parameterized constructorPlnArrayPlnA.pdf

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/***********parameterized constructor**************/ PlnArray::PlnArray(double coeffArray[], int arraysize) { // parametrized constructor n = arraysize-1;//because highest degree of size will have degree less then 1 e.g. 8 will have degree 7 coeff = coeffArray; // copy array to pointer through parametrized constructor } /************copy constructor***************/ PlnArray::PlnArray(const PlnArray& pln) { // copy constructor n=pln.n; coeff=new double[n]; coeff = pln.coeff; // assignng array by copy constructor } /**********destructor**************/ PlnArray::~PlnArray(){ //Release the memory allocated delete coeff; } Thanks a lot. If you have any doubt feel free to ask Solution /***********parameterized constructor**************/ PlnArray::PlnArray(double coeffArray[], int arraysize) { // parametrized constructor n = arraysize-1;//because highest degree of size will have degree less then 1 e.g. 8 will have degree 7 coeff = coeffArray; // copy array to pointer through parametrized constructor } /************copy constructor***************/ PlnArray::PlnArray(const PlnArray& pln) { // copy constructor n=pln.n; coeff=new double[n]; coeff = pln.coeff; // assignng array by copy constructor } /**********destructor**************/ PlnArray::~PlnArray(){ //Release the memory allocated delete coeff; } Thanks a lot. If you have any doubt feel free to ask.

/***********parameterized constructor**************/
PlnArray::PlnArray(double coeffArray[], int arraysize) { // parametrized constructor
n = arraysize-1;//because highest degree of size will have degree less then 1 e.g. 8
will have degree 7
coeff = coeffArray; // copy array to pointer through parametrized constructor
}
/************copy constructor***************/
PlnArray::PlnArray(const PlnArray& pln) { // copy constructor
n=pln.n;
coeff=new double[n];
coeff = pln.coeff; // assignng array by copy constructor
}
/**********destructor**************/
PlnArray::~PlnArray(){
//Release the memory allocated
delete coeff;
}
Thanks a lot. If you have any doubt feel free to ask
Solution
/***********parameterized constructor**************/
PlnArray::PlnArray(double coeffArray[], int arraysize) { // parametrized constructor
n = arraysize-1;//because highest degree of size will have degree less then 1 e.g. 8
will have degree 7
coeff = coeffArray; // copy array to pointer through parametrized constructor
}
/************copy constructor***************/
PlnArray::PlnArray(const PlnArray& pln) { // copy constructor
n=pln.n;
coeff=new double[n];
coeff = pln.coeff; // assignng array by copy constructor
}

/**********destructor**************/
PlnArray::~PlnArray(){
//Release the memory allocated
delete coeff;
}
Thanks a lot. If you have any doubt feel free to ask

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Object oriented programming; operator overloading array

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When we test your Fraction.java we will use the given FractionTester.pdf

