Jiminy Cricket Removal has a profit margin of 10 percent, total asse.pdf

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Jiminy Cricket Removal has a profit margin of 10 percent, total asset turnover of 1.14, and ROE of 14.32 percent. What is this firm’s debt–equity ratio? (Do not round intermediate calculations and round your answer to 2 decimal places, e.g., 32.16.) Debt–equity ratio ______ times Solution ROE=Profit margin*Total asset turnover*leverage 0.1432=0.1*1.14*leverage leverage=0.1432/(0.1*1.14) =1.256140351 leverage=Total assets/Equity Hence total assets =1.256140351equity Total assets=debt+equity 1.256140351equity=debt+equity Hence debt =(1.256140351-1)equity =0.256140351equity Hence debt-equity ratio=Debt/Equity =0.26 times(Approx)..

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3. A plant breeder crosses an inbred soybean cultivar with herbicide tolerance (recessive allele) and susceptibility to a fungal pathogen (dominant allele) to an inbred soybean cultivar that is susceptible to herbicides (dominant allele) but is resistant to the fungal pathogen (recessive allele). The plant breeder generates F2 individuals and evaluates these individuals for herbicide tolerance and resistance to the fungal pathogen. The plant breeder generates thousands of F2 individuals which he inbreeds to generate purelines. The plant breeder finds that almost every plant that has herbicide tolerance is susceptible to the pathogen. What term is used to describe this phenomenon? A few of the F2 individuals described in question 3 are both herbicide tolerant and resistant to the fungal pathogen. What likely happened to the DNA in these plants in order for this to occur? Solution The phenomenon produced can be termed as epistatis where herbicide tolerance (hh, recessive allele) and susceptibility to a fungal pathogen (F(F/f),dominant allele) interact to show a mixed Dominant recessive epistasis i.e The F along with h masked the susceptible to herbicides (H,dominant allele) but is resistant to the fungal pathogen (ff, recessive allele). Therefore, most of the offspings of F2 generation were showing herbicide tolerance is susceptible to the pathogen F masked the effect of H . The plans with ff only showed both herbicide tolerant and resistant to the fungal pathogen.The DNA of these plants expressed the protein needed to express the reistant to fungal pathogen in absence of F..

3. A plant breeder crosses an inbred soybean cultivar with herbicide.pdf

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A mirror faces a cliff located some distance away. Mounted on the cliff is a second mirror, directly opposite the first mirror and facing toward it. A gun is fired very close to the first mirror. The speed of sound is 343 m/s. How many times does the flash of the gunshot travel the round- trip distance between the mirrors before the echo of the gunshot is heard Solution lets assume that echo is heard after t time. distance covered: by light = 3*10^8 * t by sound = 343*t So, number of trips = 3*10^8/343 = 8.75*10^5.

A mirror faces a cliff located some distance away. Mounted on the cli.pdf

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Why is it important to identify Classes early in the Unified Process methodology? Solution it is also known as software development process which the development is done incrementally in step by step manner =>classe plays main role in the unified process,because unified process uses object oreinted techonology for analysis and desing of the software architecture.but before doing this he want build classes according to the client requirement in the architecture design. if we do analysis and design with proper define of classes the whole architecture may get in to trouble.

Why is it important to identify Classes early in the Unified Process.pdf

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A male Drosophila melanogaster has the genotype Aa; Bb; Cc; XDY..pdf

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Which of the following facilitated the endosymbiotic acquisition of cyanobacteria that became modern chloroplasts? Question 1 options: ability of eukaryotes to carry out endocytosis similarity in biochemical pathways between chloroplasts and cyanobacteria reduction of cyanobacterial genome size conjugation between cyanobacteria and eukaryotic cell ability of eukaryotes to carry out endocytosis similarity in biochemical pathways between chloroplasts and cyanobacteria reduction of cyanobacterial genome size conjugation between cyanobacteria and eukaryotic cell Solution ability of eukaryotes to carry out endocytosis .... as cyanobacteria was endocytosed in endosymbiotic way it turned to chloroplast over an evolutionary time course .... this is called endosymbiontic theory.

Which of the following facilitated the endosymbiotic acquisition of .pdf

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Which of the following is true about replication? The lagging strand is synthesized in a continuous fashion and the leading strand is not Helicase unwinds RNA Primases lay down the primers on the lagging strand Topoisomerase unwinds DNA Solution The only correct statement among the four in the given question is \'Topoisomerase unwinds DNA\'. Explanation for others are; leading strand is synthesized in continuous fashion whereas lagging strand is not, helicase unwinds DNA (which is double stranded) not the RNA (which is single stranded), primases lay down the primers on both, the leading as well as the lagging strands..

