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V63.0121.021, Calculus I                                                    Section 4.4 : Curve Sketching   November 18, 2010



                                                                                                 Notes
                                     Section 4.4
                                   Curve Sketching

                                   V63.0121.021, Calculus I

                                       New York University


                                     November 18, 2010



 Announcements
       There is class on November 23. The homework is due on
       November 24. Turn in homework to my mailbox or bring to class on
       November 23.




 Announcements
                                                                                                 Notes




          There is class on
          November 23. The
          homework is due on
          November 24. Turn in
          homework to my mailbox or
          bring to class on
          November 23.




  V63.0121.021, Calculus I (NYU)      Section 4.4 Curve Sketching   November 18, 2010   2 / 55




 Objectives
                                                                                                 Notes




          given a function, graph it
          completely, indicating
                 zeroes (if easy)
                 asymptotes if applicable
                 critical points
                 local/global max/min
                 inflection points




  V63.0121.021, Calculus I (NYU)      Section 4.4 Curve Sketching   November 18, 2010   3 / 55




                                                                                                                            1
V63.0121.021, Calculus I                                                         Section 4.4 : Curve Sketching   November 18, 2010


 Why?
                                                                                                      Notes




 Graphing functions is like
 dissection . . . or diagramming
 sentences
 You can really know a lot about
 a function when you know all of
 its anatomy.




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching           November 18, 2010   4 / 55




 The Increasing/Decreasing Test
                                                                                                      Notes
 Theorem (The Increasing/Decreasing Test)
 If f > 0 on (a, b), then f is increasing on (a, b). If f < 0 on (a, b), then
 f is decreasing on (a, b).

 Example
 Here f (x) = x 3 + x 2 , and f (x) = 3x 2 + 2x.

                                                                 f (x)
                                                      f (x)




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching           November 18, 2010   5 / 55




 Testing for Concavity
                                                                                                      Notes
 Theorem (Concavity Test)
 If f (x) > 0 for all x in (a, b), then the graph of f is concave upward on
 (a, b) If f (x) < 0 for all x in (a, b), then the graph of f is concave
 downward on (a, b).

 Example
 Here f (x) = x 3 + x 2 , f (x) = 3x 2 + 2x, and f (x) = 6x + 2.
                                       f (x)               f (x)
                                                 f (x)




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching           November 18, 2010   6 / 55




                                                                                                                                 2
V63.0121.021, Calculus I                                                 Section 4.4 : Curve Sketching   November 18, 2010


 Graphing Checklist
                                                                                              Notes

To graph a function f , follow this plan:
 0. Find when f is positive, negative, zero, not
    defined.
 1. Find f and form its sign chart. Conclude
    information about increasing/decreasing
    and local max/min.
 2. Find f and form its sign chart. Conclude
    concave up/concave down and inflection.
 3. Put together a big chart to assemble
    monotonicity and concavity data
 4. Graph!



  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   7 / 55




 Outline
                                                                                              Notes


 Simple examples
    A cubic function
    A quartic function


 More Examples
   Points of nondifferentiability
   Horizontal asymptotes
   Vertical asymptotes
   Trigonometric and polynomial together
   Logarithmic




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   8 / 55




 Graphing a cubic
                                                                                              Notes


 Example
 Graph f (x) = 2x 3 − 3x 2 − 12x.

 (Step 0) First, let’s find the zeros. We can at least factor out one power of
 x:
                            f (x) = x(2x 2 − 3x − 12)
 so f (0) = 0. The other factor is a quadratic, so we the other two roots are
                                                      √
                       3 ± 32 − 4(2)(−12)         3 ± 105
                  x=                           =
                                  4                   4
 It’s OK to skip this step for now since the roots are so complicated.



