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![Q. In a plane electromagnetic wave, the electric field oscillates sinusoidally at a
frequency of 2.0 × 10 10
Hz and amplitude 48 V/m.
(a) What is the wavelength of the wave?
(b) What is the amplitude of the oscillating magnetic field?
(c) Show that the average energy density of the E field equals the average
energy density of the B field. [c = 3 × 10 8
m s-1
]](https://image.slidesharecdn.com/12p08electromagnetism-250802063143-87dad183/85/12P08electromagnetismadfgasdfsdfsdfsdfs-pptx-274-320.jpg)
12P08electromagnetismadfgasdfsdfsdfsdfs.pptx
- 1.
- 2. Learning Objectives Displacement current Electromagneticwaves Electromagnetic spectrum 12P08-Electromagnetic Waves
- 3.
- 4. Learning Objectives Maxwell’s argument Maxwell’sexperiment Maxwell’s equation 12P08.1 Displacement current
- 5.
- 6. Effects of motionof a charge Motion of charge
- 7. Effects of motionof a charge Motion of charge Stationary
- 8. Effects of motionof a charge Motion of charge Stationary Electric field is generated
- 9. Effects of motionof a charge Motion of charge Stationary Electric field is generated
- 10. Effects of motionof a charge Motion of charge Stationary Moving with uniform motion Electric field is generated
- 11. Effects of motionof a charge Motion of charge Stationary Moving with uniform motion Magnetic field is generated Electric field is generated
- 12. Effects of motionof a charge Motion of charge Stationary Moving with uniform motion Magnetic field is generated Electric field is generated
- 13. Effects of motionof a charge Motion of charge Stationary Moving with uniform motion Accelerated Magnetic field is generated Electric field is generated
- 14. Effects of motionof a charge EM Waves are generated Motion of charge Stationary Moving with uniform motion Accelerated Magnetic field is generated Electric field is generated
- 15. Current creates magneticfields. Maxwell’s argument Hans Oersted
- 16. Current creates magneticfields. Maxwell’s argument Oersted's experiment Hans Oersted
- 17. Magnetic field changingwith time gives rise to an electric field. Maxwell’s argument Michael Faraday
- 18. Magnetic field changingwith time gives rise to an electric field. Maxwell’s argument Faraday’s law Michael Faraday
- 19. Maxwell’s argument Is theconverse also true?
- 20. Maxwell’s argument Is theconverse also true? J.C. Maxwell
- 21. Maxwell’s argument Does thechange in electric field create magnetic field? J.C. Maxwell
- 22. A time varyingelectric field can generate magnetic field. Maxwell’s argument
- 23. A time varyingelectric field can generate magnetic field. Maxwell’s argument
- 24. A time varyingelectric field can generate magnetic field. Maxwell’s argument Ic Ic
- 25. A time varyingelectric field can generate magnetic field. Maxwell’s argument Ic Ic
- 26. A time varyingelectric field can generate magnetic field. Maxwell’s argument Ic Ic
- 27.
- 28. Electric field Electric fieldchanging with time gives rise to a magnetic field. Maxwell’s argument
- 29. Electric field Magneticfield Electric field changing with time gives rise to a magnetic field. Maxwell’s argument
- 30. Electric field Magneticfield Electric field changing with time gives rise to a magnetic field. Maxwell’s argument Magnetic field changing with time gives rise to an electric field.
- 31.
- 32. Case 1: Maxwell’s Experiment Maxwell’sexperiment (outside the capacitor)
- 33. Case 1: Maxwell’s experiment(outside the capacitor) Parallel Plate Capacitor
- 34. Case 1: Maxwell’s experiment(outside the capacitor) Parallel Plate Capacitor Compass is outside
- 35. Case 1: Maxwell’s experiment(outside the capacitor) Parallel Plate Capacitor Compass is outside Compass gets deflected
- 36. Case 1: Maxwell’s experiment(outside the capacitor) Parallel Plate Capacitor Compass is outside Compass gets deflected Magnetic field is present
- 37. Apply Ampere’s law Maxwell’sexperiment (outside the capacitor) Closed loop Parallel Plate Capacitor
- 38. Apply Ampere’s law Maxwell’sexperiment (outside the capacitor) Closed loop Parallel Plate Capacitor
- 39. Apply Ampere’s law Maxwell’sexperiment (outside the capacitor) Closed loop Parallel Plate Capacitor
- 40. Apply Ampere’s law Maxwell’sexperiment (outside the capacitor) Closed loop Parallel Plate Capacitor
- 41. Maxwell’s experiment (insidethe capacitor) Maxwell’s Experiment Case 2:
- 42. Maxwell’s experiment (insidethe capacitor) Parallel Plate Capacitor Case 2:
- 43. Case 2: Maxwell’s experiment(inside the capacitor) Parallel Plate Capacitor Compass is inside
- 44. Case 2: Maxwell’s experiment(inside the capacitor) Parallel Plate Capacitor Compass is inside Compass gets deflected
- 45. Case 2: Maxwell’s experiment(inside the capacitor) Parallel Plate Capacitor Compass is inside Compass gets deflected Magnetic field is present
- 46. Case 2: Maxwell’s experiment(inside the capacitor) Parallel Plate Capacitor Compass is inside Compass gets deflected Magnetic field is present Current is present
- 47. Closed loop Maxwell’s experiment(inside the capacitor) 4.31 Parallel Plate Capacitor Apply Ampere’s law
- 48. Closed loop Maxwell’s experiment(inside the capacitor) 4.31 Apply Ampere’s law Parallel Plate Capacitor
- 49. Closed loop Maxwell’s experiment(inside the capacitor) Parallel Plate Capacitor Apply Ampere’s law
- 50. Closed loop Maxwell’s experiment(inside the capacitor) Apply Ampere’s law Parallel Plate Capacitor
- 51. Change in electricfield produces magnetic field which suggest presence of current that is called displacement current. Maxwell’s experiment (Conclusion) I c I c Parallel plate capacitor
- 52. Change in electricfield produces magnetic field which suggest presence of current that is called displacement current. Maxwell’s experiment (Conclusion) I c I c
- 53. Change in electricfield produces magnetic field which suggest presence of current that is called displacement current. Maxwell’s experiment (Conclusion) I c I c
- 54. Change in electricfield produces magnetic field which suggest presence of current that is called displacement current. Maxwell’s experiment (Conclusion) Id I c I c
- 55. Using Gauss’s lawflux passing through plates Displacement current Parallel Plate Capacitor Closed loop
- 56. Using Gauss’s lawflux passing through plates Displacement current Parallel Plate Capacitor Closed loop
- 57. Using Gauss’s lawflux passing through plates Displacement current Parallel Plate Capacitor Closed loop
- 58. Using Gauss’s lawflux passing through plates Displacement current Parallel Plate Capacitor Closed loop
- 59. Using Gauss’s lawflux passing through plates Displacement current Parallel Plate Capacitor Closed loop
- 60. Using Gauss’s lawflux passing through plates Displacement current Parallel Plate Capacitor Closed loop
- 61.
