Assume that the winner of the game was to be the one who first won 4 deals out of 7. One gambler has so far won 1 deal and the other 2 deals. They agree to divide the stake according to the probability each had of winning the game. Assuming that each player had an equal probability of winning a given deal, what is each player\'s probability of winning the game? Solution Mn who has won two hands only needs two out of five so 60%. Other man needs to win 3/5 hands so his chances of winning are 40%.