  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   9 / 55




                                                                                                                         3
V63.0121.021, Calculus I                                                                   Section 4.4 : Curve Sketching   November 18, 2010


 Step 1: Monotonicity
                                                                                                                Notes



                               f (x) = 2x 3 − 3x 2 − 12x
                      =⇒ f (x) = 6x 2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                           −                  −                       +
                                                                             x −2
                                                             2
                           −                  +                       +
                                                                             x +1
                               −1
                           +                  −                       +      f (x)
                               −1                           2                f (x)
                               max                         min


  V63.0121.021, Calculus I (NYU)            Section 4.4 Curve Sketching           November 18, 2010   10 / 55




 Step 2: Concavity
                                                                                                                Notes




                                      f (x) = 6x 2 − 6x − 12
                               =⇒ f (x) = 12x − 6 = 6(2x − 1)

 Another sign chart:

                              −−                     ++                      f (x)
                                            1/2                              f (x)
                                             IP




  V63.0121.021, Calculus I (NYU)            Section 4.4 Curve Sketching           November 18, 2010   11 / 55




 Step 3: One sign chart to rule them all
                                                                                                                Notes



 Remember, f (x) = 2x 3 − 3x 2 − 12x.

                     +   −                     −                 +        f (x)
                      −1                               2                  monotonicity
                    −−   −−                  ++                  ++       f (x)
                                      1/2                                 concavity
                          7          −61/2           −20                  f (x)
                         −1           1/2             2                   shape of f
                         max          IP             min




  V63.0121.021, Calculus I (NYU)            Section 4.4 Curve Sketching           November 18, 2010   12 / 55




                                                                                                                                           4
V63.0121.021, Calculus I                                                                      Section 4.4 : Curve Sketching   November 18, 2010


 Combinations of monotonicity and concavity
                                                                                                                   Notes
                   increasing,                                               decreasing,
                   concave                                                   concave
                   down                                                      down

                                      II                                I




                                     III                            IV


                   decreasing,                                               increasing,
                   concave up                                                concave up

  V63.0121.021, Calculus I (NYU)          Section 4.4 Curve Sketching                November 18, 2010   13 / 55




 Step 3: One sign chart to rule them all
                                                                                                                   Notes



 Remember, f (x) = 2x 3 − 3x 2 − 12x.

                     +   −                   −                  +            f (x)
                      −1                             2                       monotonicity
                    −−   −−                ++                ++              f (x)
                                    1/2                                      concavity
                          7        −61/2           −20                       f (x)
                         −1         1/2             2                        shape of f
                         max        IP             min




  V63.0121.021, Calculus I (NYU)          Section 4.4 Curve Sketching                November 18, 2010   14 / 55




 Step 4: Graph
                                               f (x)                                                               Notes




                    f (x) = 2x 3 − 3x 2 − 12x

                        √
                                      (−1, 7)
                      3− 105
                        4    ,0                          (0, 0)
                                                                                             √
                                                                                              x
                                                                (1/2, −61/2)               3+ 105
                                                                                             4    ,0

                                                                        (2, −20)


                                            7            −61/2              −20               f (x)
                                           −1             1/2                2                shape of f
                                           max             IP               min
  V63.0121.021, Calculus I (NYU)          Section 4.4 Curve Sketching                November 18, 2010   15 / 55




                                                                                                                                              5
V63.0121.021, Calculus I                                                                   Section 4.4 : Curve Sketching   November 18, 2010


 Graphing a quartic
                                                                                                                Notes




 Example
 Graph f (x) = x 4 − 4x 3 + 10

 (Step 0) We know f (0) = 10 and lim f (x) = +∞. Not too many other
                                                  x→±∞
 points on the graph are evident.




  V63.0121.021, Calculus I (NYU)          Section 4.4 Curve Sketching             November 18, 2010   16 / 55




 Step 1: Monotonicity
                                                                                                                Notes



                                     f (x) = x 4 − 4x 3 + 10
                            =⇒ f (x) = 4x 3 − 12x 2 = 4x 2 (x − 3)

 We make its sign chart.

                              + 0             +                   +
                                                                        4x 2
                                0
                              −               −              0 +
                                                                        (x − 3)
                                                             3
                              − 0             −              0 +        f (x)
                                0                            3          f (x)
                                                            min


  V63.0121.021, Calculus I (NYU)          Section 4.4 Curve Sketching             November 18, 2010   17 / 55




 Step 2: Concavity
                                                                                                                Notes



                                    f (x) = 4x 3 − 12x 2
                           =⇒ f (x) = 12x 2 − 24x = 12x(x − 2)

 Here is its sign chart:

                                   − 0     +                   +
                                                                         12x
                                     0
                                   −       −          0        +
                                                                         x −2
                                                      2
                              ++ 0        −−          0       ++         f (x)
                                 0                    2                  f (x)
                                IP                   IP


  V63.0121.021, Calculus I (NYU)          Section 4.4 Curve Sketching             November 18, 2010   18 / 55




                                                                                                                                           6
V63.0121.021, Calculus I                                                               Section 4.4 : Curve Sketching   November 18, 2010


 Step 3: Grand Unified Sign Chart
                                                                                                            Notes



 Remember, f (x) = x 4 − 4x 3 + 10.