- 62.
- 63.
- 64.
- 65.
- 66. Displacement current Parallel Plate Capacitor Closedloop Total current
- 67. Displacement current Parallel Plate Capacitor Closedloop Total current Id = 0
- 68. Displacement current Parallel Plate Capacitor Closedloop Total current Id = 0 Ic = 0 Id = Ic Id
- 69.
- 70.
- 71. Maxwell Ampere’s law WhereIc = Conduction current Displacement current
- 72. Maxwell Ampere’s law WhereIc = Conduction current Id = Displacement current Displacement current
- 73. Definition Current flowing betweenthe capacitor plates without motion of charges is called displacement current. Displacement current between capacitor plates Displacement current
- 74. Definition Current flowing betweenthe capacitor plates without motion of charges is called displacement current. Current arises due to changing of electric field. Displacement current
- 75. Definition Current flowing betweenthe capacitor plates without motion of charges is called displacement current. Current arises due to changing of electric field. Displacement current Displacement current
- 76. Definition Current flowing betweenthe capacitor plates without motion of charges is called displacement current. Current arises due to changing of electric field. Displacement current Displacement current
- 77. Definition Current flowing betweenthe capacitor plates without motion of charges is called displacement current. Current arises due to changing of electric field. Displacement current Displacement current
- 78.
- 79. Q. The chargeon a parallel plate capacitor varies as . The plates are very large and close together (Area = A, Separation = d). Neglecting the edge effect find the displacement current through the capacitor?
- 80. Q. The chargeon a parallel plate capacitor varies as . The plates are very large and close together (Area = A, Separation = d). Neglecting the edge effect find the displacement current through the capacitor? Pause video (Time duration : 2 minutes)
- 81.
- 82. Sol. Displacement current Platearea (A)
- 83. Sol. Displacement current Electricfield Plate area (A)
- 84. Sol. Displacement current Electricfield Plate area (A)
- 85. Sol. Displacement current Electricfield Plate area (A)
- 86. Sol. Displacement current Electricfield Plate area (A)
- 87. Sol. Displacement current Electricfield Plate area (A)
- 88. Sol. Displacement current Electricfield Plate area (A)
- 89. Sol. Displacement current Electricfield Plate area (A)
- 90.
- 91. 1. (Gauss’s Lawfor electrostatics) Electric field exists due to charge. Maxwell’s Equation
- 92. 1. (Gauss’s Lawfor electrostatics) Electric field exists due to charge. 2. (Gauss’s Law for magnetism) Magnetic field lines form closed loop. Maxwell’s Equation
- 93. 3. (Faraday’s Law) Electricfield is generated due to change of magnetic field. Maxwell’s Equation
- 94. 3. (Faraday’s Law) Electricfield is generated due to change of magnetic field. 4. (Maxwell-Ampere’s Law) Magnetic field generates due to change of electric field. Maxwell’s Equation
- 95.
- 96.
- 97. Q. Figure showsa capacitor made of two circular plate each of radius 12 cm , and separated by 5.0 cm . The capacitor is being charged by an external source (not shown in figure). The charging current is constant and equal to 0.15 A . Parallel plate capacitor
- 98. Q. Figure showsa capacitor made of two circular plate each of radius 12 cm , and separated by 5.0 cm . The capacitor is being charged by an external source (not shown in figure). The charging current is constant and equal to 0.15 A . (a) Calculate the capacitance and the rate of change of potential difference between the plates. Parallel plate capacitor
- 99. Q. Figure showsa capacitor made of two circular plate each of radius 12 cm , and separated by 5.0 cm . The capacitor is being charged by an external source (not shown in figure). The charging current is constant and equal to 0.15 A . (a) Calculate the capacitance and the rate of change of potential difference between the plates. (b) Obtain the displacement current across the plates. Parallel plate capacitor
- 100. Q. Figure showsa capacitor made of two circular plate each of radius 12 cm , and separated by 5.0 cm . The capacitor is being charged by an external source (not shown in figure). The charging current is constant and equal to 0.15 A . (a) Calculate the capacitance and the rate of change of potential difference between the plates. (b) Obtain the displacement current across the plates. (c) Is Kirchhoff's first rule valid at each plate of the capacitor ? Explain it. Parallel plate capacitor
- 101. Sol. (a) Capacitance ofthe Parallel plate capacitor Separation d = 5 cm Radius of plate r = 12 cm Parallel plate capacitor
- 102. Sol. (a) Capacitance ofthe Parallel plate capacitor Separation d = 5 cm Radius of plate r = 12 cm Parallel plate capacitor
- 103. Sol. (a) Capacitance ofthe Parallel plate capacitor Separation d = 5 cm Radius of plate r = 12 cm Parallel plate capacitor
- 104. Sol. (a) Capacitance ofthe Parallel plate capacitor Separation d = 5 cm Radius of plate r = 12 cm Parallel plate capacitor
- 105. Sol. (a) Capacitance ofthe Parallel plate capacitor Separation d = 5 cm Radius of plate r = 12 cm Parallel plate capacitor
- 106. Rate of changeof potential difference = = ?
- 107. Rate of changeof potential difference = = ? Given I = 0.15 A
- 108. Rate of changeof potential difference = = ? Given I = 0.15 A
- 109. Rate of changeof potential difference = = ? Given I I = 0.15 A
- 110. Rate of changeof potential difference = = ? Given I I I = 0.15 A
- 111. Rate of changeof potential difference = = ? Given I I I I = 0.15 A
- 112.
- 113. (b) Displacement current GivenI = 0.15 A
- 114. (b) Displacement current GivenI = 0.15 A
- 115. (b) Displacement current GivenI = 0.15 A
- 116. (b) Displacement current GivenI = 0.15 A
- 117. (b) Displacement current GivenI = 0.15 A
- 118. (b) Displacement current Given I= Id 0.15 I = 0.15 A
- 119. (c) Is Kirchhoff'sfirst rule valid at each plate of the capacitor ? Explain it. Yes, kirchoff’s law is valid at each plate of capacitor.
- 120. (c) Is Kirchhoff'sfirst rule valid at each plate of the capacitor ? Explain it. Yes, kirchoff’s law is valid at each plate of capacitor. As we know that kirchoff’s law states that algebraic sum of currents at any junction of circuit must be zero.
