The document is solving a physics problem where a sack of sand is dropped vertically from a height with an initial velocity of 4m/s. It takes 5.6 seconds to reach the surface. The problem determines the velocity at which it reaches the surface, which is -58.9m/s, and the height from which it was dropped, which is -176.1m. The document shows the relevant equations and calculations to arrive at the solutions for velocity and height.

1. EJERCICIO 10

2. 10.-UN SACO DE ARENA SE LANZA VERTICALMENTE HACIA ABAJO CON
UNA VELOCIDAD INICIAL DE 4M/S Y LLEGA A LA SUPERFICIE DESPUÉS
DE 5.6 SEGUNDOS. DETERMINA LA VELOCIDAD CON QUE LLEGA A LA
SUPERFICIE Y LA ALTURA A LA QUE ESTA EL GLOBO.
Datos
Vo=-4m/s
V=?
a= -9.8 m/s²
T=5.6s
Y=?
Ecuaciones
Vo=Vo + at
V²=Vot+2ay
Y=Vot+at²/2
V=Vo + at
V=-4+(-9.8)(5.6)
V=-4+(-54.9)
V=-4-54.9
V=-58.9m/s Y=VoT+aT²/2
Y=-4(5.6)+(-9.8)(5.6)²/2
Y=-22.4+(-307.3)/2
Y=-22.4+(-153.6)
Y=-22.4-153.6
Y=-176.1m