What is the difference between a BSS and a ESSSolutionBSS sta.pdf

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what is IOT what us Solution Ans. IOT stands for Internet of Things: It is a connection of devices over internet to build applications and services which will serve people needs. It is a network of applications built over a planned structure to make human lives easy. It can cover as small a need like an email protocol to as large a need as smart homes. With the advent of internet and cloud technologies, it has a bright future ahead. It can be extended to army services too..

What is the difference between a BSS and a ESS?
Solution
BSS statnds for Basic Service Set, where as ESS is Extended Service Set.
BSS consists of single central access point whereas, ESS is a multiple BSS networks connected
together.
BSS connects wireless clients to wired infrastructure, and is called infrastructure mode, ESS
cover a wide area and allows for roaming between accesspoints.
BSS is more secured, whereas, ESS is not as secure as BSS.

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saplinglearning.com O.CHM.111.309A.SP18 Northern Virginia Community College, Alexandria-CHM 111 - Spring Chlorine Jump to... 2/26/2018 12:00 AM O 3.6/5 ( 2/25/2018 10:17 PM Gradeboo Calculator IncorrectIncarrect -Print -d Periodic Table Question 11 of 13 Map Sapling Learning gas can be prepared in the laboratory by the reaction of hydrochiloric acid with manganese(iy) oxide: You add 43.3 g of MnO2 to a solution containing 43.7 g of HCI. (a) What is the limiting reactant? HC (b) What is the theoretical yield of Ch? Number 70.29 CI (c) If the yield of the reaction is 763%, what is the actual yield of chlorine? Number 53.63 g CI Exit ePrev ous Give Up & View Souton OCheck Answer ONect about us careers privacy policy e of use contact us help Solution a) according to balanced reaction 4 x 36.5 g HCl reacts with 86.94 g MnO2 43.7 g HCl reacts with 43.7 x 86.94 / 4 x 36.5 = 26.02 g MnO2. but we have 43.3 g MnO2. so MnO2 present in exess. limiting reagent = HCl limiting reagent = HCl b) 4 x 36.5 g HCl gives 71 g Cl2 43.7 g HCl gives 43.7 x 71 / 4 x 36.5 = 21.25 g therotical yield of Cl2 = 21.25 g c) % yield = (actual yield / therotical yield) x 100 76.3 = (actual yield / 21.25) x 100 0.763 = actual yield / 21.25 actual yield = 16.21 g.

Satellites in geosynchronous orbit have the desirable property of re.pdf

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Requirement 1. Determine the maturity date and maturity value of each note. (For each applicable note, compute interest using a 365-day year. Round to the nearest dollar.) Due date Date Principal Amount Interest Rate Month/Day Year Maturity value Note (1) Apr. 1 (2) Sep. 30 Term Apr. 12019 20,000 22,000 16,000 13% 5% 11% 1 year 6 months Sep. 302019 Dec. 18 2018 Sep. 19 90 days Requirement 2. Jounalize the entries to establish each Note Receivable and to record collection of principal and interest at maturity. Include a single adjusting entry on December 31, 2018, the fiscal year-end, to record accrued interest revenue on any applicable note. Explanations are not required. Round to the nearest dollar. (Record debits first, then credits. Exclude explanations from journal entries.) Begin with the jounal entry to establish nate 1 Debit Credit Date 2018 Apr. 1 Data Table Date Principal Amount Interest Rate Term 1 year 6 months Note (1) Apr. (2) Sep. 30 20,000 22,000 16,000 13% 5% 11% Jcurnalize the entry to establish note 2. Debit Credit Sep. 19 90 days Date 2018 Sep. 30 Accounts and Explanation PrintDone Solution.

