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Modul Bestari Matematik UPSR
                                                                                        JPNS 2011


UNIT 7

LENGTH


Objective Questions

1.      Convert 5 800 mm to cm.
        Tukarkan 5 800 mm kepada cm.
        A     0.58
        B     5.8
        C     58
        D     580

2.      8 m 72 cm + 6 m 19 cm =
        A      2 m 53 cm
        B      14 m 91 cm
        C      22 m 24 cm
        D      24 m 91 cm

3.      2160 cm – 98 cm =
        A     76. 4 cm
        B     118 cm
        C     2 062 cm
        D     2 602 cm

4.      The length of a pencil box is 25 cm. What is the total length of 6 similar pencil boxes,
        in m?
        Panjang sebuah kotak pensel ialah 25 cm. Berapakah jumlah panjang 6 buah kotak
        pensel yang sama, dalam m?
        A      0.15
        B      1.5
        C      15
        D      150


5.                cm + 21 cm = 5 021 cm

        A       5
        B       50
        C       500
        D       5 000


6.      0.75 m –            m = 0.56 m
        A      0.11
        B      0.19
        C      0.21

Unit 7 Length                                                                            Page 189
Modul Bestari Matematik UPSR
                                                                                       JPNS 2011


        D       0.29
7.      The total length of 9 similar pencils is 144 cm. What is the length of a pencil, in cm?
        Jumlah panjang 9 batang pensel yang sama ialah 144 cm. Berapakah panjang sebatang
        pensel, dalam cm?
        A       14
        B       16
        C       17
        D       18

8.      Subtract 69 m from 91 m.
        Tolakkan 69 m daripada 91 m.
        A      160 m
        B      156 m
        C      100 m
        D      22 m

9.      4.3 cm × 1 000 =
        A      43 cm
        B      430 cm
        C      4 300 cm
        D      43 000 cm

10.     100.8 cm ÷ 6 =
        A      1.68 cm
        B      16.8 cm
        C      168 cm
        D      1680 cm

11.     A rope measuring 96 m is cut into 8 equal parts. What is the length of each part?
        Seutas tali yang berukuran 96 m telah dipotong kepada 8 bahagian yang sama panjang.
        Berapakah panjang satu bahagian tali itu?
        A      11 m
        B      12 m
        C      13 m
        D      14 m

12.     7 m 98 cm – 5 m 89 cm =
        A      22 m 99 cm
        B      21 m 91 cm
        C      12 m 19 cm
        D      2 m 9 cm

13.     Calculate 4 m 8 cm ÷ 4 =
        Hitungkan 4 m 8 cm ÷ 4 =
        A      1 m 2 cm
        B      4 m 4 cm
        C      8 m 12 cm
        D      16 m 32 cm

Unit 7 Length                                                                           Page 190
Modul Bestari Matematik UPSR
                                                                                  JPNS 2011



14.     Find the difference between 8 cm 14 mm and 2 cm 8 mm
        Cari perbezaan antara 8 cm 14 mm dan 2 cm 8 mm
        A      22 cm 99 mm
        B      20 cm 19 mm
        C      10 cm 22 mm
        D      6 cm 6 mm

15.     Find the product of 1.25 m and 6
        Cari hasil darab 1.25 m dan 6.
        A      70.5 m
        B      7.5 m
        C      7.05 m
        D      7.005 m

16.     Convert 3.25 km to m
        Tukarkan 3.25 km kepada m
        A     325 m
        B     3 250 m
        C     32 500 m
        D     325 000 m

17.     9 km 700 m – 7 km 650 m =
        A     20 km 500 m
        B     16 km 150 m
        C     16 km 15 m
        D     2 km 50 m

18.     0.39 km × 100 =
        A      39 m
        B      390 m
        C      3 900 m
        D      39 000 m

19.     950 m ÷ 10 =
        A     0.95 km
        B     0.095 km
        C     0.0095 km
        D     0.00095 km

20.     120.5 km – 75 m =
        A      45.5 km
        B      120.425 km
        C      455 km
        D      120 425 km



Unit 7 Length                                                                      Page 191
Modul Bestari Matematik UPSR
                                                                                      JPNS 2011



21.     1.25 km × 6 =
        A      0.75 m
        B      7.50 m
        C      750 m
        D      7 500 m

22.     Find the difference between 0.9 km and 475 m.
        Cari beza antara 0.9 km dan 475 m
        A      385 m
        B      425 m
        C      474.1 m
        D      852.5 m

23.     1 957 m × 12 =
        A      23.484 km
        B      234.84 km
        C      2 348.4 km
        D      23 484 km

24.     6 km 125 m +             = 8 km 425 m

        What must be written into the box above?
        Apakah yang perlu diisi dalam petak di atas?
        A     1 km 700 m
        B     2 km 300 m
        C     14 km 300 m
        D     14 km 550 km

25.     1.75 km ÷ 10 =
        A      0.175 m
        B      1.75 m
        C      17.5 m
        D      175 m

26.     Mosque                School
        Masjid                Sekolah     John’s house
                   7.25 km
                                          Rumah John
                                 825 m
               Diagarm 1
                Rajah 1
        Diagram 1 shows a road map. Find the distance, in km, from the mosque to John’s house
        passing through the school.
        Rajah 1 menunjukkan peta jalan. Cari jarak, dalam km, dari masjid ke rumah John
        melalui sekolah
        A      8.075 km
        B      8.25 km
        C      7.25 km

Unit 7 Length                                                                          Page 192
Modul Bestari Matematik UPSR
                                                                                           JPNS 2011


