Muhammed Fuad Rashid Petroleum Engineering Department at Koya University Fluid Mechanics Laboratory 2020

1. Title Page No.
Aim of experiment 2
introduction 2
Procedure 3
Discussion 5
Table of reading 6

2. Aim of the Experiment: -
Calibrating the Bourdon gauge & it is a device used for balancing a fluid pressure with a
known weight. Typically, it is used for static calibration of pressure gages.
Introduction: -
*Weight pressure Gauge is used for checking and adjusting pressure gauges. The pressure
is applied via weights which are placed on a weight support. The latter has a piston which
acts on hydraulic oil in a pipe system, so that a pressure gauge which is also connected to
the system should indicate certain pressures.
*The device contains a Bourdon gauge with a transparent dial. The display mechanism and
the various adjustment opportunities are therefore clearly identifiable.
*water is used to transfer pressure.
The Description Unit
The device for calibrating pressure gauges
essentially consists of two units:
1. The pressure gauge unit
This is where the pressure gauge to be calibrated is
screwed in. For experimental purposes, the unit
comes supplied with a Bourdon gauge already
screwed in.
2. The load unit
The load unit consists of several weights and a
cylinder with a piston. An increase in the load results
in an increase in pressure. The load unit is
connected to the pressure gauge unit via an oil-filled
line,
1-Base Plate 4-Weights
2-Bourdon gauge 5-overflow
3-Weight support 6-Drain plug

3. Procedure of the Experiment:-
- Open the overflow valve
- Remove the transport-cap
- If necessary topping up the hydraulic oil
- Inserting the piston
-To check the zero point of Bourdon gauge, proceed
as follows:
* Press the piston out of the cylinder
using the hand wheel.
* Remove the piston and weight support.
*Adjust the oil level in the open cylinder until the
cylinder is filled up to the edge.
Calculating: -
We have to find Force to determine actual pressure by using its
mass and gravity:
A=315*10-6
m2
g=9.81m/s2
No.1: m1=2.5kg
F1=mg
F1=2.5*9.81
F1=0.245KN
Pact.=
𝑭
𝑨
Pact.=
𝟎.𝟐𝟒𝟓
𝟑𝟏𝟓∗𝟏𝟎−𝟔
Pact.=77.857KN/m2
No.2: m2=3.5kg

4. F2=mg
F2=3.5*9.81
F2=0.343KN
Pact.=
𝑭
𝑨
Pact.=
𝟎.𝟑𝟒𝟑
𝟑𝟏𝟓∗𝟏𝟎−𝟔
Pact.=108.999KN/m2
No.3: m3=4.2kg
F3=mg
F3=4.2*9.81
F3=0.412KN
Pact.=
𝑭
𝑨
Pact.=
𝟎.𝟒𝟏𝟐
𝟑𝟏𝟓∗𝟏𝟎−𝟔
Pact.=130.8KN/m2
Table of calculating:-
No. Pm
(KN/m2
)
Pact.
(KN/m2
)
1 76 77.857
2 104 108.999
3 126 130.8

5. Discussion:
1-A Calibration curve is a general method for determining the
concentrationof a substance in an unknown sample by
comparing the unknown to a set of standard samples of known
concentration. A calibration curve is one approach to the
problemof instrument calibration; otherapproachesmay mix
the standard into the unknown.
2-
3.
F= mg
Pact =
𝒎𝒈
𝑨
Pact =m
𝒈
𝑨
Pact =m
𝟗.𝟖𝟏
𝟑𝟏𝟓∗𝟏𝟎−𝟔
Pact=m*31142 N/m2
Pact =m*31.14 KN/m2
77.857
108.999
130.8
75
79
83
87
91
95
99
103
107
111
115
119
123
127
131
74 77 80 83 86 89 92 95 98 101 104 107 110 113 116 119 122 125 128
Pm
Pact
Pact =
𝑭
𝑨