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Siva Sankara Raju R, D.Ashok, Thimothy Pandi / International Journal of Engineering
             Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com
                     Vol. 3, Issue 1, January -February 2013, pp.733-737
Determination Of Stress And Deformations Analysis On Lpg Steel
                           Cylinder
               Siva Sankara Raju R*, D.Ashok**, Thimothy Pandi**
               *(Department of Mechanical Engineering, GIET, Gunupur, and Odisha, India.)
     ** (Department of Mechanical Engineering, BVSR ENGG.college , Chimakurthy ,Ongole,A.P, India.)
      ** (Department of Mechanical Engineering , MIRACLE., Bhogapuram, Vizianagaram, A.P, India.)


ABSTRACT
          This paper aims, Design and Analysis of       and the liquid reverts to gas. This means that it can
Liquefied Petroleum Gas (LPG) cylinders made            be transported and stored as liquid and burnt as gas.
of Steel. LP-gas inside a container is in two states    The expansion ratio of gas from liquid is 270:1 at
of matter, liquid and vapour. The liquid portion        atmospheric pressure. It is this expansion factor
of container is in the bottom and the vapour is in      which makes LP-Gas more economical to transport
the uppermost part of the vessel. Liquefied             and store large quantities of gaseous fuel in a small
Petroleum (LP) Gas is stored and handled as a           container in liquid state.
liquid when under pressure inside a LP-Gas                        LP-gas inside a container is in two states of
container. When compressed moderately at                matter, liquid and vapour. The liquid portion of
normal temperature, it becomes liquid. When gas         container is in the bottom and the vapour is in the
is withdrawn, the pressure drops and the liquid         uppermost part of the vessel, i.e. the space above the
reverts to gas. This means that it can be               liquid level. Containers are normally filled 80-85%
transported and stored as liquid and burnt as           liquid, leaving a 15-20% vapour space for expansion
gas.                                                    due to temperature increase. The vapour pressure of
          A number of cases are considered to           propane increases as the liquid temperature
study the stresses and deformations due to              increases. Propane at -420C inside a container would
pressure loading inside the cylinder. First, the        register zero pressure. At 00C, propane vapour
results of stresses and deformation for steel           pressure will increase to 380 kPa. At 380C, the
cylinders are compared with the analytical              vapour pressure of propane would be 1200 kPa [1].
solution available in literature in order to            LP-gas is odorless and non-toxic. A distinct
validate the model and the software. A variation        smelling odourant such as ethyl mercaptan is added
of stresses and deformations throughout the             as a detection agent for all domestic, and for most
cylinder made of steel is studied.                      commercial and industrial LP-gas. The purpose is to
          In this the cylinder is designed in Pro-E     introduce sufficient odourant so that the presence of
WILDFIRE to study the stresses and                      unburnt gas can be readily detected before it reaches
deformations of the cylinder. And it is converted       a mixture that is flammable and comes in contact
to Pro-E model to ANSYS to know variations of           with a source of ignition.
the steel cylinder when it is under some                II. LIQUEFIED PETROLEUM GAS (LPG)
conditions.                                             CYLINDERS

Keywords - LPG cylinder, Stress, Deformation,
FEM modeling.

I. INTRODUCTION
          LPG (propane or butane) is a colorless
liquid which readily evaporates into a gas. It has no
smell, although it will normally have an odour
added to help detect leaks. When mixed with air, the
gas can burn or explode when it meets a source of
ignition. It is heavier than air, so it tends to sink
towards the ground. Liquefied Petroleum (LP) Gas
is composed predominantly a mixture of the
following hydrocarbons: propane, propylene, butane
or butylenes. Liquefied Petroleum (LP) Gas is
stored and handled as a liquid when under pressure
inside a LP-Gas container. When compressed
moderately at normal temperature, it becomes            Fig. 1.1 Conventional Steel LPG cylinders
liquid. When gas is withdrawn, the pressure drops


