Explain the use of the half year convention for MACRS deprecation fo.pdf
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Explain the use of the half year convention for MACRS deprecation for assets other than real estate and the exception to the half-year convention rule. Year of the acquisition Year of disposal Mid-quarter convention Solution An applicable convention, is an assumption about when property is placed into service. It is used to determine when property depreciation begins. There are three types of conventions. The first, the “half-year convention,” assumes that all property placed into service, or disposed of, during a taxable year was placed into service, or disposed of, at the midpoint of that year. The second, the “mid-month convention,” assumes that all property placed into service, or disposed of, during any month was placed into service, or disposed of, at the midpoint of that month. The third, the “mid-quarter convention,” assumes that all property placed into service, or disposed of, during any quarter of a taxable year was placed into service, or disposed of, at the midpoint of that quarter. Half-Year Convention This convention applies to all depreciable tangible personal property. Exemptions: Residential rental and non residential real property Property subject to mid-quarter convention Mid-quarter convention If more than 40% of the total basis of property is placed in service during the last three months of the tax year, the mid-quarter convention applies. Exemptions: Property that is being depreciated under a method other than MACRS..
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Accounting for Leases .docx
Accounting for Leases
Unit-III
Leasing Environment:
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expressed in terms of the operators?
Solution
The parity transformation, P, is a unitary operator, acting on a state as follows: P(r) = ei/2(r).
Also, P2(r) =ei(r), since an overall phase is unobservable. The operatorP2, which reverses the
parity of a state twice, leaves the spacetime invariant, and so is an internal symmetry which
rotates its eigenstates by phasesei. IfP2is an elementeiQof a continuous U(1) symmetry group of
phase rotations, theneiQ/2is part of this U(1) and so is also a symmetry. We can defineP=PeiQ/2,
which is also a symmetry, and so we can choose to callPour parity operator, instead ofP. Note
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Write a function which return a list of all of the n element subset .pdf
Write a function which return a list of all of the n element subset of a given set
Implement in JAVA Question 3 Write a function that returns a list of all of the n-element subsets
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contain [1,2], [1,3], and [2,3]. The order of the elements is not important.
Solution
The program for this problem is as follows:
Comments are included in the program for explaining the steps.
A sample output is attached below the program.
package com.temp;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
/**
* Program to find sublists of a list.
* @author Rohit Phatak
*
*/
public class subset {
/**
* This list will contain the resultant sublists.
*/
static List list = new ArrayList<>();
public static void main(String arg[]){
/**
* Input a list comma separated.
*/
System.out.println(\"Enter a list : \");
Scanner scanner = new Scanner(System.in);
String s = scanner.nextLine();
String[] sArr = s.split(\",\");
/**
* Input a value of n.
*/
System.out.println(\"Enter value of n : \");
Integer n = scanner.nextInt();
/**
* Check if value of n is greater than entered list.
*/
if(sArr.length < n){
System.out.println(\"Length of list is less than value of n\");
} else if(sArr.length > 0){
getSubsetList(sArr,n);
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/**
* Printing the sublists.
*/
for(String[] str : list){
String printVar = \"\";
for(String temps : str)
printVar+=temps+\",\";
System.out.println(\"[\"+printVar.substring(0, printVar.length()-1)+\"]\");
}
} else {
System.out.println(\"Please enter atleast one element:\");
}
scanner.close();
}
/**
* This method calls the recursive function which is used to obtain the sublists.
* @param sArr
* @param n
* @return
*/
public static List getSubsetList(String[] sArr,Integer n){
List lista = new ArrayList<>();
sublist(sArr, 0, n, new String[n]);
return lista;
}
/**
* This is a recursive function.
* This function will iterate over itself for finding the sublist.
*
* Parameters are as follows:
*
* @param arr -> List entered by the user.
* @param n -> Value of sublist entered by user.
* @param startPosition -> index to start creating the sublist.
* @param result -> resultant sublist
*/
public static void sublist(String[] arr, int startPosition, int n, String[] result){
/**
* Check for the value of n ==0.
* If n==0 break from the recursion.
*/
if (n == 0){
/**
* Add the sublist \'result\' in the list.
*/
list.add(result.clone());
return;
}
/**
* Iterate through for loop starting from startPosition till length of list minus entered value
n.
*/
for (int i = startPosition; i <= arr.length-n; i++){
/**
* Here result is a temporary sublist.
* This for loop adds an element to the temporary sublist in each iteration.
* The element is added from the complete list entered by user.
* Location of element is iTh index.
*/
result[result.length - n] = arr[i];
/**
* After adding the element to the temporary sublist, the sublist an.
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Accounting for Leases .docx
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1. Transfers ownership to the lessee.
