D. 192.168.1.0 0.0.0.63The IP address and wildcard mask to identif.pdf
•
0 likes•2 views
D. 192.168.1.0 0.0.0.63 The IP address and wildcard mask to identify the hosts in 192.168.1.0/26 would be 192.168.1.0 0.0.0.63 Solution D. 192.168.1.0 0.0.0.63 The IP address and wildcard mask to identify the hosts in 192.168.1.0/26 would be 192.168.1.0 0.0.0.63.
Report
Share
Report
Share
Download to read offline
Recommended
When two data sets are pooled together the pooled mean will alway.pdf
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e)
Solution
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e).
DELTOID flexes and medially rotates arm; prime mover of arm abduct.pdf
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm.
Solution
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm..
Event Cash Flow Assets Claims Income Statement OAIAFA Cash.pdf
Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock +
Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock +
Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000
+ - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 =
70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA
(3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - =
17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + +
1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - =
+ + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 =
70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000
Solution
Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock +
Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock +
Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000
+ - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 =
70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA
(3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - =
17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + +
1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - =
+ + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 =
70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000.
We know that Molarity = No . of moles Volume of.pdf
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol
Solution
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol.
there are no molecules given..pls repost and post.pdf
there are no molecules given..pls repost and post on my profile
Solution
there are no molecules given..pls repost and post on my profile.
The false statement is Oxygen forms binary compou.pdf
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides.
Solution
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides..
the concentration is 0.1550 .pdf
The document states that the concentration is 0.1550. It then repeats that the concentration is 0.1550. The key information is that the concentration is 0.1550.
The area is how many Hydrogens are on the graph. .pdf
The area is how many Hydrogens are on the graph. You would need a correlation
table to determine what groups are on the figure. First, calculate the degrees of saturation. (18-
10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene
Solution
The area is how many Hydrogens are on the graph. You would need a correlation
table to determine what groups are on the figure. First, calculate the degrees of saturation. (18-
10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene.
Recommended
When two data sets are pooled together the pooled mean will alway.pdf
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e)
Solution
When two data sets are pooled together the pooled mean will always be more accurate, between
original mean values and more precise.
Ans: (e).
DELTOID flexes and medially rotates arm; prime mover of arm abduct.pdf
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm.
Solution
DELTOID : flexes and medially rotates arm; prime mover of arm abduction; extends and
laterally rotates arm. LATISSIMUS DORI : prime mover of arm extension; adducts and medially
rotates arm (big muscle). PECTORALIS MAJOR : prime mover of arm flexion, adducts and
medially rotates arm ( big muscle). TERES MAJOR : Extends, adducts and medially rotates arm..
Event Cash Flow Assets Claims Income Statement OAIAFA Cash.pdf
Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock +
Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock +
Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000
+ - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 =
70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA
(3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - =
17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + +
1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - =
+ + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 =
70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000
Solution
Event Cash Flow Assets Claims Income Statement OA/IA/FA Cash + Supplies stock +
Fixed asset = Note payable + Bank loan short term + Accounts payable + Common Stock +
Retained Earnings Revenue - Expense = Net Income a FA 75,000 + + = + + + 75,000
+ - = b OA (5,000) + 5,000 + = + + + + - = c IA (10,000) + + 80,000 =
70,000 + + + + - = d OA 27,000 + + = + 27,000 + + + - = e FA
(3,500) + + = + + + + (3,500) - = f OA 17,000 + + = + + + + 17,000 - =
17,000 g OA (4,000) + + = + + + + - 4,000 = (4,000) h OA + 1,000 + = + +
1,000 + + - = + + = + + + + - = + + = + + + + - = + + = + + + + - =
+ + = + + + + - = + + = + + + + - = 96,500 + 6,000 + 80,000 =
70,000 + 27,000 + 1,000 + 75,000 + (3,500) 17,000 - 4,000 = 13,000.
We know that Molarity = No . of moles Volume of.pdf
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol
Solution
We know that Molarity = No . of moles / Volume of solution in L 0.5 M = n / 1.0 L
---> n = 0.5 mol Li2SO4 ---> 2Li+ + SO4 2- So 1 mole of Li2SO4 produces 1 mole of SO4 2- &
2 moles of Li+ So No . of moles of SO4 2- ions present in 0.5 mol of Li2SO4 is 1 * 0.5 = 0.5
mol.
there are no molecules given..pls repost and post.pdf
there are no molecules given..pls repost and post on my profile
Solution
there are no molecules given..pls repost and post on my profile.
The false statement is Oxygen forms binary compou.pdf
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides.
Solution
The false statement is Oxygen forms binary compounds with nonmetals called acid
anhydrides..
the concentration is 0.1550 .pdf
The document states that the concentration is 0.1550. It then repeats that the concentration is 0.1550. The key information is that the concentration is 0.1550.
The area is how many Hydrogens are on the graph. .pdf
The area is how many Hydrogens are on the graph. You would need a correlation
table to determine what groups are on the figure. First, calculate the degrees of saturation. (18-
10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene
Solution
The area is how many Hydrogens are on the graph. You would need a correlation
table to determine what groups are on the figure. First, calculate the degrees of saturation. (18-
10)/2 = 4 degrees this could be a ring wth 3 pi bonds maybe benxene.
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l)
Solution
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l).
oxygen double bond oxygen .pdf
This very short document appears to be discussing chemical bonds, mentioning oxygen and a double bond. It provides a solution related to the chemical structure of oxygen double bonded to oxygen but does not give any further details. The document is too brief to extract much meaningful information in a summary.
Once HCl is added in solution, the ions would dis.pdf
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:
Solution
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:.
its e1 OMe attacks at 3-position by transfer of a.pdf
its e1 OMe attacks at 3-position by transfer of anion to stable form
Solution
its e1 OMe attacks at 3-position by transfer of anion to stable form.
H and F are identical, you just need to rotate H .pdf
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other.
Solution
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other..
From weakest to strongest A, B, C Butanal is an .pdf
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms.
Solution
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms..
Effusion is inversely proportional to the mass. .pdf
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide
Solution
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide.
Benzoin and methanol both have an alcohol group, .pdf
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group).
Solution
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group)..
When acid and base react together they form salt and water.This reac.pdf
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions.
Solution
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions..
There are 37 classes in java.lang package as per Java SE7 The java.pdf
There are 37 classes in java.lang package as per Java SE7
The java.lang package contains classes that are fundamental to the design of the Java language.
1) Object, Class, ClassLoader, System and Compiler classes
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
3) Math, StrictMath classes
4) String, StringBuffer and StringBuilder classes
5) Process, ProcessBuilder, Runtime, RuntimePermission classes
6) Enum>, Throwable, Void classes
----------------------------------------------
1) Object, Class, ClassLoader, System and Compiler classes
----------------------------------------------
Object: The Object class is the root of the class hierarchy. Every class has Object as a
superclass. All objects, including arrays, implement the methods of this class.