- 121. (c) Is Kirchhoff'sfirst rule valid at each plate of the capacitor ? Explain it. Yes, kirchoff’s law is valid at each plate of capacitor. As we know that kirchoff’s law states that algebraic sum of currents at any junction of circuit must be zero. At point A apply kirchoff’s law Ic Ic Id A Parallel plate capacitor
- 122. (c) Is Kirchhoff'sfirst rule valid at each plate of the capacitor ? Explain it. Yes, kirchoff’s law is valid at each plate of capacitor. As we know that kirchoff’s law states that algebraic sum of currents at any junction of circuit must be zero. At point A apply kirchoff’s law Ic Ic Id A
- 123. (c) Is Kirchhoff'sfirst rule valid at each plate of the capacitor ? Explain it. Yes, kirchoff’s law is valid at each plate of capacitor. As we know that kirchoff’s law states that algebraic sum of currents at any junction of circuit must be zero. At point A apply kirchoff’s law Ic Ic Id A
- 124. (c) Is Kirchhoff'sfirst rule valid at each plate of the capacitor ? Explain it. Yes, kirchoff’s law is valid at each plate of capacitor. As we know that kirchoff’s law states that algebraic sum of currents at any junction of circuit must be zero. At point A apply kirchoff’s law Ic Ic Id A
- 125. ● Displacement currenthas same effect as the conduction current. ● The displacement current may be zero since the electric field does not change with time. ● In charging capacitor both the displacement and conduction current may be present in different regions of space. ● Electric field changing with time gives rise to magnetic field and consequently displacement current is the source of magnetic field. ● Displacement current is given as Summary
- 126.
- 127. Learning Objectives What isEM Waves Source and Nature of EM Waves Properties of EM Waves 12P08.2 Electromagnetic waves
- 128.
- 129. What is EMWaves What is Wave? Disturbance that travels through a medium or without medium, transporting energy from one location to another location without transporting medium. Wave
- 130. Types of waves (i)Longitudinal Waves:- Particle of waves are displaced along the direction of propagation of wave. 130 What is EM Waves
- 131. Types of waves (i)Longitudinal Waves:- Particle of waves are displaced along the direction of propagation of wave. Example : Sound waves 131 What is EM Waves Longitudinal wave
- 132. (ii) Transverse Waves:-Particles of waves are displaced perpendicular to the direction of propagation. What is EM Waves
- 133. (ii) Transverse Waves:-Particles of waves are displaced perpendicular to the direction of propagation. Example : Waves of guitar’s string What is EM Waves Transverse wave
- 134. Definition of Electromagneticwaves What is EM Waves
- 135. What is EMWaves Definition of Electromagnetic waves Electric field, magnetic field and direction of propagation of wave are mutually perpendicular. Propagation direction Z
- 136. What is EMWaves Definition of Electromagnetic waves Electric field, magnetic field and direction of propagation of wave are mutually perpendicular. Electromagnetic waves are non material waves. Propagation direction Z
- 137. What is EMWaves Definition of Electromagnetic waves Electric field, magnetic field and direction of propagation of wave are mutually perpendicular. Electromagnetic waves are non material waves. Z Y X Z
- 138. How EM Wavesare produced? An accelerated or oscillated charge generates EM Waves. 138 ret What is EM Waves Y X Z Z
- 139.
- 140. http://www.mysearch.org.uk/website1/images/animations/472.emwave.gif Oscillating Charge OscillatingElectric Field What is EM Waves
- 141.
- 142. http://www.mysearch.org.uk/website1/images/animations/472.emwave.gif Oscillating Charge Oscillating ElectricField Oscillating Magnetic Field Oscillating Electric Field What is EM Waves
- 143. Oscillating Electric Field Whatis EM Waves
- 144. Oscillating Magnetic Field OscillatingElectric Field What is EM Waves
- 145. Oscillating magnetic field Oscillatingelectric field EM Waves What is EM Waves Oscillating Magnetic Field Oscillating Electric Field
- 146.
- 147. Q. A planeEM Waves travels in vacuum along z - direction. What can you say about the directions of its electric and magnetic field vectors?
- 148. Q. A planeEM Waves travels in vacuum along z - direction. What can you say about the directions of its electric and magnetic field vectors? Pause video (Time duration : 2 minutes)
- 149. Q. A planeEM Waves travels in vacuum along z - direction. What can you say about the directions of its electric and magnetic field vectors? Sol. Electric field and magnetic field are in x-y plane and perpendicular to each other as shown below in figure.
- 150. Q. A planeEM Waves travels in vacuum along z - direction. What can you say about the directions of its electric and magnetic field vectors? Sol. Electric field and magnetic field are in x-y plane and perpendicular to each other as shown below in figure. Z X Y Propagation direction
- 151. Q. A planeEM Waves travels in vacuum along z - direction. What can you say about the directions of its electric and magnetic field vectors? Sol. Electric field and magnetic field are in x-y plane and perpendicular to each other as shown below in figure. E or B or E Velocity of wave Z X Y X Y Z Propagation direction
- 152. 12P08.2 CV2 Source and Natureof EM Waves
- 153. Source of Electromagneticwaves: Source of electromagnetic wave is a vibrating or accelerating charge or oscillating charge. Source and Nature of EM Waves
- 154. Source of Electromagneticwaves: Source of electromagnetic wave is a vibrating or accelerating charge or oscillating charge. Source and Nature of EM Waves Change in Electric Field
- 155. Source of Electromagneticwaves: Source of electromagnetic wave is a vibrating or accelerating charge or oscillating charge. Source and Nature of EM Waves Change in Electric Field Change in Magnetic Field
- 156. Source of Electromagneticwaves: Source of electromagnetic wave is a vibrating or accelerating charge or oscillating charge. Source and Nature of EM Waves Change in Electric Field Change in Magnetic Field
- 157. Nature of EMWaves EM Waves are transverse and non material waves . Source and Nature of EM Waves
- 158. Equation of electromagneticwaves Source and Nature of EM Waves Representation of EMW Z Propagation direction
- 159. Equation of electromagneticwaves Source and Nature of EM Waves Z Propagation direction
- 160. Equation of electromagneticwaves Source and Nature of EM Waves Z Propagation direction
- 161. Equation of electromagneticwaves Here = angular frequency(rad/sec) ⍵ Source and Nature of EM Waves Z Propagation direction
- 162. Equation of electromagneticwaves Here = angular frequency(rad/sec) ⍵ k = magnitude of wave vector Source and Nature of EM Waves Z Propagation direction
- 163. Equation of electromagneticwaves Here = angular frequency(rad/sec) ⍵ k = magnitude of wave vector λ = wavelength of EMWs Source and Nature of EM Waves Z Propagation direction
- 164. Equation of electromagneticwaves Here = angular frequency(rad/sec) ⍵ k = magnitude of wave vector λ = wavelength of EMWs z = propagation direction Source and Nature of EM Waves Z Propagation direction
- 165. Equation of electromagneticwaves Here = angular frequency(rad/sec) ⍵ k = magnitude of wave vector λ = wavelength of EMWs z = propagation direction t = specific time Source and Nature of EM Waves Z Propagation direction
- 166. c = speedof electromagnetic wave = speed of light = 3 × 108 m/sec Source and Nature of EM Waves
- 167. Magnitude of wavepropagation vector Source and Nature of EM Waves
- 168. Relationship between permittivity( 𝟄0 ) of free space and magnetic permeability of free space ( 𝝻0 ) Source and Nature of EM Waves
- 169. For any othermaterial the velocity of EM Waves Source and Nature of EM Waves
- 170. For any othermaterial the velocity of EM Waves Source and Nature of EM Waves
- 171. For any othermaterial the velocity of EM Waves Where 𝟄 and 𝝻 are permittivity and permeability of material respectively. Source and Nature of EM Waves
- 172.
