) {
return targetStart + (targetStop - targetStart) * ((value - start) / (stop - start));
}
public static void main(String[] args) {
launch(args);
}
}
Solution
mport javafx.application.Application;
import javafx.scene.Node;
import javafx.scene.Scene;
import javafx.scene.SnapshotParameters;
import javafx.scene.effect.ColorAdjust;
import javafx.scene.image.Image;
import javafx.scene.image.ImageView;
import javafx.scene.image.WritableImage;
import javafx.scene.layout.HBox;
import javafx.scene.paint.C.
In the above reaction the substrate is H2O2.Enzyme is CatalasePr.pdf
In the above reaction the substrate is H2O2.
Enzyme is Catalase
Products is Water and Oxygen.
Solution
In the above reaction the substrate is H2O2.
Enzyme is Catalase
Products is Water and Oxygen..
In genetics, dominant allele is always represented by uppercase lett.pdf
In genetics, dominant allele is always represented by uppercase letter. Therefore, IA allele is
dominant over \'i\' allele.
Solution
In genetics, dominant allele is always represented by uppercase letter. Therefore, IA allele is
dominant over \'i\' allele..
aside from the two given already, there is still .pdf
aside from the two given already, there is still one more correct statement: HCl is a
stronger acid than H2S because Cl is more electronegative than S.
Solution
aside from the two given already, there is still one more correct statement: HCl is a
stronger acid than H2S because Cl is more electronegative than S..
Al2(SO4)3.14H2O + 3Ca(HCO3)2 --- 2Al(OH)3 + 3CaS.pdf
Al2(SO4)3.14H2O + 3Ca(HCO3)2 ---> 2Al(OH)3 + 3CaSO4 + 6CO2 + 14H2O
Solution
Al2(SO4)3.14H2O + 3Ca(HCO3)2 ---> 2Al(OH)3 + 3CaSO4 + 6CO2 + 14H2O.
For two vectors U and A The vector component of U along A is give.pdf
For two vectors U and A :
The vector component of U along A is given as { (U.A)/||A||^2 } A
U =(14,7,7,14) ; A =(4, -4 ,2 , -2)
U.A = 14.4 -7.4 +7.2 -14.2 = 56-28+14-28 =14
||A||^2 = ( 4^2 +4^2+2^2 +2^2) =(16+16+4+4)= (40)
vector component of U along A is given as = (14/ 40)(A) =(14/ 40){4,-4,2,-2}
=(56/40 ,-56/40, 28/40 , -28/40)
vector component of U orthogonal to A is given as = vector U - vector component of U along A
= (14,7,7,14) -(56/40 ,-56/40, 28/40 , -28/40)
=(504/40 ,336/40 ,252/40 ,588/40)
Solution
For two vectors U and A :
The vector component of U along A is given as { (U.A)/||A||^2 } A
U =(14,7,7,14) ; A =(4, -4 ,2 , -2)
U.A = 14.4 -7.4 +7.2 -14.2 = 56-28+14-28 =14
||A||^2 = ( 4^2 +4^2+2^2 +2^2) =(16+16+4+4)= (40)
vector component of U along A is given as = (14/ 40)(A) =(14/ 40){4,-4,2,-2}
=(56/40 ,-56/40, 28/40 , -28/40)
vector component of U orthogonal to A is given as = vector U - vector component of U along A
= (14,7,7,14) -(56/40 ,-56/40, 28/40 , -28/40)
=(504/40 ,336/40 ,252/40 ,588/40).
Efforts to restore the number of apex predators includeHarbor sea.pdf
Efforts to restore the number of apex predators include:
Harbor seals in coastal regions of the Northeast Pacific Ocean (Olesiuk, 2010), and
Cheetahs in Tanzania (Kelly, 1998) reached desired increases in abundance and distribution
apart from this few more other important apex predators include:
Polar Bear: These mighty nomads are the largest land carnivores on earth . Polar bears have been
known to stake out blowholes in the ice for hours, waiting for seals to come up for a gulp of air.
African Lions: Panthera leo it is the female lioness that does most of the killing.
Hyenas: Crocuta crocuta which likes to prey on the aged and infirm.
Solution
Efforts to restore the number of apex predators include:
Harbor seals in coastal regions of the Northeast Pacific Ocean (Olesiuk, 2010), and
Cheetahs in Tanzania (Kelly, 1998) reached desired increases in abundance and distribution
apart from this few more other important apex predators include:
Polar Bear: These mighty nomads are the largest land carnivores on earth . Polar bears have been
known to stake out blowholes in the ice for hours, waiting for seals to come up for a gulp of air.
