Week 5 HomeworkHomework #1Ms. Lisa Monnin is the budget dire.docx

Week 5 Homework
Homework #1
Ms. Lisa Monnin is the budget director for Nexus Media Inc.
She would like to compare the daily travel expenses for the
sales staff and the audit staff. She collected the following
sample information.
Sales ($)
129
137
142
162
137
145
Audit ($)
128
98
128
140
148
110
132
At the 0.1 significance level, can she conclude that the mean
daily expenses are greater for the sales staff than the audit
staff?
(a)
State the decision rule. (Round your answer to 3 decimal
places.)
Reject H0 if t >

(b)
Compute the pooled estimate of the population variance. (Round
your answer to 2 decimal places.)
Pooled variance
(c)
Compute the test statistic. (Round your answer to 3 decimal
places.)
Value of the test statistic
(d)
State your decision about the null hypothesis.
H0 : μs ≤ μa
(e)
Estimate the p-value. (Round your answers to 3 decimal places.)
p-value
Homework #2
Suppose you are an expert on the fashion industry and wish to
gather information to compare the amount earned per month by
models featuring Liz Claiborne attire with those of Calvin
Klein. Assume the population standard deviations are not the
same. The following is the amount ($000) earned per month by
a sample of Claiborne models:
$5.4

$4.3
$3.7
$6.7
$4.9
$5.9
$3.1
$5.2
$4.7
$3.5
5.8
4
3.1
5.6
6.9
The following is the amount ($000) earned by a sample of Klein
models.
$2.5
$2.6
$3.5
$3.4
$2.8
$3.1
$4
$2.5
$2
$2.9
2.7
2.3

(1)
Find the degrees of freedom for unequal variance test. (Round
down your answer to the nearest whole number.)
Degrees of freedom
(2)
State the decision rule for 0.01 significance
level: H0: μLC ≤ μCK; H1: μLC > μCK. (Round your answer to
3 decimal places.)
Reject H0 if t>
(3)
Compute the value of the test statistic. (Round your answer to 3
decimal places.)
(4)
Is it reasonable to conclude that Claiborne models earn more?
Use the 0.01 significance level.
H0. It is to conclude that Claiborne models earn more.

Homework #3
A recent study focused on the number of times men and women
who live alone buy take-out dinner in a month. The information
is summarized below.
Statistic
Men
Women
Sample mean
23.82
21.38
Population standard deviation
5.91
4.87
Sample size
34
36
At the .01 significance level, is there a difference in the mean
number of times men and women order take-out dinners in a
month?
(a)
decimal places.)
(b)
What is your decision regarding on null hypothesis?
The decision is the null hypothesis that the means are the
same.

(c)
What is the p-value? (Round your answer to 4 decimal places.)
p-value
rev: 04_04_2012, 04_25_2014_QC_48145
Homework #4
Suppose the manufacturer of Advil, a common headache
remedy, recently developed a new formulation of the drug that
is claimed to be more effective. To evaluate the new drug, a
sample of 210 current users is asked to try it. After a one-month
trial, 189 indicated the new drug was more effective in relieving
a headache. At the same time a sample of 300 current Advil
users is given the current drug but told it is the new
formulation. From this group, 255 said it was an improvement.
(1)
State the decision rule for .02 significance
level: H0: πn ≤ πc; H1: πn > πc. (Round your answer to 2
decimal places.)
Reject H0 if z >
(2)
Compute the value of the test statistic. (Do not round the
intermediate value. Round your answer to 2 decimal places.)
(3)

Can we conclude that the new drug is more effective? Use the
.02 significance level.
H0. We conclude that the new drug is more effective.
Homework #5
Lester Hollar is vice president for human resources for a large
manufacturing company. In recent years he has noticed an
increase in absenteeism that he thinks is related to the general
health of the employees. Four years ago, in an attempt to
improve the situation, he began a fitness program in which
employees exercise during their lunch hour. To evaluate the
program, he selected a random sample of eight participants and
found the number of days each was absent in the six months
before the exercise program began and in the last six months.
Below are the results.
Employee
Before
After
1
5
5
2
5
3
3
6
3
4
5
2
5
4
2
6

