This document discusses an approach to solving the FizzBuzz coding challenge in Ruby using complex numbers. It presents a one-line Ruby code that evaluates to an array mapping each number from 1 to 100 to either "Fizz", "Buzz", "FizzBuzz", or the number itself. This is done by taking the argument of the complex number (n%3)i - (n%5), which returns the appropriate string depending on whether n is divisible by 3, 5, or both.

1. FizzBuzz in Complex Plane
Kaoru Maeda
@mad_p
Feb. 2013

2. FizzBuzz Code Golf in Ruby (Tokyo Ruby Kaigi 10*)
My answer (77 chars):
puts eval($*.join'..').map{|n|%W[FizzBuzz Buzz #{n} Fizz][((n%3).i-n%5).arg]}
Im
Select Fizz, Buzz, FizzBuzz, or Number by
êarg((nmod3)i - (nmod 5))ú
ë
û
14
8
2
Buzz
11
5
nmod3
4
13
7
1
10
Fizz
1,2,3 radians
9
3
12
-nmod5
* http://codeiq.hatenablog.com/entry/2013/01/16/002033
6
0
Re
FizzBuzz
(Luckily, 0.arg == 0 in Ruby)