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Please make sure it works I\'ve been struggling with this and so far every answer I\'ve got back is wrong. l. Input an integer value altitude and use a loop to write your own graphics program \'fall.cpp\' that produces a graphic representation of falling object (e.g. circle). An object has initial downward velocity 0. Each second, it\'s velocity increases by 32 ft/sec Plot the descent of the falling object. Note that terminal velocity is 174 ft/sec so the object\'s velocity cannot exceed that speed. Now modify your program to read an integer variable secondstoopen to open a parachute after n seconds. Assume the velocity decreases by 100 ft/sec after the chute opens until the downward velocity hits 17 ft/sec. Note that outside the bottom of the loop is the code for where the chutist has landed put a message there. (use C++ code please) Solution #include #include using namespace std; void fuel(float & dist); void distance(float dist, float & time, float & time2 ); void Altitude(float time, float time2, float altlevel); void Climb_Descend(float altlevel); int main(int argc, char *argv[]) { float altlevel; float dist; int fuelcon; float speed=300, altspeed; char choice; bool OK; do { fuel(dist); //calls distance(dist, speed, altspeed); Altitude(speed, altspeed, altlevel); Climb_Descend (altlevel); cout <<\"do you want to calaculate again?\"<>choice; if(choice==\'Y\' || choice==\'y\') { OK=true; } else OK=false; } while (OK==true); system(\"PAUSE\"); return EXIT_SUCCESS; } void fuel (float & dist) //function { cout<<\"Enter the distance of flight \"<>dist; } void distance(float dist, float & time, float & time2) { time = dist/300; // Speed is constant 300mph time2 = (time - 0.30)*60; //30 minutes is needed to get to the top level cout<< \" the flight will last \"<.

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Please help with this MIPS Assembly Language question! The task for a function named foo is to increase the return value of the function bar (in register $v0) by 1 and return the result back to the caller. The code of the function_foo is shown below: _foo: jal_bar addi $v0, $v0, 1 jr $ra Assume that the function bar has been implemented. What is wrong with the function_foo above? a. Nothing is wrong. b. Function _foo cannot use $v0. c. It will not go back to the caller. d. The last instruction should be j $ra. Solution _foo: jal _bar //Jumps to the calculated address, and stored the return address in $ra. addi $v0, $v0, 1 //Adds 1 to the value in $v0. jr $ra //Jumps to address in register $ra. So, nothing wrong with this function. The answer is: a. Nothing is wrong..

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Please check. I am trying to fix the two errors but I don\'t know what I\'m doing wrong. #include #include int main() { char choice; // choice of user int percentArray[50]; int percentage; int count=0; char LetterGrade; for (count=0; count<50; count++){ //for loop to read the grades till array size printf(\"-------------------Enter percentage---------------\ Add marks(a) \ Quit(q) \ \") scanf choice if(choice == \'a\'){ //if user choice is a, then read the grade printf \"Enter grade:\"; scanf percentage; percentArray[count] = percentage; //add the grade to array } if(choice == \'q\'){ //if the user choice is q, then exit the loop break; } } printf \"Grades are: \" for (int i=0; i Solution #include #include int main() { char choice; // choice of user int percentArray[50]; int percentage; int count=0,i; //char LetterGrade; for(count=0; count<50; count++) { //for loop to read the grades till array size printf(\"-------------------Enter percentage---------------\ Add marks(a) \ Quit(q) \ \"); scanf(\"%c\",&choice); if(choice == \'a\') { //if user choice is a, then read the grade printf( \"Enter grade:\"); scanf(\"%d\", &percentage); percentArray[count] = percentage; //add the grade to array } if(choice == \'q\') { //if the user choice is q, then exit the loop break; } } printf(\"Grades are: \"); for(i=0; i.

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multiple choice Assuming that the probability for each shot is independent, how many points, on average, can jenny expect to make when she shoots a one-and-one ( when she only gets a second shot if she makes the first)? A. .96 B. 1 C. 2 D. .36 E. 0 Solution Average = 1 × P( she makes the first shot but misses the second shot) + 2× P( she makes both the shots) Average = 1× 0.6 × 0.4 + 2× 0.6 × 0.6 = 0.96.