Class: The Class class instance represent classes and interfaces in a running Java application.It
has no public constructor.
ClassLoader: The ClassLoader class is an object that is responsible for loading classes. This class
is an abstract class. It may be used by security managers to indicate security domains.
System: The System class contains several useful class fields and methods. It cannot be
instantiated.
Some of the facilities provided by System class are standard input, output, error output streams
and access to externally defined properties and environment variables. This class has a utility
method for quickly copying a portion of an array. Also it has methods for loading files and
libraries
Compiler: The Compiler class is provided to support Java-to-native-code compilers and related
services. By design, it serves as a placeholder for a JIT compiler implementation.
SecurityManager: The SecurityManager class allows applications to implement a security policy.
It allows an application to determine, before performing a possibly unsafe or sensitive operation,
what the operation is and whether it is being attempted in a security context that allows the
operation to be performed. The application can allow or disallow the operation.
----------------------------------------------
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
----------------------------------------------
Frequently it is necessary to represent a value of primitive type as if it were an object. The
wrapper classes serve this purpose.
An object of type Double, for example, contains a field whose type is double, representing that
value in such a way that a reference to it can be stored in a variable of reference type. These
classes also provide a number of methods for converting among primitive values, as well as
supporting such standard methods as equals and hashCode.
Other classes in support to wrapper classes:
----------------------------------------------
Number: The Number class is the superclass of classes BigDecimal, BigInteger, Byte, Double,
Float, Integer, Long, and Short.The Subclasses of Number must provide methods to convert the
represented num.
The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf
The solution provides code for an employee payroll program. It includes classes for Employee, Company, and EmployeeDemo (the main class). EmployeeDemo gets input for multiple employees and uses the Employee class to calculate payroll values like taxes, wages, deductions. It then passes the data to the Company class which collects overall payroll statistics.
The precations to be given to the workers areSolutionThe prec.pdf
The precations to be given to the workers are:
Solution
The precations to be given to the workers are:.
At 1700 cm-1 a strong signal in an IR spectum is .pdf
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated).
Solution
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated)..
Resultbest_fit_for_X1 =DistName tlocationscaleNLogL 2.1.pdf
Result:
best_fit_for_X1 =
DistName: \'tlocationscale\'
NLogL: 2.1206e+03
BIC: 4.2620e+03
AIC: 4.2472e+03
AICc: 4.2473e+03
ParamNames: {\'mu\' \'sigma\' \'nu\'}
ParamDescription: {\'location\' \'scale\' \'degrees of freedom\'}
Params: [1.0071 1.9637 37.4643]
Paramci: [2x3 double]
ParamCov: [3x3 double]
Support: [1x1 struct]
best_fit_for_X2 =
DistName: \'generalized extreme value\'
NLogL: 2.4968e+03
BIC: 5.0142e+03
AIC: 4.9995e+03
AICc: 4.9995e+03
ParamNames: {\'k\' \'sigma\' \'mu\'}
ParamDescription: {\'shape\' \'scale\' \'location\'}
Params: [-0.2802 2.9571 1.0858]
Paramci: [2x3 double]
ParamCov: [3x3 double]
Support: [1x1 struct]
correlation_between_X1_X2 = 0.0084 (hence X1 and X2 are independent)
meanY = 3.1394
varY = 12.8269
meanZ = 4.1492
varZ = 25.1576
correlation_between_Y_Z = 0.9438 (Hence Y and Z are dependent)
Code:
function main
load X.mat
[D PD]=allfitdist(X1,\'NLogL\');
[D2 PD2]=allfitdist(X2,\'NLogL\');
%best fit using maximum likelihood
best_fit_for_X1=D(1)
best_fit_for_X2=D2(1)
correlation_between_X1_X2=correlation(X1,X2)
Y=X1+X2;
Z=2*X1+X2;
meanY=mean(Y)
varY=var(Y)
meanZ=mean(Z)
varZ=var(Z)
correlation_between_Y_Z=correlation(Y,Z)
end
function[r]=correlation(x,y)
avx = mean(x); ex2 = sum((x - avx).^2); %Wasteful multiple passes are a pain,
avy = mean(y); ey2 = sum((y - avy).^2); %But explicit loops
exy = sum((x - avx).*(y - avy)); %Are interpreted slowly.
r = exy/sqrt(ex2*ey2); %Division by N cancels; ignoring the N - 1 ritual.
end
function [D PD] = allfitdist(data,sortby,varargin)
%ALLFITDIST Fit all valid parametric probability distributions to data.
% [D PD] = ALLFITDIST(DATA) fits all valid parametric probability
% distributions to the data in vector DATA, and returns a struct D of
% fitted distributions and parameters and a struct of objects PD
% representing the fitted distributions. PD is an object in a class
% derived from the ProbDist class.
%
% [...] = ALLFITDIST(DATA,SORTBY) returns the struct of valid distributions
% sorted by the parameter SORTBY
% NLogL - Negative of the log likelihood
% BIC - Bayesian information criterion (default)
% AIC - Akaike information criterion
% AICc - AIC with a correction for finite sample sizes
%
% [...] = ALLFITDIST(...,\'DISCRETE\') specifies it is a discrete
% distribution and does not attempt to fit a continuous distribution
% to the data
%
% [...] = ALLFITDIST(...,\'PDF\') or (...,\'CDF\') plots either the PDF or CDF
% of a subset of the fitted distribution. The distributions are plotted in
% order of fit, according to SORTBY.
%
% List of distributions it will try to fit
% Continuous (default)
% Beta
% Birnbaum-Saunders
% Exponential
% Extreme value
% Gamma
% Generalized extreme value
% Generalized Pareto
% Inverse Gaussian
% Logistic
% Log-logistic
% Lognormal
% Nakagami
% Normal
% Rayleigh
% Rician
% t location-scale
% Weibull
%
% Discrete (\'DISCRETE\')
% Binomial
% Negative binomial
% Poisson
%
% Optional inputs:
% [...] = ALLFITDIST(...,\'n\',N,...)
% For the \'binomial\' .
Please rate the solution give thumbs if this is helpful.Impact of .pdf
Please rate the solution give thumbs if this is helpful.
Impact of data quality on business performance:
Functions of the database technology:
Differences between centralized and distributed database architecture:
The role of a master reference file:
Solution
Please rate the solution give thumbs if this is helpful.
Impact of data quality on business performance:
Functions of the database technology:
Differences between centralized and distributed database architecture:
The role of a master reference file:.
Please find the answers and explanations belowPart 1 (TrueFalse).pdf
Please find the answers and explanations below:
Part 1 (True/False)
1. Replication and transcription proceed in 5\' to 3\' direction: TRUE (Both DNA replication and
transcription of mRNA proceed in 5\' to 3\' direcition. This is because the firstly, the DNA
polymerase retains only 5\' to 3\' directionality and thus, replication begins only in this direction.
