Write a program that prompts the user to enter a positive integer and.pdf

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Write a program that prompts the user to enter a positive integer and displays all its smallest factors in decreasing order. For example, if the integer is 120, the smallest factors are displayed as 5, 3, 2, 2, 2. Use the StackOflntegers class to store the factors (e.g., 2, 2, 2, 3, 5) and retrieve and display them in reverse order. Solution #include #include using namespace std; class StackOfIntegers { int s[100],top; public: StackOfIntegers() { top=-1; } void put(int n) { top++; s[top]=n; } int get() { if(top==-1) { return -1; } return s[top--]; } }stack; void primeFactors(int n) { while (n%2 == 0) { stack.put(2); n = n/2; } for (int i=3; i<=sqrt(n); i=i+2) { while (n%i==0) { stack.put(i); n = n/i; } } if (n > 2) stack.put(n); } int main() { int n; cout<<\"Enter a positive integer : \"; cin>>n; primeFactors(n); int f; f=stack.get(); while(f>0) { cout<.

Education

n = n/i;
}
}
if (n > 2)
stack.put(n);
}
int main() {
int n;
cout<<"Enter a positive integer : ";
cin>>n;
primeFactors(n);
int f;
f=stack.get();
while(f>0) {
cout<

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Using following main file and solve the task Instead of ID and GPA, now consider following fields: Name, ID and Contact numberInsert last (already done)Display All (already done)Insert at the beginningDelete the first elementDelete the last elementSearch an element (by ID)Insert after an elementDisplay how many elements are there in the listFind the element with highest (biggest) IDFind the element with lowest (smallest) ID // main file please solve all it ... Thank You :) Using following main file and solve the task Instead of ID and GPA, now consider following fields: Name, ID and Contact numberInsert last (already done)Display All (already done)Insert at the beginningDelete the first elementDelete the last elementSearch an element (by ID)Insert after an elementDisplay how many elements are there in the listFind the element with highest (biggest) IDFind the element with lowest (smallest) ID // main file please solve all it ... Thank You :) Instead of ID and GPA, now consider following fields: Name, ID and Contact numberInsert last (already done)Display All (already done)Insert at the beginningDelete the first elementDelete the last elementSearch an element (by ID)Insert after an elementDisplay how many elements are there in the listFind the element with highest (biggest) IDFind the element with lowest (smallest) ID // main file please solve all it ... Thank You :) // main file please solve all it ... Thank You :) Solution // main file #include #include using namespace std; struct node{ //change to name , ID and contact number string name; int ID; ; string phone; //double GPA; node *link; }; node *head=NULL, *t; void insertNode() { node *temp=new node; cout<<\"Enter name..\"; cin>>temp->name; cout<<\"Enter the ID..\"; cin>>temp->ID; cout<<\"Enter Phone..\"; cin>>temp->phone; temp->link=NULL; if(head==NULL)//list is empty { head=temp; } else { t=head; while(t->link!=NULL) t=t->link; t->link=temp; } } void displayAll() { node *t=head; while(t!=NULL) { cout<<\"Name=\"<name<ID<phone<link; } } void isertAtbegin() { node *cur = head; node *temp=new node; cout<<\"Enter name..\"; cin>>temp->name; cout<<\"Enter the ID..\"; cin>>temp->ID; cout<<\"Enter Phone..\"; cin>>temp->phone; head = temp; temp->link = cur; } void deleteFirstElement() { node *cur = head,*prev=head; head = head->link; free(cur); } void searchElement(int ID) { node *cur = head; int found = 0,pos=0; while( cur!=NULL) { if( ID == cur->ID ) { found = 1; break; } cur = cur->link; ++pos; } if( found ) cout<<\"Element with Id= \"<link; node *temp=new node; cout<<\"Enter name..\"; cin>>temp->name; cout<<\"Enter the ID..\"; cin>>temp->ID; cout<<\"Enter Phone..\"; cin>>temp->phone; temp->link=next; cur->link = temp; break; } cur = cur->link; ++pos; } } void displayNumberOfelements() { node *cur = head; int count = 0; while( cur!=NULL) { ++count; cur = cur->link; } cout<<\"Number of elements in list = \"<ID; while( cur!=NULL) { if(max < cur ->ID) { max = cur ->ID; } cur = cur->link; } cout<<\.

Using following main file and solve the taskInst.pdf

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Suppose there are 14 children trying to form two teams with seven ch.pdf

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11. Define a simple deformable model to detect a half-circular shape (may be rotated). What will be the energy function? Solution shape is a recurring theme in computer vision. For example, shape is one of the main sources of information that can be used for object recognition. In medical image analysis, geometrical models of anatomical structures play an important role in automatic tissue segmentation. The shape of an organ can also be used to diagnose diseases. In a completely different setting, shape plays an important role in the perception of optical illusions (we tend to see particular shapes) and this can be used to explain how our visual system interprets the ambiguous and incomplete information available in an image. Our main goal is to develop techniques that can be used to represent and detect relatively generic objects in images. The techniques we present here revolve around a particular shape representation, based on the description of objects using triangulated polygons. Triangulated polygons allow us to describe complex shapes using simple building blocks. As we show in the next section, the triangles that decompose a polygon without holes are connected together in a tree structure, and this has important algorithmic consequences. By picking a particular triangulation for the polygons we obtain decompositions of objects into meaningful parts. This yields a discrete representation closely related to Blum’s medial axis transform [6]. In this paper we concentrate on the task of finding the location of a deformable shape in an image. This problem is important for the recognition of non-rigid objects. Moreover, objects in many generic classes can be described as deformed versions of an ideal template. In this setting, the location of an object is given by a continuous map from a template to an image. Figure 1 illustrates how we use a deformable template to detect a particular anatomical structure in an MR image. We will show how triangulated polygons provide rich models for deformable shapes. These models can capture both boundary and interior information of an object and can be deformed in an intuitive way. Equally important, we present an efficient algorithm for finding the optimal location of a deformable shape in an image. In contrast, previous methods that take into account the interior of deformable objects. The geometric properties of rigid objects are well understood. We know how three dimensional features such as corners or edges project into images, and there are a number of methods that can be used to represent rigid shapes and locate their projections. Some techniques, such as the alignment method [23], use explicit three dimensional representations. Other techniques, such as linear combination of views [36], capture the appearance of three dimensional shapes using a small number of two dimensional pictures. These and similar techniques assume that all shape variation comes from the viewpoint dependency of two dimensiona.

11. Define a simple deformable model to detect a half-circular shape.pdf

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