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Dr. Anand Bhabhor
Senior Intensivist
Jaslok Hospital & Research Centre
413746
Range For calculation
pH 7.35 – 7.45 7.4
PaCO2 35 – 45 mmHg 40 mmHg
PaO2 > 80 mmHg > 95 mmHg
HCO3- 22 – 26 mEq/L 24 mEq/L
 PaO2 and SaO2
PaO2 / FiO2 ratio
 Normal = 300 – 500 mmHg
 < 300 = acute lung injury [previous definition]
 < 200 = ARDS [previous definition]
Berlin definition:
 200 – 300 [with PEEP/CPAP > 5] = mild ARDS
 < 200 [with PEEP > 5] = moderate ARDS
 <100 [with PEEP > 5] = severe ARDS
 Step 1: Acidemic, alkalemic, or normal?
 Step 2: Is the primary disturbance respiratory or metabolic?
 Step 3: For a primary respiratory disturbance, is it acute or chronic?
 Step 4: For a metabolic disturbance, is the respiratory system
compensating OK?
 Step 5: For a metabolic acidosis, is there an increased anion gap?
 Step 6: For an increased anion gap metabolic acidosis, are there other
derangements?
 The hydrogen ion concentration [H+] in extracellular fluid
is determined by the balance between the PaCO2 and
HCO3- in the fluid.
 The pH is the –log [H]. So by altering either the PCO2 or
the HCO3-, [H] will change, and so will pH.
 An acidemia(low pH) can result from either a low HCO3-
or a high CO2
 An alkalemia (high pH) can result from either a high HCO3
or a low CO2
 If pH and PaCO2 changes in same direction, the
primary disorder is metabolic and if they change in
opposite direction ,the primary disorder is respiratory.
Chemical change Primary disorder pH
Low HCO3- Metabolic acidosis low pH
High HCO3- Metabolic
alkalosis
High pH
High PaCO2 Respiratory
acidosis
Low pH
Low PaCO2 Respiratory
alkalosis
High pH
 Respiratory acidosis is due to a primary rise in CO2
 Hypercapnia almost always results from alveolar
hypoventilation due to one of the following causes:
1. Respiratory center depression
2. Neuromuscular disorder
3. Upper airway obstruction
4. Pulmonary disease
 A respiratory alkalosis is due to decrease in PaCO2.
 It results from hyperventilation leading to decrease in
CO2.
 Causes of respiratory alkalosis:
1. Hypoxemia from any causes
2. Respiratory center stimulation
3. Mechanical hyperventilation
4. Sepsis, pain
 Normal pH is 7.4
 Calculate the change in pH (from 7.4)
A. in acute respiratory disorder (acidosis / alkalosis)
change in pH = 0.008 X [PaCO2 -40]
expected pH = 7.4 +/-change in pH
B. in chronic respiratory disorder (acidosis/alkalosis)
change in pH = 0.003 X [PaCO2 -40 ]
expected pH = 7.4 +/- change in pH
Compare the pH on ABG
if pH on ABG is close to A, it is acute disorder
if pH on ABG is close to B, it is chronic disorder
 M/60 yrs, k/c/o C.O.P.D. admitted with U.T.I.
 ABG: 7.26 / 84 / 74 / 37 / 94%
 [A]. For Acute change in pH;
change in pH = 0.008 X [84 – 40 ] =0.008 X [44] =0.35
Expected pH = 7.4 – 0.35 = 7.05
 [B]. For chronic change in pH’
Change in pH = 0.003 X [84 – 40 ] = 0.003 X [44] = 0.13
Expected pH =7.4 -0.13 = 7.27
So B is near to the patient’s ABG which is 7.26; so primary disorder
is chronic respiratory acidosis.