.Secondarily, there must be sequence similarity between the DNA and the RNA transcribed from
it thus the orientation of transcription is necessarily 5\' to 3\' in nature)
2. All cells have telomerase activity : FALSE (Telomerase or terminal transferase is an enzyme
which is required for maintenance of terminal positions of chromosomes by self-replication and
prevents shortening of chromosomes. It also prevents sticking of chromosomes together and thus
clumping of chromosomes. Telomerase acitivty is absent in majority of somatic cells in the
body.)
3. Only mRNA is transcribed: TRUE (Only the mRNA which carries the necessary information
for translation is transcribed from the DNA template. The tRNA is utilized to transfer the
transcribed information and rRNA is utilized to generate the polypeptide on the ribosomal
surface during translation)
4. Promoter regions are upstream from the gene: TRUE (A gene promoter is the region of DNA
located upstream the gene to be transcribed and carries the consensus sequence which could be
recognized by RNA polymerase for its binding and carrying on transcription)
5. A single tRNA can carry several different amino acids: FALSE (The tRNA is specific for only
one kind of amino acid which it could carry. It is a highly stringent and specific nature of this
biomolecule which determines the specificness for the amino acid which will be synthesized
from the codon)
Part 2
Please find the definitions below:
1. Semi-conservative replication: The mode of replication of double stranded DNA in which a
daughter DNA molecules carries a strand from parent DNA and the complementary strand is
synthesized de novo is called semi-conservative replication.
2. Okazaki fragments: Okazaki fragments are short stretches of DNA synthesized
discountinuously on the lagging strand on the open frame of the parent DNA. These stretches of
DNA are finally conjoined together to form a continous strand of newly synthesized DNA.
3. Consensus sequence: Consensus sequences are those genetically conserved sequences of DNA
which remain similar (upto 99%) within organisms of same or different species and are actively
engaged in crucial functions such as promoter region binding, transcription sites for transcription
factors, enzymatic genes etc. Any change or deterioration in these consesus sequence might be
highly deletrious for the cells.
4. Codon: A codon can be defined as a triplet set of nucleotides which come in a specific order
and encode for a specific type of amino acid upon translation. For example, the codon AAA
encodes for amino acid lysine. Exceptionally, codons UAA, UAG and UGA do not .
Ionic product of water Kw = [H+][OH-] = 10-14[OH-] = 10-142.7 x 1.pdf
Ionic product of water Kw = [H+][OH-] = 10-14
[OH-] = 10-14/2.7 x 10-6 = 3.7 x 10-9 M
Solution
Ionic product of water Kw = [H+][OH-] = 10-14
[OH-] = 10-14/2.7 x 10-6 = 3.7 x 10-9 M.
Instruction set architecture of a machine fill the semantic gap betw.pdf
Instruction set architecture of a machine fill the semantic gap between the user
And the machines. And serve as the early point for the design of a new machine or
Modification of existing ones.
ISA design must describe how memory addresses are interpret and specified in the
Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique
address. There are two different conventions for ordering bytes within a word
one is Little Endian and the other Big Endian
Example:
Big Endian Little Endian
Address value Address value
1000 90 1000 CD
1001 AB 1001 12
1002 12 1002 AB
1003 CD 1003 90
Physical register file is an array of computer registers in a CPU more difficult CPUs use register
so that the mapping of which physical entry supplies a particular architectural register change
dynamically throughout execution
Example:
Physical register Id LastUseItag
--- ---
(p-1) 145
Solution
Instruction set architecture of a machine fill the semantic gap between the user
And the machines. And serve as the early point for the design of a new machine or
Modification of existing ones.
ISA design must describe how memory addresses are interpret and specified in the
Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique
address. There are two different conventions for ordering bytes within a word
one is Little Endian and the other Big Endian
Example:
Big Endian Little Endian
Address value Address value
1000 90 1000 CD
1001 AB 1001 12
1002 12 1002 AB
1003 CD 1003 90
Physical register file is an array of computer registers in a CPU more difficult CPUs use register
so that the mapping of which physical entry supplies a particular architectural register change
dynamically throughout execution
Example:
Physical register Id LastUseItag
--- ---
(p-1) 145.
all real numbers .pdf
This very short document discusses real numbers but provides no details. It mentions all real numbers twice but does not explain or elaborate on this topic. The document also references a solution but provides no problem or further explanation.
In the given text the following phrases reflect scientific approach .pdf
In the given text the following phrases reflect scientific approach of studying Homo floresiensis.
Comparing height with the modern humans: would stand waist high. Studying the features of
skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size
of a chimpanzee’s. All these reflect a scientific approach where the species is compared with
modern humans and conclusions drawn from the observations.
Sometimes science cannot answer all questions like the existence of supernatural powers and
beings. Moreover evolution denies the role of God in the universe. One theory beyond science is
that life on earth is created by gods. Science does not explain the existence of gods or if super
natural entities intervene in human affairs. This explanation is beyond the nature and so beyond
the scope of what can be studied by science. This theory of origin of human beings is a belief.
Science is an activity that seeks to explore the natural world using well-established, clearly-
delineated methods. Scientific method is based on the fact of asking a question, formulating a
hypothesis, performing experiments, collecting data and drawing conclusions. Studying human
evolution in a scientific way enables in better understanding of our origin and evolution.
Understanding the process by which Homo sapiens came into existence is crucial for
understanding the kind of creature we are and this is possible by studying scientifically.
Solution
In the given text the following phrases reflect scientific approach of studying Homo floresiensis.
Comparing height with the modern humans: would stand waist high. Studying the features of
skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size
of a chimpanzee’s. All these reflect a scientific approach where the species is compared with
modern humans and conclusions drawn from the observations.
Sometimes science cannot answer all questions like the existence of supernatural powers and
beings. Moreover evolution denies the role of God in the universe. One theory beyond science is
that life on earth is created by gods. Science does not explain the existence of gods or if super
natural entities intervene in human affairs. This explanation is beyond the nature and so beyond
the scope of what can be studied by science. This theory of origin of human beings is a belief.
Science is an activity that seeks to explore the natural world using well-established, clearly-
delineated methods. Scientific method is based on the fact of asking a question, formulating a
hypothesis, performing experiments, collecting data and drawing conclusions. Studying human
evolution in a scientific way enables in better understanding of our origin and evolution.
Understanding the process by which Homo sapiens came into existence is crucial for
understanding the kind of creature we are and this is possible by studying scientifically..
clinical examination of hip joint (1).pdf
described clinical examination all orthopeadic conditions .
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
This Dissertation explores the particular circumstances of Mirzapur, a region located in the
core of India. Mirzapur, with its varied terrains and abundant biodiversity, offers an optimal
environment for investigating the changes in vegetation cover dynamics. Our study utilizes
advanced technologies such as GIS (Geographic Information Systems) and Remote sensing to
analyze the transformations that have taken place over the course of a decade.