        D       6.425 km

27.     A plot of land of 1 500 m long is divided equally into 12 parts. Find the length, in km, of
        each part.
        Sebidang tanah yang panjangnya 1 500 m dibahagikan kepada 12 bahagian yang sama
        besar. Cari panjang, dalam km setiap bahagian.
        A      0.125
        B      1.5
        C      15
        D      125


28.
        P       6 519 m        Q           R

                      Diagram 2
                       Rajah 2
        In Diagram 2, PQ is 4 250 m longer than QR. Calculate the length of QR, in km.
        Dalam Rajah 2. PQ adalah 4 250 m lebih panjang daripada QR. Kira panjang QR,
        dalam km.
        A      107.69
        B      22.69
        C      10.769
        D      2.269


29.     0.035 km of rope is cut into 5 parts of the same length. Find the length of each part, in m.
        Seutas tali yang panjangnya 0.035 km telah dipotong kepada 5 bahagian yang sama
        panjang. Cari panjang setiap bahagian tali itu, dalam m.
        A      70
        B      7
        C      0.7
        D      0.07


30.     Add 2.8 km and 412 m. Give the answer in m.
        Tambahkan 2.8 km dan 412 m. Berikan jawapan dalam m.
        A      4 148
        B      3 212
        C      414.8
        D      3.212




Unit 7 Length                                                                               Page 193
Modul Bestari Matematik UPSR
                                                                               JPNS 2011




UNIT 7

LENGTH


Subjective Questions

1.      1 cm =    __________ mm

2.      1 m = ______________cm

3.      28 cm = _____________ mm

4.      20 m = ______________cm

5.      7.4 m = ___________ cm

6.      14 mm = ___________ cm

7.      807 cm = ___________ mm


8.      3 m 51 cm + 7 m 64 cm = _________ m _________ cm




9.      85 m 33 cm – 49 m 90 cm = _________ m ________ cm




10.     Convert the height of the glass below in mm.
        Tukarkan tinggi gelas di bawah kepada mm.


                            12 cm




Unit 7 Length                                                                   Page 194
Modul Bestari Matematik UPSR
                                                                                     JPNS 2011




11.     The length of the nail below is __________ cm.
        Panjang paku di bawah ialah ______ cm




12.     52 mm = ___________ cm




13.     5 cm + 20 cm = ______________ cm




14.     60 m – 20 m = ____________ m




15.     5. 4 cm x 100 = _______________ cm




16.     25 mm ÷ 5 = _____________ mm




17.     Amy walks to the cake house from her house through the bookshop. How far does she
        walk altogether, in m?
        Amy berjalan ke kedai kek dari rumahnya melalui kedai buku. Berapa jauhkah dia
        berjalan, dalam m?
                             350 m                 670 m

                Amy’s house       Bookshop                          Cake house
                Rumah Amy         Kedai buku                        Kedai kek




Unit 7 Length                                                                         Page 195
Modul Bestari Matematik UPSR
                                                                              JPNS 2011




18.     What is the length of AB, in m?
        Apakah jarak AB, dalam m?                  550 m


           A                                   B            C

                                     1 020 m




19.     5 006 m = ___________ km



20.     0.051 km = __________ m



21.     7.64 km + 0.04 km = ____________ m




22.     481 m + 865 m = ______________ km




23.     7.18 km – 1.03 km = _____________ m




24.     6 032 m – 1 153 m = _____________ km




25.     0. 003 km  2 = ____________ km




Unit 7 Length                                                                  Page 196
Modul Bestari Matematik UPSR
                                                                                        JPNS 2011




26.     Diagram 26 shows a road map.
        Rajah 26 menunjukkan sebuah peta jalan.
                           Y

           8 km                              17 km




           X                                                    Z
                               Diagram 26
                                Rajah 26

        What is the distance from X to Z through Y, in km?
        Apakah jarak dari X ke Z melalui Y, dalam km?




27.     Diagram 27 shows the location of houses A, B, C.
        Rajah 27 menunjukkan lokasi rumah A, B, C.
                                                                       C
                  A
                                                           881 km
                      602 km
                                         B

                                     Diagram 27
                                      Rajah 27

        Find the difference in the distance from house A to house B and the distance from house
        B to house C, in km.
        Cari perbezaan jarak dari rumah A ke rumah B dan jarak rumah B ke rumah C, dalam
        km.




28.     567 m = ___________ km



29.     0.640 km = __________ m

Unit 7 Length                                                                            Page 197
Modul Bestari Matematik UPSR
                                                                                   JPNS 2011




30.     30 km + 4 km = ____________ m



31.     866 m + 200 m = ______________ km




32.     8.80 km – 2.30 km = _____________ m




33.     7489 m – 298 m = _____________ km




34.     388 m  6 = ____________ m




35.     0.400 km ÷ 4 = _____________ km




36.     Diagram 36 shows the positions of three houses P, Q and R along a street.
        Rajah 36 menunjukkan kedudukan tiga buah rumah P, Q dan R sepanjang sebatang
        jalan.

                                     3.27 km




         P            1.93 km                     Q                       R
                                     Diagram 36

Unit 7 Length                                                                       Page 198
Modul Bestari Matematik UPSR
                                                                                        JPNS 2011


                                        Rajah 36
        Calculate the distance, in km, between Q and R?
        Hitungkan jarak, dalam km, antara Q dan R

37.     Diagram 37 shows the location of houses T, U and V.
        Rajah 37 menunjukkan lokasi rumah T, U dan V.
                                                                       V
                  T

                                                          6661 km
                      321 km
                                         U

                                     Diagram 37
                                     Rajah 37

        Find the total distance, in km, from house T to house U and the distance from house U
        to house V.
        Cari jumlah jarak, dalam km, antara rumah T ke rumah U dan rumah U ke rumah V.