Primary
disorder
Initial
chemic
al
change
s
Compens
a-tory
response
Compensa
-
tory
mechanis
m
Expected level of compensa-
tion
Respiratory
acidosis
↑PCO2 ↑HCO3-
Acute Buffering-
rule of 1
↑[HCO3-] = 1 mEq/L for every
10 mmHg delta PCO2
Chronic Generation
of new
HCO3 –
rule of 3
[HCO-] = 3 mEq/L for every
10mmHg delta PCO2
Primary
disorder
Initial
chemic
al
change
s
Compen
sa-tory
respons
e
Compensa-
tory
mechanism
Expected level of
compensa-
tion
Respiratory
alkalosis
↓PCO2 ↓HCO3-
Acute buffering- rule
of 2
↓[HCO-] = 2 mEq/L for
every 10 mmHg delta PCO2
chronic Decreased
reabsorption
of HCO3- rule
or 4
↓[HCO3-] = 4 mEq/L for every
10 mmHg delta PCO2
 Metabolic acidosis results from a primary decrease in
plasma [HCO3-]
 Check the respiratory compensation by winter’s
formula:
Primary
disorder
Initial
chemica
l
changes
Compens
a-tory
response
Compensa-
tory
mechanism
Expected level of
compensa-
tion
Metabolic
acidosis
↓HCO3- ↓PCO2 Hyperventila-
tion
PCO2 = 1.5 X [HCO3-]+
8 +/-2
Metabolic
alkalosis
↑HCO3- ↑PCO2 Hypoventilation PCO2 = 0.7 X [HCO3] +
21+/- 2
 7.23 / 34 /88 /17 [ metabolic acidosis]
 Winter ‘s formula:
 Expected PaCO2 = 1.5 X [HCO3-] + 8 +/- 2
= 1.5 X [17] + 8 +/ -2
= 33.5 + / -2 = 31.5 – 35.5 mmHg
 7.45 / 43 / 95 / 30 [ metabolic alkalosis]
 Winter ‘s formula:
 Expected PaCO2= 0.7 X [HCO3-] + 21 + / - 2
= 0.7 X [30] + 21 + / - 2
=42 + / -2 = 40 – 44 mmHg
 Metabolic alkalosis reflects an increase in plasma
[HCO3-]
 It can be classified into saline responsive or
nonresponsive.
 More than 20 mEq/L urinary chloride is saline
unresponsive and less than 20 mEq/L is saline
responsive.
Causes of Urine CL > 20 mEq/L Causes of Urine CL < 20 mEq/L
Mineralocorticoid excess Vomiting, nasogastric suctioning
K + and Mg ++ deficiency chloride-wasting diarrhea
Liddle’s syndrome Villous adenoma of colon
Barter’s syndrome Posthypercapnia
Hypercalcemia with secondary
hyperparathyroidism
Poorly reabsorbed anions like
carbenicillin
Milk – alkali syndrome Diuretic therapy
 A1 : calculate AG in case of metabolic acidosis
 High denotes raised AG metabolic acidosis, and
normal or narrow denotes non-AG acidosis.
Unmeasured Anions Unmeasured Cation
Albumin: 15 mEq/L Calcium: 5 mEq/L
Organic Acids: 5 mEq/L Potassium: 4.5 mEq/L
Phosphate: 2 mEq/L Magnesium: 1.5 mEq/L
Sulfate: 1 mEq/L
Total UA: 23 mEq/L Total UC: 11 mEq/L
Anion AG = UA – UC = 12 mEq/L
Adjusted AG = calculated AG + 2.5 X [4 – S.albumin gm%]
 It is used to determine if a metabolic acidosis is due to
an accumulation of non- volatile acids [e.g. lactic
acidosis] or a net loss of bicarbonate [e.g. diarrhea]
 Na + UC = [ Cl + HCO3 ] + UA
 UA – UC [ Anion gap] = Na –[ Cl + HCO3- ]
 AG= Na –[Cl + HCO3]; normal AG is 12+/-2 mEq/L
 7.23 / 34 /88 /17 : Metabolic Acidosis
 Na : 135 / Cl: 99 / K: 3.5
 AG = Na - [ Cl + HCO3-] = 135 – [ 99 + 17] = 19
 High AG
Pneumonic Causes
M Methanol
U Uremia
D Diabetic ketoacidosis
P Paraldehyde
I Isoniazid / iron
L Lactate
E Ethanol, ethylene glycol
R Rhabdomyolysis / renal failure
S Salicylate / sepsis
Pneumonic Causes
H Hyper alimentation
A Acetazolamide
R Renal tubular acidosis
D Diarrhea
U Uremia (acute)
P Post ventilation hypocapnia
 Check urinary AG in non-AG metabolic acidosis
 U Na + U K – U Cl
 Normal : negative
 Non-renal loss of bicarbonate [diarrhea] : negative
 Renal loss of bicarbonate[ RTA / H+ excretion]
: positive
 In less obvious cases, the coexistence of two metabolic
acid-base disorders may be apparent by calculating the
difference between the change in AG [delta AG] and
the change in serum HCO3- [delta HCO3-].