The complex relationship between human activities and the environment has been the focus
of extensive research and worry. As the global community grapples with swift urbanization,
population expansion, and economic progress, the effects on natural ecosystems are becoming
more evident. A crucial element of this impact is the alteration of vegetation cover, which plays a
significant role in maintaining the ecological equilibrium of our planet.Land serves as the foundation for all human activities and provides the necessary materials for
these activities. As the most crucial natural resource, its utilization by humans results in different
'Land uses,' which are determined by both human activities and the physical characteristics of the
land.
The utilization of land is impacted by human needs and environmental factors. In countries
like India, rapid population growth and the emphasis on extensive resource exploitation can lead
to significant land degradation, adversely affecting the region's land cover.
Therefore, human intervention has significantly influenced land use patterns over many
centuries, evolving its structure over time and space. In the present era, these changes have
accelerated due to factors such as agriculture and urbanization. Information regarding land use and
cover is essential for various planning and management tasks related to the Earth's surface,
providing crucial environmental data for scientific, resource management, policy purposes, and
diverse human activities.
Accurate understanding of land use and cover is imperative for the development planning
of any area. Consequently, a wide range of professionals, including earth system scientists, land
and water managers, and urban planners, are interested in obtaining data on land use and cover
changes, conversion trends, and other related patterns. The spatial dimensions of land use and
cover support policymakers and scientists in making well-informed decisions, as alterations in
these patterns indicate shifts in economic and social conditions. Monitoring such changes with the
help of Advanced technologies like Remote Sensing and Geographic Information Systems is
crucial for coordinated efforts across different administrative levels. Advanced technologies like
Remote Sensing and Geographic Information Systems
9
Changes in vegetation cover refer to variations in the distribution, composition, and overall
structure of plant communities across different temporal and spatial scales. These changes can
occur natural.
More Related Content
More from aparnatiwari291
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l)
Solution
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)============> H2SO3(aq) + Sn{4+}
(aq)+ H2O(l).
oxygen double bond oxygen .pdf
This very short document appears to be discussing chemical bonds, mentioning oxygen and a double bond. It provides a solution related to the chemical structure of oxygen double bonded to oxygen but does not give any further details. The document is too brief to extract much meaningful information in a summary.
Once HCl is added in solution, the ions would dis.pdf
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:
Solution
Once HCl is added in solution, the ions would dissociate into their component parts
(H+ and Cl-). As per the second equation, adding more H+ would initially increase the quantity
of products, thusly shifting the reaction towards the reactants by LeChatlier\'s Principle. If
NaOH was added, the dissociation would create OH- anions that would soak up H+ cations. By
removing products, the equlibrium is shifted towards the products by LeChatlier\'s Principle.
Best of wishes! (:.
its e1 OMe attacks at 3-position by transfer of a.pdf
its e1 OMe attacks at 3-position by transfer of anion to stable form
Solution
its e1 OMe attacks at 3-position by transfer of anion to stable form.
H and F are identical, you just need to rotate H .pdf
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other.
Solution
H and F are identical, you just need to rotate H until it matches F, I is also identical
to G. H and F are enantiomers of I and G, this also means that they are Chiral (non super
imposable on their mirror image) to each other..
From weakest to strongest A, B, C Butanal is an .pdf
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms.
Solution
From weakest to strongest: A, B, C Butanal is an aldehyde which means it has the
C=O so it cannot hydrogen bond, only dipole-dipole interactions. However, butanol can
hydrogen-bond because of the OH group so it would have the strongest intermolecular force.
Pentane would have weakest because it has no electronegative atoms..
Effusion is inversely proportional to the mass. .pdf
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide
Solution
Effusion is inversely proportional to the mass. Hence, Methane > HF > Propane >
Hydrogen sulfide.
Benzoin and methanol both have an alcohol group, .pdf
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group).
Solution
Benzoin and methanol both have an alcohol group, but benzoin has a ketone group
and phenyl groups within it also. The interesting part about benzoin is that it is a conjugated pi
system, meaning that electrons from the phenyl groups can shift around the double bonds
throughout the whole molecule without effecting anything; this also impacts the ketone group.
This is also known as resonance, you can see an example here
http://alevelchem.com/drop/peptide_angles.gif Because of this effect, the whole rest of the
benzoin moiety (besides the alcohol group) can be considered one giant add-on (Let\'s call it R)
If methanol looks like this... H3C-OH Then our benzoin because of its delocalized resonant
electrons will, in comparison, just look like... R-OH When placed side by side this is how both
molecules will act with each other. Therefore the polarities of both molecules are similar because
electronically both molecules function the same way (Methanol with a CH3, and Benzoin with a
conjugated R group)..
When acid and base react together they form salt and water.This reac.pdf
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions.
Solution
When acid and base react together they form salt and water.This reaction is known as
Neutralization Reaction. ForExample
HCl+NaOH ---------> NaCl + H2O
HCl is acid while NaOH is a base, when they react with eachother they form NaCl, that is a salt
(table salt)
These reactions are also reversible reactions..
There are 37 classes in java.lang package as per Java SE7 The java.pdf
There are 37 classes in java.lang package as per Java SE7
The java.lang package contains classes that are fundamental to the design of the Java language.
1) Object, Class, ClassLoader, System and Compiler classes
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
3) Math, StrictMath classes
4) String, StringBuffer and StringBuilder classes
5) Process, ProcessBuilder, Runtime, RuntimePermission classes
6) Enum>, Throwable, Void classes
----------------------------------------------
1) Object, Class, ClassLoader, System and Compiler classes
----------------------------------------------
Object: The Object class is the root of the class hierarchy. Every class has Object as a
superclass. All objects, including arrays, implement the methods of this class.
Class: The Class class instance represent classes and interfaces in a running Java application.It
has no public constructor.
ClassLoader: The ClassLoader class is an object that is responsible for loading classes. This class
is an abstract class. It may be used by security managers to indicate security domains.
System: The System class contains several useful class fields and methods. It cannot be
instantiated.
Some of the facilities provided by System class are standard input, output, error output streams
and access to externally defined properties and environment variables. This class has a utility
method for quickly copying a portion of an array. Also it has methods for loading files and
libraries
Compiler: The Compiler class is provided to support Java-to-native-code compilers and related
services. By design, it serves as a placeholder for a JIT compiler implementation.
SecurityManager: The SecurityManager class allows applications to implement a security policy.
It allows an application to determine, before performing a possibly unsafe or sensitive operation,
what the operation is and whether it is being attempted in a security context that allows the
operation to be performed. The application can allow or disallow the operation.
----------------------------------------------
2) Wrapper classes:- Boolean, Character, Byte, Short, Integer, Long, Float, and Double
----------------------------------------------
Frequently it is necessary to represent a value of primitive type as if it were an object. The
wrapper classes serve this purpose.
An object of type Double, for example, contains a field whose type is double, representing that
value in such a way that a reference to it can be stored in a variable of reference type. These
classes also provide a number of methods for converting among primitive values, as well as
supporting such standard methods as equals and hashCode.
