Seminar at School

1. Math Seminar

4. Presents……

6. TOPIC……..
 Linear Equation in One Variable….

7. Definition…

8. Meaning…
In a linear equation, each term is
written either in the form of a constant
or the product of first power of a
variable and the constant.
A linear equation in one variable is a
first-degree equation that can be
written in the form :
ax = b, a ≠≠ 0,
where a and b are real numbers.

9. Parts of an Equation
Here we
have an
equation
4x − 7 = 5
 A Variable is a symbol for a number
we don't know yet. It is usually a letter
like x or y.
 A number on its own is called
a Constant.
 A Coefficient is a number used to
multiply a variable
(4x means 4 times x, so 4 is a
coefficient)
 Variables without a number have a
coefficient of 1 (x is really 1x)
 Sometimes a letter stands in for the
number:

10. Parts of an Equation (Example)
4x − 7 = 5
 ‘4’ is the Coefficient.
 ‘x’ is the Variable.
 ‘-’ sign is the Operator.
 ‘7’ & ‘5’ are the Constants.
 ‘4x-7’ is the Expression.
 ‘4x’, ‘7’ & ‘5’ are the terms.

11. LHS & RHS…
In mathematics, LHS is
informal shorthand for
the left-hand side of
an equation.
Similarly, RHS is
the right-hand side.
The two sides have the
same value, expressed
differently, since
equality is symmetric.

12. Equation…
=LHS RHS

14. Solution of a Linear Equation…
Linear Equation with one variable
has only one solution and this
solution is also called as root of
the equation.
A value of the variable which
when substituted for the variable
in an equation makes LHS=RHS,
is called a solution / root of the
equation.

15. Strategy for Solving a Linear Equation …

16. APPLICATION OF LINEAR EQUATION
TO PRACTICAL PROBLEMS……

18. Solving Practical Problem…
This is first translated in the
form of an equation containing
unknown quantities (variables)
& known quantities (constants)
Then we can find the root /
solution of the linear equation.

19. PROBLEM-SOLVING STRATEGY FOR APPLICATIONS
OF LINEAR EQUATIONS
 Step 1: Define the Problem. Read the problem carefully.
Identify what you are trying to find and determine what
information is available to help you find it.
 Step 2: Assign Variables. Choose a variable to assign to an
unknown quantity in the problem.
 Step 3: Translate into an Equation. Use the relationships
among the known and unknown quantities to form an
equation.
 Step 4: Solve the Equation. Determine the value of the
variable and use the result to find any other unknown
quantities in the problem.
 Step 5: Check the Reasonableness of Your Answer. Check
to see if your answer makes sense within the context of the
problem. If not, check your work for errors and try again.
 Step 6: Answer the Question. Write a clear statement that
answers the question posed.

20. Linear Equation in Daily Life…
 We use equations frequently in our everyday lives,
and without even realizing it! We not only use
equations, we actually need equations, to solve most
of our problems that involves calculations.
 The applications of linear equations are observed on
a wide scale to solve word problems. In real life, the
applications of linear equations are vast. To tackle
real life problems using equations, we convert the
given situation into mathematical statements.

21. Linear equations
can be a useful tool
for comparing
rates of pay
If one company offers to pay you
Rs 450/- per week and the other
offers Rs 10/- per hour, and both
ask you to work 40 hours per
week, which company is offering
the better rate of pay?
A linear equation can help you !
The first company's offer is
expressed as 450 = 40x.
The second company's offer is
expressed as y = 10(40).
After comparing the two offers,
the equations tell you that the
first company is offering the
better rate of pay at Rs 11.25 per
hour.

22. Calculate your cab
fare for a trip home
by forming a linear
equation.
The boarding rate that the
driver requires is a
constant and the meter
rate is also a constant, but
must be multiplied by how
far you went. So, if the
meter rate is Rs 2/-,
the boarding rate is Rs 4/-
and time is represented by
"x", the linear equation
would be
2x + 4 = cab fare

23. 26/07/2017
Any Questions!!

25. Thank You