2) (x-14)(x^3+4x)domain of F isx^3 + 4x = 0==x(x^2 + 4) =.pdf

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2) (x-14)/(x^3+4x) domain of F is? x^3 + 4x = 0 ==> x(x^2 + 4) = 0 x = 0, 2i, -2i Domain is R - {0} or (-infy, 0) U (0, +infy) 3)6x/ square root X+7 the domain is? x + 7 > 0 ==> x > -7 Domain is (-7, +infy) Solution 2) (x-14)/(x^3+4x) domain of F is? x^3 + 4x = 0 ==> x(x^2 + 4) = 0 x = 0, 2i, -2i Domain is R - {0} or (-infy, 0) U (0, +infy) 3)6x/ square root X+7 the domain is? x + 7 > 0 ==> x > -7 Domain is (-7, +infy).

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$2) (x-14)/(x^3+4x) domain of F is? x^3 + 4x = 0 ==> x(x^2 + 4) = 0 x = 0, 2i, -2i Domain is R - {0} or (-infy, 0) U (0, +infy) 3)6x/ square root X+7 the domain is? x + 7 > 0 ==> x > -7 Domain is (-7, +infy) Solution 2) (x-14)/(x^3+4x) domain of F is? x^3 + 4x = 0$

$==> x(x^2 + 4) = 0 x = 0, 2i, -2i Domain is R - {0} or (-infy, 0) U (0, +infy) 3)6x/ square root X+7 the domain is? x + 7 > 0 ==> x > -7 Domain is (-7, +infy)$

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Ques-1: How would agriculture be impacted in this country if the soils were lacking in microbes? Can you imagine a time in the future when we will have eliminated all of the fatal diseases caused by microbes? If you could cure just one microbial disease which one would it be and why? Which disease would be the easiest and cheapest to prevent and why? Answer: Microbes are natural scavangers and they are essential to convert disposing waste sludge into final product as an organic fertilizer through the anaerobic digestion, pasteurization and compost preparation. In order to minimize the error and to enable efficient growth of plant, it is better to supply plant with equal ratios at which plant can survive followed by supplying soil worms to enable proper nitrate and phosphorous fixation. These soil worms also should be in a proper ratio. In order to get better yield, fertilizers, which have the properties of not inhibiting the growth of soil microbes, are crucial. Providing plants with sufficient mineral supply is also important. The above methods of waste sludge treatment produces ----> organic manure or organic natural fertilizer for plant growth. Therefore, absence of microbes is leading to lack of leaf, shoot and root systems for plants result in no adequate mineral supplement to plants. This is leading to imbalance of ecosystem equilibrium. Plant growth was observed only in plants with soil and soil with worms. The major reason behind this is aerobic decomposition of soil microbes and worms supplying sufficient amount of nutrient such as nitrogen, phosphorous in the form of nitrates, phosphates. Soil worms efficiently performing nitrate fixation and phosphate fixation followed by carbon fixation. Soil worms are major symbiotic parasites, which can fix these complex phosphates, nitrates to supply to the plant efficiently as plant cannot fix nitrate and phosphates straightaway. Soil worms are natural scavengers. But in the treatments \"fertilizers with no worms and also fertilizers with worms, plant growth did not observed considerably as in which organophosphorous nitrate and phosphate fertilizers may have properties to act on soil microbes to inhibit their growth and reproduction. Thereby excess fertilizers may lead to excessive concentration inside the plant root cells (endoderm) followed by hyperosmotic cell death finally result in plant roots inability to supply minerals and water to the plant. Growth is going to be inhibited by excessive amount of fertilizers or even in the absence of soil worms. No, it is not possible to eliminate all the communicable diseases caused by microbes in future because microbes do exist antibiotic resistant and they have a property of transferring genes (transformation, conjugation and transduction) to other microbe of same genus result in acquiring resistance to host defense system. Sometimes some viral species have ability to undergo phage variation through mutated genome in the host cells. Curing a micro.

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2) (x-14)(x^3+4x)domain of F isx^3 + 4x = 0==x(x^2 + 4) =.pdf

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2) (x-14)(x^3+4x)domain of F isx^3 + 4x = 0==x(x^2 + 4) =.pdf