Other classes in support to wrapper classes:
----------------------------------------------
Number: The Number class is the superclass of classes BigDecimal, BigInteger, Byte, Double,
Float, Integer, Long, and Short.The Subclasses of Number must provide methods to convert the
represented num.
The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf
The solution provides code for an employee payroll program. It includes classes for Employee, Company, and EmployeeDemo (the main class). EmployeeDemo gets input for multiple employees and uses the Employee class to calculate payroll values like taxes, wages, deductions. It then passes the data to the Company class which collects overall payroll statistics.
The precations to be given to the workers areSolutionThe prec.pdf
The precations to be given to the workers are:
Solution
The precations to be given to the workers are:.
At 1700 cm-1 a strong signal in an IR spectum is .pdf
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated).
Solution
At 1700 cm-1 a strong signal in an IR spectum is the result of a ketone (C=O). (It
can shift if the compound is conjugated)..
Resultbest_fit_for_X1 =DistName tlocationscaleNLogL 2.1.pdf
Result:
best_fit_for_X1 =
DistName: \'tlocationscale\'
NLogL: 2.1206e+03
BIC: 4.2620e+03
AIC: 4.2472e+03
AICc: 4.2473e+03
ParamNames: {\'mu\' \'sigma\' \'nu\'}
ParamDescription: {\'location\' \'scale\' \'degrees of freedom\'}
Params: [1.0071 1.9637 37.4643]
Paramci: [2x3 double]
ParamCov: [3x3 double]
Support: [1x1 struct]
best_fit_for_X2 =
DistName: \'generalized extreme value\'
NLogL: 2.4968e+03
BIC: 5.0142e+03
AIC: 4.9995e+03
AICc: 4.9995e+03
ParamNames: {\'k\' \'sigma\' \'mu\'}
ParamDescription: {\'shape\' \'scale\' \'location\'}
Params: [-0.2802 2.9571 1.0858]
Paramci: [2x3 double]
ParamCov: [3x3 double]
Support: [1x1 struct]
correlation_between_X1_X2 = 0.0084 (hence X1 and X2 are independent)
meanY = 3.1394
varY = 12.8269
meanZ = 4.1492
varZ = 25.1576
correlation_between_Y_Z = 0.9438 (Hence Y and Z are dependent)
Code:
function main
load X.mat
[D PD]=allfitdist(X1,\'NLogL\');
[D2 PD2]=allfitdist(X2,\'NLogL\');
%best fit using maximum likelihood
best_fit_for_X1=D(1)
best_fit_for_X2=D2(1)
correlation_between_X1_X2=correlation(X1,X2)
Y=X1+X2;
Z=2*X1+X2;
meanY=mean(Y)
varY=var(Y)
meanZ=mean(Z)
varZ=var(Z)
correlation_between_Y_Z=correlation(Y,Z)
end
function[r]=correlation(x,y)
avx = mean(x); ex2 = sum((x - avx).^2); %Wasteful multiple passes are a pain,
avy = mean(y); ey2 = sum((y - avy).^2); %But explicit loops
exy = sum((x - avx).*(y - avy)); %Are interpreted slowly.
r = exy/sqrt(ex2*ey2); %Division by N cancels; ignoring the N - 1 ritual.
end
function [D PD] = allfitdist(data,sortby,varargin)
%ALLFITDIST Fit all valid parametric probability distributions to data.
% [D PD] = ALLFITDIST(DATA) fits all valid parametric probability
% distributions to the data in vector DATA, and returns a struct D of
% fitted distributions and parameters and a struct of objects PD
% representing the fitted distributions. PD is an object in a class
% derived from the ProbDist class.
%
% [...] = ALLFITDIST(DATA,SORTBY) returns the struct of valid distributions
% sorted by the parameter SORTBY
% NLogL - Negative of the log likelihood
% BIC - Bayesian information criterion (default)
% AIC - Akaike information criterion
% AICc - AIC with a correction for finite sample sizes
%
% [...] = ALLFITDIST(...,\'DISCRETE\') specifies it is a discrete
% distribution and does not attempt to fit a continuous distribution
% to the data
%
% [...] = ALLFITDIST(...,\'PDF\') or (...,\'CDF\') plots either the PDF or CDF
% of a subset of the fitted distribution. The distributions are plotted in
% order of fit, according to SORTBY.
%
% List of distributions it will try to fit
% Continuous (default)
% Beta
% Birnbaum-Saunders
% Exponential
% Extreme value
% Gamma
% Generalized extreme value
% Generalized Pareto
% Inverse Gaussian
% Logistic
% Log-logistic
% Lognormal
% Nakagami
% Normal
% Rayleigh
% Rician
% t location-scale
% Weibull
%
% Discrete (\'DISCRETE\')
% Binomial
% Negative binomial
% Poisson
%
% Optional inputs:
% [...] = ALLFITDIST(...,\'n\',N,...)
% For the \'binomial\' .
Please rate the solution give thumbs if this is helpful.Impact of .pdf
Please rate the solution give thumbs if this is helpful.
Impact of data quality on business performance:
Functions of the database technology:
Differences between centralized and distributed database architecture:
The role of a master reference file:
Solution
Please rate the solution give thumbs if this is helpful.
Impact of data quality on business performance:
Functions of the database technology:
Differences between centralized and distributed database architecture:
The role of a master reference file:.
Please find the answers and explanations belowPart 1 (TrueFalse).pdf
Please find the answers and explanations below:
Part 1 (True/False)
1. Replication and transcription proceed in 5\' to 3\' direction: TRUE (Both DNA replication and
transcription of mRNA proceed in 5\' to 3\' direcition. This is because the firstly, the DNA
polymerase retains only 5\' to 3\' directionality and thus, replication begins only in this direction.
.Secondarily, there must be sequence similarity between the DNA and the RNA transcribed from
it thus the orientation of transcription is necessarily 5\' to 3\' in nature)
2. All cells have telomerase activity : FALSE (Telomerase or terminal transferase is an enzyme
which is required for maintenance of terminal positions of chromosomes by self-replication and
prevents shortening of chromosomes. It also prevents sticking of chromosomes together and thus
clumping of chromosomes. Telomerase acitivty is absent in majority of somatic cells in the
body.)
3. Only mRNA is transcribed: TRUE (Only the mRNA which carries the necessary information
for translation is transcribed from the DNA template. The tRNA is utilized to transfer the
transcribed information and rRNA is utilized to generate the polypeptide on the ribosomal
surface during translation)
4. Promoter regions are upstream from the gene: TRUE (A gene promoter is the region of DNA
located upstream the gene to be transcribed and carries the consensus sequence which could be
recognized by RNA polymerase for its binding and carrying on transcription)
5. A single tRNA can carry several different amino acids: FALSE (The tRNA is specific for only
one kind of amino acid which it could carry. It is a highly stringent and specific nature of this
biomolecule which determines the specificness for the amino acid which will be synthesized
from the codon)
Part 2
Please find the definitions below:
1. Semi-conservative replication: The mode of replication of double stranded DNA in which a
daughter DNA molecules carries a strand from parent DNA and the complementary strand is
synthesized de novo is called semi-conservative replication.
