University problems on Engineering Mechanics solved in differrent way part II
Projectiom of hexognal solid step by step process
1. A hexagonal Prism of base side 30mm axis length 60mm is resting on HP on one
of its base side with its axis inclined at HP and parallel to VP. Draw its projection
Ashoka Institution
2. Draw hexagon with
one edge as shown
Draw x y line as shown
X Y
Distance is
approximate
30
a
b
c
df
e
5. X Y
30
60 500
Draw the base of prism
as shown, Pl note that
axis is 400 degree to HP
and hence base will
have 500 to HP
a
b
c
df
e
a’(f’) b’ (e’) c’(d’)
P’(u’) q’(t’) r’(s’)
q
r
s
t
u
p
6. X Y
30
60 500
Draw the
view as
shown
a
b
c
df
e
a’(f’) b’ (e’) c’(d’)
P’(u’) q’(t’) r’(s’)
q
r
s
t
u
p
7. X Y
30
60 500
Draw projector as shown
a
b
c
df
e
a’(f’) b’ (e’) c’(d’)
P’(u’) q’(t’) r’(s’)
q
r
s
t
u
p
8. X Y
30
60 500
Draw projector as shown
and mark
a’(f’) b’ (e’) c’(d’)
P’(u’) q’(t’) r’(s’)
a
b
c
df
e
q
r
s
t
u
p
a1
b1
c1
d1
e1
f1
10. X Y
30
60
500
Draw projector as shown
and mark
a
b
c
df
e
q
r
s
t
u
p
a’(f’) b’ (e’) c’(d’)
P’(u’) q’(t’) r’(s’)
a1
b1
c1
d1
e1
f1
r1
q1
p1
s1
t1
u1
11. X Y30
60
500
Draw the picture as shown
a
b
c
df
e
q
r
s
t
u
p
a’(f’) b’ (e’) c’(d’)
P’(u’) q’(t’) r’(s’)
a1
b1
c1
d1
e1
f1
r1
q1
p1
s1
t1
u1
13. X Y
30
60
500
a
b
c
d
e
a’(f’) b’ (e’) c’(d’)
P’(u’)
q
r
s
t
f
u
p
q’(t’) r’(s’)
a1
b1
c1
d1
e1
f1
r1
q1
p1
s1
t1
u1
400
All Dimensions are mm
Scale 1:1
VP
HP