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Mathematical Statistics.....Could answer be typed (is there any link between the two and if so can you discuss them) Discuss the link, if any, between linear transformations and calculating probabilities. Solution Mathematical statistics the application of mathematics to statistics the answer can be uploaded in any manner as long as it is neatly uploaded and legible or any mathematical tool can also be used to upload the answer or you can simply type your text.

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Mathematical Statistics.....Could answer be typed (is there any link.pdf

Mathematical Statistics.....Could answer be typed (is there any link.pdf

Modify the Stack class given in the book in order for it to store double numbers (instead of void* pointers). Add a destructor that will delete all the stack by making calls to pop(), and for each element destroyed the element will be printed to the output. Now add two constructors: the default one that will create an empty stack, and another one that will receive an integer n and will build a stack of n elements, such that the first element is 1.0, and the next ones are incremented of 0.1. Upload your Stack class. It will be then tested for correctness with stacks.cpp. Stack.h: //: C05:Stack2.h // Nested structs via linked list #ifndef STACK2_H #define STACK2_H class Stack { struct Link { void* data; Link* next; void initialize(void* dat, Link* nxt); }* head; public: void initialize(); void push(void* dat); void* peek(); void* pop(); void cleanup(); }; #endif // STACK2_H ///:~ Stack.cpp: Sample Output: 2 1.5 1 0.5 1.3 1.2 1.1 1 end. Solution Hi, Please find my implemntation; Please let me know in case of any issue. //: C05:Stack2.h // Nested structs via linked list #ifndef STACK2_H #define STACK2_H #include #include using namespace std; class Stack { struct Link { double data; Link* next; void initialize(double dat, Link* nxt){ data = dat; next = nxt; } }; Link *head; public: Stack(){ head = NULL; } Stack(int n){ for(double i=1; i<=n; i= i+ 0.1){ push(i); } } ~Stack(){ if(head != NULL){ while(head != NULL){ cout<data<<\" \"; Link *temp = head; head = head->next; delete temp; } cout<initialize(dat, head); head = newNode; } double peek(){ if(head == NULL){ cout<<\"Stack is Empty!!!\"<data; } double pop(){ double d = -1; if(head != NULL){ Link *temp = head; d = temp->data; head = head->next; delete temp; }else{ cout<<\"Stack is Empty!!!\"<.

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Java program I made this Account.java below. Using the attached code I need help with 10.7 (Game: ATM machine) Use the Account class created in Programming Exercise 9.7 to simulate an ATM machine. Create ten accounts in an array with id 0, 1, . . . , 9, and initial balance $100. The system prompts the user to enter an id. If the id is entered incorrectly, ask the user to enter a correct id. Once an id is accepted, the main menu is displayed as shown in the sample run. You can enter a choice 1 for viewing the current balance, 2 for withdrawing money, 3 for depositing money, and 4 for exiting the main menu. Once you exit, the system will prompt for an id again. Thus, once the system starts, it will not stop. */ import java.util.Date; public class Account { /** * @param args */ private int id=0; private double balance=0; private double annualIntrestRate=0; private Date dateCreated; public Account() { super(); } public Account(int id, double balance) { super(); this.id = id; this.balance = balance; } public int getId() { return id; } public void setId(int id) { this.id = id; } public double getBalance() { return balance; } public void setBalance(double balance) { this.balance = balance; } public double getAnnualIntrestRate() { return annualIntrestRate; } public void setAnnualIntrestRate(double annualIntrestRate) { this.annualIntrestRate = annualIntrestRate; } public Date getDateCreated() { return dateCreated; } public void setDateCreated(Date dateCreated) { this.dateCreated = dateCreated; } public double getMonthlyInterestRate() { return (this.getAnnualIntrestRate()/12); } public double getMonthlyInterest() { return (getBalance() *getMonthlyInterestRate()/100); } public double withDraw(double balance) { this.setBalance(this.getBalance()-balance); return this.getBalance(); } public double diposite(double balance) { this.setBalance(this.getBalance()+balance); return this.getBalance(); } public double totalBalance() { balance =balance + getMonthlyInterest(); return balance; } } //AccountTest.java import java.util.Calendar; import java.util.Date; import java.util.Scanner; public class AccountTest { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc=new Scanner(System.in); Account ac=new Account(1,5000.00); System.out.println(\"Enter the annual intrest rate\"); double intrestRate=sc.nextDouble(); ac.setAnnualIntrestRate(intrestRate); Date d=new Date(); Calendar currentDate = Calendar.getInstance(); ac.setDateCreated(currentDate.getTime()); System.out.println(\"Date id \"+ac.getDateCreated()); System.out.println(\"Monthly intrest rate is :\"+ac.getMonthlyInterestRate()); System.out.println(\"Monthly intrest is :\"+ac.getMonthlyInterest()); System.out.println(\"Enter Amount for diposite \"); double dipositeAmount=sc.nextDouble(); System.out.println(\"The amount after diposite is :\"+ac.diposite(dipositeAmount)); System.out.println(\"Enter Amount to withdraw :\"); double withdramount= sc.nextDouble.

