For this micro assignment, you must implement two Linked List functi.docx
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For this micro assignment, you must implement two Linked List functions. We will use the following example Linked List: 2 0 -1 5 7 getElementAt(index) This function should return the element (i.e. value) of the Nth item inside the linked list. For example, on the Linked List above, getElementAt(0) should return 2; getElementAt(3) should return 5. addElementAt(value, location) This function should insert a new value at the given location. Note that the location supplied must be within bounds of the LinkedList. For example, we cannot call addElementAt(4, 11) on the above Linked List because 11 is beyond the size of the Linked List. Here are some examples. If we call addElementAt(0, 1), the above Linked List would now look like: 1 2 0 -1 5 7 If we again call addElementAt(2, 123), we would get: 1 2 123 0 -1 5 7 Grading Your submission will be graded based on the following: 1. [7] Your solution does not cause any runtime issues and your file passes all test cases 2. [3] Your code contains good style. For example, You provide meaningful variable names You provide sufficient and meaningful comments Your code is well structured @@@@@@@@@@@@@@@@@@@@@@@@ #ifndef LINKED_LIST_H #define LINKED_LIST_H #include #include #include "LinkedListNode.h" #include using namespace std; template class LinkedList { private: //points to the front of the linked list LinkedListNode *_front = nullptr; //keeping track of size in a variable eliminates need to continually //count LL boxes. int _size = 0; protected: //creates a new LinkedListNode for us virtual LinkedListNode *createNode(T value) { return new LinkedListNode < T > { value }; } public: //default constructor LinkedList() { _front = nullptr; } //copy constructor LinkedList(const LinkedList &other) { for (int i = 0; i < other.getSize(); i++) { addElement(other.getElementAt(i)); } } //move constructor LinkedList(LinkedList &&other) { //take other's data _front = other._front; _size = other._size; //reset other's pointers other._front = nullptr; } //initializer list constructor LinkedList(initializer_list values) { for (auto item : values) { addElement(item); } } //Always remember to clean up pointers in destructor! virtual ~LinkedList() { LinkedListNode *current = _front; while (current != nullptr) { LinkedListNode *temp = current->getNext(); delete current; current = temp; } } //will return true if the LL is empty. virtual bool isEmpty() const { return _size == 0; } //returns the size of the LL. virtual int getSize() const { return _size; } .
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![Grading
Your submission will be graded based on the following:
1. [7] Your solution does not cause any runtime issues and your
file passes all test cases
2. [3] Your code contains good style. For example,
ble names
@@@@@@@@@@@@@@@@@@@@@@@@
#ifndef LINKED_LIST_H
#define LINKED_LIST_H
#include
#include
#include "LinkedListNode.h"
#include
using namespace std;](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Recommended
This assignment and the next (#5) involve design and development of a.pdf
This assignment and the next (#5) involve design and development of a sequential
non contiguous and dynamic datastructure called LinkedList. A linked list object is
a container consisting of connected ListNode objects. As before, we are not going
to use pre-fabricated classes from the c++ library, but construct the LinkedList
ADT from scratch.
The first step is construction and testing of the ListNode class. A ListNode object
contains a data field and a pointer to the next ListNode object (note the recursive
definition).
#This assignment requires you to
1. Read the Assignment 4 Notes
2. Watch the Assignment 4 Support video
3. Implement the following methods of the ListNode class
-custom constructor
-setters for next pointer and data
4. Implement the insert and remove method in the main program
5. Scan the given template to find the above //TODO and implement the code
needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
void insert(ListNode<int> * &front,int value)
# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
#include <iostream>
#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
How do I fix it in LinkedList.javaLinkedList.java Define.pdf
How do I fix it in LinkedList.java?
LinkedList.java:
/**
* Defines a doubly-linked list class
* @author
* @author
*/
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
public T getFirst() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
if (iterator != null){
return iterator.data;
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return length;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return length == 0;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return iterator == null;
}
/**** MUTATORS ****/
public void addFirst(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
public void addLast(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIterator(T data) throws NullPointerException{
if(iterator != null){
Node newNode = new Node(data);
newNode.next = iterator.next;
iterator.next = newNode;
if (iterator == first){
first = newNode;
}
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/
public void removeFirst() throws NoSuchElementExcept.
LabProgram.javaimport java.util.NoSuchElementException;public .pdf
LabProgram.java
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
/**
* Returns the value stored in the first node
* @precondition <>
* @return the value stored at node first
* @throws NoSuchElementException <>
*/
public T getFirst() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
/**
* Returns the value stored in the last node
* @precondition <>
* @return the value stored in the node last
* @throws NoSuchElementException <>
*/
public T getLast() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
return iterator.data;
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return length;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return length == 0;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return iterator == null;
}
/**** MUTATORS ****/
/**
* Creates a new first element
* @param data the data to insert at the front of the LinkedList
* @postcondition <>
*/
public void addFirst(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
/**
* Creates a new last element
* @param data the data to insert at the end of the LinkedList
* @postcondition <>
*/
public void addLast(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIter.
How do I fix it in LinkedList.javaLabProgram.javaLinkedList.jav.pdf
How do I fix it in LinkedList.java?
LabProgram.java
LinkedList.java:
/**
* Defines a doubly-linked list class
* @author
* @author
*/
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
public T getFirst() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
if (iterator != null){
return iterator.data;
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return length;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return length == 0;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return iterator == null;
}
/**** MUTATORS ****/
public void addFirst(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
public void addLast(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIterator(T data) throws NullPointerException{
if(iterator != null){
Node newNode = new Node(data);
newNode.next = iterator.next;
iterator.next = newNode;
if (iterator == first){
first = newNode;
}
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/
public void removeFirst() throws NoS.
How do I fix it in javaLinkedList.java Defines a doubl.pdf
How do I fix it in java?
LinkedList.java:
/**
* Defines a doubly-linked list class
* @author
* @author
*/
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
public T getFirst() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
if (iterator != null){
return iterator.data;
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return length;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return length == 0;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return iterator == null;
}
/**** MUTATORS ****/
public void addFirst(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
public void addLast(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIterator(T data) throws NullPointerException{
if(iterator != null){
Node newNode = new Node(data);
newNode.next = iterator.next;
iterator.next = newNode;
if (iterator == first){
first = newNode;
}
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/
public void removeFirst() throws NoSuchElementException {
if(is.
import java-util--- public class MyLinkedList{ public static void.pdf
import java.util.*; public class MyLinkedList{ public static void main(String[] args){ } } //copy
MyList to here interface MyList extends Collection { /* MyList will inherite all methods from
Collection public boolean add(E e); public boolean addAll(Collection extends E> c); public void
clear(); public boolean contains(Object o); public boolean containsAll(Collection> c); public
boolean isEmpty(); public boolean remove(Object o); public boolean removeAll(Collection> c);
public boolean retainAll(Collection> c); public int size(); public Object[] toArray(); public T[]
toArray(T[] arr); */ //abstract method public void add(int index, E e); public E get(int index);
public int indexOf(Object e); public int lastIndexOf(E e); public E remove(int index); public E
set(int index, E e); //default method @Override public default boolean add(E e){ add(size(), e);
return true; } @Override public default boolean isEmpty(){ return size()==0; } @Override
public default boolean remove(Object e){ if(indexOf(e) >= 0){ remove(indexOf(e)); return true;
} else{ return false; } } @Override public default boolean containsAll(Collection> c){
for(Object e : c){ if(!contains(e)){ return false; } } return true; } @Override public default
boolean addAll( Collection extends E> c){ for(E e : c){ add(e); } return true; } /* removeAll:
this[1,1,2,3] c[1,2,4] this.removeAll(c) [3] */ @Override public default boolean removeAll(
Collection> c){ for(Object e : c){ while(contains(e)){ this.remove(e); } } return true; } /*
retainAll this[1,1,2,3] c[1,2,4] this.retainAll(c) [1,1,2] */ @Override public default boolean
retainAll( Collection> c){ for(E e : this){ if(!c.contains(e)){ this.remove(e); } } return true; }
@Override public default Object[] toArray(){ Object[] results = new Object[size()]; int i = 0;
for(E e : this){ results[i++] = e; } return results; } /* T[] array */ @Override public default T[]
toArray(T[] array){ int i = 0; for(E e : this){ array[i++] = (T)e; } return array; } } class
TwoWayLinkedList implements MyList { //inner static class Node public class Node { E
element; Node next; Node previous; public Node(E e){ element = e; } } private Node head, tail;
private int size = 0; public TwoWayLinkedList(){ /* head = null; tail = null; size = 0; */ } public
TwoWayLinkedList(E[] objects){ } public E getFirst(){ return null; } public E getLast(){ return
null; } public void addFirst(E e){ } public void addLast(E e){ } public E removeFirst(){ return
null; } public E removeLast(){ return null; } @Override public void add(int index, E e){ }
@Override public E remove(int index){ return null; } @Override public void clear(){ }
@Override public boolean contains(Object e){ return false; } @Override public E get(int index){
return null; } @Override public int indexOf(Object e){ return -1; } @Override public int
lastIndexOf(Object e){ return -1; } @Override public E set(int index, E e){ return null; }
@Override public int size(){ return size; } //toString() @Override public String.
could you implement this function please, im having issues with it..pdf
could you implement this function please, im having issues with it.
void makeList (const ListNode::value_type [],const size_t& count)
class ListNode
{
public:
typedef int value_type;
ListNode (value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum () const { return datum; }
ListNode const* getNext () const { return next; }
//Mutator
void setDatum (const value_type& d) {datum = d; }
ListNode* getNext () { return next; }
void setNext (ListNode* new_link) {next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList ();
virtual ~LinkedList ();
void insertItem (ListNode::value_type);
void makeList (const ListNode::value_type [],const size_t& count);
void deleteList ();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
This is the pseudocode, but i still have a hard time undertanding it.
Creating a List (makeList(const ListNode::value_type [],const size_t& count)) This function
receives an array in the order that we want to add it to the linkedlist. Index 0 will be the head
node, index n will be the last node.
First, create a node initialized with a data value and a NULL pointer. Set the \"head\" to point to
the first node. Set up a current-pointer to the first node (or \"head\"). Get a data value for the next
node. While more nodes to add { Create a new node initialized with the data value and a NULL
pointer. Set the current-pointer link member (\"next\") to the new node. Set the current-pointer to
point to the new node. Get a data value for the next node. }
Thanks.
Solution
//linkedList.h
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
#include
#include
class ListNode
{
public:
typedef int value_type;
ListNode(value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum() const { return datum; }
ListNode const* getNext() const { return next; }
//Mutator
void setDatum(const value_type& d) { datum = d; }
ListNode* getNext() { return next; }
void setNext(ListNode* new_link) { next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList();
virtual ~LinkedList();
void insertItem(ListNode::value_type);
void makeList(const ListNode::value_type[], const size_t& count);
void deleteList();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
#endif
-------------------------------------------------------------
//linkedList.cpp
#include \"linkedlist.h\"
LinkedList::LinkedList()
{
head = NULL;
}
LinkedList::~LinkedList()
{
ListNode *tmp = head;
while (tmp != NULL)
{
head = head->getNext();
delete tmp;
tmp = head;
}
}
void LinkedList::insertItem(ListNode::value_type item)
{
ListNode *newNode,*cur = head;
newNode = new ListNode;
newNode->setDatum(item);
newNode->setNext(NULL);.
C++ Please write the whole code that is needed for this assignment- wr.docx
Brianca plans to save $5,000, $1,000, and $42,000 a year over the next three years, respectively. How much would you need to deposit in one lump sum today to have the same amount as Brianca three years from now if you both earn 10.9 percent, compounded annually? $36,115 $35,192 $43,282 $41,635 $35,372
.
Recommended
This assignment and the next (#5) involve design and development of a.pdf
This assignment and the next (#5) involve design and development of a sequential
non contiguous and dynamic datastructure called LinkedList. A linked list object is
a container consisting of connected ListNode objects. As before, we are not going
to use pre-fabricated classes from the c++ library, but construct the LinkedList
ADT from scratch.
The first step is construction and testing of the ListNode class. A ListNode object
contains a data field and a pointer to the next ListNode object (note the recursive
definition).
#This assignment requires you to
1. Read the Assignment 4 Notes
2. Watch the Assignment 4 Support video
3. Implement the following methods of the ListNode class
-custom constructor
-setters for next pointer and data
4. Implement the insert and remove method in the main program
5. Scan the given template to find the above //TODO and implement the code
needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
void insert(ListNode<int> * &front,int value)
# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
#include <iostream>
#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
How do I fix it in LinkedList.javaLinkedList.java Define.pdf
How do I fix it in LinkedList.java?