                                                                                               733 | P a g e
Siva Sankara Raju R, D.Ashok, Thimothy Pandi / International Journal of Engineering
             Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com
                     Vol. 3, Issue 1, January -February 2013, pp.733-737
LPG is supplied in pressurised cylinders to keep it    Radius of Cylinder =162.5mm
liquefied. The LPG (Liquefied Petroleum Gas)           Note: Here mean radius (160mm) has been taken
Cylinders (fig.1.1), from past many years, are being   for modeling.
manufactured in our country from the very              Empty gas cylinder weight = 15.9kg (with frames
conventional metallic material such as steel. The      and holders)          13.0kg (without frames)
weight of the cylinder becomes more as density of      Gas weight = 14.2kg
steel is higher compared to other light weight         Assumption: End dome is hemispherical.
materials. In household applications, thrust should    2.4 Cylindrical Portion
be given towards use of low density materials so
that the weight will come down. With the               DO =325mm         Di= (325-2t) mm
advancement of low-density materials like FRP [2]      t= Thickness of the cylinder.
(Fiber Reinforced Plastic) Composites, we can think    Volume =V1= π/ 4(DO2-Di2) ×L …..(6)
of producing LPG cylinders with FRP to reduce its       = π /4 (3252 - (325-2t) 2)  L = π/4 (1300t-4t2)
weight in future.                                       360
         The present work deals with the Finite        2.5 END PORTION [4]
Element Analysis of LPG cylinders made of              Volume=V2=43  8 πD3 = π6 (DO3 – Di3) … (7)
conventional material (such as steel).                 = π6 {(325)3 – (325-2t) 3)}
                                                          =π6 {(3253) – [(3253) - (2t3) - 3  325  2t (325-
III. INDENTATIONS AND EQUATIONS                        2t)]} =π6 [8t3+633750t-3900t2]
IV. LPG CYLINDER MADE CALCULATIONS                     Total Volume V=V1+V2 … (8)
[3]                                                         =π4 (468000t-1440t2) +π 6 (8t3+633750t-
Input Specifications                                   3900t2)
Empty gas cylinder weight = 15.9 kg (with frames       Mass=volume  density ….(9)
and holders)            13.0 kg (without frames)      Density=7.8gmcm3 = 7.8e-3 gmmm3
Gas weight                 =14.2kg                     V = [32t3-(15600+8640t2) + (2535000+2808000) t]
Volume of the Gas          = 47.8 liters               mm3
Perimeter                  = 102cm                     = 24 *13000 *1000 mm3
Assumptions: (1) End dome is hemispherical                      7.8 * 
 (2) Cylinder has been modeled without end frames.     Or 32t3-24240t2+5343000t =12732395.45
Thickness of the cylinder = 2.4mm~2.5mm                  Or 32t3-24240t2+5343000t-12732395.45 = 0
                                                       After solving above equation, Thickness of the
Analytical Calculation for LPG Steel cylinder          cylinder = 2.4mm ~ 2.5 mm
A. Cylindrical portion
                    pd 1.2 * 320                       V. GEOMETRIC MODEL
HoopStress,  H                 76.8Mpa                      The geometry of the gas cylinder [5] is
                    2t   2 * 2.5
                                                       shown in fig.2. It has been approximated by
..(1)
                                                       hemispherical ends of 160mm radius. Length of the
Longitudinal
                                                       cylindrical portion is 360mm. The total length of the
stress,  L  pd  1.2 * 320  38.4Mpa …(2)            cylinder is 680mm.
              4t    4 * 2.5
Longitudinalstrain,
     L         38.4
                      0.000185…(3)
      E       207 * E 3
Longitudinal
Deformation,   Pr 1     0.050 mm …(4)
                   2


                    2 Et
b. Hemispherical End dome portion
Hoop stress,
       pd 1.2 * 320
L                 38.4Mpa … (5)
       4t   4 * 2.5
LPG Cylinder wall thickness calculation
        Since the thickness of LPG cylinder is not
provided by the manufacturer, it has been              Fig 2:Geometric model of LPG cylinder without
approximated using following approach.                 end frames
Perimeter of Cylinder, P =102cm
Diameter of Cylinder, D = 102/π = 32.46 cm             VI. MATERIAL PROPERTIES
=324.6mm                                               The material used is steel for which material
                      DO  325mm                       properties are listed below.


