Answer should be in MIPS please Please ensure you are follo.pdf
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Answer should be in MIPS please! Please ensure you are following the directions. Thank you in advanced! Your program should be able to take one integer values from user input until you enter 0 and program should end if user types in an integer 0. (The prompt should be Enter an integer: ) - Store the integer into $t5 and multiply the number by 8 using shift operations (Do not use multiplication). And then print the values of bit number 6 to 10 of $t5. (The rightmost bit is bit 0) - You need give detail comments to explain what is happening in the code. The level of detail will be graded. - You need to show the result screens for at least five pairs of numbers including negative numbers. - You need to use the newlines spaces properly so that the output prints in orderly manner. Your output should look like: The number you entered: After it is multiplied by 8: The bits [6-10] are: (there should be one space between each bit value) Please Note: The program first receives user input (integer) and stores it in $t0. Print the entered number (decimal value) Multiply the number in $t0 and print the number (decimal value) Print the value of Bit #6, 7, 8, 9, and 10 of $t5. (The output should look like: 0 1 1 0 0 ).
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![Answer should be in MIPS please! Please ensure you are following the directions. Thank you in
advanced!
Your program should be able to take one integer values from user input until you enter 0 and
program should end if user types in an integer 0.
(The prompt should be Enter an integer: )
- Store the integer into $t5 and multiply the number by 8 using shift operations (Do not use
multiplication). And then print the values of bit number 6 to 10 of $t5. (The rightmost bit is bit 0)
- You need give detail comments to explain what is happening in the code. The level of detail will
be graded.
- You need to show the result screens for at least five pairs of numbers including negative
numbers.
- You need to use the newlines spaces properly so that the output prints in orderly manner. Your
output should look like:
The number you entered:
After it is multiplied by 8:
The bits [6-10] are: (there should be one space between each bit value)
Please Note:
The program first receives user input (integer) and stores it in $t0.
Print the entered number (decimal value)
Multiply the number in $t0 and print the number (decimal value)
Print the value of Bit #6, 7, 8, 9, and 10 of $t5. (The output should look like: 0 1 1 0 0 )](https://image.slidesharecdn.com/answershouldbeinmipspleasepleaseensureyouarefollo-230318101936-b74c8032/85/Answer-should-be-in-MIPS-please-Please-ensure-you-are-follo-pdf-1-320.jpg)
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Required:
1. Prepare the entries to record the preceding transactions in Heritages books..
Given a scenario where an farmer agent walks around a meadow.pdf
Given a scenario where an farmer agent walks around a meadow that is randomly generated with
a farmer, horse, pig, chicken and various obstacles like trees and boulders. does the following
scripts look okay? If not what may i need to change?
farmeragent.cs using System.Collections; using System.Collections.Generic; using UnityEngine;
using UnityEngine.AI; using Unity.MLAgents; using Unity.MLAgents.Actuators; using
Unity.MLAgents.Sensors; public class FarmerAgent : Agent { public GameObject horse; public
GameObject pig; public GameObject chicken; public GameObject foodPrefab; public Transform
foodDropPoint; public NavMeshAgent navMeshAgent; private bool isHorseFed; private bool
isPigFed; private bool isChickenFed; private List<GameObject> foodObjects = new
List<GameObject>(); private void Start() { navMeshAgent = GetComponent<NavMeshAgent>(); }
public override void OnEpisodeBegin() { isHorseFed = false; isPigFed = false; isChickenFed =
false; // Reset animal hunger horse.GetComponent<AnimalAgent>().isFed = false;
pig.GetComponent<AnimalAgent>().isFed = false; chicken.GetComponent<AnimalAgent>().isFed
= false; // Destroy all food objects foreach (GameObject foodObject in foodObjects) {
Destroy(foodObject); } // Spawn new food objects for (int i = 0; i < 3; i++) { Vector3 randomPosition
= new Vector3(Random.Range(-5f, 5f), 0f, Random.Range(-5f, 5f)); GameObject foodObject =
Instantiate(foodPrefab, randomPosition + foodDropPoint.position, Quaternion.identity);
