c++ 1- Create lines necessary to open a file named name-txt and store.docx
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c++ 1. Create lines necessary to open a file named “name.txt” and store your name in it. 2. Create lines necessary to open a user-specified file and get a double from it. Solution 1. #include<iostream> #include<fstream> using namespace std; int main(){ string name; ofstream writeFile; writeFile.open(\"name.txt\"); cout<<\"Enter your name: \"; getline(cin, name); writeFile<<name; writeFile.close(); cout<<\"Name has written successfully in file\"<<endl; return 0; } 2. #include<iostream> #include<fstream> using namespace std; int main(){ string filename;; ifstream readFile; cout<<\"Enter input file name: \"; cin>>filename; readFile.open(filename.c_str()); double num; readFile>>num; readFile.close(); cout<<\"Double number from file is: \"<<num<<endl; return 0; } .
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C++ program Revising the Array-Based List ADT Given the data structure.docx
C++ program
Revising the Array-Based List ADT
Given the data structure
typedef char *Element;
struct List {
Element *data;
int count;
int capacity;
};
Modify the following insertTail operations, instead of returning false when the array is full, the function should attempt to double the capacity of the list and the old array list is copied into the new array list, and then insert new element. Given the following implementation to modify:
bool insertTail(List* l, Element e) {
if (fullList(l)) {
return false;
} else {
l->data[l->count] = e;
l->count++;
return true;
}
}
Solution
Creating tempElement array.. and copy old elements. Then replace old array with new temp Array. And also we need to update capacity of list.
bool insertTail(List* l, Element e) {
if (fullList(l)) {
// temp list declared with double size
int tempCount = l->count;
Element * temp = new Element[2*tempCount];
// copying old list to new list
for(int i=0; i<tempCount; i++){
temp[i] = list->data[i];
}
//now referencing old array with new array
l->data = temp;
l->capacity = 2*tempCount;
}
// no else condition.. it will continue to insert
l->data[l->count] = e;
l->count++;
return true;
}
.
C++ help!! Im not familiar with how to save- read file so that the pro.docx
C++ help!! Im not familiar with how to save/ read file so that the program works so i\'d realllyy appreaciate it if you wrote down the steps along with the code!
Solution
#include<fstream>
#include<iostream>
using namespace std;
int main()
{
int i,j;
int a[4][4],trans[4][4];
ifstream infile(\"Matrix_01.txt\");//change the file name to test for matrix_02 it must be in the same folder
if(!infile)
{
cout<<\"Cannot open file1.\ \";
return
}
for(i=0;i<4;i++)//reads from the file
{
for(j=0;j<4;j++)
{
infile1>>a[i][j];
}
}
cout<<\"Matrix:\"<<endl;//displays the matrix
for(i=0; i<4; ++i)
{
for(j=0; j<4; ++j)
{
cout << \" \" << a[i][j];
}
cout<<endl;
}
cout<<\"Transpose:\"<<endl;
for(i=0; i<4; ++i)//calculates transpose
for(j=0; j<4; ++j)
{
trans[j][i]=a[i][j];
}
for(i=0; i<4; ++i)//prints transpose
{
for(j=0; j<4; ++j)
{
cout << \" \" << trans[i][j];
}
cout<<endl;
}
cout<<\"Upper Triangle:\ \";
for (int i = 0; i < 4;i++)//prints upper traingle
{
for (int j = 0; j < (4- i); j++)
{
cout << a[i][j] << \" \";
}
cout << \"\ \";
}
cout<<\"Lower Triangle:\ \";
for(i=0;i<4;i++)//prints lower triangle
{
for(j=0;j<=i;j++)
{
cout<<a[i][j]<<\" \";
}
cout<<\"\ \";
}
for ( i = 0 ; i < 4 ; i++ )//checks for transpose
{
for ( j = 0 ; j < 4 ; j++ )
{
if ( a[i][j] != trans[i][j] )
break;
}
if ( j != 4 )
break;
}
if ( i == 4 )
cout<<\"It is a Symmetric matrix.\ \";
else
cout<<\"It is not a Symmetric matrix.\ \";
}
.
c++ computer architecture and memory What is fragmentation- Briefly ex.docx
c++ computer architecture and memory
What is fragmentation? Briefly explain what it is and how we address it. Explain the role of the stack and the heap, using an example of calling a function that then allocates memory for 100 integers to a local pointer variable. You may use a diagram if you wish.
Solution
A)Fragmentation is an phenomenon in which using of storage capacity in efficiently
There are three types of fragmentation
1.internal fragmentation
2.external fragmentation
3.data fragmentation
Addressing is in the form offsets,data grand
B)stack is an one of the data structure in which push and pop operations are done
In this first all the elements are push in to stack and then popping out the elementsI
Is done pop()function
Ex:for example I have 100integer variable iam allocating it to stack data structure
main()
{
Int *elements[]; //declaring pointer variabl
Stackelements();
Void stackelements()
{
For(I=0;I<=100;i±+)
Elements[i]=n
}
.
C# There are two schools of thought on the use of implicitly typed var.docx
C#
There are two schools of thought on the use of implicitly typed variables. One school advocates avoiding the use of implicitly types variables in all but a few very specific situations, while another feels it is ok as long as the data type is obvious from the variable declaration. Which camp are you in? Discuss the advantages and dis-advantages of using implicitly typed variables in your applications.
Solution
Dis-advantages over using the implicitly types variable in application:
1. Implicitly-typed variables lose descriptiveness
2. var’ encourages Hungarian Notation
3. Specificity vs. Context
There’s no doubt that variable names must be specific, however, they need never be universally-specific.
Just as a local variable in one method doesn’t need to differentiate itself from variables in other methods
Advantages over using the implicitly types variable in application
1. Increased reliance on IntelliSense
2. No backwards compatibility
.