LinkedList.java:
/**
* Defines a doubly-linked list class
* @author
* @author
*/
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
public T getFirst() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
if (iterator != null){
return iterator.data;
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return length;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return length == 0;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return iterator == null;
}
/**** MUTATORS ****/
public void addFirst(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
public void addLast(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIterator(T data) throws NullPointerException{
if(iterator != null){
Node newNode = new Node(data);
newNode.next = iterator.next;
iterator.next = newNode;
if (iterator == first){
first = newNode;
}
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/
public void removeFirst() throws NoSuchElementExcept.
LabProgram.javaimport java.util.NoSuchElementException;public .pdf
LabProgram.java
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
/**
* Returns the value stored in the first node
* @precondition <>
* @return the value stored at node first
* @throws NoSuchElementException <>
*/
public T getFirst() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
/**
* Returns the value stored in the last node
* @precondition <>
* @return the value stored in the node last
* @throws NoSuchElementException <>
*/
public T getLast() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
return iterator.data;
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return length;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return length == 0;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return iterator == null;
}
/**** MUTATORS ****/
/**
* Creates a new first element
* @param data the data to insert at the front of the LinkedList
* @postcondition <>
*/
public void addFirst(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
/**
* Creates a new last element
* @param data the data to insert at the end of the LinkedList
* @postcondition <>
*/
public void addLast(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIter.
How do I fix it in LinkedList.javaLabProgram.javaLinkedList.jav.pdf
How do I fix it in LinkedList.java?
LabProgram.java
LinkedList.java:
/**
* Defines a doubly-linked list class
* @author
* @author
*/
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
public T getFirst() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
if (iterator != null){
return iterator.data;
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return length;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return length == 0;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return iterator == null;
}
/**** MUTATORS ****/
public void addFirst(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
public void addLast(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIterator(T data) throws NullPointerException{
if(iterator != null){
Node newNode = new Node(data);
newNode.next = iterator.next;
iterator.next = newNode;
if (iterator == first){
first = newNode;
}
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/
public void removeFirst() throws NoS.
How do I fix it in javaLinkedList.java Defines a doubl.pdf
How do I fix it in java?
LinkedList.java:
/**
* Defines a doubly-linked list class
* @author
* @author
*/
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
public T getFirst() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (isEmpty()){
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
if (iterator != null){
return iterator.data;
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return length;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return length == 0;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return iterator == null;
}
/**** MUTATORS ****/
public void addFirst(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
public void addLast(T data) {
Node newNode = new Node(data);
if(isEmpty()){
first = newNode;
last = newNode;
}
else{
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIterator(T data) throws NullPointerException{
if(iterator != null){
Node newNode = new Node(data);
newNode.next = iterator.next;
iterator.next = newNode;
if (iterator == first){
first = newNode;
}
}else{
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
/
public void removeFirst() throws NoSuchElementException {
if(is.
import java-util--- public class MyLinkedList{ public static void.pdf
import java.util.*; public class MyLinkedList{ public static void main(String[] args){ } } //copy
MyList to here interface MyList extends Collection { /* MyList will inherite all methods from
Collection public boolean add(E e); public boolean addAll(Collection extends E> c); public void
clear(); public boolean contains(Object o); public boolean containsAll(Collection> c); public
boolean isEmpty(); public boolean remove(Object o); public boolean removeAll(Collection> c);
public boolean retainAll(Collection> c); public int size(); public Object[] toArray(); public T[]
toArray(T[] arr); */ //abstract method public void add(int index, E e); public E get(int index);
public int indexOf(Object e); public int lastIndexOf(E e); public E remove(int index); public E
set(int index, E e); //default method @Override public default boolean add(E e){ add(size(), e);
return true; } @Override public default boolean isEmpty(){ return size()==0; } @Override
public default boolean remove(Object e){ if(indexOf(e) >= 0){ remove(indexOf(e)); return true;
} else{ return false; } } @Override public default boolean containsAll(Collection> c){
for(Object e : c){ if(!contains(e)){ return false; } } return true; } @Override public default
boolean addAll( Collection extends E> c){ for(E e : c){ add(e); } return true; } /* removeAll:
this[1,1,2,3] c[1,2,4] this.removeAll(c) [3] */ @Override public default boolean removeAll(
Collection> c){ for(Object e : c){ while(contains(e)){ this.remove(e); } } return true; } /*
retainAll this[1,1,2,3] c[1,2,4] this.retainAll(c) [1,1,2] */ @Override public default boolean
retainAll( Collection> c){ for(E e : this){ if(!c.contains(e)){ this.remove(e); } } return true; }
@Override public default Object[] toArray(){ Object[] results = new Object[size()]; int i = 0;
for(E e : this){ results[i++] = e; } return results; } /* T[] array */ @Override public default T[]
toArray(T[] array){ int i = 0; for(E e : this){ array[i++] = (T)e; } return array; } } class
TwoWayLinkedList implements MyList { //inner static class Node public class Node { E
element; Node next; Node previous; public Node(E e){ element = e; } } private Node head, tail;
private int size = 0; public TwoWayLinkedList(){ /* head = null; tail = null; size = 0; */ } public
TwoWayLinkedList(E[] objects){ } public E getFirst(){ return null; } public E getLast(){ return
null; } public void addFirst(E e){ } public void addLast(E e){ } public E removeFirst(){ return
null; } public E removeLast(){ return null; } @Override public void add(int index, E e){ }
@Override public E remove(int index){ return null; } @Override public void clear(){ }
@Override public boolean contains(Object e){ return false; } @Override public E get(int index){
return null; } @Override public int indexOf(Object e){ return -1; } @Override public int
lastIndexOf(Object e){ return -1; } @Override public E set(int index, E e){ return null; }
@Override public int size(){ return size; } //toString() @Override public String.
could you implement this function please, im having issues with it..pdf
could you implement this function please, im having issues with it.
void makeList (const ListNode::value_type [],const size_t& count)
class ListNode
{
public:
typedef int value_type;
ListNode (value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum () const { return datum; }
ListNode const* getNext () const { return next; }
//Mutator
void setDatum (const value_type& d) {datum = d; }
ListNode* getNext () { return next; }
void setNext (ListNode* new_link) {next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList ();
virtual ~LinkedList ();
void insertItem (ListNode::value_type);
void makeList (const ListNode::value_type [],const size_t& count);
void deleteList ();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
This is the pseudocode, but i still have a hard time undertanding it.
Creating a List (makeList(const ListNode::value_type [],const size_t& count)) This function
receives an array in the order that we want to add it to the linkedlist. Index 0 will be the head
node, index n will be the last node.
First, create a node initialized with a data value and a NULL pointer. Set the \"head\" to point to
the first node. Set up a current-pointer to the first node (or \"head\"). Get a data value for the next
node. While more nodes to add { Create a new node initialized with the data value and a NULL
pointer. Set the current-pointer link member (\"next\") to the new node. Set the current-pointer to
point to the new node. Get a data value for the next node. }
Thanks.
Solution
//linkedList.h
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
#include
#include
class ListNode
{
public:
typedef int value_type;
ListNode(value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum() const { return datum; }
ListNode const* getNext() const { return next; }
//Mutator
void setDatum(const value_type& d) { datum = d; }
ListNode* getNext() { return next; }
void setNext(ListNode* new_link) { next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList();
virtual ~LinkedList();
void insertItem(ListNode::value_type);
void makeList(const ListNode::value_type[], const size_t& count);
void deleteList();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
#endif
-------------------------------------------------------------
//linkedList.cpp
#include \"linkedlist.h\"
LinkedList::LinkedList()
{
head = NULL;
}
LinkedList::~LinkedList()
{
ListNode *tmp = head;
while (tmp != NULL)
{
head = head->getNext();
delete tmp;
tmp = head;
}
}
void LinkedList::insertItem(ListNode::value_type item)
{
ListNode *newNode,*cur = head;
newNode = new ListNode;
newNode->setDatum(item);
newNode->setNext(NULL);.
C++ Please write the whole code that is needed for this assignment- wr.docx
Brianca plans to save $5,000, $1,000, and $42,000 a year over the next three years, respectively. How much would you need to deposit in one lump sum today to have the same amount as Brianca three years from now if you both earn 10.9 percent, compounded annually? $36,115 $35,192 $43,282 $41,635 $35,372
.
To complete the task, you need to fill in the missing code. I’ve inc.pdf
To complete the task, you need to fill in the missing code. I’ve included code to create an
Iterator. An Iterator is an object that iterates over another object – in this case, a circular linked
list. You can use the .next() method to advance the Iterator to the next item (the first time you
call it, the iterator will travel to node at index 0). Using iterator’s .remove() removes the node the
iterator is currently at. Say that we had a CircularLinkedList that looked like this: A ==> B ==>
C ==> D ==> E ==> Calling .next() three times will advance the iterator to index 2. Calling
.remove() once will remove the node at index 2. A ==> B ==> D ==> E ==> Calling .remove()
once more will remove the node now at index 2. A ==> B ==> E ==> The Iterator methods
handle wrapping around the CircularLinkedList. Be sure to create the iterator using l.iterator()
and after you’ve added all the nodes to the list, where l is your CircularLinkedList
Solution
import java.util.Iterator;
class CircularLinkedList implements Iterable {
// Your variables
// You can include a reference to a tail if you want
Node head;
int size; // BE SURE TO KEEP TRACK OF THE SIZE
// implement this constructor
public CircularLinkedList() {
head=null;
}
// writing helper functions for add and remove, like the book did can help
// but remember, the last element\'s next node will be the head!
// attach a node to the end of the list
// Be sure to handle the adding to an empty list
// always returns true
public boolean add(E e) {
Node newNode=new Node(e);
if(size==0){
head=newNode;
}
else{
Node last=getNode(size-1);
last.next=newNode;
}
newNode.next=head; //last element node is set to head
size++;
return true;
}
// need to handle
// out of bounds
// empty list
// adding to front
// adding to middle
// adding to \"end\"
// REMEMBER TO INCREMENT THE SIZE
public boolean add(int index, E e){
if(index>size) return false;
Node tmp=new Node(e);
if(index==0){
tmp.next=head;
Node last=getNode(size-1);
head=tmp;
last.next=head;
}
else {
Node curr=getNode(index-1);
tmp.next=curr.next;
curr.next=tmp;
}
size++;
return true;
}
// I highly recommend using this helper method
// Return Node found at the specified index
// be sure to handle out of bounds cases
private Node getNode(int index ) {
Node prev=head;
for(int i=0;isize) {
e=null;
}
else if(index==0){
e = head.getElement();
Node last=getNode(size-1);
head=head.next;
last.next=head;
size--;
}
else{
Node prev=getNode(index-1);
Node curr=getNode(index);
e=curr.getElement();
prev.next=curr.next;
size--;
}
return e;
}
// Turns your list into a string
// Useful for debugging
public String toString(){
Node current = head;
StringBuilder result = new StringBuilder();
if(size == 0){
return \"\";
}
if(size == 1) {
return head.getElement().toString();
}
else{
do{
result.append(current.getElement());
result.append(\" ==> \");
current = current.next;
} while(current != head);
}
return result.toString();
}
public Iterator iterator() {
return new ListIterator();
}
/.
How do I fix it in LinkedList.javathis is what i didLabProgra.pdf
The document provides instructions for implementing iterator methods in a LinkedList class. It describes updating the default constructor to initialize the iterator field to null, and modifying removeFirst() and removeLast() methods to handle cases where the iterator is at the first or last node. It then lists 8 steps to implement iterator methods like positionIterator(), offEnd(), getIterator(), advanceIterator(), reverseIterator(), addIterator(), and removeIterator(). The main() method creates a linked list and calls the iterator methods to test their functionality.
Given below is the completed implementation of MyLinkedList class. O.pdf
Given below is the completed implementation of MyLinkedList class. Other classes are not
modified and remain same as in question - MyList, MyAbstractList, TestMyLinkedList.
The output of TestMyLinkedList is shown below. Please don\'t forget to rate the answer if it
helped. Thank you very much.
