Límites primer de batchillerato
- 1. Robert Masip Quintana Lmites
a) lim
x!1
x6
x3 3x2 + 3x 1
=
I
I = IND
lim
x!1
x6
x3
= lim
x!1
x3
1
= lim
x!1x3
= ( I)
3
= I
b) lim
x!1
x 1
x3 3x2 + 3x 1
=
I
I = IND
lim
x!1
x 1
x3 3x2 + 3x 1
= lim
x!1
x
x3
= lim
x!1
1
x2
= lim
x!1
1
(I)
2
= 0
c) lim
x!1
px 1
x 1
= lim
x!1
(
px 1)(
px+ 1)
(x 1)(
px+ 1)
(
px 1)(
px+ 1) = (
px 1)
2
ya que A (a+ b)(a b) = (a b)
2
lim
x!1
(
px 1)
2
(x 1)(
px+ 1)
= lim
x!1
x 1
2
(x 1)(
px+ 1)
= lim
x!1
1
px+ 1
=
1
p
1 + 1
=
1
2
1