Java programI made this Account.java below. Using the attached cod.pdf

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In the follwoing double bond hydration reaction: styrene + water (solvent) + H2SO4 (reagent) --- -> 1-phenylethanol, what role does H2SO4 play? a. it lowers the energy of activation. b. it will deprotonate water. c. it makes the reaction less exothermic. d. it makest the reaction more exothermic. I know that H2SO4 in this reaction catalyses the hydration of the double bond, but I do not fully understand why. I believe the answer is a, but would appreciate correction/and or explanation from someone with a better grasp of OChem! Thanks :) Solution a. it lowers the energy of activation Once the H+ ion is attacking styrene, it will form a carbocation, it is an intermediate and its activation energy will be less when campred with the starting material..

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Indicate whether each of the following items is an asset, liability, or part of owner’s equity. (a)Accounts receivable Owner’s EquityLiabilityAsset(b)Salaries and wages payable Owner’s EquityAssetLiability(c)Equipment AssetLiabilityOwner’s Equity(d)Supplies AssetLiabilityOwner’s Equity(e)Owner’s capital Owner’s EquityAssetLiability(f)Notes payable Owner’s EquityAssetLiability Solution (a) Accounts receivable - Asset (b) Salaries and wages payable - Liability (c) Equipment - Asset (d) Supplies - Asset (e) Owner’s capital - Owner’s Equity (f) Notes payable - Liability.

Indicate whether each of the following items is an asset, liability,.pdf

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In this project you implement a program such that it simulates the process of repeated attempts to hit a target with a projectile. The goal is to shoot the projectile within a 1 foot distance from the target, since such a short miss is accepted as a hit. Your program is responsible for the following tasks. Compute the trajectory data of a projectile (such as the time, the maximum height and the distance as described by the formulas above) for a given launch velocity and a launch angle, in particular for an initial choice of a 45 degree angle Determine if the target is within the range for the given launch velocity, that is check if at the first attempt the distance is sort to the target with more than 1 foot; if so the process is terminated and then restarted with an increased launch velocity (note that for any velocity the longest range is attained if the launch angle is of 45 degrees) Compute the error of a shot (error = projectile range – distance to target) Check if the error is less than 1 foot in absolute value (the absolute error); if so, notify the user about the result and terminate the process Offer the user four chances to modify the launch angle and try to hit the target Keep track of the smallest absolute error produced by the subsequent attempts; report the best effort to the user Analysis and Requirements Input Initial input values are (i) launch velocity (feet/sec) (ii) distance to the desired target (feet) (iii) gravitational acceleration (a constant) Additional input values are the launch angles for the repeated attempts when apply. The angle must always be in the range of 0.0 – 45.0 degrees. Distance, velocity and launch angle are solicited from the user on JOptionPane input windows. Output Output messages are displayed both on JOptionPane windows and on the console. Every time a launch has been executed by the program, a report providing the details of the trajectory must be displayed. Design For this project you shall design a single class which contains all the necessary data and operations. A suggested class name is Projectile. You must decide upon the necessary import(s). The Projectile class contains the main method, which in turn contains all your code, including the variable declarations. The main method is responsible for the following tasks: opens a welcoming window declares and assigns a named constant for the gravitational acceleration; the value is 32 declares variables (all double) to store projectile data velocity, distance and angle; all initialized to 0 solicits the input values as explained in the Analysis section, if either of these input is the empty string or null (Cancel button), the message as shown in Figure 11 displayed and the program exits; valid input parsed and saved in the relevant variables computes all the trajectory and output data and saves those in relevant variables (declare and use the necessary variables as specified in the class description below) builds up and stores the output messag.