Since the MyList is not completely pasted in the question ... giving the complete class file below
MyList.java
public interface MyList> extends java.lang.Iterable
{
// Add a new element at the end of this list
public void add (E e);
// Add a new element at specified index in this list
public void add (int index, E e);
// Return true if this list contains the element
public boolean contains (E e);
// Return the element at the specified index
public E get (int index);
// Return the index of the first matching element
// Return -1 if no match.
public int indexOf (E e);
// Return the index of the last matching element
// Return -1 if no match.
public int lastIndexOf (E e);
E remove(int index);
void clear();
E set(int index, E e);
}
MyLinkedList.java
public class MyLinkedList> extends MyAbstractList
implements Comparable>
{
private Node head, tail; // head and tail pointers
// Create a default list
public MyLinkedList()
{
}
public int size()
{
return size;
}
// Need this for implementing Comparable
public int compareTo (MyLinkedList e)
{
return(size() - e.size());
}
// Create a list from an array of objects
public MyLinkedList (E[] objects)
{
super(objects); // Passes the array up to abstract parent
}
// Return the head element in the list
public E getFirst()
{
if (size == 0)
{
return null;
}
else
{
return head.element;
}
}
// Return the last element in the list
public E getLast()
{
if (size == 0)
{
return null;
}
else
{
return tail.element;
}
}
// Add an element to the beginning of the list
public void addFirst (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // new node is only node
{
tail = head;
}
}
// Add an element to the end of the list
public void addLast (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
if (tail == null)
{
head = tail = newNode; // new node is only node
}
else
{
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
// Remove the head node and
// return the object from the removed node
public E removeFirst()
{
if (size == 0)
{
return null;
}
else
{
Node temp = head;
head = head.next;
size--;
if (head == null)
{
tail = null;
}
return temp.element;
}
}
// Remove the last node and return the object from it
public E removeLast()
{
if (size == 0)
{
return null;
}
else if (size == 1)
{
Node temp = head;
head = tail = null;
size = 0;
return temp.element;
}
else
{
Node current = head;
for (int i = 0; i < size - 2; i++)
{
current = current.next;
}
Node temp = tail;
tai.
Hi,I have added the methods and main class as per your requirement.pdf
Hi,
I have added the methods and main class as per your requirement. it is working fine now.
Highlighted the code changes.
MyLinkedListTest.java
public class MyLinkedListTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
MyLinkedList list = new MyLinkedList();
list.addFirst(\"AAAAA\");
list.add(\"1\");
list.add(\"2\");
list.add(\"3\");
list.addLast(\"ZZZZZ\");
System.out.println(\"Linked List Elements : \"+list.toString());
System.out.println(\"First element: \"+list.getFirst());
System.out.println(\"Second element: \"+list.getLast());
System.out.println(\"Removed First Element: \"+list.removeFirst());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed Last Element: \"+list.removeLast());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed all element: \");
list.removeAll();
System.out.println(\"Now Linked List Elements : \"+list.toString());
}
}
MyLinkedList.java
public class MyLinkedList extends MyAbstractList {
private Node head, tail;
/** Create a default list */
public MyLinkedList() {
}
/** Create a list from an array of objects */
public MyLinkedList(E[] objects) {
super(objects);
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return (E)head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return (E)tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node newNode = new Node(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node newNode = new Node(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
/** Add a new element at the specified index in this list
* The index of the head element is 0 */
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node temp = current.next;
current.next = new Node(e);
(current.next).next = temp;
size++;
}
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
Node temp = head;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return (E)temp.element;
}
}
/** Remove all elements from list */
public void removeAll() {
while(true) {
if (size == 0) {
break;
}
else {
Node temp = head;
head =.
Consider a double-linked linked list implementation with the followin.pdf
Consider a double-linked linked list implementation with the following node: struct Node {int
data; Node *prev; Node *next;} Write a copyList method that is not a member of any class.
The method should take a head pointer and return another pointer. Do not modify the input.
Solution
struct Node {
Node *prev; // previous node
Node *next; // next node
int data; // stored value
};
#include
#include \"List.h\" // std: #include
using namespace std;
typedef DataList ; // std: typedef list Data;
int main() {
Data k;
// back stuff
k.push_back(5);
k.push_back(6);
cout << k.back() << endl;
k.pop_back();
// front stuff
k.push_front(4);
k.push_front(3);
cout << k.front() << endl;
k.pop_front();
// forward iterator
Data::iterator pos;
for (pos = k.begin(); pos != k.end(); ++pos)
cout << *pos << endl;
// output and delete list
while (!k.empty()) {
cout << k.front() << endl;
k.pop_front();
}
k.push_front(5);
k.push_front(6);
// remove and erase
k.remove(5);
pos = k.begin();
k.erase(pos);
k.push_front(5);
k.push_front(6);
// copy constructor
Data l = k;
// assignment operator
Data m;
m = k;
return 0;
}
// List.h
struct Node;
classIterator List;
class List {
public:
typedef ListIterator iterator;
// constructor
List();
// destructor
virtual ~List();
// copy constructor
List(const List& k);
// assignment operator
List& operator=(const List& k);
// insert value in front of list
void push_front(double data);
// insert value in back of list
void push_back(double data);
// delete value from front of list
void pop_front();
// delete value from back of list
void pop_back();
// return value on front of list
double front() const;
// return value on back of list
double back() const;
// delete value specified by iterator
void erase(const iterator& i);
// delete all nodes with specified value
void remove(double data);
// return true if list is empty
bool empty() const;
// return reference to first element in list
iterator begin() const;
// return reference to one past last element in list
iterator end() const;
private:
Node *head; // head of list
};
class ListIterator {
public:
// default constructor
ListIterator() {
i = 0;
}
// construct iterator for given pointer (used for begin/end)
ListIterator(Node *p) {
i = p;
}
// convert iterator to Node*
operator Node*() const {
return i;
}
// test two iterators for not equal
bool operator!=(const ListIterator& k) const {
return i != k.i;
}
// preincrement operator
ListIterator& operator++() {
i = i->next;
return *this;
}
// return value associated with iterator
double& operator*() const {
return i->data;
}
private:
Node *i; // current value of iterator
};
list.cpp
// delete list
static void deleteList(Node *head) {
Node *p = head->next;
while (p != head) {
Node *next = p->next;
delete p;
p = next;
}
delete head;
}
// copy list
static void copyList(const Node *from, Node *&to) {
// create dummy header
to = new Node;
to->next = to->prev = to;
// copy nodes
for (Node *p = from->next; p != from; p = p->next) {
Node *t = new Node;
t.
This is problem is same problem which i submitted on 22017, I just.pdf
There is a host of sociological and cultural research that paints a robust picture of the effects of
globalization on culture. This Application focuses on the flows of culture between Western and
developing nations. As a practitioner in this global environment, you should be familiar with
these culture effects. Use newspapers, magazines, and the Internet to research cultural changes in
both Western and developing countries due to globalization. Then perform the following tasks:
Outline the cultural aspects of globalization. Take an anthropological, rather than a business,
perspective. Explain how you think understanding culture helps in doing business in today\'s
global economy. Cite resources to justify your response.
Solution
Information technology has penetrated almost every aspect of our lives, “shrinking” our world
into a global village.
Economies and cultures have come closer. People are now aware of the cultures, traditions,
lifestyle, living conditions
prevailing in almost every corner of the world. Interestingly, this is going beyond awareness and
into a state of
integration that is a result of cross-pollinated views, ideologies, products and services.
This evolution is termed as “globalization.”
Culture has many definitions. My own definition is that culture is our collective experience as a
society,
and its impact on our reaction and decision-making relative to every-day facts and
circumstances.
Why is cross-cultural competence critical to your professional future and the viability of your
company?
It’s omnipresent in every business interaction and strategic decision.It is not feasible to be an
expert on
all the world’s cultures. It is possible, however, to incorporate a cross-cultural framework that
improves
cross-cultural understanding and interactions.
Multinational firms whose operations are borderless have to consider the cultural variability of
different regions
of the world and develop cultural understanding. Major cultural constraints encountered by
businesses include local
attitudes, taste preferences, language, religion, management style, gender discrimination, skills,
personalities,
education, etc. To be successful, they need to mold their business actions in accordance with the
local cultural models,
they need to establish a global mindset.
Let’s consider an example of the food giant, McDonald’s. The company enjoys a global
presence; operating in more than
100 countries serving 70 million people every day. Their headquarters and senior management
are U.S.-based but they
entrust their local operations to local managers of the countries they operate in. Operations in
more than 50 percent of
their outlets are franchised. Furthermore, their menus are customized according to cultural
habits and local taste
preferences in every country. It is without a doubt that global thinking and cultural
understanding are both powerful
business tools which allow multinational firms to dominate the local markets and establish a
global pres.
How do you stop infinite loop Because I believe that it is making a.pdf
How do you stop infinite loop? Because I believe that it is making an infinite circular list.
c++ code:
Here is the list class:
#ifndef LIN_J_LIST
#define LIN_J_LIST
typedef unsigned int uint;
#include
#include
using namespace std;
/**
* a simplified generic singly linked list class to illustrate C++ concepts
* @author Jerry Lin
* @version 2/17/17
*/
template< typename Object >
class List
{
private:
/**
* A class to store data and provide a link to the next node in the list
*/
class Node
{
public:
/**
* The constructor
* @param data the data to be stored in this node
*/
explicit Node( const Object & data )
: data{ data }, next{ nullptr } {}
Object data;
Node * next;
};
public:
/**
* The constructor for an empty list
*/
List()
: size{ 0 }, first{ nullptr }, last{ nullptr } {}
/**
* the copy constructor-creates and copy the list
*/
List( List && rhs ) = delete;
List( const List & rhs )
{
count = 0;
size = 0;
if(rhs.size != 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first;
size++;
while(current->next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op.
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode->next;
size++;
}
}
// you document and implement this method
}
/**
* the operator= method-copies the list
*/
List & operator=( List && rhs) = delete;
List & operator=( const List & rhs )
{
count = 0;
size = 0;
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
if(rhs.size!= 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first; //create a temporary to store
size++;
while(current -> next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode -> next;
size++;
}
}
return *this;
// you document and implement this method
}
/**
* accessor
* @return count
*/
int get_count() const
{
return count;
}
/**
* The destructor that gets rid of everything that\'s in the list and
* resets it to empty. If the list is already empty, do nothing.
*/
~List()
{
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
}
/**
* Put a new element onto the beginning of the list
* @param item the data the new element will contain
*/
void push_front( const Object& item )
{
Node * new_node = new Node( item );//basic op.
if(is_empty())
{
last = new_node;
}
else
{
new_node->next = first;
}
first = new_node;
size++;
/* you complete the rest */
}
/**
* Remove the element that\'s at the front of the list. Causes an
* assertion error if the list is empty.
*/
void pop_front()
{
assert( !is_empty() );
Node * temp = first;
if( first == last )
{
first = last = nullptr;
}
else
{
first = first->next;
}
delete temp;
size--;
}
/**
* Accessor to return the da.
hi i have to write a java program involving link lists. i have a pro.pdf
hi i have to write a java program involving link lists. i have a problem with the nodes, as it is
posting errors with the nodes.
please help me with this problem. thank you.
public class LinkLists {
/* only need to store a single pointer to the node at the head
* of the list.
* The pointer is null if the list is empty.
* Also record the size of the list.
*/
protected Node head;
/* invariant: size is the number of nodes in the list pointed to by head */
protected int size;
/* no-arguments default constructor creates an empty list */
public LinkLists() {
head = null; // start with an empty list
size = 0;
}
/* accessor method */
public int size() {
return size;
}
/* value to add to the end of the list
*/
public void add(T value) {
head = addAtEnd(head, value);
size++;
}
/* node of the list to which the value should be added
* value to add to the end of the list
*/
private Node addAtEnd(Node node, T value) {
if (node == null) { // special case
return new Node(value, null);
} else if (node.getNext() == null) { // other special case
node.setNext(new Node(value, null));
} else {
addAtEnd(node.getNext(), value);
}
return node;
}
/* iterative implementation of the same method
* value to add to the end of the list
*/
public void add2(T value) {
if (head == null) {
head = new Node(value, null);
} else {
Node node = head; // guaranteed not to be null initially
while (node.getNext() != null) {
node = node.getNext(); // guaranteed not to be null here
}
// now, node.getNext() is guaranteed to be null
// similar to the second special case in addAtEnd
node.setNext(new Node(value, null));
}
size++;
}
public void remove(int position) throws BadItemCountException {
if ((position < 1) || (position > size)) {
throw new
BadItemCountException(\"invalid position \" + position +
\", only 1..\" + size + \" available\");
}
if (position == 1) {
head = head.getNext();
} else {
Node node = head;
for (int i = 2; i < position; i++) {
node = node.getNext();
}
node.setNext(node.getNext().getNext());
}
size--; // one less item
}
public String toString() {
return toString(head);
}
private String toString(Node node) {
if (node == null) {
return \"\";
} else {
return node.getValue() + \"\ \" + toString(node.getNext());
}
}
public static void main(String[] args) {
/* create two empty lists, make sure they print out correctly */
LinkLists list1 = new LinkLists();
LinkLists list2 = new LinkLists();
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* insert some items, keep checking */
list1.add(\"hello\");
list1.add(\"world\");
list2.add(\"foo\");
list2.add(\"bar\");
list2.add(\"baz\");
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* remove an item at an invalid position */
boolean caught = false;
try {
list2.remove(4);
} catch .