- 173. Q. The sourceof EM Waves can be a charge (a) Moving with a constant velocity (b) Moving in a circular orbit (c) At rest (d) Falling in an electric field
- 174. Q. The sourceof EM Waves can be a charge (a) Moving with a constant velocity (b) Moving in a circular orbit (c) At rest (d) Falling in an electric field Pause video (Time duration : 2 minutes)
- 175. Q. The sourceof EM Waves can be a charge (a) Moving with a constant velocity (b) Moving in a circular orbit (c) At rest (d) Falling in an electric field Sol. (b) Moving in a circular orbital ( In circular motion a particle is having centripetal acceleration so it can be a source of EM Waves ) (d) Falling in an electric field (In electric field a charge particle is experienced force so that it gets accelerated, so it can be a source EM Waves)
- 176.
- 177. Q. Which physicalquantity is same for X- rays of wavelength 10 -10 m , red light of wavelength 6800 Å and radio waves of wavelength 500 m ? (a) Velocity (b) Frequency (c) Amplitude (d) acceleration
- 178. Q. Which physicalquantity is same for X- rays of wavelength 10 -10 m , red light of wavelength 6800 Å and radio waves of wavelength 500 m ? (a) Velocity (b) Frequency (c) Amplitude (d) acceleration Pause video (Time duration : 2 minutes)
- 179. Q. Which physicalquantity is same for X- rays of wavelength 10 -10 m , red light of wavelength 6800 Å and radio waves of wavelength 500 m ? Sol. (a) Velocity
- 180.
- 181. Q. A radiocan tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?
- 182. Q. A radiocan tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band? Pause video (Time duration : 2 minutes)
- 183. Q. A radiocan tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band? Sol. We know that
- 184. Q. A radiocan tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band? Sol. We know that
- 185. Q. A radiocan tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band? Sol. We know that
- 186. Q. A radiocan tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band? Sol. We know that
- 187. Q. A radiocan tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band? Sol. We know that
- 188. Q. A radiocan tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band? Sol. We know that So that corresponding wavelength band 40 m to 25 m.
- 189.
- 190. Q. A chargedparticle oscillates about its mean equilibrium position with a frequency of 109 Hz. what is the frequency of the electromagnetic waves produced by the oscillator?
- 191. Q. A chargedparticle oscillates about its mean equilibrium position with a frequency of 109 Hz. what is the frequency of the electromagnetic waves produced by the oscillator? Pause video (Time duration : 2 minutes)
- 192. Q. A chargedparticle oscillates about its mean equilibrium position with a frequency of 109 Hz. what is the frequency of the electromagnetic waves produced by the oscillator? Sol. Frequency of Electromagnetic wave must be equal to the frequency of oscillation of charged particle. So frequency of EM Waves is 10 9 Hz.
- 193.
- 194. Properties of EMWaves Electromagnetic waves are transverse in nature.Properties of EMWs Transverse wave
- 195. Speed of EMWaves is equal to the speed of light. Properties of EM Waves
- 196. Speed of EMWaves is equal to the speed of light. c = speed of wave in vacuum = 3 × 10 8 m/s Characteristics of EMW Properties of EM Waves
- 197. Speed of EMWaves is equal to the speed of light. c = speed of wave in vacuum = 3 × 10 8 m/s λ = wavelength of EM Waves Characteristics of EMW Properties of EM Waves
- 198. Speed of EMWaves is equal to the speed of light. c = speed of wave in vacuum = 3 × 10 8 m/s λ = wavelength of EM Waves A = amplitude of wave Characteristics of EMW Properties of EM Waves
- 199. Speed of EMWaves is equal to the speed of light. c = speed of wave in vacuum = 3 × 10 8 m/s λ = wavelength of EM Waves A = amplitude of wave 𝝂 = frequency of wavelength Characteristics of EMW Properties of EM Waves
- 200. Velocity of EMWaves Properties of EM Waves
- 201. Relationship between magnitudeof electric field and magnetic field Properties of EM Waves
- 202. Relationship between magnitudeof electric field and magnetic field Where E0 = Maximum value of electric field Properties of EM Waves
- 203. Relationship between magnitudeof electric field and magnetic field Where E0 = Maximum value of electric field B0 = Maximum value of magnetic field Properties of EM Waves
- 204. Poynting vector:- Therate of flow of energy in an electromagnetic wave per unit area per unit second is called poynting vector. Properties of EM Waves
- 205. Poynting vector:- Therate of flow of energy in an electromagnetic wave per unit area per unit second is called poynting vector. Representation of poynting vector Properties of EM Waves
- 206. Poynting vector:- Therate of flow of energy in an electromagnetic wave per unit area per unit second is called poynting vector. Representation of poynting vector in circuit Properties of EM Waves
- 207. Poynting vector:- Therate of flow of energy in an electromagnetic wave per unit area per unit second is called poynting vector. Representation of poynting vector in circuit Properties of EM Waves
- 208. Poynting vector:- Therate of flow of energy in an electromagnetic wave per unit area per unit second is called poynting vector. SI Unit of S is watt / m2 . Representation of poynting vector in circuit Properties of EM Waves
- 209. The electric vectoris responsible for optical effect of electromagnetic waves. Properties of EM Waves
- 210. The electric vectoris responsible for optical effect of electromagnetic waves. Because moving particle oscillates primarily due to the electric field. Properties of EM Waves
- 211. The energy inan electromagnetic wave is equally divided in electric vector and magnetic vector. Properties of EM Waves
- 212. The energy inan electromagnetic wave is equally divided in electric vector and magnetic vector. Energy distribution in EMWs Properties of EM Waves
- 213. The Average energydensity of electric field Properties of EM Waves
- 214. The Average energydensity of magnetic field Properties of EM Waves
- 215. Intensity of EMWaves is defined as the energy crossing per unit area per unit time perpendicular to the propagation of electromagnetic wave. Properties of EM Waves
- 216. Intensity of EMWsis defined as the energy crossing per unit area per unit time perpendicular to the propagation of electromagnetic wave. Properties of EM Waves
- 217. The existence ofEM Waves was confirmed by Hertz in 1888. Heinrich hertz Properties of EM Waves
- 218. Total momentum deliveredto surface by EM Waves Properties of EM Waves
- 219. Total momentum deliveredto surface by EM Waves p = Total momentum delivered Properties of EM Waves
- 220. Total momentum deliveredto surface by EM Waves p = Total momentum delivered U = Total energy of EM Waves Properties of EM Waves
- 221. Total momentum deliveredto surface by EM Waves p = Total momentum delivered U = Total energy of EM Waves c = Speed of light Properties of EM Waves
- 222.