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Identify main functions of a proposed internal information system and why they are important to the business. Include main functions of the System and its importance. Solution The internal information system of a business can be classified ito the four major parts: 1. Marketing information system : Marketing information system supports the decision making regarding the four marketing mix whic are price, product place and promotion. It helps marketing planning, promoting and sellling the goods and services of the company. It also helps in identifying the current marketing trends, the various needs and requirements of the customers to serve them better. Some of the major fuctions of marketing information system are the pricing decisons and sales forecasting. pricing decisions are important as it will determine the total revenue generated for the company, sales forcasting is the way of estimating the future. 2. Mnufacturing information system : Information system plays an important role in manufacturing process. The manufacturing information system includes product design and engineering, product scheduling, quality control etc.two of the major tools which are used for product design and engineering are CAD(Computer aided design) and CAE( Computer aided engineering). Product scheduling ensures that appropriate combination of man material and machine are provided at the appropiate time for the right production of the goods. 3. accounting and financial information system : The accounting and financial information system helps in keeping a track of the various transactions of the company. It takes the stock of the flows of money and others assets in and out of the organization. The various functions of accounting and financial information system are financial forcasting and planning, financial control, funds management and internal auditing etc. 4. Human resource information system : The human resource information system performs various taks such as keeping the track of the employees and their performnaces, fetching the information to the employees regarding the various benefit palns,helping the managers to evaluate his subordninates and other employees etc..

Identify main functions of a proposed internal information system an.pdf

Identify main functions of a proposed internal information system an.pdf

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If elected officials are assumed to be driven by rational self-interest, they are likely to: 0 a. have a profit incentive to act on consumer feedback. Ob. adopt a stance of rational ignorance. O c. maximize their hours worked. Od. best serve the public interest. O e. maximize their political support Solution Option E. Maximize their political support. Explanation: The self-interest of an elected official will remain in staying in power for which they will need the continued political support of their supporters..

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I need help with 1 question You are working for the NSA and they have decided that they want to keep records on every human being on the planet who is now alive or will be in the next 100 years. If the NSA wants to use the smallest amount of data possible, and that data can cross bytes, how much storage should you plan for? Assumptions: World population is 7.5 billion It is projected that 15 billion people will be born in the next 100 years The NSA wants to maintain 10,000 data points per person Each data point can have a maximum of 50 possible values The NSA wants to allow for a possible 50% expansion of data points and possible values. They also want to allow for the possibility that the up to 50% more people than anticipated will be born in the next 100 years. Solution the UN reports that their estimate of World population has 1-2% error. An evaluation of a series of United Nations population projections between the 1950s and 1990s found that all but one had a margin of error of less than 4%. Most factors indicate an undercount. World population could be 7.4 billion or even 7.5 billion now. High population growth in Nigeria and other African countries but they have the oldest and most inaccurate Census * China hiding many second and third children * Various scientific studies show that assumed decreased fertility in Africa is not happening or happening more slowly which means a lot more children, so a census with missing people from ten years ago assumes smaller families but there were more Countries like Eritrea, South Sudan and the Democratic Republic of the Congo did not conduct population censuses between 2005 and 2014, as required by the UN for their 2010 round of projections. This year Angola conducted its first national census in 30 years, Dr Mady Biaye, Technical Advisor for East and Southern Africa at the United Nations Population Fund told Africa Check. Nigeria for example has far less accurate population recording systems. Other countries have not held censuses for decades. In Nigeria the country’s census figures have been the subject of controversy for decades. Accusations of rigging date back to the 1950s and have continued unabated under military and civilian regimes. These numbers, along with most of what we think of as facts in development, are actually estimates. We have actual numbers on maternal mortality for just 16% of all births, and on malaria for about 15% of all deaths. For six countries in Africa, there is basically no information at all. The world of development has had an odd double-think about data for decades now. On the one hand, researchers and others will freely admit to the huge gaps and problems with development data (indeed, it\'s sometimes hard to get people to stop talking about it). But on the other hand, these same individuals and institutions have quite big vested interests in downplaying the unreliability of data. An academic who has just carried out a complex piece of econometrics based on househo.