                                                                                             734 | P a g e
Siva Sankara Raju R, D.Ashok, Thimothy Pandi / International Journal of Engineering
             Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com
                     Vol. 3, Issue 1, January -February 2013, pp.733-737
Density, ρ                          = 7.8 gm/cc
Young’s modulus, E                  = 207Gpa
Poisson ratio,                     = 0.3
UTS, σ                              = 800 MPa
Yield strength                      = 480 MPa




                                                        Fig 6 Internal pressure applied on Steel cylinder

                                                        VIII. RESULTS AND DISCUSSIONS
                                                                 The       longitudinal    (X-component)
                                                        Displacement contour plot is shown in fig.7. For
Fig 3: 3-D View of the geometric model                  which the maximum displacement is occurring at
                                                        the extreme points in the x-direction. Maximum
VII. LOADS AND BOUNDARY CONDITIONS                      Longitudinal displacement = 0.0332 mm
          The figure 4 is the finite element model of
the steel cylinder. Mapped mesh has been done for
this model taking size control as 28 X 4 along the
circumference of hemisphere and size control 40
along the longitudinal length of the cylinder.[7]
          An internal pressure load of 1.2 MPa has
been applied as shown in fig.6. To simulate a proper
boundary condition, the mid symmetrical nodes of
the cylinder are fixed in X-degree of freedom (Ux =
0) as shown in fig.5. Here it has been assumed that
the mid plane deformation along x-direction is zero.


                                                        Fig 7 Longitudinal Displacement (in mm) plot for
                                                        steel cylinder
                                                                  The longitudinal (X-component) Stress
                                                        contour plot is shown in fig.8. For which the
                                                        maximum stress is occurring at the mid plane at
                                                        which the cylinder is constrained along the
                                                        longitudinal direction (x-direction).
                                                        Maximum Longitudinal stress = 43.48 MPa




Fig 4: FE Mesh Model for Steel cylinder




                                                        Fig 8 Longitudinal stress (in MPa) contour plot
                                                        for steel cylinder
                                                                  The Hoop (Y-component) Stress contour
                                                        plot is shown in fig.9. Maximum Hoop stress =
                                                        79.30 MPa
Fig 5 Boundary condition applied on cylinder


                                                                                            735 | P a g e
Siva Sankara Raju R, D.Ashok, Thimothy Pandi / International Journal of Engineering
             Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com
                     Vol. 3, Issue 1, January -February 2013, pp.733-737




Fig 9 Hoop stress (MPa) contour plot for steel         Fig 12: Graph for the Longitudinal Displacement
cylinder
         The figure 10 is the figure showing the
Vonmises stress plot for steel cylinder .For which
the Maximum Vonmises stress =68.81 MPa and the
yield strength of the steel is 480 MPa. So, the
maximum stress occurring is within the limits and
the design is safe. Maximum Vonmises stress
=68.81 MPa




                                                       Fig: 13 Longitudinal Stress variations Graph for
                                                       Steel Cylinder
                                                                 The detailed results of FE analysis as well
                                                       as classical method for the cylinder are listed below.

                                                       Table 1:Comparison of results for steel
                                                                            FE            CLASSICAL
                                                       Sl.No RESULTS
                                                                            METHOD METHOD
                                                               Longitudinal
Fig 10 Von-mises stress contour plot for steel         1                    43.48         38.4
                                                               stress, MPa
cylinder
         The figure 11 shows the nodes which are                                 Hoop stress,
                                                       2                                                  79.3            76.8
selected to draw the Longitudinal Displacement                                   MPa
variation graph (fig 12) and the Longitudinal Stress                             Von-mises
variation graph (fig 13) for Steel Cylinder.           3                                                  68.81           66.5
                                                                                 stress, MPa

                                                                                 Longitudinal
                                                       4                         Deformation,             0.033           0.05
                                                                                 mm

                                                                                    com parision results for steel


                                                                        90
                                                                        80
                                                                        70
                                                                        60
                                                           stress MPa




                                                                        50                                                       Finite element menthod
                                                                        40                                                       classical method
                                                                        30
                                                                        20
                                                                        10
                                                                        0
                                                                             0        1       2           3       4   5
Fig 11: Nodes selected along the axis                                                             SI.NO