African Lions: Panthera leo it is the female lioness that does most of the killing.
Hyenas: Crocuta crocuta which likes to prey on the aged and infirm..
B. A switch is a device used to connect numerous computers together .pdf
B. A switch is a device used to connect numerous computers together in the same network
segment and that allows the full bandwidth of the network to be used between any two network
nodes connected to the switch.
Solution
B. A switch is a device used to connect numerous computers together in the same network
segment and that allows the full bandwidth of the network to be used between any two network
nodes connected to the switch..
ANS#include iostream int Rn_get(int low, int high); int cva.pdf
ANS:
#include
int Rn_get(int low, int high);
int cvalue(int card);
int toca(int deck[]);
int handva(const int hand[]);
bool pla_hand(char&);
bool draw_u(char&);
void inti(int deck[]);
void d_deck(int deck[], int size);
void dhudd(int deck[], int size);
void show_card(int card);
void card_s(const int cards[], int numCards, bool hideFirstCard);
void wiwh(const int pHand[], const int dHand[]);
void cbust(const int pHand[], const int dHand[], char p1);
void bbjack(const int pHand[], const int dHand[], char p1);
void nbjack(const int pHand[], const int dHand[], char p1);
void play_one();
void scboard(const int pHand[], const int dHand[]);
void bakkdor(const int hand[]);
void sffot(int pHand[]);
void go_to(int dHand[], int pHand[]);
void choo_def();
void sh_rules();
void add_hand(int hand[], int cardToAdd);
void stand_hit(int dHand[], int deck[], int pHand[]);
int tcard = 0;
float wi = 1.00;
int l_1;
int main()
{
sh_rules();
choo_def();
play_one();
return 1;
}
void sh_rules()
{
}
void choo_def()
{
cout << \"\ \";
cout << \"Level of Difficulty: Beginner (1), Expert (2). \";
cin >> l_1;
cout << \"\ \";
if(l_1 != 1)
{
if(l_1 != 2)
{
cin.clear();
cin.ignore(numeric_limits::max(), \'\ \');
cout << \"Please enter your l_1 of difficulty using the number 1 or 2.\" << endl;
choo_def();
}
}
}
void play_one()
{
char p1 = \'N\';
do
{
char dr = \'H\';
int deck[52];
inti(deck);
dhudd(deck, 51);
int pHand[10] = {0};
int dHand[10] = {0};
add_hand(pHand, toca(deck));
add_hand(dHand, toca(deck));
add_hand(pHand, toca(deck));
add_hand(dHand, toca(deck));
cout << \"The Dealer dhuddd and dealt you each your cards. \";
nbjack(pHand, dHand, \'y\');
bbjack(pHand, dHand, \'Y\');
cout << \"Your hand:\" << endl;
card_s(pHand, 10, false);
cout << \"\ \ Dealer\'s hand:\" << endl;
card_s(dHand, 10, true);
sffot(pHand);
while (draw_u(dr))
{
add_hand(pHand, toca(deck));
cout << \"The Dealer dealt you another card.\ \" << endl;
cout << \"Your hand:\" << endl;
card_s(pHand, 10, false);
sffot(pHand);
cbust(pHand, dHand, \'y\');
bbjack(pHand, dHand, \'Y\');
}
stand_hit(dHand, deck, pHand);
cout << endl;
cbust(pHand, dHand, \'Y\');
bbjack(pHand, dHand, \'Y\');
wiwh(pHand, dHand);
cout << endl;
cout << \"Winnings multiplier: \" << wi << endl;
}
while (pla_hand(p1));
}
void inti(int deck[])
{
int Rank = 101;
int i = 0;
for (i = 0 ; i<=13; i++)
{
deck[i] = Rank++;
}
for (i = 13 ; i<=26; i++)
{
deck[i] = Rank++ + 100 - 14;
}
for (i = 26 ; i<=39; i++)
{
deck[i] = Rank++ + 200 - 28;
}
for (i = 39 ; i<=51; i++)
{
deck[i] = Rank++ + 300 - 42;
}
}
void dhudd(int deck[], int size)
{
for(int i = 0; i < 500; i++)
{
int T1 = 0;
int R1 = Rn_get(0, size);
int R2 = Rn_get(0, size);
T1 = deck[R1];
deck[R1] = deck[R2];
deck[R2] = T1;
}
}
void show_card(int card)
{
if(card == 0)
{
cout << \"\";
}
else
{
switch(card % 100)
{
case 1:
cout << \"A\";
break;
case 11:
cout << \"J\";
break;
case 12:
cout << \"K\";
break;
case 13:
cout << \"Q\";
break;
case 14:
cout << \"A\";
break;
default:
cout << card % 100;.