foodObjects.Add(foodObject); } // Move farmer to random position Vector3 farmerPosition = new
Vector3(Random.Range(-4f, 4f), 0f, Random.Range(-4f, 4f));
navMeshAgent.Warp(farmerPosition); } public override void CollectObservations(VectorSensor
sensor) { // Is each animal fed? sensor.AddObservation(isHorseFed);
sensor.AddObservation(isPigFed); sensor.AddObservation(isChickenFed); } public override void
OnActionReceived(ActionBuffers actions) { Vector3 position = transform.position; Vector3 forward
= transform.forward; float moveSpeed = 0f; float turnSpeed = 0f; int action =
actions.DiscreteActions[0]; switch (action) { case 0: // Move forward moveSpeed = 1f; break; case
1: // Move backward moveSpeed = -1f; break; case 2: // Turn left turnSpeed = -1f; break; case 3: //
Turn right turnSpeed = 1f; break; case 4: // Drop apple for horse DropFood(horse,
FoodType.Apple); break; case 5: // Drop truffle for pig DropFood(pig, FoodType.Truffle); break;
case 6: // Drop corn for chicken DropFood(chicken, FoodType.Corn); break; default: break; } //
Apply movement and rotation transform.Translate(moveSpeed * Time.deltaTime *
transform.forward, Space.World); transform.Rotate(0f, turnSpeed * Time.deltaTime * 100f, 0f); //
Update perception sensors horseSensor.UpdateSensor(); pigSensor.UpdateSensor();
chickenSensor.UpdateSensor(); } private void DropFood(GameObject animal, FoodType
foodType) { if (animal == null) { return; } Vector3 dropPosition = animal.transform.position +
Vector3.up; GameObject foodObject.
Bonita Corporation issued 700 shares of nopar common stock .pdf
Bonita Corporation issued 700 shares of no-par common stock for $7,800. Prepare Bonita's
journal entry if (a) the stock has no stated value, and (b) the stock has a stated value of $2 per
share. (List all debit entries before credit entries. Credit account titles are automatically indented
when the amount is entered. Do not indent manually. If no entry is required, select "No Entry" for
the account titles and enter O for the amounts.).
Dozier Corporation is a fastgrowing supplier of office prod.pdf
Dozier Corporation is a fast-growing supplier of office products. Analysts project the following free
cash flows during the next 3 years, after which FCF is expected to grow at a constant 7.40% rate.
Dozier's WACC is 11.40%.
Year
0
1
2
3
FCF ($ millions)
10
20
30
a. What is Dozier's horizon, or continuing, value?
b. What is the firm's value today?
c. Suppose Dozier has $200 million of debt and 100 million shares of stock outstanding. What is
your estimate of the current price per share?
Year 0 1 2 3
FCF ($ millions) 10 20 30.
1 Huntington disease HD is a genetic disorder caused by a.pdf
1. Huntington disease (HD) is a genetic disorder caused by a dominant allele-we will call it H-that
is located on an autosome. What are the chances that parents with the following genotypes will
have a child with HD?
Aa X Aa ll. aa X Aa III. AA X aa IV. Aa X AA
Hemophilia is a genetic disease (HD) is a genetic disorder caused by a recessive allele-we will call
it h-that is located on the X chromosome. What are the chances that parents with the following
genotypes will have a child with hemophilia?
1. XAxA x Xay
II. XAya x Xay Ill. XAXa x XAy IV. Xaya x XAy
3. Study the pedigree shown below. Is the disorder allele dominant or recessive? Is the disorder
allele located on an autosome or on the X chromosome? What are the genotypes of the
individuals 1 in and 2 in generation I?
A Hacked
In humans one of the genes determining color vision is located on the X chromosome. The
dominant form (C) produces a normal color vision; red-green deficiency (c) is recessive. If a man
with normal color vision marries a color-deficient woman, what are the probability of them having a
color-blind son? A colorblind daughter?
If the phenotype of a heterozygous is intermediate between the phenotypes of the two
homozygous, this pattern of inheritance is called
If the heterozygous expresses of both homozygous and
heterozygous(not intermediate, but showing both traits), this called
. In many genes, usually with similar effects, on a phenotype, control the inheritance of a trait..
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sensor) { // Is each animal fed? sensor.AddObservation(isHorseFed);
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transform.forward, Space.World); transform.Rotate(0f, turnSpeed * Time.deltaTime * 100f, 0f); //
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