Which of the following is true about replication The lagging s.pdf

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Which is a common trait among all land plants? Vascular tissues transport water and nutrients, and provide support Seeds facilitate survival and dispersal of the species Flowers facilitate cross-pollination The embryo is protected within maternal tissues The haploid phase of the life cycle is the dominant phase Flowers facilitate cross-pollination The embryo is protected within maternal tissues The haploid phase of the life cycle is the dominant phase Solution First we see common traits of land plants and then see listed traits in details one by one: 1. Ability to withstand desiccation. Extant land plants have a cuticle and guard cells. 2. Ability to withstand the effects of more intense radiation, particularly DNA-damaging radiation. Extant land plants have several compounds in their vacuoles that absorb UV. Since the vacuole of a plant occupies most of a mature cell, this helps protect the DNA in other organelles. 3. Ability to protect their spores from desiccation. Early land plants have spores that are encased in a sporopollenin wall. Sporopollenin is a very resistant polymer, resistant to UV and almost everything including desiccation, squashing, etc. To remove sporopollenin from spores, one boils them in a mixture of acetic and hydrochloric acid. 4. Ability to move solutions from the ground to portions of the plant that are not in contact with the ground, and from the photosynthetic portions of the plant to non-photosynthetic portions. Some land plants do this better than others. 5. Ability to support themselves. Aquatic plants float; terrestrial plants cannot do so. Most terrestrial plants have lignin in some of their conducting cells. There is some debate as to whether this was selected for by the advantages of growing tall or the need to protect against embolism in the conducting cells. Since both are important, it seems most realistic to accept that both contributed to the success of plants with the ability to manufacture lignin, the tracheophytes or vascular plants. 6. Ability to acquire the carbon dioxide required for photosynthesis from the atmosphere. This ability is associated with stomatal cells, specialized cells that surround openings (stomates) in the outer cell layer of land plants. Now we see Options given one by one: Vascular tissues transport water and nutrients, and provide support Transport of Water and Minerals: The xylem tissue transports water and minerals. It consists of interconnected vessels and tracheids organized into continuous conducting tubes stretching from the roots to the leaves. These tubes carry water and minerals to all parts of the plant. Plants absorb water from the soil through the root and transport it to the stem, leaves and flowers. Roots have root hairs that are unicellular, thin-walled outgrowths of the epiblema (skin of the root). The root hairs are in close contact with the thin film of water surrounding the soil particles. There are mineral salts such as nitrates, chlorides, sulphates, phos.

Which is a common trait among all land plantsVascular tissues tra.pdf

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Which of the following is an example of company whose business model is based on access to large databases through the web? Fortune Facebook Cartner Microsoft 18M Solution Answer: As we are alrready aware about the fact that Facebook features vedios , music , profiles with lot of information supplied by almost 1.71 billion of users , their every information like : age , DOB , marital stattus, bio and all . It maintains a huge database to manage all these information of billion users..

Which of the following is an example of company whose business model .pdf

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what role(s) played by the Equatorial Segment Protein 1 (ESP1) during fertilization. Solution The structure of a spermatozoa consists of three parts. They are, Acrosome is the elongated head region of the sperm containing 2/3rd of the nucleus. The enzymes present in the acrosome are essential for the penetration of a sperm into a secondary oocyte (egg). The acrosomal layer necessary for the fusion and penetration into the oocyte is deficient in mice lacking Equatorial Segment Protein 1 (ESP1). This indicates that ESP1 is necessary for the development of \"fusion-competent sperm.\".

what role(s) played by the Equatorial Segment Protein 1 (ESP1) durin.pdf

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What are the similarities and differences between simple linear regr.pdf

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What does it mean if a human female oocyte is no longer arrested in metaphase II of meiosis? Solution Answer: Primary oocytes forms prenatally and remain suspended in prophase of meiosis I until it reaches puberty. An oocyte completes meiosis I as its follicle matures resulting in a secondary oocyte and the first polar body. After ovulation, each oocyte continues to meiosis II metaphase. Meiosis II is completed only if fertilization occurs. This results in a fertilized mature ovum and the second polar body. Thus, the human female oocyte is arrested in metaphase II until fertilization by a sperm takes place..

