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Quadratic
Functions
π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐 = 0
Quadratic Functions
Here are examples of different types of parabolas
As you can see looking at the image, all the
parabolas are U-shaped and they open either
upwards or downwards. If you rotate it to open
sideways, this function fails the vertical line test
β€’ Polynomial equation in a single variable where the highest exponent of the variable is 2
β€’ Also known as a parabola (U-shaped and they open in 1 direction)
π‘Žπ‘₯2 βˆ’ π‘žπ‘’π‘Žπ‘‘π‘Ÿπ‘Žπ‘‘π‘–π‘ π‘‘π‘’π‘Ÿπ‘š 𝑏π‘₯ βˆ’ π‘™π‘–π‘›π‘’π‘Žπ‘Ÿ π‘‘π‘’π‘Ÿπ‘š 𝑐 βˆ’ π‘π‘œπ‘›π‘ π‘‘π‘Žπ‘›π‘‘
Here are some examples:
a = 2; b = 5; c = 3
a = 1; b = - 3; c = 0
not a quadratic equation
In Disguise Quadratic Equations π‘Žπ‘₯2
+ 𝑏π‘₯ + 𝑐 = 0
2π‘₯ (4π‘₯ + 1) = 3 8π‘₯2
+ 2π‘₯ βˆ’ 3 = 0
(π‘₯ + 3)2
= 0 π‘₯2
+ 6π‘₯ + 9 = 0
1
π‘₯
=
2π‘₯
π‘₯ + 4
2π‘₯2
βˆ’ π‘₯ βˆ’ 4 = 0
Determine if the given equations are quadratic
equations.
a. 4π‘₯2 + 8π‘₯ βˆ’ 2 = 0
b. 9π‘₯2
+ 45 = 0
c. π‘₯3
+ 5π‘₯2
βˆ’ 4 = 0
d. π‘₯ βˆ’ 4 = 0
e.6π‘₯5 + π‘₯3 + 3 = 0
f. 10π‘₯2 βˆ’ 5π‘₯ = 12
Quadratic
Quadratic
Non - quadratic
Non - quadratic
Non - quadratic
Quadratic
Determine if the given equations are quadratic equations.
a. π‘₯2 + 3π‘₯ = 0
b. 2π‘₯ βˆ’ 6 = 0
c. 2 βˆ’ 5π‘₯2 + π‘₯3 = 0
Quadratic
Non - quadratic
Non - quadratic
1. Express the following quadratic equations in the
form of π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐 = 0
a. π‘₯2 = 5π‘₯ + 6
b. βˆ’π‘₯2
= 4π‘₯ + 4
c. 3x βˆ’ 6π‘₯2 = 7
d. βˆ’π‘₯2 βˆ’ 2 = 3π‘₯
π‘₯2 βˆ’ 5π‘₯ βˆ’ 6 = 0
π‘₯2
+ 4π‘₯ + 4 = 0
6π‘₯2 βˆ’ 3π‘₯ + 7 = 0
π‘₯2 + 3π‘₯ + 2 = 0
2. Show that 5x(x+3) = 4x – 5 is a quadratic equation.
5x(x+3) = 4x – 5
5π‘₯2 + 15π‘₯ = 4π‘₯ βˆ’ 5
5π‘₯2 + 15π‘₯ βˆ’ 4π‘₯ + 5 = 0
5π‘₯2 + 11π‘₯ + 5 = 0
5π‘₯2 + 11π‘₯ + 5 = 0
a. Express 2π‘₯2 = 6 βˆ’ 7π‘₯ in the form of π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐 = 0
b. Write (2x+1)(x-3) = 0 as a quadratic equation in
standard form
a. 2π‘₯2
+ 7π‘₯ βˆ’ 6 = 0
b. 2π‘₯2 βˆ’ 5π‘₯ βˆ’ 3 = 0
Practice and Apply
I.Determine if the equations are quadratic or non – quadratic equations. Write Q if
the equation is a quadratic equation, write NQ if the equation is non – quadratic,
justify.
1. z2 βˆ’ 2z βˆ’ 1 = 0
2. 4c2 βˆ’ 5c = 0
3. x3
βˆ’ 8 = 0
4. h βˆ’ 24h βˆ’ h2 = 0
5. 4d – 3 = 10
6. 9v2
+ v = 9v2
βˆ’ 6
7. 12x2 βˆ’ 10x = 5x βˆ’ x5
8. 5w2
βˆ’ 25 = 0
9. (x+1)(x-3)=0
10. x = 2x2 + 1
11. 3-a2
= 0
12. w3 + 2 = w2
13. 3(3x+1)=0
14. x(x2
βˆ’ 1) = x
15. -b2 = b βˆ’ 2
NQ
NQ
NQ
NQ
NQ
Q
Q
Q
NQ
Q
Q
Q
Q
Q
NQ
II.Write the following quadratic equations in the form π‘Žπ‘₯2
+ 𝑏π‘₯ + 𝑐 = 0. Identify
the values of a, b, c.
