Load Combinations
Example(1):
Find the maximum vertical reactions for the frame
supporting the shown loads
Using ASD Method & LRFD Method for load
combination
Dead Load including self-weight of structure (DL=5
KN/m’)
Live Load of occupancy (LL=5 KN/m’)
Wind Load (W=5 KN/m’)
Earthquake (E=20 KN)
Combinations Solution
L=5m
H=5m
E=20kN
DL=5kN/m’
LL=5kN/m’
W=5kN/m’
Eng. Mohamed Ismail Kotb
LOAD COMBINATIONS DL= 5 kN/m'
Structure Data LL= 5 kN/m'
Height H= 5 m E= 20 kN
Span L= 5 m
Laoding Data
DL= 5 KN/m'
LL= 5 KN/m'
m
W= 5 KN/m'
5
5
E= 20 KN
w=
H=
Left Support Right Support Left Support Right Support
DL+LL 25 25 1.4DL 17.5 17.5 L= 5 m
D+L+W 12.5 37.5 1.2DL+1.6LL 35 35
D + (∝𝐿)/1.2+𝐸/1.4 0.82 29.4 1..2DL+1.3W+0.5LL 5 37.5
0.9DL 11.25 11.25 1.2D+E+0.5L 1.25 41.25
0.9DL+W ‐1.25 23.75 0.9DL+1.3W ‐5 27.5
0.9DL +𝐸/1.4 ‐3 25.5 0.9DL+E ‐8.75 31.25
ASD Method LRFD Method
kN/m
Eng. Mohamed Ismail Kotb

ECP-201_ Ch.2 Load combinations (ASD & LRFD )_Lecture 2B_Example.pdf

  • 1.
    Load Combinations Example(1): Find themaximum vertical reactions for the frame supporting the shown loads Using ASD Method & LRFD Method for load combination Dead Load including self-weight of structure (DL=5 KN/m’) Live Load of occupancy (LL=5 KN/m’) Wind Load (W=5 KN/m’) Earthquake (E=20 KN) Combinations Solution L=5m H=5m E=20kN DL=5kN/m’ LL=5kN/m’ W=5kN/m’ Eng. Mohamed Ismail Kotb
  • 2.
    LOAD COMBINATIONS DL= 5kN/m' Structure Data LL= 5 kN/m' Height H= 5 m E= 20 kN Span L= 5 m Laoding Data DL= 5 KN/m' LL= 5 KN/m' m W= 5 KN/m' 5 5 E= 20 KN w= H= Left Support Right Support Left Support Right Support DL+LL 25 25 1.4DL 17.5 17.5 L= 5 m D+L+W 12.5 37.5 1.2DL+1.6LL 35 35 D + (∝𝐿)/1.2+𝐸/1.4 0.82 29.4 1..2DL+1.3W+0.5LL 5 37.5 0.9DL 11.25 11.25 1.2D+E+0.5L 1.25 41.25 0.9DL+W ‐1.25 23.75 0.9DL+1.3W ‐5 27.5 0.9DL +𝐸/1.4 ‐3 25.5 0.9DL+E ‐8.75 31.25 ASD Method LRFD Method kN/m Eng. Mohamed Ismail Kotb