1) The document discusses dimensional analysis and similitude, which are qualitative techniques used in many fields of science and engineering.
2) Dimensional analysis involves identifying the fundamental dimensions involved in a physical phenomenon and representing the phenomenon in terms of dimensionless parameters. This allows experiments to determine the nature of relationships.
3) An example of dimensional analysis of flow velocity V in terms of gravitational acceleration g, height h, and kinematic viscosity ν is shown. Dimensionless groups like the Froude and Reynolds numbers are derived.
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c
a b
2 2 2
c a b
:smaller of two acute angles
A
B CD
Area of triangle
ABC: 2
cA c f
Similarly area
of triangle ABD:
2
aA a f
Similarly area
of triangle ACD:
2
bA b f c a bA A A
2 2 2
c f a f b f 2 2 2
c a b
The theorem is proved using dimension‐related
arguments only
For quasi‐steady,
incompressible,
frictionless flow, we have
derived (Bernoulli Eq.)
2V gh
Alternate approach
Experiment (or thought experiment) suggests
1 ,V f g h 2V f u
where is made of and
and has the same dimension as that of
u g h
V
m n
u g h
u gh
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2V f gh
m n
u g h 1 2 m n
LT LT L
L
LT-2
2m n m
L T
LT-1
1; 2 1m n m
1 2m n u gh
Think about the nature of f2
; is a constantV c gh c
The constant can be
evaluated from experiments
; is nondiemsnional
V
c
gh
The solution may
also be written as
Summary
0; is nondimensional
Where V, g, and h are
dimensional, as shown before
The technique described above is known as
Dimensional Analysis
, , 0f V g h Given
The above system is equivalent to
V
gh
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Dimensional Analysis
If certain physical phenomenon is governed by
1 2, ,.... 0nf x x x
where some/all of the
variables are dimensionalx
Then the above phenomena can be represented as
1 2, ,.... 0m where all the variables
are non-dimensional
m n
The nature of f and ψ may be obtained from
experiments
Dimensional Analysis: Buckingham Pi Theorem
1 2, ,.... 0nf x x x
where some/all
are dimensional
x
1 2, ,.... 0m
where all are
non-dimensional
where ,m n m n k
Minimum number of fundamental dimensions
involved: k
, , 0f V g h Example:
3n 2k 1m n k
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Experiment shows
Above Equation suggests
, , 0f V g h
a b c
V g h
0
where is made of , and and
is dimensionless
V g h
0 0 1 2a b c
L T LT LT L
2a b c a b
L T
2 0a b c a b 2b c a
a
V
gh
Any arbitrary value of a
should be ok 0
V
gh
Pi Theorem: Repeating and non‐repeating variables
1 2, ,.... nx x x 1 2 1 2, ,.... ; , ,....r r rk nr nr nrmx x x x x x
11 12 13 1
1 1 1 2 3 ... ka a a a
nr r r r rkx x x x x
Construction of Pi‐terms
21 22 23 2
2 2 1 2 3 ... ka a a a
nr r r r rkx x x x x
1 2 3
1 2 3 ...m m m mka a a a
m nrm r r r rkx x x x x
.....
.....
Selection of repeating
variables:
o They must be
dimensionally
independent
o Together, they
must include all
fundamental
dimensions
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Experiment shows, for
viscous flow , , , 0f V g h
2k
We have to select two
(02) repeating variables
Let’s take the repeating variables: ,g h
2m 4n
Non‐repeating variables: ,V
M L T
V 0 1 ‐1
g 0 1 ‐2
h 0 1 0
ν 0 2 ‐1
, , , 0f V g h L T
V 1 ‐1
g 1 ‐2
h 1 0
ν 2 ‐1
2k
Repeating variables: ,g h
2m 4n
Non‐repeating variables: ,V
11 12 13 1
1 1 1 2 3 ... ka a a a
nr r r r rkx x x x x
1
a b
V g h 0 0 1 2 a b
L T LT LT L
1 1 2a b a
L T
2 0 1 2a b a
1 2a b 1
V
gh
2similarly
a b
g h 0 0 2 1 2 a b
L T L T LT L
1 2, 3 2a b 2 3
gh
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, , , 0f V g h 1 3
, 0
V
f
gh gh
Fr
V
gh
Fr
Re
Froude number 3
V
Vhghgh
We may also write 2 Fr,Fr Re 0f Fr Fr Re
Frictionless flow: Fr constant
Viscous flow: Experiments are
necessary to find the
nature of function
Fr Fr Re