Inspect the class declaration for a doubly-linked list node in Node-h-.pdf
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables: a double data value, a pointer to the next node, and a pointer to the previous
node. Each member variable is protected. So code outside of the class must use the provided
getter and setter member functions to get or set a member variable. Node.h is read only, since no
changes are required. Step 2: Implement the Insert() member function A class for a sorted,
doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList class's
Insert() member function. The function must create a new node with the parameter value, then
insert the node into the proper sorted position in the linked list. Ex: Suppose a
SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node with data
value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order
and yielding: 23 35.5 47.25 86 Step 3: Test in develop mode Code in main() takes a space-
separated list of numbers and inserts each into a SortedNumberList. The list is displayed after
each insertion. Ex: If input is 77 15 -42 63.5 then output is: List after inserting 77: 77 List after
inserting 15: 15 77 List after inserting -42: -42 15 77 List after inserting 63.5: -42 15 63.5 77 Try
various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove()
member function Implement the SortedNumberList class's Remove() member function. The
function takes a parameter for the number to be removed from the list. If the number does not
exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the
number is removed from the list and true is returned. Uncomment the commented-out part in
main() that reads a second input line and removes numbers from the list. Test in develop mode to
ensure that insertion and removal both work properly, then submit code for grading. Ex: If input
is 84 72 19 61 19 84 then output is: List after inserting 84: 84 List after inserting 72: 72 84 List
after inserting 19: 19 72 84 List after inserting 61: 19 61 72 84 List after removing 19: 61 72 84
List after removing 84: 61 72
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std; void PrintList(SortedNumberList& list); vector SpaceSplit(string source);
int main(int argc, char *argv[]) { // Read the line of input numbers string inputLine; getline(cin,
inputLine); // Split on space character vector terms = SpaceSplit(inputLine); // Insert each value
and show the sorted list's contents after each insertion SortedNumberList list; for (auto term :
terms) { double number = stod(term); cout << "List after inserting " << number << ": " << endl;
list.Insert(number); PrintList(list); } /* // Read the input line with numbers to remove getline(cin,
inputLi.
Lab-2.4 101.pdf
The document contains C program code to implement three data structures using linked lists:
1) A stack using a singly linked list with push, pop, and display functions.
2) A queue using a singly linked list with enqueue, dequeue, and display functions.
3) A program to merge two sorted linked lists by comparing nodes and appending to the merged list.
Pseudocode and sample test cases are provided for each problem.
Copy your completed LinkedList class from Lab 3 into the LinkedList..pdf
Copy your completed LinkedList class from Lab 3 into the LinkedList.java file below.
During this lab we will add more constructors, an equals method and more challenging methods
as listed below.
Also inspect the LabProgram.java file and notice that the main() method of the LabProgram
copies and compares two linked lists. The main() method also calls the more challenging
methods. Use Develop mode to test your LinkedList iterator code as you develop it.
In Submit mode you will need to complete all lab steps to pass all automatic tests.
Step 2: Implement clear()
Method clear() re-sets the LinkedList to empty as if the default constructor had just been called.
Constructor LinkedList(T[] array) converts the given array into a LinkedList.
Constructor LinkedList(LinkedList original) instantiates a new LinkedList by copying another
List.
Method equals() determines whether the given Object is another LinkedList, containing the same
data in the same order, returning whether there is equality.
Method spinList(int numMoves) moves all nodes in the list towards the end of the list the
number of times specified. Any node that falls off the end of the list as it moves forward will be
placed at the front of the list.
Method altLists() splices together two LinkedLists to create a third List which contains
alternating values from the original list and the given parameter.
*Below is my Lab3 LinkedList.class.
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
public T getFirst() throws NoSuchElementException {
if (first == null) throw new NoSuchElementException();
return first.data;
}
public T getLast() throws NoSuchElementException {
if (last == null) throw new NoSuchElementException();
return last.data;
}
public T getIterator() throws NullPointerException {
if (iterator == null) {
throw new NullPointerException("Iterator is off end.");
}
return iterator.data;
}
public int getLength() {
return length;
}
public boolean isEmpty() {
return length == 0;
}
public boolean offEnd() {
return iterator == null;
}
public void addFirst(T data) {
Node newNode = new Node(data);
if (length == 0) {
first = newNode;
last = newNode;
} else .
STAGE 2 The Methods 65 points Implement all the methods t.pdf
STAGE 2: The Methods (65 points) Implement all the methods that are marked as Left as
Exercise. The Driver program only works when you have done all the methods. I have added the
template of all the methods with a placeholder value as return types of the methods. For example,
return 0 if method returns an int value.
List of the methods left as exercise are as follows: /** Create a list from an array of objects */
@SuppressWarnings("unchecked") public MyLinkedList(E[] objects) /** Add a new element at the
specified index in this list in ascending order */ public void addInOrder(E e) /** Check to see if this
list contains element e */ public boolean contains(E e) /** Remove all the occurrences of the
element e * from this list. Return true if the element is * removed. */ public boolean removeAll(E e)
/** Remove the first occurrence of the element e * from this list. Return true if the element is *
removed. */ public boolean remove(E e) /** Return the element at the specified index */ public E
get(int index) /** Return the index of the head matching element in * this list. Return -1 if no match.
*/ public int indexOf(Object e) /** Return the index of the last matching element in * this list. Return
-1 if no match. */ public int lastIndexOf(E e) /** Replace the element at the specified position * in
this list with the specified element. */ public E set(int index, E e) /** Print this list using recursion */
public void printList() /** Returns an array containing all of the elements * in this collection; * the
runtime type of the returned array is that of * the specified array. */ public <E> E[] toArray(E[]
array) /** Split the original list in half. The original * list will continue to reference the * front half of
the original list and the method * returns a reference to a new list that stores the * back half of the
original list.
public class MyLinkedList<E extends Comparable<E>> {
private Node<E> head, tail;
private int size = 0; // Number of elements in the list
public MyLinkedList() {
head=tail=null;
size=0;
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node<E> newNode = new Node<>(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node<E> newNode = new Node<>(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = newNode; // tail now points to the last node
}
size++; // Incr.
public class MyLinkedListltE extends ComparableltEgtg.pdf
public class MyLinkedList<E extends Comparable<E>> {
private Node<E> head, tail;
private int size = 0; // Number of elements in the list
public MyLinkedList() {
head=tail=null;
size=0;
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node<E> newNode = new Node<>(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node<E> newNode = new Node<>(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = newNode; // tail now points to the last node
}
size++; // Increase size
}
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node<E> current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node<E> temp = current.next;
current.next = new Node<>(e);
(current.next).next = temp;
size++;
}
}
//Add e to the end of this linkedlist
public void add(E e) {
// Left as Exercise
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
E temp = head.element;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return temp;
}
}
/** Remove the last node and
* return the object that is contained in the removed node. */
public E removeLast() {
if (size == 0) {
return null;
}
else if (size == 1) {
E temp = head.element;
head = tail = null;
size = 0;
return temp;
}
else {
Node<E> current = head;
for (int i = 0; i < size - 2; i++) {
current = current.next;
}
E temp = tail.element;
tail = current;
tail.next = null;
size--;
return temp;
}
}
/** Remove the element at the specified position in this
* list. Return the element that was removed from the list. */
public E remove(int index) {
if (index < 0 || index >= size) {
return null;
}
else if (index == 0) {
return removeFirst();
}
else if (index == size - 1) {
return removeLast();
}
else {
Node<E> previous = head;
for (int i = 1; i < index; i++) {
previous = previous.next;
}
Node<E> current = previous.next;
previous.next = current.next;
size--;
return current.element;
}
}
/** Clear the list */
public void clear() {
size = 0;
head = tail = null;
}
/** Override toString() to return elements in the list in [] separated by , */
public String toString() {
StringBuilder result = new StringBuilder("[");
Node<E> current = head;
for (int i = 0; i < size; i++) {
result.append(current..
Data Structures in C++I am really new to C++, so links are really .pdf
Data Structures in C++
I am really new to C++, so links are really hard topic for me. It would be nice if you can provide
explanations of what doubly linked lists are and of some of you steps... Thank you
In this assignment, you will implement a doubly-linked list class, together with some list
operations. To make things easier, you’ll implement a list of int, rather than a template class.
Solution
A variable helps us to identify the data. For ex: int a = 5; Here 5 is identified through variable a.
Now, if we have collection of integers, we need some representation to identify them. We call it
array. For ex: int arr[5]
This array is nothing but a Data Structure.
So, a Data Structure is a way to group the data.
There are many Data Structures available like Arrays, Linked List, Doubly-Linked list, Stack,
Queue, etc.
Doubly-Linked list are the ones where you can traverse from the current node both in left and
right directions.
Why so many different types of Data Structures are required ?
Answer is very simple, grouping of data, storage of data and accessing the data is different.
For example, in case of Arrays we store all the data in contiguous locations.
What if we are not able to store the data in contiguous locations because we have huge data.
Answer is go for Linked List/Doubly-Linked list.
Here we can store the data anywhere and link the data through pointers.
I will try to provide comments for the code you have given. May be this can help you.
#pragma once
/*
dlist.h
Doubly-linked lists of ints
*/
#include
class dlist {
public:
dlist() { }
// Here we are creating a NODE, it has a integer value and two pointers.
// One pointer is to move to next node and other to go back to previous node.
struct node {
int value;
node* next;
node* prev;
};
// To return head pointer, i.e. start of the Doubly-Linked list.
node* head() const { return _head; }
// To return Tail pointer, i.e. end of the Doubly-Linked list.
node* tail() const { return _tail; }
// **** Implement ALL the following methods ****
// Returns the node at a particular index (0 is the head).
node* at(int index){
int cnt = 0;
struct node* tmp = head();
while(tmp!=NULL)
{
if (cnt+1 == index)
return tmp;
tmp = tmp->next;
}
}
// Insert a new value, after an existing one
void insert(node *previous, int value){
// check if the given previous is NULL
if (previous == NULL)
{
printf(\"the given previous node cannot be NULL\");
return;
}
// allocate new node
struct node* new_node =(struct node*) malloc(sizeof(struct node));
// put in the data
new_node->data = new_data;
// Make next of new node as next of previous
new_node->next = previous->next;
// Make the next of previous as new_node
previous->next = new_node;
// Make previous as previous of new_node
new_node->prev = previous;
// Change previous of new_node\'s next node
if (new_node->next != NULL)
new_node->next->prev = new_node;
}
// Delete the given node
void del(node* which){
struct node* head_ref = head();
/* base case */
if(*head_ref == NUL.
Labprogram.javaLinkedList.javaimport java.util.NoSuchElementEx.pdf
Labprogram.java
LinkedList.java
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
*
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
*
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
public T getFirst() throws NoSuchElementException {
if (isEmpty()) {
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (isEmpty()) {
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
public T getIterator() throws NullPointerException {
if (iterator != null) {
return iterator.data;
} else {
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
public int getLength() {
return length;
}
public boolean isEmpty() {
return length == 0;
}
public boolean offEnd() {
return iterator == null;
}
public void addFirst(T data) {
Node newNode = new Node(data);
if (isEmpty()) {
first = newNode;
last = newNode;
} else {
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
public void addLast(T data) {
Node newNode = new Node(data);
if (isEmpty()) {
first = newNode;
last = newNode;
} else {
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
public void addIterator(T data) throws NullPointerException {
if (offEnd()) {
throw new NullPointerException("addIterator Iterator is off end.");
}
if (iterator == last) {
addLast(data);
} else {
Node newNode = new Node(data);
Node next = iterator.next;
newNode.next = next;
newNode.prev = iterator;
iterator.next = newNode;
next.prev = newNode;
length++;
}
}
public void removeFirst() throws NoSuchElementException {
if (isEmpty()) {
throw new NoSuchElementException("The list is empty");
}
if (length == 1) {
first = null;
last = null;
iterator = null;
} else {
if (iterator == first) {
iterator = null;
}
first = first.next;
first.prev = null;
}
length--;
}
public void removeLast() throws NoSuchElementException {
if (isEmpty()) {
throw new NoSuchElementException("The list is empty");
}
if (length == 1) {
first = null;
last = null;
iterator = null;
} else {
if (iterator == last) {
iterator = null;
}
last = last.prev;
last.next = null;
}
length--;
}
public void removeIterator() throws NullPointerException {
if (offEnd()) {
throw new NullPointerException("Iterator is off the end opf the list.");
}
if (iterator .
