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The Emitter Follower
1. PT. Electronusa Mechanical System [Research Center for Electronic and Mechanical]
The Emitter Follower
Umar Sidik.BEng.MSc*
Director of Engineering
PT. Electronusa Mechanical System
*umar.sidik@engineer.com
1. Introduction
Figure 1. The emitter follower
ܸா ൌ ܸ െ 0.7ܸ
While, the current output of transistor (ܫா ) is:
ܸா
ܫா ൌ
ܴா
In the computation, the emitter follower can be described as following.
Figure 2. Real circuit of the emitter follower
This circuit involve ݎ as the internal resistance of emitter. Furthermore, ݎ and ܴா form a parallel
resistance. Furthermore, this circuit can be simplified to be following circuit.
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2. PT. Electronusa Mechanical System [Research Center for Electronic and Mechanical]
Figure 3. The equivalent circuit of the follower emitter
In this circuit, the input impedance is:
ܴ ൌ ሺߚ 1ሻሺݎ ||ܴா ሻ
For BC547, ߚ is 200, ܴா is 10kΩ, while ݎ is:
25Ω
ݎ ൌ
ܫா
Where ܸா is (ܸ is 5 volt)
ܸ ൌ ܸா ܸா
5 ݒൌ 0.7 ݒ ܸா
ܸா ൌ 5 ݒെ 0.7ݒ
ܸா ൌ 4.3ݒ
Then ݎ is:
25Ω
ݎ ൌ
4.3ݒ
ݎ ൌ 5.81 Ω
Then, the input impedance is:
ܴ ൌ ሺߚ 1ሻሺݎ ||ܴா ሻ
ܴ ൌ ሺ200 1ሻሺ5.81||10݇Ωሻ
1 1
ܴ ൌ ሺ201ሻ ൬ ൰
5.81 10,000Ω
10,000 5.81
ܴ ൌ ሺ201ሻ ൬ ൰
58,100Ω 58,100Ω
10,005.81
ܴ ൌ ሺ201ሻ ൬ ൰
58,100Ω
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3. PT. Electronusa Mechanical System [Research Center for Electronic and Mechanical]
58,100Ω
ܴ ൌ ሺ201ሻ ൬ ൰
10,005.81
ܴ ൌ ሺ201ሻሺ5.80Ωሻ
ܴ ൌ 1,17݇Ω
2. Simulation
We try with the following data:
ܴா = 10kΩ
ܸ = 5v
The, the result:
Figure 4. Simulation of the emitter follower
ܸா ൌ 4.35ݒ
3. Result and Discussion
In the analytical work, ܸா is 4.3v due to ܸா is 0.7v, while in the simulation ܸா is 4.35v due to ܸா is
0.65v.
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