7
6
7
5
4
8
5
7
At the 0.05 significance level, can he conclude that the number
of absences has declined? Hint: For the calculations, assume the
"Before" data as the first sample.
Reject H0 if t > . (Round your answer to 3 decimal places.)
The test statistic is . (Round your answer to 3 decimal places.)
The p-value is .
Decision: H0.
Homework # 7
What is the critical F value for a sample of four observations in
the numerator and seven in the denominator? Use a one-tailed
test and the .01 significance level. (Round your answer to 2
decimal places.)
Homework #8
The following hypotheses are given.
Ho : σ1² = σ2²
H1 : σ1² ≠ σ2²
A random sample of eight observations from the first population

resulted in a standard deviation of 10. A random sample of six
observations from the second population resulted in a standard
deviation of 7.
(1)
State the decision rule for .02 significance level: (Round your
answer to 1 decimal place.)
Reject Ho if F >
(2)
decimal places.)
(3)
At the .02 significance level, is there a difference in the
variation of the two populations?
Ho. There is in the variations of the two populations.
Homework #9
A study of the effect of television commercials on 12-year-old
children measured their attention span, in seconds. The
commercials were for clothes, food, and toys.
Clothes
Food
Toys
26
45
60
21

48
51
43
43
43
35
53
54
28
47
63
31
42
53
17
34
48
31
43
58
20
57
47
47
51
44
51
54
Click here for the Excel Data File

(a)
Complete the ANOVA table. Use .05 significance level. (Round
the SS and MS values to 1 decimal place and F value to 2
decimal places. Leave no cells blank - be certain to enter "0"
wherever required. Round the DF values to nearest whole
number.)
Source
DF
SS
MS
F
P
Factors
Error
Total

(b)
Find the values of mean and standard deviation. (Round the
mean and standard deviation values to 3 decimal places.)
Level
N
Mean
StDev
Clothes
Food
Toys
(c)
Is there a difference in the mean attention span of the children
for the various commercials?

The hypothesis of identical means can definitely be .
There is in the mean attention span.
(d)
Are there significant differences between pairs of means?
Clothes have a mean attention span of at least ten minutes the
other groups.
Homework #10 through #16
Given the following sample information, test the hypothesis that
the treatment means are equal at the .05 significance level.
Treatment 1
Treatment 2
Treatment 3
8
3
3
11
2
4
10
1
5
3
4
2

10.
value:
4.50 points
(a-1)
State the null hypothesis and the alternate hypothesis.
Null hypothesis
Ho: μ1 = μ2
Ho: μ1 = μ2 = μ3
check my workreferences
11.
value:
4.50 points
(a-2)
Alternative hypothesis
H1: Treatment means are all the same
H1: Treatment means are not all the same
12.
value:
6.00 points

(b)
What is the decision rule? (Round your answer to 2 decimal
places.)
Reject Ho if F >
13.
value:
6.00 points
(c)
Compute SST, SSE, and SS total. (Round your answers to 2
decimal places.)
SST
SSE
SS total
14.
value:

6.00 points
(d)
Complete an ANOVA table. (Round F, SS to 2 decimal places
and MS to 3 decimal places.)
Source
SS
df
MS
F
Treatments
Error
Total

15.
value:
4.50 points
(e)
State your decision regarding the null hypothesis.
Reject H0.
Do not reject H0.
16.
value:
6.00 points
(f)
If H0 is rejected, can we conclude that treatment 1 and
treatment 2 differ? Use the 95 percent level of confidence.
, we conclude that the treatments 1 and 2 have different
means.
Quiz #1