- 223. Q. The amplitudeof the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave?
- 224. Q. The amplitudeof the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave? Pause video (Time duration : 2 minutes)
- 225. Q. The amplitudeof the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave? Sol. Given B0 = 510 nT
- 226. Q. The amplitudeof the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave? Sol. Given B0 = 510 nT
- 227. Q. The amplitudeof the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave? Sol. Given B0 = 510 nT
- 228. Q. The amplitudeof the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave? Sol. Given B0 = 510 nT
- 229. Q. The amplitudeof the magnetic field part of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave? Sol. Given B0 = 510 nT
- 230. Reference Questions NCERT :Example 8.2, 8.3, 8.4, 8.5
- 231.
- 232. Q. Suppose thatthe electric field amplitude of an electromagnetic wave is E0 = 120 N/C and that its frequency is f = 50 MHz.
- 233. Q. Suppose thatthe electric field amplitude of an electromagnetic wave is E0 = 120 N/C and that its frequency is f = 50 MHz. (a) Determine B0, 𝟂, k and λ.
- 234. Q. Suppose thatthe electric field amplitude of an electromagnetic wave is E0 = 120 N/C and that its frequency is f = 50 MHz. (a) Determine B0, 𝟂, k and λ. (b) Find expression for E and B.
- 235. Q. Suppose thatthe electric field amplitude of an electromagnetic wave is E0 = 120 N/C and that its frequency is f = 50 MHz. (a) Determine B0, 𝟂, k and λ. (b) Find expression for E and B. Pause video (Time duration : 2 minutes)
- 236. Sol. (a) Magnitude ofmagnetic field vector Given E0 = 120 N/C f = 50 MHz
- 237. Sol. (a) Magnitude ofmagnetic field vector Given E0 = 120 N/C f = 50 MHz
- 238. Sol. (a) Magnitude ofmagnetic field vector Given E0 = 120 N/C f = 50 MHz
- 239. Sol. (a) Magnitude ofmagnetic field vector Given E0 = 120 N/C f = 50 MHz
- 240. Sol. (a) Magnitude ofmagnetic field vector Given E0 = 120 N/C f = 50 MHz
- 241. Sol. Angular frequency Given E0 =120 N/C f = 50 MHz
- 242. Sol. Angular frequency Given E0 =120 N/C f = 50 MHz
- 243. Sol. Angular frequency Given E0 =120 N/C f = 50 MHz
- 244. Sol. Angular frequency Given E0 =120 N/C f = 50 MHz
- 245. Sol. Wavelength Given E0= 120 N/C f = 50 MHz
- 246. Sol. Wavelength Given E0= 120 N/C f = 50 MHz
- 247. Sol. Wavelength Given E0= 120 N/C f = 50 MHz
- 248. Sol. Wavelength Given E0= 120 N/C f = 50 MHz
- 249. Sol. Magnitude ofpropagation vector Given E0 = 120 N/C f = 50 MHz
- 250. Sol. Magnitude ofpropagation vector Given E0 = 120 N/C f = 50 MHz
- 251. Sol. Magnitude ofpropagation vector Given E0 = 120 N/C f = 50 MHz
- 252. Sol. Magnitude ofpropagation vector Given E0 = 120 N/C f = 50 MHz
- 253. E0 = 120 N/C f= 50 MHz Sol. (b) Expression of electric field Given
- 254. Sol. (b) Expression ofelectric field Given E0 = 120 N/C f = 50 MHz
- 255. Sol. (b) Expression ofelectric field Given E0 = 120 N/C f = 50 MHz
- 256. Sol. Expression of magneticfield Given E0 = 120 N/C f = 50 MHz
- 257. Sol. Expression of magneticfield Given E0 = 120 N/C f = 50 MHz
- 258. Sol. Expression of magneticfield Given E0 = 120 N/C f = 50 MHz
- 259.
- 260. Q. A parallelplate capacitor made of circular plates each of radius R = 6 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V AC supply with an angular frequency of 300 rad / sec .
- 261. Q. A parallelplate capacitor made of circular plates each of radius R = 6 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V AC supply with an angular frequency of 300 rad / sec . (a) What is the rms value of the conduction current?
- 262. Q. A parallelplate capacitor made of circular plates each of radius R = 6 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V AC supply with an angular frequency of 300 rad / sec . (a) What is the rms value of the conduction current? (b) Is the conduction equal to the displacement current?
- 263. Sol. Given radiusR = 6 cm C = 100 pF 𝞈 = 300 rad / sec Vrms= 230 V
- 264. Sol. Given We knowthat for an LC circuit radius R = 6 cm C = 100 pF 𝞈 = 300 rad / sec Vrms= 230 V
- 265. Sol. Given We knowthat for an LC circuit radius R = 6 cm C = 100 pF 𝞈 = 300 rad / sec Vrms= 230 V
- 266. Sol. Given We knowthat for an LC circuit radius R = 6 cm C = 100 pF 𝞈 = 300 rad / sec Vrms= 230 V
- 267. Sol. Given We knowthat for an LC circuit radius R = 6 cm C = 100 pF 𝞈 = 300 rad / sec Vrms= 230 V
- 268. Sol. Given We knowthat for an LC circuit radius R = 6 cm C = 100 pF 𝞈 = 300 rad / sec Vrms= 230 V
- 269. (b) Is theconduction equal to the displacement current? Sol. (b) Yes, because from the formula of displacement current, we can get conduction current without changing the dimension.
- 270.
- 271. Q. In aplane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 × 10 10 Hz and amplitude 48 V/m.
- 272. Q. In aplane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 × 10 10 Hz and amplitude 48 V/m. (a) What is the wavelength of the wave?
- 273. Q. In aplane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 × 10 10 Hz and amplitude 48 V/m. (a) What is the wavelength of the wave? (b) What is the amplitude of the oscillating magnetic field?