2. Okazaki fragments: Okazaki fragments are short stretches of DNA synthesized
discountinuously on the lagging strand on the open frame of the parent DNA. These stretches of
DNA are finally conjoined together to form a continous strand of newly synthesized DNA.
3. Consensus sequence: Consensus sequences are those genetically conserved sequences of DNA
which remain similar (upto 99%) within organisms of same or different species and are actively
engaged in crucial functions such as promoter region binding, transcription sites for transcription
factors, enzymatic genes etc. Any change or deterioration in these consesus sequence might be
highly deletrious for the cells.
4. Codon: A codon can be defined as a triplet set of nucleotides which come in a specific order
and encode for a specific type of amino acid upon translation. For example, the codon AAA
encodes for amino acid lysine. Exceptionally, codons UAA, UAG and UGA do not .
Ionic product of water Kw = [H+][OH-] = 10-14[OH-] = 10-142.7 x 1.pdf
Ionic product of water Kw = [H+][OH-] = 10-14
[OH-] = 10-14/2.7 x 10-6 = 3.7 x 10-9 M
Solution
Ionic product of water Kw = [H+][OH-] = 10-14
[OH-] = 10-14/2.7 x 10-6 = 3.7 x 10-9 M.
Instruction set architecture of a machine fill the semantic gap betw.pdf
Instruction set architecture of a machine fill the semantic gap between the user
And the machines. And serve as the early point for the design of a new machine or
Modification of existing ones.
ISA design must describe how memory addresses are interpret and specified in the
Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique
address. There are two different conventions for ordering bytes within a word
one is Little Endian and the other Big Endian
Example:
Big Endian Little Endian
Address value Address value
1000 90 1000 CD
1001 AB 1001 12
1002 12 1002 AB
1003 CD 1003 90
Physical register file is an array of computer registers in a CPU more difficult CPUs use register
so that the mapping of which physical entry supplies a particular architectural register change
dynamically throughout execution
Example:
Physical register Id LastUseItag
--- ---
(p-1) 145
Solution
Instruction set architecture of a machine fill the semantic gap between the user
And the machines. And serve as the early point for the design of a new machine or
Modification of existing ones.
ISA design must describe how memory addresses are interpret and specified in the
Instructions. Most machines are byte addressed. That is a 8 bits is the smallest unique
address. There are two different conventions for ordering bytes within a word
one is Little Endian and the other Big Endian
Example:
Big Endian Little Endian
Address value Address value
1000 90 1000 CD
1001 AB 1001 12
1002 12 1002 AB
1003 CD 1003 90
Physical register file is an array of computer registers in a CPU more difficult CPUs use register
so that the mapping of which physical entry supplies a particular architectural register change
dynamically throughout execution
Example:
Physical register Id LastUseItag
--- ---
(p-1) 145.
all real numbers .pdf
This very short document discusses real numbers but provides no details. It mentions all real numbers twice but does not explain or elaborate on this topic. The document also references a solution but provides no problem or further explanation.
In the given text the following phrases reflect scientific approach .pdf
In the given text the following phrases reflect scientific approach of studying Homo floresiensis.
Comparing height with the modern humans: would stand waist high. Studying the features of
skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size
of a chimpanzee’s. All these reflect a scientific approach where the species is compared with
modern humans and conclusions drawn from the observations.
Sometimes science cannot answer all questions like the existence of supernatural powers and
beings. Moreover evolution denies the role of God in the universe. One theory beyond science is
that life on earth is created by gods. Science does not explain the existence of gods or if super
natural entities intervene in human affairs. This explanation is beyond the nature and so beyond
the scope of what can be studied by science. This theory of origin of human beings is a belief.
Science is an activity that seeks to explore the natural world using well-established, clearly-
delineated methods. Scientific method is based on the fact of asking a question, formulating a
hypothesis, performing experiments, collecting data and drawing conclusions. Studying human
evolution in a scientific way enables in better understanding of our origin and evolution.
Understanding the process by which Homo sapiens came into existence is crucial for
understanding the kind of creature we are and this is possible by studying scientifically.
Solution
In the given text the following phrases reflect scientific approach of studying Homo floresiensis.
Comparing height with the modern humans: would stand waist high. Studying the features of
skull: shape and thickness of the bones were human like. Size of the brain: her brain was the size
of a chimpanzee’s. All these reflect a scientific approach where the species is compared with
modern humans and conclusions drawn from the observations.
Sometimes science cannot answer all questions like the existence of supernatural powers and
beings. Moreover evolution denies the role of God in the universe. One theory beyond science is
that life on earth is created by gods. Science does not explain the existence of gods or if super
natural entities intervene in human affairs. This explanation is beyond the nature and so beyond
the scope of what can be studied by science. This theory of origin of human beings is a belief.
Science is an activity that seeks to explore the natural world using well-established, clearly-
delineated methods. Scientific method is based on the fact of asking a question, formulating a
hypothesis, performing experiments, collecting data and drawing conclusions. Studying human
evolution in a scientific way enables in better understanding of our origin and evolution.
Understanding the process by which Homo sapiens came into existence is crucial for
understanding the kind of creature we are and this is possible by studying scientifically..
More from aparnatiwari291 (20)
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf
SO4{2-} (aq) + Sn{2+} (aq) + 4 H{+} (aq)=========.pdf
Once HCl is added in solution, the ions would dis.pdf
Once HCl is added in solution, the ions would dis.pdf
its e1 OMe attacks at 3-position by transfer of a.pdf
its e1 OMe attacks at 3-position by transfer of a.pdf
H and F are identical, you just need to rotate H .pdf
H and F are identical, you just need to rotate H .pdf
From weakest to strongest A, B, C Butanal is an .pdf
From weakest to strongest A, B, C Butanal is an .pdf
Effusion is inversely proportional to the mass. .pdf
Effusion is inversely proportional to the mass. .pdf
Benzoin and methanol both have an alcohol group, .pdf
Benzoin and methanol both have an alcohol group, .pdf
When acid and base react together they form salt and water.This reac.pdf
When acid and base react together they form salt and water.This reac.pdf
There are 37 classes in java.lang package as per Java SE7 The java.pdf
There are 37 classes in java.lang package as per Java SE7 The java.pdf
The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf
The solution is as belowEmployeeDemo.javaimport java.util.Scann.pdf
The precations to be given to the workers areSolutionThe prec.pdf
The precations to be given to the workers areSolutionThe prec.pdf
At 1700 cm-1 a strong signal in an IR spectum is .pdf
At 1700 cm-1 a strong signal in an IR spectum is .pdf
Resultbest_fit_for_X1 =DistName tlocationscaleNLogL 2.1.pdf
Resultbest_fit_for_X1 =DistName tlocationscaleNLogL 2.1.pdf
Please rate the solution give thumbs if this is helpful.Impact of .pdf
Please rate the solution give thumbs if this is helpful.Impact of .pdf
Please find the answers and explanations belowPart 1 (TrueFalse).pdf
Please find the answers and explanations belowPart 1 (TrueFalse).pdf
Ionic product of water Kw = [H+][OH-] = 10-14[OH-] = 10-142.7 x 1.pdf
Ionic product of water Kw = [H+][OH-] = 10-14[OH-] = 10-142.7 x 1.pdf
Instruction set architecture of a machine fill the semantic gap betw.pdf
Instruction set architecture of a machine fill the semantic gap betw.pdf
In the given text the following phrases reflect scientific approach .pdf
In the given text the following phrases reflect scientific approach .pdf
Recently uploaded
clinical examination of hip joint (1).pdf
described clinical examination all orthopeadic conditions .