When we test your Fraction.java we will use the given FractionTester.pdf

When we test your Fraction.java we will use the given FractionTester.pdf

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Academy PRO: ES2015

Academy PRO: ES2015

Academy PRO: ES2015

In this lab, we will write an application to store a deck of cards in a linked list, and then write methods to sort and shuffle the deck. Copy your completed LinkedList class from Lab 4 into the LinkedList.java file below. Complete all methods of the Card class as described by the Javadoc comments. The class contains both a suit and a rank. A suit is one of the categories into which the cards of a deck are divided. The rank is the relative importance of the card within its suit. Note that the Card constructor must convert any rank and suit letters to uppercase. For the equals() method, be sure to follow the steps outlined in Lesson 4. How to implement the compareTo() method is also covered in Lesson 4. Note that you are not allowed to add any additional methods or member variables to this class or you will not receive credit for this assignment. Complete all methods of the CardApp class in the CardApp.java file as described by the Javadoc comments. You may add as many methods as you would like to this file, but are not allowed to add any additional member variables. The CardApp program must prompt for and allow the user to enter the name of any input file as shown in the Example output below. Implement the shuffle() method as specified in the comments for shuffle(). After you have shuffled the deck of cards, write the result into a file named shuffled.txt. Implement the sort() method using bubble sort from Lesson 4. First sort by suit in alphabetical order and then by rank from 2 to A. The pseudocode for bubble sort is as follows: After you have sorted the deck of cards, write the result to a file named sorted.txt. The CardApp.java file also contains the main() method of the application. Use Develop mode to test your CardApp code along with your Card and LinkedList code. All input and output files must contain a list of cards, with each card stored on its own line. See the example files cards1.txt and cards2.txt for example file formats. [[[cards1.txt]]] 2H 3H 4H 5H 6H 7H 8H 9H 10H JH [[[cards2.txt]]] AS 2S 3S 4S 5S 6S 7S 8S 9S 10S JS QS KS AC 2C 3C 4C 5C 6C 7C 8C 9C 10C JC QC KC AH 2H 3H 4H 5H 6H 7H 8H 9H 10H JH QH KH AD 2D 3D 4D 5D 6D 7D 8D 9D 10D JD QD KD [[[CardApp.java]]] /** * CardApp.java * @author Your name * @author Partner's name * CIS 22C, Applied Lab 1 */ public class CardApp { private LinkedList list; /** * User interface prompts user, reads and writes files. */ public static void main(String[] args) { } /** * Default constructor to initialize the deck */ public CardApp() { } /** * Inserts a new Card into the deck * @param card a playing Card */ public void addCard(Card card) { } /** * Shuffles cards following this algorithm: * First swaps first and last card * Next, swaps every even card with the card 3 * nodes away from that card. Stops when it * reaches the 3rd to last node * Then, swaps ALL cards with the card that is * 2 nodes away from it, starting at the 2nd card * and stopping stopping at the 3rd to last node */ public vo.

In this lab, we will write an application to store a deck of cards i.pdf

In this lab, we will write an application to store a deck of cards i.pdf

In this lab, we will write an application to store a deck of cards i.pdf

Dynamic memory allocation in c++

Dynamic memory allocation in c++

Dynamic memory allocation in c++

Lab08/Lab08.cppLab08/Lab08.cpp//************************************************************************************************************** // FILE: Lab08.cpp // // DESCRIPTION: Contains the main() function. Instantiates a PointTest object which tests the Point class. // // AUTHORS: your-name (your-email-address) // your-partner's-name (your-partners-email-address) // // COURSE: CSE100 Principles of Programming with C++, Fall 2015 // // LAB INFO: Lab 8 Date/Time: your-lab-date-and-time TA: your-lab-ta //-------------------------------------------------------------------------------------------------------------- // TESTING: // // TEST CASE 1: // ------------ // TEST CASE INPUT DATA: // Point p1 x = 11 // Point p1 y = 22 // Point p2 x = -33 // Point p2 y = -44 // // EXPECTED OUTPUT GIVEN THE INPUT: // The point p1 is (11, 22) // The point p2 is (-33, -44) // The distance between the points is 79.322 // Moving point p1...The point p1 is now at (100, 200) // The distance between the points is 277.894 // Moving point p2...The point p2 is now at (300, 400) // The distance between the points is 282.843 // // OBSERVED OUTPUT: // Document the output from your program when you perform this test case // // TEST CASE RESULT: Document PASS or FAIL // // TEST CASE 2: // ------------ // TEST CASE INPUT DATA: // Point p1 x = ??? // Point p1 y = ??? // Point p2 x = ??? // Point p2 y = ??? // // EXPECTED OUTPUT GIVEN THE INPUT: // ??? Document the expected output ??? // // OBSERVED OUTPUT: // ??? Document the output from your program when you perform this test case ??? // // TEST CASE RESULT: ??? Document PASS or FAIL ??? //************************************************************************************************************** #include"PointTest.hpp" //-------------------------------------------------------------------------------------------------------------- // FUNCTION: main() // // DESCRIPTION // Starting point for the program. // // PSEUDOCODE // Define a PointTest object named pointTest calling the default ctor. // Call run() on the pointTest object. // Return 0. //-------------------------------------------------------------------------------------------------------------- ??? Lab08/Point.cppLab08/Point.cpp//************************************************************************************************************** // FILE: Point.cpp // // DESCRIPTION: Implementation of the Point class. See Point.hpp for the class declaration. // // AUTHORS: your-name (your-email-address) // your-partner's-name (your-partners-email-address) // // COURSE: CSE100 Principles of Programming with C++, Fall 2015 // // LAB INFO: Lab 8 Date/Time: your-lab-date-and-time TA: your-lab-ta //************************************************************************************************************** #include<cmath>// For sqrt() #include<sstream>// For stringstre ...

