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Max f(x) = 4x1 + 3x2                       Max f(x) = 4x1 + 3x2
sujeta a 2x1 + 3x2 ≤ 6                     sujeta a 2x1 + 3x2 + h1 = 6
        -3x1 + 2x2 ≤ 3                             -3x1 + 2x2 + h2 = 3
              2x2 ≤ 5                                    2x2 + h3 = 5
         2x1 + x2 ≤ 4                               2x1 + x2 + h4 = 4
            x1, x2 ≥ 0                                 x1, x2, h1, h2, h3, h4 ≥ 0

Base    f(x)       x1        x2            h1             h2       h3
f(x)           1        -4        -3              0            0        0
h1             0         2         3              1            0        0
h2             0        -3         2              0            1        0
h3             0         0         2              0            0        1
h4             0         2         1              0            0        0

Base    f(x)       x1        x2            h1             h2       h3
f(x)           1        0         -1              0            0        0
h1             0        0          2              1            0        0
h2             0        0         3 1/ 2          0            1        0
h3             0        0          2              0            0        1
x1             0        1           1/ 2          0            0        0

Base    f(x)       x1        x2            h1             h2       h3
f(x)           1        0          0               1/ 2        0        0
x2             0        0          1               1/ 2        0        0
h2             0        0          0            -1 3/ 4        1        0
h3             0        0          0             -1            0        1
x1             0        1          0             - 1/ 4        0        0

                  Solución óptima                         Var.     Coef. E
                  f(x) =        9                         x1             4
                  x1 =         1 1/ 2                     x2             3
                  x2 =          1
Max f(x) = 4x1 + 3x2
sujeta a 2x1 + 3x2 ≤ 6
        -3x1 + 2x2 ≤ 3                                    f(x) =        9
              2x2 ≤ 5
2x1 + x2 ≤ 4
   x1, x2 ≥ 0
f(x) - 4x1 - 3x2 = 0




h2, h3, h4 ≥ 0

        h4         Soluci.
              0        0
              0        6           3
              0        3          -1
              0        5         #DIV/0!
              1        4           2

        h4          Soluci.
              2         8
             -1         2          1
             1 1/ 2     9         2 4/ 7
              0         5         2 1/ 2
               1/ 2     2          4

        h4          Soluci.
             1 1/ 2     9
             - 1/ 2     1
             3 1/ 4    5 1/ 2
              1         3
               3/ 4    1 1/ 2

        valor      Coef. Tecnolog.         L.I.         L.D
            1 1/ 2     2        3               6             6
              1       -3        2             -2 1/ 2         3
                       0        2               2             5
                       2        1               4             4
                   x1       x2
Max U = 55m + 25s                             Max U = 55m + 25s
sujeta a 1m + 1s ≤ 60                         sujeta a 1m + 1s + h1= 60
        3m + 1s ≤ 115                                 3m + 1s +h2 =115
 6m + 25s ≤ 297.5                              6m + 25s +h3=297.5
        19m + 11s ≤ 510                               19m + 11s +h4= 510
           m, s ≥ 0                                      m, s ≥ 0

Base    f(x)       x1         x2              h1                 h2
f(x)           1        -55         -25                   0           0
h1             0          1           1                   1           0
h2             0          3           1                   0           1
h3             0          6          25                   0           0
h4             0         19          11                   0           0

Base    f(x)       x1         x2              h1                 h2
f(x)           1         0          6 16/19               0           0
h1             0         0             8/19               1           0
h2             0         0          - 14/19               0           1
h3             0         0         21 10/19               0           0
x1             0         1            11/19               0           0

Base    f(x)       x1         x2              h1                 h2
f(x)           1         0            0             -16   1/ 4        0
x2             0         0            1               2   3/ 8        0
h2             0         0            0               1   3/ 4        1
h3             0         0            0             -51   1/ 8        0
x1             0         1            0              -1   3/ 8        0

               Solución óptima                                   Var.
               U=           937 1/ 2                             m
               m=            -18 3/ 4                            s
               s=             78 3/ 4
Max U = 55m + 25s
sujeta a 1m + 1s ≤ 60
        3m + 1s ≤ 115     f(x) =
 6m + 25s ≤ 297.5
        19m + 11s ≤ 510
           m, s ≥ 0
U -55m - 25s = 0
 + h1= 60
+h2 =115

1s +h4= 510


       h3         h4            Soluci.
              0          0                   0
              0          0                  60                  60
              0          0                 115                 38 1/ 3
              1          0                297 1/ 2              49 4/7
              0          1                 510                26 16/19

       h3         h4       Soluci.
              0    2 17/19        1476 6/19
              0     - 1/19           33 3/19                    78 3/ 4
              0     - 3/19           34 9/19                 -46 11/14
              1     - 6/19         136 17/38                   6 21/62
              0       1/19          26 16/19                   46 4/11

       h3         h4            Soluci.
              0     3    3/ 4           937   1/ 2
              0      -   1/ 8            78   3/ 4
              0      -   1/ 4            92   1/ 2
              1     2    3/ 8         -1558   3/ 4
              0          1/ 8           -18   3/ 4