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
This Dissertation explores the particular circumstances of Mirzapur, a region located in the
core of India. Mirzapur, with its varied terrains and abundant biodiversity, offers an optimal
environment for investigating the changes in vegetation cover dynamics. Our study utilizes
advanced technologies such as GIS (Geographic Information Systems) and Remote sensing to
analyze the transformations that have taken place over the course of a decade.
The complex relationship between human activities and the environment has been the focus
of extensive research and worry. As the global community grapples with swift urbanization,
population expansion, and economic progress, the effects on natural ecosystems are becoming
more evident. A crucial element of this impact is the alteration of vegetation cover, which plays a
significant role in maintaining the ecological equilibrium of our planet.Land serves as the foundation for all human activities and provides the necessary materials for
these activities. As the most crucial natural resource, its utilization by humans results in different
'Land uses,' which are determined by both human activities and the physical characteristics of the
land.
The utilization of land is impacted by human needs and environmental factors. In countries
like India, rapid population growth and the emphasis on extensive resource exploitation can lead
to significant land degradation, adversely affecting the region's land cover.
Therefore, human intervention has significantly influenced land use patterns over many
centuries, evolving its structure over time and space. In the present era, these changes have
accelerated due to factors such as agriculture and urbanization. Information regarding land use and
cover is essential for various planning and management tasks related to the Earth's surface,
providing crucial environmental data for scientific, resource management, policy purposes, and
diverse human activities.
Accurate understanding of land use and cover is imperative for the development planning
of any area. Consequently, a wide range of professionals, including earth system scientists, land
and water managers, and urban planners, are interested in obtaining data on land use and cover
changes, conversion trends, and other related patterns. The spatial dimensions of land use and
cover support policymakers and scientists in making well-informed decisions, as alterations in
these patterns indicate shifts in economic and social conditions. Monitoring such changes with the
help of Advanced technologies like Remote Sensing and Geographic Information Systems is
crucial for coordinated efforts across different administrative levels. Advanced technologies like
Remote Sensing and Geographic Information Systems
9
Changes in vegetation cover refer to variations in the distribution, composition, and overall
structure of plant communities across different temporal and spatial scales. These changes can
occur natural.
Pengantar Penggunaan Flutter - Dart programming language1.pptx
Pengantar Penggunaan Flutter - Dart programming language1.pptx
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
Denis is a dynamic and results-driven Chief Information Officer (CIO) with a distinguished career spanning information systems analysis and technical project management. With a proven track record of spearheading the design and delivery of cutting-edge Information Management solutions, he has consistently elevated business operations, streamlined reporting functions, and maximized process efficiency.
Certified as an ISO/IEC 27001: Information Security Management Systems (ISMS) Lead Implementer, Data Protection Officer, and Cyber Risks Analyst, Denis brings a heightened focus on data security, privacy, and cyber resilience to every endeavor.
His expertise extends across a diverse spectrum of reporting, database, and web development applications, underpinned by an exceptional grasp of data storage and virtualization technologies. His proficiency in application testing, database administration, and data cleansing ensures seamless execution of complex projects.
What sets Denis apart is his comprehensive understanding of Business and Systems Analysis technologies, honed through involvement in all phases of the Software Development Lifecycle (SDLC). From meticulous requirements gathering to precise analysis, innovative design, rigorous development, thorough testing, and successful implementation, he has consistently delivered exceptional results.
Throughout his career, he has taken on multifaceted roles, from leading technical project management teams to owning solutions that drive operational excellence. His conscientious and proactive approach is unwavering, whether he is working independently or collaboratively within a team. His ability to connect with colleagues on a personal level underscores his commitment to fostering a harmonious and productive workplace environment.
Date: May 29, 2024
Tags: Information Security, ISO/IEC 27001, ISO/IEC 42001, Artificial Intelligence, GDPR
-------------------------------------------------------------------------------
Find out more about ISO training and certification services
Training: ISO/IEC 27001 Information Security Management System - EN | PECB
ISO/IEC 42001 Artificial Intelligence Management System - EN | PECB
General Data Protection Regulation (GDPR) - Training Courses - EN | PECB
Webinars: https://pecb.com/webinars
Article: https://pecb.com/article
-------------------------------------------------------------------------------
For more information about PECB:
Website: https://pecb.com/
LinkedIn: https://www.linkedin.com/company/pecb/
Facebook: https://www.facebook.com/PECBInternational/
Slideshare: http://www.slideshare.net/PECBCERTIFICATION
How to deliver Powerpoint Presentations.pptx
"How to make and deliver dynamic presentations by making it more interactive to captivate your audience attention"
Leveraging Generative AI to Drive Nonprofit Innovation
In this webinar, participants learned how to utilize Generative AI to streamline operations and elevate member engagement. Amazon Web Service experts provided a customer specific use cases and dived into low/no-code tools that are quick and easy to deploy through Amazon Web Service (AWS.)
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...Dr. Vinod Kumar Kanvaria
Exploiting Artificial Intelligence for Empowering Researchers and Faculty,
International FDP on Fundamentals of Research in Social Sciences
at Integral University, Lucknow, 06.06.2024
By Dr. Vinod Kumar KanvariaHow to Manage Your Lost Opportunities in Odoo 17 CRM
Odoo 17 CRM allows us to track why we lose sales opportunities with "Lost Reasons." This helps analyze our sales process and identify areas for improvement. Here's how to configure lost reasons in Odoo 17 CRM
Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...
Librarians are leading the way in creating future-ready citizens – now we need to update our spaces to match. In this session, attendees will get inspiration for transforming their library spaces. You’ll learn how to survey students and patrons, create a focus group, and use design thinking to brainstorm ideas for your space. We’ll discuss budget friendly ways to change your space as well as how to find funding. No matter where you’re at, you’ll find ideas for reimagining your space in this session.