Brief introduction of the WorldComSolutionWorldCom was started by Bill.docx
Brief introduction of the WorldCom
Solution
WorldCom was started by Bill Fields in Hattiesburg, Mississippi, in 1983 under the name \'Long Distance Discount Services\' (LDDS), providing telecommunication (telecom) services. From the starting day, the services runs profitably. Now, we going to know about big head of Services, Bernie Ebbers (Ebbers) was the take up as company\'s CEO in 1985. Bernie takes up the services to all over the world. Firstly, the company made the number in public trade list in 1989 after that company CEO put concertation on enlarging the company operations by acquiring various companies. Unfoutunaterly, \'Long Distance Discount Services\' (LDDS), LLDS changed its name as WorldCom in In 1995. LDDS survived 12 years good name but World com had only 7 years up to 2002 the company survived with good name. After 2002, WorldCom became to known as MCI after that a massive accounting scandal was taken by company through filing for bankruptcy protection in 2002 and CEO Bernard Ebbers was penalized to 25 years in prison,
.
Brief Exercise 5-5 Crane Corporation has the following accounts includ.docx
Brief Exercise 5-5
Crane Corporation has the following accounts included in its December 31, 2014, trial balance: Equity Investments (trading) $21,000; Goodwill $150,000; Prepaid Insurance $12,000; Patents $220,000; Franchises $130,000.
Prepare the intangible assets section of the balance sheet.
Current AssetsCurrent LiabilitiesIntangible AssetsLong-term InvestmentsLong-term LiabilitiesProperty, Plant and EquipmentStockholders\' EquityTotal AssetsTotal Current AssetsTotal Current LiabilitiesTotal Intangible AssetsTotal InvestmentsTotal LiabilitiesTotal Liabilities and Stockholders\' EquityTotal Long-term LiabilitiesTotal Property, Plant and EquipmentTotal Stockholders\' Equity
Brief Exercise 5-6
Patrick Corporation
Solution
Exercise 5-5
Balance Sheet as at Dec. 31,2014
Exercise 5-6
Exercise 5-9
.
Briefly describe some of the similarities and differences between U-S-.docx
Briefly describe some of the similarities and differences between U.S. GAAP and IFRS with respect to the accounting for investments.
Solution
Similarities 1) An equity investment that gives an investor significant influence over an investee is considered an equity method investment under both US GAAP and IFRS. 2) Further the equity method of accounting for such investments if applicable generally is consistent under both US GAAP and IFRS. 3) Under both US GAAP And IFRS the determination of whether entities are consolidated by a reporting entity is based on control although there is some differences in the definition of control. 4) Further uniform accounting policies are used for all the entities within a consolidated group. Differences 1)Under US GAAP focus is on controlling Financial interests whereas under IFRS focus is on power to control. 2) Under US GAAP preparaion of consolidated financial statements is required in general although certain industry specific exceptions exist. Under IFRS it is also required in general but there is limited exemption from preparing consolidated financial statements for a parent company that is itself a wholly owned subsidiary or is apartially owned subsidiary if certain conditions are met. 3) Under US GAAP potential voting rights are generally not considered in the determination of significant influence whereas under IFRS potential voting rights are considered if currently exercisable in determining significant influence.
.
Briefly describe what the query evaluation engine performs inside a DB.docx
Briefly describe what the query evaluation engine performs inside a DBMS.
Solution
Generally we write queries to retrieve data from database.What we know is just simply submit the query.Actually,so many people don\'t know after submitting query What happend really in between submission of query and retrieving data is: query handeld to query processor .That query processor having different components to process that query
one of the components of query processor is :query evaluation engine :1)it executes the low-level instructions that are generated by DML compiler.DML compiler generate the execution plan with that low-level instructions from the query.
2)query evaluation engine takes input from query optimizer and gives out physical operations.
query optimizer produces best execution plan out of many plans by considering some cost like no of operations,cpu time etc.What actually execution plan consists is logical operators.
These logical operators are taken by query evaluation engine and generate physical operations.
While doing physical operation evaluation engine closely takes into the available resources like memory.
physial operations like sorting,hashing,disk access etc.
.
Recommended
C++ program Revising the Array-Based List ADT Given the data structure.docx
C++ program
Revising the Array-Based List ADT
Given the data structure
typedef char *Element;
struct List {
Element *data;
int count;
int capacity;
};
Modify the following insertTail operations, instead of returning false when the array is full, the function should attempt to double the capacity of the list and the old array list is copied into the new array list, and then insert new element. Given the following implementation to modify:
bool insertTail(List* l, Element e) {
if (fullList(l)) {
return false;
} else {
l->data[l->count] = e;
l->count++;
return true;
}
}
Solution
Creating tempElement array.. and copy old elements. Then replace old array with new temp Array. And also we need to update capacity of list.
bool insertTail(List* l, Element e) {
if (fullList(l)) {
// temp list declared with double size
int tempCount = l->count;
Element * temp = new Element[2*tempCount];
// copying old list to new list
for(int i=0; i<tempCount; i++){
temp[i] = list->data[i];
}
//now referencing old array with new array
l->data = temp;
l->capacity = 2*tempCount;
}
// no else condition.. it will continue to insert
l->data[l->count] = e;
l->count++;
return true;
}
.
C++ help!! Im not familiar with how to save- read file so that the pro.docx
C++ help!! Im not familiar with how to save/ read file so that the program works so i\'d realllyy appreaciate it if you wrote down the steps along with the code!
