The document provides an overview of assignment operators in the C programming language, illustrating their use for value assignment, type casting, and within conditional statements. It explains that using the assignment operator in an if statement can lead to always evaluating to true, as the assigned value is treated as a non-zero number. Additionally, it details shorthand assignment operators with examples demonstrating their functionality.

1. C Language Assignment Help
Way 1 : Assignment Operator used to Assign Value
int main() {
int value;
value = 55;
return (0);
}
In the abov e ex ampl e, w e hav e assigned 55 to a v ariabl e ‘v al ue’.
Way 2 : Assignment Operator used To Type Cast.
int value;
value = 55.450;
printf("%d",value);
Assignment operator can ty pe cast higher v al ues to l ow er v al ues. It can al so cast l ow er v al ues to higher v al ues
Way 3 : Assignment Operator in If Statement
if(value = 10)
printf("True");
else
printf("False");

2. It w ould be interesting tounderstand above program. Above Program will always execute True Condition because Assignment Operator is used inside if
statement not comparison operator. Lets see w hat w il l happen in abov e ex ampl e –
Constant number 10 will be assignedtovariable ‘value’. Variable ‘value’ will be treated as positive non-zero number, w hich is considered as true condition.
if(value = 0)
printf("True");
else
printf("False");
In bel ow case el se bl ock w il l be ex ecuted
Shorthand assignment operator
Shorthand assignment operator is used ex press the sy ntax that are al ready av ail abl e in shorter w ay
Operator symbol Name of the operator Example Equivalent construct
+= Addition assignment x += 4; x = x + 4;
-= Subtraction assignment x -= 4; x = x – 4;
*= Multiplication assignment x *= 4; x = x * 4;
/= Division assignment x /= 4; x = x / 4;
%= Remainder assignment x %= 4; x = x % 4;
Example : Shorthand assignment operator
#include<stdio.h>
int main() {
int res;
res = 11;
res += 4;
printf("nResult of Ex1 = %d", res);
res = 11;
res -= 4;
printf("nResult of Ex2 = %d", res);
res = 11;
res *= 4;
printf("nResult of Ex3 = %d", res);
res = 11;
res /= 4;
printf("nResult of Ex4 = %d", res);
res = 11;

3. res %= 4;
printf("nResult of Ex5 = %d", res);
return 0;
}
Output :
Result of Ex1 = 15
Result of Ex2 = 7
Result of Ex3 = 44
Result of Ex4 = 2
Result of Ex5 = 3