- 274. Q. In aplane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 × 10 10 Hz and amplitude 48 V/m. (a) What is the wavelength of the wave? (b) What is the amplitude of the oscillating magnetic field? (c) Show that the average energy density of the E field equals the average energy density of the B field. [c = 3 × 10 8 m s-1 ]
- 275. Sol. (a) Wavelength Given 𝜈 =2.0 × 10 10 E0 = 48 V/m
- 276. Sol. (a) Wavelength Given 𝜈 =2.0 × 10 10 E0 = 48 V/m
- 277. Sol. (a) Wavelength Given 𝜈 =2.0 × 10 10 E0 = 48 V/m
- 278. Sol. (a) Wavelength Given 𝜈 =2.0 × 10 10 E0 = 48 V/m
- 279. Sol. (b) Amplitude ofmagnetic field vector Given 𝜈 = 2.0 × 10 10 E0 = 48 V/m
- 280. Sol. (b) Amplitude ofmagnetic field vector Given 𝜈 = 2.0 × 10 10 E0 = 48 V/m
- 281. Sol. (b) Amplitude ofmagnetic field vector Given 𝜈 = 2.0 × 10 10 E0 = 48 V/m
- 282. Sol. (b) Amplitude ofmagnetic field vector Given 𝜈 = 2.0 × 10 10 E0 = 48 V/m
- 283. Sol. (b) Amplitude ofmagnetic field vector Given 𝜈 = 2.0 × 10 10 E0 = 48 V/m
- 284. Sol. (c) Energydensity in electric field
- 285. Sol. (c) Energydensity in electric field Energy density in magnetic field
- 286. Sol. (c) Energydensity in electric field Energy density in magnetic field
- 287. Sol. (c) Energydensity in electric field Energy density in magnetic field
- 288. Sol. (c) Energydensity in electric field Energy density in magnetic field
- 289. Sol. (c) Energydensity in electric field Energy density in magnetic field
- 290. Sol. (c) Energydensity in electric field Energy density in magnetic field
- 291. Sol. (c) Energydensity in electric field Energy density in magnetic field
- 292. Sol. (c) Energydensity in electric field Energy density in magnetic field
- 293. ● EM Wavesare non material waves and transverse in nature. ● EM Waves travel at the speed of light. ● EM Waves are in sinusoidal form. ● EM Waves are produced due to vibrating or accelerating or oscillating charges. ● Expression of electric field ● Expression of magnetic field ● Speed of EM Waves Summary
- 294.
- 295. Learning objectives What isEM Spectrum? Classification of EM Waves 12P08.3 Electromagnetic Spectrum
- 296. 12P08.3 CV1 What is EMSpectrum
- 297. The arrange arrayof electromagnetic radiation in the sequence of their wavelength or frequency is called Electromagnetic spectrum. What is EM spectrum
- 298. The arrange arrayof electromagnetic radiation in the sequence of their wavelength or frequency is called Electromagnetic spectrum. This consists electromagnetic energy ranging from Gamma Rays to Radio waves. What is EM spectrum
- 299. What is EMspectrum Electromagnetic spectrum
- 300. Radio Waves Microwave Waves Infrared Waves Visible Rays UV Rays X-Rays Gamma Rays Whatis EM spectrum Relationship between Energy, Wavelength and Frequency for Electromagnetic spectrum
- 301. Radio Waves Microwave Waves Infrared Waves Visible Rays UV Rays X-Rays Gamma Rays Wavelength(λ) What is EM spectrum Relationship between Energy, Wavelength and Frequency for Electromagnetic spectrum
- 302. Radio Waves Microwave Waves Infrared Waves Visible Rays UV Rays X-Rays Gamma Rays Wavelength(λ) Energy (E) What is EM spectrum Relationship between Energy, Wavelength and Frequency for Electromagnetic spectrum Wavelength (λ)
- 303. Radio Waves Microwave Waves Infrared Waves Visible Rays UV Rays X-Rays Gamma Rays Wavelength(λ) Energy (E) Frequency (f) What is EM spectrum Relationship between Energy, Wavelength and Frequency for Electromagnetic spectrum Wavelength (λ)
- 304. Memory based question Readyfor challenge
- 305. Q. Which electromagneticwave has the shortest wavelength and highest frequency ? (a) Gamma rays (b) Radio waves (c) X-rays (d) Ultraviolet rays
- 306. Q. Which electromagneticwave has the shortest wavelength and highest frequency ? (a) Gamma rays (b) Radio waves (c) X-rays (d) Ultraviolet rays Pause video (Time duration : 2 minutes)
- 307. Q. Which electromagneticwave has the shortest wavelength and highest frequency ? (a) Gamma rays (b) Radio waves (c) X-rays (d) Ultraviolet rays Sol. (e) Gamma rays
- 308. Memory based question Readyfor challenge
- 309. Q. Electromagnetic wavesthat you can see are called (a) Infrared rays (b) Microwaves (c) X-rays (d) Visible light
- 310. Q. Electromagnetic wavesthat you can see are called (a) Infrared rays (b) Microwaves (c) X-rays (d) Visible light Pause video (Time duration : 2 minutes)
- 311. Q. Electromagnetic wavesthat you can see are called (a) Infrared rays (b) Microwaves (c) X-rays (d) Visible light Sol. (d) Visible light
- 312. Memory based question Readyfor challenge
- 313. Q. Longest wavelengthof spectrum (a) Radio waves (b) Ultraviolet rays (c) Visible light (d) Microwaves
- 314. Q. Longest wavelengthof spectrum (a) Radio waves (b) Ultraviolet rays (c) Visible light (d) Microwaves Pause video (Time duration : 2 minutes)
- 315. Q. Longest wavelengthof spectrum (a) Radio waves (b) Ultraviolet rays (c) Visible light (d) Microwaves Sol. (e) Radio waves
- 316. Memory based question Readyfor challenge
- 317. Q. Which colourhas the shortest wavelength in visible light? (a) Red (b) Violet (c) Blue (d) Green
- 318. Q. Which colourhas the shortest wavelength in visible light? (a) Red (b) Violet (c) Blue (d) Green Pause video (Time duration : 2 minutes)
- 319. Q. Which colourhas the shortest wavelength in visible light? (a) Red (b) Violet (c) Blue (d) Green Sol. (b) Violet
- 320. 12P08.3 CV2 Classification of EMSpectrum
- 321. 1. Radio waves Classificationof EM Waves
- 322. 1. Radio waves Production- Due to accelerated charge in wire or antena Classification of EM Waves
- 323. 1. Radio waves Production- Due to accelerated charge in wire or antena Wavelength range - Greater than 0.1 m Classification of EM Waves
- 324. 1. Radio waves Production- Due to accelerated charge in wire or antena Wavelength range - Greater than 0.1 m Detection- Receiver’s Aerial Classification of EM Waves
- 325. Classification of EMWaves
- 326. Application of Radiowaves Radio waves are used in radio and television communication systems. Classification of EM Waves
- 327. Application of Radiowaves Radio waves are used in radio and television communication systems. Radio waves are used in Cellular phones to transmit voice communication in the ultrahigh frequency band. Classification of EM Waves
- 328. 2. Microwaves Classification ofEM Waves
- 329. 2. Microwaves Production -Klystron valve or magnetron valve Microwave oven Classification of EM Waves
- 330. 2. Microwaves Production -Klystron valve or magnetron valve Wavelength range - 0.1 m to 1 mm Classification of EM Waves
- 331. 2. Microwaves Production -Klystron valve or magnetron valve Wavelength range - 0.1 m to 1 mm Detection - Point contact diodes Classification of EM Waves