Solution
#include<fstream>
#include<iostream>
using namespace std;
int main()
{
int i,j;
int a[4][4],trans[4][4];
ifstream infile(\"Matrix_01.txt\");//change the file name to test for matrix_02 it must be in the same folder
if(!infile)
{
cout<<\"Cannot open file1.\ \";
return
}
for(i=0;i<4;i++)//reads from the file
{
for(j=0;j<4;j++)
{
infile1>>a[i][j];
}
}
cout<<\"Matrix:\"<<endl;//displays the matrix
for(i=0; i<4; ++i)
{
for(j=0; j<4; ++j)
{
cout << \" \" << a[i][j];
}
cout<<endl;
}
cout<<\"Transpose:\"<<endl;
for(i=0; i<4; ++i)//calculates transpose
for(j=0; j<4; ++j)
{
trans[j][i]=a[i][j];
}
for(i=0; i<4; ++i)//prints transpose
{
for(j=0; j<4; ++j)
{
cout << \" \" << trans[i][j];
}
cout<<endl;
}
cout<<\"Upper Triangle:\ \";
for (int i = 0; i < 4;i++)//prints upper traingle
{
for (int j = 0; j < (4- i); j++)
{
cout << a[i][j] << \" \";
}
cout << \"\ \";
}
cout<<\"Lower Triangle:\ \";
for(i=0;i<4;i++)//prints lower triangle
{
for(j=0;j<=i;j++)
{
cout<<a[i][j]<<\" \";
}
cout<<\"\ \";
}
for ( i = 0 ; i < 4 ; i++ )//checks for transpose
{
for ( j = 0 ; j < 4 ; j++ )
{
if ( a[i][j] != trans[i][j] )
break;
}
if ( j != 4 )
break;
}
if ( i == 4 )
cout<<\"It is a Symmetric matrix.\ \";
else
cout<<\"It is not a Symmetric matrix.\ \";
}
.
c++ computer architecture and memory What is fragmentation- Briefly ex.docx
c++ computer architecture and memory
What is fragmentation? Briefly explain what it is and how we address it. Explain the role of the stack and the heap, using an example of calling a function that then allocates memory for 100 integers to a local pointer variable. You may use a diagram if you wish.
Solution
A)Fragmentation is an phenomenon in which using of storage capacity in efficiently
There are three types of fragmentation
1.internal fragmentation
2.external fragmentation
3.data fragmentation
Addressing is in the form offsets,data grand
B)stack is an one of the data structure in which push and pop operations are done
In this first all the elements are push in to stack and then popping out the elementsI
Is done pop()function
Ex:for example I have 100integer variable iam allocating it to stack data structure
main()
{
Int *elements[]; //declaring pointer variabl
Stackelements();
Void stackelements()
{
For(I=0;I<=100;i±+)
Elements[i]=n
}
.
C# There are two schools of thought on the use of implicitly typed var.docx
C#
There are two schools of thought on the use of implicitly typed variables. One school advocates avoiding the use of implicitly types variables in all but a few very specific situations, while another feels it is ok as long as the data type is obvious from the variable declaration. Which camp are you in? Discuss the advantages and dis-advantages of using implicitly typed variables in your applications.
Solution
Dis-advantages over using the implicitly types variable in application:
1. Implicitly-typed variables lose descriptiveness
2. var’ encourages Hungarian Notation
3. Specificity vs. Context
There’s no doubt that variable names must be specific, however, they need never be universally-specific.
Just as a local variable in one method doesn’t need to differentiate itself from variables in other methods
Advantages over using the implicitly types variable in application
1. Increased reliance on IntelliSense
2. No backwards compatibility
.
Brief introduction of the WorldComSolutionWorldCom was started by Bill.docx
Brief introduction of the WorldCom
Solution
WorldCom was started by Bill Fields in Hattiesburg, Mississippi, in 1983 under the name \'Long Distance Discount Services\' (LDDS), providing telecommunication (telecom) services. From the starting day, the services runs profitably. Now, we going to know about big head of Services, Bernie Ebbers (Ebbers) was the take up as company\'s CEO in 1985. Bernie takes up the services to all over the world. Firstly, the company made the number in public trade list in 1989 after that company CEO put concertation on enlarging the company operations by acquiring various companies. Unfoutunaterly, \'Long Distance Discount Services\' (LDDS), LLDS changed its name as WorldCom in In 1995. LDDS survived 12 years good name but World com had only 7 years up to 2002 the company survived with good name. After 2002, WorldCom became to known as MCI after that a massive accounting scandal was taken by company through filing for bankruptcy protection in 2002 and CEO Bernard Ebbers was penalized to 25 years in prison,
.
Brief Exercise 5-5 Crane Corporation has the following accounts includ.docx
Brief Exercise 5-5
Crane Corporation has the following accounts included in its December 31, 2014, trial balance: Equity Investments (trading) $21,000; Goodwill $150,000; Prepaid Insurance $12,000; Patents $220,000; Franchises $130,000.
Prepare the intangible assets section of the balance sheet.
Current AssetsCurrent LiabilitiesIntangible AssetsLong-term InvestmentsLong-term LiabilitiesProperty, Plant and EquipmentStockholders\' EquityTotal AssetsTotal Current AssetsTotal Current LiabilitiesTotal Intangible AssetsTotal InvestmentsTotal LiabilitiesTotal Liabilities and Stockholders\' EquityTotal Long-term LiabilitiesTotal Property, Plant and EquipmentTotal Stockholders\' Equity
Brief Exercise 5-6
Patrick Corporation
Solution
Exercise 5-5
Balance Sheet as at Dec. 31,2014
Exercise 5-6
Exercise 5-9
.
Briefly describe some of the similarities and differences between U-S-.docx
Briefly describe some of the similarities and differences between U.S. GAAP and IFRS with respect to the accounting for investments.