 This is called the Delta gap or gap –gap.
 Delta gap = delta AG – delta HCO3-
 Where delta AG = patient’s AG – 12 mEq/L
 Delta HCO3- = 24 mEq/L – patient’s HCO3-
 Normally the delta gap is zero :
 AG acidosis
 A positive delta gap of more than 6 mEq/L :
 metabolic alkalosis and/or HCO3- retention.
 The delta gap of less than 6 mEq/L :
 Hypercholremic acidosis and/or HCO3- excretion.
 7.23 / 34 /88 /17 : Metabolic Acidosis
 Na : 138 / Cl: 99 / K: 3.5
 AG = Na - [ Cl + HCO3-] = 138 – [ 99 + 17] = 22
Next step is to calculate the Delta Gap.
 Delta AG = patient’s AG -12 = 22 – 12 = 10
 Delta HCO3- = 24 – patient’s HCO3- = 24 – 17 = 7
 Delta gap = Delta AG- Delta HCO3- = 10 – 7 = 3
 Additional metabolic alkalosis is also present with high AG
metabolic acidosis.
 Step 1: Acidemic, alkalemic, or normal?
 Step 2: Is the primary disturbance respiratory or metabolic?
 Step 3: For a primary respiratory disturbance, is it acute or chronic?
 Step 4: For a metabolic disturbance, is the respiratory system
compensating OK?
 Step 5: For a metabolic acidosis, is there an increased anion gap?
 Step 6: For an increased anion gap metabolic acidosis, are there other
derangements?
 65 years old male with CKD presenting with nausea,
diarrhea and acute respiratory distress
 ABG: 7.23/17/235/7 with 50% FiO2 on V.M.
 Electrolytes: Na: 123 mEq/L, Cl: 97 mEq/L, S.K 3.5
 Renal function: S. Creat: 5.1 mg%, BUN: 119
 Acidemic ?
 Alkalemic ?
 Respiratory / metabolic ?
 ABG: 7.23/17/235/7 with 50% FiO2 on V.M.
 pH and PaCO2 goes in same direction; so it is
primarily metabolic disorder.
 ABG: 7.23/17/235/7 with 50% FiO2 on V.M.
 Winter’s formula:
 Expected PaCO2 = 1.5 X [7] + 8 +/- 2 = 18.5 +/-2
 ABG: 7.23/17/235/7 with 50% FiO2 on V.M.
 Electrolytes: Na: 123 mEq/L, Cl: 97 mEq/L, S.K 3.5
 AG = Na – [Cl +HCO3-] = 123 – [97 + 7] = 19
 High AG metabolic acidosis
 Delta gap = Delta AG – Delta HCO3-
 = [19 - 12 ] – [24 – 7 ]
 = 7 – 7 = 0
 Non –anion gap metabolic acidosis
 High AG metabolic acidosis with non-anion metabolic
acidosis
 High AG metabolic acidosis is due to BUN 119
 Non anion metabolic acidosis is due to diarrhea
 Very sick 56 year old man being evaluated for a
possible double lung transplant
 Dyspnoea on minimal exertion
 On home oxygen therapy
(nasal prongs, 2 lpm)
 Numerous pulmonary medications
 ABG: 7.30/65/88/31.1
 Acidemia ?
 Alkalemia ?
 pH and PaCO2 goes in opposite direction; so primary
disorder is respiratory.
 For Acute disorder;
 Change in pH = 0.008 X [65 – 40 ]=0.2
 Expected pH = 7.40 – 0.2 = 7.20
 For chronic disorder;
 Change n pH= 0.003 X [65 – 40 ] = 0.07
 Expected pH = 7.40 – 0.07 = 7.33
 So its chronic respiratory acidosis.
 delta PaCO2 = 25
 So rise in HCO3- will be by 7.5 mEq/L, which should
be 24 + 7.5 = 31.5 mEq/L
 Which is expected HCO3-
 Primary chronic respiratory acidosis.