- 332. Application of microwaves Theyare suitable for the radar systems used in aircraft navigation. Classification of EM Waves
- 333. Application of microwaves Theyare suitable for the radar systems used in aircraft navigation. Microwave oven is an interesting domestic application of these waves. Classification of EM Waves
- 334. 3. Infrared rays Classificationof EM Waves
- 335. 3. Infrared rays Production- Vibration of atoms and molecules Infrared wireless communication Infrared rays generation Classification of EM Waves
- 336. 3. Infrared rays Production- Vibration of atoms and molecules Wavelength range - 1 mm to 700 nm Infrared wireless communication Classification of EM Waves
- 337. 3. Infrared rays Production- Vibration of atoms and molecules Wavelength range - 1 mm to 700 nm Detection - Infrared photographic film Infrared wireless communication Classification of EM Waves
- 338. Application of Infraredrays Infrared lamps are used in physical therapy. Classification of EM Waves
- 339. Application of Infraredrays Infrared lamps are used in physical therapy. Infrared rays maintain the earth’s temperature. Classification of EM Waves
- 340. Application of Infraredrays Infrared lamps are used in physical therapy. Infrared rays maintain the earth’s temperature. Infrared detectors are used in earth satellites, both for military purpose and to observe the growth of crops. Classification of EM Waves
- 341. Application of Infraredrays Infrared lamps are used in physical therapy. Infrared rays maintain the earth’s temperature. Infrared detectors are used in earth satellites, both for military purpose and to observe the growth of crops. Electronic devices also emit infrared rays and widely used in the remote switches of household electronic systems such as TV sets, video recorders, and wi-fi systems. Classification of EM Waves
- 342. 4. Visible light Classificationof EM Waves
- 343. 4. Visible light Production- Electrons in atoms emit light when they move from higher energy level to lower energy level. Spectrum of visible light Classification of EM Waves
- 344. 4. Visible light Production- Electrons in atoms emit light when they move from higher energy level to lower energy level. Wavelength range- 400 nm to 700 nm Classification of EM Waves
- 345. 4. Visible light Production- Electrons in atoms emit light when they move from higher energy level to lower energy level. Wavelength range- 400 nm to 700 nm Detection - Eye photocells, photographic film Classification of EM Waves
- 346. Colour Wavelength (nm) Classificationof EM Waves
- 347. Colour Wavelength (nm) Violet400 - 450 Classification of EM Waves
- 348. Colour Wavelength (nm) Violet400 - 450 Blue 450 - 500 Classification of EM Waves
- 349. Colour Wavelength (nm) Violet400 - 450 Blue 450 - 500 Green 500 - 550 Classification of EM Waves
- 350. Colour Wavelength (nm) Violet400 - 450 Blue 450 - 500 Green 500 - 550 Yellow 550 - 600 Classification of EM Waves
- 351. Colour Wavelength (nm) Violet400 - 450 Blue 450 - 500 Green 500 - 550 Yellow 550 - 600 Orange 600 - 650 Classification of EM Waves
- 352. Colour Wavelength (nm) Violet400 - 450 Blue 450 - 500 Green 500 - 550 Yellow 550 - 600 Orange 600 - 650 Red 650 - 700 Classification of EM Waves
- 353. Application of visiblelight Visible light emitted or reflected from objects around us provides us information about the world. Classification of EM Waves
- 354. 5. Ultraviolet rays Classificationof EM Waves
- 355. 5. Ultraviolet rays Production-The sun is an important source of UV Rays. Inner shell electrons in atoms moving from one energy level to lower energy level. UV rays generation Classification of EM Waves
- 356. 5. Ultraviolet rays Production-The sun is an important source of UV Rays. Inner shell electrons in atoms moving from one energy level to lower energy level. Wavelength range- 400 nm to 1 nm Classification of EM Waves
- 357. 5. Ultraviolet rays Production-The sun is an important source of UV Rays. Inner shell electrons in atoms moving from one energy level to lower energy level. Wavelength range- 400 nm to 1 nm Detection - Photocells, photographic films Classification of EM Waves
- 358. Application of Ultravioletrays UV lamps are used to kill germs in water purifiers. Classification of EM Waves
- 359. Application of Ultravioletrays UV radiations can be focused into very narrow beams for high precision applications such as LASIK eye surgery. Classification of EM Waves
- 360. Application of Ultravioletrays Ozone layer in the atmosphere absorbs UV rays coming from sun. Classification of EM Waves
- 361. 6. X-rays Classification ofEM Waves
- 362. 6. X-rays Production- X-raystube or inner shell electrons X-rays generation Classification of EM Waves
- 363. 6. X-rays Production- X-raystube or inner shell electrons Wavelength range - 1 nm to 10 -3 nm Classification of EM Waves
- 364. 6. X-rays Production- X-raystube or inner shell electrons Wavelength range - 1 nm to 10 -3 nm Detection - photographic film, Geiger tubes, Ionisation chamber Classification of EM Waves
- 365. Application of X-rays X-raysare used as a diagnostic tool in medicine. X-rays of body Classification of EM Waves
- 366. Application of X-rays X-raysare also used in treatment of certain form of cancer. X-rays damage or destroy living tissues and organism. Destroying living tissues by using X rays Classification of EM Waves
- 367. Application of X-rays X-raysare used in luggage scanner at airport, railway station etc. Luggage scanner Classification of EM Waves
- 368. 7. Gamma rays Classificationof EM Waves
- 369. 7. Gamma rays Production- Radioactive decay of nucleus Classification of EM Waves
- 370. 7. Gamma rays Production- Radioactive decay of nucleus Wavelength range - less than 10 -3 nm Classification of EM Waves
- 371. 7. Gamma rays Production- Radioactive decay of nucleus Wavelength range - less than 10 -3 nm Detection - detected by observing Classification of EM Waves
- 372. Application of Gammarays They are used in medicine to destroy cancer cells. Classification of EM Waves
- 373. Application of Gammarays They are used in medicine to destroy cancer cells. They are used to treat malignant tumours in radiotherapy. Classification of EM Waves
- 374. Memory based question Readyfor challenge
- 375. Q. What typeof waves are used to transmit cellular telephone messages? (a) Gamma rays (b) Microwaves (c) Radio waves (d) Visible light
- 376. Q. What typeof waves are used to transmit cellular telephone messages? (a) Gamma rays (b) Microwaves (c) Radio waves (d) Visible light Pause video (Time duration : 2 minutes)