Solution
Similarities 1) An equity investment that gives an investor significant influence over an investee is considered an equity method investment under both US GAAP and IFRS. 2) Further the equity method of accounting for such investments if applicable generally is consistent under both US GAAP and IFRS. 3) Under both US GAAP And IFRS the determination of whether entities are consolidated by a reporting entity is based on control although there is some differences in the definition of control. 4) Further uniform accounting policies are used for all the entities within a consolidated group. Differences 1)Under US GAAP focus is on controlling Financial interests whereas under IFRS focus is on power to control. 2) Under US GAAP preparaion of consolidated financial statements is required in general although certain industry specific exceptions exist. Under IFRS it is also required in general but there is limited exemption from preparing consolidated financial statements for a parent company that is itself a wholly owned subsidiary or is apartially owned subsidiary if certain conditions are met. 3) Under US GAAP potential voting rights are generally not considered in the determination of significant influence whereas under IFRS potential voting rights are considered if currently exercisable in determining significant influence.
.
Briefly describe what the query evaluation engine performs inside a DB.docx
Briefly describe what the query evaluation engine performs inside a DBMS.
Solution
Generally we write queries to retrieve data from database.What we know is just simply submit the query.Actually,so many people don\'t know after submitting query What happend really in between submission of query and retrieving data is: query handeld to query processor .That query processor having different components to process that query
one of the components of query processor is :query evaluation engine :1)it executes the low-level instructions that are generated by DML compiler.DML compiler generate the execution plan with that low-level instructions from the query.
2)query evaluation engine takes input from query optimizer and gives out physical operations.
query optimizer produces best execution plan out of many plans by considering some cost like no of operations,cpu time etc.What actually execution plan consists is logical operators.
These logical operators are taken by query evaluation engine and generate physical operations.
While doing physical operation evaluation engine closely takes into the available resources like memory.
physial operations like sorting,hashing,disk access etc.
.
Briefly explain the purposes of adjustments Briefly explain the purp.docx
Briefly explain the purposes of adjustments
Briefly explain the purposes of adjustments
Solution
The accounting process involves the preparation of adjusting entries. Adjusting journal entries are made to update the accounts and bring them to their correct balances.
The preparation of adjusting entries is an application of the accrual concept of accounting and the matching principle .
The accrual concept states that income is recognized when earned regardless of when collected and expenses are recognized when incurred regardless of when paid.
Also, the matching principle aims to align expenses with revenues. Expenses should be recognized in the period when the revenues earned with them are recognized.
Why Are Adjusting Entries Necessary
The purpose of adjusting entries is to update the accounts to conform with the accrual concept . At the end of the accounting period, some income and expenses may have not been recorded, taken up or updated; hence, there is a need to update the accounts.
If adjusting entries are not prepared, some income, expense, asset, and liability accounts may not reflect their true values when reported in the financial statements. For this reason, adjusting entries are necessary.
BELOW are the types of journal entires.
Generally, there are 4 types of adjusting entries. Adjusting entries are prepared for the following:
.
Budget Martin Corporation granted a nonqualified stock option to e.docx
Budget
Solution
Answer:
Caroline must recognise the following incomes:
1. Long term capital gain of $50,000 as she sold the stock one year later at a price of $300 per share , while she exercised the stoock at a price of $250 per share. [(1000 shares*300)-(1000shares*250)]
2. And Oridinary Income of $100,000 as she exercised the option at the rate of $250 per share while the stok was granted at the rate of $150.[(1000shares*250)-(1000 shares*150)]
.
Calculate fost of goods sold and ending inventory and analyze effect o (1).docx
Calculate fost of goods sold and ending inventory and analyze effect of each method on financial statements. Jefferson company had the following sales and purchases during 2011, its first year of business:
January 5 Purchased 40 units at $100 each
February 15 Sold 15 units at $150 each
April 10 Sold 10 units at $150 each
June 30 Purchased 30 units at $105 each
August 15 Sold 25 units at $150 each
November 28 Purchased 30 untis at $110 each
Solution
Part A: Record the effect of the following transactions on the accounting equation assuming LIFO perpetual:
Transactions in January, 2011:
Assets
Liabilities
Shareholders
.
Calculate fost of goods sold and ending inventory and analyze effect o.docx
Calculate fost of goods sold and ending inventory and analyze effect of each method on financial statements. Jefferson company had the following sales and purchases during 2011, its first year of business:
January 5 Purchased 40 units at $100 each
February 15 Sold 15 units at $150 each
April 10 Sold 10 units at $150 each
June 30 Purchased 30 units at $105 each
August 15 Sold 25 units at $150 each
November 28 Purchased 30 untis at $110 each
Solution
Part A: Record the effect of the following transactions on the accounting equation assuming LIFO perpetual:
Transactions in January, 2011:
Assets
Liabilities
Shareholders
.
Ca(OH)2 is insoluble- What is the total concentration of ions if 2M of.docx
Ca(OH)2 is insoluble. What is the total concentration of ions if 2M of Ca(OH)2 dissolves in water.
Ca(OH)2 is insoluble. What is the total concentration of ions if 2M of Ca(OH)2 dissolves in water.
Solution
Ca(OH)2 is partially soluble in water and we can find solubility based on solubility product
Ca(OH)2 (s) <-----> Ca2+ (aq) + 2OH- (aq)
at equilibrium [Ca2+] = S , [OH-] = 2S
Ksp = [Ca2+] [OH-]^2 ( where Ksp is solubility product of Ca(OH)2 in water)
5.5 x 10^ -6 = (S) (2S)^2
S = 0.0111 M
Thus [Ca2+] = 0.0111 , [OH-] = 2 x 0.0111 = 0.0222 M
Total concetrations of ions = [Ca2+] + 2 [OH-] = ( 0.0111) + 2 ( 0.0222) = 0.0555 M
.
c- Since BEEF hooks to Metasploit- is there any safe way to use the we.docx
c. Since BEEF hooks to Metasploit, is there any safe way to use the web today? Explain.
Solution
a.) The safe way of using web is by implementing firewalls,secure virtual private networks and antivirus.
b.) Implementing the firewalls is an imperative solution for all organizations to protect their sensitive data fro getting lost.Firewall keeps everything secure from the possible attacks.This is done by analysing the data that gets transmitted back and forth in the network.
c.) Implementation is possible through the following steps
- defining the security needs to finf out the level of security necessary.