 Patient has a long standing pulmonary disease so
bicarbonate is in the compensation.
 A 44 year old moderately dehydrated man was
admitted with a two day history of acute severe
diarrhea.
 ABG: 7.31 / 33 / 88 /16 / 95%
 Elect: Na: 136 mEq/L, Cl: 103 mEq/L, K: 2.9 mEq/L
 Acidemia ?
 Alkalemia ?
 pH and PaCO2 goes in the same direction; so primary
disorder is metabolic.
 Winter’s formula
 Expected PaCO2= 1.5 X [16] + 8 +/ -2
 = 32 -/+ 2 = 30 – 34 mEq/L
 So it is fully compensated metabolic disorder.
 AG = Na – [Cl + HCO3-] = 134 – [104 + 16 ] = 14
 Non AG metabolic acidosis
 Patient lost bicarbonate in diarrhea leading to non
anion gap metabolic acidosis.
 A 38-year-old woman is 12 weeks pregnant. For the last 10
days she has had worsening nausea and vomiting. When
seen by her physician, she is dehydrated and has shallow
respirations. Arterial blood gas data is as follow
 ABG: 7.56/54/110/45
 Acidemia ?
 Alkalemia ?
 pH and PaCO2 goes in same direction so the primary
disorder is metabolic alkalosis.
 Expected PaCO2 = 0.7 X [ HCO3-] + 21 +/- 2
= 0.7 X [ 45 ] + 21 +/ - 2
= 52.5 +/-2
= 50.5 – 54.5
 Metabolic alkalosis
 Patient has lost lot of gastric juice and hydrochloric
acid in vomit leading to metabolic alkalosis.
 Step 1: Acidemic, alkalemic, or normal?
 Step 2: Is the primary disturbance respiratory or metabolic?
 Step 3: For a primary respiratory disturbance, is it acute or chronic?
 Step 4: For a metabolic disturbance, is the respiratory system
compensating OK?
 Step 5: For a metabolic acidosis, is there an increased anion gap?
 Step 6: For an increased anion gap metabolic acidosis, are there other
derangements?
THANK YOU ! !!

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ABG Analysis.pptx

  • 1. Dr. Anand Bhabhor Senior Intensivist Jaslok Hospital & Research Centre 413746
  • 2.
  • 3. Range For calculation pH 7.35 – 7.45 7.4 PaCO2 35 – 45 mmHg 40 mmHg PaO2 > 80 mmHg > 95 mmHg HCO3- 22 – 26 mEq/L 24 mEq/L
  • 4.  PaO2 and SaO2 PaO2 / FiO2 ratio  Normal = 300 – 500 mmHg  < 300 = acute lung injury [previous definition]  < 200 = ARDS [previous definition] Berlin definition:  200 – 300 [with PEEP/CPAP > 5] = mild ARDS  < 200 [with PEEP > 5] = moderate ARDS  <100 [with PEEP > 5] = severe ARDS
  • 5.  Step 1: Acidemic, alkalemic, or normal?  Step 2: Is the primary disturbance respiratory or metabolic?  Step 3: For a primary respiratory disturbance, is it acute or chronic?  Step 4: For a metabolic disturbance, is the respiratory system compensating OK?  Step 5: For a metabolic acidosis, is there an increased anion gap?  Step 6: For an increased anion gap metabolic acidosis, are there other derangements?
