please write carefully and explain clearly. Thank you. Solution Ksp of CoCO3 = 1*10^-10 CoCO3 (s) -----------------> Co^2+ (aq) + CO3^2- (aq) s s Ksp = [Co^2+][CO3^2-] Ksp = s*s Ksp = s^2 1*10^-10 = s^2 s^2 = 1*10^-10 s = 1*10^-5 mole/L molar mass of CoCO3 = 118.94g/mole solubility of cobalt(II) carbonate = 1*10^-5 mole/L = 1*10^-5 mole/L * 118.94g/mole = 1.1894*10^-3g/L = 1.1894mg/L The solubility of CoCO3 = 1.1894mg/L .