38.     Calculate 3.27 km – 216 m. Give your answer in m.
        Hitungkan 3.27 km – 216 m. Berikan jawapan anda dalam m.




39.     7.26 km ÷ 3 =
        Express your answer in m.
        Tukarkan jawapan anda dalam m.




40.     18.03 km – 386 m =
        Give your answer in km.
        Berikan jawapan anda dalam km.



Unit 7 Length                                                                            Page 199
Modul Bestari Matematik UPSR
                                                                                            JPNS 2011




41.     The distance from P to Q is 7 times the distance from Q to R. The distance from Q to R
        is 9.465 km. What is the distance from P to Q?
        Jarak dari P ke Q ialah 7 kaloi jarak dari Q ke R. Jarak dari Q ke R ialah 9.465 km.
        Berapakah jarak dari P ke Q?




42.     Mr Wong stays in Lok Kawi. He works in Inanam. He has to pass Putatan before
        reaching Inanam. The distance from Lok Kawi to Putatan is 7.8 km, while the distance
        from Putatan to Inanam is 20 km 750 m. How far is Mr Wong’s house from his office?
        En. Wong tinggal di Lok Kawi. Dia bekerja di Inanam. Dia perlu melalui Putatan
        sebelum sampai ke Inanam. Jarak dari Lok Kawi ke Putatan ialah 7.8 km, sementara
        jarak dari Putatan ke Inanam ialah 20 km 750 m. Berapa jauhkah pejabat En.Wong dari
        rumahnya?




43.     The perimeter of a basketball court is 127.5 m. Ranjit ran 9 rounds around the basketball
        court. How many kilometres did he run? Give your answer in three decimal places.
        Perimeter sebuah gelanggang bola keranjang ialah 127.5 m. Ranjit lari 9 pusingan
        mengelilingi gelanggang itu. Berapa kilometer Ranjit telah lari. Berikan jawapan anda
        dalam tiga tempat perpuluhan.




44.     In a map, 2 cm represents 2.5 km. What distance does 7 cm on the map represents?
        Dalam sebuah peta, 2 cm mewakili 2.5 km. Apakah jarak yang diwakili oleh 7 cm di atas
        peta itu?




45.     The length of a roll wire is 0.015 km. Fuad cuts it into three parts. The length of the first
                    4
        part is 3     m while the second part measures 6.04 m. Find the length, in m, of the third
                    5
        part.
        Panjang segulung dawai ialah 0.015 km. Fuad potong dawai itu kepada tiga bahagian.
                                              4
        Panjang bahagian pertama ialah 3        m manakala bahagian kedua berukuran 6.04 m.
                                              5
        Cari panjang, dalam m, bahagian ketiga.


Unit 7 Length                                                                                 Page 200
Modul Bestari Matematik UPSR
                                                                                           JPNS 2011




46.     After cutting 20 pieces of ribbons, each measuring 4.2 m, Husniza has 88.5 m of ribbon
        left. Find the length, in m, of the original piece of ribbon.
        Selepas memotong 20 helai reben, yang berukuran 4.2 m setiap satu, Reben Husniza
        masih tinggal 88.5 m. Cari panjang asal reben itu, dalam m.




                              1
47.     Mr Goon drove for 3     km before he stopped for a rest. Then he drove another 5 km
                              2
        900 m to reach his house. What is the total distance, in km, covered by Mr Goon?
                                      1
        En. Goon memandu sejauh 3       km sebelum dia berhenti untuk rehat. Kemudian, dia
                                      2
        memandu 5 km 900 m untuk sampai ke rumahnya. Berapakah jumlah jarak, dalam km,
        yang dilalui oleh En. Goon?




48.     The length of a roll wire is 216 m. Find the length, in km, of 8 similar rolls of copper
        wire.
        Panjang segulung dawai ialah 216 m. Cari panjang, dalam km, 8 gulung dawai yang
        sama panjang.




49.     Azlan jogged 5 km a day. If he jogs 5 days with the same distance, how far did he jog, in
        m, in five days?
        Azlan berjoging 5 km sehari. Jika dia berjoging selama 5 hari dengan jarak yang sama,
        berapa jauhkah dia berjoging, dalam m, dalam 5 hari.




50.     Amir has a rope which measures 7.26 m long. He cuts the rope into 3 equal parts. Find
        the length, in cm, of each rope.
        Amir ada seutas tali yang berukuran 7.26 m panjang. Dia potong tali itu kepada 3
        bahagian yang sama panjang. Cari panjang, dalam cm, setiap tali itu.


Unit 7 Length                                                                               Page 201
Modul Bestari Matematik UPSR
                                                                                           JPNS 2011




UNIT 7

LENGTH

Sample Answers

21.     7.64 km + 0.04 km = ____________ m

        7.64 km                7.68km × 1000 = 7680 m
      + 0.04 km
        7.68 km




48.     The length of a roll wire is 216 m. Find the length, in km, of 8 similar rolls of copper
        wire.
        Panjang segulung dawai ialah 216 m. Cari panjang, dalam km, 8 gulung dawai yang
        sama panjang.