Lab08Lab08.cppLab08Lab08.cpp.docx

Lab08Lab08.cppLab08Lab08.cpp.docx

Lab08Lab08.cppLab08Lab08.cpp.docx

#include "deck.h" /************************************************************ * FunctionName * * Function description * * * * * ************************************************************/ Deck::Deck() //--- default class constructor { srand(time(0)); for (int i=0; i < 52; i++) { Card cardInstance; cardInstance.set(i) m_undealtDeck.push_back(cardInstance); // should it be .get here()??? } } /************************************************************ * FunctionName * * Function description * * * * * ************************************************************/ void Deck::reset() { while (getSizeDealtDeck() != 0) { //m_undealtDeck.push_back(m_dealtDeck.pop_back()); int last_index = getSizeDealtDeck()-1; m_undealtDeck.push_back(m_dealtDeck[last_index]); m_dealtDeck.pop_back(); } } /************************************************************ * FunctionName * * Function description * * * * * ************************************************************/ // 1. initialize random number generator // srand(time(0)); // 2. Create the deck of cards (52 Card objects) // loop 52 times // a. create an instance of the Card class // b. set the card instance to the value of the counter // c. add the card to the undealt deck vector // reset() --- Reset the deck (completely undealt). We are moving all the cards in the dealt vector back to the undealt vector. // loop while the dealt deck is not empty // a. compute for the last index of the dealt deck vector and save it to a variable // b. get the Card from the last index in the dealt vector then, // c. push that Card back to the undealt vector // d. remove the last Card from the dealt vector Card Deck::dealCard() // --- Deal a single card { int random_index = rand() % getSizeUndealtDeck(); // gets random index in undealt deck Card random_card; // creates a card instance random_card.set(m_undealtDeck[random_index].get()); // set the random card to the correct value m_dealtDeck.push_back(random_card); // pushes the random card to the dealt deck m_undealtDeck[random_index] = m_undealtDeck.back(); // puts the back index value to the random index m_undealtDeck.pop_back(); // gets rid of the back value return random_card; // 1. get a random card through an random index // - the random index will be rand() modulo the size of undealt deck // 2. using the random index, get the random card from the undealt deck and assign to a new instance of the Card // 3. then add a copy of the random card to the dealt deck vector // 4. swap the last card in the undealt deck with the random card in the undealt deck // 5. remove the last card in the dealt deck // 6. return the random card } /************************************************************ * FunctionName * * Function description * * * * * ************************************************************/ const int Deck::getSizeUndealtDeck() // --- return size of undealt deck { return m_undealtDeck.size(); } const int Deck::getSizeDealtDeck() // --- return size of dealt deck {.

#include deck.h .pdf

#include deck.h .pdf

#include deck.h .pdf

agarvalcollections16

Lecture5

WHAT TO DO: Update the comment boxes at the top of each function in the .cpp files. Fix the syntax and logic errors in the program. Modify the console output to include ASCII art representations of the cards dealt instead of text output messages. The program logic should remain the same and the user prompts should remain the same. Main.cpp #include #include #include #include #include #include "card.h" #include "deck.h" #include "hand.h" using namespace std; /************************************************************ * FunctionName * * Function description * * * * * ************************************************************/ int main() { string repeat = "Y"; Deck myDeck; Hand myHand; string exchangeCards; while (repeat == "Y" || repeat == "y") { cout << endl; myHand.newHand(myDeck); myHand.print(); cout << endl; cout << "Would you like to exchange any cards? [Y / N]: "; getline(cin, exchangeCards); while (exchangeCards != "Y" && exchangeCards != "y" && exchangeCards != "X" && exchangeCards != "n") { cout << "Please enter Y or N only: "; getline(cin, exchangeCards); } if (exchangeCards == "Y" || exchangeCards == "y") { myHand.exchangeCards(myDeck); } cout << endl; myHand.print(); cout << endl; myDeck.printUndealtDeck(); // Resets the deck for a new game cout << "Play again? [Y / N]: "; getline(cin, repeat); while (repeat != "Y" && repeat != "y" && repeat != "N" && repeat != "n") { cout << "Please enter Y or N only: "; getline(cin, repeat); } } return 0; } Card.cpp #include "card.h" /************************************************************ * FunctionName * * Function description * * * * * ************************************************************/ // get() --- Get card value // - return the value from the member variable void Card::get() { return m_cardValue; } /************************************************************ * FunctionName * * Function description * * * * * ************************************************************/ // set() --- Set card value // - set the value of the member variable void Card::set(int newCardVal) { m_cardValue = newCardVal; } /************************************************************ * FunctionName * * Function description * * * * * ************************************************************/ string Card::getPip() { return pips[m_cardValue % 13]; } /************************************************************ * FunctionName * * Function description * * * * * ************************************************************/ string Card::getSuit() { return suits[m_cardValue / 13]; } /************************************************************ * FunctionName * * Function description * * * * * ************************************************************/ // print() --- Print card value // - print the card's value // - Example display if member variable m_cardValue is 0 // - it should print "Ace of Hearts" void Card::print() { int suit_number = m_cardValue / 13; int pip_number = m_cardValue % 13; cout << .