                                                       Fig: 14 Stress variations Graph comparison
                                                       results for Steel Cylinder


                                                                                                                          736 | P a g e
Siva Sankara Raju R, D.Ashok, Thimothy Pandi / International Journal of Engineering
            Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com
                    Vol. 3, Issue 1, January -February 2013, pp.733-737
IX. CONCLUSION                                          Reinforced Composites; Wiley publishers;
          Based on the analysis of LPG cylinder              2nd Edition; 1990.
made of steel, the following salient conclusions        7)   Geoff Eckold; “Design and Manufacture of
have emerged out from the present investigations:            Composite Structures”; Jaico publishing
By conducting analysis of LPG steel cylinder the             House; 1995.
stresses and deformations under pressure load of the
cylinder are found. These results are compared with
analytical solutions which are seen in the table
above Table: 1.
Several stresses and deformations are studied and
the solutions are given in the form of diagrams and
graphs.
          Some variations of results of the LPG steel
cylinder is generated while studying FE method and
Analytical method.

X. FEATURE SCOPE OF WORK
1. Material properties evaluation of FRP composite
   laminate by coupon level testing. The properties
   used for FE analysis are taken from available
   literatures, whereas the end properties of
   composites are highly dependent on process and
   laborer’s skill.
2. Optimization of winding angle in CNC filament
   winding process.
3. Fiber orientation is the decisive factor in the
   strength of the composites.
4. Detailed design of FRP cylinders including end
   frames and its attachment with the cylinders.
5. Burst Test of the LPG cylinders for its
   qualification as per ASME.
6. Workout for the complete costing for FRP
   cylinders as well as existing steel cylinders, and
   to study its suitability in Indian scenario.

REFERENCES
  1)     Determination of stresses of LPG gas
         cylinder by finite element method, Mrs.
         P.m. Zode, P.G. Mehar, Laxmikant D.
         Rangari,          issn        no-2231-5063
         vol.1,issue.x/april 2012 pp.1-4.
  2)     Jones, R. M; Mechanics of Composite
         Materials; Mc Graw Hill Book Co.; 1975.
  3)     Failure analysis of an exploded gas
         cylinder ,Majid M. Mirzaei / Engineering
         Failure Analysis 15 (2008) 820–834
  4)     Transportable Refillable Welded Duplex
         Stainless Steel LPG Cylinders-for use in
         Hot Air Balloons and Hot Air Airships.
         CYL-HAB-01, Issue 1,Revision A:
         September 2004 .
  5)     PTC (2008-01-16). "PTC Introduces
         Pro/ENGINEER® Wildfire® 4.0 With
         New Industry Leading Capabilities To
         Drive Process Improvements". Press
         release.
         http://www.ptc.com/appserver/wcms/stand
         ards/textsub.jsp?&im_dbkey=65281.
  6)     Agarwal, B. D and Brootman, L. J;
         Analysis and performance of Fiber