- researching soutions to match the specified needs
- and finally installing,configuring and maintaining the firewalls.
d.) Virtual private network as the name itself suggest extends a private network across the public network of internet.I tprovides functionality,network management and security benefits to the user.
e.) The antivirus helps in preventing,detecting and removing the malicious software.I tprovides protection from various computer threats phishing attacks,online identity attacks,malicious URL\'s and etc.
.
9- Fill in the following table with names or formulas- as appropriate-.docx
9. Fill in the following table with names or formulas, as appropriate: Names silver sulfate hydrocyanic acid gold(III) chlorite perbromic acid calcium phosphide mercury(I) nitrate sulfurous acid aluminum chromate tin(IV) carbonate oxalic acid Formulas Fe(HC03)2 HNO2(aq (NH4)3BO3 Li2Cr20, Hl(aq)
Solution
silver sulfate = Ag2So4
hydrocyanic acid = HCN
gold(III) chlorite = Au(Clo2)3
perbromic acid = Hbro4
calcium phosphide = ca3p2
mercury(I)nitrate = hg2(no3)2
sulfurous acid = H2So3
aluminum chromate = Al2(cro4)3
tin(iv)carbonate = sn(co3)2
oxalic acid = (cooh)2
iron(ii)hydrogen carbonate = Fe(hco3)2
aqueous nitrous acid =HNo2(aq)
ammonium borate = (NH4)3Bo3
lithium dichromate = Li2Cr2o7
aqueous hydro iodic acid = HI(aq)
the above names based on the type of elements or substituents
attached to the compounds
.
9- A combination of sand- salt- and water is an example of a A) homoge.docx
9. A combination of sand, salt, and water is an example of a A) homogeneous mixture B) heterogeneous mixture C) compound D) pure substance E) solid 10. Forthe following reaction Chldh +Oz ? CO2 + 11,0 what is the coefficient of oxygen? a. 2 b. 4 c. 6 d. 8 e. None of the above
Solution
9) Salt, sand and water mixture contains two different phases. liquid phase and solid phase.
and moreover they dont mix and form separate phases.
So, this is example of heterogeneous mixture. (B)
10)
Balance the reaction :
C 3 H 4 O2 + O 2 -----------> CO 2 + H 2 O
balance the reaction for Carbon ,
C 3 H 4 O2 + O 2 -----------> 3 CO 2 + H 2 O
balance the reaction for hydrogen,
C 3 H 4 O2 + O 2 -----------> 3 CO 2 + 2 H 2 O
now balance the reaction for oxygen,
C 3 H 4 O2 + 3 O 2 -----------> 3 CO 2 + 2 H 2 O
So, the answer is 3 and option is none of the above.
.
8-6- Which of the highlighted elements in Figure P8-6 has the greatest.docx
8.6. Which of the highlighted elements in Figure P8.6 has the greatest electronegativity? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 FIGURE P8.6
Solution
Electronegativity is a chemical property of an atom that describes how well the atom withdraws shared pair of electrons towards it. It is measured in terms of Pauling Scale from   0 to 4.
The higher the value, the more the electronegativity of the atom.
The highlighted element 17 (Fluorine, F) has the highest electronegativity value is 3.98 .
The highlighted element 1 (Lithium, Li) has the highest electronegativity value is 0.98.
The highlighted element 2 (Beryllium, Be) has the highest electronegativity value is 1.57.
The highlighted element 13 (Boron, B) has the highest electronegativity value is 2.04.
The highlighted element 14 (Carbon, C) has the highest electronegativity value is 2.55.
The highlighted element 15 (Nitrogen, N) has the highest electronegativity value is 3.04.
The highlighted element 16 (Oxygen, O) has the highest electronegativity value is 3.44.
The highlighted element 18 (Neon, Ne) has the highest electronegativity value is 0.
.
870 The plates of a capacitor are not quite parallel- the distance bet.docx
870 The plates of a capacitor are not quite parallel, the distance between them at the bottom being (D a) and at the top (Dta), where a
Solution
let length of each plate be L and width be W.
then area A=L*W
at a distance x from the bottom end of the plate, distance between the plates as a function of x is given as
d=D-a+(2*a/L)*x
consider a small segment of length dx at a distance of x from the bottom end
area of the segment=W*dx
distance between the two plates=d=(D-a+(2*a/L)*x)
then capacitance=dC=epsilon*area/distance between plates
=epsilon*W*dx/(D-a+(2*a/L)*x)
let D-a+(2*a/L)*x=y
==>(2*a/L)*dx=dy
==>dx=L*dy/(2*a)
substituting,
dC=epsilon*W*L*dy/(2*a*y)
integrating both sides,
C=(epsilon*W*L/(2*a))*ln(y)
as y varies from D-a to D+a
C=(epsilon*W*L/(2*a))*ln((D+a)/(D-a))
as A=W*L
and ln((D+a)/(D-a))
=ln((1+(a/D))/(1-(a/D)))
=2*(a/D)*(1+(a^2/(3*D^2)))
then C=(epslion*A/(2*a))*(2*a/D)*(1+(a^2/(3*D^2)))
=(epsilon*A/D)*(1+(a^2/(3*D^2)))
.
8- What are concurrency design patterns- Explain-Solution8) we have fi.docx
8. What are concurrency design patterns? Explain.
Solution
8)
we have five concurrency design patterns:
-------------------------------------------------
First pattern is Active object design pattern . This pattern decouples method invocation. This is to enhance
concurrency and simplify synchronized access to objects that reside in their own threads of control.
Second pattern is Monitor pattern which synchronizes concurrent method execution to ensure that only one
method at a time runs within an object. It allows obkect methods to schedule their execution sequence.
Third pattern is haof sync / half async pattern which decouples synchrounous and synchronous processing in
concurrent systems, so that it will simplify programmming without reducing performance undudly.