                             − 0         −           − 0 +                   f (x)
                                0                      3                     monotonicity
                             ++ 0       −−        0 ++ ++                    f (x)
                                0                 2                          concavity
                               10                −6 −17                      f (x)
                                0                 2    3                     shape
                               IP                IP min




  V63.0121.021, Calculus I (NYU)        Section 4.4 Curve Sketching           November 18, 2010   19 / 55




 Step 4: Graph
                                             y                                                              Notes




            f (x) = x 4 − 4x 3 + 10


                                   (0, 10)
                                                                                       x
                                                  (2, −6)
                                                                  (3, −17)

                                         10                  −6       −17              f (x)
                                          0                   2        3               shape
                                         IP                  IP       min
  V63.0121.021, Calculus I (NYU)        Section 4.4 Curve Sketching           November 18, 2010   20 / 55




 Outline
                                                                                                            Notes


 Simple examples
    A cubic function
    A quartic function


 More Examples
   Points of nondifferentiability
   Horizontal asymptotes
   Vertical asymptotes
   Trigonometric and polynomial together
   Logarithmic




  V63.0121.021, Calculus I (NYU)        Section 4.4 Curve Sketching           November 18, 2010   21 / 55




                                                                                                                                       7
V63.0121.021, Calculus I                                                        Section 4.4 : Curve Sketching   November 18, 2010


 Graphing a function with a cusp
                                                                                                     Notes




 Example
 Graph f (x) = x +                 |x|

 This function looks strange because of the absolute value. But whenever
 we become nervous, we can just take cases.




  V63.0121.021, Calculus I (NYU)         Section 4.4 Curve Sketching   November 18, 2010   22 / 55




 Step 0: Finding Zeroes
                                                                                                     Notes

 f (x) = x +          |x|
       First, look at f by itself. We can tell that f (0) = 0 and that f (x) > 0
       if x is positive.
       Are there negative numbers which are zeroes for f ?
                                    √
                                x + −x = 0
                                    √
                                      −x = −x
                                                        −x = x 2
                                                    2
                                                  x +x =0

       The only solutions are x = 0 and x = −1.



  V63.0121.021, Calculus I (NYU)         Section 4.4 Curve Sketching   November 18, 2010   23 / 55




 Step 0: Asymptotic behavior
                                                                                                     Notes


 f (x) = x +          |x|
        lim f (x) = ∞, because both terms tend to ∞.
       x→∞
         lim f (x) is indeterminate of the form −∞ + ∞. It’s the same as
       x→−∞          √
         lim (−y + y )
       y →+∞
                                                                     √
                                           √              √            y +y
                             lim (−y +         y ) = lim ( y − y ) · √
                            y →+∞                   y →∞               y +y
                                                         y − y2
                                                   = lim √      = −∞
                                                    y →∞   y +y




  V63.0121.021, Calculus I (NYU)         Section 4.4 Curve Sketching   November 18, 2010   24 / 55




                                                                                                                                8
V63.0121.021, Calculus I                                                               Section 4.4 : Curve Sketching   November 18, 2010


 Step 1: The derivative
                                                                                                            Notes


 Remember, f (x) = x + |x|.
 To find f , first assume x > 0. Then
                                         d     √      1
                               f (x) =      x + x =1+ √
                                         dx          2 x

 Notice
       f (x) > 0 when x > 0 (so no critical points here)
         lim f (x) = ∞ (so 0 is a critical point)
       x→0+
        lim f (x) = 1 (so the graph is asymptotic to a line of slope 1)
       x→∞




  V63.0121.021, Calculus I (NYU)         Section 4.4 Curve Sketching          November 18, 2010   25 / 55




 Step 1: The derivative
                                                                                                            Notes
 Remember, f (x) = x + |x|.
 If x is negative, we have
                                        d     √          1
                             f (x) =       x + −x = 1 − √
                                        dx             2 −x
 Notice
         lim f (x) = −∞ (other side of the critical point)
       x→0−
         lim f (x) = 1 (asymptotic to a line of slope 1)
       x→−∞
       f (x) = 0 when