a) Calcium chloride is used to create the competent cells as treatme.pdf
a) Calcium chloride is used to create the competent cells as treatment of cells with calcium
chloride makes transient pores in the cell wall of recepient cells (mostly prokaryotic cells)
making it permeable and allowing the passsage of foreign DNA insert into the cell. The cells
after treatment with calcium chloride are called as competent cells.
b) Antibiotics are the substances which are produced naturally by some living organisms so as to
check the growth of other organisms. Mostly fungi and some prokaryotes produce it. Antibiotics
are the pontential chemical which serve to inhibit the growth and infection of bacteria and
therefore, are used in prevention and cure of bacterial infections.
Solution
a) Calcium chloride is used to create the competent cells as treatment of cells with calcium
chloride makes transient pores in the cell wall of recepient cells (mostly prokaryotic cells)
making it permeable and allowing the passsage of foreign DNA insert into the cell. The cells
after treatment with calcium chloride are called as competent cells.
b) Antibiotics are the substances which are produced naturally by some living organisms so as to
check the growth of other organisms. Mostly fungi and some prokaryotes produce it. Antibiotics
are the pontential chemical which serve to inhibit the growth and infection of bacteria and
therefore, are used in prevention and cure of bacterial infections..
Mean is the average of given numbers.double array_mean(double a.pdf
// Mean is the average of given numbers.
double array_mean(double arr[], int num_items){
double sum=0;
for(int i=0;i< num_items;i++){
sum = sum + arr[i];
}
return sum/num_items;
}
Solution
// Mean is the average of given numbers.
double array_mean(double arr[], int num_items){
double sum=0;
for(int i=0;i< num_items;i++){
sum = sum + arr[i];
}
return sum/num_items;
}.
Walmart Business+ and Spark Good for Nonprofits.pdf
"Learn about all the ways Walmart supports nonprofit organizations.
You will hear from Liz Willett, the Head of Nonprofits, and hear about what Walmart is doing to help nonprofits, including Walmart Business and Spark Good. Walmart Business+ is a new offer for nonprofits that offers discounts and also streamlines nonprofits order and expense tracking, saving time and money.
The webinar may also give some examples on how nonprofits can best leverage Walmart Business+.
The event will cover the following::
Walmart Business + (https://business.walmart.com/plus) is a new shopping experience for nonprofits, schools, and local business customers that connects an exclusive online shopping experience to stores. Benefits include free delivery and shipping, a 'Spend Analytics” feature, special discounts, deals and tax-exempt shopping.
Special TechSoup offer for a free 180 days membership, and up to $150 in discounts on eligible orders.
Spark Good (walmart.com/sparkgood) is a charitable platform that enables nonprofits to receive donations directly from customers and associates.
Answers about how you can do more with Walmart!"
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touchesSolutiontouches.pdf
This very short document does not contain enough contextual information to generate a meaningful 3 sentence summary. The document consists of only 3 words with no other context provided.
There are various factors are responsible for reproductive isolation.pdf
There are various factors are responsible for reproductive isolation during the period of
geographical isolation.
1. Species specific breeding season: in this the species of same genus having different time for
breading will not able to interbreed. Failure of fertilization of egg: this is also happen even the
species are interbred.
2. Prezygotic isolation-
3. Postzygotic isolation-
Solution
There are various factors are responsible for reproductive isolation during the period of
geographical isolation.
1. Species specific breeding season: in this the species of same genus having different time for
breading will not able to interbreed. Failure of fertilization of egg: this is also happen even the
species are interbred.
2. Prezygotic isolation-
3. Postzygotic isolation-.
The film is a mix of social drama and comedy. The content is present.pdf
The film is a mix of social drama and comedy. The content is presented in a satire. How did
people survived the great depression of the world is being documented here. The conditions
werre miserable like acute shortage of work, factory closings, labor strikes and political unrest
etc.