  • 6.  The hydrogen ion concentration [H+] in extracellular fluid is determined by the balance between the PaCO2 and HCO3- in the fluid.  The pH is the –log [H]. So by altering either the PCO2 or the HCO3-, [H] will change, and so will pH.  An acidemia(low pH) can result from either a low HCO3- or a high CO2  An alkalemia (high pH) can result from either a high HCO3 or a low CO2
  • 7.  If pH and PaCO2 changes in same direction, the primary disorder is metabolic and if they change in opposite direction ,the primary disorder is respiratory. Chemical change Primary disorder pH Low HCO3- Metabolic acidosis low pH High HCO3- Metabolic alkalosis High pH High PaCO2 Respiratory acidosis Low pH Low PaCO2 Respiratory alkalosis High pH
  • 8.  Respiratory acidosis is due to a primary rise in CO2  Hypercapnia almost always results from alveolar hypoventilation due to one of the following causes: 1. Respiratory center depression 2. Neuromuscular disorder 3. Upper airway obstruction 4. Pulmonary disease
  • 9.  A respiratory alkalosis is due to decrease in PaCO2.  It results from hyperventilation leading to decrease in CO2.  Causes of respiratory alkalosis: 1. Hypoxemia from any causes 2. Respiratory center stimulation 3. Mechanical hyperventilation 4. Sepsis, pain
  • 10.  Normal pH is 7.4  Calculate the change in pH (from 7.4) A. in acute respiratory disorder (acidosis / alkalosis) change in pH = 0.008 X [PaCO2 -40] expected pH = 7.4 +/-change in pH B. in chronic respiratory disorder (acidosis/alkalosis) change in pH = 0.003 X [PaCO2 -40 ] expected pH = 7.4 +/- change in pH Compare the pH on ABG if pH on ABG is close to A, it is acute disorder if pH on ABG is close to B, it is chronic disorder
  • 11.  M/60 yrs, k/c/o C.O.P.D. admitted with U.T.I.  ABG: 7.26 / 84 / 74 / 37 / 94%  [A]. For Acute change in pH; change in pH = 0.008 X [84 – 40 ] =0.008 X [44] =0.35 Expected pH = 7.4 – 0.35 = 7.05  [B]. For chronic change in pH’ Change in pH = 0.003 X [84 – 40 ] = 0.003 X [44] = 0.13 Expected pH =7.4 -0.13 = 7.27 So B is near to the patient’s ABG which is 7.26; so primary disorder is chronic respiratory acidosis.
  • 12. Primary disorder Initial chemic al change s Compens a-tory response Compensa - tory mechanis m Expected level of compensa- tion Respiratory acidosis ↑PCO2 ↑HCO3- Acute Buffering- rule of 1 ↑[HCO3-] = 1 mEq/L for every 10 mmHg delta PCO2 Chronic Generation of new HCO3 – rule of 3 [HCO-] = 3 mEq/L for every 10mmHg delta PCO2
  • 13. Primary disorder Initial chemic al change s Compen sa-tory respons e Compensa- tory mechanism Expected level of compensa- tion Respiratory alkalosis ↓PCO2 ↓HCO3- Acute buffering- rule of 2 ↓[HCO-] = 2 mEq/L for every 10 mmHg delta PCO2 chronic Decreased reabsorption of HCO3- rule or 4 ↓[HCO3-] = 4 mEq/L for every 10 mmHg delta PCO2
  • 14.  Metabolic acidosis results from a primary decrease in plasma [HCO3-]  Check the respiratory compensation by winter’s formula:
  • 15. Primary disorder Initial chemica l changes Compens a-tory response Compensa- tory mechanism Expected level of compensa- tion Metabolic acidosis ↓HCO3- ↓PCO2 Hyperventila- tion PCO2 = 1.5 X [HCO3-]+ 8 +/-2 Metabolic alkalosis ↑HCO3- ↑PCO2 Hypoventilation PCO2 = 0.7 X [HCO3] + 21+/- 2
  • 16.  7.23 / 34 /88 /17 [ metabolic acidosis]  Winter ‘s formula:  Expected PaCO2 = 1.5 X [HCO3-] + 8 +/- 2 = 1.5 X [17] + 8 +/ -2 = 33.5 + / -2 = 31.5 – 35.5 mmHg  7.45 / 43 / 95 / 30 [ metabolic alkalosis]  Winter ‘s formula:  Expected PaCO2= 0.7 X [HCO3-] + 21 + / - 2 = 0.7 X [30] + 21 + / - 2 =42 + / -2 = 40 – 44 mmHg
  • 17.  Metabolic alkalosis reflects an increase in plasma [HCO3-]  It can be classified into saline responsive or nonresponsive.  More than 20 mEq/L urinary chloride is saline unresponsive and less than 20 mEq/L is saline responsive.
  • 18. Causes of Urine CL > 20 mEq/L Causes of Urine CL < 20 mEq/L Mineralocorticoid excess Vomiting, nasogastric suctioning K + and Mg ++ deficiency chloride-wasting diarrhea Liddle’s syndrome Villous adenoma of colon Barter’s syndrome Posthypercapnia Hypercalcemia with secondary hyperparathyroidism Poorly reabsorbed anions like carbenicillin Milk – alkali syndrome Diuretic therapy
  • 19.  A1 : calculate AG in case of metabolic acidosis  High denotes raised AG metabolic acidosis, and normal or narrow denotes non-AG acidosis.