                                                                                       737 | P a g e

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Dg31733737

  • 1. Siva Sankara Raju R, D.Ashok, Thimothy Pandi / International Journal of Engineering Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com Vol. 3, Issue 1, January -February 2013, pp.733-737 Determination Of Stress And Deformations Analysis On Lpg Steel Cylinder Siva Sankara Raju R*, D.Ashok**, Thimothy Pandi** *(Department of Mechanical Engineering, GIET, Gunupur, and Odisha, India.) ** (Department of Mechanical Engineering, BVSR ENGG.college , Chimakurthy ,Ongole,A.P, India.) ** (Department of Mechanical Engineering , MIRACLE., Bhogapuram, Vizianagaram, A.P, India.) ABSTRACT This paper aims, Design and Analysis of and the liquid reverts to gas. This means that it can Liquefied Petroleum Gas (LPG) cylinders made be transported and stored as liquid and burnt as gas. of Steel. LP-gas inside a container is in two states The expansion ratio of gas from liquid is 270:1 at of matter, liquid and vapour. The liquid portion atmospheric pressure. It is this expansion factor of container is in the bottom and the vapour is in which makes LP-Gas more economical to transport the uppermost part of the vessel. Liquefied and store large quantities of gaseous fuel in a small Petroleum (LP) Gas is stored and handled as a container in liquid state. liquid when under pressure inside a LP-Gas LP-gas inside a container is in two states of container. When compressed moderately at matter, liquid and vapour. The liquid portion of normal temperature, it becomes liquid. When gas container is in the bottom and the vapour is in the is withdrawn, the pressure drops and the liquid uppermost part of the vessel, i.e. the space above the reverts to gas. This means that it can be liquid level. Containers are normally filled 80-85% transported and stored as liquid and burnt as liquid, leaving a 15-20% vapour space for expansion gas. due to temperature increase. The vapour pressure of A number of cases are considered to propane increases as the liquid temperature study the stresses and deformations due to increases. Propane at -420C inside a container would pressure loading inside the cylinder. First, the register zero pressure. At 00C, propane vapour results of stresses and deformation for steel pressure will increase to 380 kPa. At 380C, the cylinders are compared with the analytical vapour pressure of propane would be 1200 kPa [1]. solution available in literature in order to LP-gas is odorless and non-toxic. A distinct validate the model and the software. A variation smelling odourant such as ethyl mercaptan is added of stresses and deformations throughout the as a detection agent for all domestic, and for most cylinder made of steel is studied. commercial and industrial LP-gas. The purpose is to In this the cylinder is designed in Pro-E introduce sufficient odourant so that the presence of WILDFIRE to study the stresses and unburnt gas can be readily detected before it reaches deformations of the cylinder. And it is converted a mixture that is flammable and comes in contact to Pro-E model to ANSYS to know variations of with a source of ignition. the steel cylinder when it is under some II. LIQUEFIED PETROLEUM GAS (LPG) conditions. CYLINDERS Keywords - LPG cylinder, Stress, Deformation, FEM modeling. I. INTRODUCTION LPG (propane or butane) is a colorless liquid which readily evaporates into a gas. It has no smell, although it will normally have an odour added to help detect leaks. When mixed with air, the gas can burn or explode when it meets a source of ignition. It is heavier than air, so it tends to sink towards the ground. Liquefied Petroleum (LP) Gas is composed predominantly a mixture of the following hydrocarbons: propane, propylene, butane or butylenes. Liquefied Petroleum (LP) Gas is stored and handled as a liquid when under pressure inside a LP-Gas container. When compressed moderately at normal temperature, it becomes Fig. 1.1 Conventional Steel LPG cylinders liquid. When gas is withdrawn, the pressure drops 733 | P a g e