Before we go on to the answers of the given questions lets first have a quick view on the possible
ehtical dilemmas of the film:
The major ethical dilemmas consist whether out of poverty stealing is right or wrong and
whether the replacement of labors for machines that makes the life of labors miserable is right or
wrong.. However this movie glorifies the struggle of the poor rather than verifying them for
stealing food to survive. By glorifying the struggle the movie takes on yet another social issue:
when the poor steal to eat it is not criminal, just survival. The entire movie is spent giving
specific (and comical) examples of the increasing futility of working for a living in a world
where machines and assembly lines are replacing skilled laborers. Minor ones include
1) The major ethical dillema of replacaement of skilled labors over machines leads to the
construct of the movie. The ethics of Modern Times is best represented in the closing scenes of
the film, starting with Chaplin’s sly and explicit dance, through to the closing credits, when
Chaplin and Goddard walk off into the sunrise, no scene drives it home as well as does the final
scene, when they give up and move on.
The dilemmas that are still remain unanswered include many such as, spying of employers on
employees; in the world of progress does honesty has its place as soon as Goddard obtains
money through hard work, she is arrested for prior vagrancy, thus throwing her back into
vagrancy; etc.
2) Spying is a clear cut threat to privacy of individuals. Although it is necessary to make
effeciecny through labor works but adopting such method is extreme autocratic that makes only
employees disgust and left them to disloyal to employers. Employees need to be motivated
through great leadership various incentives, attachment to the company to make best out of them.
Honesty can not be left in vain in any stage of progress in world. It is a prerequiste to have best
welfare of the societ as whole in fast developments in the economies that may lead to threat to
welfare in general. Goddard should have not run from the prior crime as it had led her into
another crime of being run away from law.
Solution
The film is a mix of social drama and comedy. The content is presented in a satire. How did
people survived the great depression of the world is being documented here. The conditions
werre miserable like acute shortage of work, factory closings, labor strikes and political unrest
etc.
Before we go on to the answers of the given questions lets first have a quick view on the possible
ehtical dilemmas of the film:
The major ethical dilemmas consist whether out of poverty stealing is right or wrong and
whether the .
The chart shows how to interpret the experimental results to identif.pdf
The chart shows how to interpret the experimental results to identify unknown species. Suppose
you started the experiment with collection of sample. The nature of sample itself gives some idea
on what is to be identified. Let the sample is stool sample collected froma person suffering from
diarrhea. The suspected organisms are gram negative enteropathogens like E. coli, Shigella
(though it causes dysentry and not diarrhea), Salmonella, Vibrio, etc.
The sample is initially processed and inoculated on suitable bacteriological medium. Let the
sample is inoculated on EMB agar, thiosulfate-citrate-bile salts sucrose agar, and wilson and
blair bismuth sulfite agar. If colonies are found on EMB agar, the suspected organisms are
enterobacteriaceae.
The colony morphology is observed initially, the size, color, margins, texture, all indicate colony
morphology. If black colonies with metallic sheen is seen, it indicates E.coli. Pink color colonies
indicate Enterobacter. Further confirmation is done through gram staining. Gram staining gives
the result if the organism is gram positive or gram negative.
If the organism is gram negative, to further differentiate among the enterobacteriaceae, IMVIC
tests are done. Each organims of enterobacteriaceae show specific patterns of results for IMVIC
tests. Biochemical tests like oxidase and catalase help to differentiate if the organism is aerobic
or anaerobic.
Solution
The chart shows how to interpret the experimental results to identify unknown species. Suppose
you started the experiment with collection of sample. The nature of sample itself gives some idea
on what is to be identified. Let the sample is stool sample collected froma person suffering from
diarrhea. The suspected organisms are gram negative enteropathogens like E. coli, Shigella
(though it causes dysentry and not diarrhea), Salmonella, Vibrio, etc.
The sample is initially processed and inoculated on suitable bacteriological medium. Let the
sample is inoculated on EMB agar, thiosulfate-citrate-bile salts sucrose agar, and wilson and
blair bismuth sulfite agar. If colonies are found on EMB agar, the suspected organisms are
enterobacteriaceae.
The colony morphology is observed initially, the size, color, margins, texture, all indicate colony
morphology. If black colonies with metallic sheen is seen, it indicates E.coli. Pink color colonies
indicate Enterobacter. Further confirmation is done through gram staining. Gram staining gives
the result if the organism is gram positive or gram negative.