1. 6p2
= 42
2. b2 = 9 βˆ’ 13b
3. t2
βˆ’ 5 = 4t
4. βˆ’3x2
= 2b βˆ’ 9
5. 4 – 7g βˆ’ g2 = 0
6. x2
= 3x βˆ’ 5
7. L=m2 βˆ’ 6m
8. 2c2
= 5 βˆ’ c
9. 12-f=f2
10. k2
βˆ’ l = k
11. x2 = βˆ’5
12. 6x2 βˆ’ 4x = 1
13.
1
2
b2 = b + 1
14. m=3-m2
15. 10=y2 βˆ’ 3y
III.Express each of the following equations as a quadratic equation. Write your answers
in the form π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐 = 0.
1. (2x+1)(x – 1) = 0
2. (x βˆ’ 4)(2x βˆ’ 5) = 0
3. x 3 βˆ’ 5x = 2
4. (x+5)(3x βˆ’ 1) = x(x + 1)
5. x x + 1 = x + 2
6. 3x(x+1)=(x βˆ’ 2)2
7. (2x βˆ’ 5)(x + 1) = 3x βˆ’ 2
8. (3x βˆ’ 1)2= x + 1
9. 5x = 2 + (x βˆ’ 1)(x + 2)
10. 6x(3x+2)=2x(10x-1)
The quadratic formula is
used for finding the value
of x
a, b , c = constants, where a β‰  0
π‘₯2 + 3π‘₯ βˆ’ 4 = 0
a = 1 b = 3 c = -4
x = 1
x +4 = 0
x = -4
By factoring: (x – 1)(x + 4) = 0
x – 1 = 0
π‘₯2 + 3π‘₯ βˆ’ 4 = 0
a = 1 b = 3 c = -4
By factoring: (x – 1)(x + 4) = 0
π‘₯ =
βˆ’π‘ Β± 𝑏2 βˆ’ 4π‘Žπ‘
2π‘Ž
π‘₯ =
βˆ’3 Β± (3)2βˆ’4(1)(βˆ’4)
2(1)
π‘₯ =
βˆ’3 Β± 9 + 16
2
π‘₯ =
βˆ’3 Β± 25
2
π‘₯ =
βˆ’3 Β± 5
2
π‘₯ =
βˆ’3 + 5
2
=
2
2
= 1
π‘₯ =
βˆ’3 βˆ’ 5
2
=
βˆ’8
2
= βˆ’4
4𝑛2 + 16 = 0
2π‘₯2 + 4π‘₯ + 8 = 24
2π‘₯2 βˆ’ 4π‘₯ βˆ’ 3 = 0
2π‘₯2 + 5π‘₯ + 3 = 0
π‘₯2 βˆ’ 3π‘₯ = 0
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Quadratic Functions.pptx

  • 2. Quadratic Functions Here are examples of different types of parabolas As you can see looking at the image, all the parabolas are U-shaped and they open either upwards or downwards. If you rotate it to open sideways, this function fails the vertical line test β€’ Polynomial equation in a single variable where the highest exponent of the variable is 2 β€’ Also known as a parabola (U-shaped and they open in 1 direction)
  • 3. π‘Žπ‘₯2 βˆ’ π‘žπ‘’π‘Žπ‘‘π‘Ÿπ‘Žπ‘‘π‘–π‘ π‘‘π‘’π‘Ÿπ‘š 𝑏π‘₯ βˆ’ π‘™π‘–π‘›π‘’π‘Žπ‘Ÿ π‘‘π‘’π‘Ÿπ‘š 𝑐 βˆ’ π‘π‘œπ‘›π‘ π‘‘π‘Žπ‘›π‘‘
  • 4. Here are some examples: a = 2; b = 5; c = 3 a = 1; b = - 3; c = 0 not a quadratic equation
  • 5. In Disguise Quadratic Equations π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐 = 0 2π‘₯ (4π‘₯ + 1) = 3 8π‘₯2 + 2π‘₯ βˆ’ 3 = 0 (π‘₯ + 3)2 = 0 π‘₯2 + 6π‘₯ + 9 = 0 1 π‘₯ = 2π‘₯ π‘₯ + 4 2π‘₯2 βˆ’ π‘₯ βˆ’ 4 = 0
  • 6. Determine if the given equations are quadratic equations. a. 4π‘₯2 + 8π‘₯ βˆ’ 2 = 0 b. 9π‘₯2 + 45 = 0 c. π‘₯3 + 5π‘₯2 βˆ’ 4 = 0 d. π‘₯ βˆ’ 4 = 0 e.6π‘₯5 + π‘₯3 + 3 = 0 f. 10π‘₯2 βˆ’ 5π‘₯ = 12 Quadratic Quadratic Non - quadratic Non - quadratic Non - quadratic Quadratic
  • 7. Determine if the given equations are quadratic equations. a. π‘₯2 + 3π‘₯ = 0 b. 2π‘₯ βˆ’ 6 = 0 c. 2 βˆ’ 5π‘₯2 + π‘₯3 = 0 Quadratic Non - quadratic Non - quadratic