  • 2. Siva Sankara Raju R, D.Ashok, Thimothy Pandi / International Journal of Engineering Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com Vol. 3, Issue 1, January -February 2013, pp.733-737 LPG is supplied in pressurised cylinders to keep it Radius of Cylinder =162.5mm liquefied. The LPG (Liquefied Petroleum Gas) Note: Here mean radius (160mm) has been taken Cylinders (fig.1.1), from past many years, are being for modeling. manufactured in our country from the very Empty gas cylinder weight = 15.9kg (with frames conventional metallic material such as steel. The and holders)  13.0kg (without frames) weight of the cylinder becomes more as density of Gas weight = 14.2kg steel is higher compared to other light weight Assumption: End dome is hemispherical. materials. In household applications, thrust should 2.4 Cylindrical Portion be given towards use of low density materials so that the weight will come down. With the DO =325mm Di= (325-2t) mm advancement of low-density materials like FRP [2] t= Thickness of the cylinder. (Fiber Reinforced Plastic) Composites, we can think Volume =V1= π/ 4(DO2-Di2) ×L …..(6) of producing LPG cylinders with FRP to reduce its = π /4 (3252 - (325-2t) 2)  L = π/4 (1300t-4t2) weight in future.  360 The present work deals with the Finite 2.5 END PORTION [4] Element Analysis of LPG cylinders made of Volume=V2=43  8 πD3 = π6 (DO3 – Di3) … (7) conventional material (such as steel). = π6 {(325)3 – (325-2t) 3)} =π6 {(3253) – [(3253) - (2t3) - 3  325  2t (325- III. INDENTATIONS AND EQUATIONS 2t)]} =π6 [8t3+633750t-3900t2] IV. LPG CYLINDER MADE CALCULATIONS Total Volume V=V1+V2 … (8) [3] =π4 (468000t-1440t2) +π 6 (8t3+633750t- Input Specifications 3900t2) Empty gas cylinder weight = 15.9 kg (with frames Mass=volume  density ….(9) and holders)  13.0 kg (without frames) Density=7.8gmcm3 = 7.8e-3 gmmm3 Gas weight =14.2kg V = [32t3-(15600+8640t2) + (2535000+2808000) t] Volume of the Gas = 47.8 liters mm3 Perimeter = 102cm = 24 *13000 *1000 mm3 Assumptions: (1) End dome is hemispherical 7.8 *  (2) Cylinder has been modeled without end frames. Or 32t3-24240t2+5343000t =12732395.45 Thickness of the cylinder = 2.4mm~2.5mm Or 32t3-24240t2+5343000t-12732395.45 = 0 After solving above equation, Thickness of the Analytical Calculation for LPG Steel cylinder cylinder = 2.4mm ~ 2.5 mm A. Cylindrical portion pd 1.2 * 320 V. GEOMETRIC MODEL HoopStress,  H    76.8Mpa The geometry of the gas cylinder [5] is 2t 2 * 2.5 shown in fig.2. It has been approximated by ..(1) hemispherical ends of 160mm radius. Length of the Longitudinal cylindrical portion is 360mm. The total length of the stress,  L  pd  1.2 * 320  38.4Mpa …(2) cylinder is 680mm. 4t 4 * 2.5 Longitudinalstrain, L 38.4    0.000185…(3) E 207 * E 3 Longitudinal Deformation,   Pr 1     0.050 mm …(4) 2 2 Et b. Hemispherical End dome portion Hoop stress, pd 1.2 * 320 L    38.4Mpa … (5) 4t 4 * 2.5 LPG Cylinder wall thickness calculation Since the thickness of LPG cylinder is not provided by the manufacturer, it has been Fig 2:Geometric model of LPG cylinder without approximated using following approach. end frames Perimeter of Cylinder, P =102cm Diameter of Cylinder, D = 102/π = 32.46 cm VI. MATERIAL PROPERTIES =324.6mm The material used is steel for which material DO  325mm properties are listed below. 734 | P a g e
  • 3. Siva Sankara Raju R, D.Ashok, Thimothy Pandi / International Journal of Engineering Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com Vol. 3, Issue 1, January -February 2013, pp.733-737 Density, ρ = 7.8 gm/cc Young’s modulus, E = 207Gpa Poisson ratio,  = 0.3 UTS, σ = 800 MPa Yield strength = 480 MPa Fig 6 Internal pressure applied on Steel cylinder VIII. RESULTS AND DISCUSSIONS The longitudinal (X-component) Displacement contour plot is shown in fig.7. For Fig 3: 3-D View of the geometric model which the maximum displacement is occurring at the extreme points in the x-direction. Maximum VII. LOADS AND BOUNDARY CONDITIONS Longitudinal displacement = 0.0332 mm The figure 4 is the finite element model of the steel cylinder. Mapped mesh has been done for this model taking size control as 28 X 4 along the circumference of hemisphere and size control 40 along the longitudinal length of the cylinder.[7] An internal pressure load of 1.2 MPa has been applied as shown in fig.6. To simulate a proper boundary condition, the mid symmetrical nodes of the cylinder are fixed in X-degree of freedom (Ux = 0) as shown in fig.5. Here it has been assumed that the mid plane deformation along x-direction is zero. Fig 7 Longitudinal Displacement (in mm) plot for steel cylinder The longitudinal (X-component) Stress contour plot is shown in fig.8. For which the maximum stress is occurring at the mid plane at which the cylinder is constrained along the longitudinal direction (x-direction). Maximum Longitudinal stress = 43.48 MPa Fig 4: FE Mesh Model for Steel cylinder Fig 8 Longitudinal stress (in MPa) contour plot for steel cylinder The Hoop (Y-component) Stress contour plot is shown in fig.9. Maximum Hoop stress = 79.30 MPa Fig 5 Boundary condition applied on cylinder 735 | P a g e