If the organism is gram negative, to further differentiate among the enterobacteriaceae, IMVIC
tests are done. Each organims of enterobacteriaceae show specific patterns of results for IMVIC
tests. Biochemical tests like oxidase and catalase help to differentiate if the organism is aerobic
or anaerobic..
Solution-D. Providing more favorable financial information.Expla.pdf
Solution
-
D. Providing more favorable financial information.
Explanation-
Internal control is important aspect for any company, in internal control the main focus area is
financial information because that information helps the company stakeholders as well as
company perfomance amongst the shareholders..
Implementing Systems OverviewHealth information technology (HIT) e.pdf
Implementing Systems Overview
Health information technology (HIT) encompasses implementing a broad scope of applications,
technology, and operational activities (1.1 HIT Visioning and Strategic Planning), depending on
your organization and its goals (1.2 Goal Setting). This tool provides an overview of a typical
implementation of an electronic health record (EHR) system for a hospital. Use this tool to
understand the broad range of topics that you will need to consider during HIT implementation.
Overview of Implementation
Although specifics with respect to an implementation will vary by vendor and application, any
implementation should follow a similar high level structure:
1. Project management
2. Workflow and process redesign
3. Detailed plan creation
4. Issues management
5. Workflow and process redesign
6. Preparing for and installing hardware
7. Network development/refinement
8. Security risk analysis and controls
9. Super user training
10. Software installation and system configuration (a.k.a., “system build”), including report
writing, interfaces, data conversion
11. Testing
12. End user training
13. Preparation for go live
14. Go live
15. Benefits realization and recognition
16. Optimization strategies
Project Management
Even though your vendor will supply significant project support, you need to designate an
individual within your hospital to be the project manager, representing your interests and
ensuring that information learned during the process is retained within the hospital for future
reference. (1.2 Project Management, 1.2 Project Management Job Description)
Your project manager will be responsible for many activities:
o Managing your harmonized project plan, making sure the project gets completed on time and
within budget.
o Organizing your staff resources, team building, maintaining the project budget, approving
invoices, and handling other elements of making sure the hospital completes the designated tasks
on the project plan completely, accurately, and on time.
o Carrying out your communication plan (1.1 Communication Plan), including reminding others
to perform their necessary communications and potentially even scripting them for others such as
the CEO.
Workflow and Process Redesign
Ideally during the planning phases you will map current workflows and processes, using these to
initiate change management and create expectations to achieve goals, to help you identify system
requirements and select the most appropriate vendor, and potentially even to make adjustments
in workflows and processes today where streamlining or other improvements are feasible without
HIT. Mapping current workflows and processes gives you slightly less work to do during
implementation. This step is essential for configuring the system to your specifications and
anticipating changes with the new system.
Over just the past few years, the industry as a whole has come to recognize that not attending to
workflow and process redesign during HIT planning .
Second option is the correct one dear... sorry i was unable to uploa.pdf
Second option is the correct one dear... sorry i was unable to upload the image again
H = -ve
S = -Ve
G = -ve
Solution
Second option is the correct one dear... sorry i was unable to upload the image again
H = -ve
S = -Ve
G = -ve.
proofSolutionproof.pdf
This very short document does not contain enough contextual information to generate a meaningful 3 sentence summary. It consists of only 4 words with no other context provided.
Ph = - log(1.0x10-2)= 2 log(10)= 2SolutionPh = - log(1.0x1.pdf
The document shows the calculation of the pH of a solution that has a hydrogen ion concentration of 1.0x10-2. It takes the negative logarithm of the hydrogen ion concentration to get the pH, which equals 2 log(10) or simply 2.