                  1        √     1         1          1
              1− √   = 0 =⇒ −x =   =⇒ −x =   =⇒ x = −
                2 −x             2         4          4



  V63.0121.021, Calculus I (NYU)         Section 4.4 Curve Sketching          November 18, 2010   26 / 55




 Step 1: Monotonicity
                                                                                                            Notes


                                               1
                                           1 + √
                                                                  if x > 0
                                   f (x) =     2 x
                                           1 − √1
                                                                  if x < 0
                                               2 −x
  We can’t make a multi-factor sign chart because of the absolute value,
 but we can test points in between critical points.

                                    +     0 − ∞                        +              f (x)
                                         −1   0                                       f (x)
                                           4
                                         max min




  V63.0121.021, Calculus I (NYU)         Section 4.4 Curve Sketching          November 18, 2010   27 / 55




                                                                                                                                       9
V63.0121.021, Calculus I                                                                  Section 4.4 : Curve Sketching   November 18, 2010


 Step 2: Concavity
                                                                                                               Notes
       If x > 0, then
                                            d         1                      1
                               f (x) =             1 + x −1/2             = − x −3/2
                                            dx        2                      4
       This is negative whenever x > 0.
       If x < 0, then
                                       d        1                            1
                         f (x) =             1 − (−x)−1/2                 = − (−x)−3/2
                                       dx       2                            4
     which is also always negative for negative x.
                                1
     In other words, f (x) = − |x|−3/2 .
                                4
 Here is the sign chart:

                                   −−                −∞                   −−             f (x)
                                                      0                                  f (x)

  V63.0121.021, Calculus I (NYU)            Section 4.4 Curve Sketching          November 18, 2010   28 / 55




 Step 3: Synthesis
                                                                                                               Notes


 Now we can put these things together.

                                            f (x) = x +           |x|

   +1                              +        0 − ∞                         +       +1 (x)
                                                                                   f
                                  −1     0                                         monotonicity
                                     4
  −∞                           −−     −−−∞                            −−          −∞ (x)
                                                                                   f
                                         0                                         concavity
                                   1
  −∞          0                    4     0                                        +∞(x)
                                                                                   f
             −1                   −1     0                                         shape
                                     4
            zero                  max min




  V63.0121.021, Calculus I (NYU)            Section 4.4 Curve Sketching          November 18, 2010   29 / 55




 Graph
                                                                                                               Notes


                                            f (x) = x +           |x|

                                                      f (x)



                                        (− 1 , 1 )
                                           4 4
              (−1, 0)
                                                                                          x
                                                           (0, 0)

                                               1
           −∞ 0                                4 0                                +∞ f (x)
              −1                            −1   0                                   shape
                                              4
             zero                           max min

  V63.0121.021, Calculus I (NYU)            Section 4.4 Curve Sketching          November 18, 2010   30 / 55




                                                                                                                                         10
V63.0121.021, Calculus I                                                  Section 4.4 : Curve Sketching   November 18, 2010


 Example with Horizontal Asymptotes
                                                                                               Notes




 Example
                             2
 Graph f (x) = xe −x




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   31 / 55




 Step 1: Monotonicity
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   32 / 55




 Step 2: Concavity
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   33 / 55




                                                                                                                         11
V63.0121.021, Calculus I                                                  Section 4.4 : Curve Sketching   November 18, 2010


 Step 3: Synthesis
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   34 / 55




 Step 4: Graph
                                                                                               Notes
                                        f (x)




                                                                                 x




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   35 / 55




 Example with Vertical Asymptotes
                                                                                               Notes




 Example
                      1   1
 Graph f (x) =          + 2
                      x  x




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   36 / 55




                                                                                                                         12
V63.0121.021, Calculus I                                                  Section 4.4 : Curve Sketching   November 18, 2010


 Step 0
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   37 / 55




 Step 1: Monotonicity
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   39 / 55




 Step 2: Concavity
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   40 / 55




                                                                                                                         13
V63.0121.021, Calculus I                                                  Section 4.4 : Curve Sketching   November 18, 2010


 Step 3: Synthesis
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   41 / 55




 Step 4: Graph
                                                                                               Notes