  • 4. Siva Sankara Raju R, D.Ashok, Thimothy Pandi / International Journal of Engineering Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com Vol. 3, Issue 1, January -February 2013, pp.733-737 Fig 9 Hoop stress (MPa) contour plot for steel Fig 12: Graph for the Longitudinal Displacement cylinder The figure 10 is the figure showing the Vonmises stress plot for steel cylinder .For which the Maximum Vonmises stress =68.81 MPa and the yield strength of the steel is 480 MPa. So, the maximum stress occurring is within the limits and the design is safe. Maximum Vonmises stress =68.81 MPa Fig: 13 Longitudinal Stress variations Graph for Steel Cylinder The detailed results of FE analysis as well as classical method for the cylinder are listed below. Table 1:Comparison of results for steel FE CLASSICAL Sl.No RESULTS METHOD METHOD Longitudinal Fig 10 Von-mises stress contour plot for steel 1 43.48 38.4 stress, MPa cylinder The figure 11 shows the nodes which are Hoop stress, 2 79.3 76.8 selected to draw the Longitudinal Displacement MPa variation graph (fig 12) and the Longitudinal Stress Von-mises variation graph (fig 13) for Steel Cylinder. 3 68.81 66.5 stress, MPa Longitudinal 4 Deformation, 0.033 0.05 mm com parision results for steel 90 80 70 60 stress MPa 50 Finite element menthod 40 classical method 30 20 10 0 0 1 2 3 4 5 Fig 11: Nodes selected along the axis SI.NO Fig: 14 Stress variations Graph comparison results for Steel Cylinder 736 | P a g e
  • 5. Siva Sankara Raju R, D.Ashok, Thimothy Pandi / International Journal of Engineering Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com Vol. 3, Issue 1, January -February 2013, pp.733-737 IX. CONCLUSION Reinforced Composites; Wiley publishers; Based on the analysis of LPG cylinder 2nd Edition; 1990. made of steel, the following salient conclusions 7) Geoff Eckold; “Design and Manufacture of have emerged out from the present investigations: Composite Structures”; Jaico publishing By conducting analysis of LPG steel cylinder the House; 1995. stresses and deformations under pressure load of the cylinder are found. These results are compared with analytical solutions which are seen in the table above Table: 1. Several stresses and deformations are studied and the solutions are given in the form of diagrams and graphs. Some variations of results of the LPG steel cylinder is generated while studying FE method and Analytical method. X. FEATURE SCOPE OF WORK 1. Material properties evaluation of FRP composite laminate by coupon level testing. The properties used for FE analysis are taken from available literatures, whereas the end properties of composites are highly dependent on process and laborer’s skill. 2. Optimization of winding angle in CNC filament winding process. 3. Fiber orientation is the decisive factor in the strength of the composites. 4. Detailed design of FRP cylinders including end frames and its attachment with the cylinders. 5. Burst Test of the LPG cylinders for its qualification as per ASME. 6. Workout for the complete costing for FRP cylinders as well as existing steel cylinders, and to study its suitability in Indian scenario. REFERENCES 1) Determination of stresses of LPG gas cylinder by finite element method, Mrs. P.m. Zode, P.G. Mehar, Laxmikant D. Rangari, issn no-2231-5063 vol.1,issue.x/april 2012 pp.1-4. 2) Jones, R. M; Mechanics of Composite Materials; Mc Graw Hill Book Co.; 1975. 3) Failure analysis of an exploded gas cylinder ,Majid M. Mirzaei / Engineering Failure Analysis 15 (2008) 820–834 4) Transportable Refillable Welded Duplex Stainless Steel LPG Cylinders-for use in Hot Air Balloons and Hot Air Airships. CYL-HAB-01, Issue 1,Revision A: September 2004 . 5) PTC (2008-01-16). "PTC Introduces Pro/ENGINEER® Wildfire® 4.0 With New Industry Leading Capabilities To Drive Process Improvements". Press release. http://www.ptc.com/appserver/wcms/stand ards/textsub.jsp?&im_dbkey=65281. 6) Agarwal, B. D and Brootman, L. J; Analysis and performance of Fiber 737 | P a g e