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P= Principal
N= Number of years
R= Rate of interest
Amount= Principal+Simple Interest
S.I = Pni
i= r/100
Amount= P+Pni or P (1+ni)
Simple Interest (SI)
1. What is the simple interest earned from the
principal of Rs.6000 at 15%interest p.a in 2
years?
Given:
Principal= Rs.6000
N= 2 years
R= 15%
Simple interest= PNR/100
 6000*2*15/100
 Rs.1800
Amount= Principal + SI
 6000 + 1800
 Rs. 7800
2. Find the amount and simple interest for
Rs.5000 10% p.a for 3 years?
Given:
Principals = Rs.5000
Rate = 10% pa
N =3 years
Simple interest= PNR/100
 5000*3*10/100
 Rs.1500
Amount= Principal + SI
 5000 + 1500
 Rs. 6500
3. Calculate the total interest on Rs.500 for73
days, Rs.720 for 14 weeks and Rs.900 for 3
months at 6 %.
Given:
(i) Principal = Rs.500, n= 73/365, r= 6/100
(ii) Principal = Rs.720, n= 14/52, r= 6/100
(iii) Principal = Rs.900, n= 3/12, r= 6/100
Solution:
(i)S.I=PNR/100(500*6*73)/(100*365) Rs.6
(ii)S.I=PNR/100(720*6*14)/(100*52)
Rs.11.63
(i)S.I=PNR/100(900*6*3)/(100*12)
Rs.13.5
Total interest= rs.( 6+11.63+ 13.5)
Rs.31.13
4. Find the principal sum which yields simple
interest of rs.77 in 8 years at 3.5% pa?
Given
Principal = ?
R = 3.5%
N = 8 years
S.I = Rs.77
S.I = PNR/100
77 = P * 3.5 * 8/ 100
77*100 = 3.5 * 8 * P
7700 = 28 * P
P = 7700/28
Principal = Rs.275
5. What sum of money invested at 10%pa in
Simple interest will amount to Rs.1200 in 2 years?
Given:
Principal = ?
R = 10%
N = 2 years
Amount = Rs.1200
A= P (1+ni)
1200= P (1+ 10*2/100)
1200 = P (6/5)
P = 1200 * 5 / 6
Principal = Rs.1000
6. Find the period of which a sum of Rs.1200 will
amount to rs.1700 at 12%pa ?
Given:
Principal = Rs.1200
R = 12%
N = ?
Amount = Rs.1700
S.I = Amount- Principal
 1700-1200
 Rs. 500
S.I = PNR/100
500= (1200 *12* N)/100
500*100 = 1200*12*N
N = 500*100/1200*12
N = 500/12* 12
N = 3.47 years
7. Find the rate of interest p.a if the Simple
interest on a principal of Rs.5000 is Rs.800 for 4
years.
Given
Principal = Rs.5000
R = ?
N = 4 years
S.I = Rs.800
S.I = PNR/100
800 = 5000 * 4 * R / 100
800 * 100 = 20000 * R
80000 = 20000 * R
R = 80000/20000
R = 4 %
8. What time will a sum of money double itself at
10%pa in Simple interest.
Solution:
Let Principal be Rs.100
Amount double of principal Rs.200
S.I  Amount – Principal
= 200-100  Rs.100
R = 10%
N = ?
S.I = PNR/100
100 = 100 * N * 10 /100
10N = 100
N = 100/10
Number of years = 10years
9. What time will a sum of money triple itself at
10%pa in Simple interest.
Solution:
Let Principal be Rs.100
Amount triple of principal Rs.300
S.I  Amount – Principal
= 300-100  Rs.200
R = 10%
N = ?
S.I = PNR/100
200 = 100 * N * 10 /100
10N = 200
N = 200/10
Number of years = 20 years
10. A sum of money amounted to Rs.1,071 in 6 months
and Rs.1,106 in 16 months, calculate the rate of Simple
Interest.
Solution:
Amount = Rs.1,1071 in 6 months
Rs.1,106 in 16 months
A= P (1+ni)
1071 = P ( 1+(6/12)i)
1106 = P ( 1+(16/12)i)
1071 * 12 = P (12 + 6i)  12852 =P (12 + 6i)–(1)
 P = 12852/(12 +6i)
1106 * 12 = P(12 + 16i)13272 =P(12 + 16i) - (2)
P = 12852/(12 +6i) substitute in (1)
i= 5040/126000
i = 0.04
R= 0.04*100
R=4%
Compound Interest
1. Find the compound interest, if the principal
Rs.6000, rate of interest is 10% pa in 3 years.
Solution
2. Find the number of years in which a sum of
money will double it self at 4% pa in compound
interest.
Solution
3. The difference between SI and CI is Rs,121.
number of years is 5 and the rate of interest is
8%. Find out the Sum?
Solution
4. What rate of interest is denoted by 6% pa,
payable quarterly? - Effective rate of interest
Business Mathematics
Business Mathematics

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Business Mathematics

  • 1.