mport javafx.application.Application;import javafx.scene.Node;im.pdf
mport javafx.application.Application;
import javafx.scene.Node;
import javafx.scene.Scene;
import javafx.scene.SnapshotParameters;
import javafx.scene.effect.ColorAdjust;
import javafx.scene.image.Image;
import javafx.scene.image.ImageView;
import javafx.scene.image.WritableImage;
import javafx.scene.layout.HBox;
import javafx.scene.paint.Color;
import javafx.scene.paint.CycleMethod;
import javafx.scene.paint.RadialGradient;
import javafx.scene.paint.Stop;
import javafx.scene.shape.Circle;
import javafx.stage.Stage;
public class Main extends Application {
@Override
public void start(Stage primaryStage) {
HBox root = new HBox();
// create alpha masked image
Image image = createImage(createAlphaMaskedRing(200));
// create original imageview
ImageView original = new ImageView( image);
// create imageview with color adjustment
ImageView modified = new ImageView( image);
// colorAdjust effect
ColorAdjust colorAdjust = new ColorAdjust();
// set saturation to 1, otherwise hue won\'t have an effect
colorAdjust.setSaturation(1);
// define target color
Color targetColor = Color.GREEN;
// calculate hue: map from [0,360] to [-1,1]; TODO: here\'s the problem
double hue = map( targetColor.getHue(), 0, 360, -1, 1);
colorAdjust.setHue(hue);
// apply color adjustment
modified.setEffect(colorAdjust);
root.getChildren().addAll( original, modified);
Scene scene = new Scene(root,1024,500, Color.yellow);
primaryStage.setScene(scene);
primaryStage.show();
}
/**
* Snapshot an image out of a node, consider transparency.
* @param node
* @return
*/
public static Image createImage( Node node) {
WritableImage wi;
SnapshotParameters parameters = new SnapshotParameters();
parameters.setFill(Color.TRANSPARENT);
int imageWidth = (int) node.getBoundsInLocal().getWidth();
int imageHeight = (int) node.getBoundsInLocal().getHeight();
wi = new WritableImage( imageWidth, imageHeight)
node.snapshot(parameters, wi);
return wi;
}
/**
* Create an alpha masked ring with gradient colors from Blueto Yellow/Transparent. Used e.
g. for particles.
*
* @param radius
* @return
*/
public static Node createAlphaMaskedRing( double radius) {
Circle ring = new Circle(radius);
RadialGradient gradient1 = new RadialGradient(0,
.1,
0,
0,
radius,
false,
CycleMethod.NO_CYCLE,
new Stop(0, Color.WHITE.deriveColor(1,1,1,1)),
new Stop(1, Color.YELLOW.deriveColor(1,1,1,0)));
ring.setFill(gradient1);
return ring;
}
public static double map(double value, double start, double stop, double targetStart, double
targetStop) {
return targetStart + (targetStop - targetStart) * ((value - start) / (stop - start));
}
public static void main(String[] args) {
launch(args);
}
}
Solution
mport javafx.application.Application;
import javafx.scene.Node;
import javafx.scene.Scene;
import javafx.scene.SnapshotParameters;
import javafx.scene.effect.ColorAdjust;
import javafx.scene.image.Image;
import javafx.scene.image.ImageView;
import javafx.scene.image.WritableImage;
import javafx.scene.layout.HBox;
import javafx.scene.paint.C.
In the above reaction the substrate is H2O2.Enzyme is CatalasePr.pdf
In the above reaction the substrate is H2O2.
Enzyme is Catalase
Products is Water and Oxygen.
Solution
In the above reaction the substrate is H2O2.
Enzyme is Catalase
Products is Water and Oxygen..
In genetics, dominant allele is always represented by uppercase lett.pdf
In genetics, dominant allele is always represented by uppercase letter. Therefore, IA allele is
dominant over \'i\' allele.
Solution
In genetics, dominant allele is always represented by uppercase letter. Therefore, IA allele is
dominant over \'i\' allele..
aside from the two given already, there is still .pdf
aside from the two given already, there is still one more correct statement: HCl is a
stronger acid than H2S because Cl is more electronegative than S.
Solution
aside from the two given already, there is still one more correct statement: HCl is a
stronger acid than H2S because Cl is more electronegative than S..
Al2(SO4)3.14H2O + 3Ca(HCO3)2 --- 2Al(OH)3 + 3CaS.pdf
Al2(SO4)3.14H2O + 3Ca(HCO3)2 ---> 2Al(OH)3 + 3CaSO4 + 6CO2 + 14H2O
Solution
Al2(SO4)3.14H2O + 3Ca(HCO3)2 ---> 2Al(OH)3 + 3CaSO4 + 6CO2 + 14H2O.