  • 20. Unmeasured Anions Unmeasured Cation Albumin: 15 mEq/L Calcium: 5 mEq/L Organic Acids: 5 mEq/L Potassium: 4.5 mEq/L Phosphate: 2 mEq/L Magnesium: 1.5 mEq/L Sulfate: 1 mEq/L Total UA: 23 mEq/L Total UC: 11 mEq/L Anion AG = UA – UC = 12 mEq/L Adjusted AG = calculated AG + 2.5 X [4 – S.albumin gm%]
  • 21.  It is used to determine if a metabolic acidosis is due to an accumulation of non- volatile acids [e.g. lactic acidosis] or a net loss of bicarbonate [e.g. diarrhea]  Na + UC = [ Cl + HCO3 ] + UA  UA – UC [ Anion gap] = Na –[ Cl + HCO3- ]  AG= Na –[Cl + HCO3]; normal AG is 12+/-2 mEq/L
  • 22.  7.23 / 34 /88 /17 : Metabolic Acidosis  Na : 135 / Cl: 99 / K: 3.5  AG = Na - [ Cl + HCO3-] = 135 – [ 99 + 17] = 19  High AG
  • 23. Pneumonic Causes M Methanol U Uremia D Diabetic ketoacidosis P Paraldehyde I Isoniazid / iron L Lactate E Ethanol, ethylene glycol R Rhabdomyolysis / renal failure S Salicylate / sepsis
  • 24. Pneumonic Causes H Hyper alimentation A Acetazolamide R Renal tubular acidosis D Diarrhea U Uremia (acute) P Post ventilation hypocapnia
  • 25.  Check urinary AG in non-AG metabolic acidosis  U Na + U K – U Cl  Normal : negative  Non-renal loss of bicarbonate [diarrhea] : negative  Renal loss of bicarbonate[ RTA / H+ excretion] : positive
  • 26.  In less obvious cases, the coexistence of two metabolic acid-base disorders may be apparent by calculating the difference between the change in AG [delta AG] and the change in serum HCO3- [delta HCO3-].  This is called the Delta gap or gap –gap.
  • 27.  Delta gap = delta AG – delta HCO3-  Where delta AG = patient’s AG – 12 mEq/L  Delta HCO3- = 24 mEq/L – patient’s HCO3-  Normally the delta gap is zero :  AG acidosis  A positive delta gap of more than 6 mEq/L :  metabolic alkalosis and/or HCO3- retention.  The delta gap of less than 6 mEq/L :  Hypercholremic acidosis and/or HCO3- excretion.
  • 28.  7.23 / 34 /88 /17 : Metabolic Acidosis  Na : 138 / Cl: 99 / K: 3.5  AG = Na - [ Cl + HCO3-] = 138 – [ 99 + 17] = 22 Next step is to calculate the Delta Gap.  Delta AG = patient’s AG -12 = 22 – 12 = 10  Delta HCO3- = 24 – patient’s HCO3- = 24 – 17 = 7  Delta gap = Delta AG- Delta HCO3- = 10 – 7 = 3  Additional metabolic alkalosis is also present with high AG metabolic acidosis.
  • 29.  Step 1: Acidemic, alkalemic, or normal?  Step 2: Is the primary disturbance respiratory or metabolic?  Step 3: For a primary respiratory disturbance, is it acute or chronic?  Step 4: For a metabolic disturbance, is the respiratory system compensating OK?  Step 5: For a metabolic acidosis, is there an increased anion gap?  Step 6: For an increased anion gap metabolic acidosis, are there other derangements?
  • 30.  65 years old male with CKD presenting with nausea, diarrhea and acute respiratory distress  ABG: 7.23/17/235/7 with 50% FiO2 on V.M.  Electrolytes: Na: 123 mEq/L, Cl: 97 mEq/L, S.K 3.5  Renal function: S. Creat: 5.1 mg%, BUN: 119
  • 31.  Acidemic ?  Alkalemic ?
