The integral has a pole at z=-1 Integral region is around a circle in the first quadrant with unit radius, z=1 to z=i means angle 0 to pi/2 Using residue theorem the integral is 2pii (log (-1+1)) = -infty Solution The integral has a pole at z=-1 Integral region is around a circle in the first quadrant with unit radius, z=1 to z=i means angle 0 to pi/2 Using residue theorem the integral is 2pii (log (-1+1)) = -infty.

1. The integral has a pole at z=-1
Integral region is around a circle in the first quadrant with unit radius,
z=1 to z=i means
angle 0 to pi/2
Using residue theorem
the integral is 2pii (log (-1+1))
= -infty
Solution
The integral has a pole at z=-1
Integral region is around a circle in the first quadrant with unit radius,
z=1 to z=i means
angle 0 to pi/2
Using residue theorem
the integral is 2pii (log (-1+1))
= -infty