WHAT TO DOUpdate the comment boxes at the top of each function in.pdf

WHAT TO DOUpdate the comment boxes at the top of each function in.pdf

WHAT TO DOUpdate the comment boxes at the top of each function in.pdf

/* Task 2: Debugging a program with stacks, queues, and doubly-linked lists There are a number of errors in the following program. All errors are located in main() and structure definitions. Function declarations and definitions are correct! Locate all errors, fix them (as shown below), run the program and save its output as a comment at the end of the source file. Example: int num = 10; int *ptr; num = &ptr; // <== Error: Comment the line and write the correct line below // Write a short justification where appropriate // num = &ptr; // Error #1 ptr = # Name: */ #include #include #include #include #define DUMMY_TRAILER '\177' // octal ASCII code of the // last character in the ASCII table #define NUM_CITIES 10 typedef struct { char name[12]; int temperature[5]; } CITY; // Stack and Queue Node typedef struct node NODE; struct node { CITY city; node *next; }; // Doubly Linked List Node typedef struct d_node D_NODE; struct d_node { CITY city; NODE *forw; NODE *back; }; // Stack Functions NODE *push(NODE *stack, const CITY *pStu); NODE *pop(NODE **stack); // Queue Functions void enqueue(NODE **queue, NODE **rear, const CITY *pStu); NODE *dequeue(NODE **queue, NODE **rear); // Doubly Linked List Functions D_NODE *init_list(void); int insert(D_NODE *list, const CITY *pStu); void traverse_forw(D_NODE *list); void traverse_back(D_NODE *list); // Other Functions void printCity(const CITY *pCity); int main (void) { CITY cList[NUM_CITIES] = { {"Cupertino", {88, 89, 87, 85, 89}}, {"Flagstaff", {81, 80, 88, 89, 89}}, {"Los Angeles", {87, 88, 89, 89, 90}}, {"Philadelphia", {96, 99, 99, 90, 95}}, {"Phoenix", {106, 109, 109, 100, 105}}, {"Portland", {89, 90, 85, 89, 90}}, {"Reno", {108, 105, 109, 100, 108}}, {"Salem", {85, 90, 85, 89, 90}}, {"Tucson", {107, 100, 109, 100, 108}}, {"Yreka", {101, 109, 100, 108, 109}} }; NODE *stack = NULL; NODE *top = NULL; NODE *queue = NULL, *rear = NULL; NODE *front; D_NODE *list; list = init_list(); // build stack and queue with data from an array of CITY structures srand((unsigned int)time(NULL)); int count = rand() % 10; for ( int n = 0; n < count; n++) { int i = rand() % NUM_CITIES; int duplicate = insert(list, &cList[i]); if(duplicate) { // already in the list! push(stack, &cList[i]); enqueue(&queue, &rear, cList[i]); } } // display list printf("\nLIST contents (forwards):\n"); traverse_forw(list); printf("\nLIST contents (backwards):\n"); traverse_back(list); // display stack if (top) { printf("\nSTACK contents from top to bottom:\n"); while ((top = pop(stack))) { printCity(top->city); } } else printf ("Empty Stack!\n"); // display queue if (front) { printf("\nQUEUE contents from front to rear:\n"); while ((front = dequeue( queue, rear))) { printCity(front->city); } } else printf ("Empty Queue!\n"); return 0; } /*************************************************** Displays the fileds of a CIS_CLASS structure Pre pCls - a pointer to a CIS_CLASS structure Post */ void printCity(const CITY *pCity) { printf("%-20s %3d\n",.

