Parsing Expression With Xtext

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Sven Efftinge

A slide show that shows how expression trees are created with Xtext.

Software

Addition returns Expression:
Multiplication ({AdditionalExpression.left=current} '+' right=Multiplication)*;
Multiplication returns Expression:
PrimaryExpression ({MultiplyExpression.left=current} '*' right=PrimaryExpression)*;
PrimaryExpression returns Expression:
{NumberLiteral} value=INT |
'(' Addition ')';
( 1 + 20 ) * 2
1.Addition
StackAST
Grammar
Text

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Please make it to clear 12-95. The basketball passed through the hoop even though it barely cleared the hands of the player B who attempted to block it. Neglecting the size of the ball, determine the magnitude vn of its initial velocity and the height h of the ball when it passes over player B 10 ft 5 ft Prob. 12-95 Solution Consider the motion along horizontal direction Vox = initial velocity in horizontal direction = Va Cos30 X = horizontal distance = 25 + 3 = 28 ft t = time taken t = X / Vox = 28/(Va Cos30) eq-1 consider the motion in vertical direction Y = vertical displacement = 10 - 7 = 3 ft a = acceleration = - 32.2 Voy = initial velocity = Va Sin30 t = time taken using the equation Y = Voy t + (0.5) a t2 3 = (Va Sin30) (28/(Va Cos30)) + (0.5) (- 32.2) (28/(Va Cos30))2 Va = 35.8 m/s t\' = time taken to reach B = 25 / (Va Cos30) = 25 / (35.8 Cos30) = 0.81 sec h = 7 + Voy t\' + (0.5) a t\'2 h = 7 + (35.8 Sin30) (0.81) + (0.5) (- 32.2) (0.81)2 h = 10.94 ft.

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