In C++ please, do not alter node.hStep 1 Inspect the Node.h file.pdf
In C++ please, do not alter node.h
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new
node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
77 15 -42 63.5
then output is:
List after inserting 77:
77 List after inserting 15:
15 77
List after inserting -42:
-42 15 77
List after inserting 63.5:
-42 15 63.5 77
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
84 72 19 61 19 84
then output is:
List after inserting 84:
84
List after inserting 72:
72 84
List after inserting 19:
19 72 84
List after inserting 61:
19 61 72 84
List after removing 19:
61 72 84
List after removing 84:
61 72
Code below:
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = Space.
Write a function to merge two doubly linked lists. The input lists ha.pdf
Write a function to merge two doubly linked lists. The input lists have their elements in sorted
order, from lowest to highest. The output list should also be sorted from lowest to highest. Your
algorithm should run in linear time on the length of the output list. Provide an algorithm for your
function Implement and show some samples of your running function
Solution
The algorithm for LinkedList MergeSort is as follows.
The trick in this algorithm is to use a local list to store the value which is pointing to the actual
list to be returned as a result of the function
Step1: START
Step2: GET inputs of list1 and list2
Step3: INITIALIZE mergelist
STEP4: SET mylist = mergelist
Step5: WHILE list1 OR list2 is EMPTY
DO
IF (list1 AND list2) are NOT EMPTY
IF list1.value > list2.value
mylist.next = list2
ELSE
mylist.next = list1
ELSE IF list1 is EMPTY
mylist.next = list2
ELSE
mylist.next = list1
Step6: RETURN mergelist
Step7: STOP
Sample program for the same implemented in C++
//====================================================================
========
// Name : DoublyLinkedList.cpp
// Author : Kaju
// Version : 0.1
// Copyright : This is just an example code
// Description : MergeSort in C++, Ansi-style
//====================================================================
========
/*
* C++ Program to Implement Doubly Linked List
*/
#include
#include
#include
/*
* Node Declaration
*/
using namespace std;
// struct declaration for node which will hold the integer data with links to previous data and next
data
struct node
{
int data;
struct node *next;
struct node *prev;
};
/*
Class Declaration
*/
class DoublyLinkedList
{
private:
struct node *start; // collection of all the nodes
public:
void create(int value);
int peek();
int delete_head();
void display();
int count();
void mergeSort(DoublyLinkedList list1, DoublyLinkedList list2);
DoublyLinkedList()
{
start = NULL;
}
};
/*
* Add data into the list
*/
void DoublyLinkedList::create(int value)
{
struct node *s, *temp;
temp = new(struct node);
temp->data = value;
temp->next = NULL;
if (start == NULL)
{
temp->prev = NULL;
start = temp;
}
else
{
s = start;
while (s->next != NULL)
s = s->next;
s->next = temp;
temp->prev = s;
}
}
/*
* Deletion of the first element from the list
* store the first element in a temp node and then remove it from start.
*/
int DoublyLinkedList::delete_head()
{
struct node *tmp, *q;
int value;
tmp = start;
if(start->next!=NULL)
{
start = start->next;
start->prev = NULL;
}
else
start = NULL;
value = tmp->data;
free(tmp);
return value;
}
/*
* return the first element of Doubly Link List
*/
int DoublyLinkedList::peek()
{
struct node *q;
if (start == NULL)
{
cout<<\"List is empty\"<data;
}
}
/*
* Display elements of Doubly Link List
*/
void DoublyLinkedList::display()
{
struct node *q;
if (start == NULL)
{
cout<<\"List is empty\"<data;
q = q->next;
if(q != NULL)
{
cout<<\", \";
}
}
cout<<\"]\"<next;
cnt++;
}
return cnt;
}
/*
* MergeSort - takes two input lists and then based on the.
File LinkedList.java Defines a doubly-l.pdf
File: LinkedList.java
/**
* Defines a doubly-linked list class
*/
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
/**
* Returns the value stored in the first node
* @precondition
* @return the value stored at node first
* @throws NoSuchElementException
*/
public T getFirst() throws NoSuchElementException {
return null;
}
/**
* Returns the value stored in the last node
* @precondition
* @return the value stored in the node last
* @throws NoSuchElementException
*/
public T getLast() throws NoSuchElementException {
return null;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
return null;
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return -1;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return false;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return false;
}
/**** MUTATORS ****/
/**
* Creates a new first element
* @param data the data to insert at the front of the LinkedList
* @postcondition
*/
public void addFirst(T data) {
return;
}
/**
* Creates a new last element
* @param data the data to insert at the end of the LinkedList
* @postcondition
*/
public void addLast(T data) {
return;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIterator(T data) throws NullPointerException{
return;
}
/**
* removes the element at the front of the LinkedList
* @precondition
* @postcondition
* @throws NoSuchElementException
*/
public void removeFirst() throws NoSuchElementException {
return;
}
/**
* removes the element at the end of the LinkedList
* @precondition
* @postcondition
* @throws NoSuchElementException
*/
public void removeLast() throws NoSuchElementException {
return;
}
/**
* removes the element referenced by the iterator
* @precondition
* @pos.
Data Structures and Agorithm: DS 05 Doubly Linked List.pptx
Data Structures and Agorithm: DS 05 Doubly Linked List.pptx
Need done for Date Structures please! 4-18 LAB- Sorted number list imp.pdf
Need done for Date Structures please!
4.18 LAB: Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number.
Conduct an internet search finding a job you are interested (HR .docx
An online job posting for an HR Director included the salary range, allowing commentary on pros and cons from employer and employee perspectives. From an employer perspective, including salary range promotes transparency but may limit candidate pools. From an employee perspective, seeing the salary range upfront helps determine fit and interest level, but could feel restrictive for negotiations.
Conduct an Internet or library search for information on The Bay of.docx
The Bay of Pigs invasion was a failed attempt by Cuban exiles to invade Cuba and overthrow Fidel Castro in 1961. Poor decisions were likely made due to bounded awareness, where the focus was too narrow and long term consequences were not considered. Focalism and focusing illusion, where too much attention is paid to one narrow aspect, may have contributed to the failure by limiting perspective.
More Related Content
Similar to For this micro assignment, you must implement two Linked List functi.docx
To complete the task, you need to fill in the missing code. I’ve inc.pdf
To complete the task, you need to fill in the missing code. I’ve included code to create an
Iterator. An Iterator is an object that iterates over another object – in this case, a circular linked
list. You can use the .next() method to advance the Iterator to the next item (the first time you
call it, the iterator will travel to node at index 0). Using iterator’s .remove() removes the node the
iterator is currently at. Say that we had a CircularLinkedList that looked like this: A ==> B ==>
C ==> D ==> E ==> Calling .next() three times will advance the iterator to index 2. Calling
.remove() once will remove the node at index 2. A ==> B ==> D ==> E ==> Calling .remove()
once more will remove the node now at index 2. A ==> B ==> E ==> The Iterator methods
handle wrapping around the CircularLinkedList. Be sure to create the iterator using l.iterator()
and after you’ve added all the nodes to the list, where l is your CircularLinkedList
Solution
import java.util.Iterator;
class CircularLinkedList implements Iterable {
// Your variables
// You can include a reference to a tail if you want
Node head;
int size; // BE SURE TO KEEP TRACK OF THE SIZE
// implement this constructor
public CircularLinkedList() {
head=null;
}
// writing helper functions for add and remove, like the book did can help
// but remember, the last element\'s next node will be the head!
// attach a node to the end of the list
// Be sure to handle the adding to an empty list
// always returns true
public boolean add(E e) {
Node newNode=new Node(e);
if(size==0){
head=newNode;
}
else{
Node last=getNode(size-1);
last.next=newNode;
}
newNode.next=head; //last element node is set to head
size++;
return true;
}
// need to handle
// out of bounds
// empty list
// adding to front
// adding to middle
// adding to \"end\"
// REMEMBER TO INCREMENT THE SIZE
public boolean add(int index, E e){
if(index>size) return false;
Node tmp=new Node(e);
if(index==0){
tmp.next=head;
Node last=getNode(size-1);
head=tmp;
last.next=head;
}
else {
Node curr=getNode(index-1);
tmp.next=curr.next;
curr.next=tmp;
}
size++;
return true;
}
// I highly recommend using this helper method
// Return Node found at the specified index
// be sure to handle out of bounds cases
private Node getNode(int index ) {
Node prev=head;
for(int i=0;isize) {
e=null;
}
else if(index==0){
e = head.getElement();
Node last=getNode(size-1);
head=head.next;
last.next=head;
size--;
}
else{
Node prev=getNode(index-1);
Node curr=getNode(index);
e=curr.getElement();
prev.next=curr.next;
size--;
}
return e;
}
// Turns your list into a string
// Useful for debugging
public String toString(){
Node current = head;
StringBuilder result = new StringBuilder();
if(size == 0){
return \"\";
}
if(size == 1) {
return head.getElement().toString();
}
else{
do{
result.append(current.getElement());
result.append(\" ==> \");
current = current.next;
} while(current != head);
}
return result.toString();
}
public Iterator iterator() {
return new ListIterator();
}
/.
How do I fix it in LinkedList.javathis is what i didLabProgra.pdf
The document provides instructions for implementing iterator methods in a LinkedList class. It describes updating the default constructor to initialize the iterator field to null, and modifying removeFirst() and removeLast() methods to handle cases where the iterator is at the first or last node. It then lists 8 steps to implement iterator methods like positionIterator(), offEnd(), getIterator(), advanceIterator(), reverseIterator(), addIterator(), and removeIterator(). The main() method creates a linked list and calls the iterator methods to test their functionality.
Given below is the completed implementation of MyLinkedList class. O.pdf
Given below is the completed implementation of MyLinkedList class. Other classes are not
modified and remain same as in question - MyList, MyAbstractList, TestMyLinkedList.
The output of TestMyLinkedList is shown below. Please don\'t forget to rate the answer if it
helped. Thank you very much.
Since the MyList is not completely pasted in the question ... giving the complete class file below
MyList.java
public interface MyList> extends java.lang.Iterable
{
// Add a new element at the end of this list
public void add (E e);
// Add a new element at specified index in this list
public void add (int index, E e);
// Return true if this list contains the element
public boolean contains (E e);
// Return the element at the specified index
public E get (int index);
// Return the index of the first matching element
// Return -1 if no match.
public int indexOf (E e);
// Return the index of the last matching element
// Return -1 if no match.
public int lastIndexOf (E e);
E remove(int index);
void clear();
E set(int index, E e);
}
MyLinkedList.java
public class MyLinkedList> extends MyAbstractList
implements Comparable>
{
private Node head, tail; // head and tail pointers
// Create a default list
public MyLinkedList()
{
}
public int size()
{
return size;
}
// Need this for implementing Comparable
public int compareTo (MyLinkedList e)
{
return(size() - e.size());
}
// Create a list from an array of objects
public MyLinkedList (E[] objects)
{
super(objects); // Passes the array up to abstract parent
}
// Return the head element in the list
public E getFirst()
{
if (size == 0)
{
return null;
}
else
{
return head.element;
}
}
// Return the last element in the list
public E getLast()
{
if (size == 0)
{
return null;
}
else
{
return tail.element;
}
}
// Add an element to the beginning of the list
public void addFirst (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // new node is only node
{
tail = head;
}
}
// Add an element to the end of the list
public void addLast (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
if (tail == null)
{
head = tail = newNode; // new node is only node
}
else
{
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
// Remove the head node and
// return the object from the removed node
public E removeFirst()
{
if (size == 0)
{
return null;
}
else
{
Node temp = head;
head = head.next;
size--;
if (head == null)
{
tail = null;
}
return temp.element;
}
}
// Remove the last node and return the object from it
public E removeLast()
{
if (size == 0)
{
return null;
}
else if (size == 1)
{
Node temp = head;
head = tail = null;
size = 0;
return temp.element;
}
else
{
Node current = head;
for (int i = 0; i < size - 2; i++)
{
current = current.next;
}
Node temp = tail;
tai.