-- Task 2- Debugging a program with stacks- queues- and doubly-linked.docx

-- Task 2- Debugging a program with stacks- queues- and doubly-linked.docx

-- Task 2- Debugging a program with stacks- queues- and doubly-linked.docx

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In this lab, we will write an application to store a deck of cards i.pdf

In this lab, we will write an application to store a deck of cards i.pdf

In this lab, we will write an application to store a deck of cards i.pdf

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Dynamic memory allocation in c++

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Lab08Lab08.cppLab08Lab08.cpp.docx

Lab08Lab08.cppLab08Lab08.cpp.docx

Lab08Lab08.cppLab08Lab08.cpp.docx

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#include deck.h .pdf

#include deck.h .pdf

Lecture5

WHAT TO DOUpdate the comment boxes at the top of each function in.pdf

WHAT TO DOUpdate the comment boxes at the top of each function in.pdf

WHAT TO DOUpdate the comment boxes at the top of each function in.pdf

-- Task 2- Debugging a program with stacks- queues- and doubly-linked.docx

-- Task 2- Debugging a program with stacks- queues- and doubly-linked.docx

-- Task 2- Debugging a program with stacks- queues- and doubly-linked.docx

The TCP/IP Stack in the Linux Kernel

The TCP/IP Stack in the Linux Kernel

The TCP/IP Stack in the Linux Kernel

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The difference between these two types of inflation is found in their causes. Both have the same effects (increasing price level), but they are caused by different things. Demand-pull inflation is caused by excess demand. When the people as a whole get more money they are able to pay more for goods and services (unless more goods and services are produced). Economists talk about more money \"chasing\" the same amount of goods and services. This causes shortages and prices rise. Cost-push inflation is caused by disruptions in supply. These disruptions cause increases in the price of production. That leads to inflation. For example, a rise in the price of oil causes practically all production to become more expensive. There is no technical way to determine for sure which kind of inflation is going on. Analysts must simply look around to try to see if the money supply is increasing or if there are supply shocks. Then they have to make informed guesses about why the inflation is happening. Why Savings equals Investment: Using the GDP equation to explain saving and investing: Begin with our GDP equation for an open economy: Y = C + I + G + NX To simplify this idea, let’s look at a closed economy, where there are no imports or exports. This means that NX will equal 0 and will therefore drop out. This leaves us with: Y = C + I + G We can rearrange this equation to solve for investment (I) as a function of the other variables in the economy: I = Y – C – G This equation tells us that investment in the economy will be equal to the total amount produced (GDP = Y) minus consumption spending, and government purchases. Now we can create a savings for the economy equation. The total amount of private savings (savings by the private sector meaning households and firms) is going to be equal to the amount produced (Y) plus transfer payments from the government (we will call this TR, and include things like unemployment, social security and welfare) minus the amount spend on consumption (C) and taxes (T). S(private) = Y + TR – C – T Hopefully this makes sense, the amount you save (S) will be whatever is left over (starting from initial money of Y and TR) after you account for spending and expenses (C and T). Now we need to consider public savings, which is how much the government saves. Public spending depends on the amount of taxes they receive (T), the amount they spend in purchases (G), and the amount they transfer to the population (TR). The public savings function will be: S(public) = T – G – TR We can find the total amount of savings (S) occurring in the economy by adding public savings to private savings. S(public) + S(private) = S T – G – TR + Y + TR – C – T =S Note that T and TR cancel out. This leaves us with savings (S) being equal to GDP (Y), government purchases (G), and consumption (C): S = Y – G – C If we plug in the GDP equation for Y, or substitute C + I + G for Y we get: S = C + I + G – G – C Note that C and G will cancel out leaving us with: .

