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Introduction to Orders of Operations and
            Linear Equations
Order Of Operations

Rule 1:            First perform any calculations inside
                   parentheses.

Rule 2:            Next perform all multiplications and
                   divisions, working from left to right.



Rule 3:            Lastly, perform all additions and
                   subtractions, working from left to right.
Example 3:        Evaluate 9 - 5 ÷
                    (8 - 3) x 2 + 6
                    using the order
                    of operations.




  Solution:

  Step 1:           9 - 5 ÷ (8 - 3) x 2 =               9-5÷5x2+6         Parentheses
                    +6
  Step 2:           9-5÷5x2+6          =                9-1x2+6           Division

  Step 3:           9-1x2+6            =                9-2+6             Multiplication

  Step 4:           9-2+6              =                7+6               Subtraction

  Step 5:           7+6                =                13                Addition

In Examples 2 and 3, you will notice that multiplication and division were evaluated
from left to right according to Rule 2. Similarly, addition and subtraction were evaluated
from left to right, according to Rule 3.
Example 2:   Evaluate 3 + 6 x
             (5 + 4) ÷ 3 - 7
             using the order
             of operations.




Solution:
Step 1:      3 + 6 x (5 + 4) ÷ 3 =   3 + 6 x 9 ÷ 3 - 7 Parentheses
             -7
Step 2:      3+6x9÷3-7          =    3 + 54 ÷ 3 - 7   Multiplication
Step 3:      3 + 54 ÷ 3 - 7     =    3 + 18 - 7       Division
Step 4:      3 + 18 - 7         =    21 - 7           Addition
Step 5:      21 - 7             =    14               Subtraction
Example Evaluate
4:      150 ÷ (6
        + 3 x 8) -
        5 using
        the
        order of
        operatio
        ns.

Solution
:
Step 1: 150 ÷ (6     =                  150 ÷ (6 + 24) - 5       Multiplication inside
         + 3 x 8)                                                Parentheses
         -5
Step 2: 150 ÷ (6     =                  150 ÷ 30 - 5             Addition inside Parentheses
         + 24) - 5
Step 3: 150 ÷        =                  5-5                      Division
         30 - 5
Step 4: 5 - 5        =                  0                        Subtracti

  When two or more operations occur inside a set of parentheses, these operations should
  be evaluated according to Rules 2 and 3. This is done in Example 4 below.
Example 5:   Evaluate the arithmetic expression below:




Solution:

             This problem includes a fraction bar (also called a
             vinculum), which means we must divide the
             numerator by the denominator. However, we must
             first perform all calculations above and below the
             fraction bar BEFORE dividing.




Thus
             Evaluating this expression, we get:
Multiplying a Fraction and a Whole Number


   4 X 2/3 =


4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3
Multiplying a Fraction and a Whole Number


   4 X 2/3 =


4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3
Multiplying a Fraction and a Whole Number


    4 X 2/3 =


4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3
Multiplying a Fraction and a Whole Number


    4 X 2/3 =


4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3
Multiplying a Fraction and a Whole Number


    4 X 2/3 =


4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3
Problem One
T= 2
V= 1
P=14
R=3
C=0
I=2
F=0
Problem Two
T= 3
V= 0
P=1
R=17
C=7
I=4
F=1

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Fantacy foot ball introduction

  • 1. Introduction to Orders of Operations and Linear Equations
  • 2. Order Of Operations Rule 1: First perform any calculations inside parentheses. Rule 2: Next perform all multiplications and divisions, working from left to right. Rule 3: Lastly, perform all additions and subtractions, working from left to right.
  • 3. Example 3: Evaluate 9 - 5 ÷ (8 - 3) x 2 + 6 using the order of operations. Solution: Step 1: 9 - 5 ÷ (8 - 3) x 2 = 9-5÷5x2+6 Parentheses +6 Step 2: 9-5÷5x2+6 = 9-1x2+6 Division Step 3: 9-1x2+6 = 9-2+6 Multiplication Step 4: 9-2+6 = 7+6 Subtraction Step 5: 7+6 = 13 Addition In Examples 2 and 3, you will notice that multiplication and division were evaluated from left to right according to Rule 2. Similarly, addition and subtraction were evaluated from left to right, according to Rule 3.
  • 4. Example 2: Evaluate 3 + 6 x (5 + 4) ÷ 3 - 7 using the order of operations. Solution: Step 1: 3 + 6 x (5 + 4) ÷ 3 = 3 + 6 x 9 ÷ 3 - 7 Parentheses -7 Step 2: 3+6x9÷3-7 = 3 + 54 ÷ 3 - 7 Multiplication Step 3: 3 + 54 ÷ 3 - 7 = 3 + 18 - 7 Division Step 4: 3 + 18 - 7 = 21 - 7 Addition Step 5: 21 - 7 = 14 Subtraction
  • 5. Example Evaluate 4: 150 ÷ (6 + 3 x 8) - 5 using the order of operatio ns. Solution : Step 1: 150 ÷ (6 = 150 ÷ (6 + 24) - 5 Multiplication inside + 3 x 8) Parentheses -5 Step 2: 150 ÷ (6 = 150 ÷ 30 - 5 Addition inside Parentheses + 24) - 5 Step 3: 150 ÷ = 5-5 Division 30 - 5 Step 4: 5 - 5 = 0 Subtracti When two or more operations occur inside a set of parentheses, these operations should be evaluated according to Rules 2 and 3. This is done in Example 4 below.
  • 6. Example 5: Evaluate the arithmetic expression below: Solution: This problem includes a fraction bar (also called a vinculum), which means we must divide the numerator by the denominator. However, we must first perform all calculations above and below the fraction bar BEFORE dividing. Thus Evaluating this expression, we get:
  • 7.
  • 8. Multiplying a Fraction and a Whole Number 4 X 2/3 = 4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3
  • 9. Multiplying a Fraction and a Whole Number 4 X 2/3 = 4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3
  • 10. Multiplying a Fraction and a Whole Number 4 X 2/3 = 4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3
  • 11. Multiplying a Fraction and a Whole Number 4 X 2/3 = 4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3
  • 12. Multiplying a Fraction and a Whole Number 4 X 2/3 = 4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3
  • 13. Problem One T= 2 V= 1 P=14 R=3 C=0 I=2 F=0
  • 14. Problem Two T= 3 V= 0 P=1 R=17 C=7 I=4 F=1