       Coef. E    valor         Coef. Tecnolog.                           L.I.
          55          1                    1                     1                2
          25          1                    3                     1                4
                                           6                    25               31
                                          19                    11               30
m   s
80
L.D
   6
   3
   5
   4
Ejemplos De Metodo Simplex

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Ejemplos De Metodo Simplex

  • 1. Max f(x) = 4x1 + 3x2 Max f(x) = 4x1 + 3x2 sujeta a 2x1 + 3x2 ≤ 6 sujeta a 2x1 + 3x2 + h1 = 6 -3x1 + 2x2 ≤ 3 -3x1 + 2x2 + h2 = 3 2x2 ≤ 5 2x2 + h3 = 5 2x1 + x2 ≤ 4 2x1 + x2 + h4 = 4 x1, x2 ≥ 0 x1, x2, h1, h2, h3, h4 ≥ 0 Base f(x) x1 x2 h1 h2 h3 f(x) 1 -4 -3 0 0 0 h1 0 2 3 1 0 0 h2 0 -3 2 0 1 0 h3 0 0 2 0 0 1 h4 0 2 1 0 0 0 Base f(x) x1 x2 h1 h2 h3 f(x) 1 0 -1 0 0 0 h1 0 0 2 1 0 0 h2 0 0 3 1/ 2 0 1 0 h3 0 0 2 0 0 1 x1 0 1 1/ 2 0 0 0 Base f(x) x1 x2 h1 h2 h3 f(x) 1 0 0 1/ 2 0 0 x2 0 0 1 1/ 2 0 0 h2 0 0 0 -1 3/ 4 1 0 h3 0 0 0 -1 0 1 x1 0 1 0 - 1/ 4 0 0 Solución óptima Var. Coef. E f(x) = 9 x1 4 x1 = 1 1/ 2 x2 3 x2 = 1 Max f(x) = 4x1 + 3x2 sujeta a 2x1 + 3x2 ≤ 6 -3x1 + 2x2 ≤ 3 f(x) = 9 2x2 ≤ 5
  • 2. 2x1 + x2 ≤ 4 x1, x2 ≥ 0
  • 3. f(x) - 4x1 - 3x2 = 0 h2, h3, h4 ≥ 0 h4 Soluci. 0 0 0 6 3 0 3 -1 0 5 #DIV/0! 1 4 2 h4 Soluci. 2 8 -1 2 1 1 1/ 2 9 2 4/ 7 0 5 2 1/ 2 1/ 2 2 4 h4 Soluci. 1 1/ 2 9 - 1/ 2 1 3 1/ 4 5 1/ 2 1 3 3/ 4 1 1/ 2 valor Coef. Tecnolog. L.I. L.D 1 1/ 2 2 3 6 6 1 -3 2 -2 1/ 2 3 0 2 2 5 2 1 4 4 x1 x2
  • 4.
  • 5. Max U = 55m + 25s Max U = 55m + 25s sujeta a 1m + 1s ≤ 60 sujeta a 1m + 1s + h1= 60 3m + 1s ≤ 115 3m + 1s +h2 =115 6m + 25s ≤ 297.5 6m + 25s +h3=297.5 19m + 11s ≤ 510 19m + 11s +h4= 510 m, s ≥ 0 m, s ≥ 0 Base f(x) x1 x2 h1 h2 f(x) 1 -55 -25 0 0 h1 0 1 1 1 0 h2 0 3 1 0 1 h3 0 6 25 0 0 h4 0 19 11 0 0 Base f(x) x1 x2 h1 h2 f(x) 1 0 6 16/19 0 0 h1 0 0 8/19 1 0 h2 0 0 - 14/19 0 1 h3 0 0 21 10/19 0 0 x1 0 1 11/19 0 0 Base f(x) x1 x2 h1 h2 f(x) 1 0 0 -16 1/ 4 0 x2 0 0 1 2 3/ 8 0 h2 0 0 0 1 3/ 4 1 h3 0 0 0 -51 1/ 8 0 x1 0 1 0 -1 3/ 8 0 Solución óptima Var. U= 937 1/ 2 m m= -18 3/ 4 s s= 78 3/ 4 Max U = 55m + 25s
  • 6. sujeta a 1m + 1s ≤ 60 3m + 1s ≤ 115 f(x) = 6m + 25s ≤ 297.5 19m + 11s ≤ 510 m, s ≥ 0
  • 7. U -55m - 25s = 0 + h1= 60 +h2 =115 1s +h4= 510 h3 h4 Soluci. 0 0 0 0 0 60 60 0 0 115 38 1/ 3 1 0 297 1/ 2 49 4/7 0 1 510 26 16/19 h3 h4 Soluci. 0 2 17/19 1476 6/19 0 - 1/19 33 3/19 78 3/ 4 0 - 3/19 34 9/19 -46 11/14 1 - 6/19 136 17/38 6 21/62 0 1/19 26 16/19 46 4/11 h3 h4 Soluci. 0 3 3/ 4 937 1/ 2 0 - 1/ 8 78 3/ 4 0 - 1/ 4 92 1/ 2 1 2 3/ 8 -1558 3/ 4 0 1/ 8 -18 3/ 4 Coef. E valor Coef. Tecnolog. L.I. 55 1 1 1 2 25 1 3 1 4 6 25 31 19 11 30
  • 8. m s 80
  • 9. L.D 6 3 5 4