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        AN

        EXCELLENT
        BORING
        PRESENTATION
        FOR 2 REASONS.
AN

EXCELLENT
BORING
PRESENTATION
FOR 2 REASONS. I GUESS SO.
BORING
                BECAUSE
#1




         too many equations. text. garbage.
EXCELLENT
            BECAUSE


               storytelling.
BORING
                 BECAUSE
#2




         random blah blah. bad storytelling.
GET READY




            to be bored.
ISHTIAQUE ZICO / BANGLADESH
RIGHT!
THAT’S
MY NAME


          ISHTIAQUE ZICO / BANGLADESH
AND
MY
COUNTRY


          ISHTIAQUE ZICO / BANGLADESH
MY BIO
INDEPENDENT
FILMMAKER


              WRITER. ALSO.
I LOVE IDEAS,
EXPERIMENT &
LIMITATION


                twitter.com/iazico
& ENJOY
WORKING WITH
RUPANTOR


               MICROCINEMA TEAM
BUT ONCE
I STUDIED
MATHEMATICS


              UNDERGRAD. BORING.
I HAD TO MAKE
PRESENTATION WITH
MATHEMATICS


                    THAT’S WHY BORING
AND THIS
PRESENTATION DEALS
SCATTERING THEORY


                     ALSO SCARING
SO LET’S EXPLORE
INVERSE SCATTERING &
SCATTERING BLAH BLAH


                       YOU ARE WARNED.
& WHAT IS SCATTERING




          deflection of subatomic particles
& WHAT IS




            subatomic particles
GOOGLE. PLEASE.




                            [search]
                  subatomic particles
ALWAYS.




          I would do the same thing.
SCATTERING. EXAMPLE.
Wave scattering
Sunlight scattered by rain drops
SCATTERING. EXAMPLE.




                  Particle scattering
          The motion of billiard balls
SCATTERING. EXAMPLE.




                  Particle scattering
          The motion of billiard balls
SCATTERING. EXAMPLE.




                  Particle scattering
          The motion of billiard balls
TIPS #1


      To make your
presentation boring,
 never insert photo.

                       like me.
TIPS #1


      To make your
presentation boring,
 never insert photo.

                       use clipart.
Direct Scattering Problem

           Scatterer




           Spectrum
AND TIPS #2


   use




          symbol. jargon. whenever you can.
Direct Scattering Problem
Sturm-Liouville equation
CONSIDER :


  xx  (  u ( x))  0
        Eigenvalue   Potential   Eigenfunction
                      (t=0)



  INPUT : Potential
OUTPUT : Spectrum
Direct Scattering Problem
Ha Ha Ha…
CONSIDER :

    SOMETHING WAS HERE

       Eigen blah    Blah   Eigen blah
                    (t=0)



  INPUT : blah
OUTPUT : BLAH
Direct Scattering Problem
Ha Ha Ha…
CONSIDER :

                    blah BLAH

       Eigen blah        Blah   Eigen blah
                        (t=0)



  INPUT : blah
OUTPUT : BLAH
Direct Scattering Problem
Spectrum Types

               spectrum { , }
  discrete               continuous

      = negative          = positive

       = blah blah     = again blah
Direct Scattering Problem
  Graph : When Discrete
                                                      1


                                                    0.8


                                                    0.6


                                                    0.4


                                                    0.2



                     -6    -5   -4   -3   -2   -1




eigenfunction decays exponentially
Direct Scattering Problem
And when continuous


                u

  Transmitted       Reflected
                                Incident



                                           v
HA HA HA…
TIPS #3




            use 1980s style graph!
Direct Scattering Problem
Example | Direc Delta*
u ( x)  U 0 ( x)


          , x  0
  ( x)  
           0, x  0


                       * distribution, not function.
ENOUGH.




          Next.
Inverse Scattering Problem

          Spectrum




           Scatterer
Inverse Scattering Problem
Just the inverse




             BLAH blah
  INPUT : Spectrum
 OUTPUT : Potential
INPUT BECOMES OUTPUT.




                  and vice versa.
BORED?




            not yet?
         you will be.
Inverse Scattering Problem
Our Goal


    xx  (  u )  0
              k   2




   xx  (k  u )  0
              2
Inverse Scattering Problem
Our Boredom
   The solution is assumed to be:
                                    
        ( x; k )  e     ikx
                                   K ( x, z )e dz  ikz
                                    x



                              MAGIC


                    ˆ
                    dK  
     e ikx  u  2       ( K xx  K zz  u ( x) K )e ikz dz  0
                   dx  x
                      
Inverse Scattering Problem
Sorry
   From Cauchy’s theorem we get:
                
                   (  e   ikx
                      ˆ             )e dz  0
                                     ikz
             



                     MAGIC. AGAIN.


                      C    B 
Inverse Scattering Problem
One More
   Input particle energy = variable
   Impact parameter      = constant




                           BORED?


                               
    K ( x, z )  F ( x  z )   K ( x, z ) F ( y  z )dy  0
                              x
Inverse Scattering Problem
Almost Done
             Scattering
 U(x,0)                                S(0)


                                Time
     KdV

           Inverse Scattering
 U(x,t)                                S(t)
IN BRIEF HISTORY OF TIME

STEPHEN HAWKING SAID,
STEPHEN HAWKING SAID,




                             every equation
          helps to lose the readers by half.
SOMETHING LIKE THIS.




                              every equation
           helps to lose the readers by half.
HA HA HA…




            how many equations
              I have used here?
OOPS.




        you there?
HELLO.




         anybody?
SORRY.




         forget everything I said.
THE END




          of boredom.
NOW

BLAME ME OR
        GOOGLE ME OR
rupantor.blogspot.com

 VISIT MY CINEMA TEAM BLOG.
AND

THANK ME
FOR BORING YOU.
ALSO

THANK YOURSELF
FOR YOUR PATIENCE.

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