           216 m               1728m ÷ 1000 = 1.728 km
        ×    8
          1728 m




Unit 7 Length                                                                               Page 202
Modul Bestari Matematik UPSR
                                                                              JPNS 2011




UNIT 7

LENGTH

Answers for Objective Questions


    1                 D             11       B            21              D
    2                 B             12       D            22              B
    3                 C             13       A            23              A
    4                 B             14       D            24              B
    5                 D             15       B            25              D
    6                 B             16       B            26              A
    7                 B             17       D            27              A
    8                 D             18       D            28              D
    9                 C             19       B            29              B
   10                 B             20       B            30              B



UNIT 7                                                               PETUNJUK:
                                                                     P – Pengetahuan
LENGTH                                                               K – Kaedah
                                                                     N – Nilai
Answers for Subjective Questions


Questions                                  Sub    Total
                      Suggested Answers                           Remarks
  No.                                     Marks   Marks
     1          10                         P1       1
     2          100                        P1       1

                28 cm × 10                 K1
     3                                              2
                280 mm                     N1


                20 m × 100                 K1
     4                                              2
                2 000 cm                   N1


                7.4 m × 100                K1
     5                                              2
                740 cm                     N1

     6                                     K1       2
                14 mm ÷ 10                 N1
                1.4 cm

Unit 7 Length                                                                  Page 203
Modul Bestari Matematik UPSR
                                                                                    JPNS 2011




Questions                                         Sub    Total
                      Suggested Answers                                 Remarks
  No.                                            Marks   Marks

                807 cm × 10                       K1
     7                                                     2
                8 070 mm                          N1

                      1
                      3   m    5   1   cm         K1
     8                                                     2
                 +    7   m    6   4   cm         N1
                 1    1   m    1   5   cm


                      8   5    m   3   3    cm
                 -    4   9    m   9   0    cm
                                                  K1
     9                3   5    m   4   3    cm             2
                                                  N1




                12 cm × 10                        K1
    10                                                     2
                120 mm                            N1

    11          5.4                               P1       1

                52 mm ÷ 10                        K1
    12                                                     2
                5.2 cm                            N1


                          5
                 +    2   0
                                                  K1
    13                2   5                                2
                                                  N1



                      6   0    m
                 -    2   0    m
                      4   0    m
                                                  K1
    14                                                     2
                                                  N1




                                                  K1
    15          5.4 cm × 100                               2
                                                  N1
                540 cm

Unit 7 Length                                                                        Page 204
Modul Bestari Matematik UPSR
                                                                                                   JPNS 2011



                                                                 K1
    16          25 mm ÷ 5                                                 2
                                                                 N1
                5 mm
                       1
                            3       5       0       m
                 +          6       7       0       m
                       1    0       2       0       m            K1
    17                                                                    2
                                                                 N1




Questions                                                        Sub    Total
                         Suggested Answers                                              Remarks
  No.                                                           Marks   Marks
                       0   9    12
                       1    0       2       0       m
                 -          5       5       0       m
                            4       7       0       m            K1
    18                                                                    2
                                                                 N1




                                                                 K1
    19          5.006 km                                                  2
                                                                 N1
                                                                 K1
    20          51 m                                                      2
                                                                 N1

                       7    .   6       4       k       m
                 +     0    .   0       4       k       m        K1
    21                 7    .   6       8       k       m                 2
                                                                 N1

                7.68 km × 1 000
                7 680 m
                     1
                       0    .   4       8       1       k   m    K1
    22           +     0    .   8       6       5       k   m             2
                                                                 N1
                       1    .   3       4       6       k   m



                       7    .   1       8       0       k   m
                 -     1    .   0       3       0       k   m    K1
    23                 6    .   1       5       0       k   m    K1       3
                                                                 N1
                6.150 km × 1 000
                6 150 m

Unit 7 Length                                                                                       Page 205
Modul Bestari Matematik UPSR
                                                                               JPNS 2011


                     5      9   12 12
                     6      0   3   2   m
                 -   1      1   5   3   m    K1
    24               4      8   7   9   m    K1       3
                                             N1
                4 879 m ÷ 1 000
                4.879 km
                                             K1
    25          0.003 km × 2                          2
                                             N1
                0.006 km
                                             K1
    26          8 km + 17 km                          2
                                             N1
                25 km

Questions                                    Sub    Total
                     Suggested Answers                              Remarks
  No.                                       Marks   Marks

                                             K1
    27          881 km – 602 km                       2
                                             N1
                279 km
                                             P1
    28                                                1
                0.567 km
                                             P1
    29                                                1
                640 m

                30 km + 4 km                 K1
    30                                                2
                34 km × 1 000                N1
                34 000 m

                866 m + 200 m                K1
    31                                                2
                1 066 m ÷ 1 000              N1
                1.066 km

                8.80 km – 2.30 km            K1
    32                                                2
                6.50 km × 1 000              N1
                6 500 m

                7 489 m – 298 m              K1
    33
                7 191 m ÷ 1 000              N1
                7.191 km
                                             K1
    34          388 m × 6                             2
                                             N1
                2 328 m
                                             K1
    35          0.400 km ÷ 4                          2
                                             N1
                0.100 km
                                             K1
    36          3.27 km – 1.93 km                     2
                                             N1
                1.34 km

Unit 7 Length                                                                   Page 206
Modul Bestari Matematik UPSR
                                                                                     JPNS 2011



                                                   K1
    37          321 km + 6 661 km                           2
                                                   N1
                6 982 km

                3.27 km – 216 m                    K1
    38                                                      2
                3 270 m – 216 m                    N1
                3 054 m

                7.26 km ÷ 3                        K1
    39                                                      2
                7 260 m ÷ 3                        N1
                2 420 m
                                                   K1
    40          18.03 km – 0.386 km                         2
                                                   N1
                17.644 km