  • 2. P= Principal N= Number of years R= Rate of interest Amount= Principal+Simple Interest S.I = Pni i= r/100 Amount= P+Pni or P (1+ni) Simple Interest (SI)
  • 3. 1. What is the simple interest earned from the principal of Rs.6000 at 15%interest p.a in 2 years? Given: Principal= Rs.6000 N= 2 years R= 15% Simple interest= PNR/100  6000*2*15/100  Rs.1800 Amount= Principal + SI  6000 + 1800  Rs. 7800
  • 4. 2. Find the amount and simple interest for Rs.5000 10% p.a for 3 years? Given: Principals = Rs.5000 Rate = 10% pa N =3 years Simple interest= PNR/100  5000*3*10/100  Rs.1500 Amount= Principal + SI  5000 + 1500  Rs. 6500
  • 5. 3. Calculate the total interest on Rs.500 for73 days, Rs.720 for 14 weeks and Rs.900 for 3 months at 6 %. Given: (i) Principal = Rs.500, n= 73/365, r= 6/100 (ii) Principal = Rs.720, n= 14/52, r= 6/100 (iii) Principal = Rs.900, n= 3/12, r= 6/100 Solution: (i)S.I=PNR/100(500*6*73)/(100*365) Rs.6 (ii)S.I=PNR/100(720*6*14)/(100*52) Rs.11.63 (i)S.I=PNR/100(900*6*3)/(100*12) Rs.13.5 Total interest= rs.( 6+11.63+ 13.5) Rs.31.13
  • 6. 4. Find the principal sum which yields simple interest of rs.77 in 8 years at 3.5% pa? Given Principal = ? R = 3.5% N = 8 years S.I = Rs.77 S.I = PNR/100 77 = P * 3.5 * 8/ 100 77*100 = 3.5 * 8 * P 7700 = 28 * P P = 7700/28 Principal = Rs.275
  • 7. 5. What sum of money invested at 10%pa in Simple interest will amount to Rs.1200 in 2 years? Given: Principal = ? R = 10% N = 2 years Amount = Rs.1200 A= P (1+ni) 1200= P (1+ 10*2/100) 1200 = P (6/5) P = 1200 * 5 / 6 Principal = Rs.1000
  • 8. 6. Find the period of which a sum of Rs.1200 will amount to rs.1700 at 12%pa ? Given: Principal = Rs.1200 R = 12% N = ? Amount = Rs.1700 S.I = Amount- Principal  1700-1200  Rs. 500 S.I = PNR/100 500= (1200 *12* N)/100 500*100 = 1200*12*N N = 500*100/1200*12 N = 500/12* 12 N = 3.47 years
  • 9. 7. Find the rate of interest p.a if the Simple interest on a principal of Rs.5000 is Rs.800 for 4 years. Given Principal = Rs.5000 R = ? N = 4 years S.I = Rs.800 S.I = PNR/100 800 = 5000 * 4 * R / 100 800 * 100 = 20000 * R 80000 = 20000 * R R = 80000/20000 R = 4 %
  • 10. 8. What time will a sum of money double itself at 10%pa in Simple interest. Solution: Let Principal be Rs.100 Amount double of principal Rs.200 S.I  Amount – Principal = 200-100  Rs.100 R = 10% N = ? S.I = PNR/100 100 = 100 * N * 10 /100 10N = 100 N = 100/10 Number of years = 10years
  • 11. 9. What time will a sum of money triple itself at 10%pa in Simple interest. Solution: Let Principal be Rs.100 Amount triple of principal Rs.300 S.I  Amount – Principal = 300-100  Rs.200 R = 10% N = ? S.I = PNR/100 200 = 100 * N * 10 /100 10N = 200 N = 200/10 Number of years = 20 years
  • 12. 10. A sum of money amounted to Rs.1,071 in 6 months and Rs.1,106 in 16 months, calculate the rate of Simple Interest. Solution: Amount = Rs.1,1071 in 6 months Rs.1,106 in 16 months A= P (1+ni) 1071 = P ( 1+(6/12)i) 1106 = P ( 1+(16/12)i) 1071 * 12 = P (12 + 6i)  12852 =P (12 + 6i)–(1)  P = 12852/(12 +6i) 1106 * 12 = P(12 + 16i)13272 =P(12 + 16i) - (2) P = 12852/(12 +6i) substitute in (1) i= 5040/126000 i = 0.04 R= 0.04*100 R=4%
  • 14. 1. Find the compound interest, if the principal Rs.6000, rate of interest is 10% pa in 3 years. Solution
  • 15. 2. Find the number of years in which a sum of money will double it self at 4% pa in compound interest. Solution
  • 16. 3. The difference between SI and CI is Rs,121. number of years is 5 and the rate of interest is 8%. Find out the Sum? Solution
  • 17. 4. What rate of interest is denoted by 6% pa, payable quarterly? - Effective rate of interest