2. Contains a bargain purchase option.
3. Lease term is equal to or greater than 75 percent of the estimated economic life of the leased property.
4. The present value of the minimum lease payments (excluding executor costs) equals .
Leases
Leases means good business sense to many business-men. Leases provide most convenient mode of financing assets.
Tenant's Rights Presentation
This is the Powerpoint slideshow presented by Erika Lim and Mike Ellsworth to the Law Society and attendees of the Tenant's Rights Workshop.
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rotates its eigenstates by phasesei. IfP2is an elementeiQof a continuous U(1) symmetry group of
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Solution
The program for this problem is as follows:
Comments are included in the program for explaining the steps.
A sample output is attached below the program.
package com.temp;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
/**
* Program to find sublists of a list.
* @author Rohit Phatak
*
*/
public class subset {
/**
* This list will contain the resultant sublists.
*/
static List list = new ArrayList<>();
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*/
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*/
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*/
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List lista = new ArrayList<>();
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}
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*
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*
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* @param result -> resultant sublist
*/
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/**
* Check for the value of n ==0.
* If n==0 break from the recursion.
*/
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* Add the sublist \'result\' in the list.
*/
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*/
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*/
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Q.No 1
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Q.No 2
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Q.No 3
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program using namespace std;
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{
private:
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{
public:
int data;
Node *left, *right;
Node(int d=0)
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};
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Node * trav(int, Node * &);
void chop(Node * N);
void copy(Node * N);
void print(ostream &, Node *, int) const;
void print(Node *, int) const;
public:
BStree(void);
~BStree(void);
bool find(int);
void insert(int);
void remove(int);
bool empty(void) const;
Tree(const BStree &);
const BStree & operator=(const BStree &);
friend ostream & operator<<(ostream &, const BStree &);
};
BStree::BStree(void)
{
root=NULL;
}
bool Tree::empty(void) const
{
return !root;
}
BStree::Node * BStree::trav(int foo, Node * & par)
{
Node * curr=root;
par=NULL;
while(curr && curr->data != foo)
{
par=curr;
if(foo < curr->data)
curr=curr->left;
else
curr=curr->right;
}
return curr;
}
bool BStree::find(int foo)
{
Node * par=NULL;
Node * curr=trav(foo, par);
return curr;
}
void BStree::insert(int foo)
{
Node * par=NULL;
Node * curr=trav(foo,par);
if(!curr)
{
curr= new Node(foo);
if(!par)
root=curr;
else if(foo < par->data)
par->left=curr;
else
par->right=curr;
}
}
void BStree::remove(const int foo)
{
Node * par=NULL;
Node * curr=trav(foo,par);
if(curr)
{
if(curr->left && curr->right)
{
Node * tmp=curr;
par=curr;
curr=curr->left;
while(curr->right)
{
par=curr;
curr=curr->right;
}
tmp->data=curr->data;
}
Node *tmp=(curr->left ? curr->left : curr->right);
if(!par)
root=tmp;
else if(par->data < curr->data)
par->right=tmp;
else
par->left=tmp;
delete curr;
}
}
void BStree::chop(Node *N)
{
if(N)
{
chop(N->left);
chop(N->right);
delete N;
}
}
BStree::~BStree(void)
{
chop(root);
}
BStree::BStree(const BStree & T)
{
root=NULL;
copy(T.root);
}
void BStree::copy(Node * N)
{
if(N)
{
insert(N->data);
copy(N->left);
copy(N->right);
}
}
const BStree & BStree::operator=(const BStree & T)
{
if(this != &T)
{
chop(root);
root=NULL;
copy(T.root);
}
return *this;
}
void BStree::print(ostream & ost, Node * curr, int level) const
{
if(curr)
{
print(ost,curr->right,level+1);
ost<data<le.
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ve targets. ball and sodket hinge joint condyloid joint saddle joint Ch 05 HW Ch 08 HW pivot
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Solution
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is the wrist joint.
Saddle joint : The carpometacarpal joint of the thumb makes the human thumb opposable by
allowing it to move across the palm to contact the other four fingers of the hand.
Plane joint :Plane joints permit sliding movements in the plane of articular surfaces.
This one is for you - assume that this pedigree shows the inheritance.pdf
This one is for you - assume that this pedigree shows the inheritance of a rare autosomal
condition. Note that the father (II-4) is a known carrier and that this couple has had 3 normal
children. What is the probability that she is a carrier?
Solution
The disease is rare autosomal. In other words it is autosomal recessive disorder. Now the male
and female in II-1 and II-2 have disease. Lets call their genotype as \"aa\". But Their parents in I
generation are normal. This means they are carriers of the disease with genotype Aa and Aa.