Questions                                          Sub    Total
                       Suggested Answers                                  Remarks
  No.                                             Marks   Marks

                9.465 km × 7                       K1
    41                                                      2
                66.255 km                          N1

                7.8 km + 20 km 750 m               K1
    42          7.8 km + 20.75 km                           2
                                                   N1
                28.55 km
                9 × 127.5 m                        K1
    43          1 147.5 m ÷ 1 000                  K1       3
                1.1475 km                          N1
                1.148 km (three decimal places)
                1 cm on the map represents;
                2.5 km ÷ 2                         K1
                1.25 km
    44                                                      3
                7 cm represents;
                7 × 1.25 km                        K1
                8.75 km                            N1

                0.015 km = 15 m
                    4                              K1
    45          3     m = 3.80 m                            3
                    5
                15 m – 3.80 m – 6.04 m             K1
                5.16 m                             N1
                20 × 4.2 m                         K1
    46          84.0 m + 88.5 m                    K1       3
                172.5 m                            N1
    47                                                      3
                 1                                 K1
                3 km + 5 km 900 m
                 2
                3.5 km + 5.9 km                    K1

Unit 7 Length                                                                         Page 207
Modul Bestari Matematik UPSR
                                                                  JPNS 2011


                9.4 km                N1

                8 × 216 m = 1 728 m   K1
    48                                K1   3
                1 728 m ÷ 1 000
                1.728 km              N1

                5 km × 5 = 25 km      K1
    49          25 km × 1 000         K1   3
                25 000 m              N1
                7.26 m ÷ 3 = 2.42 m   K1
    50          2.42 m × 100          K1   3
                242 cm                N1