Fourth pattern is Leader pattern which provides concurrency model where multiple threads take turns to share
a set of event sources to detect, demultiplexm dispatch and process service requests that occur on the
event sources.
Fifth pattern is thread specific storage design pattern to allow multiple threads to use one logical global
access point to retrieve an object that is local to a thread, without uncurring locking overload on each access
to the object.
.
8- Calculate the distance from the donor (D) to the acceptor (A) in th.docx
8. Calculate the distance from the donor (D) to the acceptor (A) in the protein represented. Assume that there is a single D-A distance, and that diffusion does not occur during the donor excited-state lifetime. Given:
A.The F DA /F D ratio is 0.50 (that is, the ratio between the fluorescence intensity of the donor in the presence of the acceptor (F DA ) and the fluorescence of the respective control molecule which lacks the acceptor (F D )).
B.The spectral overlap integral  ( J (l)) for this donor-acceptor pair is 4.5 x 10 13 M -1 cm -1 nm 4 .
C.The refractive index of the solution is 1.4.
D.The fluorescence quantum yield of the donor in the absence of acceptor is 0.3.
Solution
Fret E = 1- FDA/FD
E = 1-0.50
= 0.50
Rn = R0 (n(1-E)/E)1/6
Rn is the distance between A and D
E = 0.5
R0 = 4.5 X 1013 unit
Hence Rn = 4.5 X 1013 X 1.4 (1-0.5/0.5)1/6
=4.5 X 1013 X (1.4)1/6
= 4.5 X 1013 X 8.4
= 38291.4 angstrom
N = 1.4
.
7- You want to create an SSIS package that copies data from a source t.docx
7. You want to create an SSIS package that copies data from a source to a destination. You want to run the package after you create it. Which is the simplest method to accomplish that?
Solution
SQL Server Integration Services ( SSIS ) is a component of the Microsoft SQL Server database software that can be used to perform a broad range of data migration tasks.
SSIS is a platform for data integration and workflow applications. It features a fast and flexible data warehousing tool used for dataextraction, transformation, and loading (ETL). The tool may also be used to automate maintenance of SQL Server databases and updates to multidimensional cube data.
First released with Microsoft SQL Server 2005, SSIS replaced Data Transformation Services, which had been a feature of SQL Server since Version 7.0. Unlike DTS, which was included in all versions, SSIS is only available in the \"Standard\", \"Business Intelligence\" and \"Enterprise\" editions.
.
9- List four interface design issues present in the development of mos.docx
9. List four interface design issues present in the development of most user interfaces?
Solution
The interface design issues are:
There are four interface design issues they are
1) Access and short cut keys 2) Bit maps and Icons 3) UI controls 4) Messages.
Access and shortcut keys: Short cut keys doesnot contains characters from the double bite character.
Bitmaps and Icons: These functionality dont use in text when working with bit maps and icons consider of following rules. Bit maps which are not international standards avoid using them. And we need to check whether the Access key and short cut key are there are not. Limitation of this functionality is ude function keys and numbers instead of letters in short cut keys.
UI controls: There are so many UI controls like buttons, List boxes, Combo boxes etc.,These are the building blocks of dailogue boxes.
- Hiding a control behind another control is not the correct way to locate it. It will happen due to language expansion.
- By using controls as part os scentences the sentences suffer the same problem as concatenation strings.
Messages: Text strings are usually larger than english text strings in other languages. The growth rate which is acute in short strings become less of a problem as string length increases.
.
9- Nomenclature- A table describing the name and formula an ion- eleme.docx
9. Nomenclature: A table describing the name and formula an ion, eleme ionic or molecular compound is iption correct, or incorrect? Correct any parts of the table that you believe are incorrect. (9 points) Correct or Incorrect Name Formula Phosphate lon ??? Aluminum Carbonate Al2(HCO3)
Solution
Answer :
.
The Challenger.pdf DNHS Official Publication
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Basic Civil Engineering Notes of Chapter-6, Topic- Ecosystem, Biodiversity G...
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Types of Ecosystem
(1) Natural Ecosystem
(2) Artificial Ecosystem
component of ecosystem
Biotic Components
Abiotic Components
Producers
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Decomposers
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Species Biodiversity
Ecological Biodiversity
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Hydrological Cycle
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Briefly explain the purposes of adjustments
Briefly explain the purposes of adjustments
Solution
The accounting process involves the preparation of adjusting entries. Adjusting journal entries are made to update the accounts and bring them to their correct balances.
The preparation of adjusting entries is an application of the accrual concept of accounting and the matching principle .
The accrual concept states that income is recognized when earned regardless of when collected and expenses are recognized when incurred regardless of when paid.
Also, the matching principle aims to align expenses with revenues. Expenses should be recognized in the period when the revenues earned with them are recognized.
Why Are Adjusting Entries Necessary
The purpose of adjusting entries is to update the accounts to conform with the accrual concept . At the end of the accounting period, some income and expenses may have not been recorded, taken up or updated; hence, there is a need to update the accounts.
If adjusting entries are not prepared, some income, expense, asset, and liability accounts may not reflect their true values when reported in the financial statements. For this reason, adjusting entries are necessary.
BELOW are the types of journal entires.
Generally, there are 4 types of adjusting entries. Adjusting entries are prepared for the following:
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Budget Martin Corporation granted a nonqualified stock option to e.docx
Budget
Solution
Answer:
Caroline must recognise the following incomes:
1. Long term capital gain of $50,000 as she sold the stock one year later at a price of $300 per share , while she exercised the stoock at a price of $250 per share. [(1000 shares*300)-(1000shares*250)]
2. And Oridinary Income of $100,000 as she exercised the option at the rate of $250 per share while the stok was granted at the rate of $150.[(1000shares*250)-(1000 shares*150)]
.