For two vectors U and A The vector component of U along A is give.pdf
For two vectors U and A :
The vector component of U along A is given as { (U.A)/||A||^2 } A
U =(14,7,7,14) ; A =(4, -4 ,2 , -2)
U.A = 14.4 -7.4 +7.2 -14.2 = 56-28+14-28 =14
||A||^2 = ( 4^2 +4^2+2^2 +2^2) =(16+16+4+4)= (40)
vector component of U along A is given as = (14/ 40)(A) =(14/ 40){4,-4,2,-2}
=(56/40 ,-56/40, 28/40 , -28/40)
vector component of U orthogonal to A is given as = vector U - vector component of U along A
= (14,7,7,14) -(56/40 ,-56/40, 28/40 , -28/40)
=(504/40 ,336/40 ,252/40 ,588/40)
Solution
For two vectors U and A :
The vector component of U along A is given as { (U.A)/||A||^2 } A
U =(14,7,7,14) ; A =(4, -4 ,2 , -2)
U.A = 14.4 -7.4 +7.2 -14.2 = 56-28+14-28 =14
||A||^2 = ( 4^2 +4^2+2^2 +2^2) =(16+16+4+4)= (40)
vector component of U along A is given as = (14/ 40)(A) =(14/ 40){4,-4,2,-2}
=(56/40 ,-56/40, 28/40 , -28/40)
vector component of U orthogonal to A is given as = vector U - vector component of U along A
= (14,7,7,14) -(56/40 ,-56/40, 28/40 , -28/40)
=(504/40 ,336/40 ,252/40 ,588/40).
Efforts to restore the number of apex predators includeHarbor sea.pdf
Efforts to restore the number of apex predators include:
Harbor seals in coastal regions of the Northeast Pacific Ocean (Olesiuk, 2010), and
Cheetahs in Tanzania (Kelly, 1998) reached desired increases in abundance and distribution
apart from this few more other important apex predators include:
Polar Bear: These mighty nomads are the largest land carnivores on earth . Polar bears have been
known to stake out blowholes in the ice for hours, waiting for seals to come up for a gulp of air.
African Lions: Panthera leo it is the female lioness that does most of the killing.
Hyenas: Crocuta crocuta which likes to prey on the aged and infirm.
Solution
Efforts to restore the number of apex predators include:
Harbor seals in coastal regions of the Northeast Pacific Ocean (Olesiuk, 2010), and
Cheetahs in Tanzania (Kelly, 1998) reached desired increases in abundance and distribution
apart from this few more other important apex predators include:
Polar Bear: These mighty nomads are the largest land carnivores on earth . Polar bears have been
known to stake out blowholes in the ice for hours, waiting for seals to come up for a gulp of air.
African Lions: Panthera leo it is the female lioness that does most of the killing.
Hyenas: Crocuta crocuta which likes to prey on the aged and infirm..
B. A switch is a device used to connect numerous computers together .pdf
B. A switch is a device used to connect numerous computers together in the same network
segment and that allows the full bandwidth of the network to be used between any two network
nodes connected to the switch.
Solution
B. A switch is a device used to connect numerous computers together in the same network
segment and that allows the full bandwidth of the network to be used between any two network
nodes connected to the switch..
ANS#include iostream int Rn_get(int low, int high); int cva.pdf
ANS:
#include
int Rn_get(int low, int high);
int cvalue(int card);
int toca(int deck[]);
int handva(const int hand[]);
bool pla_hand(char&);
bool draw_u(char&);
void inti(int deck[]);
void d_deck(int deck[], int size);
void dhudd(int deck[], int size);
void show_card(int card);
void card_s(const int cards[], int numCards, bool hideFirstCard);
void wiwh(const int pHand[], const int dHand[]);
void cbust(const int pHand[], const int dHand[], char p1);
void bbjack(const int pHand[], const int dHand[], char p1);
void nbjack(const int pHand[], const int dHand[], char p1);
void play_one();
void scboard(const int pHand[], const int dHand[]);
void bakkdor(const int hand[]);
void sffot(int pHand[]);
void go_to(int dHand[], int pHand[]);
void choo_def();
void sh_rules();
void add_hand(int hand[], int cardToAdd);
void stand_hit(int dHand[], int deck[], int pHand[]);
int tcard = 0;
float wi = 1.00;
int l_1;
int main()
{
sh_rules();
choo_def();
play_one();
return 1;
}