  • 8. 1. Express the following quadratic equations in the form of π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐 = 0 a. π‘₯2 = 5π‘₯ + 6 b. βˆ’π‘₯2 = 4π‘₯ + 4 c. 3x βˆ’ 6π‘₯2 = 7 d. βˆ’π‘₯2 βˆ’ 2 = 3π‘₯ π‘₯2 βˆ’ 5π‘₯ βˆ’ 6 = 0 π‘₯2 + 4π‘₯ + 4 = 0 6π‘₯2 βˆ’ 3π‘₯ + 7 = 0 π‘₯2 + 3π‘₯ + 2 = 0
  • 9. 2. Show that 5x(x+3) = 4x – 5 is a quadratic equation. 5x(x+3) = 4x – 5 5π‘₯2 + 15π‘₯ = 4π‘₯ βˆ’ 5 5π‘₯2 + 15π‘₯ βˆ’ 4π‘₯ + 5 = 0 5π‘₯2 + 11π‘₯ + 5 = 0 5π‘₯2 + 11π‘₯ + 5 = 0
  • 10. a. Express 2π‘₯2 = 6 βˆ’ 7π‘₯ in the form of π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐 = 0 b. Write (2x+1)(x-3) = 0 as a quadratic equation in standard form a. 2π‘₯2 + 7π‘₯ βˆ’ 6 = 0 b. 2π‘₯2 βˆ’ 5π‘₯ βˆ’ 3 = 0
  • 11. Practice and Apply I.Determine if the equations are quadratic or non – quadratic equations. Write Q if the equation is a quadratic equation, write NQ if the equation is non – quadratic, justify. 1. z2 βˆ’ 2z βˆ’ 1 = 0 2. 4c2 βˆ’ 5c = 0 3. x3 βˆ’ 8 = 0 4. h βˆ’ 24h βˆ’ h2 = 0 5. 4d – 3 = 10 6. 9v2 + v = 9v2 βˆ’ 6 7. 12x2 βˆ’ 10x = 5x βˆ’ x5 8. 5w2 βˆ’ 25 = 0 9. (x+1)(x-3)=0 10. x = 2x2 + 1 11. 3-a2 = 0 12. w3 + 2 = w2 13. 3(3x+1)=0 14. x(x2 βˆ’ 1) = x 15. -b2 = b βˆ’ 2 NQ NQ NQ NQ NQ Q Q Q NQ Q Q Q Q Q NQ
  • 12. II.Write the following quadratic equations in the form π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐 = 0. Identify the values of a, b, c. 1. 6p2 = 42 2. b2 = 9 βˆ’ 13b 3. t2 βˆ’ 5 = 4t 4. βˆ’3x2 = 2b βˆ’ 9 5. 4 – 7g βˆ’ g2 = 0 6. x2 = 3x βˆ’ 5 7. L=m2 βˆ’ 6m 8. 2c2 = 5 βˆ’ c 9. 12-f=f2 10. k2 βˆ’ l = k 11. x2 = βˆ’5 12. 6x2 βˆ’ 4x = 1 13. 1 2 b2 = b + 1 14. m=3-m2 15. 10=y2 βˆ’ 3y
  • 13. III.Express each of the following equations as a quadratic equation. Write your answers in the form π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐 = 0. 1. (2x+1)(x – 1) = 0 2. (x βˆ’ 4)(2x βˆ’ 5) = 0 3. x 3 βˆ’ 5x = 2 4. (x+5)(3x βˆ’ 1) = x(x + 1) 5. x x + 1 = x + 2 6. 3x(x+1)=(x βˆ’ 2)2 7. (2x βˆ’ 5)(x + 1) = 3x βˆ’ 2 8. (3x βˆ’ 1)2= x + 1 9. 5x = 2 + (x βˆ’ 1)(x + 2) 10. 6x(3x+2)=2x(10x-1)
  • 14. The quadratic formula is used for finding the value of x a, b , c = constants, where a β‰  0
  • 15. π‘₯2 + 3π‘₯ βˆ’ 4 = 0 a = 1 b = 3 c = -4 x = 1 x +4 = 0 x = -4 By factoring: (x – 1)(x + 4) = 0 x – 1 = 0
  • 16. π‘₯2 + 3π‘₯ βˆ’ 4 = 0 a = 1 b = 3 c = -4 By factoring: (x – 1)(x + 4) = 0 π‘₯ = βˆ’π‘ Β± 𝑏2 βˆ’ 4π‘Žπ‘ 2π‘Ž π‘₯ = βˆ’3 Β± (3)2βˆ’4(1)(βˆ’4) 2(1) π‘₯ = βˆ’3 Β± 9 + 16 2 π‘₯ = βˆ’3 Β± 25 2 π‘₯ = βˆ’3 Β± 5 2 π‘₯ = βˆ’3 + 5 2 = 2 2 = 1 π‘₯ = βˆ’3 βˆ’ 5 2 = βˆ’8 2 = βˆ’4
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