                                          y




                                                                 x




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   42 / 55




 Trigonometric and polynomial together
                                                                                               Notes




 Problem
 Graph f (x) = cos x − x




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   43 / 55




                                                                                                                         14
V63.0121.021, Calculus I                                                  Section 4.4 : Curve Sketching   November 18, 2010


 Step 0: intercepts and asymptotes
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   44 / 55




 Step 1: Monotonicity
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   45 / 55




 Step 2: Concavity
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   46 / 55




                                                                                                                         15
V63.0121.021, Calculus I                                                  Section 4.4 : Curve Sketching   November 18, 2010


 Step 3: Synthesis
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   47 / 55




 Step 4: Graph
                                                                                               Notes
 f (x) = cos x − x
                   y

                                                                                x




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   48 / 55




 Logarithmic
                                                                                               Notes




 Problem
 Graph f (x) = x ln x 2




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   49 / 55




                                                                                                                         16
V63.0121.021, Calculus I                                                  Section 4.4 : Curve Sketching   November 18, 2010


 Step 0: Intercepts and Asymptotes
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   50 / 55




 Step 1: Monotonicity
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   51 / 55




 Step 2: Concavity
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   52 / 55




                                                                                                                         17
V63.0121.021, Calculus I                                                  Section 4.4 : Curve Sketching   November 18, 2010


 Step 3: Synthesis
                                                                                               Notes




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   53 / 55




 Step 4: Graph
                                                                                               Notes




                                            y



                                                                                           x




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   54 / 55




 Summary
                                                                                               Notes




       Graphing is a procedure that gets easier with practice.
       Remember to follow the checklist.




  V63.0121.021, Calculus I (NYU)   Section 4.4 Curve Sketching   November 18, 2010   55 / 55




                                                                                                                         18

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Lesson 21: Curve Sketching (Section 021 handout)

