calculate the hydrogen ion concentration in mol/ for the following solutions 2.42 11.21 6.96 15.00 Solution PH=-log[H+] [H+]=10^(-Ph) 1)[H+]=10^(-2.62) 2)[H+]=10^(-11.21) 3)[H+]=10^(-6.96) 4)[H+]=10^(-15) But in the 4th case it is smaller than [H+] concentration of water...So there will be a equilibrium and hence the [H+]=10^(-14) ionic product of water....