Their third daughter II-3 has no disease, Her genotype can be Aa or AA, so probability to carry a
recessive allee a is 1/2. If she had had a diseased child, her genotype would have been Aa with
100%probability. But as has all healthy kids, probability of her being carrier is 1/2..
There are 7 people in the elevator in a 10-story building. They are .pdf
There are 7 people in the elevator in a 10-story building. They are allequally likely to exit on any
oor and they are independent of each other.What is the probability that 3 of them will exit on one
oor, 2 on another,and the last two on two dierent oors.
Solution
As the events are independent, probability can be calculated as below.
P(3)=3/7=0.43 that is 3 people exit on floor floor
P(2)=2/7=0.29 that is 2 people exit on another floor
P(1)=1/7=0.14 that is probability of last two person each who will exit on different floors.
Here events are independent so events are not affected by previous events and so we have
calculated probability for each one of them with same n=7..
safety Construction Safety-Quiz 1 According to OSHA, what must man.pdf
safety Construction Safety-Quiz 1 According to OSHA, what must management provide for their
workers/employees? When and for what reason does OSHA require an employer to provide a
certified first aid responder on a construction site 1926 as compared to 1910? are moving signs,
provided by workers, such as flaggers, or devices, such as flashing lights, to warn of possible
existing hazards. ASHA are the warnings of hazard, temporarily or permanently affixed or
placed, at a person approved or assigned by the employer to perform a specific type of one who,
by possession of a recognized degree, certificate, or professional locations where hazards exist.
duty or to be at a specific location at a jobsite. standing......has successfully demonstrated his/her
ability to solve problems relating to the Name the four parts of a Safety and Health program:
Name to three type of citations OSHA issues to standards?Alashi What does the OSHA standard
5a1 cover or réter to Sape s that are non-compliant with OSHA harka to companies that fail to
comply with their standards. 18. OSHA issues 2 Discuss Direct and Indirect Costs involving an
employee injury/accident . What are the 4 elements of OSHA\'s Focus Four policy and discuss
what companies are required to have in place in order to qualify for a Focus 4 inspection as
compared to a comprehensive (wall to wall) project inspection. asing mo
Solution
Answer1. Under the OSHA law, employers have a responsibility to provide a safe workplace.
Provide a workplace free from serious recognized hazards and comply with standards, rules and
regulations issued under the OSHA Act.
Examine workplace conditions to make sure they conform to applicable OSHA standards.
Make sure employees have and use safe tools and equipment and properly maintain this
equipment.
Provide medical examinations and training when required by OSHA standards and many other
OSHA standards.
Answer2. OSHA\'s standard for first aid training at Construction site
In the absence of an infirmary, clinic, or hospital in near proximity to the workplace which is
used for the treatment of all injured employees, a person or persons shall be adequately trained to
render first aid. Adequate first aid supplies shall be readily available.
The primary requirement addressed by these standards is that an employer must ensure prompt
first aid treatment for injured employees, either by providing for the availability of a trained first
aid provider at the worksite, or by ensuring that emergency treatment services are within
reasonable proximity of the worksite.
Answer3. The OSHA standards are divided into four major categories based on the type of work
being performed:agriculture(1928), construction (Part 1926), general industry (Part 1910) and
maritime (Part 1918).
The construction standard states that fall protection is required when an employee is working on
a walking/working surface (horizontal and vertical surface) with an unprotected side or edge
which is six feet or more a.
Question 1 A ____________ is an intelligent device that controls the.pdf
Question 1 A ____________ is an intelligent device that controls the flow or transmissions in
and out of a network. A. bridge B. gateway C. router D. switch 2.5 points
Question 2 A _____________________ provides a physical address to a device because it has a
unique ID written on a chip that is mounted in the card. A. network interface card B. sound card
C. repeater D. physical cable 2.5 points
Question 3 What type of network connects devices in a limited geographical area? A. MAN B.
LAN C. WAN D. PAN 2.5 points
Question 4 Each computer attached to a network or the Internet has a unique address called a(n)
________. A. local address B. IP address C. network address D. Internet address 2.5 points
Question 5 In February of 2011 the Internet Assigned Number Authority (IANA) assigned the
last block of IPv4 addresses. What is the new address standard? A. IPV5 B. IPv6 C. IPv7 D.
DARPA
Solution
Answer 1. A Router is an intelligent device that controls the flow or transmissions in and out of a
network.
the correct option is C. Router
Answer 2. A network interface card provides a physical address to a device because it has a
unique ID written on a chip that is mounted in the card.
the correct option is A. network interface card
Answer 3. What type of network connects devices in a limited geographical area?
Answer is LAN. option B. LAN
Answer 4. Option B. IP address
Answer 5. IPv6 option B..