Hi,I have added the methods and main class as per your requirement.pdf
Hi,
I have added the methods and main class as per your requirement. it is working fine now.
Highlighted the code changes.
MyLinkedListTest.java
public class MyLinkedListTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
MyLinkedList list = new MyLinkedList();
list.addFirst(\"AAAAA\");
list.add(\"1\");
list.add(\"2\");
list.add(\"3\");
list.addLast(\"ZZZZZ\");
System.out.println(\"Linked List Elements : \"+list.toString());
System.out.println(\"First element: \"+list.getFirst());
System.out.println(\"Second element: \"+list.getLast());
System.out.println(\"Removed First Element: \"+list.removeFirst());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed Last Element: \"+list.removeLast());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed all element: \");
list.removeAll();
System.out.println(\"Now Linked List Elements : \"+list.toString());
}
}
MyLinkedList.java
public class MyLinkedList extends MyAbstractList {
private Node head, tail;
/** Create a default list */
public MyLinkedList() {
}
/** Create a list from an array of objects */
public MyLinkedList(E[] objects) {
super(objects);
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return (E)head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return (E)tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node newNode = new Node(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node newNode = new Node(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
/** Add a new element at the specified index in this list
* The index of the head element is 0 */
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node temp = current.next;
current.next = new Node(e);
(current.next).next = temp;
size++;
}
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
Node temp = head;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return (E)temp.element;
}
}
/** Remove all elements from list */
public void removeAll() {
while(true) {
if (size == 0) {
break;
}
else {
Node temp = head;
head =.
Consider a double-linked linked list implementation with the followin.pdf
Consider a double-linked linked list implementation with the following node: struct Node {int
data; Node *prev; Node *next;} Write a copyList method that is not a member of any class.
The method should take a head pointer and return another pointer. Do not modify the input.
Solution
struct Node {
Node *prev; // previous node
Node *next; // next node
int data; // stored value
};
#include
#include \"List.h\" // std: #include
using namespace std;
typedef DataList ; // std: typedef list Data;
int main() {
Data k;
// back stuff
k.push_back(5);
k.push_back(6);
cout << k.back() << endl;
k.pop_back();
// front stuff
k.push_front(4);
k.push_front(3);
cout << k.front() << endl;
k.pop_front();
// forward iterator
Data::iterator pos;
for (pos = k.begin(); pos != k.end(); ++pos)
cout << *pos << endl;
// output and delete list
while (!k.empty()) {
cout << k.front() << endl;
k.pop_front();
}
k.push_front(5);
k.push_front(6);
// remove and erase
k.remove(5);
pos = k.begin();
k.erase(pos);
k.push_front(5);
k.push_front(6);
// copy constructor
Data l = k;
// assignment operator
Data m;
m = k;
return 0;
}
// List.h
struct Node;
classIterator List;
class List {
public:
typedef ListIterator iterator;
// constructor
List();
// destructor
virtual ~List();
// copy constructor
List(const List& k);
// assignment operator
List& operator=(const List& k);
// insert value in front of list
void push_front(double data);
// insert value in back of list
void push_back(double data);
// delete value from front of list
void pop_front();
// delete value from back of list
void pop_back();
// return value on front of list
double front() const;
// return value on back of list
double back() const;
// delete value specified by iterator
void erase(const iterator& i);
// delete all nodes with specified value
void remove(double data);
// return true if list is empty
bool empty() const;
// return reference to first element in list
iterator begin() const;
// return reference to one past last element in list
iterator end() const;
private:
Node *head; // head of list
};
class ListIterator {
public:
// default constructor
ListIterator() {
i = 0;
}
// construct iterator for given pointer (used for begin/end)
ListIterator(Node *p) {
i = p;
}
// convert iterator to Node*
operator Node*() const {
return i;
}
// test two iterators for not equal
bool operator!=(const ListIterator& k) const {
return i != k.i;
}
// preincrement operator
ListIterator& operator++() {
i = i->next;
return *this;
}
// return value associated with iterator
double& operator*() const {
return i->data;
}
private:
Node *i; // current value of iterator
};
list.cpp
// delete list
static void deleteList(Node *head) {
Node *p = head->next;
while (p != head) {
Node *next = p->next;
delete p;
p = next;
}
delete head;
}
// copy list
static void copyList(const Node *from, Node *&to) {
// create dummy header
to = new Node;
to->next = to->prev = to;
// copy nodes
for (Node *p = from->next; p != from; p = p->next) {
Node *t = new Node;
t.
This is problem is same problem which i submitted on 22017, I just.pdf
There is a host of sociological and cultural research that paints a robust picture of the effects of
globalization on culture. This Application focuses on the flows of culture between Western and
developing nations. As a practitioner in this global environment, you should be familiar with
these culture effects. Use newspapers, magazines, and the Internet to research cultural changes in
both Western and developing countries due to globalization. Then perform the following tasks:
Outline the cultural aspects of globalization. Take an anthropological, rather than a business,
perspective. Explain how you think understanding culture helps in doing business in today\'s
global economy. Cite resources to justify your response.
Solution
Information technology has penetrated almost every aspect of our lives, “shrinking” our world
into a global village.
Economies and cultures have come closer. People are now aware of the cultures, traditions,
lifestyle, living conditions
prevailing in almost every corner of the world. Interestingly, this is going beyond awareness and
into a state of
integration that is a result of cross-pollinated views, ideologies, products and services.
This evolution is termed as “globalization.”
Culture has many definitions. My own definition is that culture is our collective experience as a
society,
and its impact on our reaction and decision-making relative to every-day facts and
circumstances.
Why is cross-cultural competence critical to your professional future and the viability of your
company?
It’s omnipresent in every business interaction and strategic decision.It is not feasible to be an
expert on
all the world’s cultures. It is possible, however, to incorporate a cross-cultural framework that
improves
cross-cultural understanding and interactions.
Multinational firms whose operations are borderless have to consider the cultural variability of
different regions
of the world and develop cultural understanding. Major cultural constraints encountered by
businesses include local
attitudes, taste preferences, language, religion, management style, gender discrimination, skills,
personalities,
education, etc. To be successful, they need to mold their business actions in accordance with the
local cultural models,
they need to establish a global mindset.
Let’s consider an example of the food giant, McDonald’s. The company enjoys a global
presence; operating in more than
100 countries serving 70 million people every day. Their headquarters and senior management
are U.S.-based but they
entrust their local operations to local managers of the countries they operate in. Operations in
more than 50 percent of
their outlets are franchised. Furthermore, their menus are customized according to cultural
habits and local taste
preferences in every country. It is without a doubt that global thinking and cultural
understanding are both powerful
business tools which allow multinational firms to dominate the local markets and establish a
global pres.
How do you stop infinite loop Because I believe that it is making a.pdf
How do you stop infinite loop? Because I believe that it is making an infinite circular list.
c++ code:
Here is the list class:
#ifndef LIN_J_LIST
#define LIN_J_LIST
typedef unsigned int uint;
#include
#include
using namespace std;
/**
* a simplified generic singly linked list class to illustrate C++ concepts
* @author Jerry Lin
* @version 2/17/17
*/
template< typename Object >
class List
{
private:
/**
* A class to store data and provide a link to the next node in the list
*/
class Node
{
public:
/**
* The constructor
* @param data the data to be stored in this node
*/
explicit Node( const Object & data )
: data{ data }, next{ nullptr } {}
Object data;
Node * next;
};
public:
/**
* The constructor for an empty list
*/
List()
: size{ 0 }, first{ nullptr }, last{ nullptr } {}
/**
* the copy constructor-creates and copy the list
*/
List( List && rhs ) = delete;
List( const List & rhs )
{
count = 0;
size = 0;
if(rhs.size != 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first;
size++;
while(current->next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op.
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode->next;
size++;
}
}
// you document and implement this method
}
/**
* the operator= method-copies the list
*/
List & operator=( List && rhs) = delete;
List & operator=( const List & rhs )
{
count = 0;
size = 0;
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
if(rhs.size!= 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first; //create a temporary to store
size++;
while(current -> next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode -> next;
size++;
}
}
return *this;
// you document and implement this method
}
/**
* accessor
* @return count
*/
int get_count() const
{
return count;
}
/**
* The destructor that gets rid of everything that\'s in the list and
* resets it to empty. If the list is already empty, do nothing.
*/
~List()
{
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
}
/**
* Put a new element onto the beginning of the list
* @param item the data the new element will contain
*/
void push_front( const Object& item )
{
Node * new_node = new Node( item );//basic op.
if(is_empty())
{
last = new_node;
}
else
{
new_node->next = first;
}
first = new_node;
size++;
/* you complete the rest */
}
/**
* Remove the element that\'s at the front of the list. Causes an
* assertion error if the list is empty.
*/
void pop_front()
{
assert( !is_empty() );
Node * temp = first;
if( first == last )
{
first = last = nullptr;
}
else
{
first = first->next;
}
delete temp;
size--;
}
/**
* Accessor to return the da.
hi i have to write a java program involving link lists. i have a pro.pdf
hi i have to write a java program involving link lists. i have a problem with the nodes, as it is
posting errors with the nodes.
please help me with this problem. thank you.
public class LinkLists {
/* only need to store a single pointer to the node at the head
* of the list.
* The pointer is null if the list is empty.
* Also record the size of the list.
*/
protected Node head;
/* invariant: size is the number of nodes in the list pointed to by head */
protected int size;
/* no-arguments default constructor creates an empty list */
public LinkLists() {
head = null; // start with an empty list
size = 0;
}
/* accessor method */
public int size() {
return size;
}
/* value to add to the end of the list
*/
public void add(T value) {
head = addAtEnd(head, value);
size++;
}
/* node of the list to which the value should be added
* value to add to the end of the list
*/
private Node addAtEnd(Node node, T value) {
if (node == null) { // special case
return new Node(value, null);
} else if (node.getNext() == null) { // other special case
node.setNext(new Node(value, null));
} else {
addAtEnd(node.getNext(), value);
}
return node;
}
/* iterative implementation of the same method
* value to add to the end of the list
*/
public void add2(T value) {
if (head == null) {
head = new Node(value, null);
} else {
Node node = head; // guaranteed not to be null initially
while (node.getNext() != null) {
node = node.getNext(); // guaranteed not to be null here
}
// now, node.getNext() is guaranteed to be null
// similar to the second special case in addAtEnd
node.setNext(new Node(value, null));
}
size++;
}
public void remove(int position) throws BadItemCountException {
if ((position < 1) || (position > size)) {
throw new
BadItemCountException(\"invalid position \" + position +
\", only 1..\" + size + \" available\");
}
if (position == 1) {
head = head.getNext();
} else {
Node node = head;
for (int i = 2; i < position; i++) {
node = node.getNext();
}
node.setNext(node.getNext().getNext());
}
size--; // one less item
}
public String toString() {
return toString(head);
}
private String toString(Node node) {
if (node == null) {
return \"\";
} else {
return node.getValue() + \"\ \" + toString(node.getNext());
}
}
public static void main(String[] args) {
/* create two empty lists, make sure they print out correctly */
LinkLists list1 = new LinkLists();
LinkLists list2 = new LinkLists();
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* insert some items, keep checking */
list1.add(\"hello\");
list1.add(\"world\");
list2.add(\"foo\");
list2.add(\"bar\");
list2.add(\"baz\");
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* remove an item at an invalid position */
boolean caught = false;
try {
list2.remove(4);
} catch .