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I got an answer but don\'t know how to show it with the correct work. Some correct work would be greatly appreciated. Solution f(x)=x^3+6x inverval is 1 to 4 x=(4-1)/n=3/n xi=1+i*3/n Right riemann sum Sum (R)= (i=1 to n) f(xi)xi = (i=1 to n) [[1+i*3/n]^3+6[1+i*3/n]](3/n) = (i=1 to n) 3/n[1+27i^3/n^3.........] calculate (its easy) then find the left riemann sum xi-1=1+(i-1)*3/n=3i/n-3/n+1 calculate Sum (L)= (i=1 to n) f(x(i-1))x put limit n--->infinity if Sum (R)=Sum (L)=some value :).

I got an answer but dont know how to show it with the correct .pdf

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Gunther dies intestate. The debts of the estate are paid by his? a. ?heirs, before the estate’s assets are distributed. b. ?estate, before its assets are distributed. c. ?heirs, after the estate’s assets are distributed. d. ?estate, after its assets are distributed. Solution Answer : C ACCORDING TO LAW OF LAND IF A PERSON DIES WITH MAKING ANY WILL I WOULD NOT DENY HIS LIABILITY TOWARDS CREDITORS HIS LEGAL HEIRS WILL BE LIABLE TO THE EXTENT THE VALUE OF PROPERTY DISTRIBUTED , THE LIABILITY OF HEIRS IS TO THE EXTENT OF VALUE OF PROPERTY INHERITED THANK YOU HOPE MY OPINION IS USEFULL I.

Gunther dies intestate. The debts of the estate are paid by his a. .pdf

Gunther dies intestate. The debts of the estate are paid by his a. .pdf

Gunther dies intestate. The debts of the estate are paid by his a. .pdf

F varies directly with m and inversely with the square of d. If F = 120 when m = 640 and d = 4. find F when m = 200 and d = 2. F = Solution Dear Student Thank you for using Chegg !! Given F Varies directly with m F varies inversely with square of d F = K (m/d^2) where K is proportionality constant F1 120 F2 m1 640 m2 200 d1 4 d2 2 F1 *d1^2 / m1 = F2 *d2^2 / m2 120*4^2/ 640 = F2*2^2/200 3 = F2 / 50 F2 = 150.

F varies directly with m and inversely with the square of d. If F = 1.pdf

F varies directly with m and inversely with the square of d. If F = 1.pdf

F varies directly with m and inversely with the square of d. If F = 1.pdf

Dr Snow could not randomly assign people to drink water from the well that he supposed was the source of cholera so his study was. (a). An experiment (b). Randomization (c). Correlational (d). Confounding Dr Snow could not randomly assign people to drink water from the well that he supposed was the source of cholera so his study was. (a). An experiment (b). Randomization (c). Correlational (d). Confounding Solution Answer is a..

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Dr Snow could not randomly assign people to drink water from the w.pdf

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