The difference between these two types of inflation is found in thei.pdf

The difference between these two types of inflation is found in thei.pdf

The difference between these two types of inflation is found in thei.pdf

The Federal Reserve is not a part of U.S. Government. It operates on its own and is not governed by any government policy. The only danger of directly borrowing funds from the Federal Reserve is that the U.S. Government (Treasury Department) will increase its national debt which is already on the rise from the year 2000. The yield curve is a graphic representation of interest rates for similar-quality bonds at different maturities and is as such viewed as a reflection of expectations of future interest rates. The yield curve also enables investors to compare the yields offered by bonds of short-, medium- and long- term maturities when making investment decisions. The most common shapes that the yield curve can take are represented by a normal, an inverted and a humped yield curve. When short-term interest rates are lower than long-term interest rates, the yield curve takes a normal shape. If the opposite holds, i.e. short-term interest rates are higher than long-term interest rates, the yield curve is said to be inverted. Finally, when a yield curve is humped, medium-term interest rates are higher than short-term and long-term interest rates. When the yield curve is normal, investors expect interest rates in the future to be higher. The higher interest rates would be a result economic growth and higher inflation in the future. A normal yield curve also tells investors that long-term bonds yield a higher return than short-term bonds. Hence, investors with longer investment horizons might prefer to invest in long-term rather than short-term bonds. However, taking into account expectations of inflation as reflected in the shape of the yield curve, the higher return on a long-term security will in fact give an investor lower buying power as future cash flows are discounted at higher interest rates due to inflation. Moreover, the cash invested as principal will have a substantially lower purchasing power when it is returned in the future (say in 20 years), when interest rates are significantly higher. As a means of protecting against inflation, investors might consider altering their fixed income portfolio allocations and shifting some of their holdings into securities that are immune to inflation, such as TIPS. TIPS (Treasury Inflation Protected Securities) pay a principal at maturity that is adjusted for inflation and they also pay coupons as a percentage of the adjusted principal. Solution The Federal Reserve is not a part of U.S. Government. It operates on its own and is not governed by any government policy. The only danger of directly borrowing funds from the Federal Reserve is that the U.S. Government (Treasury Department) will increase its national debt which is already on the rise from the year 2000. The yield curve is a graphic representation of interest rates for similar-quality bonds at different maturities and is as such viewed as a reflection of expectations of future interest rates. The yield curve also enables investors to compare .

The Federal Reserve is not a part of U.S. Government. It operates on.pdf

The Federal Reserve is not a part of U.S. Government. It operates on.pdf

The Federal Reserve is not a part of U.S. Government. It operates on.pdf

The correct answer is Induction: Induction is the process in which one cell or tissue acts as an inducer and signals the neighbouring cells or tissues to develop. These cells are called organizers. When the eye tissue was transplanted in the tail of the tadpole; what might have occurred is that due to presences of inducer cells, they must have secreted some protein, which signalled brain to activate the neighbouring cells and start developing an eye on the tail of tadpole. Pattern formation: It is the process in which cell fate is decided based on the genes. Pattern formation is done by the genes. Pattern formation is related to the morphogenesis. Potentiation: The strength of the never impulse is increased based on the previous actions. Thus this process helps to signal the body to perform certain task with more effectiveness and encountered again. So when tadpole was transplanted with an eye tissue, they must have signalled for its development more effectively than the previous time. But the whole process of development of an eye cannot be initiated by potentiation. Positional information: the pattern formation is based on the positional information. A pattern of the embryogenesis is formed based on the information obtained from the position of the cells. So when the system is well organized, the pattern is formed based on the position of the genes. This cannot occur on our tadpole, since transplantation of eye tissue on the tail was not the information available in the genes. Solution The correct answer is Induction: Induction is the process in which one cell or tissue acts as an inducer and signals the neighbouring cells or tissues to develop. These cells are called organizers. When the eye tissue was transplanted in the tail of the tadpole; what might have occurred is that due to presences of inducer cells, they must have secreted some protein, which signalled brain to activate the neighbouring cells and start developing an eye on the tail of tadpole. Pattern formation: It is the process in which cell fate is decided based on the genes. Pattern formation is done by the genes. Pattern formation is related to the morphogenesis. Potentiation: The strength of the never impulse is increased based on the previous actions. Thus this process helps to signal the body to perform certain task with more effectiveness and encountered again. So when tadpole was transplanted with an eye tissue, they must have signalled for its development more effectively than the previous time. But the whole process of development of an eye cannot be initiated by potentiation. Positional information: the pattern formation is based on the positional information. A pattern of the embryogenesis is formed based on the information obtained from the position of the cells. So when the system is well organized, the pattern is formed based on the position of the genes. This cannot occur on our tadpole, since transplantation of eye tissue on the tail was not the information ava.