I finished most of the program, but having trouble with some key fea.pdf
I finished most of the program, but having trouble with some key features. I bolded and italicized
the parts I can\'t figure out, and included them below. I included my code at the bottom. Thanks!
1. I can\'t get my RemoveItem() and ModifyItem() functions to work.
2. GetNumItemsInCart() is returning the wrong value. For example, my cart has 5 chocolate chip
cookies, 1 headphone, and 2 sneakers. GetNumItemsInCart() returns 3 instead of 8 when I output
my shopping cart.
3. When PrintDescriptions() is called, the first letter of my item description is missing. For
example, for the chocolate chip cookies, the description is Semi-sweet. When PrintDescriptions()
is called, it returns emi-sweet, with the S gone.
4. Shopping Cart improperly initialized with default constructor , and I don\'t know why.
12.9 Program: Online shopping cart (continued) (C++)
This program extends the earlier \"Online shopping cart\" program.
(1) Extend the ItemToPurchase class per the following specifications:
Parameterized constructor to assign item name, item description, item price, and item quantity
(default values of 0). (1 pt)
Public member functions
SetDescription() mutator & GetDescription() accessor (2 pts)
PrintItemCost() - Outputs the item name followed by the quantity, price, and subtotal
PrintItemDescription() - Outputs the item name and description
Private data members
string itemDescription - Initialized in default constructor to \"none\"
Ex. of PrintItemCost() output:
Ex. of PrintItemDescription() output:
(2) Create three new files:
ShoppingCart.h - Class declaration
ShoppingCart.cpp - Class definition
main.cpp - main() function (Note: main()\'s functionality differs from the warm up)
Build the ShoppingCart class with the following specifications. Note: Some can be function
stubs (empty functions) initially, to be completed in later steps.
Default constructor
Parameterized constructor which takes the customer name and date as parameters (1 pt)
Private data members
string customerName - Initialized in default constructor to \"none\"
string currentDate - Initialized in default constructor to \"January 1, 2016\"
vector < ItemToPurchase > cartItems
Public member functions
GetCustomerName() accessor (1 pt)
GetDate() accessor (1 pt)
AddItem()
Adds an item to cartItems vector. Has parameter ItemToPurchase. Does not return anything.
RemoveItem()
Removes item from cartItems vector. Has a string (an item\'s name) parameter. Does not return
anything.
If item name cannot be found, output this message: Item not found in cart. Nothing removed.
ModifyItem()
Modifies an item\'s description, price, and/or quantity. Has parameter ItemToPurchase. Does not
return anything.
If item can be found (by name) in cart, check if parameter has default values for description,
price, and quantity. If not, modify item in cart.
If item cannot be found (by name) in cart, output this message: Item not found in cart. Nothing
modified.
GetNumItemsInCart() (2 pts)
Returns quantity of all items .
In sliding window protocol the left wall of the sender sliding winod.pdf
In sliding window protocol the left wall of the sender sliding winodow movws to the _____
when it ___ a data.
A.) right; receives
B.) right; sends
C.) left; receives
D.) left; sends
Solution
ans is A
In sliding window protocol the left wall of the sender sliding winodow movws to the __right___
when it _receives__ a data.
In mice, the black allele (B) is dominant to the recessive white all.pdf
In mice, the black allele (B) is dominant to the recessive white allele (b). Two black mice of
unknown genotype are mated to each other, resulting in 6 black and 1 white . What is the
genotype of the mother?
Solution
Answer: genotype of the mother = Bb
Explanation:
The only possible genotype for parents are
P1: Bb (Black Mouse) X Bb (Black Mouse)
F1: BB (Black), Bb(Black), Bb(black), bb(Black).
How will the rate of diffusion of an interstitial i Impurity atom Inc.pdf
How will the rate of diffusion of an interstitial i Impurity atom Increases? CIRCLE THE BEST
ANSWER Increase Decrease The rate of diffusion will be unaffected by changes In the size of
the impurity species. impurity species change as the size of the impurity species.
Solution
The rate of diffusion will decrease as the size of the impurity atoms increases because greater the
size of impurity atoms greater will be the difficulty in accomodating the impurity atoms at
interstitial sites and also larger size will decrease its mobility and provide hindrance during its
movement from one site to another. all these factors contribute in decrease in rate of diffusion..
Let R be an integral domain. Prove 1R and -1R are the only units of .pdf
Let R be an integral domain. Prove 1R and -1R are the only units of R that are equal to their own
multiplicative inverses. Tip: Consider the equation x2 - 1R = 0R.
Solution
If x is its own inverse then
x^2-1 =0
(x-1)(x+1)=0
But, x is in R which is a domain
HEnce,
x-1=0 or x+1=0 as there are no zero divisors in R an integral domain
So, x=1 or -1.
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