Unit 7 Length                                                      Page 208

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Unit 7 length

  • 1. Modul Bestari Matematik UPSR JPNS 2011 UNIT 7 LENGTH Objective Questions 1. Convert 5 800 mm to cm. Tukarkan 5 800 mm kepada cm. A 0.58 B 5.8 C 58 D 580 2. 8 m 72 cm + 6 m 19 cm = A 2 m 53 cm B 14 m 91 cm C 22 m 24 cm D 24 m 91 cm 3. 2160 cm – 98 cm = A 76. 4 cm B 118 cm C 2 062 cm D 2 602 cm 4. The length of a pencil box is 25 cm. What is the total length of 6 similar pencil boxes, in m? Panjang sebuah kotak pensel ialah 25 cm. Berapakah jumlah panjang 6 buah kotak pensel yang sama, dalam m? A 0.15 B 1.5 C 15 D 150 5. cm + 21 cm = 5 021 cm A 5 B 50 C 500 D 5 000 6. 0.75 m – m = 0.56 m A 0.11 B 0.19 C 0.21 Unit 7 Length Page 189
  • 2. Modul Bestari Matematik UPSR JPNS 2011 D 0.29 7. The total length of 9 similar pencils is 144 cm. What is the length of a pencil, in cm? Jumlah panjang 9 batang pensel yang sama ialah 144 cm. Berapakah panjang sebatang pensel, dalam cm? A 14 B 16 C 17 D 18 8. Subtract 69 m from 91 m. Tolakkan 69 m daripada 91 m. A 160 m B 156 m C 100 m D 22 m 9. 4.3 cm × 1 000 = A 43 cm B 430 cm C 4 300 cm D 43 000 cm 10. 100.8 cm ÷ 6 = A 1.68 cm B 16.8 cm C 168 cm D 1680 cm 11. A rope measuring 96 m is cut into 8 equal parts. What is the length of each part? Seutas tali yang berukuran 96 m telah dipotong kepada 8 bahagian yang sama panjang. Berapakah panjang satu bahagian tali itu? A 11 m B 12 m C 13 m D 14 m 12. 7 m 98 cm – 5 m 89 cm = A 22 m 99 cm B 21 m 91 cm C 12 m 19 cm D 2 m 9 cm 13. Calculate 4 m 8 cm ÷ 4 = Hitungkan 4 m 8 cm ÷ 4 = A 1 m 2 cm B 4 m 4 cm C 8 m 12 cm D 16 m 32 cm Unit 7 Length Page 190
  • 3. Modul Bestari Matematik UPSR JPNS 2011 14. Find the difference between 8 cm 14 mm and 2 cm 8 mm Cari perbezaan antara 8 cm 14 mm dan 2 cm 8 mm A 22 cm 99 mm B 20 cm 19 mm C 10 cm 22 mm D 6 cm 6 mm 15. Find the product of 1.25 m and 6 Cari hasil darab 1.25 m dan 6. A 70.5 m B 7.5 m C 7.05 m D 7.005 m 16. Convert 3.25 km to m Tukarkan 3.25 km kepada m A 325 m B 3 250 m C 32 500 m D 325 000 m 17. 9 km 700 m – 7 km 650 m = A 20 km 500 m B 16 km 150 m C 16 km 15 m D 2 km 50 m 18. 0.39 km × 100 = A 39 m B 390 m C 3 900 m D 39 000 m 19. 950 m ÷ 10 = A 0.95 km B 0.095 km C 0.0095 km D 0.00095 km 20. 120.5 km – 75 m = A 45.5 km B 120.425 km C 455 km D 120 425 km Unit 7 Length Page 191
  • 4. Modul Bestari Matematik UPSR JPNS 2011 21. 1.25 km × 6 = A 0.75 m B 7.50 m C 750 m D 7 500 m 22. Find the difference between 0.9 km and 475 m. Cari beza antara 0.9 km dan 475 m A 385 m B 425 m C 474.1 m D 852.5 m 23. 1 957 m × 12 = A 23.484 km B 234.84 km C 2 348.4 km D 23 484 km 24. 6 km 125 m + = 8 km 425 m What must be written into the box above? Apakah yang perlu diisi dalam petak di atas? A 1 km 700 m B 2 km 300 m C 14 km 300 m D 14 km 550 km 25. 1.75 km ÷ 10 = A 0.175 m B 1.75 m C 17.5 m D 175 m 26. Mosque School Masjid Sekolah John’s house 7.25 km Rumah John 825 m Diagarm 1 Rajah 1 Diagram 1 shows a road map. Find the distance, in km, from the mosque to John’s house passing through the school. Rajah 1 menunjukkan peta jalan. Cari jarak, dalam km, dari masjid ke rumah John melalui sekolah A 8.075 km B 8.25 km C 7.25 km Unit 7 Length Page 192
  • 5. Modul Bestari Matematik UPSR JPNS 2011 D 6.425 km 27. A plot of land of 1 500 m long is divided equally into 12 parts. Find the length, in km, of each part. Sebidang tanah yang panjangnya 1 500 m dibahagikan kepada 12 bahagian yang sama besar. Cari panjang, dalam km setiap bahagian. A 0.125 B 1.5 C 15 D 125 28. P 6 519 m Q R Diagram 2 Rajah 2 In Diagram 2, PQ is 4 250 m longer than QR. Calculate the length of QR, in km. Dalam Rajah 2. PQ adalah 4 250 m lebih panjang daripada QR. Kira panjang QR, dalam km. A 107.69 B 22.69 C 10.769 D 2.269 29. 0.035 km of rope is cut into 5 parts of the same length. Find the length of each part, in m. Seutas tali yang panjangnya 0.035 km telah dipotong kepada 5 bahagian yang sama panjang. Cari panjang setiap bahagian tali itu, dalam m. A 70 B 7 C 0.7 D 0.07 30. Add 2.8 km and 412 m. Give the answer in m. Tambahkan 2.8 km dan 412 m. Berikan jawapan dalam m. A 4 148 B 3 212 C 414.8 D 3.212 Unit 7 Length Page 193
  • 6. Modul Bestari Matematik UPSR JPNS 2011 UNIT 7 LENGTH Subjective Questions 1. 1 cm = __________ mm 2. 1 m = ______________cm 3. 28 cm = _____________ mm 4. 20 m = ______________cm 5. 7.4 m = ___________ cm 6. 14 mm = ___________ cm 7. 807 cm = ___________ mm 8. 3 m 51 cm + 7 m 64 cm = _________ m _________ cm 9. 85 m 33 cm – 49 m 90 cm = _________ m ________ cm 10. Convert the height of the glass below in mm. Tukarkan tinggi gelas di bawah kepada mm. 12 cm Unit 7 Length Page 194