- 377. Q. What typeof waves are used to transmit cellular telephone messages? (a) Gamma rays (b) Microwaves (c) Radio waves (d) Visible light Sol. (c) Radio waves
- 378. Memory based question Readyfor challenge
- 379. Q. Which ofthe following is correct in order of lowest to highest frequency? (a) X-rays, visible light, microwaves (b) Ultraviolet rays, visible light, gamma rays (c) Microwaves,visible light, gamma rays (d) Gamma rays, visible light, x rays
- 380. Q. Which ofthe following is correct in order of lowest to highest frequency? (a) X-rays, visible light, microwaves (b) Ultraviolet rays, visible light, gamma rays (c) Microwaves,visible light, gamma rays (d) Gamma rays, visible light, x rays Pause video (Time duration : 2 minutes)
- 381. Q. Which ofthe following is correct in order of lowest to highest frequency? (a) X-rays, visible light, microwaves (b) Ultraviolet rays, visible light, gamma rays (c) Microwaves,visible light, gamma rays (d) Gamma rays, visible light, x rays Sol. (c) Microwaves, visible light, gamma rays
- 382. Memory based question Readyfor challenge
- 383. Q. Why areradio waves used extensively for communication? (a) Short wavelength (b) High frequency (c) High energy (d) Long wavelength
- 384. Q. Why areradio waves used extensively for communication? (a) Short wavelength (b) High frequency (c) High energy (d) Long wavelength Pause video (Time duration : 2 minutes)
- 385. Q. Why areradio waves used extensively for communication? (a) Short wavelength (b) High frequency (c) High energy (d) Long wavelength Sol. (d) Long wavelength
- 386. Memory based question Readyfor challenge
- 387. Q. The energyof the EM Waves is of the order of 15 kev. Which part of the spectrum does it belong (a) X-rays (b) Infrared rays (c) Ultraviolet rays (d) Gamma rays
- 388. Q. The energyof the EM Waves is of the order of 15 kev. Which part of the spectrum does it belong (a) X-rays (b) Infrared rays (c) Ultraviolet rays (d) Gamma rays Pause video (Time duration : 2 minutes)
- 389. Q. The energyof the EM Waves is of the order of 15 kev. Which part of the spectrum does it belong (a) X-rays (b) Infrared rays (c) Ultraviolet rays (d) Gamma rays Sol. (e) X-rays
- 390. Memory based question Readyfor challenge
- 391. Q. The conditionunder which a microwave oven heats up food containing water molecules most efficiently is (a) The frequency of the microwave must match the resonant frequency of water molecules (b) The frequency of the microwave has no relation with natural frequency of water molecules (c) Microwaves are heat waves , so always produce heat (d) Infrared waves produce heating in a microwave oven
- 392. Q. The conditionunder which a microwave oven heats up food containing water molecules most efficiently is (a) The frequency of the microwave must match the resonant frequency of water molecules (b) The frequency of the microwave has no relation with natural frequency of water molecules (c) Microwaves are heat waves , so always produce heat (d) Infrared waves produce heating in a microwave oven Pause video (Time duration : 2 minutes)
- 393. Q. The conditionunder which a microwave oven heats up food containing water molecules most efficiently is (a) The frequency of the microwave must match the resonant frequency of water molecules (b) The frequency of the microwave has no relation with natural frequency of water molecules (c) Microwaves are heat waves , so always produce heat (d) Infrared waves produce heating in a microwave oven Sol. (e) The frequency of the microwave must match the resonant frequency of water molecules
- 394. Memory based question Readyfor challenge
- 395. Q. The decreasingorder of wavelength of infrared, microwave, ultraviolet rays and Gamma rays is (a) Gamma rays, Ultraviolet rays, Infrared rays, Microwaves (b) Microwaves, Gamma rays, Ultraviolet rays, Infrared rays (c) Infrared rays, Microwaves, Gamma rays, Ultraviolet rays (d) Microwaves, Infrared rays, Ultraviolet rays, Gamma rays
- 396. Q. The decreasingorder of wavelength of infrared, microwave, ultraviolet rays and Gamma rays is (a) Gamma rays, Ultraviolet rays, Infrared rays, Microwaves (b) Microwaves, Gamma rays, Ultraviolet rays, Infrared rays (c) Infrared rays, Microwaves, Gamma rays, Ultraviolet rays (d) Microwaves, Infrared rays, Ultraviolet rays, Gamma rays Pause video (Time duration : 2 minutes)
- 397. Q. The decreasingorder of wavelength of infrared, microwave, ultraviolet rays and Gamma rays is (a) Gamma rays, Ultraviolet rays, Infrared rays, Microwaves (b) Microwaves, Gamma rays, Ultraviolet rays, Infrared rays (c) Infrared rays, Microwaves, Gamma rays, Ultraviolet rays (d) Microwaves, Infrared rays, Ultraviolet rays, Gamma rays Sol. (d) Microwaves, Infrared rays, Ultraviolet rays, Gamma rays
- 398. ● Wavelength isinversely proportional to the frequency. ● Frequency of Gamma rays is maximum and wavelength is minimum. ● Wavelength of radio waves is maximum and frequency is minimum. ● Wavelength of red colour is maximum in visible light. ● EM spectrum is the arrangement of EM Waves in increasing order of frequency or decreasing order of wavelength. Summary
Editor's Notes
- #19 Maxwell argued that not only an electric current but also a time varying electric field can generate magnetic field.
- #20 Maxwell argued that not only an electric current but also a time varying electric field can generate magnetic field.
- #21 Maxwell argued that not only an electric current but also a time varying electric field can generate magnetic field.
- #22 Maxwell argued that not only an electric current but also a time varying electric field can generate magnetic field.
- #23 Maxwell argued that not only an electric current but also a time varying electric field can generate magnetic field.
- #24 Maxwell argued that not only an electric current but also a time varying electric field can generate magnetic field.
- #25 Maxwell argued that not only an electric current but also a time varying electric field can generate magnetic field.
- #26 Maxwell argued that not only an electric current but also a time varying electric field can generate magnetic field.
- #27 Maxwell argued that not only an electric current but also a time varying electric field can generate magnetic field.
- #28 Maxwell argued that not only an electric current but also a time varying electric field can generate magnetic field.
- #29 Maxwell argued that not only an electric current but also a time varying electric field can generate magnetic field.
- #30 Maxwell argued that not only an electric current but also a time varying electric field can generate magnetic field.