void sh_rules()
{
}
void choo_def()
{
cout << \"\ \";
cout << \"Level of Difficulty: Beginner (1), Expert (2). \";
cin >> l_1;
cout << \"\ \";
if(l_1 != 1)
{
if(l_1 != 2)
{
cin.clear();
cin.ignore(numeric_limits::max(), \'\ \');
cout << \"Please enter your l_1 of difficulty using the number 1 or 2.\" << endl;
choo_def();
}
}
}
void play_one()
{
char p1 = \'N\';
do
{
char dr = \'H\';
int deck[52];
inti(deck);
dhudd(deck, 51);
int pHand[10] = {0};
int dHand[10] = {0};
add_hand(pHand, toca(deck));
add_hand(dHand, toca(deck));
add_hand(pHand, toca(deck));
add_hand(dHand, toca(deck));
cout << \"The Dealer dhuddd and dealt you each your cards. \";
nbjack(pHand, dHand, \'y\');
bbjack(pHand, dHand, \'Y\');
cout << \"Your hand:\" << endl;
card_s(pHand, 10, false);
cout << \"\ \ Dealer\'s hand:\" << endl;
card_s(dHand, 10, true);
sffot(pHand);
while (draw_u(dr))
{
add_hand(pHand, toca(deck));
cout << \"The Dealer dealt you another card.\ \" << endl;
cout << \"Your hand:\" << endl;
card_s(pHand, 10, false);
sffot(pHand);
cbust(pHand, dHand, \'y\');
bbjack(pHand, dHand, \'Y\');
}
stand_hit(dHand, deck, pHand);
cout << endl;
cbust(pHand, dHand, \'Y\');
bbjack(pHand, dHand, \'Y\');
wiwh(pHand, dHand);
cout << endl;
cout << \"Winnings multiplier: \" << wi << endl;
}
while (pla_hand(p1));
}
void inti(int deck[])
{
int Rank = 101;
int i = 0;
for (i = 0 ; i<=13; i++)
{
deck[i] = Rank++;
}
for (i = 13 ; i<=26; i++)
{
deck[i] = Rank++ + 100 - 14;
}
for (i = 26 ; i<=39; i++)
{
deck[i] = Rank++ + 200 - 28;
}
for (i = 39 ; i<=51; i++)
{
deck[i] = Rank++ + 300 - 42;
}
}
void dhudd(int deck[], int size)
{
for(int i = 0; i < 500; i++)
{
int T1 = 0;
int R1 = Rn_get(0, size);
int R2 = Rn_get(0, size);
T1 = deck[R1];
deck[R1] = deck[R2];
deck[R2] = T1;
}
}
void show_card(int card)
{
if(card == 0)
{
cout << \"\";
}
else
{
switch(card % 100)
{
case 1:
cout << \"A\";
break;
case 11:
cout << \"J\";
break;
case 12:
cout << \"K\";
break;
case 13:
cout << \"Q\";
break;
case 14:
cout << \"A\";
break;
default:
cout << card % 100;.
a) Calcium chloride is used to create the competent cells as treatme.pdf
a) Calcium chloride is used to create the competent cells as treatment of cells with calcium
chloride makes transient pores in the cell wall of recepient cells (mostly prokaryotic cells)
making it permeable and allowing the passsage of foreign DNA insert into the cell. The cells
after treatment with calcium chloride are called as competent cells.
b) Antibiotics are the substances which are produced naturally by some living organisms so as to
check the growth of other organisms. Mostly fungi and some prokaryotes produce it. Antibiotics
are the pontential chemical which serve to inhibit the growth and infection of bacteria and
therefore, are used in prevention and cure of bacterial infections.
Solution
a) Calcium chloride is used to create the competent cells as treatment of cells with calcium
chloride makes transient pores in the cell wall of recepient cells (mostly prokaryotic cells)
making it permeable and allowing the passsage of foreign DNA insert into the cell. The cells
after treatment with calcium chloride are called as competent cells.
b) Antibiotics are the substances which are produced naturally by some living organisms so as to
check the growth of other organisms. Mostly fungi and some prokaryotes produce it. Antibiotics
are the pontential chemical which serve to inhibit the growth and infection of bacteria and
therefore, are used in prevention and cure of bacterial infections..
Mean is the average of given numbers.double array_mean(double a.pdf
// Mean is the average of given numbers.
double array_mean(double arr[], int num_items){
double sum=0;
for(int i=0;i< num_items;i++){
sum = sum + arr[i];
}
return sum/num_items;
}
Solution
// Mean is the average of given numbers.
double array_mean(double arr[], int num_items){
double sum=0;
for(int i=0;i< num_items;i++){
sum = sum + arr[i];
}
return sum/num_items;
}.
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