  • 7. Modul Bestari Matematik UPSR JPNS 2011 11. The length of the nail below is __________ cm. Panjang paku di bawah ialah ______ cm 12. 52 mm = ___________ cm 13. 5 cm + 20 cm = ______________ cm 14. 60 m – 20 m = ____________ m 15. 5. 4 cm x 100 = _______________ cm 16. 25 mm ÷ 5 = _____________ mm 17. Amy walks to the cake house from her house through the bookshop. How far does she walk altogether, in m? Amy berjalan ke kedai kek dari rumahnya melalui kedai buku. Berapa jauhkah dia berjalan, dalam m? 350 m 670 m Amy’s house Bookshop Cake house Rumah Amy Kedai buku Kedai kek Unit 7 Length Page 195
  • 8. Modul Bestari Matematik UPSR JPNS 2011 18. What is the length of AB, in m? Apakah jarak AB, dalam m? 550 m A B C 1 020 m 19. 5 006 m = ___________ km 20. 0.051 km = __________ m 21. 7.64 km + 0.04 km = ____________ m 22. 481 m + 865 m = ______________ km 23. 7.18 km – 1.03 km = _____________ m 24. 6 032 m – 1 153 m = _____________ km 25. 0. 003 km  2 = ____________ km Unit 7 Length Page 196
  • 9. Modul Bestari Matematik UPSR JPNS 2011 26. Diagram 26 shows a road map. Rajah 26 menunjukkan sebuah peta jalan. Y 8 km 17 km X Z Diagram 26 Rajah 26 What is the distance from X to Z through Y, in km? Apakah jarak dari X ke Z melalui Y, dalam km? 27. Diagram 27 shows the location of houses A, B, C. Rajah 27 menunjukkan lokasi rumah A, B, C. C A 881 km 602 km B Diagram 27 Rajah 27 Find the difference in the distance from house A to house B and the distance from house B to house C, in km. Cari perbezaan jarak dari rumah A ke rumah B dan jarak rumah B ke rumah C, dalam km. 28. 567 m = ___________ km 29. 0.640 km = __________ m Unit 7 Length Page 197
  • 10. Modul Bestari Matematik UPSR JPNS 2011 30. 30 km + 4 km = ____________ m 31. 866 m + 200 m = ______________ km 32. 8.80 km – 2.30 km = _____________ m 33. 7489 m – 298 m = _____________ km 34. 388 m  6 = ____________ m 35. 0.400 km ÷ 4 = _____________ km 36. Diagram 36 shows the positions of three houses P, Q and R along a street. Rajah 36 menunjukkan kedudukan tiga buah rumah P, Q dan R sepanjang sebatang jalan. 3.27 km P 1.93 km Q R Diagram 36 Unit 7 Length Page 198
  • 11. Modul Bestari Matematik UPSR JPNS 2011 Rajah 36 Calculate the distance, in km, between Q and R? Hitungkan jarak, dalam km, antara Q dan R 37. Diagram 37 shows the location of houses T, U and V. Rajah 37 menunjukkan lokasi rumah T, U dan V. V T 6661 km 321 km U Diagram 37 Rajah 37 Find the total distance, in km, from house T to house U and the distance from house U to house V. Cari jumlah jarak, dalam km, antara rumah T ke rumah U dan rumah U ke rumah V. 38. Calculate 3.27 km – 216 m. Give your answer in m. Hitungkan 3.27 km – 216 m. Berikan jawapan anda dalam m. 39. 7.26 km ÷ 3 = Express your answer in m. Tukarkan jawapan anda dalam m. 40. 18.03 km – 386 m = Give your answer in km. Berikan jawapan anda dalam km. Unit 7 Length Page 199
  • 12. Modul Bestari Matematik UPSR JPNS 2011 41. The distance from P to Q is 7 times the distance from Q to R. The distance from Q to R is 9.465 km. What is the distance from P to Q? Jarak dari P ke Q ialah 7 kaloi jarak dari Q ke R. Jarak dari Q ke R ialah 9.465 km. Berapakah jarak dari P ke Q? 42. Mr Wong stays in Lok Kawi. He works in Inanam. He has to pass Putatan before reaching Inanam. The distance from Lok Kawi to Putatan is 7.8 km, while the distance from Putatan to Inanam is 20 km 750 m. How far is Mr Wong’s house from his office? En. Wong tinggal di Lok Kawi. Dia bekerja di Inanam. Dia perlu melalui Putatan sebelum sampai ke Inanam. Jarak dari Lok Kawi ke Putatan ialah 7.8 km, sementara jarak dari Putatan ke Inanam ialah 20 km 750 m. Berapa jauhkah pejabat En.Wong dari rumahnya? 43. The perimeter of a basketball court is 127.5 m. Ranjit ran 9 rounds around the basketball court. How many kilometres did he run? Give your answer in three decimal places. Perimeter sebuah gelanggang bola keranjang ialah 127.5 m. Ranjit lari 9 pusingan mengelilingi gelanggang itu. Berapa kilometer Ranjit telah lari. Berikan jawapan anda dalam tiga tempat perpuluhan. 44. In a map, 2 cm represents 2.5 km. What distance does 7 cm on the map represents? Dalam sebuah peta, 2 cm mewakili 2.5 km. Apakah jarak yang diwakili oleh 7 cm di atas peta itu? 45. The length of a roll wire is 0.015 km. Fuad cuts it into three parts. The length of the first 4 part is 3 m while the second part measures 6.04 m. Find the length, in m, of the third 5 part. Panjang segulung dawai ialah 0.015 km. Fuad potong dawai itu kepada tiga bahagian. 4 Panjang bahagian pertama ialah 3 m manakala bahagian kedua berukuran 6.04 m. 5 Cari panjang, dalam m, bahagian ketiga. Unit 7 Length Page 200