How to Build a Module in Odoo 17 Using the Scaffold Method
Odoo provides an option for creating a module by using a single line command. By using this command the user can make a whole structure of a module. It is very easy for a beginner to make a module. There is no need to make each file manually. This slide will show how to create a module using the scaffold method.
Chapter wise All Notes of First year Basic Civil Engineering.pptx
Chapter wise All Notes of First year Basic Civil Engineering
Syllabus
Chapter-1
Introduction to objective, scope and outcome the subject
Chapter 2
Introduction: Scope and Specialization of Civil Engineering, Role of civil Engineer in Society, Impact of infrastructural development on economy of country.
Chapter 3
Surveying: Object Principles & Types of Surveying; Site Plans, Plans & Maps; Scales & Unit of different Measurements.
Linear Measurements: Instruments used. Linear Measurement by Tape, Ranging out Survey Lines and overcoming Obstructions; Measurements on sloping ground; Tape corrections, conventional symbols. Angular Measurements: Instruments used; Introduction to Compass Surveying, Bearings and Longitude & Latitude of a Line, Introduction to total station.
Levelling: Instrument used Object of levelling, Methods of levelling in brief, and Contour maps.
Chapter 4
Buildings: Selection of site for Buildings, Layout of Building Plan, Types of buildings, Plinth area, carpet area, floor space index, Introduction to building byelaws, concept of sun light & ventilation. Components of Buildings & their functions, Basic concept of R.C.C., Introduction to types of foundation
Chapter 5
Transportation: Introduction to Transportation Engineering; Traffic and Road Safety: Types and Characteristics of Various Modes of Transportation; Various Road Traffic Signs, Causes of Accidents and Road Safety Measures.
Chapter 6
Environmental Engineering: Environmental Pollution, Environmental Acts and Regulations, Functional Concepts of Ecology, Basics of Species, Biodiversity, Ecosystem, Hydrological Cycle; Chemical Cycles: Carbon, Nitrogen & Phosphorus; Energy Flow in Ecosystems.
Water Pollution: Water Quality standards, Introduction to Treatment & Disposal of Waste Water. Reuse and Saving of Water, Rain Water Harvesting. Solid Waste Management: Classification of Solid Waste, Collection, Transportation and Disposal of Solid. Recycling of Solid Waste: Energy Recovery, Sanitary Landfill, On-Site Sanitation. Air & Noise Pollution: Primary and Secondary air pollutants, Harmful effects of Air Pollution, Control of Air Pollution. . Noise Pollution Harmful Effects of noise pollution, control of noise pollution, Global warming & Climate Change, Ozone depletion, Greenhouse effect
Text Books:
1. Palancharmy, Basic Civil Engineering, McGraw Hill publishers.
2. Satheesh Gopi, Basic Civil Engineering, Pearson Publishers.
3. Ketki Rangwala Dalal, Essentials of Civil Engineering, Charotar Publishing House.
4. BCP, Surveying volume 1
বাংলাদেশ অর্থনৈতিক সমীক্ষা (Economic Review) ২০২৪ UJS App.pdf
বাংলাদেশের অর্থনৈতিক সমীক্ষা ২০২৪ [Bangladesh Economic Review 2024 Bangla.pdf] কম্পিউটার , ট্যাব ও স্মার্ট ফোন ভার্সন সহ সম্পূর্ণ বাংলা ই-বুক বা pdf বই " সুচিপত্র ...বুকমার্ক মেনু 🔖 ও হাইপার লিংক মেনু 📝👆 যুক্ত ..
আমাদের সবার জন্য খুব খুব গুরুত্বপূর্ণ একটি বই ..বিসিএস, ব্যাংক, ইউনিভার্সিটি ভর্তি ও যে কোন প্রতিযোগিতা মূলক পরীক্ষার জন্য এর খুব ইম্পরট্যান্ট একটি বিষয় ...তাছাড়া বাংলাদেশের সাম্প্রতিক যে কোন ডাটা বা তথ্য এই বইতে পাবেন ...
তাই একজন নাগরিক হিসাবে এই তথ্য গুলো আপনার জানা প্রয়োজন ...।
বিসিএস ও ব্যাংক এর লিখিত পরীক্ষা ...+এছাড়া মাধ্যমিক ও উচ্চমাধ্যমিকের স্টুডেন্টদের জন্য অনেক কাজে আসবে ...
PCOS corelations and management through Ayurveda.
This presentation includes basic of PCOS their pathology and treatment and also Ayurveda correlation of PCOS and Ayurvedic line of treatment mentioned in classics.
Hindi varnamala | hindi alphabet PPT.pdf
हिंदी वर्णमाला पीपीटी, hindi alphabet PPT presentation, hindi varnamala PPT, Hindi Varnamala pdf, हिंदी स्वर, हिंदी व्यंजन, sikhiye hindi varnmala, dr. mulla adam ali, hindi language and literature, hindi alphabet with drawing, hindi alphabet pdf, hindi varnamala for childrens, hindi language, hindi varnamala practice for kids, https://www.drmullaadamali.com
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
This slide is special for master students (MIBS & MIFB) in UUM. Also useful for readers who are interested in the topic of contemporary Islamic banking.
The History of Stoke Newington Street Names
Presented at the Stoke Newington Literary Festival on 9th June 2024
www.StokeNewingtonHistory.com
Recently uploaded (20)
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
Pengantar Penggunaan Flutter - Dart programming language1.pptx
Pengantar Penggunaan Flutter - Dart programming language1.pptx
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
Leveraging Generative AI to Drive Nonprofit Innovation
Leveraging Generative AI to Drive Nonprofit Innovation
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Digital Artefact 1 - Tiny Home Environmental Design
Digital Artefact 1 - Tiny Home Environmental Design
How to Manage Your Lost Opportunities in Odoo 17 CRM
How to Manage Your Lost Opportunities in Odoo 17 CRM
Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...
Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...
How to Build a Module in Odoo 17 Using the Scaffold Method
How to Build a Module in Odoo 17 Using the Scaffold Method
Chapter wise All Notes of First year Basic Civil Engineering.pptx
Chapter wise All Notes of First year Basic Civil Engineering.pptx
বাংলাদেশ অর্থনৈতিক সমীক্ষা (Economic Review) ২০২৪ UJS App.pdf
বাংলাদেশ অর্থনৈতিক সমীক্ষা (Economic Review) ২০২৪ UJS App.pdf
NEWSPAPERS - QUESTION 1 - REVISION POWERPOINT.pptx
NEWSPAPERS - QUESTION 1 - REVISION POWERPOINT.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
D. 192.168.1.0 0.0.0.63The IP address and wildcard mask to identif.pdf
- 1. D. 192.168.1.0 0.0.0.63 The IP address and wildcard mask to identify the hosts in 192.168.1.0/26 would be 192.168.1.0 0.0.0.63 Solution D. 192.168.1.0 0.0.0.63 The IP address and wildcard mask to identify the hosts in 192.168.1.0/26 would be 192.168.1.0 0.0.0.63