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PT. Electronusa Mechanical System         [Research Center for Electronic and Mechanical]

                                           The Emitter Follower

                                                           Umar Sidik.BEng.MSc*
                                                           Director of Engineering
                                                           PT. Electronusa Mechanical System

                                        *umar.sidik@engineer.com

1.   Introduction




                                      Figure 1. The emitter follower

                                               ܸா ൌ ܸ஻ െ 0.7ܸ

While, the current output of transistor (‫ܫ‬ா ) is:

                                                           ܸா
                                                    ‫ܫ‬ா ൌ
                                                           ܴா

In the computation, the emitter follower can be described as following.




                               Figure 2. Real circuit of the emitter follower

This circuit involve ‫ݎ‬௘ as the internal resistance of emitter. Furthermore, ‫ݎ‬௘ and ܴா form a parallel
resistance. Furthermore, this circuit can be simplified to be following circuit.




1|Page
PT. Electronusa Mechanical System         [Research Center for Electronic and Mechanical]




                        Figure 3. The equivalent circuit of the follower emitter

In this circuit, the input impedance is:

                                            ܴ௜௕ ൌ ሺߚ ൅ 1ሻሺ‫ݎ‬௘ ||ܴா ሻ

For BC547, ߚ is 200, ܴா is 10kΩ, while ‫ݎ‬௘ is:

                                                         25Ω
                                                  ‫ݎ‬௘ ൌ
                                                          ‫ܫ‬ா

Where ܸா is (ܸ஼஼ is 5 volt)

                                               ܸ஼஼ ൌ ܸ஻ா ൅ ܸா

                                               5‫ ݒ‬ൌ 0.7‫ ݒ‬൅ ܸா

                                               ܸா ൌ 5‫ ݒ‬െ 0.7‫ݒ‬

                                                  ܸா ൌ 4.3‫ݒ‬

Then ‫ݎ‬௘ is:

                                                         25Ω
                                                  ‫ݎ‬௘ ൌ
                                                         4.3‫ݒ‬

                                                 ‫ݎ‬௘ ൌ 5.81 Ω
Then, the input impedance is:

                                            ܴ௜௕ ൌ ሺߚ ൅ 1ሻሺ‫ݎ‬௘ ||ܴா ሻ

                                      ܴ௜௕ ൌ ሺ200 ൅ 1ሻሺ5.81||10݇Ωሻ

                                                        1     1
                                      ܴ௜௕ ൌ ሺ201ሻ ൬       ൅        ൰
                                                      5.81 10,000Ω

                                                     10,000   5.81
                                    ܴ௜௕ ൌ ሺ201ሻ ൬           ൅       ൰
                                                    58,100Ω 58,100Ω

                                                           10,005.81
                                           ܴ௜௕ ൌ ሺ201ሻ ൬            ൰
                                                            58,100Ω



2|Page
PT. Electronusa Mechanical System      [Research Center for Electronic and Mechanical]

                                                        58,100Ω
                                       ܴ௜௕ ൌ ሺ201ሻ ൬             ൰
                                                       10,005.81

                                          ܴ௜௕ ൌ ሺ201ሻሺ5.80Ωሻ

                                             ܴ௜௕ ൌ 1,17݇Ω

2. Simulation
We try with the following data:

ܴா = 10kΩ
ܸ = 5v
 ௖௖


The, the result:




                             Figure 4. Simulation of the emitter follower

                                              ܸா ൌ 4.35‫ݒ‬

3. Result and Discussion
In the analytical work, ܸா is 4.3v due to ܸ஻ா is 0.7v, while in the simulation ܸா is 4.35v due to ܸ஻ா is
0.65v.




3|Page

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The Emitter Follower

  • 1. PT. Electronusa Mechanical System [Research Center for Electronic and Mechanical] The Emitter Follower Umar Sidik.BEng.MSc* Director of Engineering PT. Electronusa Mechanical System *umar.sidik@engineer.com 1. Introduction Figure 1. The emitter follower ܸா ൌ ܸ஻ െ 0.7ܸ While, the current output of transistor (‫ܫ‬ா ) is: ܸா ‫ܫ‬ா ൌ ܴா In the computation, the emitter follower can be described as following. Figure 2. Real circuit of the emitter follower This circuit involve ‫ݎ‬௘ as the internal resistance of emitter. Furthermore, ‫ݎ‬௘ and ܴா form a parallel resistance. Furthermore, this circuit can be simplified to be following circuit. 1|Page
  • 2. PT. Electronusa Mechanical System [Research Center for Electronic and Mechanical] Figure 3. The equivalent circuit of the follower emitter In this circuit, the input impedance is: ܴ௜௕ ൌ ሺߚ ൅ 1ሻሺ‫ݎ‬௘ ||ܴா ሻ For BC547, ߚ is 200, ܴா is 10kΩ, while ‫ݎ‬௘ is: 25Ω ‫ݎ‬௘ ൌ ‫ܫ‬ா Where ܸா is (ܸ஼஼ is 5 volt) ܸ஼஼ ൌ ܸ஻ா ൅ ܸா 5‫ ݒ‬ൌ 0.7‫ ݒ‬൅ ܸா ܸா ൌ 5‫ ݒ‬െ 0.7‫ݒ‬ ܸா ൌ 4.3‫ݒ‬ Then ‫ݎ‬௘ is: 25Ω ‫ݎ‬௘ ൌ 4.3‫ݒ‬ ‫ݎ‬௘ ൌ 5.81 Ω Then, the input impedance is: ܴ௜௕ ൌ ሺߚ ൅ 1ሻሺ‫ݎ‬௘ ||ܴா ሻ ܴ௜௕ ൌ ሺ200 ൅ 1ሻሺ5.81||10݇Ωሻ 1 1 ܴ௜௕ ൌ ሺ201ሻ ൬ ൅ ൰ 5.81 10,000Ω 10,000 5.81 ܴ௜௕ ൌ ሺ201ሻ ൬ ൅ ൰ 58,100Ω 58,100Ω 10,005.81 ܴ௜௕ ൌ ሺ201ሻ ൬ ൰ 58,100Ω 2|Page
  • 3. PT. Electronusa Mechanical System [Research Center for Electronic and Mechanical] 58,100Ω ܴ௜௕ ൌ ሺ201ሻ ൬ ൰ 10,005.81 ܴ௜௕ ൌ ሺ201ሻሺ5.80Ωሻ ܴ௜௕ ൌ 1,17݇Ω 2. Simulation We try with the following data: ܴா = 10kΩ ܸ = 5v ௖௖ The, the result: Figure 4. Simulation of the emitter follower ܸா ൌ 4.35‫ݒ‬ 3. Result and Discussion In the analytical work, ܸா is 4.3v due to ܸ஻ா is 0.7v, while in the simulation ܸா is 4.35v due to ܸ஻ா is 0.65v. 3|Page