  • 1. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Notes Section 4.4 Curve Sketching V63.0121.021, Calculus I New York University November 18, 2010 Announcements There is class on November 23. The homework is due on November 24. Turn in homework to my mailbox or bring to class on November 23. Announcements Notes There is class on November 23. The homework is due on November 24. Turn in homework to my mailbox or bring to class on November 23. V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 2 / 55 Objectives Notes given a function, graph it completely, indicating zeroes (if easy) asymptotes if applicable critical points local/global max/min inflection points V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 3 / 55 1
  • 2. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Why? Notes Graphing functions is like dissection . . . or diagramming sentences You can really know a lot about a function when you know all of its anatomy. V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 4 / 55 The Increasing/Decreasing Test Notes Theorem (The Increasing/Decreasing Test) If f > 0 on (a, b), then f is increasing on (a, b). If f < 0 on (a, b), then f is decreasing on (a, b). Example Here f (x) = x 3 + x 2 , and f (x) = 3x 2 + 2x. f (x) f (x) V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 5 / 55 Testing for Concavity Notes Theorem (Concavity Test) If f (x) > 0 for all x in (a, b), then the graph of f is concave upward on (a, b) If f (x) < 0 for all x in (a, b), then the graph of f is concave downward on (a, b). Example Here f (x) = x 3 + x 2 , f (x) = 3x 2 + 2x, and f (x) = 6x + 2. f (x) f (x) f (x) V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 6 / 55 2
  • 3. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Graphing Checklist Notes To graph a function f , follow this plan: 0. Find when f is positive, negative, zero, not defined. 1. Find f and form its sign chart. Conclude information about increasing/decreasing and local max/min. 2. Find f and form its sign chart. Conclude concave up/concave down and inflection. 3. Put together a big chart to assemble monotonicity and concavity data 4. Graph! V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 7 / 55 Outline Notes Simple examples A cubic function A quartic function More Examples Points of nondifferentiability Horizontal asymptotes Vertical asymptotes Trigonometric and polynomial together Logarithmic V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 8 / 55 Graphing a cubic Notes Example Graph f (x) = 2x 3 − 3x 2 − 12x. (Step 0) First, let’s find the zeros. We can at least factor out one power of x: f (x) = x(2x 2 − 3x − 12) so f (0) = 0. The other factor is a quadratic, so we the other two roots are √ 3 ± 32 − 4(2)(−12) 3 ± 105 x= = 4 4 It’s OK to skip this step for now since the roots are so complicated. V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 9 / 55 3
  • 4. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Step 1: Monotonicity Notes f (x) = 2x 3 − 3x 2 − 12x =⇒ f (x) = 6x 2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: − − + x −2 2 − + + x +1 −1 + − + f (x) −1 2 f (x) max min V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 10 / 55 Step 2: Concavity Notes f (x) = 6x 2 − 6x − 12 =⇒ f (x) = 12x − 6 = 6(2x − 1) Another sign chart: −− ++ f (x) 1/2 f (x) IP V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 11 / 55 Step 3: One sign chart to rule them all Notes Remember, f (x) = 2x 3 − 3x 2 − 12x. + − − + f (x) −1 2 monotonicity −− −− ++ ++ f (x) 1/2 concavity 7 −61/2 −20 f (x) −1 1/2 2 shape of f max IP min V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 12 / 55 4
  • 5. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Combinations of monotonicity and concavity Notes increasing, decreasing, concave concave down down II I III IV decreasing, increasing, concave up concave up V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 13 / 55 Step 3: One sign chart to rule them all Notes Remember, f (x) = 2x 3 − 3x 2 − 12x. + − − + f (x) −1 2 monotonicity −− −− ++ ++ f (x) 1/2 concavity 7 −61/2 −20 f (x) −1 1/2 2 shape of f max IP min V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 14 / 55 Step 4: Graph f (x) Notes f (x) = 2x 3 − 3x 2 − 12x √ (−1, 7) 3− 105 4 ,0 (0, 0) √ x (1/2, −61/2) 3+ 105 4 ,0 (2, −20) 7 −61/2 −20 f (x) −1 1/2 2 shape of f max IP min V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 15 / 55 5
  • 6. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Graphing a quartic Notes Example Graph f (x) = x 4 − 4x 3 + 10 (Step 0) We know f (0) = 10 and lim f (x) = +∞. Not too many other x→±∞ points on the graph are evident. V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 16 / 55 Step 1: Monotonicity Notes f (x) = x 4 − 4x 3 + 10 =⇒ f (x) = 4x 3 − 12x 2 = 4x 2 (x − 3) We make its sign chart. + 0 + + 4x 2 0 − − 0 + (x − 3) 3 − 0 − 0 + f (x) 0 3 f (x) min V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 17 / 55 Step 2: Concavity Notes f (x) = 4x 3 − 12x 2 =⇒ f (x) = 12x 2 − 24x = 12x(x − 2) Here is its sign chart: − 0 + + 12x 0 − − 0 + x −2 2 ++ 0 −− 0 ++ f (x) 0 2 f (x) IP IP V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 18 / 55 6
  • 7. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Step 3: Grand Unified Sign Chart Notes Remember, f (x) = x 4 − 4x 3 + 10. − 0 − − 0 + f (x) 0 3 monotonicity ++ 0 −− 0 ++ ++ f (x) 0 2 concavity 10 −6 −17 f (x) 0 2 3 shape IP IP min V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 19 / 55 Step 4: Graph y Notes f (x) = x 4 − 4x 3 + 10 (0, 10) x (2, −6) (3, −17) 10 −6 −17 f (x) 0 2 3 shape IP IP min V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 20 / 55 Outline Notes Simple examples A cubic function A quartic function More Examples Points of nondifferentiability Horizontal asymptotes Vertical asymptotes Trigonometric and polynomial together Logarithmic V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 21 / 55 7