Inspect the class declaration for a doubly-linked list node in Node-h-.pdf
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables: a double data value, a pointer to the next node, and a pointer to the previous
node. Each member variable is protected. So code outside of the class must use the provided
getter and setter member functions to get or set a member variable. Node.h is read only, since no
changes are required. Step 2: Implement the Insert() member function A class for a sorted,
doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList class's
Insert() member function. The function must create a new node with the parameter value, then
insert the node into the proper sorted position in the linked list. Ex: Suppose a
SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node with data
value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order
and yielding: 23 35.5 47.25 86 Step 3: Test in develop mode Code in main() takes a space-
separated list of numbers and inserts each into a SortedNumberList. The list is displayed after
each insertion. Ex: If input is 77 15 -42 63.5 then output is: List after inserting 77: 77 List after
inserting 15: 15 77 List after inserting -42: -42 15 77 List after inserting 63.5: -42 15 63.5 77 Try
various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove()
member function Implement the SortedNumberList class's Remove() member function. The
function takes a parameter for the number to be removed from the list. If the number does not
exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the
number is removed from the list and true is returned. Uncomment the commented-out part in
main() that reads a second input line and removes numbers from the list. Test in develop mode to
ensure that insertion and removal both work properly, then submit code for grading. Ex: If input
is 84 72 19 61 19 84 then output is: List after inserting 84: 84 List after inserting 72: 72 84 List
after inserting 19: 19 72 84 List after inserting 61: 19 61 72 84 List after removing 19: 61 72 84
List after removing 84: 61 72
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std; void PrintList(SortedNumberList& list); vector SpaceSplit(string source);
int main(int argc, char *argv[]) { // Read the line of input numbers string inputLine; getline(cin,
inputLine); // Split on space character vector terms = SpaceSplit(inputLine); // Insert each value
and show the sorted list's contents after each insertion SortedNumberList list; for (auto term :
terms) { double number = stod(term); cout << "List after inserting " << number << ": " << endl;
list.Insert(number); PrintList(list); } /* // Read the input line with numbers to remove getline(cin,
inputLi.
Lab-2.4 101.pdf
The document contains C program code to implement three data structures using linked lists:
1) A stack using a singly linked list with push, pop, and display functions.
2) A queue using a singly linked list with enqueue, dequeue, and display functions.
3) A program to merge two sorted linked lists by comparing nodes and appending to the merged list.
Pseudocode and sample test cases are provided for each problem.
Copy your completed LinkedList class from Lab 3 into the LinkedList..pdf
Copy your completed LinkedList class from Lab 3 into the LinkedList.java file below.
During this lab we will add more constructors, an equals method and more challenging methods
as listed below.
Also inspect the LabProgram.java file and notice that the main() method of the LabProgram
copies and compares two linked lists. The main() method also calls the more challenging
methods. Use Develop mode to test your LinkedList iterator code as you develop it.
In Submit mode you will need to complete all lab steps to pass all automatic tests.
Step 2: Implement clear()
Method clear() re-sets the LinkedList to empty as if the default constructor had just been called.
Constructor LinkedList(T[] array) converts the given array into a LinkedList.
Constructor LinkedList(LinkedList original) instantiates a new LinkedList by copying another
List.
Method equals() determines whether the given Object is another LinkedList, containing the same
data in the same order, returning whether there is equality.
Method spinList(int numMoves) moves all nodes in the list towards the end of the list the
number of times specified. Any node that falls off the end of the list as it moves forward will be
placed at the front of the list.
Method altLists() splices together two LinkedLists to create a third List which contains
alternating values from the original list and the given parameter.
*Below is my Lab3 LinkedList.class.
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
public T getFirst() throws NoSuchElementException {
if (first == null) throw new NoSuchElementException();
return first.data;
}
public T getLast() throws NoSuchElementException {
if (last == null) throw new NoSuchElementException();
return last.data;
}
public T getIterator() throws NullPointerException {
if (iterator == null) {
throw new NullPointerException("Iterator is off end.");
}
return iterator.data;
}
public int getLength() {
return length;
}
public boolean isEmpty() {
return length == 0;
}
public boolean offEnd() {
return iterator == null;
}
public void addFirst(T data) {
Node newNode = new Node(data);
if (length == 0) {
first = newNode;
last = newNode;
} else .
STAGE 2 The Methods 65 points Implement all the methods t.pdf
STAGE 2: The Methods (65 points) Implement all the methods that are marked as Left as
Exercise. The Driver program only works when you have done all the methods. I have added the
template of all the methods with a placeholder value as return types of the methods. For example,
return 0 if method returns an int value.
List of the methods left as exercise are as follows: /** Create a list from an array of objects */
@SuppressWarnings("unchecked") public MyLinkedList(E[] objects) /** Add a new element at the
specified index in this list in ascending order */ public void addInOrder(E e) /** Check to see if this
list contains element e */ public boolean contains(E e) /** Remove all the occurrences of the
element e * from this list. Return true if the element is * removed. */ public boolean removeAll(E e)
/** Remove the first occurrence of the element e * from this list. Return true if the element is *
removed. */ public boolean remove(E e) /** Return the element at the specified index */ public E
get(int index) /** Return the index of the head matching element in * this list. Return -1 if no match.
*/ public int indexOf(Object e) /** Return the index of the last matching element in * this list. Return
-1 if no match. */ public int lastIndexOf(E e) /** Replace the element at the specified position * in
this list with the specified element. */ public E set(int index, E e) /** Print this list using recursion */
public void printList() /** Returns an array containing all of the elements * in this collection; * the
runtime type of the returned array is that of * the specified array. */ public <E> E[] toArray(E[]
array) /** Split the original list in half. The original * list will continue to reference the * front half of
the original list and the method * returns a reference to a new list that stores the * back half of the
original list.
public class MyLinkedList<E extends Comparable<E>> {
private Node<E> head, tail;
private int size = 0; // Number of elements in the list
public MyLinkedList() {
head=tail=null;
size=0;
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node<E> newNode = new Node<>(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node<E> newNode = new Node<>(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = newNode; // tail now points to the last node
}
size++; // Incr.
public class MyLinkedListltE extends ComparableltEgtg.pdf
public class MyLinkedList<E extends Comparable<E>> {
private Node<E> head, tail;
private int size = 0; // Number of elements in the list
public MyLinkedList() {
head=tail=null;
size=0;
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node<E> newNode = new Node<>(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node<E> newNode = new Node<>(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = newNode; // tail now points to the last node
}
size++; // Increase size
}
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node<E> current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node<E> temp = current.next;
current.next = new Node<>(e);
(current.next).next = temp;
size++;
}
}
//Add e to the end of this linkedlist
public void add(E e) {
// Left as Exercise
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
E temp = head.element;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return temp;
}
}
/** Remove the last node and
* return the object that is contained in the removed node. */
public E removeLast() {
if (size == 0) {
return null;
}
else if (size == 1) {
E temp = head.element;
head = tail = null;
size = 0;
return temp;
}
else {
Node<E> current = head;
for (int i = 0; i < size - 2; i++) {
current = current.next;
}
E temp = tail.element;
tail = current;
tail.next = null;
size--;
return temp;
}
}
/** Remove the element at the specified position in this
* list. Return the element that was removed from the list. */
public E remove(int index) {
if (index < 0 || index >= size) {
return null;
}
else if (index == 0) {
return removeFirst();
}
else if (index == size - 1) {
return removeLast();
}
else {
Node<E> previous = head;
for (int i = 1; i < index; i++) {
previous = previous.next;
}
Node<E> current = previous.next;
previous.next = current.next;
size--;
return current.element;
}
}
/** Clear the list */
public void clear() {
size = 0;
head = tail = null;
}
/** Override toString() to return elements in the list in [] separated by , */
public String toString() {
StringBuilder result = new StringBuilder("[");
Node<E> current = head;
for (int i = 0; i < size; i++) {
result.append(current..
Data Structures in C++I am really new to C++, so links are really .pdf
Data Structures in C++
I am really new to C++, so links are really hard topic for me. It would be nice if you can provide
explanations of what doubly linked lists are and of some of you steps... Thank you
In this assignment, you will implement a doubly-linked list class, together with some list
operations. To make things easier, you’ll implement a list of int, rather than a template class.
Solution
A variable helps us to identify the data. For ex: int a = 5; Here 5 is identified through variable a.
Now, if we have collection of integers, we need some representation to identify them. We call it
array. For ex: int arr[5]
This array is nothing but a Data Structure.
So, a Data Structure is a way to group the data.
There are many Data Structures available like Arrays, Linked List, Doubly-Linked list, Stack,
Queue, etc.
Doubly-Linked list are the ones where you can traverse from the current node both in left and
right directions.
Why so many different types of Data Structures are required ?
Answer is very simple, grouping of data, storage of data and accessing the data is different.
For example, in case of Arrays we store all the data in contiguous locations.
What if we are not able to store the data in contiguous locations because we have huge data.
Answer is go for Linked List/Doubly-Linked list.
Here we can store the data anywhere and link the data through pointers.
I will try to provide comments for the code you have given. May be this can help you.
#pragma once
/*
dlist.h
Doubly-linked lists of ints
*/
#include
class dlist {
public:
dlist() { }
// Here we are creating a NODE, it has a integer value and two pointers.
// One pointer is to move to next node and other to go back to previous node.
struct node {
int value;
node* next;
node* prev;
};
// To return head pointer, i.e. start of the Doubly-Linked list.
node* head() const { return _head; }
// To return Tail pointer, i.e. end of the Doubly-Linked list.
node* tail() const { return _tail; }
// **** Implement ALL the following methods ****
// Returns the node at a particular index (0 is the head).
node* at(int index){
int cnt = 0;
struct node* tmp = head();
while(tmp!=NULL)
{
if (cnt+1 == index)
return tmp;
tmp = tmp->next;
}
}
// Insert a new value, after an existing one
void insert(node *previous, int value){
// check if the given previous is NULL
if (previous == NULL)
{
printf(\"the given previous node cannot be NULL\");
return;
}
// allocate new node
struct node* new_node =(struct node*) malloc(sizeof(struct node));
// put in the data
new_node->data = new_data;
// Make next of new node as next of previous
new_node->next = previous->next;
// Make the next of previous as new_node
previous->next = new_node;
// Make previous as previous of new_node
new_node->prev = previous;
// Change previous of new_node\'s next node
if (new_node->next != NULL)
new_node->next->prev = new_node;
}
// Delete the given node
void del(node* which){
struct node* head_ref = head();
/* base case */
if(*head_ref == NUL.
Labprogram.javaLinkedList.javaimport java.util.NoSuchElementEx.pdf
Labprogram.java
LinkedList.java
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
*
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
*
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
public T getFirst() throws NoSuchElementException {
if (isEmpty()) {
throw new NoSuchElementException("The list is empty");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (isEmpty()) {
throw new NoSuchElementException("The list is empty");
}
return last.data;
}
public T getIterator() throws NullPointerException {
if (iterator != null) {
return iterator.data;
} else {
throw new NullPointerException("Iterator is off the end opf the list.");
}
}
public int getLength() {
return length;
}
public boolean isEmpty() {
return length == 0;
}
public boolean offEnd() {
return iterator == null;
}
public void addFirst(T data) {
Node newNode = new Node(data);
if (isEmpty()) {
first = newNode;
last = newNode;
} else {
newNode.next = first;
first.prev = newNode;
first = newNode;
}
length++;
}
public void addLast(T data) {
Node newNode = new Node(data);
if (isEmpty()) {
first = newNode;
last = newNode;
} else {
last.next = newNode;
newNode.prev = last;
last = newNode;
}
length++;
}
public void addIterator(T data) throws NullPointerException {
if (offEnd()) {
throw new NullPointerException("addIterator Iterator is off end.");
}
if (iterator == last) {
addLast(data);
} else {
Node newNode = new Node(data);
Node next = iterator.next;
newNode.next = next;
newNode.prev = iterator;
iterator.next = newNode;
next.prev = newNode;
length++;
}
}
public void removeFirst() throws NoSuchElementException {
if (isEmpty()) {
throw new NoSuchElementException("The list is empty");
}
if (length == 1) {
first = null;
last = null;
iterator = null;
} else {
if (iterator == first) {
iterator = null;
}
first = first.next;
first.prev = null;
}
length--;
}
public void removeLast() throws NoSuchElementException {
if (isEmpty()) {
throw new NoSuchElementException("The list is empty");
}
if (length == 1) {
first = null;
last = null;
iterator = null;
} else {
if (iterator == last) {
iterator = null;
}
last = last.prev;
last.next = null;
}
length--;
}
public void removeIterator() throws NullPointerException {
if (offEnd()) {
throw new NullPointerException("Iterator is off the end opf the list.");
}
if (iterator .
In C++ please, do not alter node.hStep 1 Inspect the Node.h file.pdf
In C++ please, do not alter node.h
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new
node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
77 15 -42 63.5
then output is:
List after inserting 77:
77 List after inserting 15:
15 77
List after inserting -42:
-42 15 77
List after inserting 63.5:
-42 15 63.5 77
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
84 72 19 61 19 84
then output is:
List after inserting 84:
84
List after inserting 72:
72 84
List after inserting 19:
19 72 84
List after inserting 61:
19 61 72 84
List after removing 19:
61 72 84
List after removing 84:
61 72
Code below:
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = Space.