  • 32.  Respiratory / metabolic ?  ABG: 7.23/17/235/7 with 50% FiO2 on V.M.  pH and PaCO2 goes in same direction; so it is primarily metabolic disorder.
  • 33.  ABG: 7.23/17/235/7 with 50% FiO2 on V.M.  Winter’s formula:  Expected PaCO2 = 1.5 X [7] + 8 +/- 2 = 18.5 +/-2
  • 34.  ABG: 7.23/17/235/7 with 50% FiO2 on V.M.  Electrolytes: Na: 123 mEq/L, Cl: 97 mEq/L, S.K 3.5  AG = Na – [Cl +HCO3-] = 123 – [97 + 7] = 19  High AG metabolic acidosis  Delta gap = Delta AG – Delta HCO3-  = [19 - 12 ] – [24 – 7 ]  = 7 – 7 = 0  Non –anion gap metabolic acidosis
  • 35.  High AG metabolic acidosis with non-anion metabolic acidosis
  • 36.  High AG metabolic acidosis is due to BUN 119  Non anion metabolic acidosis is due to diarrhea
  • 37.  Very sick 56 year old man being evaluated for a possible double lung transplant  Dyspnoea on minimal exertion  On home oxygen therapy (nasal prongs, 2 lpm)  Numerous pulmonary medications  ABG: 7.30/65/88/31.1
  • 38.  Acidemia ?  Alkalemia ?
  • 39.  pH and PaCO2 goes in opposite direction; so primary disorder is respiratory.
  • 40.  For Acute disorder;  Change in pH = 0.008 X [65 – 40 ]=0.2  Expected pH = 7.40 – 0.2 = 7.20  For chronic disorder;  Change n pH= 0.003 X [65 – 40 ] = 0.07  Expected pH = 7.40 – 0.07 = 7.33  So its chronic respiratory acidosis.
  • 41.  delta PaCO2 = 25  So rise in HCO3- will be by 7.5 mEq/L, which should be 24 + 7.5 = 31.5 mEq/L  Which is expected HCO3-
  • 42.  Primary chronic respiratory acidosis.
  • 43.  Patient has a long standing pulmonary disease so bicarbonate is in the compensation.
  • 44.  A 44 year old moderately dehydrated man was admitted with a two day history of acute severe diarrhea.  ABG: 7.31 / 33 / 88 /16 / 95%  Elect: Na: 136 mEq/L, Cl: 103 mEq/L, K: 2.9 mEq/L
  • 45.  Acidemia ?  Alkalemia ?
  • 46.  pH and PaCO2 goes in the same direction; so primary disorder is metabolic.
  • 47.  Winter’s formula  Expected PaCO2= 1.5 X [16] + 8 +/ -2  = 32 -/+ 2 = 30 – 34 mEq/L  So it is fully compensated metabolic disorder.
  • 48.  AG = Na – [Cl + HCO3-] = 134 – [104 + 16 ] = 14
  • 49.  Non AG metabolic acidosis
  • 50.  Patient lost bicarbonate in diarrhea leading to non anion gap metabolic acidosis.
  • 51.  A 38-year-old woman is 12 weeks pregnant. For the last 10 days she has had worsening nausea and vomiting. When seen by her physician, she is dehydrated and has shallow respirations. Arterial blood gas data is as follow  ABG: 7.56/54/110/45
  • 52.  Acidemia ?  Alkalemia ?
  • 53.  pH and PaCO2 goes in same direction so the primary disorder is metabolic alkalosis.
  • 54.  Expected PaCO2 = 0.7 X [ HCO3-] + 21 +/- 2 = 0.7 X [ 45 ] + 21 +/ - 2 = 52.5 +/-2 = 50.5 – 54.5
  • 56.  Patient has lost lot of gastric juice and hydrochloric acid in vomit leading to metabolic alkalosis.
  • 57.  Step 1: Acidemic, alkalemic, or normal?  Step 2: Is the primary disturbance respiratory or metabolic?  Step 3: For a primary respiratory disturbance, is it acute or chronic?  Step 4: For a metabolic disturbance, is the respiratory system compensating OK?  Step 5: For a metabolic acidosis, is there an increased anion gap?  Step 6: For an increased anion gap metabolic acidosis, are there other derangements?
  • 58.