  • 8. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Graphing a function with a cusp Notes Example Graph f (x) = x + |x| This function looks strange because of the absolute value. But whenever we become nervous, we can just take cases. V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 22 / 55 Step 0: Finding Zeroes Notes f (x) = x + |x| First, look at f by itself. We can tell that f (0) = 0 and that f (x) > 0 if x is positive. Are there negative numbers which are zeroes for f ? √ x + −x = 0 √ −x = −x −x = x 2 2 x +x =0 The only solutions are x = 0 and x = −1. V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 23 / 55 Step 0: Asymptotic behavior Notes f (x) = x + |x| lim f (x) = ∞, because both terms tend to ∞. x→∞ lim f (x) is indeterminate of the form −∞ + ∞. It’s the same as x→−∞ √ lim (−y + y ) y →+∞ √ √ √ y +y lim (−y + y ) = lim ( y − y ) · √ y →+∞ y →∞ y +y y − y2 = lim √ = −∞ y →∞ y +y V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 24 / 55 8
  • 9. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Step 1: The derivative Notes Remember, f (x) = x + |x|. To find f , first assume x > 0. Then d √ 1 f (x) = x + x =1+ √ dx 2 x Notice f (x) > 0 when x > 0 (so no critical points here) lim f (x) = ∞ (so 0 is a critical point) x→0+ lim f (x) = 1 (so the graph is asymptotic to a line of slope 1) x→∞ V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 25 / 55 Step 1: The derivative Notes Remember, f (x) = x + |x|. If x is negative, we have d √ 1 f (x) = x + −x = 1 − √ dx 2 −x Notice lim f (x) = −∞ (other side of the critical point) x→0− lim f (x) = 1 (asymptotic to a line of slope 1) x→−∞ f (x) = 0 when 1 √ 1 1 1 1− √ = 0 =⇒ −x = =⇒ −x = =⇒ x = − 2 −x 2 4 4 V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 26 / 55 Step 1: Monotonicity Notes  1 1 + √  if x > 0 f (x) = 2 x 1 − √1  if x < 0 2 −x We can’t make a multi-factor sign chart because of the absolute value, but we can test points in between critical points. + 0 − ∞ + f (x) −1 0 f (x) 4 max min V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 27 / 55 9
  • 10. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Step 2: Concavity Notes If x > 0, then d 1 1 f (x) = 1 + x −1/2 = − x −3/2 dx 2 4 This is negative whenever x > 0. If x < 0, then d 1 1 f (x) = 1 − (−x)−1/2 = − (−x)−3/2 dx 2 4 which is also always negative for negative x. 1 In other words, f (x) = − |x|−3/2 . 4 Here is the sign chart: −− −∞ −− f (x) 0 f (x) V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 28 / 55 Step 3: Synthesis Notes Now we can put these things together. f (x) = x + |x| +1 + 0 − ∞ + +1 (x) f −1 0 monotonicity 4 −∞ −− −−−∞ −− −∞ (x) f 0 concavity 1 −∞ 0 4 0 +∞(x) f −1 −1 0 shape 4 zero max min V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 29 / 55 Graph Notes f (x) = x + |x| f (x) (− 1 , 1 ) 4 4 (−1, 0) x (0, 0) 1 −∞ 0 4 0 +∞ f (x) −1 −1 0 shape 4 zero max min V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 30 / 55 10
  • 11. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Example with Horizontal Asymptotes Notes Example 2 Graph f (x) = xe −x V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 31 / 55 Step 1: Monotonicity Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 32 / 55 Step 2: Concavity Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 33 / 55 11
  • 12. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Step 3: Synthesis Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 34 / 55 Step 4: Graph Notes f (x) x V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 35 / 55 Example with Vertical Asymptotes Notes Example 1 1 Graph f (x) = + 2 x x V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 36 / 55 12
  • 13. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Step 0 Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 37 / 55 Step 1: Monotonicity Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 39 / 55 Step 2: Concavity Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 40 / 55 13
  • 14. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Step 3: Synthesis Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 41 / 55 Step 4: Graph Notes y x V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 42 / 55 Trigonometric and polynomial together Notes Problem Graph f (x) = cos x − x V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 43 / 55 14
  • 15. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Step 0: intercepts and asymptotes Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 44 / 55 Step 1: Monotonicity Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 45 / 55 Step 2: Concavity Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 46 / 55 15
  • 16. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Step 3: Synthesis Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 47 / 55 Step 4: Graph Notes f (x) = cos x − x y x V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 48 / 55 Logarithmic Notes Problem Graph f (x) = x ln x 2 V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 49 / 55 16
  • 17. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Step 0: Intercepts and Asymptotes Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 50 / 55 Step 1: Monotonicity Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 51 / 55 Step 2: Concavity Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 52 / 55 17
  • 18. V63.0121.021, Calculus I Section 4.4 : Curve Sketching November 18, 2010 Step 3: Synthesis Notes V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 53 / 55 Step 4: Graph Notes y x V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 54 / 55 Summary Notes Graphing is a procedure that gets easier with practice. Remember to follow the checklist. V63.0121.021, Calculus I (NYU) Section 4.4 Curve Sketching November 18, 2010 55 / 55 18