Calculate fost of goods sold and ending inventory and analyze effect o (1).docx
Calculate fost of goods sold and ending inventory and analyze effect of each method on financial statements. Jefferson company had the following sales and purchases during 2011, its first year of business:
January 5 Purchased 40 units at $100 each
February 15 Sold 15 units at $150 each
April 10 Sold 10 units at $150 each
June 30 Purchased 30 units at $105 each
August 15 Sold 25 units at $150 each
November 28 Purchased 30 untis at $110 each
Solution
Part A: Record the effect of the following transactions on the accounting equation assuming LIFO perpetual:
Transactions in January, 2011:
Assets
Liabilities
Shareholders
.
Calculate fost of goods sold and ending inventory and analyze effect o.docx
Calculate fost of goods sold and ending inventory and analyze effect of each method on financial statements. Jefferson company had the following sales and purchases during 2011, its first year of business:
January 5 Purchased 40 units at $100 each
February 15 Sold 15 units at $150 each
April 10 Sold 10 units at $150 each
June 30 Purchased 30 units at $105 each
August 15 Sold 25 units at $150 each
November 28 Purchased 30 untis at $110 each
Solution
Part A: Record the effect of the following transactions on the accounting equation assuming LIFO perpetual:
Transactions in January, 2011:
Assets
Liabilities
Shareholders
.
Ca(OH)2 is insoluble- What is the total concentration of ions if 2M of.docx
Ca(OH)2 is insoluble. What is the total concentration of ions if 2M of Ca(OH)2 dissolves in water.
Ca(OH)2 is insoluble. What is the total concentration of ions if 2M of Ca(OH)2 dissolves in water.
Solution
Ca(OH)2 is partially soluble in water and we can find solubility based on solubility product
Ca(OH)2 (s) <-----> Ca2+ (aq) + 2OH- (aq)
at equilibrium [Ca2+] = S , [OH-] = 2S
Ksp = [Ca2+] [OH-]^2 ( where Ksp is solubility product of Ca(OH)2 in water)
5.5 x 10^ -6 = (S) (2S)^2
S = 0.0111 M
Thus [Ca2+] = 0.0111 , [OH-] = 2 x 0.0111 = 0.0222 M
Total concetrations of ions = [Ca2+] + 2 [OH-] = ( 0.0111) + 2 ( 0.0222) = 0.0555 M
.
c- Since BEEF hooks to Metasploit- is there any safe way to use the we.docx
c. Since BEEF hooks to Metasploit, is there any safe way to use the web today? Explain.
Solution
a.) The safe way of using web is by implementing firewalls,secure virtual private networks and antivirus.
b.) Implementing the firewalls is an imperative solution for all organizations to protect their sensitive data fro getting lost.Firewall keeps everything secure from the possible attacks.This is done by analysing the data that gets transmitted back and forth in the network.
c.) Implementation is possible through the following steps
- defining the security needs to finf out the level of security necessary.
- researching soutions to match the specified needs
- and finally installing,configuring and maintaining the firewalls.
d.) Virtual private network as the name itself suggest extends a private network across the public network of internet.I tprovides functionality,network management and security benefits to the user.
e.) The antivirus helps in preventing,detecting and removing the malicious software.I tprovides protection from various computer threats phishing attacks,online identity attacks,malicious URL\'s and etc.
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9- Fill in the following table with names or formulas- as appropriate-.docx
9. Fill in the following table with names or formulas, as appropriate: Names silver sulfate hydrocyanic acid gold(III) chlorite perbromic acid calcium phosphide mercury(I) nitrate sulfurous acid aluminum chromate tin(IV) carbonate oxalic acid Formulas Fe(HC03)2 HNO2(aq (NH4)3BO3 Li2Cr20, Hl(aq)
Solution
silver sulfate = Ag2So4
hydrocyanic acid = HCN
gold(III) chlorite = Au(Clo2)3
perbromic acid = Hbro4
calcium phosphide = ca3p2
mercury(I)nitrate = hg2(no3)2
sulfurous acid = H2So3
aluminum chromate = Al2(cro4)3
tin(iv)carbonate = sn(co3)2
oxalic acid = (cooh)2
iron(ii)hydrogen carbonate = Fe(hco3)2
aqueous nitrous acid =HNo2(aq)
ammonium borate = (NH4)3Bo3
lithium dichromate = Li2Cr2o7
aqueous hydro iodic acid = HI(aq)
the above names based on the type of elements or substituents
attached to the compounds
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Solution
9) Salt, sand and water mixture contains two different phases. liquid phase and solid phase.
and moreover they dont mix and form separate phases.
So, this is example of heterogeneous mixture. (B)
10)
Balance the reaction :
C 3 H 4 O2 + O 2 -----------> CO 2 + H 2 O
balance the reaction for Carbon ,
C 3 H 4 O2 + O 2 -----------> 3 CO 2 + H 2 O
balance the reaction for hydrogen,
C 3 H 4 O2 + O 2 -----------> 3 CO 2 + 2 H 2 O
now balance the reaction for oxygen,
C 3 H 4 O2 + 3 O 2 -----------> 3 CO 2 + 2 H 2 O
So, the answer is 3 and option is none of the above.
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8-6- Which of the highlighted elements in Figure P8-6 has the greatest.docx
8.6. Which of the highlighted elements in Figure P8.6 has the greatest electronegativity? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 FIGURE P8.6
Solution
Electronegativity is a chemical property of an atom that describes how well the atom withdraws shared pair of electrons towards it. It is measured in terms of Pauling Scale from   0 to 4.
The higher the value, the more the electronegativity of the atom.
The highlighted element 17 (Fluorine, F) has the highest electronegativity value is 3.98 .
The highlighted element 1 (Lithium, Li) has the highest electronegativity value is 0.98.
The highlighted element 2 (Beryllium, Be) has the highest electronegativity value is 1.57.
The highlighted element 13 (Boron, B) has the highest electronegativity value is 2.04.