Clark Heter is an industrial engineer at Lyons Products. He
would like to determine whether there are more units produced
on the night shift than on the day shift. A sample of 56 day-shift
workers showed that the mean number of units produced was
336, with a population standard deviation of 19. A sample of 61
night-shift workers showed that the mean number of units
produced was 341, with a population standard deviation of 25
units.
At the .02 significance level, is the number of units produced on
the night shift larger?
(1)
This is a -tailed test.
(2)
The decision rule is to reject if Z < . (Negative amount should
be indicated by a minus sign. Round your answer to 2 decimal
places.)
(3)
The test statistic is Z = . (Negative amount should be indicated
by a minus sign. Round your answer to 2 decimal places.)
(4)
What is your decision regarding ?
Quiz #2
Each month the National Association of Purchasing Managers
publishes the NAPM index. One of the questions asked on the
survey to purchasing agents is: Do you think the economy is
contracting? Last month, of the 260 responses, 161 answered

yes to the question. This month, 172 of the 246 responses
indicated they felt the economy was contracting.
At the .02 significance level, can we conclude that a larger
proportion of the agents believe the economy is contracting this
month?
pc = . (Do not round the intermediate value. Round your
answer to 2 decimal places.)
The test statistic is . (Negative amount should be indicated by a
minus sign. Do not round the intermediate value. Round your
answer to 2 decimal places.)
Decision: the null. H0 : π1 ≥ π2
Quiz #3
The manufacturer of an MP3 player wanted to know whether a
10 percent reduction in price is enough to increase the sales of
its product. To investigate, the owner randomly selected eight
outlets and sold the MP3 player at the reduced price. At seven
randomly selected outlets, the MP3 player was sold at the
regular price. Reported below is the number of units sold last
month at the sampled outlets.
Regular price
131
127
88
116
143
121
96
Reduced price
124

135
152
131
112
101
117
115
At the .100 significance level, can the manufacturer conclude
that the price reduction resulted in an increase in sales? Hint:
For the calculations, assume the Reduced price as the first
sample.
The pooled variance is . (Round your answer to 2 decimal
places.)
H0.
Quiz #4
The null and alternate hypotheses are:
The following paired observations show the number of traffic
citations given for speeding by Officer Dhondt and Officer
Meredith of the South Carolina Highway Patrol for the last five
months.
Day
May

June
July
August
September
Officer Dhondt
30
22
25
19
26
Officer Meredith
26
19
20
15
19
At the .05 significance level, is there a difference in the mean
number of citations given by the two officers?
(a)
State the decision rule. (Negative amounts should be indicated
by a minus sign. Round your answers to 3 decimal places.)
Reject H0 if t < or t > .
(b)
decimal places.)

(c)
What is your decision regarding H0 ?
H0
(d)
The p-value is .
Quiz #5
One of the music industry's most pressing questions is: Can paid
download stores contend nose-to-nose with free peer-to-peer
download services? Data gathered over the last 12 months show
Apple's iTunes was used by an average of 1.61 million
households with a sample standard deviation of .49 million
family units. Over the same 12 months WinMX (a no-cost P2P
download service) was used by an average of 2.20 million
families with a sample standard deviation of .28 million.
Assume the population standard deviations are not the same.
(a)
Find the degrees of freedom for unequal variance test. (Round
down your answer to nearest whole number.)
Degrees of freedom
(b)
State the decision rule for .02 significance
level: H0: A = W; H1: A ≠ W . (Negative amounts should be
indicated by a minus sign. Round your answer to 3 decimal
places.)
Reject H0 if t < or t >