  • 13. Modul Bestari Matematik UPSR JPNS 2011 46. After cutting 20 pieces of ribbons, each measuring 4.2 m, Husniza has 88.5 m of ribbon left. Find the length, in m, of the original piece of ribbon. Selepas memotong 20 helai reben, yang berukuran 4.2 m setiap satu, Reben Husniza masih tinggal 88.5 m. Cari panjang asal reben itu, dalam m. 1 47. Mr Goon drove for 3 km before he stopped for a rest. Then he drove another 5 km 2 900 m to reach his house. What is the total distance, in km, covered by Mr Goon? 1 En. Goon memandu sejauh 3 km sebelum dia berhenti untuk rehat. Kemudian, dia 2 memandu 5 km 900 m untuk sampai ke rumahnya. Berapakah jumlah jarak, dalam km, yang dilalui oleh En. Goon? 48. The length of a roll wire is 216 m. Find the length, in km, of 8 similar rolls of copper wire. Panjang segulung dawai ialah 216 m. Cari panjang, dalam km, 8 gulung dawai yang sama panjang. 49. Azlan jogged 5 km a day. If he jogs 5 days with the same distance, how far did he jog, in m, in five days? Azlan berjoging 5 km sehari. Jika dia berjoging selama 5 hari dengan jarak yang sama, berapa jauhkah dia berjoging, dalam m, dalam 5 hari. 50. Amir has a rope which measures 7.26 m long. He cuts the rope into 3 equal parts. Find the length, in cm, of each rope. Amir ada seutas tali yang berukuran 7.26 m panjang. Dia potong tali itu kepada 3 bahagian yang sama panjang. Cari panjang, dalam cm, setiap tali itu. Unit 7 Length Page 201
  • 14. Modul Bestari Matematik UPSR JPNS 2011 UNIT 7 LENGTH Sample Answers 21. 7.64 km + 0.04 km = ____________ m 7.64 km 7.68km × 1000 = 7680 m + 0.04 km 7.68 km 48. The length of a roll wire is 216 m. Find the length, in km, of 8 similar rolls of copper wire. Panjang segulung dawai ialah 216 m. Cari panjang, dalam km, 8 gulung dawai yang sama panjang. 216 m 1728m ÷ 1000 = 1.728 km × 8 1728 m Unit 7 Length Page 202
  • 15. Modul Bestari Matematik UPSR JPNS 2011 UNIT 7 LENGTH Answers for Objective Questions 1 D 11 B 21 D 2 B 12 D 22 B 3 C 13 A 23 A 4 B 14 D 24 B 5 D 15 B 25 D 6 B 16 B 26 A 7 B 17 D 27 A 8 D 18 D 28 D 9 C 19 B 29 B 10 B 20 B 30 B UNIT 7 PETUNJUK: P – Pengetahuan LENGTH K – Kaedah N – Nilai Answers for Subjective Questions Questions Sub Total Suggested Answers Remarks No. Marks Marks 1 10 P1 1 2 100 P1 1 28 cm × 10 K1 3 2 280 mm N1 20 m × 100 K1 4 2 2 000 cm N1 7.4 m × 100 K1 5 2 740 cm N1 6 K1 2 14 mm ÷ 10 N1 1.4 cm Unit 7 Length Page 203
  • 16. Modul Bestari Matematik UPSR JPNS 2011 Questions Sub Total Suggested Answers Remarks No. Marks Marks 807 cm × 10 K1 7 2 8 070 mm N1 1 3 m 5 1 cm K1 8 2 + 7 m 6 4 cm N1 1 1 m 1 5 cm 8 5 m 3 3 cm - 4 9 m 9 0 cm K1 9 3 5 m 4 3 cm 2 N1 12 cm × 10 K1 10 2 120 mm N1 11 5.4 P1 1 52 mm ÷ 10 K1 12 2 5.2 cm N1 5 + 2 0 K1 13 2 5 2 N1 6 0 m - 2 0 m 4 0 m K1 14 2 N1 K1 15 5.4 cm × 100 2 N1 540 cm Unit 7 Length Page 204
  • 17. Modul Bestari Matematik UPSR JPNS 2011 K1 16 25 mm ÷ 5 2 N1 5 mm 1 3 5 0 m + 6 7 0 m 1 0 2 0 m K1 17 2 N1 Questions Sub Total Suggested Answers Remarks No. Marks Marks 0 9 12 1 0 2 0 m - 5 5 0 m 4 7 0 m K1 18 2 N1 K1 19 5.006 km 2 N1 K1 20 51 m 2 N1 7 . 6 4 k m + 0 . 0 4 k m K1 21 7 . 6 8 k m 2 N1 7.68 km × 1 000 7 680 m 1 0 . 4 8 1 k m K1 22 + 0 . 8 6 5 k m 2 N1 1 . 3 4 6 k m 7 . 1 8 0 k m - 1 . 0 3 0 k m K1 23 6 . 1 5 0 k m K1 3 N1 6.150 km × 1 000 6 150 m Unit 7 Length Page 205
  • 18. Modul Bestari Matematik UPSR JPNS 2011 5 9 12 12 6 0 3 2 m - 1 1 5 3 m K1 24 4 8 7 9 m K1 3 N1 4 879 m ÷ 1 000 4.879 km K1 25 0.003 km × 2 2 N1 0.006 km K1 26 8 km + 17 km 2 N1 25 km Questions Sub Total Suggested Answers Remarks No. Marks Marks K1 27 881 km – 602 km 2 N1 279 km P1 28 1 0.567 km P1 29 1 640 m 30 km + 4 km K1 30 2 34 km × 1 000 N1 34 000 m 866 m + 200 m K1 31 2 1 066 m ÷ 1 000 N1 1.066 km 8.80 km – 2.30 km K1 32 2 6.50 km × 1 000 N1 6 500 m 7 489 m – 298 m K1 33 7 191 m ÷ 1 000 N1 7.191 km K1 34 388 m × 6 2 N1 2 328 m K1 35 0.400 km ÷ 4 2 N1 0.100 km K1 36 3.27 km – 1.93 km 2 N1 1.34 km Unit 7 Length Page 206
  • 19. Modul Bestari Matematik UPSR JPNS 2011 K1 37 321 km + 6 661 km 2 N1 6 982 km 3.27 km – 216 m K1 38 2 3 270 m – 216 m N1 3 054 m 7.26 km ÷ 3 K1 39 2 7 260 m ÷ 3 N1 2 420 m K1 40 18.03 km – 0.386 km 2 N1 17.644 km Questions Sub Total Suggested Answers Remarks No. Marks Marks 9.465 km × 7 K1 41 2 66.255 km N1 7.8 km + 20 km 750 m K1 42 7.8 km + 20.75 km 2 N1 28.55 km 9 × 127.5 m K1 43 1 147.5 m ÷ 1 000 K1 3 1.1475 km N1 1.148 km (three decimal places) 1 cm on the map represents; 2.5 km ÷ 2 K1 1.25 km 44 3 7 cm represents; 7 × 1.25 km K1 8.75 km N1 0.015 km = 15 m 4 K1 45 3 m = 3.80 m 3 5 15 m – 3.80 m – 6.04 m K1 5.16 m N1 20 × 4.2 m K1 46 84.0 m + 88.5 m K1 3 172.5 m N1 47 3 1 K1 3 km + 5 km 900 m 2 3.5 km + 5.9 km K1 Unit 7 Length Page 207
  • 20. Modul Bestari Matematik UPSR JPNS 2011 9.4 km N1 8 × 216 m = 1 728 m K1 48 K1 3 1 728 m ÷ 1 000 1.728 km N1 5 km × 5 = 25 km K1 49 25 km × 1 000 K1 3 25 000 m N1 7.26 m ÷ 3 = 2.42 m K1 50 2.42 m × 100 K1 3 242 cm N1 Unit 7 Length Page 208