The highlighted element 14 (Carbon, C) has the highest electronegativity value is 2.55.
The highlighted element 15 (Nitrogen, N) has the highest electronegativity value is 3.04.
The highlighted element 16 (Oxygen, O) has the highest electronegativity value is 3.44.
The highlighted element 18 (Neon, Ne) has the highest electronegativity value is 0.
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870 The plates of a capacitor are not quite parallel- the distance bet.docx
870 The plates of a capacitor are not quite parallel, the distance between them at the bottom being (D a) and at the top (Dta), where a
Solution
let length of each plate be L and width be W.
then area A=L*W
at a distance x from the bottom end of the plate, distance between the plates as a function of x is given as
d=D-a+(2*a/L)*x
consider a small segment of length dx at a distance of x from the bottom end
area of the segment=W*dx
distance between the two plates=d=(D-a+(2*a/L)*x)
then capacitance=dC=epsilon*area/distance between plates
=epsilon*W*dx/(D-a+(2*a/L)*x)
let D-a+(2*a/L)*x=y
==>(2*a/L)*dx=dy
==>dx=L*dy/(2*a)
substituting,
dC=epsilon*W*L*dy/(2*a*y)
integrating both sides,
C=(epsilon*W*L/(2*a))*ln(y)
as y varies from D-a to D+a
C=(epsilon*W*L/(2*a))*ln((D+a)/(D-a))
as A=W*L
and ln((D+a)/(D-a))
=ln((1+(a/D))/(1-(a/D)))
=2*(a/D)*(1+(a^2/(3*D^2)))
then C=(epslion*A/(2*a))*(2*a/D)*(1+(a^2/(3*D^2)))
=(epsilon*A/D)*(1+(a^2/(3*D^2)))
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8- What are concurrency design patterns- Explain-Solution8) we have fi.docx
8. What are concurrency design patterns? Explain.
Solution
8)
we have five concurrency design patterns:
-------------------------------------------------
First pattern is Active object design pattern . This pattern decouples method invocation. This is to enhance
concurrency and simplify synchronized access to objects that reside in their own threads of control.
Second pattern is Monitor pattern which synchronizes concurrent method execution to ensure that only one
method at a time runs within an object. It allows obkect methods to schedule their execution sequence.
Third pattern is haof sync / half async pattern which decouples synchrounous and synchronous processing in
concurrent systems, so that it will simplify programmming without reducing performance undudly.
Fourth pattern is Leader pattern which provides concurrency model where multiple threads take turns to share
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event sources.
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access point to retrieve an object that is local to a thread, without uncurring locking overload on each access
to the object.
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8- Calculate the distance from the donor (D) to the acceptor (A) in th.docx
8. Calculate the distance from the donor (D) to the acceptor (A) in the protein represented. Assume that there is a single D-A distance, and that diffusion does not occur during the donor excited-state lifetime. Given:
A.The F DA /F D ratio is 0.50 (that is, the ratio between the fluorescence intensity of the donor in the presence of the acceptor (F DA ) and the fluorescence of the respective control molecule which lacks the acceptor (F D )).
B.The spectral overlap integral  ( J (l)) for this donor-acceptor pair is 4.5 x 10 13 M -1 cm -1 nm 4 .
C.The refractive index of the solution is 1.4.
D.The fluorescence quantum yield of the donor in the absence of acceptor is 0.3.
Solution
Fret E = 1- FDA/FD
E = 1-0.50
= 0.50
Rn = R0 (n(1-E)/E)1/6
Rn is the distance between A and D
E = 0.5
R0 = 4.5 X 1013 unit
Hence Rn = 4.5 X 1013 X 1.4 (1-0.5/0.5)1/6
=4.5 X 1013 X (1.4)1/6
= 4.5 X 1013 X 8.4
= 38291.4 angstrom
N = 1.4
.
7- You want to create an SSIS package that copies data from a source t.docx
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Solution
SQL Server Integration Services ( SSIS ) is a component of the Microsoft SQL Server database software that can be used to perform a broad range of data migration tasks.
SSIS is a platform for data integration and workflow applications. It features a fast and flexible data warehousing tool used for dataextraction, transformation, and loading (ETL). The tool may also be used to automate maintenance of SQL Server databases and updates to multidimensional cube data.
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The interface design issues are:
There are four interface design issues they are
1) Access and short cut keys 2) Bit maps and Icons 3) UI controls 4) Messages.
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Bitmaps and Icons: These functionality dont use in text when working with bit maps and icons consider of following rules. Bit maps which are not international standards avoid using them. And we need to check whether the Access key and short cut key are there are not. Limitation of this functionality is ude function keys and numbers instead of letters in short cut keys.
UI controls: There are so many UI controls like buttons, List boxes, Combo boxes etc.,These are the building blocks of dailogue boxes.
- Hiding a control behind another control is not the correct way to locate it. It will happen due to language expansion.
- By using controls as part os scentences the sentences suffer the same problem as concatenation strings.
Messages: Text strings are usually larger than english text strings in other languages. The growth rate which is acute in short strings become less of a problem as string length increases.
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Introduction to Quality Improvement Essentials
This is a presentation by Dada Robert in a Your Skill Boost masterclass organised by the Excellence Foundation for South Sudan (EFSS) on Saturday, the 25th and Sunday, the 26th of May 2024.
He discussed the concept of quality improvement, emphasizing its applicability to various aspects of life, including personal, project, and program improvements. He defined quality as doing the right thing at the right time in the right way to achieve the best possible results and discussed the concept of the "gap" between what we know and what we do, and how this gap represents the areas we need to improve. He explained the scientific approach to quality improvement, which involves systematic performance analysis, testing and learning, and implementing change ideas. He also highlighted the importance of client focus and a team approach to quality improvement.
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c++ 1- Create lines necessary to open a file named name-txt and store.docx
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