(c)
Compute the value of the test statistic. (Negative amount should
be indicated by a minus sign.Round your answer to 2 decimal
places.)
(d)
Test the hypothesis of no difference in the mean number of
households picking either variety of service to download songs.
Use the .02 significance level.
H0. There is difference in the mean number of
households picking either variety of service to download songs.
Quiz #6
When only two treatments are involved, ANOVA and the
Student t test (Chapter 11) result in the same conclusions.
Also, . As an example, suppose that 14 randomly selected
students were divided into two groups, one consisting of 6
students and the other of 8. One group was taught using a
combination of lecture and programmed instruction, the other
using a combination of lecture and television. At the end of the
course, each group was given a 50-item test. The following is a
list of the number correct for each of the two groups. Using
analysis of variance techniques, test the null hypothesis, that
the two mean test scores are equal.
Lecture and
Programmed
Instruction
Lecture and
Television
14

33
13
27
24
36
22
21
14
28
12
25
26
24
(a-1)
Complete the ANOVA table. (Round SS, MS and F values to 2
decimal places.)
Source
SS
df
MS
F
Factors
Error

Total
(a-2)
Use a level of significance. (Round your answer to 2 decimal
places.)
The test statistic is F
(b)
Using the t test from Chapter 11, compute t.(Negative amount
should be indicated by a minus sign. Round your answer to 2
decimal places.)
t
(c)
There is in the mean test scores.

Quiz #7
The following hypotheses are given.
Ho : σ1² ≤ σ2²
H1 : σ1² > σ2²
A random sample of five observations from the first population
resulted in a standard deviation of 12. A random sample of
seven observations from the second population showed a
standard deviation of 7. At the .01 significance level, is there
more variation in the first population?
Decision: Ho
Quiz #8 THROUGH #14
Treatment 1
Treatment 2
Treatment 3
8
3
3
11
2
4
10
1
5
3
4

2
8.
(a-1)
State the null hypothesis and the alternate hypothesis.
Null hypothesis
Ho: μ1 = μ2
Ho: μ1 = μ2 = μ3
9.
(a-2)
Alternative hypothesis
H1: Treatment means are all the same
H1: Treatment means are not all the same
10.
(b)
What is the decision rule? (Round your answer to 2 decimal
places.)
Reject Ho if F >

11.
(c)
Compute SST, SSE, and SS total. (Round your answers to 2
decimal places.)
SST
SSE
SS total
12.
(d)
Complete an ANOVA table. (Round F, SS to 2 decimal places
and MS to 3 decimal places.)
Source
SS
df
MS
F
Treatments

Error
Total
13.
(e)
State your decision regarding the null hypothesis.
Do not reject H0.
Reject H0.
14.
(f)
If H0 is rejected, can we conclude that treatment 1 and

treatment 2 differ? Use the 95 percent level of confidence.
, we conclude that the treatments 1 and 2 have different
means.
Quiz #15
There are four radio stations in Midland. The stations have
different formats (hard rock, classical, country/western, and
easy listening), but each is concerned with the number of
minutes of music played per hour. From a sample of 10 hours
from each station, the following sample means were offered.
SS total = 650.75
(a)
SST = . (Round your answer to 3 decimal places.)
(b)
SSE = . (Round your answer to 3 decimal places.)
(c)
Complete an ANOVA table. (Round SS, MS, F to 3 decimal
places and df to nearest whole number.)
SS
df
MS
F
Treatments

Error
Total
(d)
At the .05 significance level, is there a difference in the
treatment means?
Quiz # 16
Treatment 1
Treatment 2
Treatment 3
3

9
6
2
6
3
5
5
5
1
6
5
3
8
5
1
5
4
4
1
7
5
6
4
(a)
Ho : μ1 μ2 μ3.

H1 : Treatment means all the same
(b)
Reject Ho if F > .(Round your answer to 2 decimal places.)
(c)
SST = SSE = SS total = (Round your answers to 2 decimal
places.)
(d)
Complete the ANOVA table. (Round SS, MS and F values to 2
decimal places.)
Source
SS
df
MS
F
Treatments
Error
Total

(e)
Decision: Ho
(f)
Find the 95% confidence interval for the difference between
treatment 2 and 3. (Round your answers to 2decimal places.)
95% confidence interval is: ±
We can conclude that the treatments 2 and 3 are
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