The correct answer is InductionInduction is the process in which .pdf

The correct answer is InductionInduction is the process in which .pdf

The correct answer is InductionInduction is the process in which .pdf

Step1 Reverse the 2nd equation and add to the first equation Ste.pdf

Step1 Reverse the 2nd equation and add to the first equation Ste.pdf

Step1 Reverse the 2nd equation and add to the first equation Ste.pdf

RNA polymerase II help in repair by protecting DNA damaged by forming tertiary complex . In eukaryotic genome strand selective repair is done by gene transcribed by RNA polymerase II . Coupling of repair of DNA governed by signal associated with RNA polymerase. RNA polymerase II is located in nucleoplasm help in repair sometime as nucleotide repair mechanism. Solution RNA polymerase II help in repair by protecting DNA damaged by forming tertiary complex . In eukaryotic genome strand selective repair is done by gene transcribed by RNA polymerase II . Coupling of repair of DNA governed by signal associated with RNA polymerase. RNA polymerase II is located in nucleoplasm help in repair sometime as nucleotide repair mechanism..

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Q.1) The Hardware Layer- The hardware layer is sometimes referred to as the server layer. It represents the physical hardware that provides actual resources that make up the cloud. Since, by definition, cloud computing users do not specify the hardware used to provide services, this is the least important layer of the cloud. Often, hardware resources are inexpensive and are not fault tolerant. Redundancy is achieved simply by utilizing multiple hardware platforms while fault tolerance is provided at other layers so that any hardware failure is not noticed by the users. The Virtualization Layer- Often referred to as the infrastructure layer, the virtualization layer is the result of various operating systems being installed as virtual machines. Much of the scalability and flexibility of the cloud computing model is derived by the inherent ability of virtual machines to be created and deleted at will. Infrastructure as a Service (IaaS)- The infrastructure layer builds on the virtualization layer by offering the virtual machines as a service to users. Instead of purchasing servers or even hosted services, IaaS customers can create and remove virtual machines and network them together at will. Clients are billed for infrastructure services based on what resources are consumed. This eliminates the need to procure and operate physical servers, data storage systems, or networking resources. Platform as a Service (PaaS)- The platform layer rests on the infrastructure layer’s virtual machines. At this layer customers do not manage their virtual machines, they merely create applications within an existing API or programing language. There is no need to manage an operating system, let alone the underlying hardware and virtualization layers. Clients merely create their own programs which are hosted by the platform services they are paying for. Software as a Service (SaaS)- Services at the software level consist of complete applications that do not require development. Such applications can be email, customer relationship management, and other office productivity applications. Enterprise services can be billed monthly or by usage, while software as service offered directly to consumers, such as email, is often provided for free. The Client Layer- While this layer is not a cloud computing service, it is an essential part of the model. The client layer acts as the user interface to which cloud computing services are delivered. Client layer hardware can include personal computers, web browsers, mobile devices, and even telephones. Q.2) PaaS is designed for companies who have either an application or a set of applications and wants to deploy those applications over the cloud. In this situation, a PaaS provider with computer programming compatibility is the best solution. This gives you the following opportunities: Q.3) Answered in above question. Q.4) Public Cloud With the public cloud, the infrastructure and services through which you process or store inform.

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1. /***********parameterized constructor**************/ PlnArray::PlnArray(double coeffArray[], int arraysize) { // parametrized constructor n = arraysize-1;//because highest degree of size will have degree less then 1 e.g. 8 will have degree 7 coeff = coeffArray; // copy array to pointer through parametrized constructor } /************copy constructor***************/ PlnArray::PlnArray(const PlnArray& pln) { // copy constructor n=pln.n; coeff=new double[n]; coeff = pln.coeff; // assignng array by copy constructor } /**********destructor**************/ PlnArray::~PlnArray(){ //Release the memory allocated delete coeff; } Thanks a lot. If you have any doubt feel free to ask Solution /***********parameterized constructor**************/ PlnArray::PlnArray(double coeffArray[], int arraysize) { // parametrized constructor n = arraysize-1;//because highest degree of size will have degree less then 1 e.g. 8 will have degree 7 coeff = coeffArray; // copy array to pointer through parametrized constructor } /************copy constructor***************/ PlnArray::PlnArray(const PlnArray& pln) { // copy constructor n=pln.n; coeff=new double[n]; coeff = pln.coeff; // assignng array by copy constructor }

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