What does it mean if a human female oocyte is no longer arrested in .pdf

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What is so important about the cells in the HeLo cell culture? What book was written about this person? Solution Ans. HeLa cells are cancerous cells isolated from cervical cancer biopsy sample of Henrieta Lacks. It is the most widely used human cell lines for research purpose in the field of drug testing (John Salks tested polio vaccine on HeLa cells, 1950), cellular processes, mechanism of viral pathogenesis, and almost all other aspects. It has benn distributed to every corner of the world. Due to its extensive use, and its fast-growing (cancerous) nature, the cell line is also said to be ‘immortal. The book on Her: \'The Immortal Henrietta Lacks\' by Rebecca Skloot.

What is so important about the cells in the HeLo cell cultureWhat.pdf

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What are the advantages and disadvantages to patients of increasing .pdf

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Use the Limit definition to compute f\'(a) and find the equation of the tangent line for f(x) = x + x^-1, a=4 Solution f\'(x)= lim h approaches 0 of [f(x+h)- f(x)]/h So here we have ((x+h) + 1/(x+h) -x- 1/x )/h Simplifying and putting over a common denominator we have [h - h/x(x+h)]/h= 1 - 1/x(x+h) As h approaches 0 we have 1- 1/x^2 So f(4)= 1-1/16= 15/16 At (4, 17/4) we have 17/4 = 15/16 *4 +B B= 17/4-15/4= 2/4= 1/2 So equation of tanfent line is Y= 15/16 x +1/2.

Use the Limit definition to compute f(a) and find the equation of .pdf

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under which condition would a cell membrane be most likely to be in liquid, crystalline state, in which an individual phospholipids can rotate around its axis or move laterally through the plane of the bilayer Solution The cell membrane is critical to temperature. The membrane is stabilized at the lower temperature and is in an ordered way. When the temperatures shoot up the membranes begin to attain a fluid state and began to break up. The phospholipids are in the liquid crystalline state specifically at the warm temperature such as at 37-degree Celcius..

under which condition would a cell membrane be most likely to be in .pdf

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Two numbers together add to 300. One number is twice the size of the.pdf

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The stockholders\' interest in a corporation is called: O Liabilities O Dividends 0 Stockholders\' equity. O Assets Solution The answer is stockholder\'s equity. Stockholder\'s equity basically represents the amount invested by them in the company. It gives them right to receive dividends and right to vote in the general meetings of the company. Thus they represent a stockholder\'s interest in any company or corporation. The other terms mentioned can be defined as follows: LIABILITIES: These are the sums that are payable to external parties by a company like creditors, banks, etc. Dividend: This is the amount paid to the shareholders as return on their investment in the company. Assets: These are the physical assets, cash and other receivables owned by the company..

The stockholders interest in a corporation is called O Liabilities.pdf

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Suggest topics to write a term paper for Software Engineeering subject. Solution The topic related to software engineering can be various phases of software engineering like requirement gathering,development ,testing,maintainance.If we discuss testing then it involves basically unit testing,system testing,user acceptance testing,regression testing and thus we can explain testings like unit testing which is done individually,user acceptance testing which is done at the end and system testing which is used to test all the modules in the system..

Suggest topics to write a term paper for Software Engineeering subje.pdf

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Standardize terminologies, i.e. Vocabularies, are used to represent concepts and to communicate them would include diagnoses, procedures, health status but not symptoms. A point-of-care system may include order entry decision support systems? Which of the following would not be considered a classification system a. ICD-10-CM b. MeHIMA c. SNOMED Solution 1) False : Standardised teminologies creates a standard nominclature which help in understanding concpets and communicates inluding diagonises, health status, symptoms, procedure. 2) True : One of the feature of point of care system is computer physician order entries which allows practicioner to input instructions and plans at system 3) MeHIMA is not a classification system.

Standardize terminologies, i.e. Vocabularies, are used to represent c.pdf

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15--The Securities and Exchange Commission’s (SEC’s) adoption of rules and regulations relating to financial and other information furnished to the Commission comes under its ______ power. A. quasi-judicial B. federal C. quasi-executive D. quasi-legislative E. bargaining 16 --Which of the following statements is true of an environmental impact statement (EIS)? A. The National Environmental Policy Act requires federal agencies to follow the conclusions of the EIS. B. An EIS can be in any language as long as it is clear and to the point. C. An EIS is to be included in every recommendation or report on proposals for legislation and other major federal actions significantly affecting the quality of the human environment. D. An EIS should include technical jargon to clearly explain all the points mentioned in the statement. E. The EIS is usually a short list of points that hints at the pros of the economic profits that are outcomes of transactions concerning the human environment. Solution 15) federal 16) An EIS should include technical jargon to clearly explain all the points mentioned in the statement ..

15--The Securities and Exchange Commission’s (SEC’s) adoption of rul.pdf

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