Write a function to merge two doubly linked lists. The input lists ha.pdf
Write a function to merge two doubly linked lists. The input lists have their elements in sorted
order, from lowest to highest. The output list should also be sorted from lowest to highest. Your
algorithm should run in linear time on the length of the output list. Provide an algorithm for your
function Implement and show some samples of your running function
Solution
The algorithm for LinkedList MergeSort is as follows.
The trick in this algorithm is to use a local list to store the value which is pointing to the actual
list to be returned as a result of the function
Step1: START
Step2: GET inputs of list1 and list2
Step3: INITIALIZE mergelist
STEP4: SET mylist = mergelist
Step5: WHILE list1 OR list2 is EMPTY
DO
IF (list1 AND list2) are NOT EMPTY
IF list1.value > list2.value
mylist.next = list2
ELSE
mylist.next = list1
ELSE IF list1 is EMPTY
mylist.next = list2
ELSE
mylist.next = list1
Step6: RETURN mergelist
Step7: STOP
Sample program for the same implemented in C++
//====================================================================
========
// Name : DoublyLinkedList.cpp
// Author : Kaju
// Version : 0.1
// Copyright : This is just an example code
// Description : MergeSort in C++, Ansi-style
//====================================================================
========
/*
* C++ Program to Implement Doubly Linked List
*/
#include
#include
#include
/*
* Node Declaration
*/
using namespace std;
// struct declaration for node which will hold the integer data with links to previous data and next
data
struct node
{
int data;
struct node *next;
struct node *prev;
};
/*
Class Declaration
*/
class DoublyLinkedList
{
private:
struct node *start; // collection of all the nodes
public:
void create(int value);
int peek();
int delete_head();
void display();
int count();
void mergeSort(DoublyLinkedList list1, DoublyLinkedList list2);
DoublyLinkedList()
{
start = NULL;
}
};
/*
* Add data into the list
*/
void DoublyLinkedList::create(int value)
{
struct node *s, *temp;
temp = new(struct node);
temp->data = value;
temp->next = NULL;
if (start == NULL)
{
temp->prev = NULL;
start = temp;
}
else
{
s = start;
while (s->next != NULL)
s = s->next;
s->next = temp;
temp->prev = s;
}
}
/*
* Deletion of the first element from the list
* store the first element in a temp node and then remove it from start.
*/
int DoublyLinkedList::delete_head()
{
struct node *tmp, *q;
int value;
tmp = start;
if(start->next!=NULL)
{
start = start->next;
start->prev = NULL;
}
else
start = NULL;
value = tmp->data;
free(tmp);
return value;
}
/*
* return the first element of Doubly Link List
*/
int DoublyLinkedList::peek()
{
struct node *q;
if (start == NULL)
{
cout<<\"List is empty\"<data;
}
}
/*
* Display elements of Doubly Link List
*/
void DoublyLinkedList::display()
{
struct node *q;
if (start == NULL)
{
cout<<\"List is empty\"<data;
q = q->next;
if(q != NULL)
{
cout<<\", \";
}
}
cout<<\"]\"<next;
cnt++;
}
return cnt;
}
/*
* MergeSort - takes two input lists and then based on the.
File LinkedList.java Defines a doubly-l.pdf
File: LinkedList.java
/**
* Defines a doubly-linked list class
*/
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
/**** ACCESSORS ****/
/**
* Returns the value stored in the first node
* @precondition
* @return the value stored at node first
* @throws NoSuchElementException
*/
public T getFirst() throws NoSuchElementException {
return null;
}
/**
* Returns the value stored in the last node
* @precondition
* @return the value stored in the node last
* @throws NoSuchElementException
*/
public T getLast() throws NoSuchElementException {
return null;
}
/**
* Returns the data stored in the iterator node
* @precondition
* @return the data stored in the iterator node
* @throw NullPointerException
*/
public T getIterator() throws NullPointerException {
return null;
}
/**
* Returns the current length of the LinkedList
* @return the length of the LinkedList from 0 to n
*/
public int getLength() {
return -1;
}
/**
* Returns whether the LinkedList is currently empty
* @return whether the LinkedList is empty
*/
public boolean isEmpty() {
return false;
}
/**
* Returns whether the iterator is offEnd, i.e. null
* @return whether the iterator is null
*/
public boolean offEnd() {
return false;
}
/**** MUTATORS ****/
/**
* Creates a new first element
* @param data the data to insert at the front of the LinkedList
* @postcondition
*/
public void addFirst(T data) {
return;
}
/**
* Creates a new last element
* @param data the data to insert at the end of the LinkedList
* @postcondition
*/
public void addLast(T data) {
return;
}
/**
* Inserts a new element after the iterator
* @param data the data to insert
* @precondition
* @throws NullPointerException
*/
public void addIterator(T data) throws NullPointerException{
return;
}
/**
* removes the element at the front of the LinkedList
* @precondition
* @postcondition
* @throws NoSuchElementException
*/
public void removeFirst() throws NoSuchElementException {
return;
}
/**
* removes the element at the end of the LinkedList
* @precondition
* @postcondition
* @throws NoSuchElementException
*/
public void removeLast() throws NoSuchElementException {
return;
}
/**
* removes the element referenced by the iterator
* @precondition
* @pos.
Data Structures and Agorithm: DS 05 Doubly Linked List.pptx
Data Structures and Agorithm: DS 05 Doubly Linked List.pptx
Need done for Date Structures please! 4-18 LAB- Sorted number list imp.pdf
Need done for Date Structures please!
4.18 LAB: Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number.
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LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
This Dissertation explores the particular circumstances of Mirzapur, a region located in the
core of India. Mirzapur, with its varied terrains and abundant biodiversity, offers an optimal
environment for investigating the changes in vegetation cover dynamics. Our study utilizes
advanced technologies such as GIS (Geographic Information Systems) and Remote sensing to
analyze the transformations that have taken place over the course of a decade.
The complex relationship between human activities and the environment has been the focus
of extensive research and worry. As the global community grapples with swift urbanization,
population expansion, and economic progress, the effects on natural ecosystems are becoming
more evident. A crucial element of this impact is the alteration of vegetation cover, which plays a
significant role in maintaining the ecological equilibrium of our planet.Land serves as the foundation for all human activities and provides the necessary materials for
these activities. As the most crucial natural resource, its utilization by humans results in different
'Land uses,' which are determined by both human activities and the physical characteristics of the
land.
The utilization of land is impacted by human needs and environmental factors. In countries
like India, rapid population growth and the emphasis on extensive resource exploitation can lead
to significant land degradation, adversely affecting the region's land cover.
Therefore, human intervention has significantly influenced land use patterns over many
centuries, evolving its structure over time and space. In the present era, these changes have
accelerated due to factors such as agriculture and urbanization. Information regarding land use and
cover is essential for various planning and management tasks related to the Earth's surface,
providing crucial environmental data for scientific, resource management, policy purposes, and
diverse human activities.
Accurate understanding of land use and cover is imperative for the development planning
of any area. Consequently, a wide range of professionals, including earth system scientists, land
and water managers, and urban planners, are interested in obtaining data on land use and cover
changes, conversion trends, and other related patterns. The spatial dimensions of land use and
cover support policymakers and scientists in making well-informed decisions, as alterations in
these patterns indicate shifts in economic and social conditions. Monitoring such changes with the
help of Advanced technologies like Remote Sensing and Geographic Information Systems is
crucial for coordinated efforts across different administrative levels. Advanced technologies like
Remote Sensing and Geographic Information Systems
9
Changes in vegetation cover refer to variations in the distribution, composition, and overall
structure of plant communities across different temporal and spatial scales. These changes can
occur natural.
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RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
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For this micro assignment, you must implement two Linked List functi.docx
- 1. For this micro assignment, you must implement two Linked List functions. We will use the following example Linked List: 2 0 -1 5 7 getElementAt(index) This function should return the element (i.e. value) of the Nth item inside the linked list. For example, on the Linked List above, getElementAt(0) should return 2; getElementAt(3) should return 5. addElementAt(value, location) This function should insert a new value at the given location. Note that the location supplied must be within bounds of the LinkedList. For example, we cannot call addElementAt(4, 11) on the above Linked List because 11 is beyond the size of the Linked List. Here are some examples. If we call addElementAt(0, 1), the above Linked List would now look like: 1 2 0 -1 5 7 If we again call addElementAt(2, 123), we would get: 1 2 123 0 -1 5 7
- 2. Grading Your submission will be graded based on the following: 1. [7] Your solution does not cause any runtime issues and your file passes all test cases 2. [3] Your code contains good style. For example, ble names @@@@@@@@@@@@@@@@@@@@@@@@ #ifndef LINKED_LIST_H #define LINKED_LIST_H #include #include #include "LinkedListNode.h" #include using namespace std;
- 3. template class LinkedList { private: //points to the front of the linked list LinkedListNode *_front = nullptr; //keeping track of size in a variable eliminates need to continually //count LL boxes. int _size = 0; protected: //creates a new LinkedListNode for us virtual LinkedListNode *createNode(T value)
- 4. { return new LinkedListNode < T > { value }; } public: //default constructor LinkedList() { _front = nullptr; } //copy constructor LinkedList(const LinkedList &other) { for (int i = 0; i < other.getSize(); i++) { addElement(other.getElementAt(i));
- 5. } } //move constructor LinkedList(LinkedList &&other) { //take other's data _front = other._front; _size = other._size; //reset other's pointers other._front = nullptr; } //initializer list constructor LinkedList(initializer_list values) { for (auto item : values)
- 6. { addElement(item); } } //Always remember to clean up pointers in destructor! virtual ~LinkedList() { LinkedListNode *current = _front; while (current != nullptr) { LinkedListNode *temp = current->getNext(); delete current; current = temp; } } //will return true if the LL is empty.
- 7. virtual bool isEmpty() const { return _size == 0; } //returns the size of the LL. virtual int getSize() const { return _size; } //adds the supplied item to the end of our LL virtual void addElement(T value) { addElementAt(value, getSize()); } //Returns the value of the LinkedListNode at the given index
- 8. virtual T& getElementAt(int index) { //MA #1 TODO: ACTUALLY IMPLEMENT! **************** add here int value = -1; return value; } //adds the specified item at the specified index and shifts everything else //to the "right" by one. virtual void addElementAt(T value, int location) { LinkedListNode *new_value = createNode(value); //MA #1 TODO: IMPLEMENT! ************** and here // Add variable new_value to proper location inside // our linked list.
- 9. } }; #endif // !LINKED_LIST_H @@@@@@@@@@@@@@@@@@@@@@@ #ifndef LINKED_LIST_NODE_H #define LINKED_LIST_NODE_H //A linked list node represents a single "box" inside a lined list. In this //scheme, the LinkedList is simply a collection of LinkedListNode boxes. template class LinkedListNode { protected:
- 10. //value that our box contains T _value; //pointer to next node in the LL sequence LinkedListNode *_next; public: //constructor must accept a default value LinkedListNode(const T &value) : _value(value) { _next = nullptr; } LinkedListNode() { _next = nullptr; }
- 11. //copy constructor prevents premature deletion of next pointer LinkedListNode(const LinkedListNode &other) { _value = other.getValue(); _next = other.getNext(); } virtual ~LinkedListNode() { } //copy operator allows us to reassign previously created list nodes LinkedListNode &operator=(const LinkedListNode &other) { if (this != &other)
- 12. { LinkedListNode temp(other); swap(*this, temp); } return *this; } //returns a pointer to the next list node in the sequence LinkedListNode *getNext() { return _next; } //sets the pointer to the next node in the sequence void setNext(LinkedListNode *next) { _next = next; }
- 13. //returns the value of the list node T &getValue() { return _value; } //constant version of the getter const T& getValue() const { return _value; } //sets the value of the current list node void setValue(const T &value) { _value = value; }
- 14. }; #endif @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ @ #include #include #include "LinkedList.h" using namespace std; void linkedListTest() { cout << "***Linked List Test***" << endl; LinkedList test_list{}; test_list.addElementAt(0, 1); test_list.addElementAt(1, 2); test_list.addElementAt(0, 3);
- 15. test_list.addElementAt(2, 4); cout << "Number of elements in LL: " << test_list.getSize() << " (expected: 4)" << endl; cout << "Value at 0: " << test_list.getElementAt(0) << " (expected: 3)" << endl; cout << "Value at 1: " << test_list.getElementAt(1) << " (expected: 1)" << endl; cout << "Value at 2: " << test_list.getElementAt(2) << " (expected: 4)" << endl; cout << "Value at 3: " << test_list.getElementAt(3) << " (expected: 2)" << endl; } int main() { linkedListTest(); }